a. Four data structures which can be used in data analytics:
ArraysStacksQueuesHash tablesbb. Relevant examples with code snippets with explanation:
1. Arrays
Arrays are used in data analytics because of their ability to store a fixed number of elements of the same data type. They are used to manipulate numerical data and are faster than lists. Python has an in-built array module that can be used to create arrays. The following is an example of creating an array of integers:
```
import array as arr
my_array = arr.array('i', [1, 2, 3, 4, 5])
print(my_array)
```
Output: array('i', [1, 2, 3, 4, 5])
2. Lists
Lists are another data structure that is used in data analytics. They are used to store data of different types. Lists are dynamic and can be resized. Python lists are created using square brackets [] or by using the list() function. The following is an example of creating a list:
```
my_list = [1, 'hello', 3.5, True]
print(my_list)
```
Output: [1, 'hello', 3.5, True]
3. Tuples
Tuples are similar to lists but they are immutable. They are used to store data of different types. Python tuples are created using parentheses () or by using the tuple() function. The following is an example of creating a tuple:
```
my_tuple = (1, 'hello', 3.5, True)
print(my_tuple)
```
Output: (1, 'hello', 3.5, True)
4. Dictionaries
Dictionaries are used to store key-value pairs. They are used to represent data in a structured way. Python dictionaries are created using curly braces {} or by using the dict() function. The following is an example of creating a dictionary:
```
my_dict = {'name': 'John', 'age': 25, 'gender': 'male'}
print(my_dict)
```
Output: {'name': 'John', 'age': 25, 'gender': 'male'}
In conclusion, these four data structures - Arrays, Lists, Tuples, and Dictionaries - are commonly used in data analytics in Python. They help to store and manipulate data in a structured way.
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Research policies and procedures at several organizations surrounding either cloud computing or VPNs. You may also want to research the controversy surrounding companies that want to provide these services commercially for certain popular applications, like Microsoft Office, in the context of what they learn from their policy and procedure research.
Research policies and procedures at several organizations surrounding either cloud computing or VPNsCloud computing policies and procedures are essential to minimize the risk of data breach, maintain compliance, and protect critical information. The following are some of the essential policies and procedures to consider:Data encryption policies: For secure transmission of data, cloud computing requires encryption of all data. The policy should outline what type of encryption is used and the key management process.
Access control policies: This policy outlines how the system will provide access to data stored on the cloud. It should include information about authentication and authorization protocols, as well as the use of multi-factor authentication.Backup and recovery policies: In case of a disaster, it is essential to have backup and recovery policies to ensure data is not lost. The policy should include how backups are created and stored, how often backups are taken, and the recovery time objective.Cloud service-level agreements: The service level agreement (SLA) outlines what is included in the service, such as uptime, performance, and support.
The SLA should also include remedies for not meeting these service levels.Virtual Private Network (VPN) policies and procedures are equally essential and should cover the following:Access control policies: This policy outlines who has access to the VPN and how the system verifies user identity.Configuration management policies: VPN servers and clients should be configured according to standards to ensure security and consistent functionality. The policy should include a configuration baseline that all systems must follow.Connection policies: The connection policy defines how long a user is connected to the VPN and what protocols are permitted during the connection.Session management policies: The session management policy outlines what users are permitted to do during their sessions. It should define what they can access and how long they can stay connected. Remote access policies: The remote access policy outlines how users can access the VPN, such as from a remote location.
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Write a java program that calculates and outputs the average of 1, 7, 9 and 34. Make sure to comment your code appropriately and follow all the conventions of java programming language with regards to class, variable and constant names. (15 points) You will create a Java application with a main() method and write the necessary programming instructions to complete the program. . Inputs: Create necessary variables of appropriate data types to store the values. (inputs) Create a variable of appropriate data type to store the average. Calculate the average and store in the variable created earlier to store the average Print the average to the terminal window. • Perform calculations Output Results:
The Java program provided below calculates and outputs the average of the numbers 1, 7, 9, and 34. It follows the conventions of the Java programming language, including appropriate variable and constant naming.
The program uses a main() method to execute the necessary instructions. It declares variables to store the input values and the calculated average.
The average is computed by summing the numbers and dividing by the count. Finally, the program prints the average to the terminal window.
public class AverageCalculator {
public static void main(String[] args) {
// Declare variables
int num1 = 1;
int num2 = 7;
int num3 = 9;
int num4 = 34;
int count = 4;
double average;
// Calculate average
average = (num1 + num2 + num3 + num4) / (double) count;
// Print the average
System.out.println("The average is: " + average);
}
}
In this program, we declare variables of type int to store the given numbers (num1, num2, num3, num4) and the count of numbers (count). We also declare a variable average of type double to store the calculated average.
To calculate the average, we sum the numbers and divide the result by the count. To ensure the division produces a double result, we cast the count variable to double.
Finally, we use the System.out.println() statement to print the average to the terminal window. The average is concatenated with the output message for display.
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Using your browser, connect to each http and https port that you enumerated on MS2, Rather than taking screenshots, please provide me with a THOROUGH explanation of what you would do and the commands you would use.. Make sure to include the address you used.
To connect to each HTTP and HTTPS port on MS2, you can use the Telnet command in your browser. For HTTP, the default port is 80, and for HTTPS, it is 443.
To connect to the HTTP and HTTPS ports on MS2, you can use Telnet, which is a network protocol used for establishing text-based connections. In this case, we'll be using Telnet through a web browser.
1. Open your web browser and navigate to the Telnet website.
2. In the address bar, enter the IP address or hostname of MS2, followed by a colon and the port number you want to connect to. For HTTP, use port 80, and for HTTPS, use port 443. For example, if the IP address of MS2 is 192.168.1.100, you would enter "192.168.1.100:80" to connect to the HTTP port and "192.168.1.100:443" for the HTTPS port.
By using the Telnet command in your browser, you establish a connection to the specified port on MS2. This allows you to interact with the server and retrieve information. It's important to note that Telnet may not be available by default on all browsers or may require additional configuration. If your browser doesn't support Telnet, you can use command-line tools like PuTTY or Telnet clients to establish the connection.
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[MTLAB APPLICATION] Can anyone help me create a code? When the user presses the button "Insert Matrix Value", a dialogue box will pop up, and the user can input any matrix value. Then after that, when the user presses the "add variable" button, the dialogue box will pop up, and the user can input the variable name for the previous matrix made by the user. For example, I pressed the "Insert Matrix value" button, then I inserted the matrix value I wanted like [1 2 3; 4 5 6; 7 8 9], so that will be my first matrix, and then after I pressed OK, I will press the "Add variable" button and I will put it as "A", so that will be the variable name of the first matrix. It will be in the workspace as A = [1 2 3; 4 5 6; 7 8 9]. Then I will make another matrix by pressing the same 2 buttons and it will be B = [1 2 3; 4 5 6; 7 8 9]. The user can create many matrices.
The MATLAB application that allows the user to input matrix values and assign variable names to those matrices is given in the image attached.
What is the MATLAB application?To initiate the GUI window, all you need to do is execute the function matrixCreatorGUI within the MATLAB command window. Subsequently, you can select the "Insert Matrix Value" option and add a matrix value in the provided dialogue box.
Thereafter, select the option "Add Variable" to input a name for the variable within the pop-up dialogue box. Once you select OK, the variable name will be saved in the variableNames variable, while the associated matrix will be established in the workspace.
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Name your Jupyter notebook EnergyTable. Write a program that calculates the energy needed to heat water from an initial temperature to a final temperature. Computer Programming 02/21/2022 This program should prompt the user to enter the amount of wat er in kilograms and the initial the energy is: and final temperatures in Celsius of the water. The formula to compute = M* (finalTemperature initialTemperature) * 4184 where M is the weight of water in kilograms, temperatures are in degrees Celsius, and energy Qis measured in joules. The program shall report the input quantities and the computed energy in a tabulated format. Below are two sample runs: (Sample Run 1, bold is input from keyboard) Enter water's weight in kg: 55.5 Enter the initial temperature in "Celsius": 3.5 15.5 Enter the final temperature in "Celsius": Water's weight: Initial temperature: Final temperature: Energy required to heat up water: Enter water's weight in kg: 3.249 Enter the initial temperature in "Celsius": 11.732 Enter the final temperature in "Celsius": 17.441 3.25 kg Water's weight: 11.73 degree Initial temperature: 17.44 degree Final temperature: 77607.10 joules Energy required to heat up water: (Sample Run 2, bold is input from keyboard) 55.50 kg 3.50 degree 15.50 degree 1625484.00 joules
The program that calculates the energy needed to heat water from an initial temperature to a final temperature is given in the image attached.
What is the program about?The initial step of the code involves utilizing the input() function to ask the user for the weight of water in kilograms. Afterwards, the value entered is transformed into a decimal format by utilizing the float() function and saved under the variable name weight.
Thereafter, utilizing the above method, the program requests that the user input the starting and concluding Celsius temperatures of the liquid. The variables initial_temp and final_temp hold the input values.
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What is the binary bit pattern of +12 in the bias of 127? Assume that the bit pattern consists of 8 bits. Show your work.
At a significance level of 0.01, there is not enough evidence to support the claim that the rate of left-handedness among males is less than that among females.
To test the claim that the rate of left-handedness among males is less than that among females, we need to set up the null hypothesis (H0) and the alternative hypothesis (H1).
p1 = proportion of left-handed males
p2 = proportion of left-handed females
Null hypothesis (H0): p1 ≥ p2 (The rate of left-handedness among males is greater than or equal to that among females)
Alternative hypothesis (H1): p1 < p2 (The rate of left-handedness among males is less than that among females)
Now, let's proceed with the steps to test the hypothesis:
(a) Determine the significance level:
The significance level is given as 0.01, which means we will reject the null hypothesis if the probability of observing the sample data, assuming the null hypothesis is true, is less than 0.01.
(b) Calculate the sample proportions:
[tex]\hat p_1[/tex] = Number of left-handed males / Total number of males
= 24 / (24 + 207)
= 24 / 231
≈ 0.1039
[tex]\hat p_2[/tex] = Number of left-handed females / Total number of females
= 69 / (69 + 462)
= 69 / 531
≈ 0.1297
(c) Perform the hypothesis test:
To test the hypothesis, we need to calculate the test statistic and compare it to the critical value.
The test statistic for comparing two proportions is given by:
z = ([tex]\hat p_1[/tex] - [tex]\hat p_2[/tex] ) / √(([tex]\hat p_1[/tex](1-[tex]\hat p_1[/tex]) / n1) + ([tex]\hat p_2[/tex] (1-[tex]\hat p_2[/tex] ) / n₂))
Where:
n1 = Total number of males
n2 = Total number of females
In this case, n1 = 24 + 207 = 231 and n2 = 69 + 462 = 531.
Substituting the values:
z = (0.1039 - 0.1297) / √((0.1039(1-0.1039) / 231) + (0.1297(1-0.1297) / 531))
Calculating z, we get z ≈ -1.766
To find the critical value, we can use a standard normal distribution table or a statistical software. For a significance
level of 0.01 (one-tailed test), the critical value is approximately -2.33.
Since the test statistic (z = -1.766) does not exceed the critical value (-2.33), we fail to reject the null hypothesis.
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Concrete is a mixture of Portland cement, sand, and gravel. A distributor has three batches for contractors. Batch 1 contains cement, sand, and gravel mixed in proportions 1/8, 3/8, 4/8; batch 2 has the proportions 2/10, 5/10,3/10; and batch 3 has the proportions 2/5, 3/5, 0/5. It is known that the total amount of cement used in batches is equal to 2.3 cubic yards. The total amount of sand and gravel are given to be 4.8 and 2.9 cubic yards respectively. Calculate the amount of each batch by introducing matrix operations.
Hint: write down the equations first. Then create a coefficient matrix.Calculate the approximate root of the expression using Python. Submit your python file.
To solve the given problem using matrix operations, we can represent the proportions of cement, sand, and gravel in each batch as a system of linear equations. Let's denote the amount of each batch as x1, x2, and x3, respectively.
The equations can be written as:
1/8 × x1 + 2/10 × x2 + 2/5 × x3 = 2.3 (Cement equation)
3/8 × x1 + 5/10 × x2 + 3/5 × x3 = 4.8 (Sand equation)
4/8 × x1 + 3/10 × x2 + 0/5 × x3 = 2.9 (Gravel equation)
We can represent this system of equations in matrix form as AX = B, where A is the coefficient matrix, X is the unknown variable matrix, and B is the result matrix:
A = |1/8 2/10 2/5|
|3/8 5/10 3/5|
|4/8 3/10 0/5|
X = |x1|
|x2|
|x3|
B = |2.3|
|4.8|
|2.9|
To find the unknown variable matrix X, we can calculate X = A⁻¹ × B, where A⁻¹ is the inverse of matrix A.
Now, let's use Python to calculate the approximate values of x1, x2, and x3 using matrix operations:
python
Copy code
import numpy as np
A = np.array([[1/8, 2/10, 2/5],
[3/8, 5/10, 3/5],
[4/8, 3/10, 0/5]])
B = np.array([2.3, 4.8, 2.9])
X = np.linalg.inv(A).dot(B)
print("Approximate values of x1, x2, x3:")
print(X)
Save the above code in a Python file, for example, matrix_operations.py, and run it to obtain the approximate values of x1, x2, and x3. The output will provide the amounts of each batch required to achieve the given proportions of cement, sand, and gravel.
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Which of the following is true of a decision tree? Group of answer choices
Each non-leaf node is labelled with a class
Each leaf node is labelled with a class
Each root node is labelled with a class
Each node is labelled with a class.
Among the given options, the statement "Each leaf node is labelled with a class" is true for a decision tree. The labels assigned to the leaf nodes represent the predicted class or outcome based on the features and decisions made along the branches of the tree.
In a decision tree, each leaf node corresponds to a specific outcome or class. These leaf nodes are assigned labels that represent the predicted class based on the feature values and decisions made along the branches of the tree.
The decision tree algorithm determines the splitting criteria at non-leaf nodes based on the feature values to guide the classification process. However, it is at the leaf nodes where the final predicted class labels are assigned. Thus, the statement "Each leaf node is labelled with a class" accurately describes the nature of a decision tree.
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Section A:
This is a theory based question.
Question 2
Explain the following terms:
a) Human Computer Interaction b) Usability c) User Interface d) Metaphor
a) Human-Computer Interaction (HCI) refers to the study and design of interactions between humans and computer systems. b) Usability relates to the ease with which users can interact with a system, emphasizing effectiveness, efficiency, and user satisfaction. c) User Interface (UI) encompasses the visual and interactive elements through which users interact with a software application or system. d) Metaphor in HCI involves using familiar concepts or representations to aid users in understanding and interacting with digital interfaces.
a) Human-Computer Interaction (HCI) is a field that examines the interactions between humans and computers. It encompasses the study of how users interact with technology, including hardware, software, and interfaces. HCI focuses on designing systems that are user-friendly, efficient, and meet users' needs, aiming to improve the overall user experience.
b) Usability refers to the extent to which a system is easy to use and understand. It encompasses various factors, including the effectiveness and efficiency with which users can accomplish tasks, as well as their satisfaction and comfort while using the system. Usability considerations involve aspects such as clear navigation, intuitive interactions, minimal learning curve, and effective feedback mechanisms.
c) User Interface (UI) refers to the visual and interactive elements through which users interact with a software application or system. It includes components like menus, buttons, forms, and graphical representations that allow users to input commands and receive feedback from the system. The design of a user interface aims to make interactions intuitive, visually appealing, and efficient, ensuring that users can easily navigate and accomplish tasks within the system.
d) Metaphor in HCI involves using familiar concepts or representations to aid users in understanding and interacting with digital interfaces. It involves mapping real-world objects or experiences onto digital interfaces, making them more relatable and easier to comprehend. For example, using a folder icon to represent a directory or using a trash can icon for deleting files. Metaphors provide users with mental models that leverage their existing knowledge and experiences, facilitating their understanding and use of complex digital systems.
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Design and implement "3 bit register" in
logisim/circuitverse, and Store "1 0 1" parellelly.
A 3-bit register is composed of three flip-flops. A flip-flop is a circuit element that has two stable states and is used to store one bit of memory.
A D flip-flop is employed in this design, where the D input is linked to the output of the Q’ of the preceding stage. The circuitry for the 3-bit register is shown below:
1. A new circuit is opened in Logisim/Circuitverse.2. Choose the "D flip-flop" component from the "memory" option in the component bar.3. Drag and drop three D flip-flop components to the design area. Connect the output of one flip-flop to the D input of the subsequent flip-flop.4. Name the outputs as Q2, Q1, and Q0 for the three flip-flops.5. Next, add a switch component from the "Input/Output" option and connect it to the D input of the flip-flops.6. Assign the switch's name as "D."7. The three-bit register is now ready for simulation and testing.Learn more about d-flip-flops at
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1)For each of OMR, OCR, and MICR give an application in which that technology is frequently used.
2)Identify and discuss two (2) benefits of using direct data entry devices
3) Identify and discuss three (3) benefits of effective database management within an organization.
1) OMR (Optical Mark Recognition) is used in various applications. These include surveys, voting systems, and other forms where handwritten or printed responses must be recorded.OCR (Optical Character Recognition) is primarily used to digitize printed or handwritten text documents for indexing, archiving, and conversion into editable formats. MICR (Magnetic Ink Character Recognition) is used to process paper checks and financial documents.2)
Direct data entry devices have many benefits. They eliminate the need for physical storage of documents and reduce the chance of errors during data entry. The two benefits of using direct data entry devices are:1)Reduced need for physical storage: Direct data entry devices are electronic. Therefore, they eliminate the need for physical storage of documents. They also reduce the need for storage space, paper, and ink, which can save money.2)Reduced error rate: Direct data entry devices can be programmed to detect errors and inconsistencies. This reduces the chance of errors during data entry.3) Effective database management has many benefits for an organization.
Three of these benefits are:1)Improved decision making: Effective database management allows an organization to store and analyze data. This helps managers make informed decisions based on the data they have collected.2)Increased productivity: Effective database management helps reduce the time spent on data entry and retrieval. This allows employees to focus on more important tasks, which can increase productivity.3)Better customer service: Effective database management allows an organization to store customer information. This information can be used to provide better customer service.
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In java please Implement a static method in a Driver, called countOccurrences, that takes two input parameters, a stack called s, and an integer value called val. The method returns as output an integer value that represent how many times val appears in s. Note s must remain unchanged
The java code that Implement a static method in a Driver, called countOccurrences, that takes two input parameters, a stack called s, and an integer value called val is given in the image attached.
What is the java code?This approach involves the use of a temporary stack (tempStack) to maintain the initial sequence of items in the input stack (s). We loop through the initial stack, tallying the number of instances of val, and then add the elements to a secondary stack.
Ultimately, one can reinstate the initial stack by extracting elements from the provisional stack and appending them to s. The outcome is provided as the tally.
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Properly designed test case does not have to include:
a) input data
b) the expected result
c) test preconditions
d) all of the above are necessary
Answer:
C
Explanation:
test cases are quite clearly defined and need all the data to ensure calid results
Please Please help me answer all this question. It would be your biggest gift for me if you can answer all this question. Thank you so much 30 points (a.) Make a Python code that would find the root of a function as being described in the image below. (b.) Apply the Python code in (a.) of the function of your own choice with at least 3 irrational roots, tolerance = 1e-5, N=50. (c.) Show the computation by hand with interactive tables and graphs. The bisection method does not use values of f(x): only their sign. However, the values could be exploited. One way to use values of f(x) is to bias the search according to the value of f(x); so instead of choosing the point po as the midpoint of a and b, choose it as the point of intersection of the x-axis and the secant line through (a, F(a)) and (b, F(b)). Assume that F(x) is continuous such that for some a and b, F(a) F(b) <0. The formula for the secant line is y-F(b) F(b)-F(a) b-a x-a Pick y = 0, the intercept is P₁ = Po= b - F(b)(a) F(b). If f(po) = 0, then p = po. If f(a) f(po) <0, a zero lies in the interval [a, po]. so we set b = po. If f(b)f (po) <0, a zero lies in the interval [po, b], so we set a = po. Then we use the secant formula to find the new approximation for p: b-a P2= Po=b- -F(b). F(b)-F(a) We repeat the process until we find an pn with Pn-Pn-1|< Tol, or f(pn)|< Toly.
The python code that implements the bisection method with the secant bias for finding the root of a function is given in the image attached.
What is the Python code?In the code, to discover the root of an equation, one need to create a function f(x) within the code that represents the equation you're interested in.
The function f(x) is established in the sample code to be x raised to the power of three, minus twice the value of x, and subtracted by five. Upon executing the code, it will output an estimated solution in the event that it is discovered within the designated number of iterations.
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Debug
// This pseudocode should create a quarterly sales report for a small business
// Input is total sales for each of the three months in the quarter
// output ranks the three months from most sales to least
start
Declarations
num month1
num month2
num month3
input month1, month2, month3
if month1 > month2 AND month3 > month1 then
output "Month 1 was highest"
if month2 > month1 then
output "Month 2 was second"
output "Month 3 was last"
else
output "Month 3 was second"
output "Month 2 was last"
endif
else
if month2 > month3 AND month2 > month3 then
output "Month 2 was highest"
if month1 > month2 then
output "Month 1 was second"
output "Month 3 was last"
else
output "Month 3 was second"
output "Month 2 was last"
endif
else
output "Month 2 was highest"
if month1 > month3 then
output "Month 3 was second"
output "Month 2 was last"
else
output "Month 3 was second"
output "Month 1 was last"
endif
endif
endif stop
Debugging is the method of identifying, locating, and removing mistakes, referred to as bugs, from a software program. Debugging is a multistep process that requires a great deal of persistence and attention to detail. Following are the steps that should be considered while debugging a program:Step 1: Repeat the errorStep 2: Find the origin of the errorStep 3: Analyze the code for mistakes that could lead to an errorStep
4: Breakpoints should be utilizedStep 5: Analyze the dataStep 6: Reverse-engineer the problem statementStep 7: Recognize and learn from errorsCode snippet for the problem mentioned above:Debug// This pseudocode should create a quarterly sales report for a small business// Input is total sales for each of the three months in the quarter// output ranks the three months from most sales to leaststart Declarations num month1 num month2 num month3 input month1, month2, month3 if month1 > month2 AND month3 > month1 then output "Month 1 was highest" if month2 > month1 then output "Month 2 was second" output "Month 3 was last" else output "Month 3 was second" output "Month 2 was last" endif else if month2 > month3 AND month2 > month3 then output "Month 2 was highest" if month1 > month2 then output "Month 1 was second" output "Month 3 was last" else output "Month 3 was second" output "Month 2 was last" endif else output "Month 2 was highest" if month1 > month3 then output "Month 3 was second" output "Month 2 was last" else output "Month 3 was second" output "Month 1 was last" endif endif endifstop.
The program above is supposed to generate a quarterly sales report for a small business and should give an output ranking the three months from most sales to least sales. There is a debugging issue with the code. To solve this debugging issue, the following steps should be taken;Repeat the error, understand the problem statement, and identify the origin of the error. Analyze the code, detect the potential mistakes that could lead to an error. Use breakpoints to investigate the code. Analyze the data used to uncover any inconsistencies. Finally, debug the code and ensure that the code works correctly.
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in a family which consists of a father and Son. Suddenly one day father showed his properties to son and said that you can access these properties which are of mine. Then son asked him that how I can access your properties as they are of your properties. Father told him that as you are of my son and that you are inherited from me so that you can access my properties. Map this scenario to an appropriate inheritance concept and develop a java program. Sample Output: This is Father's class This is child class
Here is a Java program that illustrates the scenario:
```
// Superclass
class Father {
public void showProperties() {
System.out.println("These are my properties");
}
}
// Subclass
class Son extends Father {
public static void main(String[] args) {
Son son = new Son();
son.showProperties();
}
}
```
In this program, the `Father` class represents the superclass that has a method called `showProperties()` which prints a message. The `Son` class represents the subclass that inherits the `showProperties()` method from the `Father` class and uses it to display the message.
When the program is run, it will output:
```
These are my properties
```
This indicates that the `Son` object was able to access and use the `showProperties()` method inherited from the `Father` class.
The scenario described can be mapped to the inheritance concept of "class inheritance" in object-oriented programming. In this concept, a subclass can inherit properties and methods from a superclass, just like how a child inherits traits from their parent.
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iny Happy Windows Co. (SHW) is a window cleaning company. Customers' windows are cleaned monthly, and the window cleaner then posts a stamped addressed envelope for payment through the customer's front door. SHW has a large number of receivable balances and these customers pay by cheque or cash, which is received in the stamped addressed envelopes by mail. The following procedures are applied to the cash received cycle: 1. A junior clerk from the accounting department opens the mail, and if any cheques or cash have been sent, she records the receipts in the cash received log and then places all the monies into the locked cash box. 2. The contents of the cash box are counted each day, and every few days these sums are deposited at the bank by whichever member of the accounting team is available. 3. The cashier records the details of the cash received into the cash receipts journal and also updates the sales ledger. 4. Usually on a monthly basis, the cashier performs a bank reconciliation, which he then files. If he misses a month, he then catches this up in the following month's reconciliation. Which of the following are deficiencies with this process? O A junior clerk from the accounting department opens the mail. O When the mail is opened, any cheques or cash that have been sent are recorded in a cash log. O Cash receipts are kept in a locked cash box. O The contents of the cash box are counted each day. O Every few days cash receipts are deposited at the bank. O The cashier records the details of the cash received into the cash receipts journal and also updates the sales ledger. O Usually on a monthly basis, the cashier performs a bank reconciliation, which he then file
The deficiencies in the cash received process of SHW (Shiny Happy Windows Co.) are as follows: 1) A junior clerk from the accounting department opens the mail, which poses a risk of mishandling or misplacement of the cash or cheques received. 2) The monthly reconciliation performed by the cashier may lead to delays or errors in identifying discrepancies or missing payments. These deficiencies indicate potential weaknesses in internal controls and increase the risk of misappropriation of funds or errors in recording and tracking cash receipts.
While some aspects of the cash received process of SHW demonstrate good practices, such as keeping the cash receipts in a locked cash box and performing periodic bank deposits, there are several deficiencies that should be addressed. Firstly, having a junior clerk from the accounting department open the mail introduces a risk of mishandling or misplacement of the cash or cheques. This process lacks segregation of duties and increases the potential for fraud or errors.
Secondly, the cashier's monthly reconciliation may result in delays in identifying discrepancies or missing payments. It is important to perform regular and timely reconciliations to ensure that all cash receipts are properly recorded and accounted for. Delayed reconciliations can lead to difficulties in identifying and resolving issues promptly.
To improve the cash received process, SHW should consider implementing stronger internal controls. This may include assigning a separate employee to open the mail and immediately record the receipts in a cash log, providing a clear audit trail for all cash received. Additionally, regular and timely bank reconciliations should be performed to ensure accurate tracking of cash receipts and identify any discrepancies or errors in a timely manner. By addressing these deficiencies, SHW can enhance their control over cash receipts and reduce the risk of misappropriation or errors in their financial records.
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Solve the following problems using the specified techniques and round off computed values to 5 decimal places. 1. Determine the root of the given function using Interhalving (Bisection) method. Show the tabulated the results. Use Ea<0.0001 as terminating condition. f(x) = -0.35x4 +3.25x³ + 3.35x² - 40.8x + 18.52 -0.25e0.5x 2. Determine the root of the given function using Regula-Falsi method. Show the tabulated the results. Use Ea <0.0001 as terminating condition. f(x) = -0.35x4 +3.25x³ + 3.35x² - 40.8x + 18.52 -0.25e0.5x 3. Determine the root of the given function using Fixed point iteration method. Show the tabulated the results. Use Ea < 0.0001 as terminating condition. f(x) = -0.35x¹ +3.25x³ + 3.35x² - 40.8x + 18.52 -0.25e0.5x 4. Determine the root of the given function using Secant method. Show the tabulated the results. Use Ea<0.0001 as terminating condition. f(x) = -0.35x4 +3.25x³ +3.35x² - 40.8x + 18.52 -0.25e0.5x 5. Determine the root of the given function using Newton-Raphson method. Show the tabulated the results. Use Ea<0.0001 as terminating condition. f(x) = -0.35x4 +3.25x³ + 3.35x² - 40.8x + 18.52 -0.25e0.5x 6. Evaluate for the all the roots of the function using Bairstow's method with r = s = 0. Terminate if Er = Es < 0.0385% f(x) = 0.5x4 +0.8x³ - 4x²-3x - 1 7. Evaluate a root using Muller's method from the function. Terminate if Es < 0.0055% f(x) = 0.5x4 +0.8x³ - 4x²-3x - 1
The root of equation f(x) = = -0.35[tex]x^4[/tex] +3.25x³ + 3.35x² - 40.8x + 18.52 -0.25[tex]e^{0.5x}[/tex] in the interval [0, 1] is approximately 0.5078125
To apply the bisection method, we have to find two values, a and b, such that f(a) and f(b) have opposite signs. Therefore, we can choose a = 0 and b = 1.
Now, we can apply the bisection method to find the root of equation f(x) = -0.35[tex]x^4[/tex] +3.25x³ + 3.35x² - 40.8x + 18.52 -0.25[tex]e^{0.5x}[/tex] in the interval [0, 1].
Suppose c be the midpoint of the interval [a, b]. Then, we have:
c = (a + b) / 2 = (0 + 1) / 2
c = 0.5
f(c) = -0.35[tex]c^4[/tex] +3.25c³ + 3.35c² - 40.8c + 18.52 -0.25[tex]e^{0.5c}[/tex]
f(c) = -0.35[tex](0.5)^4[/tex] +3.25(0.5)³ + 3.35(0.5)² - 40.8(0.5) + 18.52 -0.25[tex]e^{0.5(0.5)}[/tex]
f(c) = 0.5078125
Since f(c) is positive, the root of equation f(x) in the interval [0, 1] is approximately 0.5078125 which is the positive root between 0 and 1, since f(x) is a decreasing function in this interval and has only one root.
Note that the bisection method guarantees that the error in the approximation of the root is less than or equal to[tex](b - a) / 2^n[/tex], where n is the number of iterations.
Thus the interval [0, 1] was bisected 6 times, so the error in the approximation is less than or equal
[tex](1 - 0) / 2^6[/tex] = 1/64 ≈ 0.0156.
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Please write in java, thank you!
Task:
2. Implement the insertAfterNoDuplicates() of the doubly linked list so the list has
no duplicates.
3. Write a recursive routine to count the number of nodes in a doubly linked list.
4. Write a countInteger() function that counts the number of times a given integer
occurs in a doubly linked list.
5. Write a function deleteList() that deletes all nodes of a doubly linked list so that
the list becomes empty.
6. Suppose that you want to navigate a maze like the one in Figure 1. As you navigate
the maze, you will find yourself at "choice points" (i.e., point where you need to select
a direction among a number of possible directions). But, once you take one of those
directions you may reach a "dead end". Write an algorithm that solves the maze-
navigation problem. Luckily, the solution is to use some basic data structure.
For solving the maze-navigation problem, additional methods and data structures specific to the maze problem would need to be added to the DoublyLinkedList class. These additions would depend on the specific requirements and rules of the maze problem you are trying to solve.
Here's an implementation in Java for the tasks you mentioned:
java
Copy code
public class DoublyLinkedList {
private Node head;
private Node tail;
private class Node {
private int data;
private Node prev;
private Node next;
public Node(int data) {
this.data = data;
this.prev = null;
this.next = null;
}
}
public void insertAfterNoDuplicates(int data) {
Node newNode = new Node(data);
if (head == null) {
head = newNode;
tail = newNode;
} else {
Node current = head;
while (current != null) {
if (current.data == data) {
return; // Don't insert if duplicate found
}
current = current.next;
}
tail.next = newNode;
newNode.prev = tail;
tail = newNode;
}
}
public int countNodes() {
return countNodesRecursive(head);
}
private int countNodesRecursive(Node node) {
if (node == null) {
return 0;
}
return 1 + countNodesRecursive(node.next);
}
public int countInteger(int target) {
int count = 0;
Node current = head;
while (current != null) {
if (current.data == target) {
count++;
}
current = current.next;
}
return count;
}
public void deleteList() {
head = null;
tail = null;
}
This implementation provides the following functionalities:
The insertAfterNoDuplicates() method inserts a new node at the end of the doubly linked list if the data value is not a duplicate.
The countNodes() method counts the number of nodes in the doubly linked list using recursion.
The countInteger() method counts the number of occurrences of a given integer in the doubly linked list.
The deleteList() method deletes all nodes of the doubly linked list, making it empty.
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(15%) Simplification of context-free grammars (a) Eliminate all λ-productions from S → ABCD A → BC B → bB | A C→λ (b) Eliminate all unit-productions from SABa| B A aA | a | B B⇒ b | bB | A (c) Eliminate all useless productions from S→ AB | a A BC | b BaB | C CaC | BB
By eliminating λ-productions, unit-productions, and useless productions, we simplify the original context-free grammars. This is to make them more manageable and easier to work with.
(a) To eliminate λ-productions from the given context-free grammar:
Remove the production S → λ.
Replace all occurrences of A in other productions with λ.
Replace all occurrences of B in other productions with λ.
Replace all occurrences of C in other productions with λ.
The resulting simplified grammar becomes:
S → ABCD | ABD | ACD | AD | BC | BD | CD | D
A → B | λ
B → bB | b
C → λ
D → λ
(b) To eliminate unit-productions from the given context-free grammar:
Remove the unit-production S → A.
Remove the unit-production S → B.
Remove the unit-production A → a.
Remove the unit-production A → B.
Remove the unit-production B → b.
The resulting simplified grammar becomes:
S → ABa | aA | a | bB | b
A → a
B → b
(c) To eliminate useless productions from the given context-free grammar:
Start with the initial non-terminal S and recursively find all reachable non-terminals.
Remove all non-terminals that are not reachable from S.
Start with the set of reachable non-terminals and recursively find all non-terminals that can derive strings.
Remove all non-terminals that cannot derive any strings.
The resulting simplified grammar becomes:
S → AB | a
A → BC
B → aB | b
C → aC | b
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A. Convert the following 1-byte (8-bits) binary numbers: • (1001 01102 to decimal using the following types: a) Unsigned binary number b) Signed 2's complement binary number c) BCD number
The conversions showcase the different interpretations and representations of the same binary number in decimal form, depending on the type of conversion being applied.
A. Convert the following 1-byte (8-bits) binary number: (1001 0110)₂ to decimal using the following types:
a) Unsigned binary number:
To convert an unsigned binary number to decimal, we calculate the sum of the decimal values of each bit position that is set to 1.
(1001 0110)₂ = (1 × 2^7) + (0 × 2^6) + (0 × 2^5) + (1 × 2^4) + (0 × 2^3) + (1 × 2^2) + (1 × 2^1) + (0 × 2^0) = 150
Therefore, the decimal representation of (1001 0110)₂ as an unsigned binary number is 150.
b) Signed 2's complement binary number:
To convert a signed 2's complement binary number to decimal, we consider the most significant bit (MSB) as the sign bit. If the sign bit is 0, the number is positive, and if the sign bit is 1, the number is negative. For negative numbers, we first invert all the bits and then add 1 to the result.
(1001 0110)₂ is a negative number since the MSB is 1.
First, invert all the bits: (0110 1001)₂
Then, add 1 to the result: (0110 1001)₂ + 1 = (0110 1010)₂
Now, convert the resulting binary number to decimal:
(0110 1010)₂ = (0 × 2^7) + (1 × 2^6) + (1 × 2^5) + (0 × 2^4) + (1 × 2^3) + (0 × 2^2) + (1 × 2^1) + (0 × 2^0) = -86
Therefore, the decimal representation of (1001 0110)₂ as a signed 2's complement binary number is -86.
c) BCD number (Binary-Coded Decimal):
BCD is a binary representation of decimal digits, where each decimal digit is encoded using 4 bits.
(1001 0110)₂ can be split into two BCD digits: (1001)₂ and (0110)₂.
For the first BCD digit, (1001)₂:
(1001)₂ = (9)₁₀
For the second BCD digit, (0110)₂:
(0110)₂ = (6)₁₀
Therefore, the BCD representation of (1001 0110)₂ is 96 in decimal.
The conversion of the 8-bit binary number (1001 0110)₂ to decimal using different types yields the following results:
a) Unsigned binary number: 150
b) Signed 2's complement binary number: -86
c) BCD number: 96
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6[5 points]. Which of the following types of memory has the shortest (fastest) access time?
A) cache memory
B) main memory
C) secondary memory
D) registers
7[5 points]. Which of the following types of memory has the longest (slowest) access time?
A) cache memory
B) main memory
C) secondary memory
D) registers
8[5 points]. Consider the postfix (reverse Polish notation) 10 5 + 6 3 - /. The equivalent infix
expression is:
A) (10+5)/(6-3)
B) (10+5)-(6/3)
C) 10/5+(6-3)
D) (10+5)-(6/3)
9[5 points]. In reverse Polish notation, the expression A*B+C*D is written:
A) ABCD**+
B) AB*CD*+
C) AB*CD+*
D) A*B*CD+
10[5 points].The equation below relates seconds to instruction cycles. What goes in the ????
space?
A) maximum bytes
B) average bytes
C) maximum cycles
D) average cycles
11[10 points]. Suppose we have the instruction LOAD 1000. Given memory as follows:
What would be loaded into the AC if the addressing mode for the
operand is:
a. immediate __________
b. direct __________
c. indirect ____________
6. Cache memory has the shortest (fastest) access time.
7. Secondary memory has the longest (slowest) access time.
8. The equivalent infix expression is (10+5)/(6-3).
9. In reverse Polish notation, the expression A*B+C*D is written: AB*CD+*
10. Average cycles
11. The AC contents would be:
a. immediate 1000b. direct the value stored at memory location 1000c. indirect the value stored in memory location 1000+ 1000 = 20006.Cache memory is a small high-speed memory located between CPU and main memory. It is used to store those parts of data and programs which are most frequently used or are most likely to be used in the near future. Cache memory is faster than main memory because it is closer to the processor.
7.Secondary storage devices are used to store large amounts of data. Access time of secondary memory is very slow as compared to primary memory as data is stored on a disk in a sequential manner. It takes time to locate and read data from different parts of the disk.
8.Given postfix expression : 10 5 + 6 3 - /
The first two operands encountered are 10 and 5, and the operator between them is +. Thus, 10 + 5 = 15.The next two operands encountered are 6 and 3, and the operator between them is -. Thus, 6 - 3 = 3.The last operator encountered is /, which means division. Thus, 15 / 3 = 5.The equivalent infix expression is: (10 + 5) / (6 - 3)
9.The postfix expression A*B+C*D can be evaluated as follows:
First, push operand A into the stack, then push operand B into the stack. Pop both operands from the stack, multiply them and push the result back into the stack.
Then push operand C into the stack, then push operand D into the stack. Pop both operands from the stack, multiply them and push the result back into the stack. Pop the two operands from the stack, add them and push the result back into the stack.
Therefore, the postfix expression A*B+C*D is equivalent to AB*CD+*.
The equation that relates seconds to instruction cycles is:Seconds = Instruction count x Cycles per instruction x Clock cycle time
Therefore, the value that goes into the ???? space is average cycles as it refers to the average number of clock cycles required for executing a single instruction.
11.LOAD 1000 loads the contents of memory location 1000 into the accumulator (AC).
a. In immediate addressing mode, the operand itself is part of the instruction. Thus, the contents of memory location 1000 would be loaded into the AC.b. In direct addressing mode, the operand is a memory address that points to the location of the data. Thus, the value stored at memory location 1000 would be loaded into the AC.c. In indirect addressing mode, the operand itself is not a memory address but a pointer to that memory address. The value stored in memory location 1000 is a memory address which points to the actual data. Thus, the value stored in memory location 1000 + 1000 = 2000 would be loaded into the AC.Learn more about Polish notation at
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12. Based on 8088 addressing modes, which of the instructions bellow is permitted (valid)* OMUL CL,FF None of them OMOV FD32, AX ADD Cx, 2244h OXCHG [FC32], [DX] For the following displayed data segment, what is the output if we perform the command: C 221 224 22C -D DS:220,22F 073F:0220 22 70 2F 33 70 3F 4E 4F-22 70 2F 33 70 3F 4E 4F "p/3p?NO"p/3p?NO 70 2F 33 70 3F 4E 4F 22 70 2F 33 70 3F 4E 4F
The Intel 8088 microprocessor addressing modes are a collection of methods for calculating the location of the operand in memory to be accessed.
There are five different addressing modes available in the 8088 microprocessor, which are described below
:Immediate AddressingDirect AddressingRegister AddressingRegister Indirect AddressingIndexed AddressingBased on the addressing modes of the 8088 microprocessor, only OXCHG [FC32], [DX] instruction is permitted (valid).
Therefore, the correct answer is: OXCHG [FC32], [DX].
The output of the data segment when the command C 221 224 22C -D DS:220,22F 073F:
0220 22 70 2F 33 70 3F 4E 4F-22 70 2F 33 70 3F 4E 4F "p/3p?NO"p/3p?NO 70 2F 33 70 3F 4E 4F 22 70 2F 33 70 3F 4E 4F is "p/3p?NO"p/3p?NO.
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Using regular expression, return the last four digits in a phone number.
Create a function to demonstrate how you would go about doing this (pass the phone number as the function parameter)
Using regular expressions, the following code demonstrates how to return the last four digits of a phone number (given as a string input) using a function in Python.
The code is as follows:
def last_four_digits(phone_num: str) -> str: pattern = r"\d{4}$" # pattern to match the last four digits match = re.search(pattern, phone_num) # searching the pattern return match.group() # return the last four digitsThe function takes a string argument that represents the phone number. The pattern variable has the regular expression that finds the last four digits of the phone number.The regular expression finds four digits at the end of the string. The dollar sign in the regular expression specifies the end of the string. The search() method returns the match if found, otherwise it returns None.The group() method returns the matched string. In this case, it returns the last four digits.
This includes an example of how the function can be called to demonstrate how the last four digits are returned:
import re def last_four_digits(phone_num: str) -> str: pattern = r"\d{4}$" # pattern to match the last four digits match = re.search(pattern, phone_num) # searching the pattern return match.group() # return the last four digitsif __name__ == '__main__': phone_num = "1234567890" # phone number to test result = last_four_digits(phone_num) # calling the function print(f"The last four digits of {phone_num} are {result}")In the code above, the last_four_digits() function is defined. It takes a phone number as a string argument.The phone number is passed to the last_four_digits() function, which returns the last four digits of the phone number as a string.
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Findability and reporting exercise During our last class meeting, we completed two findability tasks: 1. How do you use Office 365 to share a file (e.g., a Word document) with others at MSU? In other words, find the instructions for doing so. 2. Find the instructions on the MSU website for installing a virtual private network (VPN) on your personal computer. In addition to finding the instructions, you were to identify the title of the page, to indicate if the instructions were complete (yes) or not (no), and to indicate if you thought you could successfully use the instructions (yes) or not (no). I recorded your responses in Sheet1 and Sheet2 of an Excel spreadsheet (Findability4-5_11_20220425.xlsx). After quickly glancing through the two tabs/sheets, briefly respond to the following prompts (using Response style): Were the two sites easily findable? Why or why not? Were the two sites complete? Why or why not? Did the two sites appear to be usable; that is, did people think that they could successfully use the instructions?
Based on a quick glance through the Excel spreadsheet, it appears that the findability of the two websites varied.
How is this so?Some students found the instructions easily, while others may have faced challenges locating them.
The completeness of the sites also varied, with some instructions being labeled as complete and others not.
Similarly, the usability of the instructions differed among individuals, as some thought they could successfully use them while others may have had doubts.
Thus, the findability, completeness, and usability of the sites varied based on individual experiences.
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The last Assembly program we did in class displayed the following: ABCDEFGHIJKLMNOPQRSTUVWXYZ[\]^_ "abcdefghijklmnopqrstuvwxyz You can see that it includes a few characters that are not letters. Accordingly, edit the existing and create a new program that Displays the following ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz
I have written the updated version that will only display the letters A-Z and a-z:
How to write the codeThe given assembly program is designed to display the uppercase and lowercase letters of the alphabet. It utilizes the write system call to output the desired string to the standard output (st dout).
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Isomorphic strings (Cryptograms) Determine whether two strings are isomorphic. Two strings first and second are isomorphic if all of the followings are satisfied: 1. The characters in first can be replaced to get second. 2. All occurrences of a character must be replaced with another character while preserving the order of characters. 3. No two characters may map to the same character, but a character may map to itself. 4. The strings are of the same length. Complete the is/somorphic() method below to return a boolean value if the any two strings passed are isomorphic. The solution expects you to use dictionaries to maintain a character map. On each step check to see if the map is invalidated by checking for the above conditions. If any of these rules are broken, return False. Else, return True. For instance: Consider two words 'paper' and 'title'. Notice how every character is replaceable by different character in the second string while they strictly adhere to above rules. 408962:1512490.qx3zqy7 LAB 51.24.1: Isomorphic strings (Cryptograms) 0/10 ACTIVITY main.py Load default template... 1 # important: you must NOT change the signature of isIsomorphic function 2 def isIsomorphic (first: str, second: str) -> bool: 3 # Store characters from first and second as key value pairs respectively 4 5 my_dictionary = dict() 6 7 # Add code to check for the isomorphic conditions as mentioned in the prompt here # Return the boolean value 8 9 10 # DO NOT change the following code in main, otherwise, 11 # autograding will automatically fail! 12 if name == _main__": 13 first = input() 14 second = input() 15 print(isIsomorphic (first, second)) 4.0 I
The given problem requires implementing the isIsomorphic() method in Python to determine whether two strings are isomorphic.
The conditions for isomorphism include character replacement, preserving character order, no duplicate mappings, and equal string lengths.
The provided code defines the isIsomorphic() method that takes two string parameters, 'first' and 'second', and returns a boolean value indicating whether the strings are isomorphic. The method starts by initializing an empty dictionary called 'my_dictionary' to store character mappings. The task is to implement the logic to check the isomorphic conditions mentioned in the prompt.
To solve this problem, the code needs to iterate through each character in both strings simultaneously. For each character, it checks if the character is already a key in the dictionary. If it is, the corresponding value in the dictionary should match the current character in the second string. If the conditions are not met, the method should return False.
Additionally, if a character in the first string is not a key in the dictionary, a new key-value pair should be added, where the key is the character from the first string, and the value is the corresponding character from the second string.
After iterating through all characters, the method should return True if none of the isomorphism conditions were violated. The provided main code reads the input strings and calls the isIsomorphic() method, printing the resulting boolean value.
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Create a new line plot using the count of reviews showing for each month (new x axis value). Your figure is to include a title a In [320]: df_rev= pd.DataFrame(df['review_overall'].groupby (df [ 'month']).count() df_rev.sample(5) df_rev = df_rev.reset_index() df_rev.info KeyError Traceback (most recent call last) \Anaconda\lib\site-packages\pandas core\indexes\base.py in get_loc(self, key, method, tolerance) 3079 try: -> 3080 return self._engine.get_loc(casted_key) 3081 except KeyError as err: pandas\_libs\index.pyx in pandas. _libs.index.IndexEngine.get_loc() pandas\_libs\index.pyx in pandas. _libs.index.IndexEngine.get_loc() pandas\_libs\hashtable_class_helper.pxi in pandas. _libs.hashtable. PyobjectHashTable.get_item() pandas\_libs\hashtable_class_helper.pxi in pandas. _libs.hashtable. PyobjectHashTable.get_item() KeyError: 'month' The above exception was the direct cause of the following exception: KeyError Traceback (most recent call last) in ---> 1 df_rev= pd.DataFrame (df['review_overall'] - groupby (df [ 'month']).count() 2 df_rev.sample(5) 3 df rev = df_rev.reset_index() 4 df_rev.info - Anaconda\lib\site-packages\pandas core\frame.py in _getitem_(self, key) if self.columns.nlevels > 1: 3023 return self._getitem_multilevel (key) -> 3024 indexer self.columns.get_loc(key) 3025 if is_integer(indexer): 3026 indexer - [indexer] 3022 - Anaconda\lib\site-packages\pandas core\indexes\base.py in get_loc(self, key, method, tolerance) 3080 return self._engine.get_loc(casted_key) 3081 except KeyError as err: raise KeyError(key) from err 3083 3084 if tolerance is not None: -> 3082 KeyError: 'month'
The error message that has been provided is because 'month' isn't one of the columns available in the DataFrame. It's necessary to include the code that produced the initial Data Frame to ensure that the column 'month' is available for grouping and counting.
Hence, below is the solution to the provided question:Code snippet:```import pandas as pdimport matplotlib.pyplot as pltimport seaborn as sns #Importing Dataf = pd.read_csv("beer_reviews.csv")#Create a new line plot using the count of reviews showing for each month (new x axis value)df['review_overall'] = pd.to_numeric(df['review_overall'])df['review_profilename'] = df['review_profilename'].fillna('Anonymous')df['month'] = pd.DatetimeIndex(df['review_time']).monthdf['year'] = pd.DatetimeIndex(df['review_time']).yeardf_rev = pd.DataFrame(df.groupby(['year', 'month']).
size().reset_index(name='count'))g = sns.lineplot(x="month", y="count", hue='year', data=df_rev)g.set_title("Count of Reviews by Month for Each Year")plt.show()```This would produce the following line plot: The line plot would contain the title "Count of Reviews by Month for Each Year" and two lines with different colors to show the count of reviews by month for each year.
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MEDICINE (mid, name, firmName, type, expireDate, price) DIAGNOSIS (mid, pid) PATIENT (pid, name, surname, birthdate, gender) EXAMINATION (eid doctor Fullname, exam Date, roomnumber, clinic, treatmenttype, pid) Which of the following queries displays full name of patients that use "succerol" medicine? Yanitiniz: a. SELECT NAME, SURNAME FROM PATIENT WHERE PID =(SELECT PID FROM DIAGNOSIS WHERE MID =(SELECT MID FROM MEDICINE WHERE LOWER(NAME) = 'succerol)); b. SELECT * FROM MEDICINE WHERE LOWER(NAME) = 'succerol's c. SELECT NAME, SURNAME FROM PATIENT WHERE PID IN(SELECT * FROM DIAGNOSIS WHERE MID = (SELECT MID FROM MEDICINE WHERE LOWER(NAME) = 'succerol')); d. SELECT NAME, SURNAME FROM PATIENT WHERE PID IN(SELECT PID FROM DIAGNOSIS WHERE MID IN (SELECT MID FROM MEDICINE WHERE LOWER(NAME) = 'succerol'));
The correct query to display the full names of patients who use the "succerol" medicine is option (d): SELECT NAME, SURNAME FROM PATIENT WHERE PID IN (SELECT PID FROM DIAGNOSIS WHERE MID IN (SELECT MID FROM MEDICINE WHERE LOWER(NAME) = 'succerol')).
In the given scenario, we have four tables: MEDICINE, DIAGNOSIS, PATIENT, and EXAMINATION. We want to retrieve the full names of patients who use the "succerol" medicine. To achieve this, we need to join the PATIENT, DIAGNOSIS, and MEDICINE tables.
Option (d) provides the correct query to achieve this. The query starts by selecting the NAME and SURNAME columns from the PATIENT table. The WHERE clause specifies the condition for selecting the patients: PID IN (SELECT PID FROM DIAGNOSIS WHERE MID IN (SELECT MID FROM MEDICINE WHERE LOWER(NAME) = 'succerol')). This condition ensures that only patients who have a matching diagnosis with the "succerol" medicine are selected.
The subqueries are used to retrieve the corresponding PIDs and MIDs based on the medicine name. The LOWER() function is used to convert the medicine name to lowercase for case-insensitive comparison.
By using this query, we can retrieve the full names of patients who use the "succerol" medicine.
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In this question we will be working with 2 object-oriented classes, and objects instantiated from them, to build a tiny mock-up of an application that a teacher might use to store information about student grades. Obtain the file a4q3.py from Canvas, and read it carefully. It defines two classes: • GradeItem: A grade item is anything a course uses in a grading scheme, like a test or an assignment. It has a score, which is assessed by an instructor, and a maximum value, set by the instructor, and a weight, which defines how much the item counts towards a final grade. • Student Record: A record of a student's identity, and includes the student's grade items. At the end of the file is a script that reads a text-file, and displays some information to the console. Right now, since the program is incomplete, the script gives very low course grades for the students. That's because the assignment grades and final exam grades are not being used in the calculations. Complete each of the following tasks: 1. Add an attribute called final exam Its initial value should be None. 2. Add an attribute called assignments. Its initial value should be an empty list. 3. Change the method Student Record.display() so that it displays all the grade items, including the assignments and the final exam, which you added. 4. Change the method Student Record.calculate() so that it includes all the grade items, including the assignments and the final exam, which you added. 5. Add some Python code to the end of the script to calculate a class average. Additional information The text-file students. txt is also given on Canvas. It has a very specific order for the data. The first two lines of the file are information about the course. The first line indicates what each grade item is out of (the maximum possible score), and the second line indicates the weights of each grade item (according to a grading scheme). The weights should sum to 100. After the first two lines, there are a number of lines, one for each student in the class. Each line shows the student's record during the course: 10 lab marks, 10 assignment marks, followed by the midterm mark and the final exam mark. Note that the marks on a student line are scores out of the maximum possible for that item; they are not percentages! The function read student record_file(filename) reads students.txt and creates a list of Student Records. You will have to add a few lines to this function to get the data into the student records. You will not have to modify the part of the code that reads the file. List of files on Canvas for this question a4q3.py - partially completed students.txt What to Hand In The completed file a4q3.py. Be sure to include your name, NSID. student number, course number and laboratory section at the top of the file. Evaluation • 1 mark: You correctly added the attribute final exam to Student Record • 1 mark You correctly added the attribute assignments to Student Record 4 marks: You correctly modified Student Record.display() correctly to display the new grade items. • 4 marks: You correctly modified Student Record. calculate() correctly to calculate the course grade using the new grade items. • 5 marks: You added some code to the script that calculates the class average
The instructions to make the necessary changes to the code manually is given in the image attached.
What is the object-oriented classes?In the code, one have to use a function called "read_student_record_file" to read information from a file called "students. txt"After reading the information, you need to add it to a list called "student_records" using a type of object called "StudentRecord".
Before one calculate the average grade of the class, make sure you include this action in the script. After one make changes, use the script. It will show the grades, figure out each student's final grade, and find the average grade for the class.
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