Please answer this quick!
The forces among the positive protons in the nucleus of an atom are all repulsive, so we would expect the nucleus to fly apart. The
reason all the nuclei in your body are not spontaneously exploding at this moment is that there is an attractive force in action. This
force acts between neutrons and protons and does not influence chemical reactions. Which force is responsible for this
phenomenon?
A. gravitational force
B. weak nuclear force
C. electrostatic force
D. strong nuclear force
Strong nuclear force acts between neutrons and protons and does not influence chemical reactions, so nuclei in your body are not spontaneously exploding, hence option D is correct.
What is nuclear force?The nuclear force is a kind of force that acts between the protons and neutrons of atoms. Neutrons and protons, both nucleons, are influenced by the nuclear force almost equally.
It is the force that binds neutrons and protons together and does not allow them to fly apart. This force can act between neutrons and protons, protons and protons, and neutrons and neutrons.
Therefore, strong nuclear force is responsible for this phenomenon.
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If you are told that an object that weighs 20 Newtons is raised a distance of 10 meters, you know that the force of gravity on the object is 20 Newtons. True/False?
The statement; "If you are told that an object that weighs 20 Newtons is raised a distance of 10 meters, you know that the force of gravity on the object is 20 Newtons." is false
What is the force of gravity?The force of gravity is the force that attracts two objects towards each other. It is the force that keeps planets in orbit around the sun, holds the moon in orbit around the Earth, and keeps objects on the Earth's surface.
The force of gravity is proportional to the mass of the objects and the distance between them, and it decreases as the distance between the objects increases.
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a planet is attracted to the sun with a certain force. if the distance from the sun to the planet is reduced by one half, what would happen to the force?
The correct option is B, the distance between mass reduces to half then gravitation force increases by four times.
According to newton's law of gravitation,
Force between two masses F = GMm / r^2
If distance is halved r = r/2
F' = GMm / (r / 2)^2 = 4GMm / r^2 = 4F
Gravitation force is a fundamental force of nature that exists between any two objects with mass. This force is responsible for keeping objects like planets, stars, and galaxies in motion, and is essential for the formation and stability of the universe. The force of gravity is proportional to the mass of the objects and the distance between them, according to the famous equation proposed by Sir Isaac Newton: F = G(m1m2)/d^2.
The force of gravity is an attractive force, meaning it pulls objects towards each other. This force is why objects fall to the ground when dropped and why planets orbit around their suns. The gravitational force also affects the flow of time and the curvature of space, as explained by Einstein's theory of general relativity.
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Complete Question: -
A planet is attracted to the sun with a certain force. if the distance from the sun to the planet is reduced by one half, what would happen to the force?
A. decreased by two times
B. increased by four times
C. increased by two times
D. decreased by four times
The escape velocity on Earth is 11.2 km/s.The escape velocity on a planet having mass twice that of the earth and radius half that of the earth will be- a. 22.4 km/s b. 11.2 km/s c. 33.6 km/s d. None of the above
Convert 35. 9 Celsius to Fahrenheit (35. 9 °C to °F)
Celsius is a temperature measurement unit that is used to show a degree of uncertainty or inaccuracy between any two temperature values. The average body temperature of an adult is 96.7oF on this scale.
What is the parameter for converting Celsius to Fahrenheit?The change from C to F is therefore 100/180, or 5/9. It is 180/100 or 9/5 from F to C. As a result, the conversion yields °F = °C (9/5) + 32. As a result, the equation for changing from the Celsius to Fahrenheit scale becomes °F = °C (9/5) + 32.
When measuring the temperature of air, Fahrenheit produces more accurate results. In comparison to other temperature measures, it is more susceptible to atmospheric and meteorological variations.
The lower end of the scale, 32oF, corresponds to the point at which water freezes or ice melts.
[tex]\frac{5}{9}\times 35.9 (Degrees Celsius) + 32 = 96.62 Degrees Fahrenheit.[/tex]
Therefore, 96.62-degree Fahrenheit.
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How much time will it take a paper airplane to travel 5 m straight at a 2 m/s/s velocity?
By estimating, we can see if the response is reasonable: 2.5 m/s is the product of 5 metres and 2 seconds.Therefore answer is 2.5m/s.
How to calculate velocity?By dividing the amount of time it took the object to go a certain distance by the overall distance, one can calculate the object's initial velocity. V is the speed, d is the distance, and t is the time in the equation V = d/t.An object's terminal velocity is its top possible speed as it plunges through a liquid (air is the most common example). It happens when the object is subjected to a downward force of gravity (FG) equal to the total of the drag force (Fd) and buoyancy.
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what would the minimum value of the coefficient of static friction need to be for the system not to move when released from rest?
The minimum value of the coefficient of static friction necessary for the system not to move when released from rest would be 2 (10 N / 5 N = 2).
What is static friction?Static friction is the force that resists movement between two surfaces that are in contact with each other. It is the friction that acts to prevent movement between two objects, such as a car and the road, from taking place. This force is always present regardless of the objects’ motion and is perpendicular to the surfaces in contact. It is also known as stiction, sticky friction, limiting friction, or static coefficient of friction.
In order for an object to remain at rest when released from rest, the static friction force must be equal to or greater than the force of gravity acting on the object. Therefore, the minimum value of the coefficient of static friction necessary for the system not to move when released from rest is equal to the ratio of the force of gravity to the normal force between the two surfaces. This ratio is known as the static friction coefficient.
For example, if the force of gravity is 10 N and the normal force between the two surfaces is 5 N, the minimum value of the coefficient of static friction necessary for the system not to move when released from rest would be 2 (10 N / 5 N = 2).
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the sun, with its diameter of 1.4 x 106 kilometers, is how many orders of magnitude larger than the earth, with its diameter of 1.3 x 104 kilometers. group of answer choices two orders of magnitude (i.e., a factor of 100 times bigger). four orders of magnitude (i.e., a factor of 10,000 times bigger). three orders of magnitude (i.e., a factor of 1,000 times bigger). one order of magnitude (i.e., a factor of 10 times bigger).
The sun is approximately two orders of magnitude (i.e., a factor of 100 times) larger than the Earth in terms of diameter.
To determine how many orders of magnitude larger the sun is than the Earth, we need to calculate the ratio of their diameters and take the logarithm (base 10) of that ratio.
The ratio of the sun's diameter to the Earth's diameter is:
1.4 x 10^6 km / 1.3 x 10^4 km = 107.7
Taking the logarithm (base 10) of this ratio gives:
log10(107.7) = 2.03
So the answer is that the sun is approximately two orders of magnitude (i.e., a factor of 100 times) larger than the Earth in terms of diameter.
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which of the following statements concerning the motion of a physical pendulum is incorrect? responses the period is changed if the mass of the bob is doubled and the length of the pendulum is halved the period is changed if the mass of the bob is doubled and the length of the pendulum is halved the time interval between conditions of maximum potential energy is one period. the time interval between conditions of maximum potential energy is one period. the kinetic energy is a minimum when the displacement is a maximum. the kinetic energy is a minimum when the displacement is a maximum. the acceleration is a maximum when the displacement is a maximum
The statement that is incorrect is: The time interval between conditions of maximum potential energy is one period.
The time interval between conditions of maximum potential energy is not always one period. The period of a pendulum is the time it takes for the pendulum to complete one full cycle of motion, which is determined by the length of the pendulum and the acceleration due to gravity. The time interval between conditions of maximum potential energy depends on the initial conditions of the pendulum, such as the initial angle and the initial velocity. If the initial angle or the initial velocity is changed, then the time interval between conditions of maximum potential energy will change as well.
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A particle moves horizontally in uniform circular motion, over a horizontal xy−plane. At one instant, it moves through the point at coordinates (4.20 m, 4.70 m) with a velocity of -7.20^i m/s and an acceleration of +14.1^j m/s2. What are the (a)x and b)y coordinates of the center of the circular path?
the x-coordinate of the center of the circular path is 0 (since it lies on the y-axis), and the y-coordinate is 2.55 m.
define motion ?
Motion refers to a change in position or location of an object over time relative to a reference point or frame of reference. It can be described in terms of its displacement, velocity, acceleration, and time.
The x-coordinate of the center of the circle can be found by finding the distance from the point (4.20 m, 4.70 m) to the y-axis. This distance is equal to the radius of the circle, which is given by the centripetal acceleration, a = v^2/r, where v is the speed of the particle in its circular path.
To find the speed of the particle, we can use the fact that the velocity is tangential to the circle. Since the particle is moving in uniform circular motion, the magnitude of its velocity is constant. Thus, we have:
|v| = sqrt[(vx)^2 + (vy)^2] = 7.20 m/s
where vx and vy are the x and y components of the velocity vector, respectively.
To find the x-coordinate of the center of the circle, we can use the Pythagorean theorem:
r^2 = (4.20 m)^2 + (4.70 m - y_c)^2
where y_c is the y-coordinate of the center of the circle.
Solving for y_c, we get:
y_c = 4.70 m ± sqrt[r^2 - (4.20 m)^2]
Since the particle is moving to the left (i.e., in the negative x-direction), the center of the circle must be to the left of the point (4.20 m, 4.70 m). Thus, we take the minus sign:
y_c = 4.70 m - sqrt[r^2 - (4.20 m)^2]
Now, we can use the fact that the acceleration is directed in the positive y-direction:
a_y = 14.1 m/s^2 = v^2/r
Solving for the radius, we get:
r = v^2/a_y = (7.20 m/s)^2/14.1 m/s^2 = 3.67 m
Finally, substituting this value into the expression for y_c, we get:
y_c = 4.70 m - sqrt[(3.67 m)^2 - (4.20 m)^2] = 2.55 m
So the x-coordinate of the center of the circular path is 0 (since it lies on the y-axis), and the y-coordinate is 2.55 m.
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a 900 kg car driving 20 m/s collides with a 1,100 kg truck going 15 m/s. The vehicle bounce off each other and the car moves back 18 m/s. Whats the velocity of the truck after the collision?
Answer: The velocity of the truck after the collision is 18.2 m/s.
Explanation:
Step 1: Determine the total momentum of the two vehicles before the collision.
Momentum is equal to mass multiplied by velocity (p = mv). The momentum of the car before the collision was 900 kg x 20 m/s = 18,000 kg m/s. The momentum of the truck before the collision was 1,100 kg x 15 m/s = 16,500 kg m/s. The total momentum of the two vehicles before the collision was 34,500 kg m/s.
Step 2: Determine the total momentum of the two vehicles after the collision.
After the collision, the car moves back 18 m/s so the momentum of the car is now 900 kg x (-18 m/s) = -16,200 kg m/s. The momentum of the truck after the collision is not given, so we will use the letter "v" to represent this. The total momentum of the two vehicles after the collision is then -16,200 kg m/s + (1,100 kg x v).
Step 3: Use the law of conservation of momentum to solve for the velocity of the truck.
The law of conservation of momentum states that the total momentum of two objects before a collision is equal to the total momentum of two objects after the collision. This means that 34,500 kg m/s = -16,200 kg m/s + (1,100 kg x v), or 34,500 kg m/s = -16,200 kg m/s + 1,100v. Since we know all of the values on the right side of the equation, we can solve for v by rearranging the equation. We get v = (34,500 kg m/s + 16,200 kg m/s) / 1,100 kg = 18.2 m/s.
Therefore, the Step 1: Determine the total momentum of the two vehicles before the collision.
Momentum is equal to mass multiplied by velocity (p = mv). The momentum of the car before the collision was 900 kg x 20 m/s = 18,000 kg m/s. The momentum of the truck before the collision was 1,100 kg x 15 m/s = 16,500 kg m/s. The total momentum of the two vehicles before the collision was 34,500 kg m/s.
Step 2: Determine the total momentum of the two vehicles after the collision.
After the collision, the car moves back 18 m/s so the momentum of the car is now 900 kg x (-18 m/s) = -16,200 kg m/s. The momentum of the truck after the collision is not given, so we will use the letter "v" to represent this. The total momentum of the two vehicles after the collision is then -16,200 kg m/s + (1,100 kg x v).
Step 3: Use the law of conservation of momentum to solve for the velocity of the truck.
The law of conservation of momentum states that the total momentum of two objects before a collision is equal to the total momentum of two objects after the collision. This means that 34,500 kg m/s = -16,200 kg m/s + (1,100 kg x v), or 34,500 kg m/s = -16,200 kg m/s + 1,100v. Since we know all of the values on the right side of the equation, we can solve for v by rearranging the equation. We get v = (34,500 kg m/s + 16,200 kg m/s) / 1,100 kg = 18.2 m/s.
Therefore, the velocity of the truck after the collision is 18.2 m/s.
unpolarized light is incident upon two polarization filters that do not have their transmission axes aligned. if 37% of the light passes through this combination of filters, what is the angle between the transmission axes of the filters?
Unpolarized light passes through a Polaroid filter and emerges as polarised light with vibrations in a single plane and half the intensity of unpolarized light. Because of the chemical makeup of the filter material, Polaroid filters can polarize light.
What use of polarization filters in unpolarized light?The intensity of the unpolarized light is I
Intensity of the light after 1 st polariser I ' = I /2
Intensity of the light after 2 nd polariser I " = 37 %of I = 0.37 I
from malus law I " = I ' cos 2 θ
from this orientation θ = cos -1 ( √[ I " / I] )
θ = cos -1 ( √[ 0.37 I / I/2 ] )
θ = cos -1 ( √[ 0.37 *2 ] )
θ = cos -1 (0.86023 )
= 30.65 degrees
~ 31 degrees
Therefore, 31 degrees is the angle between the transmission axes of the filter.
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The Arrhenius Equation The Arrhenius equation shows the relationship between the rate constant k and the temperature T in kelvins and is typically written as k = Ae^-Ea/RT where R is the gas constant (8.314 J/mol. K), A is a constant called the frequency factor, and Ea is the activation energy for the reaction. However, a more practical form of this equation is which is mathmatically equivalent to where k1 and k2 are the rate constants for a single reaction at two different absolute temperatures (T1 and T2). The activation energy of a certain reaction is 38.2 kJ/mol . At 20 degree C , the rate constant is 0.0140s^-1. At what temperature in degrees Celsius would this reaction go twice as fast? Express your answer with the appropriate units. Part B Given that the initial rate constant is 0.0140s^-1 at an initial temperature of 20 degree C , what would the rate constant be at a temperature of 180 degree C for the same reaction described in Part A?
The Arrhenius equation is a mathematical formula that describes the relationship between the rate of a chemical reaction and the temperature at which it occurs.
What would the rate constant be at a temperature of 180 degree C for the same reaction described in Part A?Part A:
We can use the modified Arrhenius equation to solve for the temperature at which the reaction goes twice as fast as at 20°C. Let's call this temperature T2:
k2 = k1 * e^(-Ea/R * (1/T2 - 1/T1))
We know k1 = 0.0140 s^-1, T1 = 20°C + 273.15 = 293.15 K, and Ea = 38.2 kJ/mol. We want to solve for T2.
First, let's rearrange the equation to isolate e^(-Ea/R * (1/T2 - 1/T1)):
e^(-Ea/R * (1/T2 - 1/T1)) = k2/k1
Now we can take the natural logarithm of both sides:
-ln(k2/k1) = Ea/R * (1/T2 - 1/T1)
Let's plug in the values we know:
-ln(2/1) = (38.2 kJ/mol) / (8.314 J/mol.K) * (1/T2 - 1/293.15 K)
Simplifying this equation gives:
1/T2 = 1/293.15 K - ln(2) * (8.314 J/mol.K) / (38.2 kJ/mol)
Solving for T2:
T2 = 1 / (1/293.15 K - ln(2) * (8.314 J/mol.K) / (38.2 kJ/mol)) - 273.15 K
T2 ≈ 356.9 K ≈ 83.8°C
Therefore, the temperature at which the reaction goes twice as fast as at 20°C is approximately 83.8°C.
Part B:
We can again use the modified Arrhenius equation to solve for the rate constant at 180°C. Let's call this rate constant k3:
k3 = k1 * e^(-Ea/R * (1/T3 - 1/T1))
We know k1 = 0.0140 s^-1, T1 = 20°C + 273.15 = 293.15 K, and Ea = 38.2 kJ/mol. We want to solve for k3 when T3 = 180°C + 273.15 = 453.15 K.
Plugging in the values we know:
k3 = 0.0140 s^-1 * e^(-38.2 kJ/mol / (8.314 J/mol.K) * (1/453.15 K - 1/293.15 K))
k3 ≈ 11.22 s^-1
Therefore, at a temperature of 180°C, the rate constant for the reaction would be approximately 11.22 s^-1.
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Time and velocity are both vectors. True or false?
Answer:
false
Explanation:
only velocity vector
Answer:
false
Explanation:
at a particular instant, a hot air balloon is 100 m in the air and descending at a constant speed of 2.0 m/s. at this exact instant, a girl throws a ball horizontally, relative to herself, with an initial speed of 34 m/s. when she lands, where will she find the ball? ignore air resistance.
The ball will land 98.10 meters vertically below the point where it was thrown and the girl will find the ball 153.68 meters horizontally away from her and 98.10 meters vertically below her.
Since the ball is thrown horizontally relative to the girl, it has no vertical velocity component initially. Therefore, the only force acting on the ball after it is thrown is the force due to gravity, which causes it to follow a parabolic path.
We can use the fact that the horizontal motion of the ball is independent of the vertical motion to analyze each motion separately. Let's start with the horizontal motion:
The horizontal velocity of the ball remains constant at 34 m/s throughout its flight, so we can use the equation:
distance = speed x time
to determine the horizontal distance traveled by the ball.
We know that the ball is thrown at the same instant that the balloon is 100 m above the ground, so we can use this to find the time it takes for the ball to reach the ground.
The time taken for the ball to hit the ground is the same as the time taken for an object to fall 100 m under gravity, since they both have the same vertical acceleration due to gravity.
Using the equation:
distance = 1/2 x acceleration x time^2
with an initial velocity of 0 m/s and an acceleration of 9.8 m/s^2, we can find the time taken for the ball to hit the ground:
100 m = 1/2 x 9.8 m/s^2 x time^2
time^2 = 100 m / (1/2 x 9.8 m/s^2) = 20.41 s^2
time = sqrt(20.41 s^2) = 4.52 s (taking the positive square root)
Now we can use the horizontal distance equation to find the horizontal distance traveled by the ball during this time:
distance = speed x time = 34 m/s x 4.52 s = 153.68 m
So the ball will land 153.68 meters horizontally away from the point where it was thrown.
To find the vertical distance that the ball travels, we can use the same equation:
distance = 1/2 x acceleration x time^2
but this time with an initial velocity of 0 m/s and a time of 4.52 s (since the time taken for the ball to hit the ground is also the time taken for the balloon to descend 100 m).
Using the acceleration due to gravity of 9.8 m/s^2, we get:
distance = 1/2 x 9.8 m/s^2 x (4.52 s)^2 = 98.10 m
So the ball will land 98.10 meters vertically below the point where it was thrown.
Therefore, the girl will find the ball 153.68 meters horizontally away from her and 98.10 meters vertically below her.
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in the figure, a 5.00-kg block is moving at 5.00 m/s along a horizontal frictionless surface toward an ideal massless spring that is attached to a wall. after the block collides with the spring, the spring is compressed a maximum distance of 0.68 m. what is the speed of the block when it has moved so that the spring is compressed to only one-half of the maximum distance?
When a 5.0 kg block moves at 5.0 m/s over a horizontal frictionless surface towards an ideal spring attached to a wall, the maximum speed of the block is 4.33 m/s when the spring is squeezed to one-half of the maximum distance.
According to the law of conservation of energy, the kinetic energy of the mass equals the work done on the spring.
i.e.
1/2 mv² = 1/2 kx²max
In light of this:
The weight of the block is 5.0 kg.
the speed at which it is travelling = 5.0 m/s spring
compression = 0.68 m
By multiplying both sides of the equation by 2, we get:
mv² = kx²max
Making (k) the formula's subject;
k = mv²/ x²max
k = 5*5²/0.68²
k = 125/0.4624
k = 268.17 N/m
However, when the distance is reduced to one-half of its maximum, the speed is calculated as follows:
x = 0.68/2 = 0.34 m
∴
1/2 mv² - 1/2 mv² = 1/2 kx²
m(v²₀-v²) = kx²
(v²₀ - v²) = kx²/m
(5² - v²) = 268.17 * 0.34²/5.0
25-v² = 6.2
v² = 25.625
v² = 18.75
v = √18.75
v = 4.33 m/s
As a result, we may deduce that the block's speed when the spring is squeezed to only one-half of its maximum distance is 4.33 m/s.
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Why do space probes continuously move in outer space?
Answer:
It is because of the gravity. Gravity pulls things down to an planet/star, but a space probe is far enough from the Earth, so it is pulled into the Earth's orbit.
the minimum speed required to launch an object so that it remains the same distance above the ground and just falls around the earth is called:
The minimal speed necessary for an object to maintain a circular orbit around the Earth is known as the circular orbital velocity. Hence, it just circles the planet while staying at the same height above it.
The "circular orbital velocity" is the smallest speed needed to launch an object so that it stays at the same height above the ground and simply orbits the Earth. This velocity is the speed at which an object needs to move in order to stay in a circular orbit around the Earth, such that the gravitational force of the Earth is balanced by the centripetal force required to keep the object in its circular path.
To understand this concept, consider a satellite in orbit around the Earth. The gravitational force between the satellite and the Earth pulls the satellite towards the Earth's surface. However, the satellite is also moving forward with a certain velocity, which generates a centripetal force that pulls it away from the Earth. The balance between these two forces results in a circular orbit. The speed required for this balance to occur is dependent on the altitude of the orbit. The further the object is from the Earth's surface, the lower the required speed. However, if the object is too close to the Earth's surface, the required speed becomes very high, and the object will experience atmospheric drag that could cause it to slow down and fall back to Earth. The exact circular orbital velocity at any given altitude can be calculated using the following formula:
[tex]v = \sqrt{(GM/r)}[/tex]
In summary, the circular orbital velocity is the minimum speed required for an object to stay in a circular orbit around the Earth, where the gravitational force of the Earth is balanced by the centripetal force required to keep the object in its circular path.
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if the geothermal source becomes cooler over time, how will the maximum efficiency of the plant change? assume that the temperature of the surrounding air remains constant.
if the geothermal source becomes cooler over time, The efficiency will increase.
Geothermal technology extracts heat from the earth's interior, which may subsequently be used for power generation or for direct heating and cooling. To create electricity, though, medium- or high-temperature resources are necessary. These are frequently located near tectonically active regions where hot water and/or steam may be carried to the Earth's surface or accessed at relatively shallow depths. The main advantages of geothermal energy are its low cost and year-round, high capacity factor operation. As a result, it may provide reliable, dispatchable power to the electrical grid as well as additional services, if paid. These qualities become increasingly useful as solar and wind power become more widely used.
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the distance from one trough to another trough is called a _____
the distance from one trough to another trough is called a wavelength.
What is wavelength?
Wavelength is a measure of the distance between consecutive peaks of a waveform. It is a fundamental physical property of all waveforms and can be used to describe the properties of light, sound, and other forms of energy. Wavelength is most often expressed in units of meters (m). Wavelengths of different types of radiation can range from extremely short distances (nanometers) to extremely long distances (kilometers). The shorter the wavelength, the higher the energy of the radiation. Wavelengths are important for determining the behavior of waveforms, such as the speed and direction of travel, the amount of energy the wave carries, and the way in which the wave interacts with other forms of matter. Wavelengths are also important in communication technologies, such as radio and television transmission.
Therefore, the distance from one trough to another trough is called a wavelength.
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What force is your bottom pushing against the chair
The force that your bottom is pushing against the chair is called the "action force."
What does action force mean?The action force is equal and opposite to the "reaction force" that the chair is pushing back against your bottom. This is known as Newton's Third Law of Motion, which states that for every action, there is an equal and opposite reaction.
So, when you are sitting in a chair, your bottom is pushing against the chair with a certain amount of force, and the chair is pushing back against your bottom with the same amount of force. This is why you are able to sit in the chair without falling through it.
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how much solar wind kinetic energy per second would be intercepted by the sun-facing half of a 15 re sphere
A total of 1.3x10³⁶ particles are ejected from the Sun every second by the solar wind.
The solar wind is a jet of charged particles that the Sun's corona, or upper atmosphere, releases into space. Electrons, protons, and alpha particles with kinetic energies ranging from 0.5 to 10 keV make up the majority of this plasma. The solar wind plasma is made up of a variety of substances that are also present in the solar plasma, including traces of heavy ions and atomic nuclei like C, N, O, Ne, Mg, Si, S, and Fe. Other nuclei and isotopes including P, Ti, Cr, 54Fe and 56Fe, 58Ni, 60Ni, and 62Ni are also present in smaller amounts. The interplanetary magnetic field is superimposed with the solar-wind plasma.
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what type of pipe do you have? view available hint(s)for part a what type of pipe do you have? open-open closed-closed open-closed either open-open or closed-closed an air-filled pipe is found to have successive harmonics at 480 hz , 800 hz , and 1120 hz . it is unknown whether harmonics below 480 hz and above 1120 hz exist in the pipe. what is the length of the pipe?
When a closed pipe vibrates in basic mode, there is one node and one antinode.
There are two nodes and two antinodes when it vibrates in the first overtone.
As it vibrates in second overtone, there are three nodes and three antinodes.
There are four nodes and four antinodes when it vibrates in the third overtone.
The reflection is not perfect at the open end: some energy escapes. Indeed, this is self-evident, because an organ pipe would not generate any sound if no energy could exit. The sound we hear is energy escaping from the open end. We can only have odd-numbered harmonics in closed tubes. Because closed tubes, by definition, contain a node at one end and an antinode at the other, even-numbered frequencies cannot exist. We can only have odd-numbered harmonics in closed tubes. Because closed tubes, by definition, contain a node at one end and an antinode at the other, even-numbered frequencies cannot exist.
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q1=-4.60•10^-6 C, q2=+3.75•10^-5 C, and q3=-5.30•10^-6 C. Find the x-component of the net force on q2. Include the correct + or - sign to indicate direction.
Please help!!!
The net force on q2 in the x-direction is positive, indicating that it is directed to the right.
How did we get this assertion?
The x-component of the net force on q2 can be found using Coulomb's law, which states that the force between two point charges is proportional to the product of the charges and inversely proportional to the square of the distance between them. The formula for the force between two point charges q1 and q2 is given by:
F = k * (q1 * q2) / d^2
where k is the Coulomb constant (8.99 x 10^9 N * m^2 / C^2), d is the distance between the charges, and q1 and q2 are the magnitudes of the charges.
In this case, we have three charges, so we need to calculate the net force on q2 by considering the force between q2 and each of the other charges. The x-component of the net force is the sum of the x-components of the individual forces.
Let's call the distance between q2 and q1 d12 and the distance between q2 and q3 d23. If q1 is to the left of q2, then the x-component of the force on q2 due to q1 is given by:
F12x = k * (q1 * q2) / d12^2 * (-d12/d12) = -k * (q1 * q2) / d12^2
Similarly, if q3 is to the right of q2, then the x-component of the force on q2 due to q3 is given by:
F23x = k * (q2 * q3) / d23^2 * (d23/d23) = k * (q2 * q3) / d23^2
The net force on q2 in the x-direction is given by:
Fnetx = F12x + F23x = -k * (q1 * q2) / d12^2 + k * (q2 * q3) / d23^2
Plugging in the values for the charges and the Coulomb constant, we get:
Fnetx = -k * (-4.60•10^-6 C * 3.75•10^-5 C) / d12^2 + k * (3.75•10^-5 C * -5.30•10^-6 C) / d23^2 = +k * (4.60•10^-6 C * 3.75•10^-5 C) / d12^2 - k * (3.75•10^-5 C * 5.30•10^-6 C) / d23^2
Therefore, the net force on q2 in the x-direction is positive, indicating that it is directed to the right.
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IA battery moves a charge of 60coloumbs around a circuit at a constant rate in 29seconds .Find the current in the circuit
The current in the circuit is ≈ 2.07 amperes (A)
What is current circuit?A current circuit is a closed path through which electric current can flow. It typically consists of a power source, such as a battery or generator, a load, such as a light bulb or motor, and conductive wires or other components that connect the power source and load to form a complete path for the current to flow.
The current in the circuit can be calculated using the formula:
current = charge / time
In this case, the charge moved around the circuit is 60 coulombs and the time taken is 29 seconds. Thus, the current in the circuit is:
current = 60 coulombs / 29 seconds
current ≈ 2.07 amperes (A)
Therefore, The current in the circuit is ≈ 2.07 amperes (A)
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The robot arm is elevating and extending simultaneously. At a given instant. theta = 30 degree, theta with dot = 10 deg/s = constant, l = 0.5 m, i = 0.2 m/s, and l with dieresis = -0.3 m/s2. Compute: express v right words arrow and a right words arrow in terms of unit vectors I with Hat and j with Hat. the magnitudes of the velocity v and acceleration a of the gripped part P.
The velocity of the gripped part P is -0.4i_hat + 0.293j_hat m/s, and the acceleration is -0.05i_hat - 3.93j_hat m/s^2. The magnitude of the velocity is 0.5 m/s, and the magnitude of the acceleration is 3.93 m/s^2.
What is tangential acceleration?Tangential acceleration is the component of acceleration that is parallel to the instantaneous velocity of an object moving along a curved path. It represents the rate of change of the magnitude of the velocity vector of the object. Mathematically, the tangential acceleration at any instant is given by the formula:
a_t = r * d²(theta)/dt²
To compute the velocity and acceleration of the gripped part P, we can use the equations for velocity and acceleration of a particle in planar motion:
v = v_i + a_t, where v_i is the initial velocity and a_t is the tangential acceleration a = a_t + a_n, where a_n is the normal acceleration
First, let's find the position of the gripped part P at the given instant. We can use the law of cosines to find the length of the arm:
l² = i² + 2ilcos(theta) + l² cos(theta) = (l² + i² - l²)/(2il) = (i²)/(2il) = 0.2/(20.5) = 0.2
Therefore, theta = arccos(0.2) = 78.46 degrees.
Next, let's find the position vectors of the gripped part P at the given instant. We can use the polar coordinates of P:
r = l theta = theta x = rcos(theta) = 0.5cos(78.46) = 0.13 m y = rsin(theta) = 0.5sin(78.46) = 0.47 m
Now, let's find the velocity vector v. We can find the tangential acceleration using the formula:
a_t = ld^2(theta)/dt^2 = l(-0.3)*cos(theta) = -0.15 m/s^2
Therefore, the velocity vector is:
v = v_i + a_t = ltheta_dot(-sin(theta)*i_hat + cos(theta)j_hat) + (-0.15(-sin(theta)*i_hat + cos(theta)j_hat)) = (-0.25(-sin(30)*i_hat + cos(30)j_hat)) + (-0.15(-sin(30)i_hat + cos(30)j_hat)) = (-0.4i_hat + 0.293j_hat) m/s
The magnitude of the velocity is:
|v| = sqrt((-0.4)^2 + (0.293)^2) = 0.5 m/s
Next, let's find the acceleration vector a. We can find the normal acceleration using the formula:
a_n = l × (d^2(theta)/dt^2)sin(theta) = -0.30.5×sin(78.46) = -0.145 m/s^2
Therefore, the acceleration vector is:
a = a_t + a_n = (-0.15*(-sin(30)*i_hat + cos(30)j_hat)) + (-0.145sin(78.46)*cos(30)i_hat + (-0.145sin(78.46)sin(30) - 9.81)j_hat) = (-0.05i_hat - 3.93j_hat) m/s²
The magnitude of the acceleration is:
|a| = √((-0.05)² + (-3.93)²) = 3.93 m/s²
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a car starts from rest and accelerates at 0.300 m/s2 . what is the speed of the car after it has travelled 25.0 m?
The speed of the car after it has traveled 25.0 m is 3.87 m/s. when the car starts from rest and accelerates at 0.300 m/s2.
At rest, is acceleration zero?A vector quantity is acceleration. We must provide retar-dation—a negative acceleration—to the body in order for it to come to rest. The body's velocity is zero when it comes to a stop. The outcome is that the acceleration is also zero.
Is acceleration zero when at rest?Acceleration is a vector quantity. The body needs to experience retar-dation—a negative acceleration—in order to come to rest. When a body comes to a stop, its velocity is zero. As a result, the acceleration is zero as well.
v^2 = u^2 + 2as
v = final velocity
u = initial velocity = zero [start from rest]
a = acceleration = 0.300 m/s2
s = distance = 25.0 m
v^2 = 0 + 2 [0.300] [25.0]
v^2 = 15
v^2 = 3.87 m/s
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What is the name for a burst of activity on an EEG in the early stages of sleep?
gamma waves
sleep spindles
REM
lingering activation
The name for a burst of activity on an EEG in the early stages of sleep is "sleep spindle".
What is sleep spindle?A burst of brain activity during non-rapid eye movement (NREM) sleep is known as a sleep spindle and can be seen on an electroencephalogram (EEG). Although it can occur in other NREM sleep stages as well, it is a hallmark of Stage 2 sleep.
Sleep spindles are characterized by a burst of rhythmic brain activity that spans from 11 to 16 Hz and are short (often lasting only a few seconds). The thalamus, a region of the brain that is essential for transmitting sensory data to the cerebral cortex, is the source of this activity. The thalamus absorbs sensory input during sleep and modifies the information flow to the cortex, enabling the brain to filter out unimportant inputs and concentrate on significant ones.
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45. Two football players collide. The offensive player, mass= 100, was running at
8. 00 m/s. A defensive player catches up to the offensive player from behind.
The defensive player was traveling 11 m/s when he tackled the other player.
a. What was the speed of the two players after the collision?
b. What impulse is felt by each player?
c. If the collision lasted 0. 05 seconds, then what was the force felt by each player?
You may use the impulse-momentum theorem to: Momentum shifts are impulses. It is known that the impulse is 0.05 Ns (1008+10011). As a result, each participant applied a force of 1008 + 10011 N split by 0.05.
What is the impulse momentum theorem's equation?P equals F net t. The equation is also known as that of the impulse-momentum theorem. F net t F net t is referred to as the impulse. According to the equation, the impulse is equal to the average force on an object times how long it takes for that force to act. It is equivalent to the momentum shift.
What is an example of the impulse momentum theorem?The usage of side airbags in cars is one such. In cars, air bags are employed because they may reduce the impact. of the force acting on a collision-involved item. Air bags make this possible by lengthening the length of time it takes so stop the driver and passenger's motion.
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a magnetic field passes through a stationary wire loop, and its magnitude changes in time according to the graph in the drawing. the direction of the field remains constant, however. there are three equal time intervals indicated in the graph: 0 - 3.0 s, 3.0 - 6.0 s, and 6.0 - 9.0 s. (a) is the induced emf equal to zero during any of the intervals? what evidence from the graph supports your claim? (b) during which interval is the magnitude of the induced emf the largest? what evidence from the graph supports your claim? (c) if the direction of the current induced during the first interval is clockwise, what is the direction during the third interval?
The induced EMF is-0.45V and the induced current for the first and third intervals is -0.9A.
the slope of B vs t gives the dB/dt
from the relation emf = NAdB/dt
a) from 0 to 3 s
dB/dt = 0.4-0/(3-0) = 0.133 T/s
emf = 48*0.14*0.133 = 0.894 V
for 3 to 6 sec
dB/dt = 0 (slope is zero)
emf = 0
for 6 to 9 sec
dB/dt = (0.2-0.4)/(9-6) = -0.067 T/s
emf = 48*0.14(-0.067) = -0.45 V
b) if R = 0.5 ohm
current i = 0.894/0.5 = 1.788 A
for 6 to 9 sec
i = -0.45/0.5 = -0.9 A
Induced EMF (Electromotive Force) is the voltage or potential difference that is generated in a conductor when it is exposed to a changing magnetic field. This is due to Faraday’s Law of Electromagnetic Induction, which states that a time-varying magnetic field induces an electric field in a conductor.Induced EMF is the basis for the operation of many electrical devices such as generators and transformers.
Generators convert mechanical energy into electrical energy through the use of induced EMF, while transformers use it to change the voltage and current levels of an AC power system.When a conductor is placed in a magnetic field and the field strength or direction changes, it causes the magnetic flux through the conductor to change.
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Complete Question: -
A magnetic field passes through a stationary wire loop, and its magnitude changes in time according to the graph in the drawing. The direction of the field remains constant, however. There are three equal time intervals indicated in the graph: 0 – 3.0 s, 3.0 – 6.0 s, and 6.0 – 9.0 s. The loop consists of 48 turns of wire and has an area of 0.14 m2. The magnetic field is oriented parallel to the normal to loop. (a) For each interval, determine the induced emf. (b) The wire has a resistance of 0.50 Ω. Determine the induced current for the first and third intervals.