ich two particles are found in the nucleus of an atom?
neutrons and electrons
protons and electrons
protons and neutrons
neutrons and atoms
The two particles found in the nucleus of an atom are protons and neutrons. Protons carry a positive charge, while neutrons are neutral. Electrons, though essential to atoms, are located outside the nucleus in electron shells or orbitals. Option 3.
The two particles found in the nucleus of an atom are protons and neutrons. The nucleus is the central part of an atom that contains most of its mass and is positively charged. Protons are positively charged subatomic particles that carry a charge of +1.
They are crucial in determining the atomic number and identity of an element. Neutrons, on the other hand, are electrically neutral subatomic particles that do not carry a charge. They have a mass similar to protons and play a role in stabilizing the nucleus through the strong nuclear force.
Electrons, which are negatively charged subatomic particles, are not found in the nucleus. Instead, they occupy regions called electron shells or orbitals surrounding the nucleus. Electrons have a negligible mass compared to protons and neutrons.
Atoms, as a whole, consist of a positively charged nucleus surrounded by these negatively charged electrons. The number of protons in the nucleus determines the atomic number of an element, while the combined number of protons and neutrons determines its mass number. Option 3 is correct.
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chemical equation for hydrogen chloride dissolving in water
Answer:
The answer is HCl → H 2 O H+ + Cl.
Calculate the frequency of radiation with a wavelength of 4.92 cm.
Which of the following statements is true about the relationships between photon energy, wavelength, and frequency?
Group of answer choices
The photon frequency is proportional to energy and inversely proportional to wavelength.
The photon frequency is inversely proportional to energy and proportional to wavelength.
The photon frequency is proportional to energy and proportional to wavelength.
The photon frequency is inversely proportional to energy and inversely proportional to wavelength.
Answer: The Answer is A.
Explanation:
The amount of energy is directly proportional to the photon's electromagnetic frequency and thus, equivalently, is inversely proportional to the wavelength. The higher the photon's frequency, the higher its energy. Equivalently, the longer the photon's wavelength, the lower its energy.
Hope this Helps!
The photon energy, wavelength, and frequency are the characteristic of the waves and particles. "The photon frequency is proportional to energy and inversely proportional to wavelength." Thus, option A is correct.
What is photon energy?Photon energy has been defined as the energy constituted by the photon of the atom. It is given by the product of Planck's constant and wave frequency. The frequency of the photons is in inverse relation to the wavelength. It is given as,
E = hυ = h c / λ
Here, E is energy, h is Planck's constant, c is the speed of light, υ id frequency, and λ is the wavelength.
On the other hand, the frequency is in direct relation to the energy. The higher the frequency of the photons higher will be its energy.
Therefore, option A. frequency is inversely proportional to the wavelength.
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An object is moving with a velocity in the positive direction. If
the object exseriences an acceleration opposite the direction
of its motion it would be a acceleration,
Enter the answer
Check it
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improve this question
Answer:
Please elaborate. Maybe if you had actual answer choices
Explanation:
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PLEASE ANSWERRRRRR
Calculate the energy needed to boil 125 g of water that is at 50 degree C.
The boiling point of water is 100 degree C.
The Specific Heat Capacity (c) of water is 4.184 J/g C.
Heat of Vaporization is 2260 J/g.
Answer:
Explanation:
206 kl.
Which of the following are evidence that chemical change has occurred
Answer:
gas given off
Explanation:
that's the answer
in terms of atomic structure explain why the first ionization energy of selenium is
a. Less than that of bromine (atomic number 35), and
b. Greater than that of tellurium (atomic number 52)
a. The first ionization energy of selenium is less than that of bromine because selenium has a larger atomic radius and a higher effective nuclear charge than bromine.
b. The first ionization energy of selenium is greater than that of tellurium because tellurium has a larger atomic radius and a higher shielding effect from inner electron shells compared to selenium.
a. The first ionization energy is the energy required to remove the outermost electron from an atom. In the case of selenium and bromine, the first ionization energy of selenium is less than that of bromine due to differences in atomic structure.
Selenium (atomic number 34) has a larger atomic radius than bromine (atomic number 35), meaning that the outermost electron in selenium is located farther from the nucleus. As a result, the attractive force between the outermost electron and the nucleus is weaker in selenium, making it easier to remove the electron and requiring less energy compared to bromine.
Additionally, selenium has a higher effective nuclear charge (the net positive charge experienced by the outermost electron) compared to bromine. The effective nuclear charge depends on the number of protons in the nucleus and the shielding effect of inner electron shells.
Despite having one less proton than bromine, selenium has a greater effective nuclear charge due to its smaller atomic size and less shielding from inner electron shells. This stronger attraction between the nucleus and the outermost electron in bromine requires more energy to remove the electron, resulting in a higher first ionization energy for bromine.
b. The first ionization energy of selenium is greater than that of tellurium (atomic number 52) because tellurium has a larger atomic radius and a higher shielding effect. Tellurium has more electron shells compared to selenium, resulting in a larger atomic size and greater shielding of the outermost electron from the nucleus.
The larger atomic size leads to a weaker attractive force between the nucleus and the outermost electron in tellurium, making it easier to remove the electron and requiring less energy compared to selenium. Therefore, selenium has a higher first ionization energy than tellurium.
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Determine the number of atoms of C in 30.2 grams of C₁₂H₂₂O₁₁.
Number of atoms of C in 30.2 grams of C₁₂H₂₂O₁₁ = 6.39 × 10²³ atoms
Given that mass of C₁₂H₂₂O₁₁ is 30.2 grams.
We are to find out the number of atoms of C in 30.2 grams of C₁₂H₂₂O₁₁.
In order to calculate the number of atoms of C in 30.2 grams of C₁₂H₂₂O₁₁, we need to follow the steps below:
Step 1: Calculate the molecular mass of C₁₂H₂₂O₁₁
Molecular mass of C₁₂H₂₂O₁₁ = (12 × 12.01) + (22 × 1.01) + (11 × 16) = 342.34 g/mol
Step 2: Determine the mass of carbon in C₁₂H₂₂O₁₁
The atomic mass of carbon is 12.01 g/mol.
Therefore, the mass of carbon in 1 mol of C₁₂H₂₂O₁₁ = (12 × 12.01) = 144.12 g/mol
Thus, the mass of carbon in 30.2 g of C₁₂H₂₂O₁₁= (30.2 × 144.12) / 342.34= 12.73 g
Step 3: Calculate the number of moles of carbon
Now, we know that the atomic mass of carbon is 12.01 g/mol.
Moles of carbon in 12.73 g = 12.73 / 12.01= 1.06
Step 4: Calculate the number of atoms of carbon1 mole of any element contains 6.022 × 10²³ atoms of that element.
So, the number of atoms of C in 1.06 moles= 1.06 × (6.022 × 10²³)= 6.39 × 10²³ atoms of C
Thus, there are 6.39 × 10²³ atoms of C in 30.2 grams of C₁₂H₂₂O₁₁.
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how many moles are there in 3.612 x 1024 particles of carbon ?
There are 6 moles in 3.612 x 10^24 particles of carbon, calculated using Avogadro's number. Avogadro's number relates the number of particles to the number of moles in a substance.
The number of moles in 3.612 x 10^24 particles of carbon can be calculated by dividing the given number of particles by Avogadro's number, which represents the number of particles in one mole of a substance.
Avogadro's number, denoted as NA, is approximately 6.022 x 10^23 particles/mol. This means that in one mole of any substance, there are 6.022 x 10^23 particles.
To calculate the number of moles from the given number of particles, we can use the following formula:
Number of moles = Number of particles / Avogadro's number
Substituting the given values into the formula:
Number of moles = 3.612 x 10^24 particles / (6.022 x 10^23 particles/mol)
Dividing the numbers:
Number of moles = 6 moles
Therefore, there are 6 moles in 3.612 x 10^24 particles of carbon.
In summary, there are 6 moles in 3.612 x 10^24 particles of carbon. This calculation is based on Avogadro's number, which relates the number of particles to the number of moles in a substance.
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The visible absorption spectrum for FD&C Blue 1 is shown in the following graph. The estimated concentration of the dye was 7.0 uM (7.0 x 106 M). 1. What would be an optimum wavelength for measuring the absorbance versus concentration of a series of Blue 1 dye concentrations? Explain your answer. Absorbance measurements are most accurate and FD&C sensitive in the range 0.2-1.0.
The optimum wavelength for measuring the absorbance versus concentration of a series of Blue 1 dye concentrations is 628nm. The absorbance measurements are most accurate and sensitive for FD&C in the range of 0.2-1.0. Hence the estimated concentration of the dye was 7.0 uM (7.0 x 106 M).
Visible absorption spectra provide information about a dye or a compound's electronic structure and can be used to determine the concentration of a compound. To determine the optimum wavelength for measuring the absorbance versus concentration of a series of Blue 1 dye concentrations, we can refer to the visible absorption spectrum for Blue 1 dye.
The graph provided in the question shows that the maximum absorbance for Blue 1 dye occurs at approximately 628 nm. This is also confirmed by the Beer-Lambert law, which states that the concentration of a solution is proportional to its absorbance. Therefore, the optimum wavelength for measuring the absorbance versus concentration of a series of Blue 1 dye concentrations is 628 nm.
The range of 0.2-1.0 is where the absorbance measurements are most accurate and FD&C sensitive. Therefore, the absorbance measurements for Blue 1 dye should be taken at this wavelength. Hence the estimated concentration of the dye was 7.0 uM (7.0 x 106 M).
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The particle(s) found inside the nucleus are called:
Red light has a wavelength of about 6.5 x 10-7m. Find its frequency. Show all work.
True or False. A force is a push or pull exerted on an object.
Answer:
True
Explanation:
Answer:
True
Explanation:
the answer is true because Google said it and if Google said it its true
How is energy related to the change of state represented
by the model?
O Atoms gain energy as a gas changes to a solid.
O Atoms gain energy as a gas changes to a liquid.
Atoms lose energy as a gas changes to a solid.
O Atoms lose energy as a gas changes to a liquid.
Answer:I’m not really sure but I think it might be D but please I’m sorry if I get it wrong
Explanation:
you and a coworker have developed a molecule that has shown potential as cobra antivenin . this antivenin works by binding to the venom , thereby rendering it nontoxic. this reaction can be described by the rate law: you have been given the following data from your coworker: a plot of versus gives a straight line with a slope of . what is the value of the rate constant for this reaction? rate constant
In order to calculate the value of the rate constant for this reaction, we need to consider the given information, which is:A plot of versus gives a straight line with a slope of
This information allows us to find the order of the reaction, which is 1, because the slope of a plot of concentration versus time is equal to the order of the reaction. After finding the order of the reaction, we can write the rate law for the reaction as follows: rate = k [A]¹ Where A represents the concentration of the reactant (venom) and 1 represents the order of the reaction. Since we have already found that the order of the reaction is 1, we can substitute this value into the rate law to get:
rate = k [A]
Now we have all the information we need to solve for the rate constant k, which is what the question is asking for. We are given data from the coworker, but there is no information provided about the actual values of concentration and rate for the reaction. Therefore, we cannot calculate the exact value of the rate constant. We can only determine the units of the rate constant, which would be M1s1, based on the order of the reaction being 1.
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21) The measurement 25.768. 000 m in sciontific notation?
Answer:
2.5768 * 107
Explanation:
Write it in a number between 1 and 9 and add decimal accordingly. So the answer is 2.5678 multiplied by 10 raised to power 7.
Explain, using the particle theory, why
(i) the solid, sodium chloride, has a fixed shape,
Answer: because the particles in a solid are more closer to each other than the liquid and gas particles. So the closeness if the particles give a particular shape for the substance.
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A sample of metal weighing 2.51 g is combined with oxygen; the metal oxide weighs 3.01 g. The mass percent of oxygen in the compounds is __
[A] 16.6%
[B] Cannot be determined from the given information
[C] 19.9%
[D] 83.4%
[E] 50.0%
The mass percent of oxygen in the compound is 16.6%. The correct option is [A] 16.6%
From the question,
We are to determine the mass percent of oxygen in the compound
The mass percent of oxygen in the compound can be calculated from
[tex]Mass\ percent\ of\ oxygen = \frac{Mass\ of\ oxygen\ in\ the\ compound}{Mass\ of\ the\ compound } \times 100\%[/tex]
First, we will determine the mass of oxygen in the compound
Mass of oxygen in the compound = Mass of the compound - Mass of the metal before it combined with oxygen
From the question
Mass of the compound = 3.01 g
Mass of the metal before it combined with oxygen = 2.51 g
∴ Mass of oxygen in the compound = 3.01g - 2.51g
Mass of oxygen in the compound = 0.5 g
Now,
For the mass percent of oxygen in the compound
[tex]Mass\ percent\ of\ oxygen = \frac{Mass\ of\ oxygen\ in\ the\ compound}{Mass\ of\ the\ compound } \times 100\%[/tex]
∴ [tex]Mass\ percent\ of\ oxygen = \frac{0.5}{3.01} \times 100\%[/tex]
[tex]Mass\ percent\ of\ oxygen = \frac{50}{3.01} \%[/tex]
Mass percent of oxygen = 16.611%
Mass percent of oxygen ≅ 16.6%
Hence, the mass percent of oxygen in the compound is 16.6%. The correct option is [A] 16.6%
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excess electrons are placed on a small lead sphere with mass so that its net charge is (a) find the number of excess electrons on the sphere. (b) how many excess electrons are there per lead atom? the atomic number of lead is 82, and its atomic mass is
To solve this problem, we need to use the concept of elementary charge and Avogadro's number.
(a) To find the number of excess electrons on the sphere, we need to determine the net charge of the sphere.
Given:
Atomic number of lead (Z) = 82
Atomic mass of lead (M) = unknown
To calculate the mass of the lead sphere, we need to know the atomic mass of lead. However, it is not provided in the question. Could you please provide the atomic mass of lead?
(b) Once we have the atomic mass of lead, we can calculate the number of excess electrons per lead atom using the equation:
Number of excess electrons per lead atom = (Net charge of the sphere) / (Charge of one electron)
The charge of one electron is equal to the elementary charge (e), which is approximately 1.602 × 10^(-19) coulombs.
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A sample of neon gas initially at 20°C and 1.0 atm is expanded from 1.2L to 2.6L nad simulatneously heat to 40°C. Calculate ΔS for this change of state. (The neon can be treated as an ideal gas).
The change in entropy (ΔS) for the expansion and heating of neon gas is 0.514 J/K.
What is the entropy change?To calculate the change in entropy (ΔS) for the expansion and heating of neon gas, we can use the ideal gas equation and the formula for entropy change:
ΔS = nR ln(Vf/Vi) + nCv ln(T_f/Ti)
Where:
ΔS is the change in entropyn is the number of moles of gasR is the ideal gas constant (8.314 J/(mol·K))Vf and Vi are the final and initial volumes, respectivelyT_f and Ti are the final and initial temperatures, respectivelyCv is the molar heat capacity at constant volumeThe number of moles of neon gas (n) is calculated using the ideal gas equation:
n = PV / RT
Given:
P = 1.0 atm
Vf = 2.6 L
Vi = 1.2 L
T_f = 40°C = 40 + 273.15 K = 313.15 K
Ti = 20°C = 20 + 273.15 K = 293.15 K
R = 8.314 J/(mol·K)
n = (P × Vf) / (R × T_f)
n = (1.0 atm × 2.6 L) / (8.314 J/(mol·K) × 313.15 K)
n ≈ 0.1049 mol
The molar heat capacity at constant volume (Cv) for neon gas. The molar heat capacity of an ideal monatomic gas at constant volume is given as 3/2 R.
Cv = 3/2 R
Cv = (3/2) × 8.314 J/(mol·K)
Cv = 12.471 J/(mol·K)
Solving for entropy change:
ΔS = nR ln(Vf/Vi) + nCv ln(T_f/Ti)
ΔS = (0.1049 mol) × (8.314 J/(mol·K)) × ln(2.6 L / 1.2 L) + (0.1049 mol) × (12.471 J/(mol·K)) × ln(313.15 K / 293.15 K)
ΔS ≈ 0.219 J/K + 0.295 J/K
ΔS ≈ 0.514 J/K
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1. when enzyme a was run with 40 um substrate, the initial rate (vo) was 10 um/min, and when it was run with 4 mm substrate, the vo was 20 um/min. estimate the approximate vmax and km of enzyme a.
When enzyme a was run with 40 μM substrate, the initial rate ([tex]v_{0}[/tex]) was 10 μM/min, and when it was run with 4 mM substrate, the [tex]v_{0}[/tex] was 20 μM/min. The approximate ([tex]V_{max}[/tex] is 20 μM/min, and the approximate [tex]K_{m}[/tex] is 40.8 μM.
To estimate the approximate [tex]V_{max}[/tex] and [tex]K_{m}[/tex] of enzyme A, we can use the Michaelis-Menten equation, which describes the relationship between the initial reaction rate ([tex]v_{0}[/tex]), the maximum reaction rate ([tex]V_{max}[/tex] ), and the substrate concentration (S):
[tex]v_{0}[/tex] = ([tex]V_{max}[/tex] * S) / ([tex]K_{m}[/tex] + S)
For 40 μM substrate:
[tex]v_{0}[/tex] = 10 μM/min
S = 40 μM
For 4 mM substrate:
[tex]v_{0}[/tex] = 20 μM/min
S = 4 mM = 4000 μM
Using the Michaelis-Menten equation:
[tex]v_{0}[/tex] = ([tex]V_{max}[/tex]* S) / ([tex]K_{m}[/tex] + S)
Let's set up the equations using the given data points:
10 = ([tex]V_{max}[/tex] * 40) / ([tex]K_{m}[/tex] + 40)
20 = ([tex]V_{max}[/tex] * 4000) / ([tex]K_{m}[/tex] + 4000)
We can simplify these equations and solve them simultaneously:
Equation 1: 10([tex]K_{m}[/tex] + 40) = 40[tex]V_{max}[/tex]
Equation 2: 20([tex]K_{m}[/tex] + 4000) = 4000[tex]V_{max}[/tex]
Divide Equation 2 by Equation 1:
2([tex]K_{m}[/tex] + 4000) / ([tex]K_{m}[/tex] + 40) = 100
Expanding and simplifying:
2[tex]K_{m}[/tex] + 8000 = 100[tex]K_{m}[/tex] + 4000
98[tex]K_{m}[/tex] = 4000 - 8000
98[tex]K_{m}[/tex] = -4000
[tex]K_{m}[/tex] = -4000 / 98
[tex]K_{m}[/tex] ≈ 40.8 μM (Approximate [tex]K_{m}[/tex] value)
Substituting the value of [tex]K_{m}[/tex] into Equation 1:
10 = ([tex]V_{max}[/tex] * 40) / (40.8 + 40)
10 = ([tex]V_{max}[/tex] * 40) / 80.8
[tex]V_{max}[/tex] = (10 * 80.8) / 40
[tex]V_{max}[/tex] ≈ 20 μM/min (Approximate [tex]V_{max}[/tex] value)
Therefore, the approximate ([tex]V_{max}[/tex] is 20 μM/min, and the approximate [tex]K_{m}[/tex] is 40.8 μM.
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Please help with this chemistry question, please included step by step of how to do it. Thank you!
Answer:
The chemical equation for photosynthesis is:
6CO2 + 6H2O → C6H12O6 + 6O2
This equation shows that for every 6 moles of CO2 (carbon dioxide) and 6 moles of H2O (water) that are used in photosynthesis, one mole of C6H12O6 (glucose/sugar) and 6 moles of O2 (oxygen) are produced.
The molar mass of water (H2O) is 18.015 g/mol. Therefore, 100.5 g of water is equal to:
100.5 g / 18.015 g/mol ≈ 5.58 moles of water
Since the ratio of water to glucose in the equation is 6:1, we can calculate the number of moles of glucose produced as:
5.58 moles of water / 6 = 0.93 moles of glucose
The molar mass of glucose (C6H12O6) is 180.156 g/mol. Therefore, the mass of glucose produced is:
0.93 moles of glucose x 180.156 g/mol = 167.5 g of glucose
Therefore, if a plant absorbs 100.5 g of water, it will produce approximately 167.5 g of sugar through photosynthesis, assuming it has plenty of carbon dioxide available.
a bottle is filled with a small amount of a volatile liquid and sealed. sometime later it is observed that no liquid is evident in the sealed bottle. which of the following statements would explain this observation? a bottle is filled with a small amount of a volatile liquid and sealed. sometime later it is observed that no liquid is evident in the sealed bottle. which of the following statements would explain this observation? the liquid has undergone sublimation. the vapor state is favored when equilibrium is established. liquid and vapor are at equilibrium in the bottle. more time is needed to establish equilibrium. too little liquid was added to achieve a liquid vapor equilibrium in the closed system.
A bottle is filled with a small amount of a volatile liquid and sealed. Sometime later, it is observed that no liquid is evident in the sealed bottle. The following statement would explain this observation: "Liquid and vapor are at equilibrium in the bottle."
This observation could be explained by stating that liquid and vapor are at equilibrium in the bottle. It means that there is a dynamic equilibrium between the liquid and vapor phases of the substance in the closed system. When the amount of vapor in the bottle is equal to the amount of liquid that has evaporated from the bottle, the system reaches an equilibrium state.
Therefore, the vapor state is favored when equilibrium is established. The liquid has not undergone sublimation. Also, more time is not needed to establish equilibrium. Furthermore, too little liquid was not added to achieve liquid-vapor equilibrium in the closed system. Hence, the statement "Liquid and vapor are at equilibrium in the bottle" explains the observation that no liquid is evident in the sealed bottle.
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why is the peridic table called 'the pedirotic table of elements" and not "the periodic table of compounds"?
a. it would not matter id thry called the pedioric table of compounds since the word element and compound mean the same thing.
b.because the pedioric table lists all known pure subtances in the universe
c. becasue the pedirotic tab;e was created before compounds wqhere understoog
Answer:
B
Explanation:
a 15.5 ml sample of 0.215m koh solution required 21.2 ml of aqueous acetic acid (hc2h3o2) in a titration experiment. what is the molarity of the acetic acid?
the molarity of the acetic acid solution is 0.1571 M.
To determine the molarity of the acetic acid (HC2H3O2) solution, we can use the concept of stoichiometry and the volume and concentration data provided.
Given:
Volume of KOH solution = 15.5 ml
Molarity of KOH solution = 0.215 M
Volume of acetic acid solution = 21.2 ml
In a balanced chemical equation between KOH and acetic acid, the stoichiometric ratio is 1:1. This means that 1 mole of KOH reacts with 1 mole of acetic acid.
Using the equation:
KOH(aq) + HC2H3O2(aq) -> H2O(l) + KC2H3O2(aq)
The moles of KOH can be calculated using the formula:
Moles = Volume (in liters) x Molarity
Moles of KOH = (15.5 ml / 1000) L x 0.215 M
= 0.0033325 moles
Since the stoichiometric ratio is 1:1, the moles of acetic acid are also 0.0033325 moles.
The molarity of acetic acid can be calculated using the formula:
Molarity = Moles / Volume (in liters)
Molarity of acetic acid = 0.0033325 moles / (21.2 ml / 1000) L
= 0.1571 M
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in general, how do single-displacement reactions compare with synthesis and decomposition reactions in terms of the amount of energy involved?
In general, single-displacement reactions are more reactive compared to synthesis and decomposition reactions. In terms of energy involved, single-displacement reactions require the least amount of energy to take place.
The energy that is involved in chemical reactions is the energy required to break the bonds of the reactants as well as the energy that is released when the new bonds form during the creation of the products. In synthesis and decomposition reactions, more energy is required compared to single-displacement reactions.
Synthesis reactions combine two or more reactants to form a single product. This process requires energy to break the bonds in the reactants and additional energy to create the bonds between the new atoms in the product. In contrast, decomposition reactions involve breaking down a single compound into two or more simpler products. This process requires energy to break the bonds within the compound, which is generally more energy than is required in a single-displacement reaction.
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how does iodine help in promoting thyroid health
Answer:
Iodine is a mineral found in some foods. The body must have iodine to make thyroid hormones. The hormones control the body's metabolism and many other important functions. Without iodine, thyroid hormone production can decrease.
Explanation:
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im looking for someone o fill in the spots that are above module 5 dont do module 5 just do whats above thank you
Ans 1. Both
Ans 2. Once inside plants, carbon moves through food chains, where organisms become nutrients including herbivores, carnivores and ultimately, decomposers. Once buried in the soil, carbon can be converted into fossil fuels over long periods of time and then also reenter the atmosphere by combustion. The Law of Conservation of Matter states that matter cannot be created or destroyed. The carbon cycle is an example of the Law
Ans 3. Most of the chemical energy needed for life is stored in organic compounds as bonds between carbon atoms and other atoms. The law of conservation of energy states that energy can not be created or destroyed. Thus, just like matter energy is also conserved in the process.
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Thermal energy in the inner and outer core is heat that is from the original formation of Earth. Thermal energy is
transferred from the outer core towards the crust through the mantle. Which BEST describes how energy moves
through the mantle?
A
Thermal energy radiates from the outer core, through the mantle, to the crust.
B
Thermal energy moves by conduction from the outer core, through the mantle, and to the
crust by direct contact.
Thermal energy rises with heated magma from near the core and sinks back down as it cools
through convection.
D
Thermalbyergy heats up the magma by radiation and passes through the mantle as
conduction
Answer:it’s b they transfer thermal energy away from earths core towards its crust
Explanation:
Good luck!
Thermal energy moves from the outer core, through the mantle, and to the crust by conduction.
Heat transferred from the core through the mantle and to the crust in the process of conduction. The lower mantle is heated directly by conduction from the core. In conduction, heat is transferred from one particles to another.
In the process of conduction, heat flows from warmer objects to cooler objects so the outer core has high amount of heat energy which is transferred to the surrounding mantle layer due to its lower temperature so we can conclude that thermal energy moves from the outer core, through the mantle and to the crust by conduction.
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