what value of x is in the solution set of the inequality 2(3x-1)>4x-6

Answer: 11

Step-by-step explanation:

this is a sequence of odd numbers.

it goes;

1,3,5,7,9,11,13,15,17,19,21,23....

Answer:

[tex]f(x) = (x - 4)(x + 3) [/tex]

[tex]f(x) = {x}^{2} - x - 12[/tex]

The greatest common factor (GCF) of the three monomial, 21x³y⁵, 63x⁵y² and 45x¹y³ is 3xy²

The greatest common factor (GCF) of the three monomials, 21x³y5, 63x5y² and 45x¹y³ can be obtained as follow:

First, we shall determine the factors of each monomials. This is illustrated below:

21x³y⁵ = 3 × 7 × x × x × x × y × y × y × y × y

63x⁵y² = 3 × 3 × 7 × x × x × x × x × x × y × y

45x¹y³ = 3 × 3 × 5 × x × y × y × y

Finally, we shall determine the greatest common factor (GCF) from the factors listed above. This is shown below:

3 × x × y × y = 3xy²

Thus, we can conlude that the greatest common factor (GCF) of the three monomials is 3xy²

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The value of given expression is 57.

We are given that;

|—15u| + |3v| + 3

u=3, v = 3

Now,

To evaluate the expression, you need to substitute the values of u and v and simplify. The absolute value of a number is the distance from zero on the number line, so it is always positive or zero. You can write your solution as:

|—15u| + |3v| + 3 = |—15(3)| + |3(3)| + 3 = |—45| + |9| + 3 = 45 + 9 + 3 = 57

Therefore, by the given expression the answer will be 57.

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Answer: 29.9986-----30.0 degrees

Step-by-step explanation:

x = [tex]tan^-^1(5.6/9.7)\\\\toa[/tex]

[tex]\tan(x )=\cfrac{\stackrel{opposite}{5.6}}{\underset{adjacent}{9.7}} \implies \tan^{-1}(~~\tan( x )~~) \approx \tan^{-1}\left( 0.58 \right) \\\\\\ x \approx\tan^{-1}\left( 0.58 \right)\implies x \approx 30.0^o[/tex]

Step-by-step explanation:

"Range'' is the values of 'y' that a graph can have....there are no limits on this one

(-∞,+∞)

Answer: the awnser is b

Step-by-step explanation:

Answer:

The y-intercept is -3

Written as a point it is (0, -3)

Step-by-step explanation:

To find the y-intercept, let x = 0

(and to find x-intercepts, let y = 0)

So let's let x = 0

f(x) = x^2 + 2x - 3

y = x^2 + 2x - 3

y = 0^2 + 2(0) - 3

y = -3

This means the y-intercept is -3. The graph crosses the y-axis at -3. This is the point (0, -3).

The correct statements are:

When a point is reflected across the x-axis, the x-coordinate remains the same, but the y-coordinate changes sign. Therefore, statement A) is true.

When a point is reflected across the y-axis, the y-coordinate remains the same, but the x-coordinate changes sign. Therefore, statement C) is true.

It should be noted that to represent the reflection of point A (1,-2) across the y-axis, we flip the sign of the x-coordinate to obtain the image point A' (-1,-2). Therefore, statement D) is true.

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Answer:

Set your calculator to Degree mode.

10² = 6.78² + 4² - 2(6.78)(4)(cos x)

100 = 61.9684 - 54.24(cos x)

38.0316 = -54.24(cos x)

cos x = -.701173

[tex]x = {cos}^{ - 1} ( - .701173)[/tex]

x = 134.52°

The solution is, simplification of the expression is; 71.19.

Here, we have,

the given expression is:

(5/2)^4/2 * (3/2)^6

=(5/2)^2 * (3/2)^6

as we know that, 4/2 = 2.

now, we have,

(5/2)^2 * (3/2)^6

=5²/2² ^ 3⁶/2⁶

= 5² * 3⁶ / 2² * 2⁶

=5² * 3⁶  / 2 ^ (2+6)

=5² * 3⁶  / 2 ^8

=25 * 729/ 256

=18225/ 256

=71.19

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Answer:

$17,320 after 12 months.

Step-by-step explanation:

f the Coach chooses the Three-Year Plan, the total amount he will spend after 12 months can be calculated as follows:

First, we need to calculate the total amount of monthly payments made in 12 months:

12 months x $610 per month = $7,320

Then, we need to add the down payment made at the time of purchase:

$7,320 + $10,000 = $17,320

Therefore, if the Coach chooses the Three-Year Plan, he will spend a total of $17,320 after 12 months.

Answer:

Refer to the step-by-step.

Step-by-step explanation:

Verify the given identity.

[tex]E_0\cos^4(\theta)=E_0(\frac{1}{2} +\frac{\cos(2\theta)}{2} )^2[/tex]

Pick the more complex side to manipulate, in this case it is the R.H.S.

(1) - Apply the following double-angle identity

[tex]\boxed{\left\begin{array}{ccc}\text{\underline{Double-Angle Identity:}}\\\\\cos(2A)=1-2\sin^2(A)\end{array}\right}[/tex]

[tex]E_0(\frac{1}{2} +\frac{\cos(2\theta)}{2} )^2\\\\\Longrightarrow \boxed{ E_0\Big(\frac{1}{2} +\frac{1-2\sin^2(\theta)}{2}\Big )^2}[/tex]

(2) - Split of the right fraction

[tex]E_0(\frac{1}{2} +\frac{1-2\sin^2(\theta)}{2} )^2\\\\\Longrightarrow E_0(\frac{1}{2} +\frac{1}{2} -\frac{2\sin^2(\theta)}{2})^2\\\\\Longrightarrow \boxed{E_0(1 -sin^2(\theta))^2}[/tex]

Apply the following Pythagorean identity

[tex]\boxed{\left\begin{array}{ccc}\text{\underline{Pythagorean Identity:}}\\\\1-\sin^2(A)=\cos^2(A)\end{array}\right}[/tex]

[tex]E_0(1 -sin^2(\theta))^2\\ \\\Longrightarrow E_0(\cos^2(\theta))^2\\\\\therefore \boxed{E_0\cos^4(\theta)=E_0\cos^4(\theta)}[/tex]

Thus, the identity is verified.

It has been proven and verified that [tex]E_0cos^4 \theta = E_0(\frac{1}{2} +\frac{cos2 \theta}{2} )^2[/tex] below.

In Mathematics and Geometry, the standard equation of a cosine function is represented or modeled by the following mathematical equation (formula):

y = Acos(Bx - C) + D

Where:

In this exercise, you are required to prove that the right-hand side of the cosine function is equal to left-hand side of the cosine function;

[tex]E_0cos^4 \theta = E_0(\frac{1}{2} +\frac{cos2 \theta}{2} )^2[/tex]

From the double-angle formulas, we have:

2sin²θ = 1 - cos2θ

cos2θ = 1 - 2sin²θ

Next, we would evaluate the right-hand side of the cosine function by substituting "1 - 2sin²θ" for cos2θ as follows;

[tex]E_0cos^4 \theta = E_0(\frac{1}{2} +\frac{1-2sin^2 \theta}{2} )^2\\\\E_0cos^4 \theta = E_0(\frac{1}{2} +\frac{1}{2} -\frac{2sin^2 \theta}{2})^2\\\\E_0cos^4 \theta = E_0(1 -\frac{2sin^2 \theta}{2})^2\\\\E_0cos^4 \theta = E_0(1 -sin^2 \theta)^2\\\\[/tex]

E₀cos⁴θ = E₀(1² - (sin²θ)²)

E₀cos⁴θ = E₀(1 - sin⁴θ)  ⇒ (Verified).

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Step-by-step explanation:

5 P 5 = 120 ways = 5!

Answer:

I'd like to explain more but I have limited comment

chat me up

A

Answer:

Step-by-step explanation:

5 minutes is the outlier. It sticks out from the rest.

The solution is:

20/29 is the probability that a student chosen randomly from the class plays golf or soccer.

0 is the probability that a student chosen randomly from the class plays golf and soccer.

Here, we have,

given that,

In a certain Integrated Math II class of 29 students, 6 of them play golf and 14 of them play soccer.

There are 9 students who play neither.

Number of students that play = 20

let, students play golf = A

students play soccer = B

so, given that,

n ( A) = 6 and, n ( B) = 14

so, total sample space = 29

now, P(A) = 6/29

P(B) = 14/29

and, P(students who play neither) = 9/29

we get, 6/29 + 14/ 29 + 9/29 = 29/29 = 1

i.e. there are no students who play both golf and soccer = 0

all the events are independent.

so, we have,

the probability that a student chosen randomly from the class plays golf or soccer = P(A) + P(B)

               = 6/29 + 14/ 29

               = 20/29

and, the probability that a student chosen randomly from the class plays golf and soccer = 0.

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The height of the equilateral triangle is a = 5√3 inches

Given data ,

Since the triangle is equilateral, all sides are of equal length.

Let's call the length of one side x.

Therefore, the perimeter of the triangle is 3x, which is given to be 30 inches.

On simplifying , we get

3x = 30

x = 10

Now, we know that the height of an equilateral triangle is given by the formula:

height = √3/2 x

Substituting the value of x, we get:

height = √3/2 x 10

height = 5√3 inches

Hence , the height of triangle is 5√3 inches

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The restricted domain of the function is 0≤s≤25

The equation is a(s) = 37.5s - 1.5s²  models the function represented in the table

a(s) = s(37.5 - 1.5s)

The critical points are s=0 or

37.5 - 1.5s

37.5 = 1.5s

s=25

As area can not be negative, the area should be positive

s< 0 and s>25

Therefore, restricted domain is 0≤s≤25

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The width of the confidence interval is 1.2786.

From the question we are told that

The sample size is n = 16    

The mean time is x = 2.8 minutes

The standard deviation is = 1.2 minutes

Generally, the degree of freedom is mathematically represented as  

df = n-1

df = 15

From the question we are told the confidence level is 95%, hence the level of significance is =

α = 100-95

α = 0.05

Generally, the margin of error is mathematically represented as =

[tex]E = t_{\alpha/2}, 15 \times \sigma/\sqrt{n}[/tex]

E = 2.131 × 1.6 / √16

E = 0.6393

Generally, the width the confidence 95% confidence interval  

W = 2E

W = 1.2786

Hence the width of the confidence interval is 1.2786.

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The population of the town 12 years later will be 224,800 if the current population is 28,100 and the population doubles every 4 years.

Since the population doubles every 4 years, we can use the formula:

P = P0 x [tex]2^{t/4}[/tex]

where P0 is the initial population, t is the time elapsed in years, and P is the population after time t.

In this case, the initial population P0 is 28,100, and we want to know the population after 12 years, so t = 12. Substituting these values into the formula, we get:

P = 28,100  2^(12/4)

  = 28,100 x 2³

  = 28,100 * 8 = 224,800

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Answer:

p(3) = 16

Step-by-step explanation:

to evaluate p(3) substitute x = 3 into p(x)

p(3) = 0.5(3 - 5)² + 14

      = 0.5(- 2)² + 14

      = 0.5(4) + 14

      = 2 + 14

      = 16

Answer:

0.0909

Step-by-step explanation:

4 blue + 5 red + 3 black = 12 chips in total.

p=probability

1st draw:

p (blue) = 4/12

there are now 11 chips in the bag, 4-1 =3 are blue.

2nd draw?

p (blue) = 3/11

probability of pulling one blue chip followed by another blue chip is:

(4/12) X (3/11) = (4X3)/12X11)

= (12)/(132)

= 1/11

0.0909

Hello!

m     dm    cm    mm

5   ,   0        0

500cm = 5m

Answer:

[tex]20x+240y/y[/tex]

Step-by-step explanation:

1. Subtract the numbers

2. Evaluate the exponents

3. Subtract the numbers, again

4. Have a great day and thx for your inquiry :)

The value of total area of the shape is,

⇒ 82 cm²

We have to given that;

Figure of shape is shown.

Since, Figure is made by three rectangles.

And, Area of rectangle is,

A = length x width

Hence, The area of upper rectangle is,

A = 3 x 8

A = 24 cm²

Area of middle rectangle is,

A = (11 - (3 + 5)) x (8 - 2)

A = 3 × 6

A = 18 cm²

Area of lower rectangle is,

A = 5 x 8

A = 40 cm²

Thus, The value of total area of the shape is,

⇒ 24 + 18 + 40 cm²

⇒ 82 cm²

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Answer:

dört yarım saat 2 saattir

Step-by-step explanation:

09. The total sample, 118 individuals set academic goals (regardless of gender), while 310 individuals did not set academic goals.

10. The total sample, 290 individuals have cats, while 306 individuals do not have cats. Furthermore, 312 individuals have dogs, while 284 individuals do not have dogs.

In order to find the marginal frequencies, we need to calculate the totals for each category separately.

For question 9:

The marginal frequency for "Set Academic Goals - yes" is 64 + 54 = 118. This represents the total number of individuals who answered "yes" to setting academic goals.

The marginal frequency for "Set Academic Goals - no" is 168 + 142 = 310. This represents the total number of individuals who answered "no" to setting academic goals.

The marginal frequency for "Male" is 64 + 168 = 232. This represents the total number of males.

The marginal frequency for "Female" is 54 + 142 = 196. This represents the total number of females.

Interpretation:

The marginal frequencies provide us with the total counts for each category in a contingency table. In this case, we can see that out of the total sample, 118 individuals set academic goals (regardless of gender), while 310 individuals did not set academic goals. Additionally, there were 232 males and 196 females in the sample.

For question 10:

The marginal frequency for "Cat - yes" is 104 + 186 = 290. This represents the total number of individuals who have cats.

The marginal frequency for "Cat - no" is 208 + 98 = 306. This represents the total number of individuals who do not have cats.

The marginal frequency for "Dog - yes" is 104 + 208 = 312. This represents the total number of individuals who have dogs.

The marginal frequency for "Dog - no" is 186 + 98 = 284. This represents the total number of individuals who do not have dogs.

Interpretation:

The marginal frequencies reveal the total counts for each category in the contingency table. In this case, we can observe that out of the total sample, 290 individuals have cats, while 306 individuals do not have cats. Furthermore, 312 individuals have dogs, while 284 individuals do not have dogs.

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The most reasonable conclusion based on the given information is: Salad Supreme is increasing the number of restaurants by 10% each year. Option B

Based on the given equation y = 195(1.10)^x, where x represents the number of years since 2005 and y represents the number of Salad Supreme restaurants, we can draw the following conclusions:

A. Salad Supreme had 110 restaurants in 2005: This conclusion is not supported by the given equation.

B. Salad Supreme is increasing the number of restaurants by 10% each year: This conclusion is supported by the equation.

C. Salad Supreme is increasing the number of restaurants by 195 each year: This conclusion is not supported by the equation.

D. Salad Supreme is increasing the number of restaurants by 110% each year: This conclusion is not supported by the equation. The growth factor of 1.10 (or 10%) indicates a 10% increase each year, not 110%.

Therefore, the most reasonable conclusion based on the given information is: Salad Supreme is increasing the number of restaurants by 10% each year.

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