Answer:
Step-by-step explanation:The only one you probably can never do is B. It get's you no where. The way A is written, it is not much help to write 18 in base 2. So A and B both won't work. The common logs and the natural logs will both work
Log(4^(x + 3)) = Log(18)
(x + 3) Log(4) = log (18)
(x + 3) * 0.6021 = 1.2553
x + 3 = 1.2553/0.6021
x + 3 = 2.08496
Now all you need do is subtract 3 from both sides. The natural logs will give you the same answer.
You could take base-4 logs of both sides and it is a possible first step, but d and e are much more efficient. You have to change both sides to base 4 before you can proceed. This one is kind of iffy. It does say possible first steps.
Find the value of X.
3(4x + 8) = - 35+23
Answer:
x = -3
Step-by-step explanation:
3(4x + 8) = - 35+23
Combine like terms
3(4x + 8) =-12
Divide by 3
3/3(4x + 8) = -12/3
4x+8 = -4
Subtract 8 from each side
4x+8-8 = -4-8
4x = -12
Divide by 4
4x/4 = -12/4
x = -3
Answer:
x= -3
Step-by-step explanation:
first distribute 3 into the parenthesis
than it will result in 12x+24=-35+23. Than add -35+23
Than it will result in 12x+24=-12. Than subtract 24 from each sides.
This will result in 12x=-36. Than divide 12/-36 than you get -3 for x
If Taylor uses 1 3/4 tablespoons of coffee to make 5 cups of coffee, how much would he need to make one cup of coffee?
What are the x-intercept and the y-intercept of the graph of 12x – 4y = 48?
Answer:
The x-intercept and the y-intercept of the graph of 12x-4y=48 is 6.
Step-by-step explanation:
I used trial and error. I substituted x and y with 6 to get the answer.
12(6)-4(6)=48
Select the correct answer.
Jonathan has 30 chocolates. He gives some chocolates to his friend David. He then gives Sarah half the number of chocolates that he gave David and gives Lily two-thirds of what he gave David. After giving away the chocolates, Jonathan has 4 chocolates left. If the number of chocolates Jonathan gives David is x, which equation represents the situation? How many solutions does this equation have?
A.
, which has no solution
B.
, which has infinitely many solutions
C.
, which has one solution
D.
, which has one solution
E.
, which has no solution
Reset Next
Answer:
A
Step-by-step explanation:
DonaldandLauracompetedina1kmrace.DonaldcompletedtheraceinCCVII seconds and Laura completed it in CCCXLVIII seconds. By how many seconds (in Roman numerals) was Donald ahead of Laura?
a. DLV b. CXLIV c. CXL d. CXLI
Answer: D
Steps: CXLI = 141 seconds
Plz mark brainliest:)
I need help ASAP please!!!!!!
Answer:
1. d
2. c
3. b
4. a
Step-by-step explanation:
Answers:
1. d
2. c
3. b
4. a
================================================
Explanation:
For problem 1, subtracting a negative is the same as adding a positive. The two negatives cancel out
In problem 2, we can add a negative to mean we're subtracting. One way to think of it is like adding on debt to your bank balance.
Problem 3 is similar to problem 2. The first term -17 isn't changed.
Problem 4 is similar to problem 1. The only difference is that the 17 is negative this time around.
Suppose M is the midpoint of PQ. If PM=6x-49 and MQ=47-2x, find PQ
Please halp
Answer:
PQ = 46
Step-by-step explanation:
PM = 6x - 49
MQ = 47 - 2x
6x - 49 = 47 - 2x
8x - 49 = 47
8x = 96
x = 12
PM = 6x - 49
= 6(12) - 49
= 23
MQ = 47 - 2x
= 47 - 2(12)
= 47 - 24
= 23
PQ = PM + MQ
= 23 + 23
= 46
What am I supposed to do? Is it subtract 180 from 56?
How many words can be typed in 10.5 minutes?
Answer: Around 2,000 words.
In which situation is the distance traveled proportional to time?
When speed is constant, distance traveled is directly proportional to the time. As the formula tells:
Speed = Distance / Time
So, if speed is constant, and you are increasing distance then time will increase, in order to keep the speed constant
The math club decided to have a car wash to raise money for competition expenses The graph below shows the relationship between cars washed and earnings (in dollars).
What is the domain of the graphed function?
Group of answer choices
A) -20≤y≤40,where x≥0
B)-20≤y≤40, where y is all integers
C)0≤x≤12, where x≥0
D)0≤x≤12, where x is all non-negative integers
Answer:
b
Step-by-step explanation:
The domain of the graph is the value on the x-axis. Domain = 0≤y≤50,where x≥0
Since we are not given the required graph. I am going to explain in a general way that is applicable to any form of a graph
Domains are input values of a function for which the function exists.
For a graph, they are values of the curve or line function along the x-axis.
Using the attached graph for instance. The domain of the graph is the value on the x-axis. Domain = 0≤y≤50,where x≥0
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a salesperson contacts eight potential customers per day. from past experience, we know that the probability of a potential customer making a person is 0.10. what is the probability the saelesperson will make exactly two sales in a day
In this problem, the salesperson contacts 8 potential customers per day and the probability of a potential customer making a purchase is 0.10.
We have to find the probability that the salesperson will make exactly two sales in a day. This is a binomial probability problem. The binomial probability distribution is a discrete probability distribution that is used when the outcome of an experiment is binary, i.e., it can take only two values. The binomial probability distribution is characterized by two parameters: n and p. The parameter n is the number of trials in the experiment, and p is the probability of success in each trial. In this problem,
n = 8, and p = 0.10.
To find the probability of exactly two successes in 8 trials, we can use the formula:
P(X = k) = nCk * p^k * (1 - p)^(n-k)
where X is the random variable that represents the number of successes in n trials, k is the number of successes we want to find, nCk is the number of combinations of n items taken k at a time, and p is the probability of success in each trial.Using this formula, we get:
P(X = 2) = 8C2 * (0.10)^2 * (0.90)^(8-2)= 28 * 0.01 * 0.43046721= 0.0120936
Therefore, the probability that the salesperson will make exactly two sales in a day is 0.0120936 or about 1.21%.
Thus, the salesperson will make exactly two sales in a day with a probability of 0.0120936 or about 1.21%.
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2) Suppose the probability distribution for the one-period return of some asset is as follows: Retur Probability 0.27 0.25€ 0.18 0.25+ 0.10 0.30 0.04 0.20+ b. What is this asset's variance and stand
The asset's variance is approximately 0.0358, and its standard deviation is approximately 0.1891.
To calculate the variance and standard deviation of the asset's returns, we'll follow the steps mentioned earlier using the given probability distribution:
⇒ Calculate the expected return (μ):
μ = (0.27 * 0.25) + (0.18 * 0.25+) + (0.10 * 0.30) + (0.04 * 0.20+)
= 0.0675 + 0.045 + 0.03 + 0.008
= 0.1505
⇒ Calculate the variance (σ^2):
σ^2 = [(0.27 - μ)^2 * 0.25] + [(0.18 - μ)^2 * 0.25+] + [(0.10 - μ)^2 * 0.30] + [(0.04 - μ)^2 * 0.20+]
Substituting the values and simplifying:
σ^2 = [(0.27 - 0.1505)^2 * 0.25] + [(0.18 - 0.1505)^2 * 0.25+] + [(0.10 - 0.1505)^2 * 0.30] + [(0.04 - 0.1505)^2 * 0.20+]
= [(0.1195)^2 * 0.25] + [(0.0295)^2 * 0.25+] + [(-0.0505)^2 * 0.30] + [(-0.1105)^2 * 0.20+]
= 0.017972 + 0.00021617 + 0.0030309025 + 0.01459516
= 0.0358141325
⇒ Calculate the standard deviation (σ):
σ = √(σ^2)
= √(0.0358141325)
≈ 0.1891
Therefore, the asset's variance is approximately 0.0358 and the standard deviation is approximately 0.1891.
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Use Euler's method with step size 0.5 to compute the approximate y-values y1≈y(0.5),y ≈y(1),y3≈y(1.5), and y4 ≈y(2) of the so y′=2−3x+2y,y(0)=3. y1=y2=y3=y4=y-values y1≈y(0.5),y2≈y(1),y3≈y(1.5), and y4≈y(2) of the solution of the initial-value problem y′ =2−3x+2y,y(0)=3
We are given a differential equation with an initial value problem. We will be using Euler's method to compute the approximate y-values of the solution at different x-values with the given step size.
Using the given differential equation: y′ =2−3x+2y, we know that y(0) = 3.We need to compute the approximate y-values of the solution at different x-values with the given step size of 0.5. To do that we will be using Euler's method. The Euler's method is as follows:
y1 = y0 + h(y′0)
where,y0 = 3 (initial value of y at x = 0)h = 0.5 (step size)
y′0 = 2−3x0+2y0 (the differential equation at x0 = 0, y0 = 3)
y1 = 3 + 0.5(2 - 3(0) + 2(3))= 6y2 = y1 + h(y′1)
where,y1 = 6 (the value of y at x = 0.5)
y′1 = 2−3x1+2y1 (the differential equation at x1 = 0.5, y1 = 6)
y2 = 6 + 0.5(2 - 3(0.5) + 2(6))= 12y3 = y2 + h(y′2) where,y2 = 12 (the value of y at x = 1)
y′2 = 2−3x2+2y2 (the differential equation at x2 = 1, y2 = 12)
y3 = 12 + 0.5(2 - 3(1) + 2(12))= 22y4 = y3 + h(y′3)
where,y3 = 22 (the value of y at x = 1.5)
y′3 = 2−3x3+2y3 (the differential equation at x3 = 1.5, y3 = 22)
y4 = 22 + 0.5(2 - 3(1.5) + 2(22))= 36
Thus, we used the Euler's method with step size 0.5 to compute the approximate y-values of y1≈y(0.5), y2≈y(1), y3≈y(1.5), and y4 ≈y(2) of the solution of the initial-value problem y′ =2−3x+2y, y(0) = 3.
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a hybrid car uses 1 gallon of gasoline to drive 54 miles. how many gallons of gas would be used to travel 162 miles
Answer:
3
Step-by-step explanation:
162/54 = 3
Alex and 4 of his friends are planning to split the cost of lunch. they want to spend at most $6 dollars per person. write and solve an inequality to find the maximum cost of the lunch they can order.
Answer:
They can order ≤ $24 in order for the inequality to be correct
write an equation in slope-intercept form of the line that passes through the points (-2,3) and (2,7)
Which is the equation of the graphed line written in
standard form?
Answer:
D the slope of the line is 1/2 and the y intercept is 0 so the answer is y = 1/2x + 0 or just y = 1/2x
what is the radius of a circle in which the distance from the center of the circle to the edge of the circle is 4
The distance from the center of a circle to the edge is called the radius of the circle. In this case, the distance is given as 4 units.
Therefore, the radius of the circle is 4 units.
The formula for the circumference of a circle is C = 2πr, where C is the circumference and r is the radius. If you want to find the circumference of the circle, you can use this formula by substituting the radius value.
The radius of a circle is the distance from the center of the circle to any point on the edge of the circle. If the distance from the center of the circle to the edge of the circle is 4, then the radius of the circle is 4.
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Q1. (5+5 Marks) A. Base - ten positional numeral system or occasionally called Denary system is a set containing ten digits from zero to nine. We use this system in our real life to all calculations. Write a matrix that represents all digits in this system except zero. Does this matrix have an inverse? Check your answer by calculating its determinant first.
The matrix that represents all digits in the base-ten positional numeral system, except zero, is a 9x9 matrix where each element represents a digit from 1 to 9.
The matrix that represents all digits in the base-ten positional numeral system, except zero, can be represented as follows:
[1 2 3 ... 9]
To check if this matrix has an inverse, we calculate its determinant. Since the matrix is a 9x9 matrix with elements from 1 to 9, the determinant can be calculated using standard methods such as expansion by minors or row reduction. However, since the matrix is a simple sequential arrangement of numbers, we can observe that the determinant of this matrix is zero. This is because the determinant of a matrix with identical rows or columns is always zero.
Since the determinant of the matrix representing the digits from 1 to 9 in the base-ten system is zero, we can conclude that the matrix does not have an inverse. Inverse of a matrix exists only if the determinant is non-zero. In this case, since the determinant is zero, the matrix does not have an inverse.
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A number p, when truncated to 1 decimal place, is equal to 14.3
Find the upper and lower bound of p.
Lower bound =
Upper bound=
Submit Answer
The lower bound of [tex]\(p\) is \(14.25\)[/tex] and the upper bound is [tex]\(14.35\).[/tex]
The given truncated number is [tex]\(14.3\)[/tex]. To find the upper and lower bounds of [tex]\(p\)[/tex], we need to consider the possible range of values that could round to [tex]\(14.3\)[/tex] when truncated to 1 decimal place.
Lower bound: To find the lower bound, we need to consider the greatest number that rounds down to [tex]\(14.3\)[/tex]. This is obtained by subtracting 0.05 from the given truncated number:
[tex]\(\text{{Lower bound}} = 14.3 - 0.05 = 14.25\)[/tex]
Upper bound: To find the upper bound, we need to consider the smallest number that rounds up to [tex]\(14.3\)[/tex]. This is obtained by adding 0.05 to the given truncated number:
[tex]\(\text{{Upper bound}} = 14.3 + 0.05 = 14.35\)[/tex]
Therefore, the lower bound of [tex]\(p\) is \(14.25\)[/tex] and the upper bound is [tex]\(14.35\).[/tex]
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Data were collected on the ages, in years, of the men and women enrolled in a large sociology course. Let the random variables M and W represent the ages of the men and women, respectively. The distribution of M has mean 20.7 years and standard deviation 1.73 years. The distribution of W has mean 20.2 years and standard deviation 1.60 years. Of all of those enrolled in the course, 54 percent are men and 46 percent are women. What is the mean age of the combined distribution of both men and women in the course? (A) 20.2 years (B) 20.43 years (C) 20.45 years (D) 20.47 years (E) 40.9 years
The answer is 20.45 years. The mean age of the combined distribution of both men and women in the course is approximately 20.45 years.(Option-c)
Since we know the percentages of men and women enrolled in the sociology course, we can use them to calculate the weighted average of the mean ages for men and women.
Let the combined distribution of both men and women be represented by the random variable X. We know that X is a weighted average of the mean ages for men and women, with weights equal to their respective percentages. That is:
X = 0.54*M + 0.46*W
We're asked to find the mean age of X. To do that, we need to find the expected value of X, which is the same as the mean of X. So we need to calculate E(X):
E(X) = E(0.54*M + 0.46*W)
By linearity of expectation, we know that:
E(aX + bY) = aE(X) + bE(Y)
So we can simplify E(X) as:
E(X) = 0.54*E(M) + 0.46*E(W)
We're given the mean ages for M and W, so we can substitute these values into the equation:
E(X) = 0.54*20.7 + 0.46*20.2
Simplifying, we get:
E(X) = 20.45 years (option-c)
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4
B
5
1
n
In Exercises 18-21,use the following information to find the distance
between the point and the line.
The distance d between the point (x,y) and the line Ax + By = Cis d =
AX, + By, - c
A ball will be drawn from the bag containing 20 balls numbered one through 20 if each ball is equally likely to be drawn what is the probability that the number on the bar will be drawn even or less than five
Answer:
3/5
Step-by-step explanation:
There are 20 balls, numbered 1 through 20.
Of these, 10 are even, 4 are less than five, and 2 are both even and less than 5.
So the probability is:
P(even or <5) = P(even) + P(<5) − P(even and <5)
P(even or <5) = 10/20 + 4/20 − 2/20
P(even or <5) = 12/20
P(even or <5) = 3/5
Solve two and one-third times two and three fourths.
A four and three twelfths
B six and five twelfths
C seven and five twelfths
D eight and three twelfths
E nine and 8 twelfths
Answer:
B
Step-by-step explanation:
Hope this helps
A soft-drink machine can be regulated so that it discharges an average of ? oz. per cup. If the ounces of fill areNormally distributed with a standard deviation of 0.4 oz., what value should ? be set at so that 98% of 6-oz. cups will not overflow?
A. 5.18
B. 6.00
C. 6.18
D. 6.60
E. 6.82
The value of the unknown should be set at 5 so that 98 of 6- oz. mugs won't overflow is A)5.18.
Given data
A soft- drink machine can be regulated so that it discharges an normal of? oz. per mug. The ounces of filler are typically distributed with a standard divagation of0.4 oz.
What value should be set at so that 98 of 6- oz. mugs won't overflow?
Let μ be the mean ounces of filler per mug.
μ can be attained by using the formula
μ = 6 oz. = 6/8 = 0.75 mugs.
Now, given σ = 0.4 oz.
The Z- score for a 6- oz mug can be calculated as follows
z = ( x- μ)/ σ
Then, x = 6 oz = 6/8 = 0.75 mugs.
μ = 0.75 mugs
σ = 0.4 oz.
z = (0.75-0.75)/0.4 = 0
For 98 of 6- oz mugs to not overflow, we need to find the value of μ similar that P( z Since the Normal distribution is symmetric about the mean, we have
P( 0< z We can look up the value of
z_score for P( 0< z
standard normal distribution table or use the inverse function on a calculator similar as Excel.
Using a table, we get the value ofz_score = 2.33.
Now, z = ( x- μ)/ σ2.33 = (0.75- μ)/0.4
μ = 0.75-0.4 ×2.33
μ = 0.75-0.932
μ = -0.182 oz.6 oz in terms of ounces = 6 *0.125 = 0.75 oz.
oz per mug in terms of ounces = ? *0.125 oz.
Using the values from above
μ = -0.1820.75 = 0.568 oz. ≈0.57 oz.
= 0.57/0.125 = 4.56 or 5
So, the value of the unknown should be set at 5 so that 98 of 6- oz. mugs won't overflow is A)5.18.
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Need help please!!!!!
Answer:
AAS
Step-by-step explanation:
Answer:
EZ 3rd one think bout it commmon since
Step-by-step explanation:
Solve the formula for the indicated variable.
The formula for the perimeter P of a triangle with sides of length a,b, and c is P=a+b+c. Solve the formula for b.
Answer: b = p - a -c
Step-by-step explanation:
p= a + b + c Solving for b means getting b on one side by itself.
p = a + b + c To solve for b first subtract a from both sides to get,
-b -b
p - a = b + c Now subtract c from both sides to get
-c -c
p - a - c = b
b = p - a -c
Answer:
b = P - a - cStep-by-step explanation:
Perimeter P = a + b + c
find b
P - a - c = b
b = P - a - c
Which classification describes the following system of equations?
inconsistent and dependent
consistent and dependent
consistent and independent
inconsistent and independent
Step-by-step explanation:
take the 1st eqn n divide it throughout by 3, the 3rd eqn n divide throughout by 4, all 3 equations will be the same as the 2nd one
The classification which best describes the system of equations is; Consistent and dependent
Discussion:
A linear or nonlinear system of equations as the case may be is termed consistent if there is at least one set of values for the unknowns that satisfies each equation in the system. In essence, when substituted into each of the equations, they make each equation hold true.
Additionally, the system of equations is dependent because the value of each variable is dependent on the others.
Therefore, when equation 1 and 3 are divided by 3 and 4 respectively; the equations become similar to equation 2.
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how do I graph a equation using y= ⅕+3?
Answer: The y intercept (3) goes 3 up in the y axis.
To find the slope (rise/run), we start from the point we found at the y intercept ( which is 3). So we rise 1 (from the 3), and run 5.
(always run to the right)
The file is a picture of your equation.
