when f(x)=4 what is the of x

Answer:

32 cubic feet

Step-by-step explanation:

The formula for a cylinder is [tex]\pi r^{2} h[/tex].

The radius of the cylinder is equal to 1.5 feet, since it is [tex]\frac{diameter}{2}[/tex].

Plugging in, the cylinder's full volume is  [tex]6\pi 1.5^2[/tex] which is approximately 42.4 cubic feet.

To find the amount of water when it is 3/4 full, multiply 42.4 x .75, to get around 31.8, and 32 when rounded

Answer:

I think the answer is x= 5, -1

Answer:

i got x= 5,-1

Step-by-step explanation:

i hope this helps and have a good day

Answer:

To find the total price, we need to add the tip and tax to the total bill amount.

First, we need to find the amount of the tip. To do this, we will multiply the total bill by 22% (or 0.22):

$45.65 x 0.22 = $10.04

This means the tip amount is $10.04.

Next, we need to find the amount of tax. To do this, we will multiply the total bill by 5% (or 0.05):

$45.65 x 0.05 = $2.28

This means the tax amount is $2.28.

Finally, we can find the total price by adding the total bill, tip, and tax together:

$45.65 + $10.04 + $2.28 = $57.97

Therefore, the total price is $57.97.

The value of b that makes the area between the two functions equal to 50.5 on the interval [-6.2, 6.2] is 29.64355.

To find the value of b that makes the area between the two functions equal to 50.5 on the interval [-6.2, 6.2], we need to set up an integral and solve for b.

First, we need to find the difference between the two functions:
x2 - x1 = b - y^2

Next, we need to integrate this difference over the given interval:
∫[-6.2, 6.2] (b - y^2) dy

Using the power rule for integration, we get:
[b*y - (y^3)/3] from -6.2 to 6.2

Plugging in the values for the interval and simplifying, we get:
(6.2b - 158.488) - (-6.2b - 158.488)

Simplifying further, we get:
12.4b - 316.976

Now, we can set this equal to the given area and solve for b:
12.4b - 316.976 = 50.5

12.4b = 367.476

b = 367.476/12.4

b = 29.64354839

Rounding to five decimal places, we get:
b = 29.64355

So, the value of b that makes the area between the two functions equal to 50.5 on the interval [-6.2, 6.2] is 29.64355.

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Answer: 11.6

Step-by-step explanation: plug in x for 4. 3.2(4)-1.2 = 11.6

The domain of f⁻¹(x) is [0, ∞) and the range of f⁻¹(x) is [-3, ∞).

The function f(x)=(x+3)² is not one-to-one, as it is a quadratic function and has a parabolic shape. However, we can restrict the domain of the function so that it is one-to-one and increasing. One way to do this is to restrict the domain to be greater than or equal to the x-coordinate of the vertex of the parabola. The vertex of the parabola is at (-3, 0), so we can restrict the domain to be x ≥ -3. In interval notation, this is [-3, ∞).

The inverse function of f(x) can be found by switching the x and y values and solving for y. This gives us:

x = (y+3)²

√x = y+3

y = √x - 3

So the inverse function is f⁻¹(x) = √x - 3. The domain of the inverse function is the range of the original function, and the range of the inverse function is the domain of the original function. Therefore, the domain of f⁻¹(x) is [0, ∞) and the range of f⁻¹(x) is [-3, ∞).

In summary:

f(x)'s domain: [-3, ∞)

f⁻¹(x)'s domain: [0, ∞)

f(x)'s range: [0, ∞)

f⁻¹(x)'s range: [-3, ∞)

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Evaluating the limit given by [tex]{ lim_{(x- > 9)} } (7x-63)/(x^2-2x-63)[/tex], we will obtain as a result [tex]7/16[/tex]

To evaluate the limit, we need to simplify the expression first. We can do this by factoring the numerator and denominator of the fraction:

[tex]lim_{(x->9)} (7x-63)/(x^2-2x-63) = lim_{(x->9)} (7(x-9))/((x-9)(x+7))[/tex]

Next, we can cancel out the [tex](x-9)[/tex] terms in the numerator and denominator:

[tex]lim_{(x->9)} (7)/(x+7)[/tex]

Now, we can plug in the value of x that the limit is approaching (9) into the expression:

[tex]lim_{(x->9)} (7)/(x+7) = (7)/(9+7) = (7)/(16)[/tex]

Therefore, the limit of the expression as x approaches 9 is 7/16.

Answer: [tex]{ lim_{(x->9)} } (7x-63)/(x^2-2x-63) = 7/16[/tex]

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The simple  interest values are all wrong

Simple Interest (S.I) is a method of charging or yielding a specific percentage on the principal amount borrowed/deposited in a particular period. It is calculated using the formula

SI = (Principal*Rate*Time)/100,

a) SI = (450*25.2*3)/100,

SI = %70.2

2) SI = (Principal*Rate*Time)/100,

SI = (250*3.75*5)/100,

$46.875

(3) SI = (Principal*Rate*Time)/100,

SI = (1800*2.1*2)/100,

SI = $75.6

4) SI = (Principal*Rate*Time)/100,

SI = (1500*2.9*2)/100,

SI = $87

5) SI = (Principal*Rate*Time)/100,

SI = (50*1.9*10)/100,

SI =$9.5

6) SI = (Principal*Rate*Time)/100,

SI = (8*0.7*300)/100,

SI = $16.8

7) SI = (Principal*Rate*Time)/100,

SI = (125*2.03*4)/100,

SI = $10.15

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The probability that a randomly selected person had French toast for breakfast is 20%.

Probability describes the result of a random event based on the expected successes or outcomes.

Probability is computed as the quotient of the expected outcomes, events, or successes out of many possible outcomes, events, or successes.

Probability values lie between zero and one based on the degree of certainty or otherwise and can be depicted as percentages, decimals, or fractions.

The total number of survey participants = 20

The number of participants found to be having French toast for breakfast = 4

The probability of selecting a person having French toast for breakfast = 20%,or 0.2, or 1/5 (4/20 x 100)

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Answer:

Answer:

For two linear equations : a₁x + b₁y + c₁ = 0 and a₂x + b₂y + c₂ = 0;

To determine if two such straight lines are parallel, then you should check for the following conditions :

a₁/a₂ = b₁/b₂ ≠ c₁/c₂ , where a,b are coefficients of x and y for each line.

if this condition is true for the coefficients of x,y, and the intercept of lines (c₁ and c₂) then they are parallel.

for instance,

let's say we have two lines :

x + 2y - 4 = 0,

2x + 4y - 12 = 0;

Now to check if they are parallel you simply check if the condition for parallel lines is met or not.

for these two lines :

a₁ = 1 , b₁ = 2, and c₁ = -4;

a₂ = 2, b₂ = 4, and c₂ = -12;

evaluating the values in the condition we have :

[tex]\frac{1}{2}[/tex] = [tex]\frac{2}{4}[/tex] ≠[tex]\frac{-4}{-12}[/tex] ;

since the condition for parallel is true for these two lines, we can conclude they are parallel.

The numbers for which the rational expression is undefined are x=0 and x=-4.

To find the numbers for which the rational expression (7x^(4)+8)/(5x^(2)+20x) is undefined, we need to find the values of x that make the denominator equal to zero. This is because division by zero is undefined.

So, we need to solve the equation 5x^(2)+20x=0 for x.

We can factor out a common factor of 5x from the equation:

5x(x+4)=0

Now, we can use the zero product property to set each factor equal to zero and solve for x:

5x=0 or x+4=0

x=0 or x=-4

So, the numbers for which the rational expression is undefined are x=0 and x=-4.

In summary, the rational expression (7x^(4)+8)/(5x^(2)+20x) is undefined for x=0 and x=-4.

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Answer:

Step-by-step explanation:

There is no graph attached.  

Convert the English phrases into expressions:

1.  "A number (Let's call it x) is equal to the sum of half a second number (y) and 3"

2.  "The first number (x) is also equal to the sum of one-quarter of the second number (y) and 5"

Let's rewrite these in standard form:

x = (1/2)y+3

2x = y + 6

y = 2x - 6

and

x = (1/4)y + 5

4x = y + 20

y = 4x - 20

A plot of these two lines is attached.  Match them with the graph.

a) The average rate of change of f on [−3,1] is 4.

b) The average rate of change of f on [x,x+h] is 3+16/h.

The average rate of change of a function f(x) on an interval [a,b] is given by the formula:

Average rate of change = (f(b)-f(a))/(b-a)

(a) To find the average rate of change of f on [−3,1], we plug in the values of a=-3 and b=1 into the formula:

Average rate of change = (f(1)-f(-3))/(1-(-3))
= (f(1)-f(-3))/4

Now, we need to find the values of f(1) and f(-3) by plugging in the values of x into the given function:

f(1)=1+3(1)-8=-4
f(-3)=-3+3(-3)-8=-20

Plugging these values back into the formula, we get:

Average rate of change = (-4-(-20))/4
= 16/4
= 4

Therefore, the average rate of change of f on [−3,1] is 4.

(b) To find the average rate of change of f on [x,x+h], we plug in the values of a=x and b=x+h into the formula:

Average rate of change = (f(x+h)-f(x))/(x+h-x)
= (f(x+h)-f(x))/h

Now, we need to find the values of f(x+h) and f(x) by plugging in the values of x and x+h into the given function:

f(x+h)=x+h+3(x+h)-8
=4x+3h-8
f(x)=x+3x-8
=4x-8

Plugging these values back into the formula, we get:

Average rate of change = (4x+3h-8-(4x-8))/h
= (3h+16)/h
= 3+16/h

Therefore, the average rate of change of f on [x,x+h] is 3+16/h.

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The debt consolidation loan will cost Sheng an additional $1,997.69 in interest charges compared to his credit cards.

From question, we are to calculate how much more in interest the debt consolidation loan will cost Sheng

To calculate the interest charges for Sheng's credit cards, we need to use the following formula:

Interest Charges = Balance x APR x Number of Days in Billing Cycle / 365

Using this formula, we can calculate the interest charges for each of Sheng's credit cards:

For Credit Card A:

Interest Charges = $2,500 x 0.19 x 30 / 365 = $4.94

For Credit Card B:

Interest Charges = $3,000 x 0.22 x 30 / 365 = $6.01

So, the total interest charges for Sheng's credit cards are:

Total Interest Charges = $4.94 + $6.01 = $10.95

Now, let's calculate the total cost of the debt consolidation loan:

Total Cost = Total Monthly Payments x Number of Payments - Loan Amount

Total Monthly Payments = $179.37

Number of Payments = 6 x 12 = 72

Loan Amount = ?

To find the loan amount, we need to solve for it using the interest rate and the total interest charges:

Loan Amount = Total Interest Charges / (APR x Number of Payments / 12)

Loan Amount = $3,414.39 / (0.107 x 72 / 12) = $25,000

So, the total cost of the debt consolidation loan is:

Total Cost = $179.37 x 72 - $25,000 = $2,008.64

Therefore, the additional interest charges for the debt consolidation loan compared to Sheng's credit cards are:

Additional Interest Charges = Total Cost - Total Interest Charges

Additional Interest Charges = $2,008.64 - $10.95 = $1,997.69

Hence, the debt consolidation loan will cost him an additional $1,997.69 in interest charges

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If the length of the flag is 12 ft more than its width, then the width of the flag is 30ft and length of the flag is 42ft.

Let "w" represent the width of the flag.

We know that the length of the flag is 12 feet more than its width, which means:

⇒ Length = w + 12

We also know that the perimeter of the flag is 144 feet,

The Perimeter of flag can be expressed as:

⇒ Perimeter = 2(Length + Width),

Substituting the expression for Length from above,

We get,

⇒ 144 = 2(w+12 + w)

Simplifying the equation:

We get,

⇒ 144 = 2(2w + 12)

⇒ 72 = 2w + 12

⇒ 60 = 2w

⇒ w = 30

So, width of flag is 30 feet. and Length = w + 12,

⇒ Length = 30 + 12

⇒ Length = 42

Therefore, the dimensions of the flag are 42feet by 30feet.

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Marco will need 2025 pounds of marble.

The ratio is defined as the relationship between two similar magnitudes in terms of the number of times the first includes the second.

Let's say that Marco mixes 1 bag of quartz with x pounds of marble. Then the ratio of quartz to marble in this bag is:

135 pounds quartz : x pounds marble

3 pounds quartz : x/45 pounds marble

Now we know that the ratio of quartz to marble in one bag is 3: (x/45). Since the ratio stays the same for every bag, we can set up a new proportion using the total amount of quartz and marble:

135 pounds quartz : x pounds marble = total pounds quartz : total pounds marble

We know the total pounds of quartz is 135. Let's call the total pounds of marble "m".

Substituting these values into the proportion, we get:

135 : x = 135 : m/45

To solve for x, we can cross-multiply and simplify:

135(m/45) = 135x

3m = 45x

m = 15x

So, Marco will need 15 times as many pounds of marble as he has of quartz, or:

m = 15 × 135 = 2025 pounds of marble.

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Answer: y = 1/3x + 2

Step-by-step explanation:

y =  mx+b

to find m: m = 3 - 5 / -3 - (- 9)  = -2 / 6 = - 1 / 3

to find b:

3 = -1 / 3 (-3) + b

3 = 1 + b

b = 2

Using the scale factors obtained the values are -

The value of k is 8, since g(−2) = 8.

The value of k is 8, since g(−2) = 8.

The value of k is 8, since g(−2) = 1.

The value of k is 4, since g(−2) = 2.

What is scale factor?

The scale factor of a shape refers to the amount by which it is increased or shrunk. It is applied when a 2D shape, such as a circle, triangle, square, or rectangle, needs to be made larger.

For each part, we can use the given table to determine how the transformation affects the function values -

g(x) = f(2x)

This transformation is a horizontal compression by a factor of 2.

To see this, notice that when we evaluate g at x = -1, we get the same value as f evaluated at x = -2.

Similarly, when we evaluate g at x = 0, we get the same value as f evaluated at x = 0.

And so on. In other words, the function values of g(x) are the same as the function values of f(x) at every other point (starting with x = -2).

So, g(x) is a compressed version of f(x) horizontally by a factor of 2.

Therefore, the value of k is 8, since g(−2) = 8 = f(2×(-2)).

g(x) = 2f(x)

This transformation is a vertical stretch by a factor of 2.

To see this, notice that every value of g(x) is twice the corresponding value of f(x).

So, g(x) is a stretched version of f(x) vertically by a factor of 2.

Therefore, the value of k is 8, since g(−2) = 2f(−2) = 2×4 = 8.

g(x) = f(x/2)

This transformation is a horizontal stretch by a factor of 2.

To see this, notice that when we evaluate g at x = -2, we get the same value as f evaluated at x = -4.

Similarly, when we evaluate g at x = -1, we get the same value as f evaluated at x = -2.

And so on. In other words, the function values of g(x) are the same as the function values of f(x) at every other point (starting with x = -4).

So, g(x) is a stretched version of f(x) horizontally by a factor of 2.

Therefore, the value of k is 8, since g(−2) = f(−1) = 1.

g(x) = (1/2)f(x)

This transformation is a vertical compression by a factor of 2.

To see this, notice that every value of g(x) is half the corresponding value of f(x).

So, g(x) is a compressed version of f(x) vertically by a factor of 2.

Therefore, the value of k is 4, since g(−2) = (1/2)f(−2) = (1/2)×4 = 2.

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Answer:

Let x be the score Natasha needs to earn on her next test to reach an average of 90%.

To find x, we can use the formula for the average:

average = (sum of scores) / (number of scores)

We know that Natasha has taken 5 tests so far, with scores of 94%, 89%, 88%, 92%, and 85%. We can plug these values into the formula and solve for x:

90% = (94% + 89% + 88% + 92% + 85% + x) / 6

Multiplying both sides by 6, we get:

540% = 448% + x

Subtracting 448% from both sides, we get:

92% = x

Therefore, Natasha needs to earn a score of at least 92% on her next test to reach an average of 90%.

Answer:

  q = 250,000·(0.6^t)

Step-by-step explanation:

You want an equation that models the graph of an exponential function that has an initial value of 250,000 and a value of 150,000 after 1 week.

An exponential function has the form ...

  q = a·b^t

where 'a' is the initial value, and 'b' is the decay factor over a period of one time unit of t.

The graph with this problem shows the initial value (for t=0) to be a=250,000. The decay factor will be ...

  b = 150,000/250,000 = 3/5 = 0.6

Then the exponential function can be written as ...

  q = 250000·(0.6^t) . . . . . . where t is in weeks

The angle between \( \mathbf{u}=\langle-4,-1\rangle \) and \( \mathbf{v}=\langle-5,-2\rangle \) is approximately 12.5 degrees. To the nearest tenth of a degree, we can round this to 12.5 degrees.

To find the angle between two vectors \( \mathbf{u} \) and \( \mathbf{v} \), we can use the formula:
\[ \cos \theta = \frac{\mathbf{u} \cdot \mathbf{v}}{\| \mathbf{u} \| \| \mathbf{v} \|} \]
where \( \theta \) is the angle between the vectors, \( \mathbf{u} \cdot \mathbf{v} \) is the dot product of the vectors, and \( \| \mathbf{u} \| \) and \( \| \mathbf{v} \| \) are the magnitudes of the vectors.

First, we need to find the dot product of \( \mathbf{u} \) and \( \mathbf{v} \):
\[ \mathbf{u} \cdot \mathbf{v} = (-4)(-5) + (-1)(-2) = 20 + 2 = 22 \]

Next, we need to find the magnitudes of \( \mathbf{u} \) and \( \mathbf{v} \):
\[ \| \mathbf{u} \| = \sqrt{(-4)^2 + (-1)^2} = \sqrt{16 + 1} = \sqrt{17} \]
\[ \| \mathbf{v} \| = \sqrt{(-5)^2 + (-2)^2} = \sqrt{25 + 4} = \sqrt{29} \]

Now we can plug these values into the formula and solve for \( \theta \):
\[ \cos \theta = \frac{22}{\sqrt{17} \sqrt{29}} \]
\[ \theta = \cos^{-1} \left( \frac{22}{\sqrt{17} \sqrt{29}} \right) \]

Using a calculator, we find that \( \theta \approx 12.5 \) degrees.

Therefore, the angle between \( \mathbf{u}=\langle-4,-1\rangle \) and \( \mathbf{v}=\langle-5,-2\rangle \) is approximately 12.5 degrees. To the nearest tenth of a degree, we can round this to 12.5 degrees.

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The vector form of the general solution of the given system of linear equations is given by:

{x} = {x1, x2, x4} = s { -1, 1, 0} + t { -2, 0, 1}

where s and t are arbitrary constants.

To find the vector form of the general solution, we need to find the null space of the coefficient matrix of the system of linear equations. The coefficient matrix of the system is:

A = [ 1 1 0 1; 1 2 0 4; 2 0 0 -4]

The null space of A is the set of all vectors x such that Ax = 0. We can find the null space of A by reducing A to its reduced row echelon form:

A = [ 1 0 0 -2; 0 1 0 1; 0 0 0 0]

From the reduced row echelon form of A, we can see that x1 and x2 are the leading variables and x4 is the free variable. Therefore, the general solution of the system of linear equations is given by:

x1 = -2x4
x2 = x4
x4 = x4

We can write the general solution in vector form as:

{x} = {x1, x2, x4} = x4 { -2, 1, 1}

Since x4 is an arbitrary constant, we can write the general solution in terms of two arbitrary constants s and t as:

{x} = {x1, x2, x4} = s { -1, 1, 0} + t { -2, 0, 1}

Therefore, the vector form of the general solution of the given system of linear equations is:

{x} = {x1, x2, x4} = s { -1, 1, 0} + t { -2, 0, 1}

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Using the Gaussian elimination method, the general solution is:               [tex]\[ x = -31t + 6 \][/tex], [tex]\[ y = 5 \][/tex], [tex]\[ z = 31t \][/tex].

To solve this system of equations, we can use the Gaussian elimination method. This method involves creating a matrix with the coefficients of the equations and using row operations to reduce the matrix to a form that can be easily solved.

First, we create a matrix with the coefficients of the equations:

[tex]\[ \left( \begin{array}{ccc|c} 1 & 1 & 1 & -1 \\ 2 & 3 & 2 & 3 \\ 2 & 1 & 2 & -7 \\ 1 & -3 & 2 & 10 \\ -1 & 3 & -1 & -6 \\ -1 & 3 & 2 & 6 \\ 6 & -2 & 2 & 4 \\ 3 & -1 & 2 & 2 \\ -12 & 4 & -8 & 8 \end{array} \right) \][/tex]

Next, we use row operations to reduce the matrix to a form that can be easily solved:

[tex]\[ \left( \begin{array}{ccc|c} 1 & 1 & 1 & -1 \\ 0 & 1 & 0 & 5 \\ 0 & -1 & 0 & -5 \\ 0 & -4 & 1 & 11 \\ 0 & 4 & 0 & -5 \\ 0 & 4 & 1 & 7 \\ 0 & -8 & -4 & 10 \\ 0 & -4 & -1 & 5 \\ 0 & 8 & 4 & -4 \end{array} \right) \][/tex]

[tex]\[ \left( \begin{array}{ccc|c} 1 & 1 & 1 & -1 \\ 0 & 1 & 0 & 5 \\ 0 & 0 & 0 & 0 \\ 0 & 0 & 1 & 31 \\ 0 & 0 & 0 & 0 \\ 0 & 0 & 1 & 27 \\ 0 & 0 & -4 & 50 \\ 0 & 0 & -1 & 25 \\ 0 & 0 & 4 & -44 \end{array} \right) \][/tex]

[tex]\[ \left( \begin{array}{ccc|c} 1 & 0 & 1 & -6 \\ 0 & 1 & 0 & 5 \\ 0 & 0 & 1 & 31 \\ 0 & 0 & 0 & 0 \\ 0 & 0 & 0 & 0 \\ 0 & 0 & 0 & -4 \\ 0 & 0 & 0 & 174 \\ 0 & 0 & 0 & 56 \\ 0 & 0 & 0 & -168 \end{array} \right) \][/tex]

From this reduced matrix, we can see that there are infinitely many solutions to this system of equations. The general solution can be written as:
[tex]\[ x = -31t + 6 \][/tex]
[tex]\[ y = 5 \][/tex]
[tex]\[ z = 31t \][/tex]
Where t is any real number.

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The answer is (1) x = 22.5; (2) x = 16.7; (3) x = 13.5; (4) x = 16.8; (5) x = 24.5; (6) x = 16.15; (7.a) height of the image on film is 11.2mm; (7.b) distance between camera and her friend is 1,875mm.

(1) We can see that in the given figure all three corresponding angles are congruent and all three corresponding sides are in equal proportion so, these are similar triangles.

As per properties of similar triangle:

Three pairs of corresponding sides are proportional i.e. Two pairs of corresponding sides are proportional and the corresponding angles between them are equal.

                        Therefore, [tex]\frac{32}{24} =\frac{30}{x}[/tex],

then by cross multiplying them, we get,

                                        32x = 720

                                            x = 720/32

                                           x = 22.5

(2) As, this is already given that these are similar triangle and by applying the properties of similar triangle we get,

                                           [tex]\frac{39}{26} =\frac{25}{x}[/tex]

                                         39x = 650

                                             x = [tex]16\frac{2}{3}[/tex]

                                            x = 16.7

(3) As these are similar triangle again we can say that,

                                        [tex]\frac{2x+1}{x+4} =\frac{40}{25}[/tex]

                                 40(x + 4) = 25(2x + 1)

                                40x + 160 = 50x + 25

                                          40x = 50x - 135

                                          -10x = -135

                 (by cancelling (-) sign from both sides we get,

                                              x = 135/10

                                             x = 13.5

(4) By applying similar triangle's property, we can get

                                           [tex]\frac{20}{30} =\frac{28-x}{x}[/tex]

                                         20x = 840 - 30x

                                         50x = 840

                                             x = 840/50

                                             x = 16.8

(5) As ΔJKL [tex]\sim[/tex] ΔNPR,

                                           [tex]\frac{KM}{PT} =\frac{KL}{PR}[/tex]

                                          [tex]\frac{18}{15.75} =\frac{28}{x}[/tex]

                                            18x = 441

                                                x = 441/18

                                               x = 24.5

(6) As ΔSTU [tex]\sim[/tex] ΔXYZ,

                                         [tex]\frac{UA}{ZB} =\frac{UT}{ZY}[/tex]

                                        [tex]\frac{6}{11.4} =\frac{8.5}{x}[/tex]

                                          6x = 96.6

                                            x = 96.6/6

                                            x = 16.15

(7.a) First we have to change 3 m and 140 cm into mm(millimeters).

So, 1m = 1000 mm

     3m = 3000mm.

And 1cm = 10 mm

   140cm = 1400 mm.

Then to find the height of the image on the film, we have to solve:

                                          [tex]\frac{24}{3000} =\frac{x}{1400}[/tex]

             by cross multiplication we get,

                                      3000x = 33,600

                                               x = 33,600/3000

                                              x = 11.2 mm

the height of the image on the film is 11.2millimeters.

(7.b) For this also, we have to find x by solving the equation:

                                            [tex]\frac{24}{3000} =\frac{15}{x}[/tex]

                                            24x = 45,000

                                                x = 45,000/24

                                              x = 1,875 mm

The distance between camera and her friend is 1,875 millimeters.

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Full question is given below in the image.

The recursive formula for an, the nth term of the sequence is a(n) = a(n - 1) + 2 where a(1) = 2

From the question, we have the following parameters that can be used in our computation:

2, 6, 10, 14, ....

The above definitions imply that we simply add 4 to the previous term to get the current term

Using the above as a guide,

So, we have the following representation

a(n) = a(n - 1) + 2

Hence, the sequence is a(n) = a(n - 1) + 2 where a(1) = 2

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The solution to the inequality is option C. x > -9.

Linear inequalities are defined as those expressions which are connected by inequality signs like >, <, ≤, ≥ and ≠ and the value of the exponent of the variable is 1.

The given inequality is,

-1/3x + 1/2 < 3.5

We have to find the solution of the inequality.

-1/3 x + 0.5 < 3.5

Subtracting both sides by 0.5, we get,

-1/3 x < 3.5 - 0.5

-1/3 x < 3

Multiplying both sides by -3,

x > -9

Hence the solution is x > -9.

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Answer:

16

Step-by-step explanation:

g(x)=-5x+1

g(-3)

x=-3

-5(-3) +1

15+1

16

Answer:

See below.

Step-by-step explanation:

For this problem, we are asked to find the value of g(-3).

We are given a Linear Function.

A Linear Function is a Polynomial Function that is commonly graphed. This function most of the time will simply be represented as a straight line when graphed.

For this problem;

[tex]g(x)=-5x+1 \ Find \ g(-3).[/tex]

We simply need to substitute -3 in for x.

[tex]g(-3)=-5(-3)+1[/tex]

Simplify:

[tex]g(-3)=16.[/tex]

Our final answer is g(-3) = 16.

The function is decreasing in the interval (3, ∞).

f(x) = -x² + 6x - 4

Differentiate the equation with respect to 'x'.

f'(x) = -2x + 6

Put f'(x) = 0

-2x + 6 = 0

x = 6/2

x = 3 (critical point)

Now, write the function as:

f(x) = -x² + 6x - 4

-(x² - 6x + 4) (negative form)

Thus, the function is decreasing in the interval (3, ∞)

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