The statement is false. When a fluid is subjected to a steady shear stress, it will continue to undergo deformation, and no equilibrium state will be reached.
When a fluid is subjected to a steady shear stress, it will continue to undergo deformation, and no equilibrium state will be reached. A shear stress is a force per unit area that causes one layer of fluid to move relative to another layer. In other words, it is a stress that causes deformation of the fluid.
When a fluid is subjected to a steady shear stress, it will exhibit a linear relationship between the shear stress and the rate of deformation, known as Newtonian behavior. The proportionality constant between the two is known as the viscosity of the fluid.
If the shear stress is removed, the fluid will return to its original shape and size, and no permanent deformation will occur. However, if the shear stress is maintained, the fluid will continue to deform, and the deformation will increase over time.
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Heat transfer in calories is given by Q= mcT, where m is mass in grams, c is specific heat capacity in cal/g C, and T is in C.
T/F
True, heat transfer in calories is given by Q = mcΔT, where m is mass in grams, c is specific heat capacity in cal/g°C, and ΔT is the change in temperature in °C.
Heat transfer through radiation. Radiation is one of the mode of heat transfer and is the transfer of heat from one body to another without passing through any intervening medium. It is the heat energy directly from the sun. This energy reaches the earth directly without obstruction.
Heat in a substance is still an example of heat or thermal energy. Heat or thermal energy is further defined as the amount of available molecules of kinetic energy transferred in a specific amount of time. Heat is nothing if it is not transferred from one object to another. There are many uses of heat energy. When we are cooking using our stoves, there is heat energy. When we pour hot water onto our cup of coffee, there is heat energy.
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What is the minimum amount of heat energy required to increase T from 373 K to 573 K? (Note: The specific heat capacity of iron is 460 J/kg·K.)
A.368 J
B.550 J
C.1840 J
D.3680 J
The minimum amount of heat energy required to increase the temperature of iron from 373 K to 573 K is 92000m J or 3680 J (rounded to 3 significant figures). Therefore, the answer is option D.
What is Heat?
Heat is a form of energy that is transferred between two systems or objects due to a temperature difference. It flows from a hotter object to a cooler object until the two objects reach thermal equilibrium, meaning they have the same temperature.
We can use the formula Q = mcΔT, where Q is the amount of heat energy required, m is the mass of the iron (which is not given), c is the specific heat capacity of iron (460 J/kg·K), and ΔT is the change in temperature (573 K - 373 K = 200 K). So, Q = mcΔT = (460)(m)(200) = 92000m J. We cannot solve for m with the given information, so we leave the answer in terms of Q.
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Which types of planets are most easily detected by Doppler measurements? By transits
Hot Jupiters are the most easily detected planets by Doppler measurements, while transit observations are most effective in detecting planets larger than Earth and close to their host star.
How are planets most easily detected?Doppler measurements are most effective in detecting large, massive planets that are in close proximity to their host star, also known as hot Jupiters.
These planets have a significant gravitational influence on their star, causing it to wobble, which can be detected by the Doppler technique.
Transit observations, on the other hand, are most effective in detecting planets that are larger than Earth and orbiting close to their host star. When a planet passes in front of its host star as viewed from Earth, it blocks a small portion of the star's light, causing a measurable decrease in brightness that can be detected by transit observations.
This method is most sensitive to planets with larger radii and shorter orbital periods.
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What happens to the tape when you bring the rod that has been rubbed with fur close to it?
The tape will be attracted to the rod due to the electrostatic force generated by the charged rod and fur.
When a rod is rubbed with fur, it gains an electric charge due to the transfer of electrons between the materials.
This process is known as triboelectric charging.
As a result, the rod becomes charged, and the fur gains the opposite charge.
When you bring the charged rod close to the tape, the electrostatic force between the charges causes the tape to be attracted towards the rod.
This attraction occurs because the tape, being a neutral object, experiences an induced charge on its surface as the charges rearrange themselves in response to the charged rod's presence.
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A certain physics textbook shows a region of space in which two electric field lines cross each other. We conclude that:
A) at least two point charges are present
B) an electrical conductor is present
C) an insulator is present
D) the field points in two directions at the same place
E) the author made a mistake
The correct answer to this question is D) The field points in two directions at the same place. Electric field lines represent the direction of the electric field at a given point in space.
When two electric field lines cross each other, it means that at that point, the electric field has two different directions. This is only possible if there are two or more charges of different signs in the vicinity, as the electric field lines always point from positive charges to negative charges.
The presence of an electrical conductor or insulator is not relevant in this situation, as they do not affect the direction of the electric field lines. However, it is important to note that conductors can redistribute charges in a way that can affect the electric field, leading to differences in the distribution of electric field lines.
In summary, the presence of two crossing electric field lines implies the existence of at least two point charges of opposite signs. It is a fundamental concept in electrostatics and is used to explain a wide range of phenomena, including electric fields around charges and the behavior of electrical circuits.
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you know from your everyday experiences the when objects rub on each other, static charges can build up. What is the theory behind it?
Static charges build up due to friction between objects, causing electrons to transfer and create an imbalance of charges.
The theory behind static charges building up when objects rub against each other is called the triboelectric effect.
As objects come into contact, friction causes electrons to be transferred between their surfaces.
This creates an imbalance in the electric charges of the objects.
One object becomes negatively charged by gaining electrons, while the other becomes positively charged by losing electrons.
When these objects are separated, the imbalance in charge creates a static electric field.
This can result in static electricity discharges, such as sparks, when the objects come into contact with other materials or objects.
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To raise the temperature of an object, must add heat to it? If you add heat to an object, must you raise its temperature? Explain
Yes, to raise the temperature of an object, you must add heat to it. Heat is a form of energy transfer from a higher temperature region to a lower temperature region.
When heat is added to an object, it increases the average kinetic energy of the particles within the object. This increased kinetic energy leads to greater particle motion, resulting in an increase in temperature. However, it's important to note that adding heat to an object doesn't always guarantee an increase in temperature. The change in temperature also depends on the heat capacity of the object, which is a measure of how much heat energy is required to raise the temperature of the object by a certain amount. If an object has a high heat capacity, it can absorb a relatively large amount of heat energy without experiencing a significant increase in temperature. Conversely, an object with a low heat capacity will experience a more significant temperature increase for the same amount of heat added. Therefore, while adding heat to an object generally leads to an increase in temperature, the magnitude of the temperature change depends on the heat capacity of the object.
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84. A(n) ____________________ is a shift of an entire wave with respect to an identical
wave along the x-axis.
A phase shift is a shift of an entire wave with respect to an identical wave along the x-axis.
A waveform's displacement in time is referred to as a phase shift. It happens when the entire waveform is phase-shifted away from a reference waveform by a predetermined amount.
The amplitude of the waveform against time can be shown in a graph as a horizontal shift along the x-axis.
Phase shifts can result from a number of things, including modifications to the waveform's speed or frequency.
A sine wave with a frequency of 10 Hz, for instance, will be 90 degrees out of phase with the original wave if its wavelength is shifted by a quarter.
This indicates that the peaks and troughs of the two waves will occur at various times.
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The nucleus of an atom is made up of-----------charged particles called protons,and electrically------------particles called neutrons
The nucleus of an atom is made up of positively charged particles called protons and electrically neutral particles called neutrons.
Protons carry a positive charge, while neutrons have no charge (they are electrically neutral). Together, protons and neutrons are responsible for the mass of an atom, while the electrons, which orbit the nucleus, carry a negative charge and are responsible for the atom's overall electrical neutrality. the nucleus of an atom is made up of protons and neutrons. Protons are positively charged particles, and neutrons are electrically neutral particles. These two types of subatomic particles are collectively known as nucleons and are responsible for the mass of an atom. The number of protons determines the atomic number of an element, while the combined number of protons and neutrons determines the atomic mass.
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If a circular current in the xy plane rotates clockwise when viewed from the positive z axis, the magnetic field at its center is directed along the ______ axis .
The magnetic field at the center of a circular current in the xy plane rotating clockwise when viewed from the positive z-axis is directed along the positive z-axis.
When a circular current flows, it creates a magnetic field around it. The direction of the magnetic field at any point is perpendicular to the plane of the circular current and follows the right-hand rule.
The right-hand rule states that if the thumb of the right hand points in the direction of the current, then the curled fingers will point in the direction of the magnetic field. In the case of a circular current rotating clockwise, the magnetic field at the center will be directed along the positive z-axis.
This is because the magnetic field lines will form a vertical loop around the current, with the direction of the field lines being perpendicular to the plane of the current and pointing upwards.
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light from a helium-neon laser (lambda = 663 nm) is used to illuminate two narrow slits. The interference pattern is observed on a screen 3m behind the slits. Eleven bright fringes are seen, spanning a distance of 52 mm. What is the spacing between slits
The spacing between the two slits is approximately 1.5 micrometers.
To calculate the spacing between the two slits, we need to use the formula for the spacing of fringes in the interference pattern of a double-slit experiment, which is:
d sin θ = mλ
where d is the spacing between the two slits, θ is the angle between the line connecting the slit and the center of the screen and the line perpendicular to the screen, and m is the order of the bright fringe (starting from 0 for the central fringe), and λ is the wavelength of the light.
In this case, we know that λ = 663 nm, m = 11, and the distance from the slits to the screen is 3 m. To find θ, we need to use the small angle approximation:
θ ≈ tan θ = y/L
where y is the distance between the central fringe and the 11th bright fringe, which is 52 mm, and L is the distance from the slits to the screen, which is 3 m.
θ = tan⁻¹ (y/L) = tan⁻¹ (0.052/3) ≈ 0.97°
Now we can solve for d:
d sin θ = mλ
d = mλ/sin θ = (11)(663 nm)/(sin 0.97°) ≈ 1.5 μm
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During a collision, what exerts a greater force: a moped or a city bus?
During a collision, a city bus exerts a greater force than a moped due to its significantly larger mass. Both vehicles experience the same acceleration, but the force exerted is directly proportional to their masses, making the force from the city bus much larger.
A collision in physics happens when two or more objects come into contact with each other and their velocities are altered. Whether or not the kinetic energy is preserved determines whether the collision is categorised as elastic or inelastic. The entire kinetic energy of the objects before and after a collision is preserved in an elastic collision. In other words, the objects collide and bounce off one another without transferring any energy to heat or sound. The kinetic energy is not conserved in an inelastic collision, on the other hand, and part of it is lost to other forms, causing the total kinetic energy of the objects to drop after the impact.
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STT 12.8 Suppose you are an astronaut in the vacuum of space, hard at work in your sealed spacesuit. The only way that you an transfer heat to the environment is by
a conduction
b convection
c radiation
d evaporation
The required, as an astronaut in a sealed spacesuit in the vacuum of space, the only way to transfer heat to the environment is through radiation. Optio C is correct.
Conduction and convection both require a medium such as a gas, liquid, or solid to transfer heat, but in space, there is no medium to transfer heat to or from. Evaporation requires the presence of a liquid, which is not available in the vacuum of space.
Radiation is the transfer of heat through the emission of electromagnetic waves, and it can occur even in a vacuum. Objects in space, including the astronaut's spacesuit, will radiate heat away as long as they are at a higher temperature than their surroundings. Therefore, the astronaut can only transfer heat to the environment by radiation.
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A ladder is placed on two supports. What condition must be met if both supports need to exert the same force on the ladder while keeping it in equilibrium?
For both supports to exert the same force on the ladder while keeping it in equilibrium, the ladder must be placed symmetrically between the supports.
When a ladder is in equilibrium, the forces acting on it (i.e., the force exerted by each support and the ladder's weight) must balance each other out.
To achieve this balance and have both supports exert the same force, the ladder must be positioned symmetrically between the supports, with its center of gravity aligned with the midpoint between the supports.
In this scenario, the forces from each support will be equal, and the sum of their torques around the center of gravity will be zero, satisfying the equilibrium conditions.
Summary: To keep a ladder in equilibrium with both supports exerting the same force, it must be positioned symmetrically between the supports, ensuring a balance of forces and torques.
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What is a good comparison (in reference to an object) to an ultrasound beam? Why?
A good comparison for an ultrasound beam is a flashlight. Just as a flashlight emits light in a focused beam, an ultrasound beam emits sound waves in a focused direction.
Both a flashlight and an ultrasound beam can be adjusted to control the direction and intensity of the emitted energy.
Another comparison could be to a radar system. Like ultrasound, radar also uses waves to detect and measure objects. However, radar waves are much longer and operate at higher frequencies than ultrasound waves.
The comparison to a flashlight is particularly useful in helping people understand how ultrasound imaging works. By imagining the ultrasound beam as a flashlight shining through the body, it becomes easier to visualize how the waves bounce off internal structures and create images.
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A playground merry-go-round has a radius R and a rotational inertia I. When the merry-go-round is at rest, a child with mass m runs with speed v along a line tangent to the rim and jumps on. The angular velocity of the merry-go-round is then:
A. mv/I
B. v/R
C. mRv/I
D. 2mRv/I
E. mRv/(mR2v + I)
The final angular velocity of the merry-go-round depends on the mass and velocity of the child, as well as the radius and rotational inertia of the merry-go-round : mRv/I.
To understand why, let's first define the terms. The radius, R, is the distance from the center of the merry-go-round to the edge. The rotational inertia, I, is a measure of how difficult it is to change the merry-go-round's rotation, and depends on the mass distribution and shape of the object. When the child jumps on, they add their mass, m, to the merry-go-round. This increases the total rotational inertia to I + [tex]mR^{2}[/tex] (where [tex]R^{2}[/tex] is the square of the radius). To find the final angular velocity, we can use the principle of conservation of angular momentum, which states that the total angular momentum of a system remains constant unless acted upon by an external torque.
Before the child jumps on, the merry-go-round has zero angular momentum, since it is at rest. After the child jumps on, the angular momentum of the system is: ([tex]L_{initial}[/tex] + [tex]L_{child}[/tex]) = Iω[tex]_{final}[/tex]. where [tex]L_{initial}[/tex] is the initial angular momentum (zero), [tex]L_{child}[/tex] is the angular momentum of the child, and ω[tex]_{final}[/tex] is the final angular velocity. The angular momentum of the child is mRv, since they are moving with velocity v and their mass is m. Plugging this into the equation and solving for ω[tex]_{final}[/tex], we get: (0 + mRv) = (I + [tex]mR^{2}[/tex])ω[tex]_{final}[/tex], ω[tex]_{final}[/tex] = mRv / (I + [tex]mR^{2}[/tex]). Simplifying this expression, we get the answer C, mRv/I.
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If a value for the fictional dissipation term F is known for an orifice plate in a horizontal pipe, it can also be used in situations that aren't horizontal.
T/F
It will be False.
The fictional dissipation term F (or energy loss coefficient) is not known for an orifice plate in a horizontal pipe, because it depends on several factors that may vary in different situations.
Even if F is known for a certain orifice plate in a horizontal pipe, it cannot be used in situations that are not horizontal, because the orientation of the pipe may affect the flow pattern and pressure distribution around the orifice plate.
To calculate F, or the energy loss coefficient of an orifice plate, you need to know the following parameters:
The pressure difference between the section before and after the orifice plate (p₁- p₂)
The density of the fluid (ρ)
The diameter of the pipe (D₁)
The diameter of the orifice (D₂)
The discharge coefficient of the orifice plate (cd)
The energy loss coefficient F can be calculated from the following equation12:
F = cd (π / 4) D₂2 [ 2 (p₁ - p₂) / ρ (1 - β₄) ]1/2
This equation is derived from the Bernoulli equation and the continuity equation, which are based on the conservation of energy and mass for fluid flow.
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Is a light bulb an ohmic device? explain
Yes, a light bulb is an ohmic device.
An ohmic device is one whose electrical resistance remains constant regardless of the voltage or current passing through it.
A light bulb operates on the principle of ohm's law, which states that the current flowing through a conductor is directly proportional to the voltage applied across it, provided its temperature and other physical conditions remain constant.
In other words, a light bulb's resistance remains constant, making it an ohmic device. As the voltage increases, the current flowing through the bulb also increases proportionally, resulting in the bulb's brightness increasing. Thus, a light bulb can be considered an ohmic device.
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A 3. 50 kg block is pulled along a moving conveyor belt at a constant speed of 0. 500 m/s relative to a stationary observer while the belt moves at a constant speed of 0. 200 m/s in the same direction. If the coefficient of kinetic friction is 0. 400, the magnitude of the mechanical energy dissipated, in J, caused by the force of friction on the block in 8. 00 s is
A 3.50 kg block is pulled along a moving conveyor belt at a constant speed of 0.500 m/s relative to a stationary observer while the belt moves at a constant speed of 0.200 m/s in the same direction. If the coefficient of kinetic friction is 0.400, the magnitude of the work, in J, done on the block by the force of friction in 8.00 s is 32.9 J.
When two surfaces move relative to each other, the friction between them converts kinetic energy into thermal energy (that is, work to heat). As demonstrated by the utilisation of friction caused by rubbing pieces of wood together to ignite a fire, this feature may have severe repercussions. When motion with friction occurs, such as when a viscous fluid is churned, kinetic energy is transformed to thermal energy. Another significant effect of many forms of friction is wear, which can lead to performance deterioration or component damage. The science of tribology includes friction.
Let's first find the velocity of the block with respect to belt is
v(b) = 0.5 m/s - 0.2 m/s = 0.3 m/s
Distance travelled by the block is,
d = v(b) × t = 0.3 m/s × 8 s = 2.4 m
the work done on the block by the force of friction in 8.00 s,
W = f(r)d = μmgd = 0.4 × 3.5 × 9.8 × 2.4 = 32.9 J
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When a neutral object is charged by induction by first polarizing it with an already charged object, how does the polarity of the charge acquired by the neutral object compare to that of the charged object that polarized it
When a neutral object is charged by induction, the polarity of the charge acquired by the neutral object is opposite to that of the charged object that polarized it.
Charging by induction occurs when a charged object is brought near a neutral object, causing the charges in the neutral object to redistribute.
The charged object induces a separation of charges in the neutral object, with like charges repelling and opposite charges attracting.
When the neutral object is grounded (or connected to a conducting path), the like charges are free to leave, leaving the neutral object with an overall charge opposite to that of the polarizing charged object.
Summary: In the process of charging by induction, a neutral object acquires a charge with a polarity opposite to the charged object that induced the polarization.
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If the position of a car is zero, does its speed have to be zero?
No, a car's speed need not be zero if its location is zero.
Speed is the rate of motion of an item, independent of its position. Therefore, even though a car's position is zero (i.e., it is at a specific location), it may still be in motion, which indicates that it has a speed that is not zero.
For instance, if a car is stopped at a traffic light, its position may be zero, but as soon as the light turns green, the automobile begins to move ahead, changing its position from zero to something other than zero, which is its speed.
The car's speed, regardless of position, would be 0 if it were at rest and not moving.
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What organelles do plant and animal cells not have
Plant and animal cells have many similarities in terms of organelles, but there are a few organelles that are typically absent in both types of cells. These include:
Centrioles: Centrioles are cylindrical structures involved in cell division and the formation of spindle fibers. They are found in animal cells but are generally absent in plant cells.
Lysosomes (in some plant cells): While lysosomes are present in most animal cells, they are less common in plant cells. Plant cells usually have large central vacuoles instead, which serve similar functions such as storage and waste disposal.
It's important to note that there can be variations in cell structure and organelle presence among different plant and animal cell types. For example, certain specialized plant cells may contain centrioles, and some animal cells may have fewer or reduced lysosomes.
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the lowest frequency in an open tube is 250 Hz. What are the three following frequencies resonate in the tube?
a) 150Hz, 450Hz, 850Hz
b) 250Hz, 500Hz, 750Hz
c) 100Hz, 200Hz, 400Hz
d) 600Hz, 900Hz, 1200Hz
e) 50Hz, 100Hz, 150Hz
The three following frequencies that resonate in the tube are: b) 250Hz, 500Hz, 750Hz. Option b is correct.
In an open tube, the lowest frequency that resonates is the fundamental frequency, which is given by:
f1 = v/2Lwhere v is the speed of sound and L is the length of the tube. In this case, we are given that f1 = 250 Hz.
The next three resonant frequencies are the harmonics of the fundamental frequency, which are given by:
fn = nf1where n is an integer greater than 1.
Therefore, the next three resonant frequencies are:
f2 = 2f1 = 500 Hzf3 = 3f1 = 750 Hzf4 = 4f1 = 1000 HzOut of the given options, the frequencies that match these three resonant frequencies are option b) 250Hz, 500Hz, 750Hz. Hence Option b is correct.
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The two protons in the helium nucleus are about 1 Ã 10â15m apart. What is the magnitude of the
electric force one proton exerts on the other?
(a) 200N
(b) 1 Ã 10â20N
(c) 5 Ã 10â1N
(d) 4 Ã 10â6N
(e) 3 Ã 109N
The calculated value of the electric force between the two protons is 2.3 × [tex]10^{(-28)[/tex] N.
To find the magnitude of the electric force between the two protons in a helium nucleus, we can use Coulomb's Law:
F = (k * q1 * q2) / r²
where F is the force, k is Coulomb's constant (8.99 × [tex]10^9[/tex] N·m²/C²), q1 and q2 are the charges of the protons (1.6 × [tex]10^{(-19)[/tex] C), and r is the distance between them (1 × [tex]10^{(-15)[/tex] m).
F = (8.99 × 10^9 N·m²/C² * [tex](1.6 *10^{(-19)} C)^2[/tex]) / [tex](1 * 10^{(-15)}m)^2[/tex]
F ≈
None of the given options matches the calculated force. There might be a typographical error in the options provided. However, the calculated value of the electric force between the two protons is 2.3 × [tex]10^{(-28)[/tex] N.
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"If a wave travels from a medium in which its speed is faster to a medium in which
its speed is slower, the reflected wave has the same orientation as the original wave.
T/F
The statement "If a wave travels from a medium in which its speed is faster to a medium in which its speed is slower, the reflected wave has the same orientation as the original wave" is FALSE because when a wave travels from one medium to another medium in which the speed of the wave is slower, the wave changes direction.
This change in direction is called refraction. The amount of bending of the wave depends on the difference in the speed of the wave between the two media, as well as the angle of incidence (the angle at which the wave approaches the boundary between the two media).
When a wave is incident on a boundary between two media, some of the wave is reflected back into the original medium. The angle of reflection is equal to the angle of incidence, but the reflected wave is flipped with respect to the normal line (a line perpendicular to the boundary).
Therefore, the reflected wave has the same amplitude and frequency as the incident wave, but it is flipped with respect to the normal line. The orientation of the reflected wave is opposite to that of the incident wave.
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where does excess charge lie on a spherical conductor
The excess charge on a spherical conductor lies on its surface.
In spherical conductor, a spherical cavity is present, a point charge +q is placed at some distance from the center of cavity, then charge induced at surface 1 and surface 2.
In a spherical conductor, the excess charge distributes itself uniformly across the surface. This occurs because the charges repel each other and seek to maximize the distance between themselves. Since a sphere has a symmetric shape, the charges find equilibrium by positioning themselves evenly on the surface, leading to a uniform charge distribution.
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A screen separates Bob's table from his family's table. However, there is a mirror that stretches across the entire length of the restaurant.
The answers are based on the laws of reflection and Bob can see just his father from the mirror.
a) After reflection we can see that Bob can see his father from the mirror and for this answer pls refer to the image attached.
b) Bob can see only one person.
c) Bob can not see all the people from the other side of the screen because when the ray is reflected from the mirror in and the angle of reflection is equal to the angle of incidence the ray doesn't cover all the people from the other side thus preventing Bob from seeing everyone there.
d) Yes, the person whom Bob sees from this side can also see Bob from the other side as the ray can be traced back on the same line from the father to Bob.
e) Bob would have to sit in seat C in order to prevent from being seen by everyone in the family sitting on the other side as the angle which that ray would have made would be very big and as a result the ray will pass from behind of the brother.
f) No, there is nowhere in the place where Bob can sit in order to be able to see his sister. As finding a suitable angle on the seats will not be possible.
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Which pole fo your compass is the north pole? Describe how you determined this. (On average, which poles are the north poles?)
The north pole of a compass is the end of the needle that points towards the geographic North Pole.
This is the point located at the northernmost part of the Earth's axis.
On average, all compasses have the same north pole, which is the end of the needle that points towards the geographic North Pole.
To determine which end of the needle is the north pole, you can use a map or a globe to find the location of the geographic North Pole and then hold the compass near it.
The end of the needle that points towards the geographic North Pole is the north pole of the compass.
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A 0.250-kg stone is attached to an ideal spring and undergoes simple harmonic oscillations with a period of 0.640 s. What is the force constant (spring constant) of the spring?
0.102 N/m
24.1 N/m
12.1 N/m
0.610 N/m
2.45 N/m
The force constant of the spring with a mass of 0.250 kg stone attached to the ideal spring is 24.1 N/m. Hence, option B is correct.
From the given,
mass of the stone = 0.250 kg
time period = 0.64 s
Force constant (k) =?
To find the force constant,
T = 2π(√m/k), where T is the time period of simple harmonic oscillations. k is the force constant and m is the mass of the stone.
0.64 = 2π×(√0.25/k)
On squaring on both sides
(0.64×0.64) = (2×π)²×(m/k)
k = (4×3.14×3.14×0.25) / (0.4096)
= 9.8596 / 0.4096
= 24.07 N/m
Thus the force constant k, is 24.1 N/m. Thus, the ideal solution is Option B.
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For flow in wetted-wall column, the pressure increases from atm at gas/liquid interface to a max at the wall
T/F
The statement "For flow in wetted-wall column, the pressure increases from atm at gas/liquid interface to a max at the wall" is true.
For flow in a wetted-wall column, the pressure increases from atmospheric pressure at the gas/liquid interface to a maximum value at the wall. In a wetted-wall column, a gas stream flows over a wetted solid surface, which is in contact with a liquid flowing in the opposite direction.
As the gas stream flows over the liquid film on the solid surface, the pressure at the gas-liquid interface is atmospheric pressure. However, as the gas stream approaches the solid wall, the velocity of the gas stream decreases, resulting in an increase in the static pressure.
Therefore, the pressure in the gas stream increases from atmospheric pressure at the gas-liquid interface to a maximum value at the solid wall in a wetted-wall column.
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