What volume of CO2 is produced when reacting 155 g of C3H8 in a combustion reaction at STP?

As you move from left to right across a row of the periodic table, the atomic number increases, meaning there are more protons in the nucleus of the atom.

Atomic number is the number of protons in the nucleus of an atom, which determines its chemical properties and place in the periodic table of elements. The atomic number is represented by the symbol Z and is the whole number located above an element's symbol in the periodic table.

Elements are arranged in order of increasing atomic number, and elements with the same atomic number belong to the same element, regardless of their mass number or number of neutrons.

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To produce 5.4 moles of [tex]Na_{2} O[/tex] in the given reaction, 10.8 moles of NaCl are required.

The given chemical equation is a balanced equation, which means it represents the stoichiometric relationship between the reactants and products involved in the reaction.

The coefficients of the balanced equation represent the number of moles of each reactant and product involved in the reaction.

In this case, the equation is:

2 NaCl + MgO → [tex]Na_{2} O[/tex] + [tex]MgCl_{2}[/tex]

From the equation, we can see that 2 moles of NaCl are required to produce 1 mole of . Therefore, to produce 5.4 moles of [tex]Na_{2} O[/tex], we need to use stoichiometry to determine the amount of NaCl required.

We can use the following formula to calculate the number of moles of NaCl required:

moles of NaCl = moles of [tex]Na_{2} O[/tex] × (2 moles NaCl / 1 mole [tex]Na_{2} O[/tex])

Substituting the given values, we get:

moles of NaCl = 5.4 moles [tex]Na_{2} O[/tex] × (2 moles NaCl / 1 mole [tex]Na_{2} O[/tex]) = 10.8 moles NaCl

Therefore, we need 10.8 moles of NaCl to produce 5.4 moles of [tex]Na_{2} O[/tex] in the given reaction.

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The amount of NH₃ that would be produced from H₂ is less than the amount that would be produced from N₂, H₂ is the limiting reagent. Then, the theoretical yield of NH₃ is 6.98 g.

The balanced chemical equation for the reaction between H₂ and N₂ to form NH₃ is;

N₂ + 3H₂ → 2NH₃

To calculate the theoretical yield of NH₃, we need to determine the limiting reagent in the reaction. We can do this by calculating the amount of NH₃ that would be produced from each reactant, assuming that the other reactant is in excess.

For H₂; 1 mole of H₂ (2.02 g) reacts with 0.5 moles of NH₃ (17.03 g)

Therefore, 1.40 g of H₂ would produce: (0.5 mol NH₃ / 1 mol H₂) x (17.03 g NH₃ / 1 mol NH₃) x (1.40 g H₂ / 2.02 g H₂)

= 6.98 g NH₃

For N₂ 1 mole of N₂ (28.02 g) reacts with 2 moles of NH₃ (34.06 g)

Therefore, 9.66 g of N₂ would produce; (2 mol NH₃ / 1 mol N₂) x (34.06 g NH₃ / 1 mol NH₃) x (9.66 g N₂ / 28.02 g N₂) = 23.5 g NH₃

Therefore, the theoretical yield of NH₃ is 6.98 g.

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Answer:

1.44 STABLE

Explanation:

Answer:a=10.3 b=250.7c c= gass d= liquid

Explanation:

Taking into account the definition of molarity, you would recover 0.525 moles of iron (II) nitrite.

Molar concentration or molarity indicates the number of moles of solute that are dissolved in a given volume.

The molarity of a solution is calculated by dividing the moles of solute by the volume of the solution:

molarity= number of moles÷ volume

Molarity is expressed in units moles/L.

In this case, you have:

Replacing in the definition of molarity:

3.5 M= number of moles÷ 0.150 L

Solving:

3.5 M× 0.150 L= number of moles

0.525 moles= number of moles

Finally, you would recover 0.525 moles​.

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The balanced chemical equation for the production of the propane :

3C(s) + 4H₂(g) → C₃H₈(g)

The chemical equations for intermediate steps are :

(a) C₂H₈(g)+5O₂(g) --> 3CO₂(g)+ 4H₂O(l)

(b) C(s) + O₂(g) --> CO₂(g)

(c) H₂(g) + 0.5O₂(g) --> H₂O(l)

The sum of the 3(b) + 4(c) we get the reaction is as :

3b =  3C(s) + 3O₂(g) → 3CO₂

4c =  4H₂(g) + 2O₂(g) → 4H₂O(l)

3C(s) + 4H₂(g) + 5O₂(g) → 3CO₂(g) + 4H₂O(l)

Now minus the obtain reaction :

The balanced chemical equation the production of the propane, that is C₃H₈(g), from its elements, the C(s,graphite) and the H₂(g) :

3C(s) + 4H₂(g) → C₃H₈(g)

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The Sun rotates at different rates at different latitudes on the Sun

The sun revolves around its axis like a ball in motion. One cycle of the sun takes approximately 27 days. But the sun rotates at various rates in various parts. The sun's equator rotates more quickly than its poles. Differential rotation is the name given to this phenomena.

The depth of the sun also affects how quickly it rotates, with the core regions rotating more slowly than the outer regions.

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Missing parts;

Which statement about the Sun's rotation is TRUE?

The Sun rotates only at the equator, where the sunspots are found; the rest of the Sun does not rotate

Only the atmosphere of the Sun rotates, not the main body of the Sun

The Sun rotates at different rates at different latitudes on the Sun

The Sun rotates once a day

The Sun does not rotate; only planets rotate

The total moles of [tex]O_2[/tex] needed is 10

To find the moles of [tex]C2H_4[/tex] in the mixture, first, write the balanced equations for combustion:

[tex]CH_4 + 2O_2[/tex] → [tex]CO_2 + 2H_2O[/tex]

Expanding, this becomes:

[tex]C_2H_4 + 3O_2[/tex] → [tex]2CO_2 + 2H_2O[/tex]

Let x = moles of [tex]CH_4[/tex] and y = moles of [tex]C2H_4.[/tex]

The total moles of [tex]O_2[/tex] needed is 10: 2x + 3y = 10

Therefore, it can be seen that in order to burn the mixture of methane [tex]CH_4[/tex] and ethane [tex]C2H_4[/tex], there are 10 moles of CH4 that are needed in the solution.

With this in mind, the total moles of [tex]O_2[/tex] needed is 10:

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Nuclear modifications are alterations that take place inside an atom's nucleus. The amount of protons and neutrons in the nucleus may change, and this is the most fundamental degree of change that can take place in a material.

The atom is considered to have experienced a nuclear transition and is now a distinct atom when the number of protons or neutrons changes. This is thus because the element is determined by the number of protons, and the element changes if the number of protons varies.

If an atom of uranium contains 92 protons, for instance, it is uranium; nevertheless, if it has 91 protons, it is protactinium. This nuclear shift produces a distinct atom with different properties.

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The heat absorbed by the engine block when its temperature is raised from 20°C to 90°C is 665,640 J.

To calculate the heat absorbed by the engine block, we can use the equation:

Q = mcΔT

where Q is the heat absorbed, m is the mass of the engine block, c is the specific heat capacity of steel, and ΔT is the change in temperature.

First, we need to calculate the specific heat capacity of steel. The specific heat capacity of steel is typically around 0.45 J/g°C.

Using this value and the given values of mass and temperature change, we can calculate the heat absorbed by the engine block as follows:

Q = (21080 g) x (0.45 J/g°C) x (90°C - 20°C)

Q = 21080 g x 0.45 J/g°C x 70°C

Q = 665,640 J

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Answer:

A. 9.83g

B. 13.06

Explanation:

A) To calculate the mass of BaSO4 formed, you need to first write the balanced equation for the reaction:

Ba(OH)2 + H2SO4 -> BaSO4 + 2H2O

Then, you need to find the limiting reactant, which is the one that runs out first and determines how much product is formed. You can do this by converting the volumes and concentrations of the solutions to moles and comparing them with the stoichiometric coefficients.

50 mL of 1.00 M Ba(OH)2 = 0.050 L x 1.00 mol/L = 0.050 mol Ba(OH)2 88.7 mL of 0.475 M H2SO4 = 0.0887 L x 0.475 mol/L = 0.0421 mol H2SO4

According to the equation, 1 mol of Ba(OH)2 reacts with 1 mol of H2SO4, so Ba(OH)2 is in excess and H2SO4 is the limiting reactant.

Next, you need to use the mole ratio between the limiting reactant and the product to find how many moles of BaSO4 are formed:

0.0421 mol H2SO4 x (1 mol BaSO4 / 1 mol H2SO4) = 0.0421 mol BaSO4

Finally, you need to multiply the moles of BaSO4 by its molar mass to get its mass:

0.0421 mol BaSO4 x 233.39 g/mol = 9.83 g BaSO4

So, the mass of BaSO4 formed is 9.83 g.

B) To calculate the pH of the mixed solution, you need to first find the concentration of OH- ions that remain after the reaction. You can do this by subtracting the moles of OH- that reacted with H+ from the initial moles of OH- and dividing by the total volume of the solution.

The initial moles of OH- are equal to the moles of Ba(OH)2:

0.050 mol Ba(OH)2 x (2 mol OH- / 1 mol Ba(OH)2) = 0.100 mol OH-

The moles of OH- that reacted with H+ are equal to the moles of H2SO4:

0.0421 mol H2SO4 x (2 mol H+ / 1 mol H2SO4) = 0.0842 mol H+

The remaining moles of OH- are:

0.100 mol OH- - 0.0842 mol H+ = 0.0158 mol OH-

The total volume of the solution is:

50 mL + 88.7 mL = 138.7 mL = 0.1387 L

The concentration of OH- is:

0.0158 mol OH- / 0.1387 L = 0.114 M

Next, you need to use the relationship between pH and pOH to find the pH:

pOH = -log[OH-] = -log(0.114) = 0.94 pH + pOH = 14 pH = 14 - pOH = 14 - 0.94 = 13.06

So, the pH of the mixed solution is 13.06.

The experiment looks into how temperature impacts how quickly magnesium metal reacts with hydrochloric acid. The creation of hydrogen gas over time is used to determine the dependent variable, which is the reaction rate.

The experiment can be run at various temperatures to change the experiment's independent variable, which is the reaction mixture's temperature. Higher temperatures cause molecules to move more quickly, increasing the likelihood of reactant collisions and kinetic energy. By enabling more successful collisions between magnesium atoms and hydrochloric acid, can quicken the reaction and increase the amount of hydrogen gas produced. In contrast, it is anticipated that the reaction rate will be slower at lower temperatures since there will be less molecular mobility and fewer successful collisions.

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--The complete Question is, What is the effect of temperature on the rate of reaction between hydrochloric acid and magnesium metal?

The dependent variable in this experiment is the rate of reaction, which can be measured by monitoring the production of hydrogen gas over time. The independent variable is the temperature of the reaction mixture, which can be controlled and varied by conducting the experiment at different temperatures.--

Answer: The volume of oxygen that would be needed to completely burn

75.0 liters of acetylene [tex]C_{2} H_{2}[/tex] at STP is 187.5 liters.

Definition of volume : -Volume is the amount of space occupied by a substance, while mass is the amount of matter it contains.  The units of volume are liter, milliliter,  

Definition of STP : Standard temperature and pressure (STP) refers to the nominal conditions in the atmosphere at sea level. These conditions are 0 degrees Celsius and 1 atmosphere (atm) of pressure. The STP value is important to physicists, chemists, engineers, pilots and navigators, among others.

Explanation: Given : Volume of acetylene  [tex]C_{2} H_{2}[/tex]  = [tex]75[/tex] liters.

When oxygen is burnt in acetylene , the chemical reaction is given as:

[tex]C{2} H_{2} + \frac{5}{2} O_{2} = 2CO_{2} +H_{2O}[/tex]

So, for [tex]75[/tex] liters of acetylene Volume of oxygen required = [tex]\frac{5}{2}[/tex] × [tex]75[/tex] = [tex]187.5[/tex] liters.

Final answer : The volume in liters of oxygen that would be needed to completely burn 75.0 liters of acetylene [tex]C_{2} H_{2}[/tex] at STP is 187.5 liters

We need to add approximately 0.3375 moles of HCl to the 1-liter buffer solution to achieve a pH of 4.02.

To adjust the pH of a 1-liter buffer solution (1.3M acetic acid, 0.8M sodium acetate) to 4.02, use the Henderson-Hasselbalch equation: pH = pKa + log ([A-] / [HA]).

Acetic acid's pKa is 4.74.

Solving for the ratio (0.8 / 1.3) gives ≈ 0.215. After adding HCl, new concentrations are: [HA]new = 1.3 + x, [A-]new = 0.8 - x.

The new ratio (0.8 - x) / (1.3 + x) = 0.215.

Solving for x yields ≈ 0.3375 moles.

Add 0.3375 moles of HCl to achieve a pH of 4.02.

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5.93 moles of lithium oxide i.e. the product will be produced in the reaction.

The balanced chemical equation for the synthesis of lithium oxide from lithium and oxygen gas is:

4 Li + O₂ → 2 Li₂O

We must first compute the required volume of oxygen gas in order to determine the moles of lithium oxide that are created. Going by the stoichiometry of the reaction, 2.7 moles of lithium will produce 2 moles of lithium oxide when reacted with 0.675 moles of oxygen gas.

Therefore, the amount of lithium oxide generated can be calculated as follows, The formula is 2 moles Li₂O/0.675 moles O₂*1 = 5.93 moles Li₂O.

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The experiment looks into how temperature impacts how quickly magnesium metal reacts with hydrochloric acid. The creation of hydrogen gas over time is used to determine the dependent variable, which is the reaction rate.

The experiment can be run at various temperatures to change the experiment's independent variable, which is the reaction mixture's temperature. Higher temperatures cause molecules to move more quickly, increasing the likelihood of reactant collisions and kinetic energy. By enabling more successful collisions between magnesium atoms and hydrochloric acid, can quicken the reaction and increase the amount of hydrogen gas produced. In contrast, it is anticipated that the reaction rate will be slower at lower temperatures since there will be less molecular mobility and fewer successful collisions.

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--The complete Question is, What is the effect of temperature on the rate of reaction between hydrochloric acid and magnesium metal?

The dependent variable in this experiment is the rate of reaction, which can be measured by monitoring the production of hydrogen gas over time. The independent variable is the temperature of the reaction mixture, which can be controlled and varied by conducting the experiment at different temperatures.--

Fluorine (F-) is the element with the fewest valence electrons. Seven electrons make up the outermost shell of fluorine, and one of them is unpaired. As a result, fluorine possesses seven valence electrons altogether.

Eight valence electrons are present in magnesium (Mg2+), nine are present in gallium (Ga+), eight are present in argon (Ar+), four are present in carbon (C+), six are present in sulphur (S2-), and seven are present in fluorine (F-).

Fluorine has a lower number of valence electrons than the other elements because it has a greater effective nuclear charge. This indicates that the fluorine atom will take electrons away from its outermost shell since it is more attracted to electrons than the other elements.

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The right response is B. 103.5 g. The mole ratio of sodium to chloride is 1:1 according to the equation Na+ + Cl NaCl. Since 4.5 moles of chloride are provided, the equation requires 4.5 moles of sodium to be balanced. We must utilise the molar mass of sodium, which is 22.99 g/mol, to get the mass of sodium.

We obtain 103.5 g of sodium by multiplying 4.5 moles of sodium by 22.99 g/mol. The correct response is B. 103.5 g.

The equation requires 1 mole of sodium for every mole of chloride, giving 4.5 moles of sodium and 103.5 g.

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Answer:

3. d

4. c

5. i

6. h

7. a

8. g

9. j

10. b

11. e

12. f

Explanation:

In the reaction, 325 grams of iron(III) oxide would produce 227.36 grams of iron.

The balanced chemical equation for the reaction between iron(III) oxide and carbon monoxide to form iron and carbon dioxide is given as;

Fe₂O₃ + 3CO → 2Fe + 3CO₂

Molar mass of Fe₂O₃ is calculated as;

= 2 x 56 + 3 x 16

= 160 g/mol

Number of moles of 325 g of Fe₂O₃ = 325 g / 160 g/mol

= 2.03 moles

From the balanced reaction;

1 Fe₂O₃  -------- > 2 Fe

2.03 moles of Fe₂O₃  = ?

= 2 x 2.03 moles

= 4.06 moles

Molar mass of Fe = 56 g/mol

4.06 moles of Fe = ?

= 4.06 mol x 56 g/mol

= 227.36 g

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The complete question is below:

How many grams of iron would be produced by the reaction of 325 grams of iron(III) oxide and carbon monoxide?

The final temperature of the water is: T_final = 45.0°C

We can use the formula for the specific heat capacity of the water to solve this problem:

q = mcΔT

First, we can calculate the initial energy of the water:

q = mcΔT

q = (10.0 g) (4.184 J/g°C) (25.0°C)

q = 1,046 J

Next, we can calculate the final temperature after absorbing 840 J:

q = mcΔT

840 J = (10.0 g) (4.184 J/g°C) (ΔT)

ΔT = 20.0°C

Therefore, the final temperature of the water is:

T_final = T_initial + ΔT

T_final = 25.0°C + 20.0°C

T_final = 45.0°C

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Answer:Yes

Explanation:

Because Chinstrap penguins eat krills

The experiment looks into how temperature impacts how quickly magnesium metal reacts with hydrochloric acid. The creation of hydrogen gas over time is used to determine the dependent variable, which is the reaction rate.

The experiment can be run at various temperatures to change the experiment's independent variable, which is the reaction mixture's temperature. Higher temperatures cause molecules to move more quickly, increasing the likelihood of reactant collisions and kinetic energy. By enabling more successful collisions between magnesium atoms and hydrochloric acid, can quicken the reaction and increase the amount of hydrogen gas produced. In contrast, it is anticipated that the reaction rate will be slower at lower temperatures since there will be less molecular mobility and fewer successful collisions.

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--The complete Question is, What is the effect of temperature on the rate of reaction between hydrochloric acid and magnesium metal?

The dependent variable in this experiment is the rate of reaction, which can be measured by monitoring the production of hydrogen gas over time. The independent variable is the temperature of the reaction mixture, which can be controlled and varied by conducting the experiment at different temperatures.--

Answer:

radius = 16 in ; height = 27 in

The correct answer is (C) CO2 and H2O.

When C4H8 (butene) is burned, it reacts with oxygen (O2) from the air to form carbon dioxide (CO2) and water (H2O) as products. The balanced chemical equation for this reaction is:

C4H8 + 6O2 → 4CO2 + 4H2O

Therefore, the products formed when C4H8 is burned are carbon dioxide and water.

Correct answer is options b. An object is lifted to a certain height and then dropped. During the drop, kinetic energy is increased.

As the object is lifted to a certain height, its potential energy is increased due to its position in the Earth's gravitational field. When the object is dropped, it begins to move downward and its potential energy is gradually converted into kinetic energy, which is the energy of motion.

Therefore, the kinetic energy of the object is increasing during the drop.

However, the total mechanical energy of the object (which is the sum of its kinetic and potential energy) remains constant as long as there is no external work done on the system (i.e. no air resistance or friction).

This is known as the law of conservation of mechanical energy. Therefore, the total mechanical energy of the object is not increased during the drop.

So, the correct answer is (b) kinetic energy.

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The total amount of heat generated is 207.5 J, under the condition that the given sample possess 64.2-g sample of this substance with a specific heat of 50.6 J/(kg•°C).

The heat needed to change the temperature of a substance can be evaluated applying the given formula

q = m × c × ΔT

Here

q = energy added,

m = mass of the substance,

c = specific heat capacity of the substance

ΔT = change in temperature.

Then we can proceed by calculating the heat required to change its temperature from 180.0 °C to 244.0 °C by converting the mass of the substance from grams to kilograms

m = 64.2 g = 0.0642 kg

Then, we can evaluate the change in temperature

ΔT = (244.0 °C - 180.0 °C)

= 64.0 °C

Lastly, we can apply the formula above to evaluate the heat required

q = m × c × ΔT

= (0.0642 kg) × (50.6 J/(kg•°C)) × (64.0 °C)

= 207.5 J

Hence, 207.5 J of heat is required to change the temperature of this substance from 180.0 °C to 244.0 °C.

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The balanced chemical reaction for the production of the C₃H₈, the propane :

3C(s) + 4H₂(g) → C₃H₈(g)

The chemical equations are :

(a) C₂H₈(g)+5O₂(g) --> 3CO₂(g)+ 4H₂O(l)

(b) C(s) + O₂(g) --> CO₂(g)

(c) H₂(g) + 0.5O₂(g) --> H₂O(l)

On multiplying the reaction b by 3 we get :

3C(s) + 3O₂(g) → 3CO₂

On multiplying the reaction c by 4 we get :

4H₂(g) + 2O₂(g) → 4H₂O(l)

On adding the both the equation :

3C(s) + 4H₂(g) + 5O₂(g) → 3CO₂(g) + 4H₂O(l)

After subtracting the equation we get the balanced chemical equation and will produce the propane, C₃H₈(g), from the elements :

3C(s) + 4H₂(g) → C₃H₈(g)

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