Chemistry Middle School

When the speed of the bottle is 2 m/s, the KE is kg m2/s2. When the speed of the bottle is 3 m/s, the KE is kg m2/s2. When the speed of the bottle is 4 m/s, the KE is kg m2/s2. When the speed of the bottle is 5 m/s, the KE is kg m2/s2. When the speed of the bottle is 6 m/s, the KE is kg m2/s2.
instructions
In this part of the experiment, you will be changing the speed of the bottle by dropping it from different heights. You will use the same mass, 0.250 kg, for each trial, so record this mass in Table B for each velocity. Then, calculate the expected kinetic energy (KE) at each velocity. Use the formula KE = mv2,
where m is the mass and v is the speed. Record your calculations in Table B of your Student Guide.

Answers

Answer 1

Answer:

Based on the given instructions, you need to calculate the expected kinetic energy (KE) at each velocity using the formula KE = mv^2, where m is the mass and v is the speed. The mass is given as 0.250 kg.

Table B: Calculation of Kinetic Energy (KE)

Table B: Calculation of Kinetic Energy (KE)

Speed (m/s)Mass (kg)KE (kg m^2/s^2)20.2500.50030.2500.75040.2501.00050.2501.25060.2501.500

To calculate the kinetic energy at each velocity, multiply the mass (0.250 kg) by the square of the velocity.

For example, when the speed of the bottle is 2 m/s: KE = (0.250 kg) * (2 m/s)^2 = 0.250 kg * 4 m^2/s^2 = 1.000 kg m^2/s^2

Perform similar calculations for the other velocities and record the results in Table B.

Answer 2

Answer:

Explanation:mass of the bottle in each case is M = 0.250 kg

now as per given speeds we can use the formula of kinetic energy to find it

1) when speed is 2 m/s

kinetic energy is given as

2) when speed is 3 m/s

kinetic energy is given as

3) when speed is 4 m/s

kinetic energy is given as

4) when speed is 5 m/s

kinetic energy is given as

5) when speed is 6 m/s

kinetic energy is given as

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