Given:
The amount of gravity produced by the Sun was reduced to almost zero.
To find:
What would happen to the orbits of the planets
Explanation:
The centripetal force for the rotation of every planet is supplied by the gravitational force between the sun and the planet. If the gravitational force by the sum becomes zero, the planets would begin moving away from their usual path into space.
Hence, the planets would abandon their orbit and move out into space.
When conditions are difficult bacteria make new bacteria this way?A.Mitosis B. Binary fission C. Lytic cycleD. Cell cycle E. Conjunction
The situations are difficult for bacteria to make new micro organism this manner is Binary fission. alternative B.
Resistant infections are hard and from time to time not possible to deal with. Antimicrobial resistance is a clearly occurring process. however, the boom in antimicrobial resistance is resulting from a aggregate of antibiotic and antifungal publicity to micro organism and their spread and resistance mechanisms.
when resistant lines multiply they produce genetically equal copies. All of those copies are proof against antibiotics. There are two major methods that bacterial cells acquire antibiotic resistance. One is because of New bacteria mutations that arise inside the mobile's DNA during replication. every other manner bacteria accumulate resistance is through horizontal gene switch.
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With what angular speed, in rad/s, does the Earth rotate about its axis?
We know that it takes the earth approcimately 24 hours to complete one rotations about its axis.
This means that we can calcuate the angular speed using the following formula:
[tex]\omega=\frac{\theta}{t}[/tex]Where:
[tex]\begin{gathered} \theta=\text{ angle in radians} \\ t=\text{ time} \end{gathered}[/tex]We will convert the time from hours to second using the following conversion factor:
[tex]1h=3600s[/tex]Now, we mutiply noth sides by 24 and we get:
[tex][/tex]Which path in the figure below would the ball most closely follow after it exits the channel at "y" and moves across the frictionless table top?(B)OBOf(C)*(D)(E)
Answer:
(B)
Explanation:
When an object ends a circular path, the next path is tangential to the circular path, in this case, the tangential path is (B), so the ball most closely follow path (B).
A person bikes 15 km south then 3km east what the displacement
Given data
*A person bikes towards the south is u = 15 km
*Also it covers the distance towards the east is v = 3 km
The formula for the displacement is given as
[tex]s=\sqrt[]{u^2+v^2}[/tex]Substitute the known values in the above expression as
[tex]\begin{gathered} s=\sqrt[]{(15)^2+(3)^2} \\ =\sqrt[]{234} \\ =15.29\text{ Km} \end{gathered}[/tex]Hence, the displacement is s = 15.29 km
A storage tank 20 m high is filled with pure water. (Assume the tank is open and exposed to the atmosphere at the top.)
(a) Find the gauge pressure at the bottom of the tank.
(b) Calculate the magnitude of the net force that acts on a square access hatch at the bottom of the tank that measures 0.6 m by 0.6 m.
PLEASE HELP ASAP!!!
A. The overpressure at the bottom of the tank is 297500 N/m².
B. The magnitude of the net force acting on the square access hatch at the bottom of the tank is 107100 N.
Multiplying the flow rate by the minimum operating time of the pump gives the descending capacity. As a rule of thumb for a minimum run time, a pump operating at 10 gallons per minute GPM or less should produce a run time of 1 gallon per minute. For example, 10 GPM flow rate x 1 = 10 gallon drawdown capacity.
This means that the gauge pressure is equal to the absolute pressure minus the atmospheric ambient pressure. If the absolute pressure is greater than the atmospheric pressure it is called positive overpressure. If the absolute pressure is lower than atmospheric pressure it is called negative overpressure. The hydrostatic pressure at any height below water is calculated by P = hdg. where h is the height below open water.
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A vector A has components Ax = −5.50 m and Ay = 7.50 m. Find the magnitude (in m) and the direction (in degrees counterclockwise from the +x-axis) of the vector.magnitude mdirection ° counterclockwise from the +x-axis
The x-component of vector A is Ax = -5.50 m
The y-component of vector A is Ay = 7.50 m
We are asked to find the magnitude and the direction of the vector (counterclockwise from the +x-axis)
The magnitude of vector A is given by
[tex]\begin{gathered} |A|=\sqrt[]{A_x+A_y} \\ |A|=\sqrt[]{(-5.50)^2+(7.50)^2_{}} \\ |A|=\sqrt[]{30.25+56.25} \\ |A|=\sqrt[]{86.50} \\ |A|=9.3\; m \end{gathered}[/tex]So, the magnitude of vector A is 9.3 m
First, let us draw a diagram to better understand the problem.
The direction of vector A is given by
[tex]\begin{gathered} \tan \theta=\frac{A_y}{A_x} \\ \tan \theta=\frac{7.50}{-5.50} \\ \theta=\tan ^{-1}(\frac{7.50}{-5.50}) \\ \theta=-53.75\degree \end{gathered}[/tex]From the diagram, notice that θ lies in the second quadrant.
So, the counterclockwise direction from the positive x-axis is given by
[tex]180\degree-53.75\degree=126.25\degree[/tex]So, the direction is 126.25° counterclockwise from the +x-axis.
A puck of mass m = 0.065 kg is moving in a circle on a horizontal frictionless surface. It is held in its path by a massless string of length L = 0.65 m. The puck makes one revolution every t = 0.55 s. what is the magnitude of the tension in the string while the pack is revolving?if the string breaks how fast will the pack move away?
The centripetal acceleration of an object in circular motion with tangential velocity v if the radius of the trajectory is r, is:
[tex]a_c=\frac{v^2}{r}[/tex]On the other hand, if the period of one revolution is T, then the distance traveled is 2πr (which is the circumference of the trajectory) and the tangential velocity is:
[tex]v=\frac{2\pi r}{T}[/tex]In this case, the radius of the trajectory is the length of the string, 0.65m, and the period is T=0.55s. Substitute these data into the formula to find v:
[tex]v=\frac{2\pi(0.65m)}{0.55s}=7.4256\frac{m}{s}[/tex]Plug in v=7.4256m/s and r=0.65m to find the centripetal acceleration of the puck:
[tex]a_c=\frac{(7.4256\frac{m}{s})^2}{0.65m}=84.83\frac{m}{s^2}[/tex]According to Newton's Second Law of Motion, there must be a net force acting on the object responsible for the centripetal acceleration. That force F is the tension of the string. Then:
[tex]F=m\cdot a_c[/tex]Substitute the value for a and m=0.065kg to find the tension of the string:
[tex]\begin{gathered} F=0.065\operatorname{kg}\times84.83\frac{m}{s^2} \\ =5.51N \end{gathered}[/tex]If the string breaks, the puck will move as fast as its tangential velocity, which is 7.4 m/s.
Therefore, the answers are:
Tension in the string: 5.51N
Speed of the puck if the string breaks: 7.43 m/s
Ernest Rutherford's experiment of aiming a beam of alpha particles at a sheet of gold foil led to the discovery of the? A. protonB. quarkC. nucleusD. electron
To find
Ernest Rutherford's experiment of aiming a beam of alpha particles at a sheet of gold foil led to the discovery of the?
Explanation
It discovered the nucleus
Conclusion
The answer is
C.nucleus
Which picture correctly shows the path of the reflected light ray given an object inside the focal point?
The reflective surface of a concave mirror is curved inward and away from the light source. Concave mirrors focus light inward to a single focal point.
picture B correctly shows the path of the reflected light ray given an object inside the focal point.
What is concave mirror?The reflective surface of a concave mirror is curved inward and away from the light source. Concave mirrors focus light inward to a single focal point. In contrast to convex mirrors, the image formed by a concave mirror changes depending on the distance between the object and the mirror.Concave mirrors are widely used as reflectors in automobile and motor vehicle headlights, torchlights, railway engines, and so on. The light source is placed at the focal point of the mirror, so that after reflection, the light rays travel over a large distance as parallel high-intensity light beams.To learn more about : Concave mirrors
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Science AssignmentQuestion: Give 20 example each on scalar & vector quantities...
Scalar: Temperature, mass, distance, time, speed, volume, area, voltage, current, resistance, work, density, energy, amount of substance, luminous intensity, area density, chemical potential, electric current density, capacitance, inductance.
Vector: Displacement, velocity, acceleration, force, position, eletric field, magnetic field, linear momentum, angular momentum, torque, angular velocity, angular acceleration, electric field density, magnetic field density, roll, pitch, yaw, surge, sway, heave.
A 150-pound person uses 6.2 calories per minute when walking at a speed of 4 mph. How long must a person walk at this speed to use at least 230 calories?
The time taken by person to use 6.2 calories is 1 min.
Therefore, the time taken to use 230 calories can be calculated as,
[tex]\begin{gathered} t=\frac{(230\text{ calories)(1 min)}}{(6.2\text{ calories)}} \\ \approx37.1\text{ min} \end{gathered}[/tex]Thus, the time taken to use 230 calories is 37.1 min.
please help me with this homework question I really need help I have till tomorrow to do it
Relate scientific theories to the law of parsimony
In science, the law of parsimony is used to select between related scientific theories to those that contain a minor number of assumptions.
What is the law of parsimony?The law of parsimony is a well-sustained body of information that shows how the theories that contain a minor number of assumptions before experimentation are generally the correct ones.
Therefore, with this information, we can conclude that the law of parsimony can be used to select scientific theories and this approach is generally accurate to obtain the correct theory to be used due to assumptions that may hamper the scientific results.
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A large truck with mass 30 m crashes into a
small sedan with mass m. If the truck exerts a
force F on the sedan, what force will the
sedan exert on the truck?
A. F
B. 2F
C. F/30
D. 30F
Option A. F . The force will be the same as the large truck exerts on the small sedan but in opposite direction. according to Newton's third law of motion.
In physics, a force is an influence that can exchange the motion of an item. A pressure can cause an item with mass to trade its velocity, i.e., to boost up. pressure can also be defined intuitively as a push or a pull. A pressure has both significance and course, making it a vector quantity.
The word 'Force' has a specific which means. At this stage, it is completely suitable to describe a force as a push or a pull. Pressure isn't something that an object consists of or 'has in it. Pressure is exerted on one item with the aid of every other. The idea of a force isn't always restrained to living matters or non-living things.
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You are asked to find the volume of a cube that is 6.50 m long and 8.45m
wide and 7.00 m in height. Calculate the volume. How many significant
figures should you show in your answer?
Answer:
384.475 m³
6 significant figures
Explanation:
Volume of a cube is l x w x h where l- length, w = width, h = height
Volume of given cube = 6.5 x 8.45 x 7 = 384.475 m³
6 significant figures
Bone has a Young's modulus of about1.8 x 10^10 Pa. Under compression, it canwithstand a stress of about 1.69 x 10^8 Pa be-fore breakingAssume that a femur (thigh bone) is 0.49 mlong, and calculate the amount of compressionthis bone can withstand before breaking.Answer in units of mm.
Answer:
4.6 mm
Explanation:
The Young's Modulus is defined as
[tex]Y=P\frac{L_0}{\Delta L}[/tex]Where
Y = Young's Modulus
P = pressure (stress) applied
L0 = inital length
ΔL = change in length
Now in our case, we know that the femur is 0.49 m long (L0 = 0.49) and it can withstand max stress of 1.69 x 10^8 Pa ( P = 1.69 x 10^8 Pa), and Young's Modulus for the bone is 1.8 x 10^10 Pa ( Y = 1.8 x 10^10 Pa ); therefore, the above formula gives
[tex]1.8\times10^{10}=1.69\times10^8\times\frac{0.49}{\Delta L}[/tex]We have to solve the above equation for ΔL, the amount of compression.
Multiplying both sides by ΔL gives
[tex]\Delta L\times1.8\times10^{10}=1.69\times10^8\times0.49[/tex]dividing both sides by 1.8 x 10^10 gives
[tex]\Delta L=\frac{1.69\times10^8\times0.49}{1.8\times10^{10}}[/tex]which we evaluate to get
[tex]\Delta L=\frac{1.69\times0.49}{1.8}\times\frac{10^8}{10^{10}}[/tex][tex]\begin{gathered} \Delta L=4.6\times10^{-3}m \\ \boxed{\Delta L=4.6\; mm\text{.}} \end{gathered}[/tex]Hence, the amount of compression a femur can withstand is 4.6 x 10^-3 m or 4.6 mm.
Is nuclear energy apart of physics ?
Yes, the nuclear energy is a part of physics
Nuclear energy:
It basically originates from the splitting of uranium atoms. This is basically done by the process of fission. It is the energy that is released in significant amounts in processes that affect atomic nuclei, the dense cores of atoms
Find the answer to the problem
Box accelerates at a rate of 3.46 m/s.
How does acceleration work?Acceleration is the rate at which velocity changes over time in both the direction and the speed. Anything is said to have been accelerated when it goes faster or slower in a straight line. Even travel on a circle accelerates steadily since the direction is continuously changing.
What metrics are used to quantify acceleration?meters per second per second (m/s2).
Formula,
F NET = m, F NET = F1 + F2, etc.
F NET equals 33 + 3 = 36 .
Then,
a = F NET/m, where F NET = m. a
a = 36 /10.4
a = 3.46 m/s.
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What is the extension force (in lbf) of a 5 inch diameter cylinder with a pressure of 200psi?
The area of the cylinder can be given as,
[tex]A=\pi(\frac{d}{2})^2[/tex]Substitute the known value,
[tex]\begin{gathered} A=(3.14)(\frac{5\text{ in}}{2})^2 \\ =19.625in^2 \end{gathered}[/tex]The extension force acting on the cylinder is,
[tex]F=PA[/tex]Substitute the known values,
[tex]\begin{gathered} F=(200psi)(19.625in^2)(\frac{1\text{ lbf}}{1psiin^2})_{} \\ =3925\text{ lbf} \end{gathered}[/tex]Thus, the force exerted on the cylinder is 3925 lbf.
Can you give me the answers with being very organized Ans just explain goood
Explanation
the equation is base ond the Pythagorean theorem,it states that the sum of the squares on the legs of a right triangle is equal to the square on the hypotenuse (the side opposite the right angle)
[tex]a^2+b^2=c^2[/tex]so,
Step 1
if
[tex]undefined[/tex]A particle changed q= 3,10x10^-6 C stays still on point P, a second particle with the same value q and a mass of 1,80x10^-2 kg is initially in repose at a distance of r1 = 9,00 cm from point P. This is second particle is released and repelled by the first. Determine the velocity in which this second particle finds itself at a distance r2 = 25,0 cm from point P.
note 1: from what i know i have to use the potential energy formula (U= mV^2/2), and possible calculate the electric force ? but from there i get lost
note 2: sorry if this isn't grammatically correct, i translated it from spanish
The velocity in which this second particle finds itself at a distance r2 = 25,0 cm from point P is 17.22 m/s.
What is the electric force between the two particles?The electric force between the two particles is calculated from Coulomb's law of electrostatic force.
F = kq₁q₂/r²
where;
k is Coulomb's constantq₁ is magnitude of first chargeq₂ is magnitude of second charger is the distance between the two chargesF = (9 x 10⁹ x 3.10 x 10⁻⁶ x 3.10 x 10⁻⁶) / (0.09 m)²
F = 10.68 N
The velocity in which this second particle finds itself at a distance r2 = 25,0 cm from point P is calculated by applying the principle of conservation of energy.
W = ΔK.E
where;
W is work doneΔK.E is kinetic energy of the particleFr = ¹/₂mv²
2Fr = mv²
v² = 2Fr/m
v = √(2Fr/m)
v = √(2 x 10.68 x 0.25 / 1.8 x 10⁻²)
v = 17.22 m/s
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The star Wolf-359 is located 7.85 light-years away from Earth.
Which statement is therefore true about Wolf-359?
Responses
Wolf-359 produced its maximum amount of light 7.85 years ago.
It would take 7.85 years to travel from the earth to Wolf-359.
It takes light from Wolf-359 7.85 years to reach the earth.
The star Wolf-359 was born 7.85 years ago.
The statement that is therefore true about the star Wolf-359 is that it takes light from Wolf-359 7.85 years to reach the earth.
A light year is a measure of distance. It can simply be defined as the distance covered by a light wave in one Earth year. Light travels at a speed of about 300000 km / s.
Since the star Wolf-359 is located 7.85 light-years away from Earth, any light wave emitted by the star Wolf-359 would take 7.85 years to reach Earth and we could see the light wave only after 7.85 years from when the light was emitted.
Therefore, the statement that is therefore true about Wolf-359 is that it takes light from Wolf-359 7.85 years to reach the earth.
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Place the red, 100 g ball at the 60 cm mark on the ramp. How far did the box move? a90 cm b0cm cno more that 100 cm
Answer:
place it on the 50 cm mark
From which of the following motions is the displacement of the object different from the distance traveled?
A.) An infant..
The motions where the object's displacement is different than the distance traveled is option a. After a home run, a baseball player runs all the way around the bases.
What does displacement mean?An object's position changes if it moves in relation to a reference frame, such as when a passenger moves to the back of an airplane or a lecturer moves to the right in relation to a whiteboard. Displacement describes this shift in location.
Therefore, The term "displacement" refers to a shift in an object's position. It is a vector quantity with a magnitude and direction. The symbol for it is an arrow pointing from the initial location to the ending place. For instance, if an object shifts from location A to position B, its position changes.
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See full question below
For which one of the following motions is the object's displacement different than the distance traveled?
a. After a home run, a baseball player runs all the way around the bases.
b. A car accelerates from rest to a high speed.
c. A buggy car moves across the floor at a constant speed.
Draw a supply graph for pizzas. Show what would happen to the supply of pizzas if two more pizzerias open up in town. Identify the determinant of supply that caused the shift.
Pizza delivery when two more pizzerias in the city start changing their product prices.
All other things being equal an increase in demand will increase the equilibrium price. You will have more to deliver. A decrease in demand leads to a decrease in the equilibrium price. Less quantity to deliver. An increasing change in supply shifts the supply curve to the right, and a decreasing change in supply shifts the supply curve to the left.
Essentially it is an increase or decrease in quantity offered with a higher or lower offer price. As the price of pizza slices rises consumers are more likely to purchase one of these alternatives as a replacement for pizza. This reduces the amount of pizza requested. Higher prices tend to increase supply as more profits are made available.
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A wave is represented by the equation y=0.5sin 0.4π(x-60t) where the distance x is measured in cm and time(t) in seconds. what is the wave length of the wave,amplitude and frequency
The amplitude = 0.5 m
The wavelength = 5 m
The frequency = 12 Hz
Explanation:The given wave function is:
y=0.5sin 0.4π(x-60t)
This can be rewritten as:
y=0.5sin (0.4πx-24πt)................(1)
Comparing the equation above with the general wave function:
y = A sin(kx - wt).................(2)
where A represents the amplitude
k represents the wave number
w represents the angular frequency
By comparing equations (1) and (2):
the amplitude, A = 0.5 m
k = 0.4π
Also k = 2π/λ
0.4π = 2π/λ
λ = 2π/0.4π
λ = 5 m
The wavelength = 5 m
w = 24π
Also, w = 2πf
Therefore, 2πf = 24π
f = 24π/2π
f = 12 Hz
The frequency = 12 Hz
28 cubic inches of a gas with an absolute pressure of 35 psi is compressed to a volume of 5 cu.in, what is the new pressure of the gas. (Assume that there's no change in temperature.
First, we will write the formula we will be using: the Ideal gas law
[tex]PV=nRT[/tex]Now, let's see what is given to us
Volume: 28 Cubic Inches
Pressure: 35 PSI
New Volume: 5 cubic inches
New Pressure?
No change in temperature
Since we know that only the volume is changing, we can simplify the ideal gas law into Boyle's law
[tex]P_1V_1=P_2V_2[/tex]So now, we can subsititute in the values we got.
(28)(35) = 5(P2)
P2 = 196 PSI
A Petrol flows at 4m/a through a hose of 10mm diameter. What nozzle diameter will dispense it at the rate of 16m/s?
1cm of the nozzle Diameter will dispense it at the rate of 16m/s.
The continuity equation is what.
A continuity equation, sometimes referred to as a transport equation, is an equation that describes the movement of a certain quantity.
Although it can be applied generally to any significant quantity, it is extremely simple and useful when used with preserved quantities. Continuity equations can be used to explain a variety of physical processes since, under the right conditions, mass, energy, momentum, electric charge, and other natural quantities all remain constant.
From the continuity formula: A 1 V 1 = A 2 V 2.
π(1) 2 ×1=4×πr^ 2 ⇒ 41 =r 2 ⇒r= 21 cm
Thus, the nozzle's diameter is 21 2 cm, or 1 cm.
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Given a circuit consisting of a DC battery connected to a single resistor of resistance 16.0 ohms. If the electric current through the resistor is 5.00 Amperes, then which of these is the voltage of the battery in SI units?A)0.00625B)80C)0.00417D)240E)0.00313
Given:
The resistance in the circuit is R = 16 ohm
The current in the circuit is I = 5 A.
To find the voltage in the circuit.
Explanation:
The voltage in the circuit can be calculated using Ohm's law,
[tex]\begin{gathered} V=5\times16 \\ =80\text{ V} \end{gathered}[/tex]Final Answer: The voltage in the circuit is 80 V.
options are 1183420 J730,575 J-452,845 J1183420 Ek730575 Ek-452,845452,845 J-730,575 J-118342p J
Given:
The initial speed of car is: u = 140 km/h = 140 × 5/18 m/s= 38.889 m/s
The final speed of the car is: v = 110 km/h = 110 × 5/18 m/s = 30.5556 m/s
The mass of the car is: m = 1565 kg
To find:
A) Initial kinetic energy of the car.
B) The final kinetic energy of the car.
C) Work done during the deceleration.
Explanation:
A) The initial kinetic energy of the car can be calculated as:
[tex]KE_i=\frac{1}{2}mu^2[/tex]Substituting the values in the above equation, we get:
[tex]\begin{gathered} KE_i=\frac{1}{2}\times1565\text{ kg}\times(38.889\text{ m/s})^2 \\ \\ KE_i=1183417.27\text{ J} \end{gathered}[/tex]The value of initial kinetic energy is very close to the value 1183420 J given in the options. Thus, the initial kinetic energy of the car is 1183420 J.
B) The final kinetic energy of the car can be calculated as:
[tex]KE_f=\frac{1}{2}mv^2[/tex]Substituting the values in the above equations, we get:
[tex]\begin{gathered} KE_f=\frac{1}{2}\times1565\text{ kg}\times(30.5556\text{ m/s})^2 \\ \\ KE_f=730576.971\text{ J} \end{gathered}[/tex]The value of final kinetic energy is very close to the value 730575 J given in the options. Thus, the final kinetic energy of the car is 730576 J.
C) The work done in the deceleration of the car is calculated by applying the work energy theorem. Thus, we get:
[tex]\begin{gathered} W=KE_f-KE_i \\ \\ W=730575\text{ J}-1183420\text{ J} \\ \\ W=-452845\text{ J} \end{gathered}[/tex]The work done in the deceleration of the car is -452845 J. The work done is negative because the car is decelerating.
Final answer:
A) The initial kinetic energy of the car is 1183420 J.
B) The final kinetic energy of the car is 730575 J.
C) The work done in decelerating the car is -452845 J.
Johnny and Francis are participating in the Roller Skating dance championship. While 73.0-kg Johnny roller skates backwards at 3.0 m/s, 57.0-kg Francis jumps into his arms with a velocity of 5.0 m/s in the same direction. How fast do they roll backwards together?
Given,
The mass of Johnny, m₁=73.0 kg
The mass of Francis, m₂=57.0 kg
The initial velocity of Johnny, u₁=3.0 m/s
The initial velocity of Francis, u₂=5.0 m/s
From the law of conservation of momentum, the total momentum of a system will always remain the same.
Therefore,
[tex]m_1u_1+m_2u_2=(m_1+m_2)v[/tex]Where v is the velocity with which they roll backward together.
On substituting the known values in the above equation,
[tex]\begin{gathered} 73.0\times3.0+57.0+5.0=(73.0+57.0)v \\ v=\frac{219+285}{130} \\ =3.88\text{ m/s} \end{gathered}[/tex]Thus the velocity with which they roll backward together is 3.88 m/s
