what was the purpose of adding a huge excess of acetic anhydride in this experiment? draw the reaction scheme and mechanism.

Part A: If the solution is NaCl(aq), the chloride ion concentration is simply equal to the concentration of the NaCl. This is because NaCl dissociates completely in water to produce Na+ and Cl- ions. Therefore, the concentration of chloride ions is equal to the concentration of NaCl.

For example, if the concentration of NaCl is 0.10 M, then the chloride ion concentration is also 0.10 M.Part B: If the solution is FeCl3(aq), we need to consider the fact that FeCl3 dissociates into Fe3+ and Cl- ions. Therefore, we need to calculate the concentration of chloride ions from the concentration of FeCl3.

To do this, we need to use the stoichiometry of the reaction. Each formula unit of FeCl3 produces three chloride ions. Therefore, the concentration of chloride ions is three times the concentration of FeCl3.For example, if the concentration of FeCl3 is 0.10 M, then the chloride ion concentration is 3 × 0.10 M = 0.30 M.

In summary, the chloride ion concentration in a solution depends on the concentration of the salt and the degree of dissociation.

For a salt that dissociates completely, the concentration of chloride ions is equal to the concentration of the salt. For a salt that does not dissociate completely, we need to consider the stoichiometry of the reaction to determine the concentration of chloride ions.

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Answer:

gas is this: a substance (such as oxygen or hydrogen) that is like air and has no fixed shape. : a gas or mixture of gases that is burned as a fuel.

Explanation:

Gas is one of the four fundamental states of matter. A pure gas may be made up of individual atoms, elemental molecules made from one type of atom, or compound molecules made from a variety of atoms. A gas mixture, such as air, contains a variety of pure gases.

Given problem;

   (-7b + 8c) - (12a + 14) + (5a + 5b) = ?

 To this problem, we open the brackets, collect like terms and factor them.

The order of operation, PEMDAS must be strictly adhered to;

P = Parentheses

E = Exponent

M = multiplication

D = Division

A = Addition

S = Subtraction

(-7b + 8c) - (12a + 14) + (5a + 5b);

  Open the parentheses;

  Note;          + x +  = +

                      + x - = -

                      - x -  = +

                       - x + = -

So,

                     = -7b + 8c -12a - 14 + 5a + 5b

                  Collect like terms;

                     = 5a -12a + 5b - 7b + 8c -14

                     = -7a - 2b + 8c -14

The solution is -7a - 2b + 8c -14

Boiling point of the solution ≈ 100.9672°C

To determine the concentration of ethylene glycol in a solution of water in molality, we can use the equation:

ΔTf = kf * molality

Given that the freezing point dropped by 2.64°C and kf for water is 1.86°C/m, we can rearrange the equation to solve for molality:

molality = ΔTf / kf

Substituting the values, we get:

molality = 2.64°C / 1.86°C/m

molality ≈ 1.42 m

For the second question, to calculate the boiling point of the solution, we can use the equation:

ΔTb = kb * molality

Given that kb for water is 0.52°C/m, and the solution contains 10.0g of sodium chloride dissolved in 100.0g of water, we need to convert the masses to moles:

moles of sodium chloride = mass / molar mass
moles of sodium chloride = 10.0g / (22.99g/mol + 35.45g/mol) ≈ 0.186 mol

molality = moles of solute / mass of solvent (in kg)
molality = 0.186 mol / 0.1 kg = 1.86 m

Substituting the values into the equation, we get:

ΔTb = 0.52°C/m * 1.86 m

ΔTb ≈ 0.9672°C

The boiling point of the solution is the sum of the boiling point of pure water (100°C) and the ΔTb:

Boiling point of the solution = 100°C + 0.9672°C

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To solve this problem, we'll use the Beer-Lambert Law and the information given.

(a) According to the Beer-Lambert Law, the absorbance (A) is directly proportional to the concentration (c) of the absorbing species:

A = εlc

where A is the absorbance, ε is the molar absorptivity constant, l is the path length (in cm), and c is the concentration (in M).

Given:

Slope of the Beer's Law plot (εl) = 3.5 × [tex]10^3[/tex]

Absorbance (A) = 0.700

Since we have a 1 cm path length, the slope (εl) is equal to the molar absorptivity constant (ε).

Substituting the values into the equation, we can calculate the equilibrium concentrations:

ε = [tex]3.5*10^3 M^{(-1)} cm^{(-1)}[/tex]

A = 0.700

Using the Beer-Lambert Law equation, we can rearrange it to solve for the concentration (c):

c = A / (εl)

For Fe3+:

c(Fe3+) = A / (εl) = 0.700 / (3.5 × [tex]10^3[/tex]) = 2 ×[tex]10^{(-4)}[/tex] M

For SCN-:

c(SCN-) = A / (εl) = 0.700 / (3.5 × [tex]10^3[/tex]) = 2 × 1[tex]0^{(-4)}[/tex] M

For FeSCN2+:

Since FeSCN2+ is the product of the reaction between Fe3+ and SCN-, the concentration of FeSCN2+ at equilibrium will be zero until the reaction reaches equilibrium.

Therefore, the equilibrium concentrations are:

[Fe3+] = 2 × [tex]10^{(-4)}[/tex] M

[SCN-] = 2 × [tex]10^{(-4)}[/tex] M

[FeSCN2+] = 0 M

(b) To calculate the equilibrium constant (Keq), we'll use the equation:

Keq = ([FeSCN2+]) / ([Fe3+][SCN-])

Substituting the given values:

Keq = (0) / ([tex](2 * 10^{(-4)})^2[/tex]) = 0

Therefore, Keq is equal to 0.

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Answer:

Volume of gas  is 24.7×10⁴ L

Explanation:

Given data:

Moles of neon gas = 1.1×10⁴ mol

Temperature of gas = standard = 273 K

Pressure of gas = standard = 1 atm

Volume of gas = ?

Solution:

The given problem will be solve by using general gas equation,

PV = nRT

P= Pressure

V = volume

n = number of moles

R = general gas constant = 0.0821 atm.L/ mol.K  

T = temperature in kelvin

1 atm × V  = 1.1×10⁴ mol ×0.0821 atm.L/ mol.K  × 273 K

V = 24.7×10⁴ atm.L / 1 atm

V = 24.7×10⁴ L

Aligning the cuvet in the sample hold measurement er the same way each time is important to ensure that the optical windows are correctly positioned in the light path, allowing accurate of absorbance.

Both of the given statements are correct, and aligning the cuvet in the sample holder the same way each time is indeed important for accurate measurements in spectrophotometry.

1. Only two sides are transparent: Cuvets, or cuvette cells, are typically rectangular or square-shaped containers made of glass or plastic. They have two transparent sides, known as optical windows, through which light passes. The other sides are opaque. If the cuvet is placed incorrectly in the sample holder, such that the optical windows are not aligned with the light path, it will block or obstruct the passage of light, resulting in an incorrect measurement of absorbance. Consistent alignment ensures that the light passes through the cuvet properly and allows accurate determination of the absorbance of the sample.

2. Minimize the effect of imperfections: The glass or plastic material used to make cuvets may have minor imperfections, such as scratches or impurities. These imperfections can cause variations in the transmission of light through the cuvet. By aligning the cuvet in the same way each time, any effects caused by the imperfections can be minimized or averaged out, leading to more reliable and consistent results. In this way, consistent alignment helps to reduce potential errors or inconsistencies in the measurements caused by the cuvet itself.

In summary, aligning the cuvet in the sample holder the same way each time is important to ensure that the optical windows are correctly positioned in the light path, allowing accurate measurement of absorbance. Additionally, consistent alignment helps to minimize any effects caused by imperfections in the cuvet material, resulting in more reliable and consistent measurements.

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Answer:

First, let's determine how many moles of oxygen we have.

Atomic weight oxygen = 15.999

Molar mass O2 = 2*15.999 = 31.998 g/mol

We have 3 drops at 0.050 ml each for a total volume of 3*0.050ml = 0.150 ml

Since the density is 1.149 g/mol,

we have 1.149 g/ml * 0.150 ml = 0.17235 g of O2

Divide the number of grams by the molar mass to get the number of moles 0.17235 g / 31.998 g/mol = 0.005386274 mol

Now we can use the ideal gas law. The equation PV = nRT where P = pressure (1.0 atm) V = volume n = number of moles (0.005386274 mol) R = ideal gas constant (0.082057338 L*atm/(K*mol) ) T = Absolute temperature ( 30 + 273.15 = 303.15 K)

Now take the formula and solve for V, then substitute the known values and solve.

PV = nRT V = nRT/P V = 0.005386274 mol * 0.082057338 L*atm/(K*mol) * 303.15 K / 1.0 atm V = 0.000441983 L*atm/(K*) * 303.15 K / 1.0 atm V = 0.133987239 L*atm / 1.0 atm V = 0.133987239 L

So the volume (rounded to 3 significant figures) will be 134 ml.

The volume of the gas that will be produced in the person's stomach at body temperature (37°C) and a pressure of 1.0 atm is 48.36 mL

We'll begin by calculating the mass of the liquid oxygen. This can be obtained as follow:

Density = 1.149 g/mL

Volume = 0.053 mL

Mass = Density × Volume

Mass of O₂ = 1.149 × 0.053

Next, we shall determine the number of mole in 0.060897 g of O₂.

Mass of O₂ = 0.060897 g

Molar mass of O₂ = 2 × 16 = 32 g/mol

Mole of O₂ =?

Mole = mass / molar mass

Mole of O₂ = 0.060897 / 32

Finally, we shall determine the volume of the gas produced in the stomach. This can be obtained as follow:

Mole of O₂ (n) = 0.0019 mole

Temperature (T) = 37 °C = 37 + 273 = 310 K

Pressure (P) = 1 atm

Gas constant (R) = 0.0821 atm.L /Kmol

1 × V = 0.0019 × 0.0821 × 310

V = 0.04836 L

Multiply by 1000 to express in mL

V = 0.04836 × 1000

Therefore, the volume of the gas produced in the person's stomach is 48.36 mL

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Answer:

An alloy

Explanation:

srry if its wrong but i hope this helps!

Answer:

An alloy

Explanation:

Answer:

there should be around 41 moles

Answer: 39.99711 moles

At temperature of 100 °C, the vapor pressure of the aqueous solution of Ca(NO3)2 is approximately 1.002 atm.

To find the vapor pressure of an aqueous solution of Ca(NO3)2 at a given temperature, we can use the concept of boiling point elevation and the equation for the Clausius-Clapeyron equation. The boiling point elevation is related to the molality of the solution.

The equation for the boiling point elevation is:

ΔTb = Kbm

where ΔTb is the boiling point elevation, Kb is the molal boiling point elevation constant for the solvent (water), b is the molality of the solution, and m is the number of dissociated particles.

For Ca(NO3)2, it dissociates into three ions: Ca2+ and two NO3-. So, m = 3.

Given that the molality of the solution is 0.465 mol/kg and the boiling point elevation constant for water is approximately 0.512 °C/m, we can calculate the boiling point elevation as follows:

ΔTb = (0.512 °C/m) * (0.465 mol/kg) * (3)

ΔTb ≈ 0.710 °C

Now, we need to determine the new boiling point by adding the boiling point elevation to the normal boiling point of water, which is 100 °C:

New boiling point = 100 °C + 0.710 °C = 100.710 °C

Finally, using the Clausius-Clapeyron equation, we can calculate the vapor pressure of water at the new boiling point:

ln(P2/P1) = ΔHvap/R * (1/T1 - 1/T2)

Where P1 is the vapor pressure of water at the normal boiling point (1 atm), P2 is the vapor pressure of water at the new boiling point, ΔHvap is the enthalpy of vaporization of water, R is the ideal gas constant (0.0821 L·atm/(mol·K)), T1 is the absolute temperature at the normal boiling point, and T2 is the absolute temperature at the new boiling point.

Assuming ΔHvap is constant, we can simplify the equation to:

ln(P2/1) = ΔHvap/R * (1/373 K - 1/373.71 K)

Solving for P2:

P2/1 = e^(ΔHvap/R * (1/373 K - 1/373.71 K))

P2 ≈ 1.002 atm

Therefore, at a temperature of 100 °C, the vapor pressure of the aqueous solution of Ca(NO3)2 is approximately 1.002 atm.

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Answer:

It is 15N in that direction. When it's in the exact same direction, you combine them.

Explanation:

Answer:

4. they have the same number of protons

Explanation:

while all the other particles and attributes can be changed, protons cannot.

Answer:

[tex]\boxed {\tt 250 \ mL}[/tex]

Explanation:

First, let's remember that 1 cubic centimeter is equal to 1 milliliter.

We have a beaker that is 250 cubic centimeters. Since 1 cubic centimeter is equal to 1 milliliter,

The volume in a 250 cm³ beaker is 250 milliliters.

Answer:

a cubic centimeter is the same as a millimeter, so it would just be 250ml

Answer:

Since electromagnetic forces are responsible for regular chemical bonds, every chemical compound would dissolve. All life and all ordinary objects would cease to exist. I think your question would call on electrons and protons to cease to exist, since these particles are associated with the electromagnetic force.

Explanation:

The higher the pH value, the lower the acidity of the solution. This is observed when comparing the pH values of two solutions produced by the same concentration of ammonia (NH3) and ethylamine (C2H7N). C2H7N has a stronger basicity than NH3, leading to a higher pH value.

The higher the pH value, the lower the acidity of the solution. In other words, the solution's base is stronger. This will be observed when comparing the pH values of the two solutions produced by the same concentration of ammonia (NH3) and ethylamine (C2H7N). The Kb of NH3 is 1.8 x 10-5 m and the Kb of C2H7N is 5.1 x 10-4 m, respectively. It's worth noting that NH3 is weaker than C2H7N. This implies that the base of C2H7N is stronger than that of NH3. This will make the pH of the solution produced by C2H7N greater than that of the solution produced by NH3 at the same concentration.  C2H7N has a stronger basicity than NH3. As a result, a solution with a higher pH would be formed by the former. As we compare the pH values of the solutions produced by the two compounds, the solution produced by C2H7N would have a higher pH value than the solution produced by NH3 at the same concentration.

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Let us assume the balanced chemical equation of H2 and I2 forming HI is as follows: H2(g) + I2(g)  2HI(g) in the chemical reaction at equilibrium is said to be constant.

Hence, we can write the expression for the equilibrium constant (Kc) of the above chemical reaction as follows:

Kc = [HI]2 / [H2][I2] We know the concentration of HI is 6M, and we have to find out the molarity of H2 present. Now that we know the concentration of I2, we can use the expression above to solve for the molarity of H2. However, we don't have a concentration of I2.

Therefore, we must use the balanced chemical reaction to find the molarity of H2 as follows:

3H2(g) + 3I2(g) → 6HI(g) 2H2(g) + I2(g) → 2HI(g)

Since 2 mol of HI are formed from 1 mol of I2, if we use up all the I2, we will produce 4 mol of HI using 2 mol of H2. Therefore, we have:

2H2(g) + I2(g) → 4HI(g)At equilibrium, we have a total of 6 M of HI and 0.5 M of I2. Since I2 is a limiting reagent, we must use 0.5 M to solve for the molarity of H2 as follows:

2H2(g) + I2(g) → 4HI(g) 2x            0.5        4x x = 0.5 / 2 = 0.25 M

Therefore, the molarity of H2 is 0.25 M.

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Answer:

if I'm not mistaken, it is a mixture

It's a mixture my dude

Answer:

Most are made of copper.

Explanation:

Answer: The answer is metal

Explanation:

I took the test:) np!

2-chloro-3-methyl-2-butene exhibits three different ¹H NMR signals.

To determine the number of ¹H NMR signals exhibited by 2-chloro-3-methyl-2-butene, we need to analyze the different types of hydrogen (proton) environments in the molecule.

The structure of 2-chloro-3-methyl-2-butene can be represented as follows:

CH3-CH(Cl)-C(CH3)=CH2

Let's examine the different proton environments:

The methyl group (CH3) adjacent to the chlorine atom is chemically equivalent to the other methyl group attached to the double bond. These two methyl groups are part of the same functional group and should produce only one NMR signal. Therefore, we have one signal for these protons.

The hydrogen attached to the carbon adjacent to the chlorine atom is different from the other hydrogens in the molecule. This hydrogen is allylic to the double bond and exhibits different chemical shifts due to its proximity to the pi electrons. Thus, we have a separate signal for this hydrogen.

The hydrogens on the carbon atoms in the double bond are also chemically different from the rest of the hydrogens in the molecule. However, they are part of the same functional group and should produce only one NMR signal.

Taking all these proton environments into account, 2-chloro-3-methyl-2-butene exhibits a total of three ¹H NMR signals.

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Answer:

The right option is; an experimental investigation, because it allows for the control of variables.

Explanation:

The specific composition of oil-based paint can vary depending on the brand and formulation.

Oil-based paint typically consists of three main components: pigments, binders, and solvents. The pigments provide the color and opacity to the paint, while the binders are responsible for holding the pigment particles together and adhering them to the painted surface. The solvents help to adjust the paint's consistency and facilitate its application.

The binder in oil-based paint is commonly a natural oil, such as linseed oil or tung oil. These oils are composed of fatty acid molecules, which contain a long carbon chain with a carboxyl group (-COOH) at one end. The carboxyl group can react with oxygen in a process called oxidation, forming a cross-linked network of molecules that harden over time, creating a durable paint film.

The solvents in oil-based paint are typically organic compounds, such as mineral spirits or turpentine. These solvents dissolve the binder and pigments, making the paint flowable and easy to apply. As the solvent evaporates, the paint gradually dries and the binder undergoes the oxidation process, resulting in the formation of a solid paint film.

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The electron in sulfur that is most shielded from nuclear charge is an electron in a 3p orbital. As we move away from the nucleus, the energy level of the atom's electron orbitals increases, resulting in increased shielding from the nuclear charge. As a result, the 3p orbital electron is the most shielded from the nuclear charge in sulfur.

Sulfur is a nonmetal that is located in the periodic table's third row. It is represented by the symbol "S," and its atomic number is 16. Electrons are located in orbitals, or shells, around the nucleus of an atom. These orbitals have varying degrees of shielding from the atomic nucleus, which is influenced by the number of electrons in other orbitals and the distance from the nucleus. The 1s, 2s, 2p, 3s, 3p, 4s, 3d, 4p, and 5s orbitals are the electron orbitals in a sulfur atom.

Only three orbitals are considered for the electron shielding inquiry, which are the 1s, 2p, and 3p orbitals. The 1s orbital electron is closer to the nucleus than the 2p and 3p orbital electrons, implying that it is less shielded from the nuclear charge. Electrons in the 2p and 3p orbitals are farther from the nucleus than electrons in the 1s orbital, indicating that they are more shielded from the nuclear charge. As a result, the electron in a 3p orbital in sulfur is the most shielded from nuclear charge.

In sulfur, the electron in a 3p orbital is the most shielded from the nuclear charge since the 3p orbital electron is farther from the nucleus than the 1s orbital electron.

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a) pH is approximately 13.10. b) pH will be slightly above 7, indicating a basic solution. c) pH will be higher than the pH at the equivalence point, further indicating a basic solution.

(a) When 40.0 mL of base (0.200 M sodium hydroxide) has been added to the 40.0 mL of 0.250 M acetic acid, we have a neutralization reaction between the acid and base. Acetic acid (CH3COOH) is a weak acid, and sodium hydroxide (NaOH) is a strong base.

To calculate the pH at this point, we need to determine the moles of acid and base present and determine the excess or deficit of either. Since acetic acid and sodium hydroxide react in a 1:1 ratio, the moles of acid are equal to the moles of base added.

Using the formula:

Moles = Volume (L) x Concentration (M)

The moles of acetic acid are:

Moles of acetic acid = 0.040 L x 0.250 mol/L = 0.010 mol

Since the moles of acetic acid and sodium hydroxide are equal, we have 0.010 mol of sodium hydroxide in 0.040 L.

To calculate the concentration of hydroxide ions, we divide the moles of sodium hydroxide by the total volume (80.0 mL or 0.080 L):

Concentration of OH- = 0.010 mol / 0.080 L = 0.125 M

Using the equation for the dissociation of water (Kw = [H+][OH-]), we can calculate the concentration of H+ ions:

Kw = [H+][OH-]

1.0 x 10^-14 = [H+][0.125]

[H+] = 8.0 x 10^-14 M

Taking the negative logarithm of the concentration of H+ ions gives us the pH:

pH = -log[H+] = -log(8.0 x 10^-14) ≈ 13.10

(b) When 50.0 mL of base has been added, the calculation follows a similar process. The moles of acetic acid remain the same (0.010 mol), but the moles of sodium hydroxide increase to 0.0125 mol due to the additional volume (50.0 mL or 0.050 L) of base added.

Using the formula:

Moles = Volume (L) x Concentration (M)

The moles of sodium hydroxide are:

Moles of sodium hydroxide = 0.050 L x 0.200 mol/L = 0.010 mol

Since the moles of acetic acid and sodium hydroxide are equal (0.010 mol), we have reached the equivalence point of the titration. At the equivalence point, all the acetic acid has been neutralized by the sodium hydroxide, resulting in a solution of sodium acetate (CH3COONa) and water.

The pH at the equivalence point depends on the nature of the resulting salt, sodium acetate. Sodium acetate is the conjugate base of a weak acid, acetic acid, and is a weak base. The hydrolysis of sodium acetate in water leads to the formation of hydroxide ions, resulting in a slightly basic solution.

Therefore, at the equivalence point, the pH will be slightly above 7, indicating a basic solution.

(c) When 60.0 mL of base has been added, the calculation follows the same process as in part (b). At this point, the moles of sodium hydroxide are greater than the moles of acetic acid.

Using the formula:

Moles = Volume (L) x Concentration (M)

The moles of sodium hydroxide are:

Moles of sodium hydroxide = 0.060 L x 0.200 mol/L = 0.012 mol

Since the moles of sodium hydroxide (0.012 mol) are greater than the moles of acetic acid (0.010 mol), there is an excess of base present in the solution.

The excess base, sodium hydroxide, will result in a basic solution. The pH will be higher than at the equivalence point, indicating a stronger basic character.

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The molecular formula of all the compounds is C9H18O2. The spectral data helps to differentiate the compounds. The spectral data reveals the carbon environment of each atom of the molecule.

The structure of a molecule can be predicted by analyzing NMR spectra and the type of carbon atom in the molecule by analyzing 13C NMR spectra.The NMR spectrum for Compound B shows a peak at δ 2.2, indicating the presence of an -CH2- group. In the 13C NMR spectrum for Compound B, a peak appears at δ 30.3, indicating the presence of a carbon atom with two hydrogens attached. In the molecule of Compound B, the only carbon atom with two hydrogens attached is the one that is part of the -CH2- group. As a result, Compound B is made up of a straight-chain carbon chain with a terminal carboxyl group and a single methyl group attached to the 3rd carbon atom.The NMR spectrum for Compound A shows peaks at δ 1.6, 2.3, and 2.8, indicating the presence of an -CH3 group, a -CH2- group, and a -CH- group, respectively. In the 13C NMR spectrum for Compound A, peaks appear at δ 15.3, 22.8, and 28.5, indicating the presence of three carbon atoms with one hydrogen each. In the molecule of Compound A, the carbon atoms with one hydrogen each are the three carbon atoms that make up the -CH3 group, the -CH2- group, and the -CH- group. As a result, Compound A is made up of a branched carbon chain with a terminal carboxyl group and a single methyl group attached to the 4th carbon atom.

Compound A is made up of a branched carbon chain with a terminal carboxyl group and a single methyl group attached to the 4th carbon atom. Compound B is made up of a straight-chain carbon chain with a terminal carboxyl group and a single methyl group attached to the 3rd carbon atom. Therefore, the NMR and 13C NMR spectra are consistent with Compounds A and B, respectively, and their molecular formulas are C9H18O2.

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Answer:

Explanation:

To find the number of moles given it's number of entities we use the formula

[tex]n = \frac{N}{L} \\[/tex]

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question

N = 2.8 × 10²⁴ atoms of Cl2

So we have

[tex]n = \frac{2.8 \times {10}^{24} }{6.02 \times {10}^{23} } \\ = 4.65116279069...[/tex]

We have the final answer as

Hope this helps you

Answer:

Cerium

Explanation:

the mole fraction of dinitrogen difluoride (N2F2) is approximately 0.584, and the mole fraction of boron trifluoride (BF3) is approximately 0.416.

To calculate the mole fraction of each gas in the tank, we need to determine the number of moles of each gas and then calculate the mole fraction using the following formula:

Mole fraction = Moles of a gas / Total moles of all gases

Given:

Amount of dinitrogen difluoride gas (N2F2) = 0.045 mol

Amount of boron trifluoride gas (BF3) = 0.032 mol

Total moles of all gases = 0.045 mol + 0.032 mol = 0.077 mol

Mole fraction of dinitrogen difluoride (N2F2):

Mole fraction of N2F2 = 0.045 mol / 0.077 mol = 0.584 (rounded to three significant digits)

Mole fraction of boron trifluoride (BF3):

Mole fraction of BF3 = 0.032 mol / 0.077 mol = 0.416 (rounded to three significant digits)

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Answer:

True

Explanation:

the atoms never stop moving, so the answer is true