Which 3 pairs of side lengths are possible measurements for the triangle?

Which 3 Pairs Of Side Lengths Are Possible Measurements For The Triangle?

Answers

Answer 1

SOLUTION

From the right triangle with two interior angles of 45 degrees, the two legs are equal in length, that is AB = BC

And from Pythagoras, the square of the hypotenuse (AC) is equal to the square of the other two legs or sides (AB and AC)

So this means

[tex]\begin{gathered} |AC|^2=|AB|^2+|BC|^2 \\ since\text{ AB = BC} \\ |AC|^2=2|AB|^2,\text{ also } \\ |AC|^2=2|BC|^2 \end{gathered}[/tex]

So from the first option

[tex]\begin{gathered} BC=10,AC=10\sqrt{2} \\ |AC|^2=(10\sqrt{2})^2=100\times2=200 \\ 2|BC|^2=2\times10^2=2\times100=200 \end{gathered}[/tex]

Hence the 1st option is correct, so its possible

The second option

[tex]\begin{gathered} AB=9,AC=18 \\ |AC|^2=18^2=324 \\ 2|AB|^2=2\times9^2=2\times81=162 \\ 324\ne162 \end{gathered}[/tex]

Hence the 2nd option is wrong, hence not possible

The 3rd option

[tex]\begin{gathered} BC=10\sqrt{3},AC=20 \\ |AC|^2=20^2=400 \\ 2|BC|^2=2\times(10\sqrt{3})^2=2\times100\times3=600 \\ 400\ne600 \end{gathered}[/tex]

Hence the 3rd option is wrong, not possible

The 4th option

[tex]\begin{gathered} AB=9\sqrt{2},AC=18 \\ |AC|^2=18^2=324 \\ 2|AB|^2=2\times(9\sqrt{2})^2=2\times81\times2=324 \\ 324=324 \end{gathered}[/tex]

Hence the 4th option is correct, it is possible

The 5th option

AB = BC

This is correct, and its possible

The last option

[tex]\begin{gathered} AB=7,BC=7\sqrt{3} \\ 7\ne7\sqrt{3} \end{gathered}[/tex]

This is wrong and not possible because AB should be equal to BC

Hence the correct options are the options bolded, which are

1st, 4th and 5th


Related Questions

Solve the inequality and how do i graph ?

Answers

The most appropriate choice for linear inequation will be given by-

[tex]m > \frac{1}{2}[/tex] is the correct solution

What is linear inequation?

At first it is important to know about algebraic expressions.

Algebraic expressions consists of variables and numbers connected with addition, subtraction, multiplication and division.

Inequation shows the comparision between two algebraic expressions by connecting the two algebraic expressions by > , < , [tex]\geq, \leq[/tex]

A one degree inequation is known as linear inequation.

Here,

The given inequation is [tex]\frac{1}{2} - \frac{m}{4} < \frac{3}{8}[/tex]

Now,

[tex]\frac{1}{2} - \frac{m}{4} < \frac{3}{8}\\\\\frac{m}{4} > \frac{1}{2} - \frac{3}{8}\\\\\frac{m}{4} > \frac{4 - 3}{8}\\\\\frac{m}{4} > \frac{1}{8}\\\\m > \frac{1}{8} \times 4\\m > \frac{1}{2}[/tex]

The number line has been attached here.

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Use the Distributive Property to solve the equation 2/3 (9a + 6) = 23.8

Answers

Distributive property tell us how to solve expressions in the form a(b+c), it says:

a(b+c)=ab+ac

Then,

[tex]\begin{gathered} \frac{2}{3}(9a+6)=23.8 \\ \frac{18a}{3}+\frac{12}{3}=23.8 \\ 6a+4=23.8 \\ 6a=23.8-4 \\ a=\frac{19.8}{6}=3.3 \end{gathered}[/tex]

Hey I need help with my homework help me find the points on the graph too please Thankyouu

Answers

Given the function:

g(x) = 3^x + 1

we are asked to plot the graph of the function.

Using the table:

x y

-2 10/9

-1 4/3

0 2

1 4

2 10

The graph:

The expomential functions have a horizontal asymptote.

The equation of the horizontal asymptote is y = 1

Horizontal Asymptote: y = 1

To find the domain is finding where the question is defined.

The range is the set of values that correspond with the domain.

Domain: (-infinity, infinity), {x|x E R}

Range: (1, infinity0, {y|y > 1}.

The endpoints of diameter in a circle form an angle with point C. What is the measure of angle BCD?

Answers

Answer:

90 degrees

Explanation:

Please note that whenever a triangle is inscribed in a circle and one side of the triangle is a diameter of the circle as in the given figure, then the angle that is opposite the diameter of the circle is a right angle;

[tex]\therefore\angle BCD=90^{\circ}[/tex]

Simplify the given expression into the form a+bi, where a and b are rational numbers?

Answers

Given:

2(-36- 3i )+ (5+2i)(12-2i)

Open the parenthesis

2(-36- 3i) + 5( 12 - 2i) + 2i ( 12 - 2i)

- 72 - 6i + 60 - 10i + 24i + 4 ( Note: i² = -1)

Re-arrange

-72+60 + 4 - 6i - 10i + 24i

= -8 + 8i

Mr. Ellis has started a vegetable garden. He bought 15 bags of soil and 3 bags offertilizer for $282.72. He realized he didn't have enough supplies, so he boughtanother 5 bags of soil and 2 bags of fertilizer for $107.23. What was the cost of eachbag of soil and fertilizer? Let the cost of each bag of soil = x and the cost of eachbag of fertilizer = y. A. Each bag of soil was $12.99, and each bag of fertilizer was $16.25.B. Each bag of fertilizer was $9.75, and each bag of soil was $77.99.C. Each bag of soil was $9.75, and each bag of fertilizer was $77.99.D. Each bag of fertilizer was $12.99, and each bag of soil was $16.25.

Answers

The variables are:

x: cost of each bag of soil

y: cost of each bag of fertilizer

He bought 15 bags of soil and 3 bags of fertilizer for $282.72, that is,

15x + 3y = 282.72 (eq. 1)

He bought another 5 bags of soil and 2 bags of fertilizer for $107.23, that is,

5x + 2y = 107.23 (eq. 2)

Multiplying equation 2 by 3, we get:

3(5x + 2y) = 3(107.23)

3(5x) + 3(2y) = 3(107.23)

15x + 6y = 321.69 (eq. 3)

Subtracting equation 3 to equation 1, we get:

15x + 3y = 282.72

-

15x + 6y = 321.69

-------------------------------

-3y = -38.97

y = -38.97/-3

y = 12.99

Replacing this result into the first equation,

15x + 3(12.99) = 282.72

15x + 38.97 = 282.72

15x = 282.72 - 38.97

15x = 243.75

x = 243.75/15

x = 16.25

D. Each bag of fertilizer was $12.99, and each bag of soil was $16.25.

quick!! will give brainliest!! Given g(x) = -x + 3, solve for a when g(2) = -1

Answers

We have the following:

[tex]g(x)=-x+3[/tex]

replacing when x is 2:

[tex]g(2)=-2+3=1[/tex]

What is the probability that a randomly selected oar was purchased in the 2010s given that the oar was made from ash wood?Simplify any fractions

Answers

P (A) = probability of a car purchased in 2010's

P (B) = probability of the car being made from ash wood

P (A and B) = 4

P (B) = 4 +3 = 7

Conditional probability:

P (B/A) = P (A and B ) / P (B) = 4 / 7 = 0.5714

Leah invested $400 in an account paying an interest rate of 1 1/2%compounded annually. Lauren invested $400 in an account paying aninterest rate of 0 7/8% compounded monthly. To the nearest hundredth of ayear, how much longer would it take for Lauren's money to triple than forLeah's money to triple?

Answers

Leah investment is:

[tex]M_{\text{Leah}}=400_{}\cdot1.5^y[/tex]

Where M is the ammount of money that she has, and y the number of years.

We want to know the number of years that must elapse for her investment to triple, so we want to know the value of y such that:

[tex]\begin{gathered} 3\cdot400=400\cdot(1+\frac{1.5}{100})^y \\ 3=(1.015)^y \\ \ln 3=y\cdot\ln (1.015) \\ y=\frac{\ln (3)}{\ln (1.015)}\cong73.788\cong73.79 \end{gathered}[/tex]

It will take 73.79 years to triple her investment.

Lauren investment is:

[tex]M_{\text{Lauren}}=400\cdot(1+\frac{7}{8}\cdot\frac{1}{100})^m=400\cdot(1.00875)^{\frac{y}{12}}[/tex]

Where M is the ammount of money that she has, and m the number of months, and y is the number of years.

We want to know the number of years that must elapse for her investment to triple, so we want to know the value of y such that:

[tex]\begin{gathered} 3\cdot400=400\cdot(1.00875)^{\frac{y}{12}} \\ 3=(1.00875)^{\frac{y}{12}} \\ \ln 3=\frac{y}{12}\ln (1.00875) \\ y=12\cdot\frac{\ln 3}{\ln (1.00875)} \\ y=1513.25 \end{gathered}[/tex]

need help assap look at file attached

Answers

Answer:

length is 27, width is 9

Step-by-step explanation:

72/4= 18

2x27+ 2x9 = 54 + 18 = 72

A store charges $140 for every 10 bags of fertilizer a farmer buys. a. Complete the table. Graph the values. 30 40 Fertilizer (bags) 10 Cost ($) 140 280 840 b. How much would a farmer pay for 50 bags of fertilizer? Explain. a. Complete the table. 30 40 Fertilizer (bags) 10 Cost ($) 140 280 840

Answers

Question:

Solution

a) If for every 10 bags the store charges $140 then

1. for 10x2 = 20 bags the store charges 2x$140 = 280.

2. for 10x3 = 30 bags the store charges 3x$140 = 420.

3. for 10x4 = 40 bags the store charges 4x$140 = 560

4. for 10x6 = 60 bags the store charges 6x$140 = 840

b) According to the previous item, we can conclude that for 10x5 = 50 bags the store charges 5x$140 = 700 then, the farmer must pay $700 for 50 bags.

c)

According to the previous item, we can conclude that for 10x5 = 50 bags the store charges 5x$140 = 700 then, the farmer must pay $700 for 50 bags.

Sally Sue had spent all day preparing for the prom. All the glitz and the glamour of the evening fell apart as she stepped out of the limousine and her heel broke and she fell to the ground. Within minutes, news of her crashing fall had spread to the 550 people already at the prom. The function, p(t) = 550(1-e^-0.039t) where t represents the number of minutes after the fall, models the number of people who were already at the prom who heard the news.How many minutes does it take before all 550 people already at the prom hear the news ofthe great fall? Show your work.

Answers

We have the function

[tex]p(t)=550(1-e^{-0.039t})[/tex]

Therefore we want to determine when we have

[tex]p(t_0)=550[/tex]

It means that the term

[tex]e^{-0.039t}[/tex]

Must go to zero, then let's forget the rest of the function for a sec and focus only on this term

[tex]e^{-0.039t}\rightarrow0[/tex]

But for which value of t? When we have a decreasing exponential, it's interesting to input values that are multiples of the exponential coefficient, if we have 0.039 in the exponential, let's define that

[tex]\alpha=\frac{1}{0.039}[/tex]

The inverse of the number, but why do that? look what happens when we do t = α

[tex]e^{-0.039t}\Rightarrow e^{-0.039\alpha}\Rightarrow e^{-1}=\frac{1}{e}[/tex]

And when t = 2α

[tex]e^{-0.039t}\Rightarrow e^{-0.039\cdot2\alpha}\Rightarrow e^{-2}=\frac{1}{e^2}[/tex]

We can write it in terms of e only.

And we can find for which value of α we have a small value that satisfies

[tex]e^{-0.039t}\approx0[/tex]

Only using powers of e

Let's write some inverse powers of e:

[tex]\begin{gathered} \frac{1}{e}=0.368 \\ \\ \frac{1}{e^2}=0.135 \\ \\ \frac{1}{e^3}=0.05 \\ \\ \frac{1}{e^4}=0.02 \\ \\ \frac{1}{e^5}=0.006 \end{gathered}[/tex]

See that at t = 5α we have a small value already, then if we input p(5α) we can get

[tex]\begin{gathered} p(5\alpha)=550(1-e^{-0.039\cdot5\alpha}) \\ \\ p(5\alpha)=550(1-0.006) \\ \\ p(5\alpha)=550(1-0.006) \\ \\ p(5\alpha)=550\cdot0.994 \\ \\ p(5\alpha)\approx547 \end{gathered}[/tex]

That's already very close to 550, if we want a better approximation we can use t = 8α, which will result in 549.81, which is basically 550.

Therefore, we can use t = 5α and say that 3 people are not important for our case, and say that it's basically 550, or use t = 8α and get a very close value.

In both cases, the decimal answers would be

[tex]\begin{gathered} 5\alpha=\frac{5}{0.039}=128.2\text{ minutes (good approx)} \\ \\ 8\alpha=\frac{8}{0.039}=205.13\text{ minutes (even better approx)} \end{gathered}[/tex]

a rectangular prisim has a volume of 80cm cubed it has a length of 2cm and a width of 5cm. What is the prisms height?

Answers

rectangular prism volume is ,

[tex]\begin{gathered} V=l\times b\times h \\ 80=2\times5\times h \\ h=\frac{80}{10} \\ h=8\text{ cm } \end{gathered}[/tex]

Question60 is 40% of what number?

Answers

let the required number be x then

[tex]\begin{gathered} \frac{60}{x}\times100=40 \\ x=\frac{60}{40}\times100 \\ x=150 \end{gathered}[/tex]

So 60 is 40% of 150.

If a2 -2ab + b2 = 9 and a

Answers

If a2 -2ab + b2 = 9 and a[tex]\begin{gathered} a^2-2ab+b^2=9 \\ a

Step 1

factorize

[tex]\begin{gathered} a^2-2ab+b^2=(a-b)^2 \\ \end{gathered}[/tex]

then

[tex]\begin{gathered} (a-b)^2=9 \\ \sqrt{(a-b)^2}=\sqrt{9} \\ a-b=\pm3 \\ \\ aa-b=-3

Use the strategy to simplify 4/576Write the prime factorization of the radicand.442834O42/2832O 4./283²O4. 2882

Answers

To simplify the fraction we will need to facto

There's a roughly linear relationship between the number of times a species of cricketwill chirp in one minute and the temperature outside. For a certain type of cricket,this relationship can be expressed using the formula I = 0.3lc + 36, where Trepresents the temperature in degrees Fahrenheit and c represents the number oftimes the cricket chirps in one minute. What is the meaning of the I'-value whenc= 148?

Answers

The function T = T(c) tells us the temperature based on the number of times c the cricket has chirped in one minute. In other words, if we plug c = 148 in the formula we get:

[tex]\begin{gathered} T(c)=0.31c+36 \\ T(148)=0.31\times(148)+36 \\ T(148)=81.88^oF \end{gathered}[/tex]

That means if the cricket chirps 148 times per minute, the temperature must be 81.88 ºF.

Answer: The expected temperature in degrees Farenheit if the cricket has chirped 148 times perminute.

Kathryn needs to include a scale drawing of a race car on her science science fair project. Her actual race car is 180 inches long and 72 inches tall. if she uses a scale factor of 1 inch= 8 inches, what will the dimensions of her scale drawing?

Answers

To find the scaled measures of the race car, you have to divide the original measures by the scale. This is:

[tex]\text{length}=\frac{182in}{8}=22.75in[/tex][tex]\text{height}=\frac{72in}{8}=9in[/tex]

So the scaled measures of the race car are: length=22.75in and height=9in

five hundred twelve thousandths decimal form

Answers

The first step to answer this question is to write the fraction for the given sentences.

Five hundred twelve thousandths is:

[tex]\frac{512}{1000}[/tex]

To write it as a decimal, solve the quotient:

[tex]\frac{512}{1000}=0.512[/tex]

The answer is 0.512.

A firm incurs $70,000 in interest expenses each year. If the tax rate of the firm is 30%, what is the effective after-tax interest rate expense for the firm?

Answers

Answer:

After tax interest expenses = Interest expenses x (100 - Tax Rate) 

= 70000 x (100 - 30)% 

= 70000 x 70% 

= $49,000.00

Step-by-step explanation:

How to find the area of a regular hexagon with a radius of 12 inches? Please help

Answers

[tex]\begin{gathered} In\text{ this case, as a regular hexagon} \\ \text{radius = side} \\ Area\text{ =}3\cdot\frac{\sqrt[]{3}side^2}{2} \\ \text{side}=12in \\ side^2=144in^2 \\ Area\text{ =}3\cdot\frac{\sqrt[]{3}\cdot(144in^2)}{2} \\ \\ \text{Area}=374.1in^2 \\ \text{The regular hexagon's area is }374.1in^2 \end{gathered}[/tex]

Which equation has at least one solution? Mark all that app A. 2x-1= 2 B. 3 y + 1) = 3y 1 C. 5p - (3 + p) = 6p + 1 D. 4/5m=1-1/5m E. 10 +0.5w =1/2w - 10 F. 4a + 3(a - 2) = 8a - (6 + a) Answer Choices:

Answers

Let's check the options

A.

2x - 1 = 2

2x= 3

x= 3/2=1.5

option A has atleast one solution

B

3y+ 1 = 3y

option B has no solution

C.

5p - (3 + p) = 6p + 1

5p - 3 - p = 6p + 1

4p - 6p = 1 + 3

-2p = 4

p =-2

option C has atleast one solution

D.

4/5 m = 1- 1/5 m

4/5 m + 1/5m = 1

1m = 1

m = 1

Option D has atleast one solution

E.

10 + 0.5w = 1/2w - 10

0.5 w - 1/2 w = -10 - 10

option E has no solution

F.

4a + 3(a-2) = 8a - (6+a)

4a +3a - 6 = 8a -6 - a

7a -6 = 7a - 6

option F has many solution. Hence it also has atleast one solution

Therefore;

option A, C, D and F has atleast one solution

Kaylee drove 160 miles in 5 hours. If she continued at the same rate, how far would she travel in 17 hours?

Answers

The distance covered by Kaylee in 17 hours at the same rate is 544 miles.

According to the question,

We have the following information:

Distance covered by Kaylee = 160 miles

Time taken by Kaylee = 5 hours

We know that the following formula is used to find the speed:

Speed = distance/time

Speed = 160/5 mile/hour

Speed = 32 miles/hour

Now, we have to find the distance when time taken is 17 hours and the speed is the same.

Now, from the formula of speed, we can find the distance:

Distance = speed*time

Distance = 32*17

Distance = 544 miles

Hence, the distance covered by Kaylee in 17 hours is 544 miles.

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Evaluate f(2) and f(2.1) and use the results to approximate f '(2). (Round your answer to one decimal place.)f(x) = x(9 − x)f '(2) ≈

Answers

Given a function f(x) = x(9 - x).

We need to find the value of f(2) and f(2.1) and use them to approximate the value of f'(2).

The value of f(2) is calculated below:

[tex]\begin{gathered} f(2)=2(9-2) \\ =2(7) \\ =14 \end{gathered}[/tex]

The value of the f(2.1) is calculated as follows:

[tex]\begin{gathered} f(2.1)=2.1(9-2.1) \\ =2.1(6.9) \\ =14.49 \end{gathered}[/tex]

Now, by the definition of f'(x), we know that

[tex]f^{\prime}(x)=\frac{f(x+\Delta x)-f(x)}{(x+\Delta x)-x}=\frac{f(x+\Delta x)-f(x)}{\Delta x}[/tex]

For the given condition, x = 2, and delta x = 0.1. So, the value of f'(2) is

[tex]\begin{gathered} f^{\prime}(2)=\frac{f(2+0.1)-f(2)}{0.1} \\ =\frac{f(2.1)-f(2)}{0.1} \\ =\frac{14.49-14}{0.1} \\ =\frac{0.49}{0.1} \\ =4.9 \end{gathered}[/tex]

Thus, the approximate value of f'(2) is 4.9.

question 18:Evaluate: summation from n equals 2 to 8 of 12 times 4 tenths to the n plus 1 power period Round to the nearest hundredth. (1 point)

Answers

Given:

[tex]\sum_{n\mathop{=}2}^812(0.4)^{n+1}[/tex]

Required:

Sum of the numbers

Explanation:

Let

[tex]A_n=\sum_{n\mathop{=}2}^812(0.4)^{n+1}[/tex]

when n = 2, Aₙ becomes

[tex]A_2=12(0.4)^{2+1}=12\times(0.4)^3=0.768[/tex]

when n = 3, Aₙ becomes

[tex]A_3=12(0.4)^{3+1}=12\times(0.4)^4=0.3072[/tex]

when n = 4, Aₙ becomes

[tex]A_4=12(0.4)^{4+1}=12\times0.4^5=0.12288[/tex]

when n = 5, Aₙ becomes

[tex]A_5=12(0.4)^{5+1}=12\times0.4^6=0.049152[/tex]

when n = 6, Aₙ becomes

[tex]A_6=12(0.4)^{6+1}=12\times0.4^7=0.0196608[/tex]

when n = 7, Aₙ becomes

[tex]A_7=12(0.4)^{7+1}=12\times0.4^8=0.007866432[/tex]

when n = 8, Aₙ becomes

[tex]A_8=12(0.4)^{8+1}=12\times0.4^9=0.003145728[/tex]

So now,

[tex]\begin{gathered} A=A_1+A_2+A_3+A_4+A_5+A_6+A_7+A_8 \\ \\ A=0.768+0.3072+0.12288+0.049152+0.0196608+0.00786432+0.003145728 \\ \\ A=1.277902848\approx1.28 \end{gathered}[/tex]

Final answer:

The

Use the graph to answer the question.Which statement matches the vector operation shown on the coordinate grid?

Answers

We have the correct statement about the vectors in the graph.

We can already see that it is a sum of vectors like:

[tex]v+w=u[/tex]

As v has starting point at (-1,0) and ending point at (3,3), we can describe the vector as:

[tex]v=(3-(-1))\hat{i}+(3-0)\hat{j}=4\hat{i}+3\hat{j}[/tex]

As w starts at (3, 3) and ends on (5, 2), we can describe it as:w

[tex]w=(5-3)\hat{i}+(2-3)\hat{j}=2\hat{i}-1\hat{j}[/tex]

Finally, u starts at (-1,0) and ends at (5,2), so it can be described as:

[tex]u=(5-(-1))\hat{i}+(2-0)\hat{j}=6\hat{i}+2\hat{j}[/tex]

Answer: v + w = u for v = 4i + 3j, u = 2i - j and u = 6i + 2j [Option C].

As a test engineer, you are in charge of maintaining an experimental aircraft . According to the maintence manual, you need to inspect a wing every 10 flight hours. The aircraft flown 3 flights, each lasting 2.75 hours Since the last inspection. How many hours do you need before the wing should be inspected?

Answers

EXPLANATION

Let's see the facts:

Inspect period = 10 flight hours

Flown= 3 flights/2.75 hours

Total flights hours = 3x2.75 = 8.25 hours

The difference is 10-8.25 = 1.75 hours.

We need 1.75 hours more before the next wing inspection.

I have a question so yall can get points so Whats 1+1

Answers

answer needs at least 20 characters so here's ur answer 2

Step-by-step explanation:

thank u

Answer: 2

1 + 1 = 2

lol thanks for the points

help meeeeeeeeee pleaseee !!!!!

Answers

The simplified answer of the composite function is as follows:

(f + g)(x) = 2x + 3x²(f - g)(x) = 2x - 3x²(f. g)(x)  = 6x³(f / g)(x) = 2 / 3x

How to solve composite function?

Composite functions is a function that depends on another function.  A composite function is created when one function is substituted into another function.

In other words, a composite function is generally a function that is written inside another function.

Therefore,

f(x) = 2x

g(x) = 3x²

Hence, the composite function can be simplified as follows:

(f + g)(x) = f(x) + g(x)  = 2x + 3x²

(f - g)(x) = f(x) - g(x)  = 2x - 3x²

(f. g)(x) = f(x) . g(x) = (2x)(3x²) = 6x³

(f / g)(x) = f(x) / g(x) = 2x / 3x² = 2 / 3x

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Use the remainder theorem to find P(-2) for P(x) = x³ + 3x² +9,Specifically, give the quotient and the remainder for the associated division and the value of P(-2).QuotientRemainder =P(-2)=

Answers

Answer:

Quotient:

[tex]x^2+x-2[/tex]

Remainder:

[tex]13[/tex]

P(-2):

[tex]13[/tex]

Step-by-step explanation:

Remember that the remainder theorem states that the remainder when a polynomial p(x) is divided by (x - a) is p(a).

To calculate the quotient, we'll do the synthetic division as following:

Step one:

Write down the first coefficient without changes

Step two:

Multiply the entry in the left part of the table by the last entry in the result row (under the horizontal line).

Add the obtained result to the next coefficient of the dividend, and write down the sum.

Step 3:

Multiply the entry in the left part of the table by the last entry in the result row (under the horizontal line).

Add the obtained result to the next coefficient of the dividend, and write down the sum.

Step 4:

Multiply the entry in the left part of the table by the last entry in the result row (under the horizontal line).

Add the obtained result to the next coefficient of the dividend, and write down the sum.

Now, we will have completed the division and have obtained the following resulting coefficients:

[tex]1,1,-2,13[/tex]

Thus, we can conlcude that the quotient is:

[tex]x^2+x-2[/tex]

And the remainder is 13, which is indeed P(-2)

Other Questions
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