When a weed solution is added to a lawn, the number of weeds can be represented by the function W(d)=1650(.85)d where d is the number of days since application. By what percent does the population of weeds decrease each day?

The speed of the wave is 0.83 m/s.

According to the statement

we have given that the equation and we have to find the speed of the wave.

So, For this purpose, we know that the

The given equation is y(x,t) = (9. 13 mm) sin [(6. 65 m^-1)x - (5. 52 s^-1)t]

Then we have to find the speed of the wave

So, Comparing y(x,t) = (9. 13 mm) sin[(6. 65 m-1)x - (5. 52 s-1)t]

to the general expression y(x,t)=y m sin(kx−ωt),

Because the general expression is y(x,t)=y m sin(kx−ωt)

we see that k= 6.65 m −1 and ω= 5.52 rad/s.

The speed of the wave is

v=ω/k=(5.52 rad/s)/(6.65 m )= 0.83 m/s

So, The speed of the wave is 0.83 m/s.

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Answer:

[tex]z=\frac{t^{2}(m-3) }{4}[/tex]    or    [tex]z=\frac{1}{4}t^{2} (m-3)[/tex]

Step-by-step explanation:

[tex]t=\sqrt{\frac{4z}{m-3} }[/tex]

[tex]t^{2} =\frac{4z}{m-3}[/tex]

[tex]4z=t^{2} (m-3)[/tex]

[tex]z=\frac{t^{2}(m-3) }{4}[/tex]

Hope this helps

Answer:

C: 1 Quart

Step-by-step explanation:

2 pints are the equivalent of 1 quart

Answer:1 Quart

Step-by-step explanation: Because 2 pints equals=1 quart

The independent variable of f(c) = -3c + 9 is c

Variables in an equation are the unknown parameters of the equation that change in values

There are two types of variables

The equation of the function is given as

f(c) = -3c + 9

The dependent variable is the output of the function, while the independent variable is the input of the function

For the function, f(c) = -3c + 9

The input variable is c

Hence, the independent variable of f(c) = -3c + 9 is c

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The unknown angles are as follows;

x = 180 degrees

r = 90 degrees.

The angle subtended by an arc of a circle at its centre is twice the angle it subtends anywhere on the circle's circumference.

Therefore,

x = 2(90)

x = 180

Therefore, the sum of angle in a circle is 360 degrees.

Hence, the 2 angles of the arc are the same.

Therefore,

360 - 180 = 2r

2r = 180

divide both sides by 2

2r / 2 = 180 / 2

r = 90 degrees.

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Using limits, the correct option regarding the end behavior of the function is given by:

A. as x→∞, y→−∞ as x→−∞, y→−∞.

The end behavior is found calculating the limit of f(x) as x goes to infinity.

For this problem, the equation is given by:

[tex]f(x) = -x^6 - 6x^5 + 50x^3 + 45x^2 - 108x - 108[/tex]

Since x goes to infinity, we consider only the term with the highest exponent, hence the limits are given as follows:

[tex]\lim_{x \rightarrow -\infty} f(x) = \lim_{x \rightarrow -\infty} -x^6 - 6x^5 + 50x^3 + 45x^2 - 108x - 108 = \lim_{x \rightarrow -\infty} -x^6 = -(-\infty)^6 = -\infty[/tex]

[tex]\lim_{x \rightarrow \infty} f(x) = \lim_{x \rightarrow \infty} -x^6 - 6x^5 + 50x^3 + 45x^2 - 108x - 108 = \lim_{x \rightarrow \infty} -x^6 = -(\infty)^6 = -\infty[/tex]

Hence the correct option is:

A. as x→∞, y→−∞ as x→−∞, y→−∞.

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The answer is [tex]\boxed {\frac{3b - 8}{4b}}[/tex].

The statement that is true about the box plots is: D. The number of calories in the packs of trail mix have a greater variation than the number of calories in the packs of crackers.

For a data distribution that is displayed by a box plot, the measure of variation that can be used to describe the data distribution is the interquartile range.

Interquartile range, which is a measure of variation can be determined from a box plot by finding the value of the third quartile and first quartile, the finding their difference. The difference is the interquartile range.

Interquartile range = third quartile - first quartile.

Interquartile range for crackers = 85 - 75

Interquartile range for crackers = 10

Interquartile range for trail mix = 105 - 90

Interquartile range for trail mix = 15.

The bigger the value of the interquartile range, the more variation there is that exist in a data distribution.

Interquartile range for trial mix is the largest, therefore, the statement that is true about the box plots is: D. The number of calories in the packs of trail mix have a greater variation than the number of calories in the packs of crackers.

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The discrete probability distribution that finds  the probability that x exceeds 5 is  0.38

Opportunity provides records approximately the likelihood that something will manifest. Meteorologists, for instance, use weather patterns to are expecting the chance of rain. In epidemiology, the probability idea is used to recognize the connection between exposures and the risk of fitness consequences.

Finding the possibility of a simple event happening is fairly straightforward: upload the changes collectively. For example, if you have a 10% chance of triumphing $10 and a 25% threat of triumphing $20 then your normal odds of prevailing something is 10% + 25% = 35%.

If there is no ambiguity within the occurrence of an occasion, then the chance of such an occasion is equal to 1. In other phrases, the chance of a sure occasion is 1. If an occasion has no probability of taking place, then its chance is zero.

We want to find the probability for x exceeding 5 means for x>5

Consider,

           P(X>5)=P(x=6)+P(X=8)

              =0.18+0.2

               =0.38

Hence, the probability is  0.38

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Answer:

3.049

Step-by-step explanation:

Move the decimal place in 304.9% to the left two places in order to convert from a percentage to a decimal. 3.049 is the answer.

Brainliest, please :) Hope this helps!

Answer:

Rs.11,111.11 (2 d.p.)

Step-by-step explanation:

The original price of the mobile is 100% of the price.

Therefore, the price of the mobile after a discount of 10% is 90% of the original price.

Let x be the original price.

If the price of the mobile after the discount is Rs.10000 then:

⇒ 90% of x = Rs.10000

⇒ 0.9x = 10000

⇒ x = 10000 ÷ 0.9

⇒ x = 11111.11  (2 d.p.)

M.P. =Rs 11111.1111

Answer:

Solution Given:

Selling price (S.P.) = Rs 10,000.

Discount =10%

Marked Price (M.P.)=?

we have

M.P. = S.P. + discount% of M.P.

keeping M.P. on same side

M.P. - discount% of M.P=S.P.

substituting value

M.P. - 10% of M.P.= Rs 10,000

taking common M.P.

M.P.(1-10%)=Rs. 10,000

we know that %=1/100

M.P.(1-10/100)=Rs 10,000

(9/10)M.P.= Rs 10,000

M.P.= Rs 10,000*10/9

M.P.=Rs11111.1111

Any line through the points [tex](a,b)[/tex] and [tex](c,d)[/tex] has

[tex]\gcd(c-a,d-b)+1[/tex]

lattice points. In this case, the count is GCD(45, 264) + 1.

Using Euclid's algorithm, we have

264 = 5•45 + 39

45 = 1•39 + 6

39 = 6•6 + 3

6 = 2•3 + 0

so that GCD(45, 264) = 3. Then there are 3 + 1 = 4 lattice points.

Modern numbers are the ten numerical digits used in constructing other numbers.

Modern numbers are also called Arabic numerals. They are the ten numerical digits:

0, 1, 2, 3, 4, 5, 6, 7, 8 and 9.

Uses of modern numbers;

Hence, modern numbers are the ten numerical digits used in constructing other numbers.

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Answer:(a) 50% (b)5%

Step-by-step explanation:

For a, it's not really difficult  because the price of a jacket is 1/2 more than jeans. So it's 50%.

For b, it's similar to no. (a) because the price of the jean is 1/2 less than a jacket. So u need to divide 250 by 500 and u will get 0.5 so if u want to put in % u need to multiply with 10, so u will get 5%.

Answer: x = 4

Step-by-step explanation:

Given equation

4x - 20 = -x

Add x on both sides

4x - 20 + x = -x + x

5x - 20 = 0

Add 20 on both sides

5x - 20 + 20 = 0 + 20

5x = 20

Divide 5 on both sides

5x / 5 = 20 / 5

[tex]\Large\boxed{x=4}[/tex]

Hope this helps!! :)

Please let me know if you have any questions

Answer:

m = -5/4

Step-by-step explanation:

In the slope-intercept form formula, y = mx + b, substitute 4 for x, 7 for y, and b for 12 to solve for m.

y = mx + b

7 = 4m + 12

-5 = 4m

m = -5/4

The piecewise equation for the function shown in the diagram is [tex]f(x)=\left \{ {{{[\frac{9}{10}x+5.9\ \ \ -6 \leq x\leq -1 } \atop {[2\ \ \ \ \ \ \ \ \ \ \ -1 < x\leq 2}} \atop {[-\frac{5}{2}x+6\ \ \ 2 < x\leq 6 }} \right.[/tex]

An equation is an expression that shows the relationship between two numbers and variables.

An independent variable is a variable that does not depend on any other variable for its value whereas a dependent variable is a variable that depend on any other variable for its value.

From the diagram using the point (-6, 0.5) and (-1, 5):

y - 0.5 = [(5 - 0.5)/(-1 - (-6))](x - (-6))

y = (9/10)x + 5.9

Also, using the point (2, 1) and (4, -4):

y - 1 = [(-4 - 1)/(4 - 2)](x - 2)

y = -(5/2)x + 6

The piecewise equation for the function shown in the diagram is [tex]f(x)=\left \{ {{{[\frac{9}{10}x+5.9\ \ \ -6 \leq x\leq -1 } \atop {[2\ \ \ \ \ \ \ \ \ \ \ -1 < x\leq 2}} \atop {[-\frac{5}{2}x+6\ \ \ 2 < x\leq 6 }} \right.[/tex]

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The 99% confidence interval for the decrease in the defective rate after the reconfiguration is (-0.018, 0.086).

Let the random variable & parameters be;

x1 : Number of successes from group 1

x2 : Number of successes from group 2

p1: Proportion of successes in group 1

p2: Proportion of successes in group 2

n1 : number of trial in group 1

n2: number of trial in group 2

We are given;

x1 = 260

n1 =985

x2 = 194

n2 = 842

Thus;

p1 = 260/985

p1 =0.2640

p2 = 194/842

p2 = 0.2304

Constructing a (1 - α)100% confidence interval for proportion from the formula;

(p₁ - p₂) - z√[((p₁(1 - p₁)/n₁) + p₂(1 - p₂)/n₂)]

plugging in z = 2.576 and the values of p₁, p₂, n₁ and n₂, we have the confidence interval as;

(-0.0184631, 0.0855743)

Therefore the 99% confidence interval for the decrease in the defective rate after the reconfiguration is (-0.018, 0.086).

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Answer:

The question does not make a lot of sense to me but I think this is how its supposed to be done

so there are 15 shirts

2 are sold at 3.90, 2 x 3.90 = 7.8

15-2= 13 t shirts

13 sold at 4.70, 13 x 4.70 = 61.1

amount of money made is = 7.8 + 61.1

                                            = 68.9

The solution of the questions is given as

a)

The alternative hypothesis is that mu is equal to 3.0. ( the average GPA at KSU is not equal to 3.0)

b)

This is a case with two separate arguments. (This is a two-tailed case)

c)

Test Statistic is given by:

z= 2.00

d)

Critical values of Z come from the table and equal [tex]\pm[/tex]1.96.

e)

, p-value = 0.0455

f)

CI= (3.006, 3.594)

g)

Conclusion: The evidence does not back up the assertion that KSU students have a cumulative grade point average of 3.0.

h)

Conclusion: The evidence does not back up the assertion that KSU students have a cumulative grade point average of 3.0.

i) Conclusion: The evidence does not lend credence to the assertion that KSU's typical grade point average is equivalent to 3.0.

j)

The choices you choose in Questions 7, 8, and 9 are identical.

a)

The null hypothesis states that mu equals 3.0. ( the average GPA at KSU is equal to 3.0) (Claim)

The alternative hypothesis is that mu is equal to 3.0. ( the average GPA at KSU is not equal to 3.0)

b)

This is a case with two separate arguments.

c)

Test Statistic is given by:

[tex]z=\frac{\barx-u^0}{σ/Vn}\\\\z=33 - 3.0/1.5/V100[/tex]

z= 2.00

d)

[tex]\alpha = 0.05[/tex]

Critical values of Z come from the table and equal [tex]\pm[/tex]1.96.

e)

Z Score = 2.00

reading from table, p-value = 0.0455

f)

Confidence Interval:

[tex]CI= \barx \pm \frac{ZX\sigma }{\sqrt((n)}[/tex]

[tex]CI =3.3 \pm 1.96 x 1.5 / \sqrt{100}[/tex]

CI= (3.006, 3.594)

g)

The disparity is noteworthy given that the computed value of Z = 2.00 is higher than the crucial value of z = 1.96. Cast doubt on the null hypothesis.

Conclusion: The evidence does not back up the assertion that KSU students have a cumulative grade point average of 3.0.

h)

The difference may be considered statistically significant since the p-value of 0.0455 is lower than the alpha threshold of 0.05. Cast doubt on the null hypothesis.

Conclusion: The evidence does not back up the assertion that KSU students have a cumulative grade point average of 3.0.

i)

The difference is statistically significant since the value of 3.0 is not included in the confidence range (3.006 - 3.594). Cast doubt on the null hypothesis.

Conclusion: The evidence does not lend credence to the assertion that KSU's typical grade point average is equivalent to 3.0.

j)

The choices you choose in Questions 7, 8, and 9 are identical.

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The length of the railing needed is 31.4 feet

From the question, we are to determine the length of railing needed

To determine the length of railing needed, we will determine the length of the arc formed by the balcony

Using the formula,

l = θ/360° × 2πr

Where l is the length of the arc

θ is the angle subtended by the arc

and r is the radius

From the given information,

θ = 45°

r = 40 feet

Putting the parameters into the equation, we get

l = 45°/360° × 2 × 3.14 × 40

l = 1/8 × 2 × 3.14 × 40

l = 2 × 3.14 × 5

l = 31.4 feet

Hence, the length of the railing needed is 31.4 feet

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Answer: C

Step-by-step explanation:

Answer:

540

Step-by-step explanation:

540 =18% of 97.2

Done please

it's quotient it's a synthax error..

[tex]7x^{2} - 9x^{2} +8x-5x + 10-7[/tex] is the given expression

Like terms are terms whose variables (and their exponents such as the 2 in [tex]x^{2}[/tex]) are the same. Like terms can easily be added and substracted. Such questions just need like terms to be bought together and simplified

Infinite number of equations or expressions can be written for the given question. So writing one possibility for the given question,

= [tex]7x^{2} - 9x^{2} +8x-5x + 10-7[/tex]

which sums up to

= [tex]-2x^{2} +3x+3[/tex]

Thus [tex]7x^{2} - 9x^{2} +8x-5x + 10-7[/tex] is the given expression

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Answer:

Solve x2 − 24x = −80 by completing the square. what is the solution set of the equation?

The Answer Is X = 20 or x = 4

Answer:

hdchyf

Step-by-step explanation:

fhyrb ufgfyg hchybgvtct ugh

The linear equations that corresponds to the table is y = 4x + 3

The missing table of values in the complete question is given as:

x y

0 3

3 15

7 31

10 43

Start by calculating the slope of the equation using

m = (y2 - y1)(x2 - x1)

Substitute the values on the table in the above equation

m = (15 - 3)/(3 - 0)

Evaluate the difference

m = 12/3

Evaluate the quotient

m = 4

The linear equation is then calculated as:

y = m(x - x1) + y1

This gives

y = 4(x - 0) + 3

Evaluate the expression

y = 4x + 3

Hence, the linear equations that corresponds to the table is y = 4x + 3

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Michael took the return trip at a velocity 33.75 miles per hour.

Let suppose that Michael drove in straight line road and at constant velocity. Therefore, the speed of the vehicle (v), in miles per hour, can be defined as distance traveled by the vehicle (d), in miles, divided by travel time (t), in hours.

First trip

45 = s / 3     (1)

Second trip

v = s / 4       (2)

By (1) and (2):

45 · 3 = 4 · v

v = 33.75 mi / h

Michael took the return trip at a velocity 33.75 miles per hour.

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Answer:

Step-by-step explanation:

B is the best answer