Converting the volumes to litres is not necessary. Any volume measurement is acceptable as long as it is utilized consistently on both sides.
What is the needed volume to make dilutions?The following formula can be used to create a specific volume of a diluted solution from a stock solution. Where: V1 = Volume of stock solution required to make the new solution, C1V1 = C2V2. C1 is the stock solution's concentration. V2 is the new solution's final volume.
However, as was already said, you need to know the volume in litres if you're trying to figure out how many moles of solute are present.
Data retrieved from the query include the following:
C1 = 2.46 M
V1 =?
C2 = 0.758 M
V2 = 275 mL = 275/1000 = 0.275L
We can definitely determine the volume of the initial solution using the dilution formula C1V1 = C2V2.
C1V1 = C2V2
2.46 x V1 = 0.758 x 0.275
Divide both side by 2.46
V1 = (0.758 x 0.275) /2.46
V1 = 0.0847L
Therefore, 0.0847L volume of a 2.46 Magnesium nitrate (Mg(NO3)2)
solution would be needed to make 275 mL of a 0.758 M solution by
dilution
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Determine whether an interference pattern is observed on the other side of the slits in each experiment.
a. An electro n beam is aimed at two closely spaced slits. The beam is attenuated (made dimmer) to produce only 1 electron per minute.
b. An electron beam is aimed at two closely spaced slits. A light beam is placed at each slit to determine when an electron goes through the slit.
c. A high-intensity light beam is aimed at two closely spaced slits.
d. A gun is fired at a solid wall containing two closely spaced slits.
An interference pattern is observed on the other side of the slits in the experiments A,B,C but not in the experiment D.
A. Yes, an interference pattern is observed on the other side of the slits in this experiment. Even though the electrons are fired one at a time, the interference pattern emerges over time due to the wave-like nature of the electrons.
B. Yes, an interference pattern is observed on the other side of the slits in this experiment. The act of observing which slit the electron goes through causes the wave function to collapse and destroys the interference pattern.
C. Yes, an interference pattern is observed on the other side of the slits in this experiment. The high-intensity light beam acts as a wave and creates an interference pattern as it passes through the two slits.
D. No, an interference pattern is not observed on the other side of the slits in this experiment. A gun firing solid particles like bullets is a classical object and does not exhibit wave-like behavior, so no interference pattern can be observed.
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Which phase change represents a decrease in entropy?
a. Solid to liquid
b. Gas to solid
c. Liquid to gas
d. Solid to gas
You started a savings account by depositing $4,200. The savings account earns 2.1% APY, compounded monthly. What was the balance in the account after 2 months
The compound interest for two months will be $13.98. Then, after two months, there will be $ 4213.98 in the account.
What is compound interest ?Compound interest is the interest on normal interest. Compound interest for an amount p for a n years with a rate of interest R% can be calculated as follows:
A = P [1 + r/100]ⁿ
Given that, the amount p = $4200
rate of compound interest = 2.1 %
time period n = 2 months, it is 0.16 years.
Now the compound interest for two months = $ 4200× [1 + 2.1/100]^0.16 - $4200 = $13.98
Now, the amount after two months will be $ 4213.9.
Therefore, there will be $4213.9 in the account after two months.
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compound is 53.31% c, 53.31 % c , 11.18% h, 11.18 % h , and 35.51% o 35.51 % o by mass. what is its empirical formula? insert subscripts as needed.
The mole ratio tells us the simplest whole-number ratio of the atoms in the compound. Therefore, the empirical formula of the compound is:
C2H5O.
To find the empirical formula of the compound, we need to determine the simplest whole-number ratio of the atoms in the compound. We can assume that we have 100 g of the compound, and use the percentages given to find the masses of each element in those 100 g:
Mass of C = 53.31 g
Mass of H = 11.18 g
Mass of O = 35.51 g
Next, we need to convert these masses to moles, using the molar mass of each element:
Moles of C = 53.31 g / 12.01 g/mol = 4.44 mol
Moles of H = 11.18 g / 1.01 g/mol = 11.07 mol
Moles of O = 35.51 g / 16.00 g/mol = 2.22 mol
We can then divide each of the mole values by the smallest mole value to get the mole ratio:
Moles of C = 4.44 mol / 2.22 mol = 2.00 mol
Moles of H = 11.07 mol / 2.22 mol = 4.98 mol
Moles of O = 2.22 mol / 2.22 mol = 1.00 mol
The mole ratio tells us the simplest whole-number ratio of the atoms in the compound. Therefore, the empirical formula of the compound is:
C2H5O.
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the thermometer you use to measure the freezing temperature of the solvent actually records a temperature that is 0.12c too high. unfortunately you break this thermometer and borrow a fellow students thermometer, which reads 0.11c too low. if the molality of your solution is 0.30, calculate the contribution to the percentage error in your result due to not correcting for the errors in the thermometer readings.
The contribution to the percentage error in the freezing point depression due to the errors in the thermometer readings is 1.76%.
The freezing point depression is a colligative property that depends only on the molality of the solute particles in a solution and is independent of the identity of the solute. Therefore, the freezing point depression is given by the equation:
ΔTf = Kf x molality
where ΔTf is the change in the freezing point, Kf is the freezing point depression constant for the solvent, and molality is the concentration of solute particles in moles per kilogram of solvent.
However, in this case, there are errors in the thermometer readings that can contribute to the uncertainty in the calculated freezing point depression. The errors are +0.12°C for the initial thermometer and -0.11°C for the borrowed thermometer.
The total error due to thermometer readings is the sum of the errors from both thermometers, which is:
Total error = +0.12°C - 0.11°C = +0.01°C
The percentage error due to the thermometer readings can be calculated as:
Percentage error = (total error / measured freezing point) x 100%
The measured freezing point is the sum of the actual freezing point depression and the error due to the thermometer readings. Assuming that the actual freezing point depression was accurately measured, the measured freezing point can be expressed as:
Measured freezing point = actual freezing point depression + total error
Since the molality of the solution is given as 0.30, the actual freezing point depression can be calculated using the freezing point depression constant for the solvent.
Assuming a typical freezing point depression constant for the water of 1.86°C/m, the actual freezing point depression would be:
actual freezing point depression = Kf x molality = 1.86°C/m x 0.30 mol/kg = 0.558°C
Therefore, the measured freezing point would be:
Measured freezing point = actual freezing point depression + total error = 0.558°C + 0.01°C = 0.568°C
The percentage error due to the thermometer readings would be:
Percentage error = (total error / measured freezing point) x 100% = (0.01°C / 0.568°C) x 100% = 1.76%
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a gas at 24o c with a pressure of 100 kpa has a volume of 5.0 l. if the volume increases to 20.0 l what is its new pressure? assume that the temperature remains constant.
We can use the ideal gas law, PV = nRT, to determine the new pressure of the gas when its volume increases. The ideal gas law relates the pressure, volume, and temperature of a gas to the number of moles (n) of gas and the gas constant (R).
First, we'll convert the temperature to kelvins:
[tex]T (K) = 24°C + 273 = 297 K[/tex]
Next, we'll use the original pressure and volume to determine the number of moles of gas (n):
PV = nRT
n = PV / RT
n = (100 kPa * 5.0 L) / (8.31 J/mol K * 297 K) = 0.17 mol
Finally, we'll use the new volume, the number of moles of gas, and the temperature to determine the new pressure:
PV = nRT
P = (nRT) / V
P = (0.17 mol * 8.31 J/mol K * 297 K) / (20.0 L) = 46.5 kPa
So the new pressure of the gas is 46.5 kPa, when its volume increases from 5.0 L to 20.0 L while the temperature remains constant at 24°C.
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22.3.2 Test (CST): The Solar System
Question 7 of 10
In which coastal area is the tide rising to form a high tide?
A. One that is rotating toward the Sun
B. One that is rotating toward the Moon
C. One that is rotating away from the Moon
D. One that is rotating away from the Sun
In an ecosystem, the coastal area that is rotating toward the moon is the area where tide rising to form a high tide.
What is an ecosystem?
Ecosystem is defined as a system which consists of all living organisms and the physical components with which the living beings interact. The abiotic and biotic components are linked to each other through nutrient cycles and flow of energy.
Energy enters the system through the process of photosynthesis .Animals play an important role in transfer of energy as they feed on each other.As a result of this transfer of matter and energy takes place through the system .
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Balance the chemical reaction
using an atom inventory.
What is the coefficient for
sodium?
[?]Na + Cl₂ → [ ]NaCl
The coefficient for sodium in the balanced equation would be 1.
Balancing chemical equationWhen balancing a chemical equation, you want to make sure that the number of atoms of each element is the same on both sides of the equation. To do this, you can follow these steps:
The unbalanced equation with the correct chemical formulas for the reactants and products.Na + Cl2 -> NaCl
Count the number of atoms of each element on both sides of the equation.On the left side, there is 1 Na and 2 Cl.
On the right side, there is 1 Na and 1 Cl.
Add coefficients to the reactants and/or products to balance the number of atoms of each element. In this case, we can balance the number of chlorine atoms by adding a coefficient of 2 in front of NaCl, like this:Na + Cl2 -> 2 NaCl
Thus, the coefficient of sodium is 1.
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Threat and risk assessment of a suspect is referred to as
O suspect-based profiling
O geographical profiling
O crime scene profiling
O psychological profiling
Assessment of a suspect's threat and risk is referred to as "suspect-based profiling".
Explain about the suspect-based profiling?Understanding the numerous risks to your IT systems, assessing the amount of risk to which these systems are exposed, and suggesting the proper level of protection all require the use of a Threat and Risk Assessment (TRA).
In order to support informed risk-based decision-making, a STRA is the whole activity of assessing as well as reporting privacy issues for just an information system. Risk assessments and proposed interventions are also recorded in a STRA. Threat assessments look into problems as they arise or are tried, whereas risk assessments examine a wider range of possibilities to identify any prospective difficulties and the potential scope of damage. Providing suggestions that maximise the protection information confidentiality, integrity, and availability while maintaining functioning is the goal or conclusion of a threat and risk assessment.Thus, assessment of a suspect's threat and risk is referred to as "suspect-based profiling".
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The reaction of benzaldehyde with acetone and sodium hydroxide produces v Choose... stilbere This is an example of Choose.... reaction dibenzylideneacetone benzocaine anthracene triphenyl methanol The reaction of benzaldehyde with acetone and sodium hydroxide produces Choose... This is an example of v Choose... reaction. a Diels-Alder a Wittig an aldol condensation a Fischer esterification a Grignard
Dibenzylideneacetone is formed when benzaldehyde reacts with acetone and sodium hydroxide. An aldol condensation process is seen here. The aldol condensation reaction.
is a process that occurs in the presence of a base (sodium hydroxide) between an aldehyde or ketone to generate a beta-hydroxy aldehyde or ketone, which may then be dehydrated to form an alpha,beta-unsaturated aldehyde or ketone. In this scenario, Dibenzylideneacetone is formed when benzaldehyde reacts with acetone and sodium hydroxide. An aldol condensation process is seen here. The aldol condensation reaction. the beta-hydroxy ketone produced (dibenzylideneacetone) is dehydrated to produce the alpha,beta-unsaturated ketone (stilbene is not formed in this reaction).
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Find the ionic and net ionic equation for HC2H3O2 + Mg(OH)2 = Mg(C2H3O2)2 + H2O
The ionic and net ionic equations for HC₂H₃O₂ + Mg(OH)₂ → Mg(C₂H₃O₂)₂ + H₂O is 2H⁺ + 2(C₂H₃O₂)⁻ + Mg²⁺ + 2 (OH)⁻ → Mg ²⁺ + 2(C₂H₃O₂)⁻ + 2H⁺ + 2OH⁻.
Ion equations are chemical equations that display the ions involved in a process. Ions that mix in a solution to create new compounds, to put it another way. Spectator ions are the ions that do not participate. While a complete ionic equation also shows the spectator ions, a net ionic equation shows the chemical species engaged in the reaction.
Thus, 2H⁺ + 2(C₂H₃O₂)⁻ + Mg²⁺ + 2 (OH)⁻ → Mg ²⁺ + 2(C₂H₃O₂)⁻ + 2H⁺ + 2OH⁻ is the net ionic equation.
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determine the percent error in the experimentally determined value for the enthalpy of formation of mgo.
From the information provided, the percent error in the experimentally determined value for the enthalpy of formation of MgO is 1.96%
To determine the percent error in the experimentally determined value for the enthalpy of formation of MgO, we need to compare the experimental value to the accepted or theoretical value.
The accepted value for the enthalpy of formation of MgO is: -601.8kJ/mol. Let's assume that the experimentally determined value is -590.0 kJ/mol.
The percent error can be calculated using the following formula:
Percent error = |(Experimental value - Theoretical value) / Theoretical value| x 100%
Substituting the values, we get:
Percent error = |(-590.0 kJ/mol - (-601.8 kJ/mol)) / (-601.8 kJ/mol)| x 100%
Percent error = |(11.8 kJ/mol) / (601.8 kJ/mol)| x 100%
Percent error = 1.96%
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What is the chemical formula for lead(ll)nitrate and calculate it mole when the mass is 7. 04g
The chemical formula for lead (II) nitrate is Pb(NO3)2 and there are approximately 0.0212 moles of lead (II) nitrate present in 7.04 grams of the compound.
To calculate the number of moles of lead (II) nitrate present in 7.04 grams of the compound, we first need to determine its molar mass.
The molar mass of Pb(NO3)2 can be calculated by adding the atomic masses of lead, nitrogen, and oxygen, multiplied by the number of atoms of each element in the formula:
Molar mass of Pb(NO3)2 = (207.2 g/mol for Pb) + (2 × 14.0 g/mol for N) + (6 × 16.0 g/mol for O)
= 331.2 g/mol
Using the formula for moles:
moles = mass / molar mass
Plugging in the given mass and the calculated molar mass, we get:
moles = 7.04 g / 331.2 g/mol ≈ 0.0212 mol
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Which of these is a possible boiling point for a 1.0 M solution of sugar in water? The normal boiling point of water is 100 degrees celsius
99.7
-0.3
100.3
According to the question 100.3 is the possible boiling point for a 1.0 M solution of sugar in water.
What is boiling point?Boiling point is the temperature at which a liquid changes to a gas or vapor. It is the temperature at which the vapor pressure of the liquid becomes equal to the atmospheric pressure. Water boils at 212°F (100°C) at sea level, but the boiling point decreases as altitude increases. Boiling point is an important property of liquids and is used to separate mixtures of liquids, to determine the purity of a substance, and to measure the composition of a mixture of liquids.
100.3 is the possible boiling point for a 1.0 M solution of sugar in water. The boiling point of a solution will be higher than that of pure water due to the increased solute concentration. The increase in boiling point is dependent on the molarity (moles of solute per liter of solution) of the solution. For a 1.0 M solution of sugar, the boiling point should be about 100.3 degrees Celsius.
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Iron has a density of 7. 86 g/cm3 (1 cm3=1 mL). Calculate the volume (in dL) of a piece of iron having a mass of 4. 18 kg. Note that the density is provided in different units of volume and mass than the desired units of volume (dL) and the given units of mass (kg). You will need to express the density in kg/dL (1 cm3 = 1 mL) before calculating the volume for the piece of iron
510.17 centimetres cube is the volume of iron has a density of 7.86 gram per centimetres cube ( 1 centimetre cube = 1ml) and has a mass of 4.01 kg.
Density is the amount of mass of a substance present per volume of the cubic centimetre and it is the ratio of mass of a substance to the volume of the substance with a unit centimetre cube.
The iron has a density of 7.86 gram per centimetres cube and mass of 4.01 kg so,
mass in grams= [tex]\frac{4.01}{1000} = 0.0041g.\\Density= \frac{mass}{volume}[/tex]
Substituting the values in the equation, we get:-
volume= [tex]\frac{0.0041}{7.86} = 510.17 cm^{3} .[/tex]
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which description of luster is most accurate? question 5 options: luster refers to how a mineral reflects light. luster refers to where in earth the mineral was likely formed. luster is a description of how a mineral feels. luster is a description of how many varieties a mineral can have.
luster refers to how a mineral reflects light is the most accurate description of luster
lustre, in mineralogy, the appearance of a mineral surface in terms of its light-reflective qualities. Luster depends upon a mineral’s refractive power, diaphaneity (degree of transparency), and structure. Variations in these properties produce different kinds of luster, whereas variations in the quantity of reflected light produce different intensities of the same luster. The kind and intensity of lustre is the same for crystal faces of like symmetry but may be different on those with different symmetry.
The kinds of luster are usually described as follows (the prefix “sub-,” as in submetallic, is used to express imperfect luster of the kind): metallic, waxy, vitreous, silky, pearly, and dull are all types of luster.
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What compounds break up into ions in solution?
Answer:B
Explanation:
name the type of chemical reaction that occurs when magnesium chloride solution (mgcl2) reacts with sodium carbonate solution (na2co3).
A double displacement reaction, also known as a precipitation reaction, occurs when magnesium chloride solution (MgCl2) reacts with sodium carbonate solution (Na2CO3).
The balanced chemical equation for the reaction is
MgCl2 (aq) + Na2CO3 (aq) → MgCO3 (s) + 2NaCl (aq)
In this reaction, the magnesium ion (Mg2+) from MgCl2 reacts with the carbonate ion (CO32-) from Na2CO3 to form solid magnesium carbonate (MgCO3) and aqueous sodium chloride (NaCl). This reaction is a double displacement reaction because the positive and negative ions in the reactants switch places to form the products. Additionally, the formation of a solid product, magnesium carbonate, indicates that this reaction is also a precipitation reaction.
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What functional groups are common to all α-amino acids?
Check all that apply.
aromatic
amide
carboxylate
alcohol
thiol
protonated amine
The functional groups that are common to all α-amino acids are: Carboxylate group (COO-), Protonated amino group (NH3+)Therefore, the correct options are: Carboxylate Protonated amine
The following functional groups are not common to all α-amino acids:
Aromatic (Some α-amino acids have aromatic side chains, but not all of them have) Amide (Peptide bond formation between amino acids involves the formation of an amide bond, but not all α-amino acids have an amide functional group in their structure) Alcohol (Some α-amino acids have hydroxyl groups in their side chains, but not all of them have) Thiol (Only one α-amino acid, cysteine, has a thiol group in its side chain)
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a 1.375 g sample of a sugar found in seaweed is burned completely in oxygen to give 1.993 g of co2 and 0.9519 g of h2o. what is the empirical formula of this sugary substance?
We must establish the ratio of the atoms of each element in the compound in order to derive the empirical formula for sugar.
In chemistry, the simplest whole-number ratio of each element's atoms in a chemical compound is referred to as the empirical formula. It stands for the lowest component of a substance that nevertheless has its chemical characteristics. The empirical formula is crucial for figuring out a substance's makeup and comprehending its chemical behaviour. The empirical formula simply provides the relative proportions of the atoms, as opposed to the molecular formula, which provides the precise number of atoms in a molecule. The relative proportions of the elements in a compound must be known in order to derive the empirical formula of the substance. This information can be collected through tests like combustion analysis or elemental analysis.
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how do you determine the range of electrolyte concentration in which a controlled flocculation occurs
The range of electrolyte concentration in which controlled flocculation occurs can be determined by performing a series of experiments where the electrolyte concentration is gradually increased or decreased.
Here are the general steps for determining the range of electrolyte concentration:
Prepare a series of solutions with different electrolyte concentrations by adding increasing or decreasing amounts of the electrolyte to the sample.
Mix the solutions thoroughly and allow them to sit for a specific period of time to allow for flocculation to occur.
Observe the samples and record any changes in the sample's appearance, such as increased turbidity or formation of flocs.
Compare the results of each sample to identify the range of electrolyte concentration at which controlled flocculation occurs.
Repeat the experiment several times to confirm the range of electrolyte concentration that results in controlled flocculation.
Once the range of electrolyte concentration is determined, it can be used to optimize the flocculation process by selecting an electrolyte concentration within the range to achieve the desired flocculation effect.
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lysine is an essential amino acid. one experiment showed that each molecule of lysine contains two nitrogen atoms. another experiment showed that lysine contains 19.2% n, 9.64% h, 49.3% c, and 21.9% o by mass. what is the molecular formula for lysine?
The molecular formula for lysine is [tex]C6H14N2O2[/tex] which in one experiment showed that each molecule of lysine contains two nitrogen atoms while the other contains 19.2% N, 9.64% H, 49.3% C, and 21.9% O by mass.
The molecular formula for lysine is calculated using the percentages of each element.
Given for nitrogen, the mass percentage = 19.2%
The atomic mass of nitrogen (N) known = (14.01 g/mol)
The number of atoms of nitrogen = 19.2/14.01 = 1.38 ≈ 2
For hydrogen, the mass percentage = (9.64%)
the atomic mass of hydrogen (H) known = (1.01 g/mol)
The number of atoms of hydrogen = 9.64/1.01 = 9.54 ≈ 10
For carbon, the mass percentage = (49.3%)
the atomic mass of carbon (C) known = (12.01 g/mol)
The number of atoms of carbon = 49.3/12.01 = 4.11 ≈ 6
For oxygen, the mass percentage = (21.9%)
the atomic mass of oxygen (O) known = (16.00 g/mol)
The number of atoms of oxygen =21.9/16 = 1.36 ≈ 2
Therefore, the molecular formula of lysine is [tex]C6H14N2O2[/tex].
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Perform the following calculations and report the answer with the correct number of significant figures.
59.9x35??????????
How does the acidity of a solution change with increasing concentration of hydrogen ions (H+)?
Answer: If you add acid to a solution the concentration of hydrogen ions (acidity) increases and the pH decreases.
Explanation:
Answer:
The acidity of a solution increases with increasing concentration of hydrogen ions (H+). The concentration of H+ in a solution determines the pH of the solution, with lower pH values indicating a more acidic solution.
Explanation:
What is the role of entropy in a combustion reaction?
In a combustion reaction, entropy plays a role in determining the direction of the reaction and the amount of heat released.
What is the second law of the thermodynamics?According to the second law of thermodynamics, a reaction is favored if it leads to an increase in the overall entropy of the system. In a combustion reaction, the breaking of chemical bonds in the reactants leads to the formation of new bonds in the products, resulting in an increase in the number of microstates and entropy.
The heat released in the reaction also contributes to the increase in entropy. As a result, combustion reactions are generally exothermic and spontaneous.
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which solution has a lower boiling point? question 6 options: a 1.5m c2h6 solution a 0.75m nacl solution all four solutions have the same boiling point a 1.5m c3h8 solution a 0.5m mgcl2 solution
Ebullioscopy is the process of finding lower boiling point so that result is NaCl
Ebullioscopy is the process of changing the boiling point of a substance by adding a nonvolatile solute; T = W is the formula used to determine the temperature change. I where I is the Van't Hoff factor and W is equal to nsolute/msolvent. Since each material has the same molarity, n is constant across the board.
I is equal to the initial/final particles.
AlCl₃ dissociates atAl⁺³ and 3Cl⁻, resulting in 4 final particles and 1 initial particle, I = 4/1 = 4; NaCl dissociates at Na⁺ and Cl⁻ resulting in 2 final particles and 1 initial particle, I = 2/1 = 2; and MgCl₂ dissociates at Mg⁺² and 2Cl⁻, resulting in 3 final particles and 1 initial particle, I = 3/1 = 3.C₆H₁₂O₆ does not dissociates. The solution containing AlCl₃ will therefore have the highest T and, as a result, the Low boiling point is NaCl.
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fumaric acid is an intermediate metabolite of glucose metabolism. fumaric acid contains 41.392% c, 3.473% h, and 55.135% o by mass. what is the empirical formula for fumaric acid
Fumaric acid is an intermediate metabolite of glucose metabolism. fumaric acid contains 41.392% c, 3.473% h, and 55.135% o by mass.the empirical formula of fumaric acid is C3H4O4.
Determining the Empirical Formula of Fumaric Acid.To determine the empirical formula of fumaric acid, we need to calculate the relative number of atoms of each element present in the compound. We can assume a 100 g sample of fumaric acid, which means we have:
41.392 g of carbon (C)
3.473 g of hydrogen (H)
55.135 g of oxygen (O)
Next, we need to convert these masses to moles by dividing them by the respective atomic/molecular masses:
C: 41.392 g / 12.01 g/mol = 3.446 mol
H: 3.473 g / 1.01 g/mol = 3.441 mol
O: 55.135 g / 16.00 g/mol = 3.446 mol
We can see that the number of moles of each element is approximately the same, so the empirical formula is simply the ratio of the atoms in the compound, which is:
C3H4O4
Therefore, the empirical formula of fumaric acid is C3H4O4
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in going from room temperature (25 c) to 10 c above room temperature, the rate of reaction triples. calculate the activation energy for the reaction .
Answer: Ea=5.29 × 10⁴ J/mol
Explanation:In going from 25 °C (298 K) to 35 °C (308 K), the rate of the reaction doubles. Since the rate of the reaction depends on the rate constant (k), this implies that the rate constant doubles. We can find the activation energy (Ea) using the two-point form of the Arrhenius equation.
Explanation:
which of the following factors is not involved in the downwelling responsible for the thermohaline circulation? a. evaporation b. low precipitation c. warm surface currents d. freezing of sea water
Option (d) is correct. Freezing of sea water is not responsible for the thermohaline circulation.
Thermohaline circulation is defined as the movement of ocean water caused by density difference brought about by variations in temperature and salinity. As ocean water freezes at the poles it concentrates salt and the colder and denser water sinks. It is a part of the large scale ocean circulation that is driven by global density gradients created by surface heat and freshwater. The term thermohaline derives from word "thermo", referring to temperature and "haline", referring to salt content. Both together determine the density of sea water. Thermohaline circulations occur in certain marginal seas associated with warm waters rendered dense by their high salinity resulting from evaporation.
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a) Calculate the pH of a 0.1 mol/L solution of hydrosulfuric acid [4 marks]
b) Calculate the concentration of H3O+ present in this solution (2 marks)
Answer:
a) The pH of a 0.1 mol/L solution of hydrosulfuric acid is 1.00.
b) The concentration of H3O+ present in this solution is 0.1 mol/L.
Answer:
A) To calculate the pH of a 0.1 mol/L solution of hydrosulfuric acid (H2S), we can first calculate the concentration of hydronium ions (H3O+) produced in solution.
Hydrosulfuric acid dissociates in water according to the following equation:
H2S + H2O → H3O+ + HS-
Since the concentration of hydrosulfuric acid is 0.1 mol/L, the concentration of hydronium ions produced will also be 0.1 mol/L.
Next, we can use the concentration of hydronium ions to calculate the pH of the solution:
pH = -log[H3O+] = -log(0.1) = 1
So, the pH of a 0.1 mol/L solution of hydrosulfuric acid is 1.
B) The concentration of H3O+ present in the solution is 0.1 mol/L.
Explanation:
ALLEN
