When conducting a hypothesis test for a given sample size, if α is increased from 0.05 to 0.10, then __________.

D. Water in the pot is heated by convection. Water molecules at the bottom of the pot warm up and rise while cooler water molecules sink to the bottom of the pot, creating convection currents.

Convection currents are flowing fluid that is moving because there is a temperature or density difference within the material.

Convection heat transfer takes place only in liquids and gases.

During heat transfer by convection, the heated air will rise to the top due o its lower density while the cooler air will sink to the bottom due to its higher density.

Thus, for the model of a pot of water being heated on a stove that shows thermal energy transfer, the heat transfer occurs when the water in the pot is heated by convection. Water molecules at the bottom of the pot warm up and rise while cooler water molecules sink to the bottom of the pot, creating convection currents.

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Heat is transferred to the water. The water molecules which are in the pot become more active, and the temperature of the water rises.

What is the Kinetic energy?

Kinetic energy is the energy of the objects which is present due to the motion of the object. Kinetic energy is proportional to the mass and velocity of the object. The SI unit of Kinetic energy is Joule (J).

The kinetic energy is possessed due to the motion of the particles. The kinetic energy is directly proportional to the temperature of objects. The kinetic energy of the particles increases with the rise in temperature of object or solution.

In the given situation, the pot of water is placed on the stove. Then, the heat is transferred to the water in pot. The water molecules will move faster with the rise in temperature of the water. The water molecules will have greater amount of kinetic energy due to increase in temperature.

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Intensity of laser beam is 72.3W/m²

Given:

average power output = 0. 250 mw

To Find:

intensity of laser beam

Solution:

First of all, we need to find the area of the circular spot, which is given by:

A = πr^2

where r is the radius of the spot, which is half the diameter, therefore

r = d/2 = 2.10mm/2 = 1.05mm = 1.05 x 10^-3m

So, the area of the spot is

A = π(1.05 10^-3m)^2 = 3.46 10^-6m²

We know that the power output of the laser is

P = 0.250mW = 2.5.10^-4W

So the intensity of the laser beam is

I = P/A = 2.5^-10 W/3.46-10^-6m^2 = 72.3W/m²

So, intensity of laser beam is 72.3W/m²

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Answer:

300 Pa

Explanation:

P=F/A

= 900/3

= 300 Pa

A Final statement or concluding statement

Light rays meet at Focal Point after passing through a lens.

A focus is a place at which light or other forms of radiation converge.

A beam that enters a diverging lens parallel to its axis seems to originate at the focal  point F.

A beam passing through the focal point of a converging lens departs parallel to its axis.

Parallel light rays from the right enter a converging lens at its focal point on the left.

Light rays entering a converging lens parallel to its axis converge at the lens's focal  point F.

The focal length of a lens is the distance between its center and its focal point.

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Both the turbines take same amount of time to rotate through 1. 0 radian of angular displacement.

Given,

[tex]R_{A}[/tex] = [tex]2R_{B}[/tex]

[tex]V_{A}[/tex] = [tex]2V_{B}[/tex]

As, angular velocity is, ω

So, ω[tex]_{A}[/tex] = [tex]V_{A}[/tex] / [tex]R_{A}[/tex]

     ω[tex]_{A}[/tex] = 2[tex]V_{B}[/tex] / 2[tex]R_{B}[/tex]

      ω[tex]_{A}[/tex] = [tex]V_{B}[/tex] / [tex]R_{B}[/tex]

also, ω[tex]_{B}[/tex] = [tex]V_{B}[/tex] / [tex]R_{B}[/tex]

And angular displacement is , θ

θ = ω / t

t = θ / ω

[tex]t_{A} = t_{B}[/tex] = [tex]R_{B}[/tex] / [tex]V_{B}[/tex]

Therefore, Both the turbines take same amount of time to rotate through 1. 0 radian of angular displacement.

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The vector u represents the sum of two orthogonal vectors, and which can be written as,

[tex]u=Proj_vu+(u-Proj_vu)[/tex].

To find the answer, we have to know about the projection of vectors.

                               [tex]Proj_v u=\frac{u.v}{v.v} v[/tex]  (inner product)

              [tex]u=(u_1,u_2)\\v=(v_1,v_2)[/tex]    then, projection of u on v is,

                              [tex]Proj_vu=\frac{u_1v_1+u_2v_2}{v_1v_1+v_2v_2} (v_1,v_2)[/tex]

                 [tex]u=Proj_vu+(u-Proj_vu)[/tex]

Thus, we can conclude that, the vector u represents the sum of two

orthogonal vectors, and which can be written as,

[tex]u=Proj_vu+(u-Proj_vu)[/tex].

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Answer:

C. tiny particles called charges flowing through the wires.

Explanation:

An electric current is a stream of charged particles, such as electrons or ions, moving through an electrical conductor or space. It is measured as the net rate of flow of electric charge through a surface or into a control volume.

Hope it helps!

Answer:

c

Explanation:

electric current is tiny particles called charges flowing through the wires
pls mark me brainliest :)

Answer:

I don't know of velocity but

acceleration: 6m/s

Explanation:

here

initial velocity(u):0m/s

final velocity(v):36m

time taken(t): 6s

now

a:v-u/t

or a: 36-0/6

a:6m/s#

True

The helium-neon lasers most commonly used in student physics laboratories have average power outputs of 0. 250 mw

Intensity of laser beam is 72.3W/m²

Given:

average power output = 0. 250 mw

To Find: intensity of laser beam

First of all, we need to find the area of the circular spot, which is given by:

A = πr^2

where r is the radius of the spot, which is half the diameter, therefore

r = d/2 = 2.10mm/2 = 1.05mm = 1.05 x 10^-3m

So, the area of the spot is

A = π(1.05 10^-3m)^2 = 3.46 10^-6m²

We know that the power output of the laser is

P = 0.250mW = 2.5.10^-4W

So the intensity of the laser beam is

I = P/A = 2.5^-10 W/3.46-10^-6m^2 = 72.3W/m²

So, intensity of laser beam is 72.3W/m²

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An ECG does not show atria repolarization.

To find the answer, we need to know more about the electrocardiogram.

Thus, we can conclude that, the option d is correct.

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9.87 seconds

The time required for this system to come to rest is equal to 9.87 seconds.

We have the following data:

Mass of gear A = 675 g to kg = 0.675 kg.

Radius of gear A = 40 mm to m = 0.04 m.

Mass of gear C = 3.6 kg.

Radius of gear C = 100 mm to m = 0.1 m.

How can I calculate the time needed?

We would need to figure out the moment of inertia for gears A and C in order to compute the time needed for this system to come to rest.

Mathematically, the following formula can be used to determine the moment of inertia for a gear:

I = mr²

Where:

m is the mass.

r is the radius.

We have, For gear A:

I = mr²

I = 0.675 × 0.04²

I = 0.675 × 0.0016

I = 1.08 × 10⁻³ kg·m².

We have, For gear C:

I = mr²

I = 3.6 × 0.1²

I = 3.6 × 0.01

I = 0.036 kg·m².

The initial angular velocity of gear C would therefore be converted as follows from rotations per minute (rpm) to radians per second (rad/s):

ωc₁ = 2000 × 2π/60

ωc₁ = 4000π/60

ωc₁ = 209.44 rad/s.

Also, the initial angular velocity of gears A and B is given by:

ωA₁ = ωB₁ = rc/rA × (ωc₁)

ωA₁ = ωB₁ = 0.15/0.06 × (209.44)

ωA₁ = ωB₁ = 2.5 × (209.44)

ωA₁ = ωB₁ = 523.60 rad/s.

Taking the moment about A, we have:

I_A·ωA₁ + rA∫F_{AC}dt - M(f)_A·t = 0

On Substituting the given parameters into the formula, we have;

(1.08 × 10⁻³)·(523.60) + 0.06∫F_{AC}dt - 0.15t = 0

0.15t - 0.06∫F_{AC}dt = 0.56549   ----->equation 1.

Similarly, the moment about B is given by:

0.15t - 0.06∫F_{BC}dt = 0.56549    ------>equation 2.

Note: Let x = ∫F_{BC}dt + ∫F_{AC}dt

Adding eqn. 1 & eqn. 2, we have:

0.3t - 0.06x = (0.56549) × 2

0.3t - 0.06x = 1.13098  ------>equation 3.

Taking the moment about A, we have:

Ic·ωc₁ - rC∫F_{AC}dt - rC∫F_{BC}dt - Mc(f)_A·t = 0

0.036(209.44) - 0.3t - 0.15(∫F_{BC}dt + ∫F_{AC}dt) = 0

0.3t + 0.15x = 7.5398    ------->equation 4.

Solving eqn. 3 and eqn. 4 simultaneously, we have:

x = 30.5 Ns.

Time, t = 9.87 seconds.

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A small fly of mass 0. 30 g is caught in a spider's web. the web oscillates predominantly with a frequency of 4.3 Hz. The value of the effective spring stiffness constant k for the web is 0.21 N/m

Frequency of the oscillation is the number of oscillation in per unit time. It's SI unit is Hertz or s⁻¹.

Spring stiffness constant k is a measure of the stiffness of spring.

The Frequency of the oscillation is given by the following formula:

f = [tex]\sqrt{k/4\pi m}[/tex]

where, f is the frequency of web

           k is the stiffness constant of web

            m is the mass of small fly

On rearranging the above equation,

k = 4π²f²m

⇒ k = 4 (3.14)² (4.3)² 0.0003

⇒ k = 0.21 N/m

Hence, the Stiffness constant k for the web is 0.21 N/m

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The wavelengths of these signals is between  187.50m to 2.77 m.

Frequency describes the number of waves that skip a set region in a given quantity of time. There are two forms of frequency desk - Grouped Frequency Distribution and Ungrouped Frequency Distribution.

Wavelength is normally denoted with the aid of the Greek letter lambda (λ); it is identical to the velocity (v) of a wave train in a medium divided by means of its frequency (f)= λ = v/f.

Part A)

λ max = v / f

= 3 x 10^8 / 550x10^3 =545.45 m

λmin = 3 x 10^8 / 1600x10^3 = 187.50m

Part B)

λ max = v / f

= 3 x 10^8 / 88x10^6

 = 3.41 meters

λmin = 3 x 10^8 / 108x10^6 = 2.77 m

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The resulting change in the magnetic flux is =0.013Wb

what is magnetic flux?

Magnetic flux is defined as the total magnetic field which passes through a given area.It is the number of magnetic field lines that is flowing in a closed area.

Given:

At degree =15.5°,magnetic flux=magnetic field=0.500T

At degree=45.0°, magnetic field=0.500T

Magnetic flux=magnetic field ×Area×cos(angle)

magnetic flux (1) = 0.500×0.1×cos(15.5)

= 0.048

magnetic flux (2) = 0.500×0.1×cos(45)

=0.035

Resulting change in flux = 0.048-0.035

= 0.013Wb

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Homo erectus’s cranial capacity -  ranges from 650 cc to 1,200 cc.

Homo erectus, an extinct species of Pleistocene archaic human, first appeared about 2 million years ago. The earliest known early human with dimensions similar to modern humans, including relatively long legs and small arms compared to the size of the torso, is Homo erectus. An extinct species of hominin that existed between 1.9 million and 135,000 years ago is known as homo Erectus.

The Homo erectus had certain ape-like characteristics, including huge teeth and a hefty jaw. They hunted and ate cooked meat, and they used fire. After closer inspection, it was discovered that the species' teeth showed signs of a diversified diet that included meat intake.

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Answer:

D. 15 kgm/s is the value of impulse applied

The Inverse Square Law applies to Radiation. It states that the intensity of any radiation source is inversely proportional to the square of the distance from the source.

I would rather call it “an inverse square law”. Some things vary inversely as the square of something (usually distance) and some things don’t.

For instance, the quantity of light energy per second falling on a tiny area* is inversely related to the square of the distance from the source if a point light source emits light uniformly in all directions. The energy per second will decrease by four times with every twofold increase in distance for a certain area, and nine times with every threefold increase in distance. (Ideally, the area should be a sphere centered on the point source to make the distance clear; nonetheless, an approximate solution is a tiny plane area perpendicular to the line from the point source.) Therefore, light obeys the inverse square law (at least in Euclidean space).

The gravitational and electrical forces are some examples of entities that adhere to the inverse square law. On the other hand, gravitational and electrical potentials adhere to an inverse rule, whereby the potential must be reduced by a factor of two times the distance.

Thank you,

Eddie

The inverse square law states that the intensity or strength of a physical quantity decreases in proportion to the square of the distance from the source.

The inverse square law is expressed as:

Intensity = k / (distance)²

As you walk further from the source, the light from a point source loses intensity as it spreads out across a wider region.

The square of the distance between two objects' centers determines how much gravity there is between them. The gravitational pull between two things lessens as they are pulled apart more.

As you get further from the source of the music, the sound waves become less intense.

Inverse square law governs the strength of the magnetic and electric fields surrounding a charged particle or a wire carrying current.

An important tenet of physics is the inverse square law, which can be used to explain a variety of natural events.

Therefore,  the intensity or strength of a physical quantity decreases in proportion to the square of the distance from the source.

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Answer:

below

Explanation:

Ice melts, meaning it has a watery layer upon its surface. This allows things to be moving like they are on a liquid but it has the solidity of a solid. The thin metal of the ice skates also decrease the surface area meaning it exerts more force but in turn, it allows you to move faster and further reduces friction.

The displacement at the end of A is 1.09 mm

According to the question,

Rod's diameter, d= 20 mm

Stiffness constant, k = 55 M-N/m or,

                                 = 55 × 10⁶ N/m

Force, f = 60 kN or,

            = 60 × 10³ N

Young's modulus, E = 200 Gpa or,

                                = 200 × 10⁹ pa

We know the formula,

A=[tex]\pi d^2 /4[/tex]

By substituting the values,

     = [tex]\pi (0.02)^{2} /4[/tex]

=0.0003 m³

length, L =A×E/K

=1.14 m

hence,

The displacement be:

60×10³×1.14/0.0003×200×10³×10³×10³=1.09 mm

Displacement is  1.09 mm

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The displacement of end a is 1.09mm

given:

Rod diameter,d=20mm

stiffness constant,k=55mn/m

force,f=60kn

young modulus,E= 200gpa

we know the formula

[tex]\pi \: d {}^{2} /4[/tex]

By substituting values in the above formula

[tex] = \pi(0.02) {}^{2} /4[/tex]

[tex] = 0.0003m {}^{3} [/tex]

length L=A×E/K

=1.14m

Hence, displacement is

[tex]60 \times 10 {}^{3} \times 1.14 \times/0.0003 \times 200 \times 10 {}^{3} \times 10 {}^{3} \times 10 {}^{3} [/tex]

=1.09mm

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Answer:

C. 199.9 s

Explanation:

3 minutes = 3×60 = 180 seconds.

the turtle moves in that time 180×10 = 1800 cm.

in other words the rabbit gave it that much head-start (it does not matter if that was at the begin of in the middle of the race).

the rabbit moves with 10×10cm/s = 100cm/s.

the rabbit needs therefore 1800/100 = 18 seconds for the

1800 cm.

at that time the turtle has added another 18×10 = 180 cm.

for which the rabbit needs 180/100 = 1.8 seconds.

during that time the turtle has added 1.8×10 = 18 cm.

and so on.

in formal mathematics this looks like this :

1800 + 10x = 100x

after x seconds of the rabbit running both will have run the same distance, and it is a tie.

1800 = 90x

x = 20 seconds

so, at that point, the rabbit was actively running for 20 seconds and raced 20×100 = 2000 cm

and the turtle was actively running for 180 + 20 = 200 seconds, and also covered 200×10 = 2000 cm.

but our question tells us that the turtle won by 10 cm.

so, the race was over a little bit before these 200 seconds (for a tie).

this means, the rabbit could not run the last 10 cm for the tie (because the race was over and the turtle had won).

the rabbit would have needed 10/100 seconds for these 10 cm.

as speed = distance/time

we need to divide distance by speed

distance/1 / distance/time

to get time.

so,

10cm/1 / 100cm/s = 10s/100 = 1/10 s

so, we need to deduct this 1/10 s from the 200 seconds of the turtle (and also from the 20 seconds for the rabbit).

the race lasted of course the whole time the turtle was running (while the rabbit was resting, officially still participating in the race with speed 0 for 3 minutes).

and so, the race was 199.9 s long.

It necessary to level the rotating platform to maintain uniform circular motion.

The outcomes will be negatively impacted if the platform is not level since the heavy end will sway toward the side that is low.

To maintain a balance of the speed it is necessary to level the rotating platform.

When a particle follows a circular path while maintaining a constant speed, its motion is described as being uniformly circular.

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Answer:

Explanation:

The Sun reaches us by propagating through the vacuum of space. Sunlight reaches the Earth in about 8 minutes and 20 seconds. When this energy reaches the Earth's atmosphere, both conduction and convection play key roles to scatter it throughout the planet.

Answer: The heat from the sun reaches us through radiation and processes such as conduction and convection helps to scatter that heat on the surface of our planet.

Explanation:

The phenomenon behind the Sun's heat reaching us is radiation. It does this by propagating through the vacuum of space.

The amount of time it takes for the sunlight to reach us on Earth is approximately 8 minutes and 20 seconds. When it reaches our planet, conduction, the movement of heat or electricity through a medium or passage, as well as convection, the rising of hotter and less dense material and sinking of colder and more dense/denser material, helps to scatter the heat on Earth's surface.

The separation between the two slits, d is related to the wavelength, and angle using the formula below. Hence, the value of d is 1.22 x 10⁻⁶ m.

For ease of calculations we take 29.8° = 30°

Using the relation :

[tex]\frac{m * λ }{sin\theta}[/tex]

where :

d = distance between the slits

θ = 30°

λ = wavelength of light = 617 nm = 6.17 x 10⁻⁷ m

m = 1

Substituting the values into the equation :

d = 1 x 6.17 x 10⁻⁷ / 0.5 = 0.00000122 = 1.22 x 10⁻⁶ m

Therefore, the seperation between the two slits is 1.22 x 10⁻⁶ m.

The double-slit experiment is a demonstration that light and matter can display characteristics of both classically defined waves and particles; moreover, it displays the fundamentally probabilistic nature of quantum mechanical phenomena.

This type of experiment was first performed, using light, by Thomas Young in 1802, as a demonstration of the wave behavior of light. At that time it was thought that light consisted of either waves or particles.

With the beginning of modern physics, about a hundred years later, it was realized that light could in fact show behavior characteristic of both waves and particles. Young's experiment with light was part of classical physics long before the development of quantum mechanics and the concept of wave–particle duality.

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Hi there! Your answer is below.

Pulley sizes, cylinder size ratios, screw pitch, leverage, gear ratios, and pulley sizes

The MA increases yet the work takes longer to complete the farther the applied effort goes relative to the load. An excessive increase in the MA may be counterproductive.

Bicycle derailleurs are the most obvious example of variable MA.

Choose a low gear to climb hills more easily, but if you don't switch to another one on the flat, you'll be pedaling frantically and quickly getting nowhere. (Of course, you progress, but slowly.)

I frequently use bicycles as illustrations of intricate mechanics. They aren't actually toys at all!

Thank you,

Eddie

The distance from observer A of intensity of sound 59 db is 28.64 m and the distance from observer B of intensity of sound 83 db is 11.36m

Explanation:

Let's solve this problem in parts

let's start by finding the intensity of the sound in each observer

observer A β = 59 db

            β = [tex]10 log\frac{I_a}{I_o}[/tex]

where I₀ = [tex]1 \times 10^{-12}[/tex]  W / m²

             [tex]I_a = I_b \times 10 ^{ \frac{\beta}{10} }[/tex]

             [tex]I_a = 1\times 10 ^{-12} \times 10 ^{ \frac{59}{10} }[/tex]

             [tex]I_a[/tex] = [tex]2.51 \times 10 ^{-6}[/tex] W / m²

Similarly for Observer b [tex]I_b = 3.16 \times 10 ^ {-4}[/tex]

now we use that the emitted power that is constant is the intensity over the area of ​​the sphere where the sound is distributed

P = I A

therefore for the two observers

the area of ​​a sphere is

[tex]A= 4\pi \times r^2[/tex]

we substitute the above formula, we get

Let us call the distance from the observer A be to stereo speaker = x, so the distance from the observer B to the stereo speaker = 40- x; we substitute

            [tex]I_a (35 -x) ^2 = I_b x^2[/tex]

after solving the above equation we get  x = 28.64 m

This is the distance of observer A

similarly The distance from observer B is 35 - x

= 40 - 28.64

= 11.36m

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When cyclooctatetraene is treated with excess potassium metal dipotassium cyclooctatetraene dianion compound is formed.

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True.

Peripheral vision is very important in driving a vehicle.

Peripheral vision is the area of your field of vision that is not directly in front of you. You can keep your eyes on what's in front of you while using peripheral vision to see when other automobiles are passing you. For example, peripheral vision can tell you when it's safe to cross a street, when a pedestrian is attempting to cross, or when you need to go to the car wash because a bird just peed on your window.

Peripheral vision works in conjunction with central vision to help you make informed driving decisions. You can spot potential dangers before they enter your field of vision by using your peripheral vision.

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The annual cost of electricity is $28.908 .

work done is equal to energy consumed

therefore total energy is calculated as power times the duration of operation .

[tex]W=P.t[/tex]

where W= work done

            P=power

            t= time of operation

therefore,

total work done (W)=0.06×12×365 kw

=262.8 kw

so total annual electricity bill = 262.8×0.11

=$28.908

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When an individual enters a hypoxic breathing chamber, the changes that would occur would be an increase in the blood pH.

A hypoxic breathing chamber is a type of chamber that is built with the ability to cause an artificial high-altitude conditions.

There are various changes that would occur in the body when placed in a hypoxic state. These changes include the following:

Therefore, when an individual enters a hypoxic breathing chamber, the changes that would occur would be an increase in the blood pH.

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The angular momentum of the tire is 0.394KGm^2/s.

To find the answer, we have to know more about the angular momentum.

                             [tex]L=mvr[/tex]

where, m is mass of th body, v is the linear velocity and r is the radius of the circular orbit.

                 [tex]m=1.4kg\\r=33*10^{-2}m\\w=155rpm=2.58rps[/tex]

                   [tex]v=rw=33*10^{-2}*2.58=0.85m/s[/tex]

                  [tex]L=mvr=1.4*0.85*33*10^{-2}=0.394Kgm^2/s[/tex]

Thus, we can conclude that, the angular momentum of the tire is 0.394KGm^2/s.

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