When the points in a scatter plot cluster closely around the regression line, the correlation can be said to be?

Answers

Answer 1

The points in a scatter plot cluster closely around the regression line, the correlation can be said to be the proportion of variance in Y that is determined or explained by X.

It is critical to understand that a correlation coefficient of zero indicates that there is no linear courting, but there can also nonetheless be a strong relationship among the 2 variables.

If one point of a scatter diagram is farther from the regression line than a few other factor, then the scatter diagram has as a minimum one outlier. If two or extra points are the identical farthest distance from the regression line not a commonplace prevalence), then every of those points is an outlier.

When the y variable has a tendency to increase because the x variable increases, we say there may be a high-quality correlation between the variables. when the y variable has a tendency to lower as the x variable increases, we are saying there's a bad correlation between the variables.

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Related Questions

Suppose 5 different integers are randomly chosen from between 20 and 69, inclusive. What is the probability that they each have a different tens digit?

Answers

The probability that they each have a different tens digit is 0.047.

What is probability?

The area of mathematics known as probability deals with numerical representations of the likelihood that an event will occur or that a statement is true. An event's probability is a number between 0 and 1, where, roughly speaking, 0 denotes the event's impossibility and 1 denotes certainty. The likelihood that an event will occur increases with its probability. A straightforward illustration is tossing a fair (impartial) coin. The probability of either "heads" or "tails" is half because there are only two possible outcomes (heads or tails), and because the coin is fair, both outcomes (heads and tails) are equally likely.

Solution:- The collection contains 50 integers, hence there are [tex]^{50}C_5[/tex] different ways to select 5 different integers.

Sample space = [tex]^{50}C_5[/tex]

Each of the five numbers must correspond to one of the five available tens-digits, which are 2 through 6. There are a total of 105 ways to choose the five numbers that satisfy these properties because there are 10 ways to choose a number with a particular set of ten digits (such as 30, 31, or 39).

Therefore,

probability that each have a different tens digit = [tex]\frac{10^5}{^{50}C_5}[/tex]

                                                                                = [tex]\frac{10\times 10\times 10\times 10\times 10}{^{50}C_5}[/tex]

                                                                                = [tex]\frac{10\times 10\times 10\times 10\times 10}{\frac{50!}{(50-5)!5!} }[/tex]

                                                                                = [tex]\frac{10\times 10\times 10\times 10\times 10}{\frac{50!}{45!5!} }[/tex]

                                                                                 = 0.047

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Write the equation for a parabola with a focus at (-4,8) and a directrix at x=-6
x= ?

Answers

The equation for the parabola with a focus at (-4,8) and a directrix at x=-6 is ( y - 8)² = 4( x +5 ).

What is the equation for a parabola with a focus at (-4,8) and a directrix at x = -6?

Given that x = -6, it means the directrix is horizontal.

Equation of parabola that opens left or write is expressed as;

( y - k )² = 4p( x - h )

Given that;

Focus: ( -4, 8 )Directrix: y = -6

First, we find the vertex.

The vertex( h, k ) is halfway between the directrix and the focus.

Hence, x coordinate of the vertex is;

x = ( x coordinate of focus + directrix ) / 2

x = ( -4 + (-6) ) / 2

x = -10/2

x = -5

y coordinate of the vertex will be the same as that of the focus.
y = 8

Hence vertex will be;

( -5, 8 )

Next, we find the distance p from the focus to the vertex and from the vertex to the directrix.

Subtract x coordinate of vertex from x coordinate of focus.

p = -4 - ( -5 )

p = -4 + 5

p = 1

Now, we substitute these values into the equation.

( y - k )² = 4p( x - h )

( y - (8) )² = 4(1)( x - (-5) )

( y - 8)² = 4( x +5 )

Therefore, the equation for the parabola with a focus at (-4,8) and a directrix at x=-6 is ( y - 8)² = 4( x +5 ).

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Write the algebraic expression that represents the following: The difference of thirteen and a number

Answers

[tex]\Large\texttt{Answer}[/tex]

[tex]\bold{n-13}[/tex]

[tex]\overline{\qquad\qquad\qquad\qquad\qquad\qquad\qquad\qquad\qquad\qquad\qquad\qquad}[/tex]

[tex]\Large\texttt{Process}[/tex]

⇨ Again letting n be the number

[tex]\bold{n}[/tex]

⇨ Subtract 13 from n

[tex]\bold{n-13}[/tex]

*unlike addition, the order DOES matter, because

[tex]\bold{n-13\ne 13-n}[/tex]

Hope that helped

A carpenter can install 35 windows in 7 days. how many windows can he install in 15 days

Answers

Answer:

84

Step-by-step explanation:

Multiply 35 by 2.5

Answer:

75 windows

Step-by-step explanation:

35 ---- 7

x ----- 15

[tex]x=\frac{(35)(15)}{7} =75[/tex]

Hope this helps

Find the measure of angle x in the figure below
57
61
67

Answers

Answer:

51°

Step-by-step explanation:

posted answer to the question

(07.07 lc) a cheetah runs at a speed of 49 miles for every hour. if the distance traveled, in miles, is d and time, in hours, is t, which equation shows the relationship between d and t?

Answers

The relationship between d and t.

d = 49t

The correct equation is C.

What is Distance, speed and Time ?

How quickly something or someone is moving is determined by their speed. If you know how far an object has traveled and how long it has taken, you can calculate its average speed. Speed equals distance times time, according to the speed formula. Knowing the units for distance and time will help you determine what the units are for speed.

Given data:

speed = 49 miles/hour

Distance

Time

as we know :

Speed = Distance  /  Time .

Then:

49 = Distance/Time

Distance = 49*Time .

the relationship between d and t ( d = 49t).

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I understand that the question you are looking for is :

A cheetah runs at a speed of 49 miles for every hour. If the distance traveled, in miles, is d and time, in hours, is t, which equation shows the relationship between d and t?

A. d = 49 + t

B. t = 49 + d

C. d = 49t

D. t = 49d

What are the solutions of the system of equations y = –(x 2)2 1 and y = 4x 9? (–2, 1) and (6, –15) (–2, 1) and (–6, –15) (2, 1) and (6, –15) (2, 1) and (–6, –15)

Answers

The equations exist [tex]$y =-(x+2)^2+1[/tex] and [tex]y =4x+9[/tex] then the value of

x = -6, x = -2 and y = -15, y = 1.

How to solve the system of equations [tex]$y =-(x+2)^2+1[/tex] and

[tex]y =4x+9[/tex] ?

The given equations are [tex]$y =-(x+2)^2+1[/tex] and [tex]y =4x+9[/tex]

[tex]$-\left(x\:+\:2\right)^2\:+\:1\:=\:4x\:+\:9[/tex]

[tex]$-x^{2}-4 x-3=4 x+9[/tex]

Subtract 9 from both sides, we get

[tex]$-x^{2}-4 x-3-9=4 x+9-9[/tex]

Simplifying the equation, we get

[tex]$-x^{2}-4 x-12=4 x[/tex]

Subtract 4x from both sides

[tex]$-x^{2}-4 x-12-4 x=4 x-4 x[/tex]

[tex]$-x^{2}-8 x-12=0[/tex]

Solve with the quadratic formula

[tex]$x_{1,2}=\frac{-(-8) \pm \sqrt{(-8)^{2}-4(-1)(-12)}}{2(-1)}[/tex]

[tex]$\sqrt{(-8)^{2}-4(-1)(-12)}=4[/tex]

[tex]$x_{1,2}=\frac{-(-8) \pm 4}{2(-1)}[/tex]

Separate the solutions

[tex]$x_{1}=\frac{-(-8)+4}{2(-1)}, x_{2}=\frac{-(-8)-4}{2(-1)}[/tex]

[tex]$x=\frac{-(-8)+4}{2(-1)}=-6[/tex]

[tex]$x=\frac{-(-8)-4}{2(-1)}= \quad-2[/tex]

The solutions to the quadratic equation are x = -6, x = -2

From the above equation [tex]y =4x+9[/tex],

substitute the value of x, then we get

Put, x = -6 then y = 4(-6) + 9 = -15

Put, x = -2 then y = 4(-2) + 9 = 1

The system of equations exists (–2, 1) and (–6, –15).

Therefore, the correct answer is (–2, 1) and (–6, –15).

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Answer:

(–2, 1) and (–6, –15)

Step-by-step explanation:

flvs testing (i am not completely sure btw)

just substitute that into a last equations (seperatly if you understand=== -2 and 1 as x and y; -6 and -15 as x and y)

Arc CD is Two-thirds of the circumference of a circle. What is the radian measure of the central angle?
StartFraction 2 pi Over 3 EndFraction radians
StartFraction 3 pi Over 4 EndFraction radians
StartFraction 4 pi Over 3 EndFraction radians
StartFraction 3 pi Over 2 EndFraction radians

Answers

Using proportions, it is found that the radian measure of the central angle is given as follows:

[tex]\frac{4\pi}{3}[/tex] radians.

What is a proportion?

A proportion is a fraction of a total amount, and the measures are related using a rule of three. Due to this, relations between variables, either direct or inverse proportional, can be built to find the desired measures in the problem.

The entire circumference is equivalent to a central angle of [tex]2\pi[/tex] radians. Hence the radian measure of the central angle considering two-thirds of the circumference is given as follows:

[tex]\frac{2}{3} \times 2\pi = \frac{4\pi}{3}[/tex]

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Answer:

Step-by-step explanation:

c edge

If the mean on a test is 83 and the standard deviation is 6: What % has:

At least a 70% (passing with a C)

An 80 or above (a B)

Answers

Using the normal distribution, it is found that:

98.5% of students have at least a 70.69.15% of students have an 80 or above.

Normal Probability Distribution

The z-score of a measure X of a normally distributed variable with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex] is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The z-score measures how many standard deviations the measure is above or below the mean. Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.

The mean and the standard deviation for this problem are given, respectively, by:

[tex]\mu = 83, \sigma = 6[/tex]

The proportion of students, with a grade of at least 70 is one subtracted by the p-value of Z when X = 70, hence:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{70 - 83}{6}[/tex]

Z = -2.17

Z = -2.17 has a p-value of 0.015.

1 - 0.015 = 0.985 = 98.5% of students have at least a 70.

The proportion of students, with a grade of at least 80 is one subtracted by the p-value of Z when X = 80, hence:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{80 - 83}{6}[/tex]

Z = -0.5

Z = -0.5 has a p-value of 0.3085.

1 - 0.3085 = 0.6915 = 69.15% of students have an 80 or above.

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Line m contains the points (4, 16) and (0, 8). At what point will line m intersect with line n if the equation of line n is -8x+4y=24 ?

A) (0, 0)
B) (-4, 0)
C) The lines don't intersect
D) The lines intersect at an infinite number of points

Answers

The correct option regarding the point at which the linear functions intersect is given by:

C) The lines don't intersect.

What is a linear function?

A linear function is modeled by:

y = mx + b

In which:

m is the slope, which is the rate of change, that is, by how much y changes when x changes by 1.b is the y-intercept, which is the value of y when x = 0, and can also be interpreted as the initial value of the function.

For line m, we have that the y-intercept is of b = 8. When x changes by 4, y changes by 8, hence the slope is of 2, and the equation is:

y = 2x + 8.

Line n, in slope-intercept format, is given by:

-8x + 4y = 24

4y = 8x + 24

y = 2x + 6

Hence:

2x + 8 = 2x + 6

0x = -2

Which is impossible, hence they do not intersect and option C is correct.

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PLEASE ANSWER!!
A soccer team won only 10 of their first 30 games. How many of their remaining 20 games will they have to win to have a .500 record??

Answers

Answer: 5 games

Step-by-step explanation: They need to win half their games for a .500 record and half or 30 is 15. They already won 10 so they need to win 15- 10 = 5 more games to have a .500 record.

Identify the slope type of the graph shown above.
Question 15 options:

A)

Undefined

B)

Zero

C)

Positive

D)

Negative

Answers

Answer is B. Zero
Reason
Pick any points on that line, they will have the same y value , it means they lie on a horizontal line. The slope of such a line is 0.

Answer:

Zero

Step-by-step explanation:

Evaluate the integral
1
2
sin ¹(x/4)) ² dx
| (si
- 1
2
[(sin ~'(x/4)) ² dx
√16-x²
2
√16-x²
11

Answers

Substitute [tex]y=\sin^{-1}\left(\frac x4\right)[/tex], so that

[tex]dy = \dfrac{dx}{4\sqrt{1-\left(\frac x4\right)^2}} = \dfrac{dx}{\sqrt{16 - x^2}}[/tex]

Then the integral is

[tex]\displaystyle \int \frac{\left(\sin^{-1}\left(\frac x4\right)\right)^2}{\sqrt{16-x^2}} \,dx = \int y^2 \, dy[/tex]

and by the power rule,

[tex]\displaystyle \int y^2 \, dy = \frac13 y^3 + C[/tex]

so that the original integral is

[tex]\displaystyle \int \frac{\left(\sin^{-1}\left(\frac x4\right)\right)^2}{\sqrt{16-x^2}} \,dx = \boxed{\frac13 \left(\sin^{-1}\left(\frac x4\right)\right)^3 + C}[/tex]

Quick algebra 1 question for 10 points!

Only answer if you know the answer, quick shout-out to tariqareesha2 and MrBrainly, tysm for the help!

Answers

Use hit and trial method

Answer is (-1,4)

Verification

Put x and. y

5(-1)+3(4)=-5+12=-73(-1)-5(4)=-3-20=-23Verified

Option A

O Yes
O No
2. (02.01 LC)
Is the following relation a function? (1 point)
{(3,-2), (1, 2), (-1,-4), (-1, 2)}

Answers

Answer:

no

Step-by-step explanation:

In a function, each "x" value [input] must have only one corresponding "y" value.

We know that points are written as (x, y)

Our points: {(3,-2), (1, 2), (-1,-4), (-1, 2)}

We can see that the x-input of -1 has two y-outputs, so this is therefore not a function

hope this helps! have a lovely day :)

Using flowcharts, programmers can break large systems into subsystems that are easier to understand and code.
a. true
b. false

Answers

It is True that Using flowcharts, programmers can break large systems into subsystems that are easier to understand and code.

What is the use of flowcharts?

A flowchart  serves a picture  consisting the separate steps of a process which is in sequential order and can be used to  break large systems into subsystems during programing.

If a more cohesive module is needed, it can be formed into one unit, having the performance of  multiple functions.

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A dairy farmer decides to sell three fifth of her 500 cows. How many cows will she be left with after the deal is complete?

Answers

Answer is 200 cows
Step by step
She is selling 3/5 of 500
Multiply across 3/5 x 500
1500/5 divide to get 300 sold
Now 500-300 sold = 200 cows left
Problem solved

Eggplant has a yield of 81%. If you purchase 12lb of eggplant, how many pounds will you be able to use?(round to the nearest hundredth pound)

Answers

Answer:

9.72 lb

Step-by-step explanation:

Yield = the amount or quantity produced or returned.

Given:

Yield of eggplant = 81%Amount of eggplant purchased = 12 lb

To determine how many pounds of eggplant you will be able to use, calculate 81% of the amount of eggplant purchased.

[tex]\begin{aligned}\sf 81\% \: of \: 12 \: lb & = \sf \dfrac{81}{100} \cdot 12\\\\& = \sf \dfrac{81 \cdot 12}{100}\\\\& = \sf \dfrac{972}{100}\\\\& = \sf 9.72\:lb\end{aligned}[/tex]

Therefore, you will be able to use 9.72 lb (nearest hundredth).

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Purchase=12lb

Amount to be used

81% of 120.81(12)9.72lb

You will be able to use 9.72pounds

Please help me( '人' )​

Answers

Answer:

S(1,2)

Step-by-step explanation:

The value that is being altered is the y value if you go from Q to T and then T to S. The x value = 1 and remains the same for point S.

To go from Q to T, you go from 8 to 5 on the y value. Remember x remains the same. That's three units (8 - 5 = 3)

To go from T to S must be 3 units as well, since the small diagonal is bisected. 5 - 3 = 2 is the answer.

So point S is noted as S(1,2)

Helpppppp show your work

Answers

Answer:

-5/3

Step-by-step explanation:

Do PEMDAS

8 - 11 = -3

-3 ^ 3 = -27

-(-27) = 27

I-14I = 14

3 x 14 = 42

27 - 42 = -15

2^4 = 16

16 - 7 = 9

-15/9 = -5/3

the correct answer would be-5/3

Find the explicit form of the arithmetic function of n if the first term is 3 and the common difference is -4 . Then find the seventh term.

Answers

The explicit function is (b) f(n) = -4(n - 1) + 3; the seventh term is -21

How to determine the explicit form?

The given parameters are:

First term of the sequence, a = 3Common difference of the sequence, d = -4

The explicit form is for an arithmetic function.

An arithmetic function has an explicit form represented as:

f(n) = a + (n -1) * d

Substitute the values of n and a in the above equation

f(n) = 3 + (n -1) * -4

Evaluate the product i.e. multiply -4 by (n - 1)

f(n) = 3 -4(n - 1)

Rewrite the equation as

f(n) = -4(n - 1) + 3

The seventh term is then calculated as:

f(n) = -4(n - 1) + 3

Substitute 7 for n in the above equation

f(7) = -4(7 - 1) + 3

Evaluate

f(7) = -21

Hence, the explicit function is (b) f(n) = -4(n - 1) + 3; the seventh term is -21

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pls help questions 1-5 and 6-10

Answers

Step-by-step explanation:

1.on foot -270

by bus-180

byMTR- 126

BY SCHOOL BUS -144

2.68%

4.94%

5.70%

7.16

9.72

10.960

Quick algebra 1 question for 10 points!

Only answer if you know the answer, quick shout-out to tariqareesha2 and MrBrainly, tysm for the help!

Answers

Answer:

12.50h = 2500.75

Step-by-step explanation:

He earned $12.50 for 1 hour of work.

For 2 hours, he earned $12.50 × 2.

For 3 hours, he earned $12.50 × 3.

For h hours, he earned $12.50 × h which can be simply written as 12.50h

He earned altogether $2500.75, so 12.50h must equal 2500.75.

Answer: B 12.50h = 2500.75

Answer:

[tex]12.50 h = 2500.75[/tex]

Step-by-step explanation:

We know from the question that the student earned $12.50 per hour.

Using this information, we can say that if the student worked for h hours, they would make a total of 12.50 × h dollars.

We also know that the total money they earned is $2500.75.

∴ Therefore, we can set up the following equation:

12.50 x h = 2500.75

From here, if we want to, we can find the number of hours worked by simply making h the subject of the equation and evaluating:

[tex]h=\frac{2500.75}{12.50}[/tex]

= 200.6 Hours

if a skip rope is a meter long and its a cm less how much is it pls answer

Answers

Answer:

99cm

Step-by-step explanation:

A meter is equal to 100cm

The rope is a metre (m) long but a centimetre (cm) less.

100cm - 1cm = 99cm

The average of three numbers, p, q and 27 is 28.The average of five numbers p, q, r, s and 27 is 31.Find the average of r and s.

Answers

Using the given information, the average of r and s is 35.5

Calculating Average

From the question, we are to determine the average of r and s

From the give information,

The average of p, q and 27 is 28.

That is,  

(p + q + 27)/3 = 28

p + q + 27 = 3×28

p + q + 27 = 84

p + q = 84 - 27

p + q = 57

Also,

The average of p, q, r, s and 27 is 31

That is,

(p + q + r + s + 27)/5 = 31
p + q + r + s + 27 = 5 × 31

p + q + r + s + 27 = 155

Thus,

57 + r + s + 27 = 155

r + s = 155 - 57 - 27

r + s = 71

The average of r and s is (r + s)/2

(r + s)/2 = 71/2

(r + s)/2 = 35.5

Hence, the average of r and s is 35.5

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how do I calculate y=3x - 2 without knowing thw value of x​

Answers

Answer:

Step-by-step explanation:

easy

y=3x-2

-3x+y=-2

-3x=-2-y

x=2/3+1/3y

Please help with this geometry question

Answers

It has been proven that of all line segments drawn from a given point not on it, the perpendicular line segment is the shortest.

How to prove a Line Segment?

We know that in a triangle if one angle is 90 degrees, then the other angles have to be acute.

Let us take a line l and from point P as shown in the attached file, that is, not on line l, draw two line segments PN and PM. Let PN be perpendicular to line l and PM is drawn at some other angle.

In ΔPNM, ∠N = 90°

∠P + ∠N + ∠M = 180° (Angle sum property of a triangle)

∠P + ∠M = 90°

Clearly, ∠M is an acute angle.

Thus; ∠M < ∠N

PN < PM (The side opposite to the smaller angle is smaller)

Similarly, by drawing different line segments from P to l, it can be proved that PN is smaller in comparison to all of them. Therefore, it can be observed that of all line segments drawn from a given point not on it, the perpendicular line segment is the shortest.

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23. Which expression is NOT equivalent
to the expression 38 – 14?
A 2(19-7)
B 24
C (19-7)2
D 2(36-12)

Answers

Answer: [D] 2(36-12)

Step-by-step explanation:

    First, we will simplify the given expression.

38 – 14 = 24

    Now, we will see if the other expressions are equivalent or not.

[A] 2(19-7) = 24

[B] 24 = 24

[C] (19-7)2 = 24

[D] 2(36-12) = 48

    The expression is NOT equivalent to the expression 38 – 14 is;

                   [D] 2(36-12)

Hi :)

Let's evaluate all these expressions

———————

[tex]\boldsymbol{\boxed{38-14=24}}}[/tex]

  So Now the question boils down to --

What expression is NOT equivalent to [tex]\boldsymbol{24?}[/tex]

Option (A).

     [tex]\boldsymbol{2(19-7)}[/tex]

     [tex]\boldsymbol{2(12)}[/tex]

     [tex]\boldsymbol{24}[/tex]

Option (A) is ruled out, because we're looking for expressions that are not equivalent to 24.

Option (B)

   Well 24 is always equal to 24!

Option (C)

     [tex]\boldsymbol{(19-7)2}[/tex]

     [tex]\boldsymbol{(12)2}[/tex]

     [tex]\boldsymbol{24}[/tex]

Option (D)

    [tex]\boldsymbol{2(36-12)}[/tex]

     [tex]\boldsymbol{2(24)}[/tex]

     [tex]\boldsymbol{48}[/tex]

[tex]\tt{Learn\;More;Work\;Harder}[/tex]

:)

What is the exact value of cos(c d), given sine c = startfraction 24 over 25 endfraction for c in quadrant ii and cosine d = negative three-fourths for d in quadrant iii?

Answers

The exact value of cos(c+d) is (D) [tex]cos(c+d) = \frac{21+24\sqrt{7} }{100}[/tex].

What are trigonometric functions?Trigonometric functions are real functions in mathematics that connect an angle of a right-angled triangle to ratios of two side lengths. They are widely utilized in all geosciences, including navigation, solid mechanics, celestial mechanics, geodesy, and many more.

To find the exact value of cos(c+d):

In the second quadrant:

 c = 180° -arcsin(24/25) ≈ 106.26°

In the third quadrant:

 d = 360° -arccos(-3/4) ≈ 221.41°

Then cos(c+d) = cos(327.67°) ≈ 0.84498

This is a positive irrational number, greater than 21/100, so the only reasonable choice is the last one:

[tex]\frac{21+24\sqrt{7} }{100}[/tex] ≈ [tex]0.84498[/tex]

To prove: Perhaps you want to work this out using the trignometric identities.

cos(c) = -√(1 -sin(c)²) = -7/25

sin(d) = -√(1 -cos(d)²) = -(√7)/4

Then the desired cosine is: cos(c+d) = cos(c)cos(d) -sin(c)sin(d)

cos(c+d) = (-7/25)(-3/4) -(24/25)(-√7/4)

Therefore, the exact value of cos(c+d) is (D) [tex]cos(c+d) = \frac{21+24\sqrt{7} }{100}[/tex].

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The complete question is given below:

What is the exact value of cos(c+d), given sine c = start fraction 24 over 25 end fraction for c in quadrant ii and cosine d = negative three-fourths for d in quadrant iii?

(A) Negative StartFraction 47 Over 100 EndFraction

(B) Negative 1 and StartFraction 3 Over 100 EndFraction

(C) StartFraction 21 minus 24 StartRoot 7 EndRoot Over 100 EndFraction

(D) StartFraction 21 + 24 StartRoot 7 EndRoot Over 100 EndFraction

18
Which point is located at (-0.5.0.75)?
N
00
M
Opoint B
point G
point M
G
B
X

Answers

Answer:

Point Z

Step-by-step explanation:

Since the scale is one, first you go 0.5 to the left (-0.5 X) then you go 0.75 up (0.75 Y) then you have your answer.

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