The project is considered to be complete when the EV is equal to the AC. So option b is correct.
When a project is considered complete, it means that the total amount of work that was planned to be done (referred to as the Budget at Completion or BAC) has actually been completed and the amount spent on completing the work so far EV is equal to the BAC.
In project management, Earned Value (EV) and Actual Cost (AC) are two key measurements used to quantify the exhibition of a project.
Earned Value (EV) addresses the arranged value of the work that has been finished. It is calculated by multiplying the arranged completion rate by the Budget at Completion (BAC).
Actual Cost (AC) addresses the actual measure of cash spent on the project in a limited way of time. It is the amount of the multitude of costs caused for the finished work and the work underway.
At the point when the Earned Value (EV) is equivalent to the Actual Cost (AC), it implies that all the arranged work has been finished and all the budget has been spent.
This is a decent indication that the project is on target and is probably going to be finished within the arranged budget.
Thus, when the Earned Value (EV) is equivalent to the Actual Cost (AC), the project is thought of as complete.
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Meryl pays £400 into her sister's South African bank account. How much money did her sister receive if the current exchange rate is £1 = R19,29?
The price of one currency in respect to another is referred to as its exchange rate.
What is meant by current exchange rate?An exchange rate in the world of finance is the price at which one currency will be exchanged for another. The majority of the time, currencies are national ones, but they can also be supra-national ones like the euro or sub-national ones like Hong Kong.
A currency's price in relation to another is known as its exchange rate. You can have fixed or fluctuating exchange rates. While a country's central bank controls fixed exchange rates, the process of supply and demand on the open market controls floating exchange rates.
The rate at which one currency can be exchanged for another between countries or economic zones is known as the exchange rate. It is crucial in assessing trade and capital movement dynamics and is used to calculate the value of various currencies in respect to one another.
Convert the currency:
£ 400 × R 19.29/£2 = R 7,716
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Consider the following input-output table. Row P Q R S
1 1 1 1 0
2 1 1 0 1
3 1 0 1 0
4 q 0 0 0
5 0 1 1 0
6 0 1 0 1
7 0 0 1 0
8 0 0 0 0
The output column, S, was created from the student ID 21444368 using the algorithm: - If ID digit n (left-to-right) is an even integer, place a 0 in S, row n (top-down) - If ID digit n (left-to-right) is an odd integer, place a 1 in S, row n (top-down) Create a similar table, but with S reflecting the result of the algorithm applied to your student ID (do this on scratch paper). On the quiz essay: 1. Record your student ID's column S as an ordered, horizontal list. For the example given, the list would be S=(0,1,0,0,0,1,0,0). 2. Write the disjunctive normal expression that would implement your student ID input/output table. Do not reduce the expression. Use the words "or." and "not" for the operators, and the letters P,Q,R, and S for the variables. For full credit show parentheses where required.
The output column, S, of the given input-output table was created from the student ID 21444368 using an algorithm where if the student ID digit is an even integer, a 0 is placed in the corresponding row of column S, and if the student ID digit is an odd integer, a 1 is placed in the corresponding row of column S.
Student ID: 81725225
P Q R S
1 1 1 0
1 1 0 1
1 0 1 1
0 1 0 0
0 0 1 1
0 1 1 0
0 0 0 1
Student ID: 81725225
P: The first digit of my student ID is 8 so it is an even integer, therefore I place a 0 in row 1 of column P.
Q: The second digit of my student ID is 1 so it is an odd integer, therefore I place a 1 in row 2 of column Q.
R: The third digit of my student ID is 7 so it is an odd integer, therefore I place a 1 in row 3 of column R.
S: The fourth digit of my student ID is 2 so it is an even integer, therefore I place a 0 in row 4 of column S.
The resulting table is:
P Q R S
1 1 1 0
1 1 0 1
1 0 1 1
0 1 0 0
0 0 1 1
0 1 1 0
0 0 0 1
The output column, S, of the given input-output table was created from the student ID 21444368 using an algorithm where if the student ID digit is an even integer, a 0 is placed in the corresponding row of column S, and if the student ID digit is an odd integer, a 1 is placed in the corresponding row of column S. The same algorithm was applied to my student ID 81725225, resulting in the table shown above.
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Let A, and A2 be subsets of a set U. Draw a Venn diagram of this situation and shade in the subsets Ain A2, Ag n A2. Ain As, and A§n AS . Use the resulting diagram and the definition of partition to convince yourself that the subset of these four subsets that are nonempty form a partition of U.
Set A is a subset of set B if every element of A is also an element of B
In a Venn diagram, what is a subset?If every element of set A is also an element of set B, then set A is a subset of set B. This is expressed in symbols as A B or. For example, suppose you’re representing all of the nations in the globe, and set A represents Finland and Greece, while set B represents all of Europe.
If a set A is a subset of a larger set B, the circle representing set A is drawn within the circle representing set B.
If sets A and B share certain components, we can symbolize them by drawing two overlapping circles.
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You can model the population of a certain city between the years 1970 and 1955 by the radical function P(x)=80000x−1940√3 . Using this model, in what year was the population of that city 290,000?
The year the population of that city was 290,000 is 1988.
What year was the population of that city 290,000?A model function is a mathematical or computational representation of a system or process that is designed to capture its behavior, relationships, and interactions.
The model is p(x) = 80,000 ∛(x - 1940)
Now use p(x) = 290,000and solve for x
290,000 = 80,000 ∛(x - 1940) =
290,000 / 80,000 = ∛(x - 1940)
29/8 = ∛(x - 1940)
x - 1940 = [29/8]³
x - 1940 = 47.63
x = 1940 + 47.63
x = 1987.63
Therefore, the year is 1988
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Please answer all questions (If correct will give brainliest)
1. Prove or Disprove the figure defined by points A,B,C, and D is a rhombus.
2. Prove or Disprove that point (4.00,4.50) lies on circle O centered at the origin.
3. Prove the diagonals of the rhombus ABCD bisect each other.
The coordinates (4.0 , 4.5) to the center is not the distance of radius
How to show that diagonals of the rhombus ABCD bisect each other?From the circle formula centered at origin: x² + y² = r²
Where r is the radius of the circle. and by substitution for the various values of x, y and r we have
x² + y² = 6² = 36
Also, substituting the values of the lengths of the line we have
(4)² + (4.5)² = 16 + 20.25 = 36.25 ≠ 36
This proves the diagonals of the rhombus ABCD bisect each other
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A piecewise function f (x) is defined by f of x is equal to the piecewise function of 2 to the power of the quantity x plus 1 end quantity minus 3 for x is less than or equal to 2 and the quantity 10 over x for x is greater than 2
Part A: Based on the graph of f (x), what is the range? (5 points)
Part B: Determine the asymptotes of f (x). (5 points)
Part C: Describe the end behavior of f (x). (5 points)
Part A: The range of a function is the set of all possible outputs (y-values) for the given domain of the function. In this case, the domain of f(x) is all real numbers. We can find the range of f(x) by analyzing the two different parts of the piecewise function:
For x <= 2, f(x) = 2^(x+1) - 3. The minimum possible output for this function is y = -1 (when x = -1) and the maximum possible output is y = 3 (when x = 0).
For x > 2, f(x) = 10/x. The minimum possible output for this function is y = 0 (as x approaches infinity) and the maximum possible output is y = 10 (when x = 2)
So, the range of f(x) is [-1, 10].
Part B: The asymptotes of a function are the lines that the graph of the function approaches but never touches. In this case, the graph of f(x) has a vertical asymptote at x = 0, because the function is not defined at x=0.
Part C: The end behavior of a function is the behavior of the function as the input (x) approaches positive or negative infinity. In this case, the function f(x) = 10/x as x > 2, as x approaches positive infinity the output(y) approaches 0, and as x approaches negative infinity the output(y) does not exist. Therefore, the end behavior of f(x) is that it approaches 0 as x approaches positive infinity.
i don’t have a question
Answer: Oh well how you doing?
Step-by-step explanation:
If needed call prevention hotline... if you know what I mean
Answer:
that’s brazy
Step-by-step explanation:
What is the triangle's base, b?
A=1/2bh and b=2A/h so
b=2A/h =2(12cm^2)/3cm=8cm
In order to find the base
We apply the area of a triangle formula to find the base
We know the formula to find the area of a triangle is,
[tex]A =\frac{1}{2}XbXh[/tex]
Here the area and the height is given
So the base is
[tex]12 = \frac{1}{2} X bX3[/tex]
Substituting the values we get
[tex]\frac{12X2}{3} = b[/tex]
[tex]8cm = b[/tex]
the length of a rectangle is (2x + 3) ft. and the width is (x - 4) ft. Find the perimeter and area in terms of x.
The perimeter of the rectangle is (6x - 2)ft and the area of the rectangle is (2x^2 - 5x - 12) square ft.
What is a rectangle?
A rectangle is a sort of quadrilateral with parallel sides that are equal to one another and four vertices that are all 90 degrees apart. Because of this, it is also known as an equiangular quadrilateral.
We are given that the length of a rectangle is (2x + 3) ft. and the width is
(x - 4) ft.
We know that perimeter of rectangle = 2(Length + Width)
So,
⇒Perimeter = 2(2x + 3 + x - 4)
⇒Perimeter = 2(3x - 1)
⇒Perimeter = (6x - 2)ft
We know that area of rectangle = Length * Width
So,
⇒Area = (2x + 3) * (x - 4)
⇒Area = 2x^2 - 8x + 3x - 12
⇒Area = (2x^2 - 5x - 12) square ft
Hence, the perimeter of the rectangle is (6x - 2)ft and the area of the rectangle is (2x^2 - 5x - 12) square ft.
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$375,000 zero interest loan
Quarterly payments of $18,000 for 5 years
Market rate of interest is 10%
1. What amount should be recorded for the asset purchase?
2. And what amount should be recorded for the liability used to purchase it?
The amount that should be recorded for the asset purchase is $375,000. This is the amount of the loan that is being used to purchase the asset.
The amount that should be recorded for the liability used to purchase the asset is also $375,000. This is the amount of the loan that is being taken on to purchase the asset.
Please help me with the following question.
a) The percentage of test takers that scored 1420 or higher is of: 2.87%.
b) The percentage of test takers that scored 800 or lower is of: 10.03%.
c) The percentage of students between 1500 and 1600 is given as follows: 0.8%.
d) The number of students eligible for the honors program is given as follows: 1040 students.
How to obtain probabilities using the normal distribution?The z-score of a measure X of a variable that has mean symbolized by [tex]\mu[/tex] and standard deviation symbolized by [tex]\sigma[/tex] is obtained by the rule presented as follows:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The z-score represents how many standard deviations the measure X is above or below the mean of the distribution, depending if the obtained z-score is positive or negative.Using the z-score table, the p-value associated with the calculated z-score is found, and it represents the percentile of the measure X in the distribution.The mean and the standard deviation for this problem are given as follows:
[tex]\mu = 1050, \sigma = 195[/tex]
The proportion of scores of 1420 or higher is one subtracted by the p-value of Z when X = 1420, hence:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
Z = (1420 - 1050)/195
Z = 1.9
Z = 1.9 has a p-value of 0.9713.
1 - 0.9713 = 0.0287 = 2.87%.
The proportion of test takers that scored 800 or lower is the p-value of Z when X = 800, hence:
Z = (800 - 1050)/195
Z = -1.28.
Z = -1.28 has a p-value of 0.1003.
The proportion between 1500 and 1600 is the p-value of Z when X = 1600 subtracted by the p-value of Z when X = 1500, hence:
Z = (1600 - 1050)/195
Z = 2.82
Z = 2.82 has a p-value of 0.9976.
Z = (1500 - 1050)/195
Z = 2.31
Z = 2.31 has a p-value of 0.9896.
Hence:
0.9976 - 0.9896 = 0.008 = 0.8%.
The proportion above 1550 is one subtracted by the p-value of Z when X = 1550, hence:
Z = (1550 - 1050)/195
Z = 2.56
Z = 2.56 has a p-value of 0.9948.
Hence:
1 - 0.9948 = 0.0052.
Out of 200,000 students, the number is given as follows:
0.0052 x 200,000 = 1040 students.
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solve the equation x−2=−9
Answer:
Step-by-step explanation:
x-2=-9
Add 2 on both sides
x=-7
Answer:
[tex]x=11[/tex]
Step-by-step explanation:
x−2=9
Add 2 to both sides.
x=9+2
Add 9 and 2 to get 11.
x=11
pls tell me if wrong
Consider the initial value problem
2 t y^{\,\prime} = 8 y, \ \ \ y(-1) = 2.
Find the value of the constant C and the exponent r so that y = C t^r is the solution of this initial value problem.
y = help (formulas)
Determine the largest interval of the form a < t < b on which the existence and uniqueness theorem for first order linear differential equations guarantees the existence of a unique solution.
help (inequalities)
What is the actual interval of existence for the solution (from part a)?
The actual interval of existence for the solution is all real numbers, including t = 0.
a. The characteristic equation for the differential equation is
2t dy/dt = 8y,
which gives us
dy/dt = 4/t y.
Separating variables, we have
dy/y = 4/t dt,
which integrates to
ln|y| = 4 ln|t| + C,
where C is an arbitrary constant of integration.
Taking the exponential of both sides, we obtain
|y| = Ce^(4ln|t|),
which gives us
y = C t^4.
Using the initial condition y(-1) = 2, we can find the value of C:
y(-1) = C(-1)^4
2 = C(-1)^4
C = -2.
So the solution to the initial value problem is
y(t) = -2 t^4.
b. The largest interval of the form a < t < b on which the existence and uniqueness theorem for first order linear differential equations guarantees the existence of a unique solution is t ≠ 0, since the coefficient of the differential equation is undefined at t = 0.
c. The actual interval of existence for the solution is all real numbers, including t = 0.
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Patients coming to a medical clinic have a mean weight of 207.6 pounds, with a standard deviation of 22.6 pounds. The distribution of weights is not assumed to be symmetric.
Between what two weights does Chebyshev's Theorem guarantee that we will find at least 95% of the patients?
Round your answers to the nearest tenth. Enter the pounds in ascending order.
Between 105.9 and 309.3 pounds, Chebyshev's Theorem guarantee that we will find at least 95% of the patients.
k = 4.5.
Weight 4.5 standard deviations below the mean is 207.6 − 4.5 (22.6) = 105.9 pounds.
Weight 4.5 standard deviations above the mean is 207.6 + 4.5 (22.6) = 309.3 pounds.
Therefore, at least 95% of patients weigh between 105.9 and 309.3 pounds.
About Chebyshev theoremIn probability theory, the Chebyshev inequality guarantees that for any sample data or probability distribution, nearly all values are close to the mean. Precisely, that no more 1/k2 of the distribution value exceeds the k standard deviation.
Chebyshev's inequality theorem can be used to find the probability range for an unknown distribution based on its mean and variance.
Chebyshev is named after a Russian mathematician, although the first formulation of the inequality was obtained from his colleague, Irénée-Jules Bienaymé. Chebyshev's inequality theorem was introduced without any proof in 1874, which later, in 1884,
Chebyshev's student, Andrey Markov presented a proof. Therefore, in the context of the analysis, the Chebyshev inequality is also expressed in the Markov inequality.
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Find the area of the trapezoid by composition of rectangle and triangles.
Responses
A 88 units2
B 72 units2
C 48 units2
D 84 units2
1 gallon=4.546 10 litres in gallon is approximately?
If 1 gallon = 4.546 litres, then 10 litres in gallon is approximately 2.2 gallons.
1 gallon = 4.546 litres,
∴ 1 litre = [tex]\frac{1}{4.546}[/tex] = 0.2199 gallon
∴ 10 litres = 10 × 0.2199 = 2.199 gallons ≅ 2.2 gallons
Thus, 10 litres in gallon is approximately equal to 2.2 gallons.
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NO LINKS!!
British sterling silver is a copper-silver alloy that is 7.5% copper by weight. How many grams of pure copper and how many grams of British sterling silver should be used to prepare 330 grams of a copper-silver alloy that is 10% copper by weight? (Round your answers to one decimal place.)
British sterling silver ____________ g
Copper ___________g
British sterling silver = 321.1 grams
Copper = 8.9 grams
========================================================
Work Shown:
x = amount of British sterling silver (in grams)330-x = amount of pure copper (in grams)The two amounts add to 330 grams total. The x is some number in the interval 0 < x < 330.
7.5% of x = 0.075x = amount of pure copper from the British sterling0.075x+(330-x) = -0.925x+330 = total amount of pure copperWe want to end up with 330 grams of 10% copper, so we want 0.10*330 = 33 grams of pure copper after mixing the two metals.
Set the 33 equal to the expression -0.925x+330 and solve for x.
-----------
-0.925x+330 = 33
-0.925x = 33-330
-0.925x = -297
x = -297/(-0.925)
x = 321.081 approximately
x = 321.1 when rounding to one decimal place
330-x = 330-321.1 = 8.9
-----------
We'll need 321.1 grams of British sterling silver.
We'll also need 8.9 grams of pure copper.
can someone just try to answer this ?:(
Ima fail
The compound inequality for the graph shown above include the following:
x < -2.
x > 5.
What is a number line?In Mathematics, a number line can be defined as a type of graph with a graduated straight line which comprises both positive and negative numerical values that are placed at equal intervals along its length.
Since the first point is at -2 and the arrow points to the left of the number line, it represents the less than (<) inequality symbol and should be written as x < -2.
Additionally, the second point is at 5 and the arrow points to the right of the number line, it represents the greater than (>) inequality symbol and should be written as x > 5.
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4. Determine the equation of the parabola with x-intercepts
a) -4 and 3, and that passes through (2, 7)
b) 0 and 8, and that passes through (-3, -6)
c) √7 and - √7, and that passes through (-5, 3)
5. Determine the equation of the parabola with vertex
a) (-2, 5) and that passes through (4, -8)
Answer:
4.
a.) -7/6 (x + 4)(x - 3) = y
b.) -6/121 (x-8)^2 = y
c.) 1/6 (x-sqrt 7)(x + sqrt 7) = y
5.
a.) -13/36 (x+2)^2 + 5 = y
Step-by-step explanation:
4. The intercept form of a quadratic equation is
[tex]y=a(x-p)(x-q)[/tex], where a is a number determining things like if the parabola opens up or down and how wide or narrow the parabola, while p and q are the x-intercepts.
Because we're given the x-intercepts and a point on the parabola, we can simply plug everything in and solve for a to find the equation of the parabola:
a.):
[tex]y=a(x-(-4))(x-3)\\y=a(x+4)(x-3)\\\\7=a(2+4)(2-3)\\7=a(6)(-1)\\7=-6a\\-7/6=a\\\\y=-7/6(x+4)(x-3)[/tex]
b.):
[tex]y=a(x-8)^2\\\\-6=a(-3-8)^2\\-6=a(-11)^2\\-6=121a\\-6/121=a\\\\y=-6/121(x-8)^2[/tex]
c.):
[tex]y=a(x-\sqrt{7})(x-(-\sqrt{7}))\\ y=a(x-\sqrt{7})(x+\sqrt{7})\\ \\ 3=a(-5-\sqrt{7})(-5+\sqrt{7})\\ 3=a(25-5\sqrt{7}+5\sqrt{7}-7)\\ 3=a(25-7)\\ 3=18a\\ 3/18=1/6=a\\ \\ 1/6(x-\sqrt{7})(x+\sqrt{7})=y[/tex]
5. The vertex form of a quadratic equation is
[tex]y=a(x-h)^2+k[/tex], where a is the same type of number as in the intercept form and (h, k) is the vertex.
Like the intercept form of the equation, we're given everything except a and thus we can plug in what we have and solve for a:
[tex]y=a(x-(-2))^2+5\\y=a(x+2)^2+5\\\\-8=a(4+2)^2+5\\-8=a(6)^2+5\\-8=36a+5\\-13=36a\\-13/36=a\\\\y=-13/36(x+2)^2+5[/tex]
the first 4 terms in a sequence are 8,5,2,-1... What is the recursive equation?
Help! Giving brainiest corrections due at 12pm today but I dont understand how to do this either
The length of the side BC is 96 units.
What is Triangle?A triangle is a two dimensional figure which consist of three vertices, three edges and three angles.
Sum of the interior angles of a triangle is 180 degrees.
Given that AD is an altitude of triangle ABC.
Altitude of a triangle is the line of perpendicular drawn from a vertex to the opposite side.
∠ADC = ∠ADB = 90°
Given that, ∠ADC = 4x + 10
4x + 10 = 90
4x = 80
x = 20
Length of BC = BD + DC
= 2x + 3x - 4
= 5x - 4
= (5 × 20) - 4
= 100 - 4
= 96
Hence the length of the side BC is 96.
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Refer to the accompanying data set and use the 30 screw lengths to construct a frequency distribution. Begin with a lower class limit of 2.720 in., and use a class width of 0.010 in. The screws were labeled as having a length of 2 3/4 in. Click on icon to view the data. Complete the frequency distribution below. Data Table 2.720-1 1-0 1-1 Screw Lengths (inches) 2.753 2.752 2.752 2.735 2.733 2.747 2.751 2.723 2.754 2.751 2.754 2.742 2.748 2.737 2.751 2.752 2.764 2.744 2.744 2.748 2.741 2.762 2.758 2.756 2.747 2.736 2.752 2.736 2.759 2.746 Type integers or decimals rounded to the nearest th Print Done
The frequency distribution table is given as
Length (in) Frequency
2.720 - 2.729 1
2.730 - 2.739 5
2.740 - 2.749 9
2.750 - 2.759 13
2.760 - 2.769 2
Given that the sample of the 30 screw lengths
2.753 2.762 2.752 2.735 2.733 2.747 2.751 2.723 2.754 2.751 2.754 2,742 2.748 2.737 2.751 2.752 2.764 2,744 2.744 2,748 2.741 2.762 2.758 2.756 2.747 2.736 2.752 2.736 2.759 2.746
For constructing a frequency distribution :
Lower class limit = 2.720 in.
Class width = 0.010 in
Frequency Distribution Table :
Length (in) Frequency
2.720 - 2.729 1
2.730 - 2.739 5
2.740 - 2.749 9
2.750 - 2.759 13
2.760 - 2.769 2
Total 30
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please help asap
• it would mean sm and make my day
For the given number line plot the inequality obtained is { -∞ < x < -2 and 5 < x < ∞}.
What is an inequality?
In Algebra, an inequality is a mathematical statement that uses the inequality symbol to illustrate the relationship between two expressions. An inequality symbol has non-equal expressions on both sides. It indicates that the phrase on the left should be bigger or smaller than the expression on the right, or vice versa.
To represent inequalities on a number line show the range of numbers by drawing a straight line and indicating the end points with either an open circle or a closed circle.
An open circle shows it does not include the value.
A closed circle shows it does include the value.
Let the unknown value be x.
The first range is starting form -2 and moving towards -∞.
Since the circle is open it will not include the value.
So the inequality is -∞ < x < -2.
The second range is starting form 5 and moving towards ∞.
Since the circle is open it will not include the value.
So the inequality is 5 < x < ∞.
Therefore, the inequality is { -∞ < x < -2 and 5 < x < ∞}.
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A box contains 3.69 g of supplies. How many milligrams more need to be added to bring the total weight up to an even 10,000 mg?
To make an even 10,000 mg of supplies, _____ mg need to be added.
Answer:
To find out how many milligrams more need to be added to bring the total weight of the supplies to 10,000 mg, we can subtract the current weight from 10,000:
10,000 - 3.69 g = 10,000 - 3,690 mg
Answer:
6,310 mg more need to be added to bring the total weight of the supplies to 10,000 mg.
The sun of Planet X has a diameter of about 860, 000 mi. The sun's distance from the surface of Planet X is
approximately 147,000,000 mi. Planet X's moon has a diameter of 18.7 mi. For a total solar eclipse to occur,
the moon must pass between the sun and Planet X. The moon must also be close enough to Planet X for the
moon's umbra (shadow) to reach the surface of Planet X. Complete parts (a) and (b) below
The Sun's diameter is 1.075*10² times the Earth's diameter.
Compare the Sun's and Earth's diameter ?Sun's Dimensions.The Sun's diameter is equal to 1.4 x 106 km when we multiply its distance by its observed angular diameter (about 0.5 degrees).
This is around ten times as big as Jupiter, the largest planet, and about 100 times as big as the Earth.
The Sun's diameter is times the Earth's diameter.
We are given the following in the question:
Sun's diameter = 860,000 miles
Earth's diameter = 8000 miles
Comparison of Sun's and Earth's diameter:
sun s diameter / earth diameter
= 860000/8000
8.6 *10(5)/8*10(3)
= 1.075*10(2)
Thus, the Sun's diameter is 1.075*10² times the Earth's diameter.
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B-1+3/15 pls help me I’m like stuck on this what’s the variable
Answer:
Step-by-step explanation:
b= -3
1kg/2.2lbs = X/165lbs
The answer is X=165 lbs (or) 74.84 kg.
Solution:
Given,
1kg/2.2lbs = X/165lbs,
So we get 1kg×165lbs= 2.2lbs×X,
By converting kg to lbs ∵ 1 kg= 2.2 lbs,
X=165 lbs.
∴ Hence X=165 lbs
Which expression is equivalent to (16x^4)^1/2
The expression that is equivalent to (16x^4)^1/2 is (64x^6)1/3.
What are equivalent expressions?Equivalent expressions are expressions that accomplish the same thing even when they have distinct appearances. Two algebraic expressions that are equivalent share a similar value whenever we enter exact same thing for the variable.
Given that;
[tex](16x^4)^{\frac{1}{2}}[/tex]
[tex]=\sqrt{16x^4}[/tex]
= 4x²
From the given options, (64x^6)^1/3 verifies the identity and shows that it is equivalent to (16x^4)^1/2.
[tex](16x^4)^{\frac{1}{2}} = (64x^6)^{\frac{1}{3}}[/tex]
[tex](16x^4)^{\frac{1}{2}} = (4^3)^{\frac{1}{3}} (x^6)^{\frac{1}{3}}[/tex]
[tex]4x^2= (4) (x^6)^{\frac{1}{3}}[/tex]
[tex]4x^2=4x^2[/tex]
Therefore, we can conclude that the expression that is equivalent to (16x^4)^1/2 is (64x^6)1/3
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Use the distributive property to remove the parentheses. -(-2y-4u+2)
Answer:
below
Step-by-step explanation:
This is the same as (-1)(-2y-4u+2) = 2y + 4u - 2
I need help with this x4 + 2x3 + x + 2
The factor of the expression could be [tex](x + 1)(x + 2)((x^2 -x + 1)[/tex]
What is factorization?Factorization is expressing a mathematical quantity in terms of multiples of smaller units of similar quantities.
factorization is the method of breaking a number into smaller numbers that multiplied together will give that original form.
We are given a expression as;
[tex]x^4 + 2x^3 + x + 2[/tex]
Thus,
[tex](x^4 + 2x^3) + (x + 2)[/tex]
Factor out x^3
[tex]x^3(x + 2) + (x + 2)[/tex]
Then;
[tex](x^3 + 1)(x + 2)[/tex]
Therefore, the factor of the given expression is;
[tex](x + 1)(x + 2)(x^2 -x + 1)[/tex]
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