Which best describes a system of equations that has infinitely many solutions? 1.consistent, independent 2.inconsistent, dependent 3.consistent, dependent 4.inconsistent How many solutions does this system have? y = x + 5 y = -5x - 1 1.one 2.none 3.infinite 4.two

Answers

Answer 1

When a system of equations has infinitely many solutions, it is considered consistent and dependent.

This means that the equations are not contradictory and there are multiple solutions that satisfy both equations. In contrast, an inconsistent system of equations has no solutions and a consistent, independent system has exactly one unique solution.

For the given system of equations y = x + 5 and y = -5x - 1, we can see that both equations can be rearranged to the form y = mx + b, where m represents the slope and b represents the y-intercept. In this case, the slopes are different (-5 and 1) and the y-intercepts are different (-1 and 5). Therefore, the two lines intersect at a single point and the system has only one solution. So, the answer is option 4 - two.

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Related Questions

The population of a town was 6,000 people last year. The population is expected to increase by 4% this year. By how many people is the population expected to increase this year?

Answers

[tex]\begin{array}{|c|ll} \cline{1-1} \textit{\textit{\LARGE a}\% of \textit{\LARGE b}}\\ \cline{1-1} \\ \left( \cfrac{\textit{\LARGE a}}{100} \right)\cdot \textit{\LARGE b} \\\\ \cline{1-1} \end{array}~\hspace{5em}\stackrel{\textit{4\% of 6000}}{\left( \cfrac{4}{100} \right)6000}\implies 240[/tex]

if csc(θ)<0, then in which quadrants could θ lie? select all correct answers. .Quadrant I .Quadrant II .Quadrant III .Quadrant IV

Answers

When csc(θ)<0, it means that the cosecant of angle θ is negative. Recall that the cosecant of an angle is the reciprocal of its sine. Therefore, csc(θ)<0 when sin(θ)<0.

The sine function is negative in the third and fourth quadrants of the unit circle, where the y-coordinate of the point on the circle is negative. Therefore, if csc(θ)<0, angle θ could lie in Quadrant III or Quadrant IV. To summarize, when csc(θ)<0, angle θ could lie in Quadrant III or Quadrant IV. It cannot lie in Quadrant I or Quadrant II because the sine function is positive in those quadrants.

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Solve the equation x^2-14x-11=-30 to the nearest tenth

Answers

To solve the equation x^2-14x-11=-30, we can first move all the terms to one side of the equation: x^2 - 14x - 11 + 30 = 0Simplifying the left side:

x^2 - 14x + 19 = 0

To solve for x, we can use the quadratic formula:  

x = (-b ± sqrt(b^2 - 4ac)) / 2a

In this case, a = 1, b = -14, and c = 19. Plugging these o solve the equation x^2-14x-11=-30, we can first move all the terms to one side of the equation:

x^2 - 14x - 11 + 30 = 0

Simplifying the left side:

x^2 - 14x + 19 = 0

To solve for x, we can use the quadratic formula:

x = (-b ± sqrt(b^2 - 4ac)) / 2a

In this case, a = 1, b = -14, and c = 19. Plugging these values into the formula, we get:

x = (14 ± sqrt(14^2 - 4(1)(19))) / 2(1)

Simplifying the square root:

x = (14 ± sqrt(108)) / 2

x = (14 ± 10.39) / 2

x ≈ 12.2 or x ≈ 1.8

Therefore, the solutions to the equation x^2-14x-11=-30 to the nearest tenth are x ≈ 12.2 and x ≈ 1.8.

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for the following initial value problem, compute the first two approximations u1 and u2 given by Euler’s method using the given time stepy’(t)=t+y; y(0)=5; triangle t=0.3u1=u2=

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Using Euler's method with a time step of 0.3, the first two approximations for the solution to the initial value problem y'(t) = t + y, y(0) = 5 are u1 = 6.5 and u2 = 8.035.

Using Euler's method, we can approximate the solution to the initial value problem y'(t) = t + y, y(0) = 5 with a time step of Δt = 0.3 as follows:

At t = 0, y = 5

Using the formula: y1 = y0 + f(y0,t0)Δt, where f(y,t) = t + y

y1 = 5 + (0 + 5)0.3 = 6.5

Using the formula again with y1 and t1 = Δt:

y2 = 6.5 + (0.3 + 6.5)0.3 = 8.035

Thus, the first two approximations u1 and u2 are 6.5 and 8.035, respectively.


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a run test is usedpart 2a.in acceptance sampling to establish control.b.to examine points in a control chart to check for natural variability.c.to examine variability in acceptance sampling plans.d.to examine points in a control chart to check for nonrandom variability.e.none of the above

Answers

The answer d. To examine points in a control chart to check for nonrandom variability.

What is the random variable?

A random variable is a mathematical function that maps outcomes of a random event or experiment to numerical values. In other words, it assigns a numerical value to each outcome of a random event or experiment.

A run test is not typically used for acceptance sampling, but it can be used to examine points in a control chart to check for nonrandom variability. Control charts are used to monitor a process over time and detect any patterns or trends in the data that may indicate the presence of non-random variability, such as a shift, trend, or cycle.

A run test is a statistical test that examines patterns or runs of consecutive data points above or below the centerline on a control chart, which may indicate nonrandom variability.

If a significant run is detected, it may signal the need for further investigation and corrective action to address the underlying cause of the variation.

Therefore,

The answer d. To examine points in a control chart to check for nonrandom variability.

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The table shows conversions of common units of capacity. Units of Capacity
Customary System Units
Metric System Units
1 gallon
3. 79 liters
1 quart
0. 95 liters
1 pint
0. 473 liters
1 cup
0. 237 liters

Which expression can be used to find the number of liters in 15 quarts?

Answers

There are 14.25 liters in 15 quarts based on the expression and data given.

To find the number of liters in 15 quarts, we can use the conversion factor given in the table for quarts to liters. The table states that 1 quart is equal to 0.95 liters.

To convert 15 quarts to liters, we can set up the following expression:

Number of liters = (Number of quarts) × (Conversion factor)

In this case:
Number of liters = 15 quarts × 0.95 liters/quart

Now, you can simply multiply 15 by 0.95 to find the number of liters:
Number of liters = 15 × 0.95 = 14.25 liters

So, there are 14.25 liters in 15 quarts.

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find the solution to dydt=7y satisfying y(3)=2

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The solution to the differential equation [tex]dy/dt = 7y[/tex] satisfying y(3) = 2 is [tex]y(t) = (2/e^(21))e^(7t)[/tex].

A differential equation is a type of mathematical equation that quantifies the pace at which a quantity changes over time. It connects an unknown function to its derivatives and can be used to simulate a variety of real-world occurrences, including fluid movement, disease transmission, and item motion.


We have the differential equation [tex]dy/dt = 7y[/tex] and the initial condition y(3) = 2. Let's find the solution satisfying this condition.

Step 1: Separate the variables. Divide both sides by y to isolate dy:[tex]y(t) = (2/e^(21))e^(7t)[/tex]
[tex](dy/dt)/y = 7[/tex]

Step 2: Integrate both sides with respect to t:
[tex]\int\limits{x} \, (1/y) dy = \int\limits{x} \, 7 dt[/tex]

Step 3: Solve the integrals:
[tex]ln|y| = 7t + C₁[/tex]

Step 4: Solve for y by taking the exponent of both sides:
[tex]y(t) = e^(7t + C₁)[/tex]
Step 5: Rewrite the equation using the constant C:
[tex]y(t) = Ce^(7t)[/tex]

Step 6: Apply the initial condition y(3) = 2 to find C:
[tex]2 = Ce^(7*3)[/tex]

Step 7: Solve for C:
[tex]C = 2/e^(21)[/tex]

Step 8: Write the final solution:
[tex]y(t) = (2/e^(21))e^(7t)[/tex]


So, the solution to the differential equation [tex]dy/dt = 7y[/tex] satisfying y(3) = 2 is [tex]y(t) = (2/e^(21))e^(7t)[/tex].


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*PLS MUST ANSWER ASAP*

Answers

Answer:the 3rd option

Step-by-step explanation:

The range for a set of data is estimated to be 52. (a) What is the planning value for the population standard deviation? (b) At 95% confidence, how large a sample would provide a margin of error of 47(Round your answer up to the nearest whole number) (c) At 95% confidence, how large a sample would provide a margin of error of 27(Round your answer up to the nearest whole number)

Answers

The planning value for the population standard deviation is estimated to be 13. The sample size needed for a margin of error of 47 at 95% confidence is 36, and the sample size needed for a margin of error of 27 at 95% confidence is 91.

The range of a data set is used to estimate the population standard deviation (σ) using the formula σ ≈ range/4. Therefore, in this case, the planning value for the population standard deviation is estimated to be 52/4 = 13.

To find the sample size needed to provide a margin of error of 47 at 95% confidence, we can use the formula n = (z^2 * σ^2)/E^2, where z is the z-score corresponding to the confidence level (1.96 for 95% confidence), σ is the estimated population standard deviation, and E is the margin of error. Substituting the given values, we get n = (1.96^2 * 13^2)/47^2 ≈ 36. Therefore, a sample size of 36 or more would be needed to provide a margin of error of 47 at 95% confidence.

To find the sample size needed to provide a margin of error of 27 at 95% confidence, we can use the same formula as above. Substituting the given values, we get n = (1.96^2 * 13^2)/27^2 ≈ 91. Therefore, a sample size of 91 or more would be needed to provide a margin of error of 27 at 95% confidence.

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Select the image that is NOT a polyhedron.

Answers

Answer:

  A

Step-by-step explanation:

You want the figure that is not a polyhedron.

Polyhedron

A polyhedron is a solid figure with plane faces. The curved side of figure A means it is not a polyhedron.

Figure A is not a polyhedron.

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For which value of x must the expression √71x be further simplified?
Select 3 correct answer(s)

1: 6
2: 12
3: 19
4: 32
5: 34
6: 41
7: 48

thank you so much!!

Answers

To simplify the expression √71x, we need to find the largest perfect square factor of 71x. The prime factorization of 71 is 71 = 1 x 71 or 71 x 1, so 71 is a prime number and has no perfect square factors other than 1. Therefore, the largest perfect square factor of 71x is x itself.

To find the value of x that must be further simplified, we need to find the values of x that are perfect squares. We can do this by testing each of the answer choices:

√71(6) = 26.16... not a perfect square

√71(12) = 36.98... not a perfect square

√71(19) = 46.91... not a perfect square

√71(32) = 65.2... not a perfect square

√71(34) = 67.28... not a perfect square

√71(41) = 77.12... not a perfect square

√71(48) = 88.83... not a perfect square

None of the values of x result in a perfect square, so we cannot further simplify the expression √71x. Therefore, the answer is: None of the above (None of the values of x given require further simplification of the expression).

sam wants to improve his gpa. to earn a 4.0 this semester. his prior gpa was a 2.75. imagine that there is an equation that says his new gpa could be

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Sam needs to study approximately 4.6 hours per week to earn a 4.0 GPA. The answer is (d) 4.6 hours.

We know that Sam wants to earn a 4.0 GPA, and his class attendance hours are fixed at 4. Therefore, we can solve for the number of hours he needs to spend studying to achieve this goal by setting the equation equal to 4.0 and solving for the hours spent studying:

4.0 = (0.50 x hours spent studying) + (0.25 x 4) + (0.25 x 2.75)

4.0 = (0.50 x hours spent studying) + 1 + 0.6875

2.3125 = 0.50 x hours spent studying

hours spent studying = 4.625

The correct option is (d) 4.6 hours.

The complete question is:

Sam wants to improve his GPA. to earn a 4.0 this semester. His prior GPA was a 2.75. Imagine that there is an equation that says his new GPA could be calculated based on the number of hours he spends studying, his class attendance, and his prior GPA. Written as an equation, it is Grade = (0.50 x hours spent studying) + (0.25 x class attendance hours) + (0.25 x prior GPA). Sam plans to attend class for 4 out of 4 hours each week. Use the equation to determine approximately how many hours per week Sam needs to study to earn a 4.0.

Select one:

a. 2.3 hours

b. 4.0 hours

c. 1.7 hours

d. 4.6 hours

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if x and y are rational numbers then 3x 2y is also a rational number.

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Yes, if x and y are rational numbers, then 3x + 2y is also a rational number. This can be proven using the definition of rational numbers and the closure properties of addition and multiplication.

A rational number is defined as any number that can be expressed as the ratio of two integers, where the denominator is not zero. For example, 3/4, 7/2, and -5/6 are all rational numbers.


Now, let's assume that x and y are rational numbers. Then, by definition, we can write x = p/q and y = r/s, where p, q, r, and s are integers and q and s are not zero.

Using this notation, we can write:

3x + 2y = 3(p/q) + 2(r/s)
= (3p/q) + (2r/s)
= (3ps + 2rq) / qs

Since p, q, r, and s are all integers and qs is not zero, (3ps + 2rq) / qs is also a ratio of two integers where the denominator is not zero. Therefore, 3x + 2y is a rational number.

In conclusion, we can say that if x and y are rational numbers, then 3x + 2y is also a rational number. This result follows directly from the definition of rational numbers and the closure properties of addition and multiplication.

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a juice company gives prizes to anyone finding specially marked caps on its bottles. you and your friends buy 56 bottles of juice. you find 2 of the bottles have a winning cap. what is the experimental probability of winning a prize in the contest? express your answer as a fraction in simplest form.

Answers

The experimental probability of winning a prize in the contest is 1/28 or approximately 0.0357.

To calculate the experimental probability of winning a prize in the contest, we need to divide the number of winning caps found by the total number of caps examined.

Here are the steps to follow:

Calculate the total number of caps examined:

Total number of bottles bought x Number of caps per bottle = Total number of caps examined

56 bottles x 1 cap per bottle = 56 caps examined

Calculate the number of winning caps found:

Given: 2 winning caps were found

Calculate the experimental probability of winning a prize:

Experimental probability = Number of winning caps found / Total number of caps examined

Experimental probability = 2 / 56

Experimental probability = 1 / 28

Explanation: Out of 56 caps examined, only 2 were found to be winning caps. Therefore, the probability of finding a winning cap is 2/56, which can be simplified to 1/28. This means that on average, for every 28 caps examined, one is expected to be a winning cap.

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find the first partial derivatives of the function. f(x, y) = x4 4xy9 fx(x, y) = incorrect: your answer is incorrect. fy(x, y) = incorrect: your answer is incorrect.

Answers

The first partial derivatives of the function f(x, y) = [tex]x^4 - 4xy^9[/tex] are fx(x, y) = 4x³ and fy(x, y) = [tex]-36xy^8[/tex].

To find the first partial derivatives of the function f(x, y) = [tex]x^4 - 4xy^9[/tex], we need to take the partial derivative with respect to each variable separately while treating the other variable as a constant.
The partial derivative of f(x, y) with respect to x (fx) is obtained by differentiating [tex]x^4[/tex] with respect to x, which gives [tex]4x^3[/tex]. The second term [tex]-4xy^9[/tex] does not involve x, so it drops out in the differentiation process. Therefore, fx(x, y) = [tex]4x^3[/tex].
Similarly, the partial derivative of f(x, y) with respect to y (fy) is obtained by differentiating [tex]-4xy^9[/tex] with respect to y, which gives [tex]-36xy^8[/tex]. The first term x^4 does not involve y, so it drops out in the differentiation process. Therefore, fy(x, y) = [tex]-36xy^8[/tex].
In summary, the first partial derivatives of the function f(x, y) = [tex]x^4 - 4xy^9[/tex] are fx(x, y) = 4x³ and fy(x, y) = [tex]-36xy^8[/tex].

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in the diagram of right triangle VUT below, altitude US is drawn. which of the following ratios is equivalent to tan v?

-vu/ut
-su/vu
-su/vs
-us/ut

Answers

The required, ratio of sides that is equivalent to tan V is SU/VS.

In the given figure,
Consider the triangles VSU and VUT. By applying the tangent function to both triangles, we can establish the following relationships:

The tangent of angle V is equal to the ratio of side SU to side VS, i.e., tanV = SU/VS.

Similarly, the tangent of angle V is also equal to the ratio of side UT to side VU, i.e., tanV = UT/VU.

By utilizing the tangent function in these two triangles, we can derive these equations.

Thus. the required, ratio of sides that is equivalent to tan V is SU/VS.

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Suppose that f (x) is a differentiable, invertible function whose tangent line at x = 10 is given by y= 7(x – 10) + 12. Use this information to determine which, if any, of the following statements are true. I. f-1 (10) = 12 II. f-1 (12) = 10 III. (f-1)(12) = IV. (F-1)' (12) = -7 1 7 a) I and III only b) Oll and III only c) I, II, III and IV d) Il only e) None of the above.

Answers

The correct answer is the statements for tangent line are (b) I and III only. I) f-1 (10) = 12 (II) (f-1)(12) = 1/7

The tangent line at x=10 is given by y = 7(x-10) + 12, which has a slope of 7. This means that the derivative of f(x) at x=10, f'(10), is equal to 7.

We can use the inverse function theorem to find the derivative of the inverse function f^(-1)(x) at x=12, denoted as (f^(-1))'(12). This is given by:

(f^(-1))'(12) = 1/f'(f^(-1)(12))

Since the tangent line at x=10 is given by y=7(x-10)+12, we know that f(10) = 12. Therefore, f^(-1)(12) = 10. Substituting this into the above equation, we get:

(f^(-1))'(12) = 1/f'(10) = 1/7

So, statement IV is false.

To check the other statements, we can use the fact that f(f^(-1)(x)) = x. Substituting x=10, we get:

f(f^(-1)(10)) = 10

Since f(10) = 12, this implies that f^(-1)(10) = 10/12 = 5/6. Therefore, statement I is true.

Similarly, substituting x=12, we get:

f(f^(-1)(12)) = 12

Since f(10) = 12, this implies that f^(-1)(12) = 10. Therefore, statement II is false, and statement III is true.

In summary, the correct statements are I and III only, so the answer is (b).

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You have an SRS of six observations from a Normally distributed population. What critical value would you use to obtain an 80% confidence interval for the mean µ of the population? (a) 1.440 (b) 1.476 (c) 2.015

Answers

You have an SRS of six observations from a Normally distributed population, the correct answer is (c) 2.015

To obtain an 80% confidence interval for the mean µ of a Normally distributed population with a small sample size (n<30), we need to use a t-distribution with n-1 degrees of freedom. In this case, since we have an SRS of six observations, our degrees of freedom are 6-1=5. To determine the critical value for an 80% confidence interval using a t-distribution with 5 degrees of freedom, we can use a t-table or a calculator. Using a t-table, we would find the row corresponding to 5 degrees of freedom and the column for a two-tailed test with an area of 0.10 (80% divided by 2). The intersection of this row and column gives us a critical value of 2.015. Therefore, the correct answer is (c) 2.015. Alternatively, we could use a calculator that has a t-distribution function. In this case, we would enter a confidence level of 0.80, a degree of freedom of 5, and ask the calculator to output the critical value. This would also give us a critical value of 2.015.

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Find the average value of f(x) = 25 – x2 on the interval [0, 5].

Answers

Therefore, the average value of the function f(x) = 25 - x^2 on the interval [0, 5] is 50/3.

To find the average value of the function f(x) = 25 - x^2 on the interval [0, 5], we need to calculate the definite integral of the function over the interval and divide it by the length of the interval.

The average value (AV) is given by the formula:

AV = (1 / (b - a)) * ∫[a to b] f(x) dx

In this case, a = 0 and b = 5, so the average value becomes:

AV = (1 / (5 - 0)) * ∫[0 to 5] (25 - x^2) dx

Simplifying, we have:

AV = (1/5) * ∫[0 to 5] (25 - x^2) dx

To evaluate the integral, we integrate term by term:

AV = (1/5) * [25x - (x^3 / 3)] evaluated from 0 to 5

AV = (1/5) * [(255 - (5^3 / 3)) - (250 - (0^3 / 3))]

AV = (1/5) * [(125 - (125 / 3)) - 0]

AV = (1/5) * [(375/3 - 125/3)]

AV = (1/5) * (250/3)

AV = 250/15

AV = 50/3

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[tex]d^{2}=15^{2}+9^{2}+10^{2}[/tex]

Answers

Ur answer is in the photo below

please help:
if triangle PRT∼ triangle QRS, find PT​

Answers

Answer:

C. 40

Step-by-step explanation:

36/(5x+13)=30/(6x-2)

Cross multiply

36·(6x-2)=30·(5x+13)

216x-72=150x+390

216x-150x=390+72

66x=462

x=7

Substituting 7 in for x,

6(7)-2

42-2

40

find the curve that describes the level curve of value c of the surface z = f ( x , y ) = x 2 4 y 2 25 = c where c < 0 .

Answers

There is no curve that describes the level curve of value c for the given surface, as the condition c < 0 makes it impossible to find a real solution.

In two- or three-dimensional space, a curve is a mathematical object that symbolises a continuous, smooth path. Curves can be derived from geometric operations, parametric equations, or mathematical equations. They are commonly used to simulate real-world processes in physics, engineering, mathematics, and many other disciplines.

To find the level curve of value c for the given surface [tex]z = f(x, y) = (x^2/4) + (y^2/25) = c[/tex], where c < 0, follow these steps:

Step 1: Write down the equation of the surface.
[tex]z = f(x, y) = (x^2/4) + (y^2/25)[/tex]

Step 2: Replace z with the constant c.
[tex]c = (x^2/4) + (y^2/25)[/tex]

Step 3: Rearrange the equation to isolate [tex]y^2[/tex].
[tex]y^2 = 25(c - (x^2/4))[/tex]

However, note that we're given that c < 0. This means that the value inside the parentheses (c - ([tex]x^2/4[/tex])) must also be negative. Since y^2 can't be negative, there's no real solution for this equation.

In conclusion, there is no curve that describes the level curve of value c for the given surface, as the condition c < 0 makes it impossible to find a real solution.


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Determine the period, frequency and amplitude of the wave that produced the position vs. time graph shown below.

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Answer: I'm in 2nd grade

Step-by-step explanation: Fortnight is a acrobatic FIRST PERSON SHOOTER GAME

The distribution of weights of female college cross country runners is approximately normal width mean 122 pounds and standard deviation 8 pounds. Which of the following is closest to the percent of the runners who’s way between 114 pounds in 138 pounds 

Answers

The percentag.e of female college runners between 114 - 138 pounds is 82%

What % of runners weigh 114 - 138 pounds?

Given that X is normally distributed with mean μ = 122 pounds and standard deviation σ = 8 pounds.

We want to find [tex]P(114 < X < 138)[/tex]

To get this, we will standardize X first:

[tex]P(114 < X < 138) = P((114 - 122)/8 < (X - 122)/8 < (138 - 122)/8)[/tex]

= P(-1 < Z < 2)

Using standard normal table, we find that probability of Z falling between -1 and 2 is:

= 0.8186

That means:

[tex]P(114 < X < 138)[/tex] = 0.8186

[tex]P(114 < X < 138)[/tex] = 81.86%

[tex]P(114 < X < 138)[/tex] = 82%

Missing options:

(A)18% (B) 32% (C) 68% (D) 82% (E)95%

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The total cost, c, to throw a party can be found using the function c= 28g + 75, where g is the number guests attending the party. If there are at least 20 but not more than 25 guests attending the party, then what is the range of the function for this situation?

Answers

This situation where there are at least 20 but not more than 25 guests attending the party, the range of the function is from 655 to 875, inclusive.

To find the range of the function for this situation, we need to evaluate the function for the given range of values of g, which is 20 to 25.

If there are 20 guests attending the party, then:

c = 28g + 75 = 28(20) + 75 = 655

If there are 25 guests attending the party, then:

c = 28g + 75 = 28(25) + 75 = 875

Therefore, for This situation where there are at least 20 but not more than 25 guests attending the party, the range of the function is from 655 to 875, inclusive.

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If a = 4, then a 2 · a 3 is equivalent to all of the following except _____.
4 6
1,024
4 2 · 4 3
a 5

Answers

If a = 4, then a 2 · a 3 is equivalent to all of the following except _ 4^2 · 4^3 = 1,024

Noted that Expression in maths is defined as the collection of numbers variables and functions by using signs like addition, subtraction, multiplication, and division.

We are given that a = 4, then the expression could be;

a^2 · a ^3

Substitute the values;

a^2 · a ^3  = 4^2 · 4^3

= 16 . 64

= 1,024

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which component is the reason why ae may be different from gdp?

Answers

The component that is the reason why AE (Aggregate Expenditure) may be different from GDP (Gross Domestic Product) is unplanned inventory investment.

Unplanned inventory investment occurs when actual sales differ from expected sales, leading to unplanned changes in inventory levels. When firms produce more output than what consumers are willing to buy, the unsold goods accumulate as inventory. On the other hand, when the demand for goods exceeds the production levels, firms may run out of inventory.

The difference between actual inventory levels and planned inventory levels can lead to unplanned changes in inventory investment, which affects GDP. If actual inventory levels are greater than planned inventory levels, this indicates that firms have produced more than what consumers are willing to buy. Therefore, firms will reduce production in the future, leading to a decrease in GDP. Conversely, if actual inventory levels are lower than planned inventory levels, this indicates that firms have produced less than what consumers are willing to buy. Therefore, firms will increase production in the future, leading to an increase in GDP. Thus, unplanned inventory investment plays a significant role in the difference between AE and GDP

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help me asap please

Answers

Based on the characteristics of the line and parabola , the correct answer is: A. [tex]\(y = \begin{cases} x^2 + 2, ; x \leq 1 \\ -x + 2, ; x > 1 \end{cases}\)[/tex]

Based on the given information, let's analyze the characteristics of the line and parabola to determine the correct representation:

1. Line: In the context of graphing, a line appears as a straight line that can extend in any direction across the coordinate plane. It can have a positive or negative slope, or be horizontal or vertical.

- The line passes through the points [tex](1,1),(2,0) , (4, -2) , ( 8 , -6)[/tex]

- It extends along the first and fourth quadrants.

- A closed dot is shown at the point (1,1).

2. Parabola: In the context of graphing, a parabola appears as a curved line. It can open upward or downward and can be concave or convex. The vertex of the parabola represents the lowest or highest point on the curve, and the axis of symmetry is a vertical line that passes through the vertex, dividing the parabola into two symmetric halves.

- The parabola passes through the points [tex](1,3) , (-2,6), (10,-3)[/tex]

- It extends along the first and second quadrants.

- An open dot is shown at the point (1,3).

- The vertex of the parabola lies at (0,2).

Given these characteristics, we can determine the correct representation:

The correct answer is:

A. [tex]\(y = \begin{cases} x^2 + 2, ; x \leq 1 \\ -x + 2, ; x > 1 \end{cases}\)[/tex]

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we can express the function g(x) as a composition of f(x) with another function; that is, we can write g(x) = f h(x) . identify the "inside function" h(x).

Answers

Therefore, we can write the expression g(x) as g(x) = f(h(x)), where h(x) is the inside function. In this expression, h(x) represents the input to f(x), and f(x) represents the outer function that is being applied to the input.

In order to identify the "inside function" h(x) in the expression g(x) = f h(x), we need to understand what a composition functions means.

A composition of functions is a way of combining two or more functions to form a new function. In this case, we are combining the function f(x) with another function h(x) to form the function g(x).The inside function h(x) is the function that is being applied to the input of f(x). In other words, h(x) is the function that is being plugged into f(x) as its input. The output of h(x) is then used as the input for f(x), and the result is the value of g(x).To identify h(x), we need to look at the expression g(x) = f h(x) and determine which part of the expression represents h(x). Since h(x) is being applied to the input of f(x), we can see that h(x) must be the argument of f(x). In other words, h(x) is the function that is being plugged into f(x).By identifying the inside function h(x), we can better understand how the composition of functions works and how g(x) is related to f(x).

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Can some explain this equation ?? z = -4a for a

Answers

The solution to the equation is a = z / -4

This means that if we know the value of "z," we can plug it into this equation to find the value of "a" that satisfies the equation.

What is the equivalent expression?

Equivalent expressions are expressions that perform the same function despite their appearance. If two algebraic expressions are equivalent, they have the same value when we use the same variable value.

Sure, I can explain this equation for you!

The equation is in the form of "z equals -4a for a," which means we're trying to solve for the variable "a" in terms of "z."

Starting with the equation:

z = -4a

To isolate "a" on one side of the equation, we want to get rid of the coefficient of "-4" that's multiplied by "a".

We can do this by dividing both sides of the equation by "-4":

z / -4 = (-4a) / -4

On the right side, the "-4" in the numerator and the "-4" in the denominator cancel out, leaving only "a":

z / -4 = a

hence, the solution to the equation is a = z / -4

This means that if we know the value of "z," we can plug it into this equation to find the value of "a" that satisfies the equation.

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