Which choice below is not an example of a limiting factor:
Money
Space
Predators
Nutrients
Sunlight

Answers

Answer 1
Space, since as we think and have been thinking for decades, it is infinite.

Related Questions

PO3−4 what's the formula name?

Answers

Answer:

Phosphate ion

Explanation:

Use the Periodic Table of the Elements to answer
the question. Which element is least likely to give
away electrons?
A. fluorine B. lithium
C. carbon D. neon

Answers

Answer:

b. lithium

Explanation:

Li the least likely, to lose an electron.

In an experiment to determine the empirical formula of magnesium chloride, 0.50 g of magnesium ribbon was taken in a beaker and a few drops of HCl was added until all the Mg reacted with the acid liberating the hydrogen gas. The reaction completion was noted by observing that the bubbling stopped and no solid Mg was seen in the beaker. The beaker was heated to remove water and the dried magnesium chloride was weighed and found to be 1.99 g. What is the empirical formula for magnesium chloride based on this experiment

Answers

Answer:

The the empirical formula for magnesium chloride based on this experiment will be [tex]MgCl_{2}[/tex]

Explanation:

Given that,

Mass of Mg = 0.50 g

Mass of magnesium chloride found = 1.99 g

Let the formula of magnesium chloride be [tex]Mg_{x}Cl_{y}[/tex]

We know that,

Molar mass of Mg= 24 g/mol

Molar mass of magnesium chloride = (24x+35.5y) g/mol

We need to calculate the moles of Mg

Using formula of moles

[tex]Number\ of\ moles=\dfrac{mass}{molar\ mass\ of\ Mg}[/tex]

Put the value into the formula

[tex]Number\ of\ moles=\dfrac{0.50}{24}[/tex]

[tex]Number\ of\ moles=0.020\ mole[/tex]

We need to calculate the mole of magnesium chloride

Using formula of moles

[tex]Number\ of\ moles=\dfrac{mass}{molar\ mass\ of\ magnesium\ chloride}[/tex]

Put the value into the formula

[tex]Number\ of\ moles=\dfrac{1.99}{24x+35.5y}\ mole[/tex]

The reaction will be,

[tex]Mg+HCl\Rightarrow Mg_{x}Cl_{y}+H_{2}[/tex]

We need to calculate the value of x and y

Using number of moles of Mg in reactant and product

Moles of Mg atom in reactant=Moles of Mg atom in product

[tex]\dfrac{0.50}{24}=x\times\dfrac{1.99}{24x+35.5y}[/tex]

[tex]0.020(24x+35.5y)=x\times1.99[/tex]

[tex]0.48x+0.71y=1.99x[/tex]

[tex]0.71y=(1.99-0.48)x[/tex]

[tex]\dfrac{x}{y}=\dfrac{0.71}{1.99-0.48}[/tex]

[tex]\dfrac{x}{y}=0.47\approx0.5[/tex]

[tex]\dfrac{x}{y}=\dfrac{1}{2}[/tex]

Hence, The the empirical formula for magnesium chloride based on this experiment will be [tex]MgCl_{2}[/tex]

What is the most stable resonance structure if oxygen is the central atom in the CON– ion?

Answers

Answer:

The most stable resonance structure shown in fig (II).

Explanation:

Given that,

If oxygen is the central atom in the CON– ion

We know that,

Resonance :

The movement of electron is called resonance.

If the electronegativity is more of element then the element is more stable.

We need to find the most stable resonance structure

According to figure,

Electronegativity of N is more than C

So, N is the more stable in fig (II).

Hence, The most stable resonance structure shown in fig (II).

The most stable resonance structure is the resonance structure in which nitrogen has a formal charge of -2.

There are molecules and ions in which a single structure does not sufficiently explain the observed properties of the molecule or ion. In such cases, bonding can not be explained in terms of one single structure, the actual structure of the compound lies somewhere between many contributing structures.

For the ion CON–, the most stable resonance structure is the resonance structure in which the nitrogen atom which is more electronegative has a formal charge of -2 and less electronegative carbon has a formal charge of -1 as shown.

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How many gallons is 240 fluid ounces

Answers

Answer:

1.875 gallons

Explanation:

How many lone pairs are there in molecule C2H2Cl2?

Answers

There are six lone pairs—that is, six nonbonding electrons associated with each chlorine atom for a total of 12 nonbonding electrons.

For the equation Fe + 6HNO₃ ⇒ Fe(NO₃)₃ + 3NO₂ + 3H₂O
21.4 gram of HNO₃ is reacted with 20.3 grams of Fe.
a. What is the limiting reactant?
b. How many grams of Fe(NO₃)₃ will form?
c. Suppose only 4.02 grams of Fe(NO₃)₃ are recovered in the above reaction. What is the percent yield of Fe(NO₃)₃ will form?

Please show your work! Thank you!!

Answers

Answer:

a = 3H²o

b = 20.3 grams

ç = (NO³)³

Answer:

a. => LR is HNO₃

b. => 13.88 grams Fe(NO₃)₃

c. => 29.1%

Explanation:

a. Limiting Reactant:

Note => Determining LR is quite simple if you'll convert all data to moles and divide each mole value by the respective coefficient. The smaller value is the limiting reactant.

Given:   Fe      +                   6HNO₃ ⇒ Fe(NO₃)₃ + 3NO₂ + 3H₂O

          20.3g                          21.4g

         = 20.3g/56g/mole     =21.4g/63g/mole

         = 0.363 mole              = 0.340 mole

Divide by coefficient 1         Divide by coefficient 6

= 0.363/1 = 0.363                  = 0.340/6 = 0.057

Since 0.057 is the smaller value then HNO₃ is the limiting reactant. However, one must use the calculated mole values when applying to equation stoichometry.

b. Grams of Fe(NO₃)₃ Produced:

Problems like this can be greatly simplified if data is 1st converted to moles and solved with respect to equation reaction ratios. Then convert mole value to needed dimension.

Fe     +   6HNO₃ ⇒ Fe(NO₃)₃ + 3NO₂ + 3H₂O

Rxn Ratio between LR and Fe(NO₃)₃ => 1:6

0.340 mole HNO₃  =>  1/6(0.340mole Fe(NO₃)₃ Produced = 0.057mole Fe(NO₃)₃ x 242 g/mole = 13.8 grams of Fe(NO₃)₃ produced

c. Percent Yield:

Given:  Fe     +   6HNO₃ ⇒ Fe(NO₃)₃ + 3NO₂ + 3H₂O

Measured Lab Yield = 4.02 grams (given in problem)

Theoretical Yield = 13.8 grams (calculated in part b)

%Yield = (Lab Yield/Theoretical Yield)100%

= (4.02/13.8)100% = 29.1% (w:w)*

*w:w means calculation was based on weight values and not volume values.

HELP ASAP PLEASE!
Why is Adam's design more favorable?
(the video is a Lab report with jeff and in the video they were doing like some design thing)

The alarm clock is dependent on sunlight


The alarm clock is dependent on wind gusts


The alarm clock is dependent on batteries

Answers

Adam's design for an alarm clock being dependent on batteries is more favorable due to the reliable and consistent power supply, convenience, portability, and the ability to replace or recharge the batteries. Option 3.

Among the given options, Adam's design for the alarm clock being dependent on batteries is more favorable compared to being dependent on sunlight or wind gusts. There are several reasons for this preference.Firstly, batteries provide a reliable and consistent source of power for the alarm clock.

Unlike sunlight, which is only available during the day and can vary depending on weather conditions and location, and wind gusts, which are unpredictable and intermittent, batteries can provide a constant power supply, ensuring that the alarm clock functions consistently and accurately.

Secondly, batteries offer convenience and portability. With a battery-dependent alarm clock, users are not limited by the need for direct exposure to sunlight or reliance on specific weather conditions. They can place the alarm clock anywhere in their room, without worrying about access to natural light or wind.

This portability allows for greater flexibility and convenience in using the alarm clock.

Additionally, batteries can be easily replaced or recharged, ensuring the long-term functionality of the alarm clock. If the batteries run out of power, users can simply replace them or recharge them, allowing the alarm clock to continue functioning without significant interruption.

In contrast, relying on sunlight or wind gusts may result in the clock not being operational when these natural energy sources are unavailable. Option 3 is correct.

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A student carried out the synthesis described in this experiment. In the first step of the synthesis, the student combined 4.987 g of Fe(NH4)2(SO4)2·6H2O with 18.14 mL of 1.1 M H2C2O4. In the second step of the synthesis, the student added 20.5 mL of saturated K2C2O4, 21.2 mL of 3% H2O2, and 9.9 mL of 1.1 M H2C2O4 to the solid FeC2O4·2H2O produced in the first step. If H2C2O4 were the limiting reagent in the first step of the reaction, how many moles of FeC2O4·2H2O(s) would be created in the first step?

Answers

Answer:

[tex]n_{ FeC_2O_4\ 2H_2O}=0.020molFeC_2O_4\ 2H_2O[/tex]

Explanation:

Hello.

In this case, since the chemical reaction for the first step is:

[tex]Fe(NH_4)_2(SO_4)_2\ 6H_2O + H_2C_2O_4 \rightarrow FeC_2O_4\ 2H_2O + H_2SO_4 + (NH_4)_2SO_4 + 4H_2O[/tex]

Whereas we can see a 1:1 molar ratio between FeC2O4·2H2O(s) and H2C2O4, thus, we compute the moles of yielded FeC2O4·2H2O(s) in the first step as shown below:

[tex]n_{ FeC_2O_4\ 2H_2O}=0.01814L*1.1\frac{molH_2C_2O_4 }{L} *\frac{1molFeC_2O_4\ 2H_2O}{1molH_2C_2O_4} \\\\n_{ FeC_2O_4\ 2H_2O}=0.020molFeC_2O_4\ 2H_2O[/tex]

Best regards.

What is bacterial pollution

Answers

it’s a pollution that is bacterial and it’s world wide infected

How will volume affect the mass of a liquid?

Answers

Answer:

it will affect the mass by changing in pressure will affect the volume (and therefore density) of gases, but will not noticeably affect the volume (or density) of solids and liquids. For gases: An increase in pressure leads to a decrease in volume and an increase in density. A decrease in pressure leads to an increase in volume and an decrease in density.

Explanation:

As the volume increases the mass of the liquid also increases as there is an increase in pressure.

What is pressure?

Pressure is defined as the force applied on an object perpendicular to it's surface per unit area over which it is distributed.Gauge pressure is a pressure which is related with the ambient pressure.

There are various units by which pressure is expressed most of which are derived units which are obtained from unit of force divided by unit of area . The SI unit of pressure is pascal .

It is a scalar quantity which is related to the vector area element with a normal force acting on it.It is distributed over solid boundaries and across arbitary sections of fluid normal to the boundaries at every point.As the pressure increases, the volume decreases as they are inversely proportional at constant temperature.

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What type of compound is Copper (1) phosphate ?

Answers

Answer:

Copper phosphide, Cu3P, also copper(I) phosphide, cuprous phosphide, cuprophosphorus and phosphor copper, is a compound of copper and phosphorus, a phosphide of copper.

Explanation:

Scenario
You have discovered the newest element to be added to the periodic table.
Element Mass
419.5 amu
Number of Protons
120 where would the new element be listed on the table(period,group, atomic number )

Answers

Answer: The element having number of protons 120 will belong to Group 2, Period 8 and has an atomic number of 120.

Explanation:

We are given:

Number of protons = 120

Atomic number is equal to the number of protons present in neutral atom.

Atomic number of element = 120

Electronic configuration of element: [tex]1s^22s^22p^63s^23p^64s^23d^{10}4p^65s^24d^{10}5p^66s^24f^{14}5d^{10}6p^67s^25f^{14}6d^{10}7p^68s^2[/tex]

Electronic configuration of element in terms of noble gas: [tex][Og]8s^2[/tex]

As, the last electron is entering in s-orbital. So, it is an s-block element and there are 2 electrons in the outermost shell. So, it will belong to Group-2.

And, the value of Principal Quantum number (n) for this element is '8'. Therefor, it will belong to Period 8.

Hence, the element having number of protons 120 will belong to Group 2, Period 8 and has an atomic number of 120.

what is a nonmetal in the same group as Pb​

Answers

Answer:

Explanation:

Helium’s

2Al+3Cl2⟶2AlCl3

How many moles of Cl2 molecules are required to react with 4.89 mol Al atoms?

Answers

Answer:

7.335 moles of  Cl₂ are required to react with 4.89 miles of Al.

Explanation:

Given data:

Moles of Al = 4.89 mol

Number of moles of Cl₂ required = ?

Solution:

Chemical equation:

2Al + 3Cl₂    →   2AlCl₃

Now we will compare the moles of Al and chlorine from balance chemical equation.

                            Al           :         Cl₂

                             2           :           3

                            4.89      :         3/2×4.89 =7.335 mol

Thus, 7.335 moles of  Cl₂ are required to react with 4.89 miles of Al.        

CH4+3CI2 ---> CHCI3+3HCI

How many grams of HCI are produced when 325 grams of CHCI3 are produced??

SHOW ALL WORK INCLUDING UNITS

Answers

When 325 grams of CHCl3 is produced, approximately 297.54 grams of HCl are also produced.

To determine the amount of HCl produced when 325 grams of CHCl3 (chloroform) is produced, we need to use the balanced chemical equation for the reaction:

CH4 + 3Cl2 -> CHCl3 + 3HCl

From the balanced equation, we can see that the stoichiometric ratio between CHCl3 and HCl is 1:3. This means that for every 1 mole of CHCl3, 3 moles of HCl are produced.

To calculate the number of moles of CHCl3, we need to divide the given mass (325 grams) by its molar mass:

Molar mass of CHCl3 = 12.01 g/mol (C) + 1.01 g/mol (H) + 3 x 35.45 g/mol (Cl) = 119.38 g/mol

Moles of CHCl3 = 325 g / 119.38 g/mol = 2.72 mol

Since the stoichiometric ratio between CHCl3 and HCl is 1:3, the number of moles of HCl produced is three times that of CHCl3:

Moles of HCl = 2.72 mol x 3 = 8.16 mol

To calculate the mass of HCl, we multiply the number of moles by its molar mass:

Molar mass of HCl = 1.01 g/mol (H) + 35.45 g/mol (Cl) = 36.46 g/mol

Mass of HCl = 8.16 mol x 36.46 g/mol = 297.54 g

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What is an alloy?
A. A metal with a changed oxidation state
B.a combination of a metal with another element
C.a layering of one metal over another metal
D. A substitution of one metal for another metal

Answers

B.a combination of a metal with another element

CHEMISTRY PLEASE HELP ILL GIVE U 20

Answers

The answer is c hope it helps

What is the net ionic equation for 2AgNO3 + 2NaOH = Ag2O + 2NaNO3 + H2O

Answers

Answer:

2Ag⁺ (aq) + 2OH⁻ (aq) → Ag₂O (s) + H₂O (l)

Explanation:

Step 1: RxN

2AgNO₃ + 2NaOH → Ag₂O + 2NaNO₃ + H₂O

Step 2: Define states of matter

2AgNO₃ (aq) + 2NaOH (aq) → Ag₂O (s) + 2NaNO₃ (aq) + H₂O (l)

Step 3: Total Ionic Equation

2Ag⁺ (aq) + 2NO₃⁻ (aq) + 2Na⁺ (aq) + 2OH⁻ (aq) → Ag₂O (s) + 2Na⁺ (aq) + 2NO₃⁻ (aq) + H₂O (l)

Step 4: Cancel out spectator ions

2Ag⁺ (aq) + 2OH⁻ (aq) → Ag₂O (s) + H₂O (l)

a solution of copper sulfate slowly evaporates beautiful blue crystals made Cu(11) and sulfate ions from such that water molecules are trapped inside the crystals. the overall formula of the compound is CuSO4•5H2O. what is the percent water in this compound?​

Answers

Answer:

36.08%

Explanation:

We are given the overall formula of the compound as: CuSO4•5H2O

Now, atomic mass of the elements are;

Cu = 63.55 g/mol

S = 32.07 g/mol

O = 16 g/mol

H20 = 18.02 g/mol

Now, let's calculate the total mass of the compound:

(63.55 g/mol) + (32.07 g/mol) + 4(16 g/mol) + 5(18.02 g /mol) = 249.72 g/mol

From the above, water in the compound is 5(H20)

Thus, total water atomic mass = 5 × 18.02 = 90.1 g/mol

Thus, percentage of water = (atomic mass of water/total mass of compound) × 100%

Percentage of water = (90.1/249.72) × 100% = 36.08%

why is it necessary to heat constant mass

Answers

Answer:

A hydrated compound loses water of crystallisation when it is heated. ... We can use difference in the mass between the hydrated and anhydrous compound to calculate the mass of water of crystallisation removed by heating. Heat to constant mass to ensure all of the water of crystallisation is removed.

Explanation:

7. Given the equations V,/T, = V2/T, where V = volume and T = temperature, what is the
value of T, if V, = 250.0L, V2 = 500.0L and T, = 725K?

Answers

Answer:

1450 k

Explanation:

We are given:

V1 = 250 mL                        V2 = 500 mL

T1 = 725k                             T2 = T

V1 / T1 = V2 / T2

Now, replacing the values:

250 / 725 = 500 / T

T = 500 * 725 / 250

T = 2 * 725

T = 1450 k

Lucy had two samples of different iron ores, haematite and magnetite.
The haematite sample weighed 5 g and contained 3.5 g of iron. The magnetite sample weighed 10 g and contained 7.2 g of iron. Which of the two iron compounds contains the larger proportion of iron? show working out.

Answers

Answer:

magnetite

Explanation:

proportion of iron in haematite = 3.5/5 x 100% = 70%

proportion of iron in magnetite = 7.2/10 x 100% = 72%

What is the balance for Fe + O2 → Fe304

Answers

Answer:

3Fe + 2O2 → Fe3O4

Explanation:

Pls, Help!!!!!!!


Element A
6 valence electrons
Gas at room temperature
Needed for blood

Element H
Noble gas
Appears as red light when charged with
electricity (Used in light signs)
Ionization energy is 2nd highest of elements

Element B
Ion has charge of +3
Is a metal
Located on Metalloid staircase

Element J
Ion has charge of 2+ and is
Isoelectronic with Neon

Element C
Ion has charge of -2
Isoelectronic with Kr

Element L
Has the smallest atomic radius of any member in the Carbon family
Element D
Ion has charge of +1
Has 2 inner core levels

Element Q
Has the largest radius and lowest ionization
the energy of any element

Element F
Member of Nitrogen family
Has 2nd high ionization energy level in family

Element R
Atomic radius is larger than Ar
Isoelectronic with Ar
Ion has charge of +2

Element G
Has 2nd to the smallest radius of 3rd period

Element S
Has atomic mass larger than the element just to the right
Found in the 5th period

Answers

Answer:

Element A = Oxygen

Element H =

Element B = Aluminum

Element J = Magnesium

Element C = Selenium

Element L = Carbon

Element D = Sodium

Element Q = Francium

Element F = Antimony

Element R = Calcium

Element G = Chlorine

Element S = Tellurium

Explanation:

Element A  is Oxygen because: oxygen 6 valence electrons ; is a gas at room temperature ; and is transported in blood to cells.

Element H  is Neon because: Neon is a noble gas ;   qppears as red light when charged with  electricity (Neon light signs)  and it has the second highest Ionization energy of the elements

Element B  is Aluminum because: Aluminum is a metal and its ion has charge of +3. It is also located on the borders of the Metalloid staircase .

Element J  is Magnesium because its ion has charge of 2+ and is  isoelectronic with Neon  because it loses two electrons to now have 10 electrons.

Element C  is Selenium because its ion that has a charge of -2  is formed by gaining two electrons in order to have 36 electrons which is isoelectronic with Kr ypton

Element L  is Carbon because carbon has the smallest atomic radius of any member in the Carbon family  because it is the first member of the family and atomic radius increases on going down the group.

Element D  is Sodium because its ion has charge of +1  and it has 2 inner core levels , the 1 and 2 energy levels.

Element Q  is Francium because it has the largest radius and lowest ionization  energy of any element

Element F  is Antimony. It is a member of Nitrogen family  and has the second highest ionization energy level in family .

Element R  is calcium because its on has charge of +2  which is isoelectronic with Argon . Calcium also has atomic radius is larger than Ar gon.

Element G  is Chlorine. It has the second to the smallest radius of elements in the 3rd period  as the second to the last element in the period because atomic radius decreases across a period from left to right.

Element S  is Tellurium. It has atomic mass larger than Iodine just to the right  of it and is found in the 5th period

The names of the elements as described are as follows;

Element A = Oxygen

Element A = OxygenElement H = Neon

Element A = OxygenElement H = NeonElement B = Aluminum

Element A = OxygenElement H = NeonElement B = AluminumElement J = Magnesium

Element A = OxygenElement H = NeonElement B = AluminumElement J = MagnesiumElement C = Selenium

Element A = OxygenElement H = NeonElement B = AluminumElement J = MagnesiumElement C = SeleniumElement L = Carbon

Element A = OxygenElement H = NeonElement B = AluminumElement J = MagnesiumElement C = SeleniumElement L = CarbonElement D = Sodium

Element A = OxygenElement H = NeonElement B = AluminumElement J = MagnesiumElement C = SeleniumElement L = CarbonElement D = SodiumElement Q = Francium

Element A = OxygenElement H = NeonElement B = AluminumElement J = MagnesiumElement C = SeleniumElement L = CarbonElement D = SodiumElement Q = FranciumElement F = Antimony

Element A = OxygenElement H = NeonElement B = AluminumElement J = MagnesiumElement C = SeleniumElement L = CarbonElement D = SodiumElement Q = FranciumElement F = AntimonyElement R = Calcium

Element A = OxygenElement H = NeonElement B = AluminumElement J = MagnesiumElement C = SeleniumElement L = CarbonElement D = SodiumElement Q = FranciumElement F = AntimonyElement R = CalciumElement G = Chlorine

Element A = OxygenElement H = NeonElement B = AluminumElement J = MagnesiumElement C = SeleniumElement L = CarbonElement D = SodiumElement Q = FranciumElement F = AntimonyElement R = CalciumElement G = ChlorineElement S = Tellurium

For Element A:

Element A is oxygen as oxygen has 6 valence electrons ; is a gas at room temperature ; and is transported in blood to cells.

For Element H:

Element H is Neon as Neon is a noble gas ; appears as red light when charged with electricity and it has the second highest Ionization energy of the elements (only second to Helium)

For Element B

Aluminum is a metal and its ion has charge of +3. Additionally, It is located on the borders of the Metalloid staircase .

For Element J

Magnesium is element J because its ion has charge of 2+ and is isoelectronic with Neon because it loses two electrons to now have 10 electrons.

For Element C:

Selenium is element C because its ion is formed by attaining an electronic state of 2- is formed by gaining 2 electrons consequently having 36 electrons which is isoelectronic with Krypton (A noble gas).

For Element L:

Carbon is element L because carbon has the smallest atomic radius compared to any member in the Carbon family.

For Element D:

Sodium is element D because its ion has charge of +1 and it has 2 inner core levels, energy levels 1 and 2.

For Element Q:

Francium is element Q because it has the largest radius and lowest ionization energy of any element

For Element F:

Antimony is element F as it is a member of Nitrogen family and has the second highest ionization energy level in the family .

For Element R:

Calcium is element R because its ion has charge of +2 which is isoelectronic with Argon . Calcium also has atomic radius is larger than Argon.

For Element G:

Chlorine is element G It has the second to the smallest radius of elements in the 3rd period (only larger than Argon) because atomic radius decreases across a period

For Element S:

Tellurium is element S as it has atomic mass larger than Iodine just to the right of it and is found in the 5th period.

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Two questions.. will give brainly

1. The force of a surface pushing back on an object is called the _____ force?
a. gravity
b. normal
c. tension
d. friction

2. the force of a rope, string, or similar object pulling on an object is called the ____ force
a. gravity
b.normal
c.tension
d. friction

Answers

Answer:

1.A 2.D

Explanation:

number 1 is gravity
number 2 is friction

A student determines the cobalt(II) content of a solution by first precipitating it as cobalt(II) hydroxide, and then decomposing the hydroxide to cobalt(II) oxide by heating. How many grams of cobalt(II) oxide should the student obtain if her solution contains 53.0 mL of 0.529 M cobalt(II) nitrate?

Answers

Answer:

Explanation:

_____ grams of cobalt(II) oxide

58:15
Suppose that scientists genetically engineered an organism that could metabolize petroleum more quickly than any
other organism. Which would be the greatest effect on society?
O People might grow the organism to use in home oil spills.
O Oil spills in the environment might be cleaned up quicker.
O More people might be hired to work in the oil drilling industry.
O Companies that make chemicals to clean up oil spills might profit.

Answers

B) Oil spills in the environment might be cleaned up quicker.

Answer:

B is the right Choice

Explanation:

3/10
The atomic mass of magnesium from the Periodic Table is
24.31 amu. What does this mass represent?
a
the arithmetic average of the two most abundant
isotopes of magnesium

Answers

Answer:

the atomic mass of magnesium from the Periodic Table is the average sum of it's three most abundant isotopes.

Explanation:

We are told that the atomic mass of magnesium from the Periodic Table is

24.31 amu.

Now, this atomic mass is simply the weighted average of the individual isotopes.

This is because the common isotopes of magnesium are 24Mg, 25Mg, and

26Mg and they are respectively 79%, 10%, and 11% in abundance. The weighted average of these 3 listed isotopes of magnesium add up to 24.3 amu.

Thus, the atomic mass of magnesium from the Periodic Table is the average sum of it's three most abundant isotopes.

Taking into account the definition of isotopes and atomic mass of an element, the atomic mass of magnesium from the Periodic Table is  24.31 amu and represent the weighted average of the individual isotopes.

In first place you must know that isotopes are atoms whose atomic nuclei have the same number of protons but different numbers of neutrons.

So, the relative atomic mass is an average of the atomic masses of the different isotopes in a sample, considering the contribution of each isotope.

This is, the atomic mass of an element is the weighted average mass of its natural isotopes. Therefore, the atomic mass of an element is not a whole number.

In summary, the atomic mass of magnesium from the Periodic Table is  24.31 amu. This mass represent the weighted average of the individual isotopes.

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1. What is the Density of an object with a mass of 46.0g and a volume of 2cc?​

Answers

Answer:

23 g/cc

Explanation:

Density = mass ÷ volume

Density = 46.0 g ÷ 2cc

= 23 g/cc

Hope that helps.

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