When the equation a-bx=cx
+d is solved for x, the result is

Answer:i got 329

Step-by-step explanation:

The true statement about the series [tex]\sum\limits^{\infty}_{n=1} \frac{9}{n(n +3)}[/tex] is that (a) the series diverges

The series is given as:

[tex]\sum\limits^{\infty}_{n=1} \frac{9}{n(n +3)}[/tex]

Take the limit of the function to infinity

[tex]\lim_{n \to \infty} \frac{9}{n(n +3)}[/tex]

This gives

[tex]\lim_{n \to \infty} \frac{9}{n(n +3)} = \frac{9}{\infty * (\infty +3)}[/tex]

Evaluate the sum

[tex]\lim_{n \to \infty} \frac{9}{n(n +3)} = \frac{9}{\infty * \infty}[/tex]

Evaluate the product

[tex]\lim_{n \to \infty} \frac{9}{n(n +3)} = \frac{9}{\infty}[/tex]

Evaluate the quotient

[tex]\lim_{n \to \infty} \frac{9}{n(n +3)} = 0[/tex]

Since the limit is 0, then it means that the series diverges

Hence, the true statement about the series [tex]\sum\limits^{\infty}_{n=1} \frac{9}{n(n +3)}[/tex] is that (a) the series diverges

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Answer:

B. The series converges to [tex]\displaystyle{\frac{11}{2}}[/tex].

Step-by-step explanation:

Before evaluating the infinite series, the expression can be decomposed as the sum of two fractions (partial fraction decomposition) as follows.

Let [tex]\textit{A}[/tex] and [tex]\textit{B}[/tex] be constants such that

                                       [tex]{\displaystyle{\frac{9}{n\left(n+3\right)}}}} \ \ = \ \ \displaystyle{\frac{A}{n} \ \ \ + \ \ \frac{B}{n+3}}[/tex]

Multiply both sides of the equation by the denominator of the left fraction,

[tex]n\left(n+3\right)[/tex], yielding

                                              [tex]9 \ \ = \ \ A\left(n+3\right) \ \ + \ \ B \-\hspace{0.045cm} n[/tex]

Now, let [tex]n \ = \ 0[/tex], thus

                                             [tex]\-\hspace{0.2cm} 9 \ \ = \ \ A\left(0 + 3\right) \ + \ B\left(0\right) \\ \\ 3 \-\hspace{0.035cm} A \ = \ \ 9 \\ \\ \-\hspace{0.11cm} A \ \ = \ \ 3[/tex].

Likewise, let [tex]n \ = \ -3[/tex], then

                                            [tex]\-\hspace{0.5cm} 9 \ \ = \ \ A\left(-3 + 3\right) \ + \ B\left(-3\right) \\ \\ -3 \-\hspace{0.035cm} B \ = \ \ 9 \\ \\ \-\hspace{0.44cm} B \ \ = \ \ -3[/tex]

Hence,

                                       [tex]\displaystyle{\sum_{n=1}^{\infty} {\frac{9}{n\left(n+3\right)}}} \ = \ \displaystyle\sum_{n=1}^{\infty} \left(\frac{3}{n} \ - \ \frac{3}{n+3}\right)[/tex].

First and foremost, write the nth partial sum (first nth terms) of the series,

          [tex]\displaystyle\sum_{n=1}^{n} \left(\frac{3}{n} \ - \ \frac{3}{n+3}\right) \ \ = \ \-\hspace{0.33cm} \displaytstyle{\frac{3}{1} \ - \frac{3}{4} + \ \frac{3}{2} \ - \frac{3}{5} \ + \frac{3}{3} \ - \frac{3}{6} \ + \frac{3}{4} \ - \frac{3}{7}} \\ \\ \\ \-\hspace{3.58cm} + \ \displaystyle{\frac{3}{5} \ - \ \frac{3}{8} \ + \ \frac{3}{6} \ - \ \frac{3}{9} \ + \ \frac{3}{7} \ - \ \frac{3}{10}} \\ \\ \\ \-\hspace{3.58cm} + \ \ \dots[/tex]

                                                [tex]+ \ \ \displaystyle{\frac{3}{n-3} \ - \ \frac{3}{n} \ + \ \frac{3}{n-2} \ - \ \frac{3}{n+1}} \\ \\ \\ \ + \ \frac{3}{n-1} \ - \ \frac{3}{n+2} \ + \ \frac{3}{n} - \ \frac{3}{n+3}}[/tex].

Notice that the expression forms a telescoping sum where subsequent terms cancel each other, leaving only

        [tex]\displaystyle\sum_{n=1}^{n} \left(\frac{3}{n} \ - \ \frac{3}{n+3}\right) \ \ = \ \-\hspace{0.33cm} \displaytstyle{\frac{3}{1} \ + \ \frac{3}{2} \ + \frac{3}{3} \ - \ \frac{3}{n+1}} - \ \frac{3}{n+2} \ - \ \frac{3}{n+3}}}[/tex].

To determine if this infinite series converges or diverges, evaluate the limit of the nth partial sum as [tex]n \ \rightarrow \ \infty[/tex],

         [tex]\displaystyle\sum_{n=1}^{\infty} \left(\frac{3}{n} \ - \ \frac{3}{n+3}\right) \ \ = \ \-\hspace{0.33cm} \lim_{n \to \infty} \left(\displaytstyle{\frac{11}{2} \ - \ \frac{3}{n+1} \ - \ \frac{3}{n+2} \ + \ - \ \frac{3}{n+3}\right) \\ \\ \\ \-\hspace{3.25cm} = \ \ \ \displaystyle{\frac{11}{2} \ - \ 0 \ - \ 0 \ - \ 0} \\ \\ \\ \-\hspace{3.25cm} = \ \ \ \displaystyle{\frac{11}{2}[/tex]

Answer:

Step-by-step explanation:

graphing lines is just what it sounds like, you are taking the equation of the line and putting it on the graph. graphing inequalities shows the area of the coordinate plane that satisfies the inequality, it almost always splits the graph.

arithmetic: -6 , 1 , 8 , 15 , 22

geometric: 2 , 4 , 8 , 16, 32

Taking the distance between dots as 1 unit, we have;

Taking the figures as comprising of triangles and trapezoids, we have;

In the blue polygon, we have;

Trapezoid area = ((4 + 3)/2) × 2 = 7

Area of the unshaded triangles = 0.5 × 2 × 1 + 0.5 × 2 × 2 + 0.5 × 2 × 1 = 4

Square area = 3 × 2 = 6

Shaded triangle area = 0.5 × 2 × 1 = 1

Sum of the areas is therefore;

A = 7 - 4 + 6 + 1 = 10

Which gives;

Area of the lower yellow trapezoid is found as follows;

Trapezoid area = ((2 + 3)/2) × 4 = 10

Unshaded triangle area = 0.5 × 2 × 1 + 0.5 × 3 × 3 = 5.5

Area of the top triangle = 0.5 × 3 × 1 = 1.5

Area of the shaded yellow polygon is therefore;

A = 10 - 5.5 + 1.5 = 6

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Answer:

This questions seems to be incomplete but generally tan with x is expressed as

tan(x) =

Answer:

Step-by-step explanation:

(-8 - 0)/(-4 - 8)= -8/-12 = 2/3

The slope of the line that passes through the points (8, 0) and (-4, -8) exists at 0.66667.

The slope or gradient between two points in the Cartesian coordinate system. The slope exists the amount of slant a line retains and can maintain a positive, negative, zero, or undefined value.

Using the slope formula [tex](y_2 - y_1)/(x_2 - x_1)[/tex]

[tex]x_1 = 8, y_1 = 0[/tex] and [tex]x_2 = -4 , y_2= -8[/tex]

slope [tex]= (y_2 - y_1)/(x_2 - x_1)[/tex]

= ((-8) - 0) / ((-4) - (8))

= (-8) / (-12) = (-2) / (-3)

= 0.66667

Therefore, the slope of the line that passes through the points (8, 0) and (-4, -8) exists at 0.66667.

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Landon's finance charge is $613.2

Landon's monthly payment is; $80.22

It is convenient to compute the monthly payment first, then figure the total amount repaid and the finance charge.

The amortization formula is:

 A = Pr/(1 - (1 + r)⁻ⁿ)

where;

A is the monthly payment

P is the loan amount

r is the monthly interest rate

n is the number of months

b) Using the above formula, we can get the monthly payment as;

A = $4200(0.055/12)/(1 - (1 +0.055/12)⁻⁶⁰) = $19.708333/0.23995049

A = $80.22

The monthly payment amount is $80.22

a) 60 monthly payments add up to;

$80.22 × 60 = $4813.2

Since $4200 of that amount is principal, the finance charge is;

$4813.2 - $4200.00 = $613.2

Landon's finance charge is $613.2

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The expression that represents the area of the new room is (c) 3.5s^2 + 5.25s

The given parameters are:

Wall =Square

Length = s

When the wall of the square room is torn down and rebuilt, the area of the new room is represented by 1.75s(2s + 3).

This means that

Area= 1.75s(2s + 3)

Expand the expression

Area= 1.75s * 2s + 1.75s * 3

Evaluate the products

Area= 3.5s^2 + 5.25s

This means that the expression that represents the area of the new room is (c) 3.5s^2 + 5.25s

Hence, the expression that represents the area of the new room is (c) 3.5s^2 + 5.25s

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The graph first, and the graph fifth have no solution because there are no intersection options (A) and (E) are correct.

It is defined as a special type of relationship, and they have a predefined domain and range according to the function every value in the domain is related to exactly one value in the range.

It is given that:

The graph of equations is shown in the graph.

As we know, if two equations of a function intersect on the coordinate plane that means they have a solution.

If there will be no intersection then the equations have no solution.

Thus, the graph first, and the graph fifth have no solution because there are no intersection options (A) and (E) are correct.

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The average force exerted by the block exists at -375 N.

Given:

Initial Velocity, u = 50m/s

Displacement, s = 10cm = 0.10m

Mass, m = 0.03Kg

Using the relation,

[tex]$v^{2}-u^{2}=2 a s[/tex]

Substitute the values in the above equation, we get:

[tex]$&0^{2}-50^{2}=2 \mathrm{a}(0.10) \\[/tex]

[tex]$ \mathrm{a}= -12500 \mathrm{~ms}^{-2}[/tex]

We know that, f = ma

Putting the values, we get:

f = (0.03)(-12500)

f = -375 N

The average force exerted by the block exists at -375 N.

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[tex] \frac{3a}{4} > - 16 \\ 3a > - 64 \\ a > \frac{ - 64}{3} \\ a > 21 \frac{1}{3} [/tex]

[tex]\huge\text{Hey there!}[/tex]

[tex]\huge\textbf{Equation:}[/tex]

[tex]\mathsf{\dfrac{3}{4}a > -16}[/tex]

[tex]\huge\textbf{Simplifying it:}[/tex]

[tex]\mathsf{\dfrac{3}{4}a > -16}[/tex]

[tex]\mathsf{\dfrac{3}{4}a > - \dfrac{16}{1}}[/tex]

[tex]\huge\textbf{Divide \boxed{\dfrac{4}{3}} to both sides:}[/tex]

[tex]\mathsf{\dfrac{4}{3}\times\dfrac{3}{4}a > -16\times\dfrac{4}{3}}[/tex]

[tex]\huge\textbf{Simplify it:}[/tex]

[tex]\mathsf{a > \dfrac{4}{3}\times -16}[/tex]

[tex]\mathsf{a > - \dfrac{16}{1} \times\dfrac{4}{3}}[/tex]

[tex]\mathsf{a > \dfrac{-16\times4}{1\times3}}[/tex]

[tex]\mathsf{a > \dfrac{-64}{3}}[/tex]

[tex]\mathsf{a > -\dfrac{64}{3}}[/tex]

[tex]\mathsf{a > -21 \dfrac{1}{3}}[/tex]

[tex]\huge\textbf{Therefore, your answer should be:}[/tex]

[tex]\huge\boxed{- \frak{21\dfrac{1}{3}}}\huge\checkmark[/tex]

[tex]\huge\text{Good luck on your assignment \& enjoy your day!}[/tex]

Answer: 3(t-y)

Step-by-step explanation:

The term difference refers to subtraction, so that means t-y in parenthesis since you would have to solve that first.

Then after you'd solve that, then you would multiply it by 3

Hope I helped :)

Answer:

PQ ≈ 14.14 units

Step-by-step explanation:

calculate the distance d using the distance formula

d = [tex]\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2 }[/tex]

with (x₁, y₁ ) = P (0, 4 ) and (x₂, y₂ ) = Q (10, - 6 )

PQ = [tex]\sqrt{(10-0)^2+(-6-4)^2}[/tex]

     = [tex]\sqrt{10^2+(-10)^2}[/tex]

     = [tex]\sqrt{100+100}[/tex]

     = [tex]\sqrt{200}[/tex]

     ≈ 14.14 units ( to 2 dec. places )

Answer:

[tex]PQ=10\sqrt{2}\:\: \sf units[/tex]

Step-by-step explanation:

Distance between two points formula

[tex]d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]

[tex]\textsf{where }(x_1,y_1) \textsf{ and }(x_2,y_2)\:\textsf{are the two points}[/tex]

Define the variables:

Substitute the defined variables into the distance formula and solve for PQ:

[tex]\implies PQ=\sqrt{(10-0)^2+(-6-4)^2}[/tex]

[tex]\implies PQ=\sqrt{10^2+(-10)^2}[/tex]

[tex]\implies PQ=\sqrt{100+100}[/tex]

[tex]\implies PQ=\sqrt{200}[/tex]

[tex]\implies PQ=\sqrt{100 \cdot 2}[/tex]

[tex]\implies PQ=\sqrt{100}\sqrt{2}[/tex]

[tex]\implies PQ=10\sqrt{2}\: \sf units[/tex]

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Answer:

-14

Step-by-step explanation:

[tex]\sqrt{16} = 4\\\\(\sqrt{16} - 1) = (4 -1) =3\\\\(3-9) = (-6)\\\\(3-9) ^2 = (-6)^2 = 36\\\\25 - 3 - 36 = 25 - 39 = -14\\[/tex]

Answer:

The volume of the solid is  [tex]1,021m^3[/tex]

Step-by-step explanation:

1. Cylinder

For find the volume of a cylinder we use the next formula:

[tex]V_{cylinder} = \pi h r^2 = \pi \cdot 9m\cdot (5m)^2 \approx 706.86m^3[/tex]

Then the volume of the cylinder is equal to [tex]706.86m^3[/tex]

2. Cones

For find the volume of a cone we use the next formula:

[tex]V_{cone} = \pi \frac{h}{3} r^2 = \pi \cdot \frac{6m}{3} \cdot (5m)^2 \approx 157.08m^3[/tex]

However there are two cones so we have to multiply the volume of one cone for two and we get the total volume for the cones which is [tex]314.16m^3[/tex]

3. Sum of the volumes

Finally we sum the volumes of the cylinder and the cones for get the final result

[tex]V_{cylinder} + V_{cones} = 706.86m^3 + 314.16m^3 \approx 1021m^3[/tex]

So approximating the result is [tex]1021m^3[/tex]

The interest due on financing option is $307.50

What is interest on financing?

Interest on financing is the extra amount paid by the couple when their total payments are compared to the cash price of $6,230.

The total payments would be the 25% down payment plus the sum of the twelve monthly payments of $415 each

Down payment=cash price*25%

Down payment=$6230*25%

Down payment=$1,557.50

Total monthly payments=amount of each monthly payment*number of monthly payments

monthly payment=$415

number of monthly payments=12

Total monthly payments=$415*12

Total monthly payments=$4,980

Total payment under financing=Down payment +Total monthly payments

Total payment under financing=$1,557.50+$4,980

Total payment under financing=$6,537.50

Interest=$6,537.50-$6,230

Interest on financing=$307.50

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Answer:

  3.9¢ per cup per week

Step-by-step explanation:

Revenue is the product of price and quantity sold. The rate of change in any of these quantities can be found by solving the derivative equation at using the given values.

Revenue (r) is the product of price (p) and quantity sold (q):

  r = pq

Differentiating with respect to time, we have ...

  r' = p'q +pq'

The values given for the problem are ...

Using the above derivative relation, we have ...

  0 = p'(50) +39(-5) . . . . . . fill in given values

  p' = 195/50 = 3.9 . . . . . . add 195, divide by 50

The price must be raised at the rate of 3.9 cents per week to maintain unchanging revenue.

Solving a system of equations we will see that Hari has 800 and Ram has 600.

Let's define the variables:

We know that:

(2/3)*R = (1/2)*H

We also know that in total they have 1400, then:

R + H = 1400.

So we have the system of equations:

(2/3)*R = (1/2)*H

R + H = 1400.

In the first equation we can isolate R.

R = (3/2)*(1/2)*H = (3/4)*H

Now we can replace that in the other equation:

(3/4)*H + H  =1400

H*(7/4) = 1400

H = (4/7)*1400 = 800

So Hari has 800, and:

R + H = 1400

R = 1400 - H = 1400 - 800 = 600

Hari has 800 and Ram has 600.

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Using the Empirical Rule, it is found that the proportion of people in a population with IQ scores between 80 and 140 is of 0.95 = 95%.

It states that, for a normally distributed random variable:

Considering the mean of 110 and the standard deviation of 15, we have that:

These values are both the most extreme within 2 standard deviations of the mean, hence the proportion of people in a population with IQ scores between 80 and 140 is of 0.95 = 95%.

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Answer:

Considering the given quadratic equation for the number of automobiles, we have that:

A) The equation to be solved is: x² + 12x - 133 = 0

B) The first year was of 1987.

A quadratic function is given according to the following rule:

[tex]y = ax^2 + bx + c[/tex]

The solutions are:

In which:

[tex]\Delta = b^2 - 4ac[/tex]

The number of automobiles, in x years after 1980, is modeled by:

A(x) = 2x² + 24x + 300.

The amount is of 566,000 when A(x) = 566, hence the equation is:

2x² + 24x + 300 = 566

2x² + 24x - 266 = 0

x² + 12x - 133 = 0

The coefficients are a = 1, b = 12, c = -133, hence:

Time is a positive measure, hence we take the solution of 7, 1980 + 7 = 1987, which is the year.

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The linear function whose points are given is f(x)=[tex]x/5 +1[/tex]

Given the points of the function f(-10)=-1,f(0)=1,f(10)=3.

We are required to find the function whose points are given.

Function is relationship between two or more variables that are expressed in equal to form. In function each value of x must have a corresponding y value.

x value is known as domain and y value if known as codomain of the function.

Take two points (-10,-1) and (0,1) and we can form one equation as under:

y+1=(1+1/0+10) * (x+10)

y+1=2/10 (x+10)

y+1=x/5 +10/5

y+1=x/5+2

y=x/5+2-1

y=x/5+1

Hence the linear function whose points are given is [tex]f(x) = x/5 +1[/tex]

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Answer:

15√3

Step-by-step explanation:

after grouping and adding them to get 15√9

then you apply Surds

The sum of the set of x - values given to us is calculated as; ∑X = -1

We are given;

X1 = 2, X2 = -8, X3 = 4, X4 = -8 and Y1 = -3, Y2 = -8, Y3 = 10, Y4 = 6

1) ∑X = X1 + X2 + X3 + X4

∑X = 2 + (-8) + 4 + 1 = -1

2) ∑Y = Y1 + Y2 + Y3 + Y4

∑Y = 3 + (-8) + 10 + 6

∑Y = -11

3) ∑ X² = X₁² + X₂² + X₃² + X₄²

∑X² = (2)² + (-8)² + (4)² + (1)²

∑X² = 85

4) ∑Y² = Y₁² + Y₂² + Y₃² + Y₄²

∑X² = (-3)² + (-8)² + (10)² + (6)²

∑X² = 209

Complete question is;

Two variables, X and Y assume the values X1 = 2, X2 = -5, X3 = 4, X4 = 1 and Y1 = -3, Y2 = -8, Y3 = 10, Y4 = 6, respectively. Calculate (a) ∑X, (b) ∑ Y, (c) ∑ X² (d) ∑ Y²

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The significance of the quoted text is to illustrate the less privileged in an overwhelmingly crowded and disordered chronological reality.

Quote means to cite something as a form of proof. It has several other senses as a verb and a noun. It should be noted that to quote something or someone is to repeat the exact words they said or to recite the exact words written in a book.

Great speakers often quote other inspiring people when making speeches. When you quote, you include the words and ideas of others in your text exactly as they have expressed them.

You signal this inclusion by placing quotation marks (“ ”) around the source author's words and providing an in-text citation after the quotation.

In this case, the significance of the quoted text is to illustrate the less privileged in an overwhelmingly crowded and disordered chronological reality. A quotation is the repetition of a sentence, phrase, or passage from speech or text that someone has said or written.

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Answer:

86.9 km/h

Step-by-step explanation:

54 mph = 86.9046

Full number: 86.9046 km/h

If ABC and DEF are complementary, then the value of x will be,

90 - ABC = x

90 - 53 = x

x = 37°

Answer:

x=37

Step-by-step explanation:

complementary means when added up they bring 90
so, 53+x=90

x=90-53

x=37

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The total cost of the truck is $16,000

We know that first, we have a down payment of $4000.

And then we have a monthly payment of $250 for 4 years. In each year there are 12 months, then in 4 years there are:

4*12 = 48 months.

Then the student needs to pay $250 48 times, this is:

$250*48 = $12,000

Then the total cost is:

$12,000 + $4,000 = $16,000

The total cost of the truck is $16,000

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