When rolling a die, what is the probability of rolling a 1 or a 4 write your answer in a fraction?

Answer:

A

Step-by-step explanation:

Cuz if the y intercept increases, so does the line

Answer:

answer A

semoga membantu

Answer:r+(2r+7)

Step-by-step explanation:

twenty four and nineteen twentieths

Answer: The coordinates of D are (-3, -7).

Step-by-step explanation:

First, we need to find the coordinates of B. In order to do that, take the average of the two points that make up the segment which are A and C.

Average of x's: -9 + -1 = -10/2 = -5

Average of y's: -4 + 6 = 2/2 = 1

Therefore, the coordinates of B are (-5, 1). Coordinates are always (x,y).

Now we can find D by noting that the E will be the average of B and D. So we can use the average equation to determine the value of D.

Average of the x's:

(B + D)/2 = E

(-5 + D)/2 = -4

-5 + D = -8

D = -3  

Average of the y's:

(B + D)/2 = E

(1 + D)/2 = -3

1 + D = -6

D = -7

The coordinates of D are (-3, -7).

Answer:

Value Added Tax Is The Correct Answer!

Step-by-step explanation:

The Value Added Tax, or VAT, in the European Union is a general, broadly based consumption tax assessed on the value added to goods and services.

Dont Forget to Mark Thanks!

Have a good day! :)

Answer:

Value Added Tax........

Answer:

[tex]x+y=19500,\:0.08x+0.15y=2400\quad :\quad x=7500,\:y=12000[/tex]

Step-by-step explanation:

x + y = 19500

.08x + .15y = 2400

Answer:

the last one

Step-by-step explanation:

because it is the right answer

First, let's declare some variables.

x = # of sticker packs

y = total # of stickers

Now, let's create an equation to model the problem.

y = 21x + 8

Let's plug in 50 for y and solve for x.

50 = 21x + 8

Subtract 8 from both sides.

42 = 21x

Divide both sides by 21

2 = x

Anthony will have to buy 2 sticker packs to have a total of 50 stickers.

Answer:

2 packs.

Step-by-step explanation:

Each sticker pack is 21 stickers and you would want to get 50 in total.

Since he already has 8 stickers, the initial value is 8.

So, 50-8 is 42. That means Anthony would need 42 more stickers to reach 50.

At this point, you can do division [tex]\frac{42}{21}[/tex] and that would give you 2.

You can check your work by working backwards and seeing that 2(21)=42.

42+8=50.

Answer:

1. Just make the ratio fraction.

2. Take L.C.M and solve it like I did.

3. Please mark me brainliest.

Answer:

is the answer

Step-by-step explanation:

Answer:

go here https://nrich.maths.org/1063/solution and there's explanations there too

Step-by-step explanation:

Answer:

a. f(2) :

[tex]f(x) = 2x - 5 \\ f(2) = 2(2) - 5 \\ f(2) = 4 - 5 \\ f(2) = - 1[/tex]

b. f(0) :

[tex]f(x) = 2x - 5 \\ f(0) = 2(0) - 5 \\ f(0) = - 5[/tex]

c. f(-3) :

[tex]f(x) = 2x - 5 \\ f( - 3) = 2( - 3) - 5 \\ = - 6 - 5 \\ = - 11[/tex]

Answer:

101. NVM

Step-by-step explanation:

23 X 101= 2323

Echoing a two-digit number to make it a four-digit number is equivalent to multiplying the two-digit number by 101.

Echoing a number means repeating the digits of that number to create a new number with a different number of digits. For instance, echoing a one-digit number once turns it into a two-digit number, and echoing a two-digit number once turns it into a four-digit number. In this explanation, we'll explore the relationship between echoing and multiplication to better understand this concept.

Let's consider a one-digit number, say "n." Echoing "n" once will result in a two-digit number "nn." We can express this as:

n → nn

To understand the relationship between echoing and multiplication, let's see what happens when we echo "n" twice:

nn → nnnn

Notice that "nn" is repeated twice to create a four-digit number. We can represent this as:

n → nn → nnnn

To find the relationship between echoing a two-digit number and multiplication, let's take a two-digit number "ab" (where "a" represents the tens digit and "b" represents the ones digit). Echoing "ab" once will give us the four-digit number "abab":

ab → abab

Now, let's echo "ab" again:

abab → abababab

Observe that "ab" is repeated three more times to form an eight-digit number. We can represent this as:

ab → abab → abababab

To generalize this pattern, we can say that echoing a two-digit number "ab" once turns it into a four-digit number "abab," echoing it twice turns it into an eight-digit number "abababab," and so on.

Now, let's examine the relationship between the number of digits in the echoed number and the number of times we echoed it:

- Echoing once: 2 digits

- Echoing twice: 4 digits

- Echoing three times: 8 digits

Notice that the number of digits in the echoed number doubles every time we echo the two-digit number.

Now, consider the powers of 10. Multiplying a number by 10 moves the decimal point one place to the right, while multiplying by 100 moves the decimal point two places to the right.

To make a two-digit number into a four-digit number, we need to multiply it by a value that moves the digits two places to the right. And this value is 100, which is equal to 10².

So, echoing a two-digit number to make it a four-digit number is equivalent to multiplying the two-digit number by 100.

To summarize: ab → abab (echoing once, equivalent to multiplying by 10²)

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Answer:

there is no question plzz attach it first

and it answer is 100000

and it is very easy

Answer:

I do not understand this question

Answer:

Minimum value: 3

Step-by-step explanation:

Minimum value coordinate: (-5, -3)

Minimum value: l - 3 l (absolute value of -3)

Minimum value: 3

Answer:-14

Step-by-step explanation:

/A/= (3 x-1)- (1 x 11)

= -3 -11= -14

answer:

a. -14

explanation: 3dg3

Answer:

-2 is the answer

Step-by-step explanation:

sorry if I am wrong

Answer: -2

Step-by-step explanation: 3+(-5)                                                                        3−5

3+−5

−2

When it comes to adding a positive number and a negative number the main point you should focus on is that if its the same sign you have to keep it and add them together. But since they aren't the same signs and they are different signs you have to subtract them and keep the sign of the bigger number which is -5 in this problem.

Answer:

Let the required number be x

The quotient of a number and -7, decreased by 2, is 10

According to the above problem, we get

[tex] \frac{x}{( -7)} - 2 = 10 \\ \frac{x}{( - 7)} = 10 + 2 \\ \frac{x}{( - 7)} = 12 \\ x = ( - 7) \times 12 \\ \boxed{x = - 84}[/tex]

Therefore, the required number is -84.

Parameterize S by

[tex]\vec r(s, t) = (1-s)(1-t)\,\vec\imath + 6s(1-t)\,\vec\jmath + 6t\,\vec k[/tex]

with 0 ≤ s ≤ 1 and 0 ≤ t ≤ 1.

Take the normal vector to S to be

[tex]\vec n = \dfrac{\partial\vec r}{\partial s}\times\dfrac{\partial\vec r}{\partial t} = (36-36t)\,\vec\imath+(6-6t)\,\vec\jmath+(6-6t)\,\vec k[/tex]

with magnitude

[tex]\|\vec n\| = 6\sqrt{38}(1-t)[/tex]

Then the surface integral is

[tex]\displaystyle \iint_S xy\,\mathrm dS = 6\sqrt{38} \int_0^1\int_0^1 (1-t)\,\mathrm dt\,\mathrm ds = \boxed{3\sqrt{\frac{19}2}}[/tex]

Answer:

IM DOING THE SANE THING AND IDFK

Conjectures are conclusions formed from evidences.

Steven's conjecture that: [tex]x^3 > 125[/tex] is true because: [tex]x > 5[/tex] or [tex]x > -5[/tex] for [tex]|x| > 5[/tex]

The parameter is given as:

[tex]|x| > 5[/tex]

Split the inequality as follows:

[tex]x > 5[/tex] or [tex]x > -5[/tex]

Take the cube of both sides

[tex]x^3 > 5^3[/tex] or [tex]x^3 > -5^3[/tex]

Evaluate all exponents

[tex]x^3 > 125[/tex] or [tex]x^3 > -125[/tex]

[tex]x^3 > 125[/tex] implies that Steven's conjecture is correct.

So:

Steven's conjecture that: [tex]x^3 > 125[/tex] is true because:

[tex]x > 5[/tex] or [tex]x > -5[/tex] for [tex]|x| > 5[/tex]

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