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at noon, ship a is 100 km west of ship b. ship a is sailing south at 35 kmh and ship b is sailing north at 25 kmh. how fast is the distance between the ships changing at 4:00 pm?
To calculate the distance between the ships by formulas.
What constitutes speed?
The speed at which a position of an object changes in any direction. Speed is defined as the ratio of distance travelled to the amount of time needed to cover that distance. Because it only has a direction and no magnitude, speed is a scalar quantity.
What is distance?
Distance is an object's overall movement, independent of direction. Distance can be described as the amount of ground that an object has covered, regardless of its starting or ending points.
Known dx/dt= 35km/h
dy/dt= 25km/h
dz/dt when x=(4.35)= 140km and
y=(4.25) = 100 km
( then =[tex]\sqrt{100^2 + 240^2}[/tex] = 260 km)
∴ 100^2 ( x+y)^2 = Z²
0+∂(x+y)(dx/dt+dy/dt)=∂z(dz/dt)
=∂(140+100)(35+25)=∂(260)(dz/dt)
dz/dt= 55.4km/h
Therefore, the distance between the ships is55.4km/h.
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A lorry travels 10km northwards, 4km eastwards, 6km southwards and 4km westwards to arrive at point T. What is the total displacement?
a 0.165 kg mass is attached to a spring and undergoes simple harmonic motion with a period of 0.95 s. the total energy of the system is 3.1 j. find the amplitude of the motion. answer in units of m.
The amplitude of the motion is 0.608.The amplitude of a particle is its maximum departure from its equilibrium position or mean position, and its direction is always in the opposite direction.
What is the amplitude of the motion?The amplitude of a particle is its maximum departure from its equilibrium position or mean position, and its direction is always in the opposite direction. Its dimensions are [L1M0 T0] and its S.I. unit is the meter.
It alludes to the greatest departure from equilibrium that an object in periodic motion can exhibit. As an illustration, consider how a pendulum moves through its equilibrium point (straight down) and then moves outward to its maximum distance.
The motion's angular frequency is
W=2[tex]\pi[/tex]/T
=2[tex]\pi[/tex]/0.95
=6.61
w=√k/m on a spring for a mass. Rearranging this formula results in
k=wm²=0.165×6.61×6.61=7.209 N/m
A system performing simple harmonic motion has a total energy of
E=a²k÷2 .Rearranging this formula results in
a=√2E÷k=√2×3.1÷7.209
=0.608 m
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Can a spectrophotometer be used to measure the absorption of a particular wavelength of light that is not visible to the human eye?.
Yes, a spectrophotometer can be used to measure the absorption of a particular wavelength of light that is not visible to a normal human eye.
Even though we can't directly perceive this light's absorption, it can be quantified. We may calculate concentration by using a spectrophotometer, which detects the absorption of light at particular wavelengths (whether visible or not) by a solution. The number of chemicals in a solution or the amount of light absorption may be measured using the common and affordable method of spectrophotometry.
Each substance in the solution either absorbs or transmits light over a certain wavelength when a light beam is directed through the sample. Combining them with colored derivatives that are visible and measurable. Another is that colorless substances typically absorb light from the part of the spectrum that is invisible to the unaided eye, as measured by a spectrophotometer.
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After energy conversions, you end up with the same total amount of energy as the original amount energy. Which law explains this rule?.
You end up with the same overall amount of energy as you did before energy conversions were made. The law of conservation of energy provides an explanation for this.
What is law of conservation of energy?Energy cannot be created or destroyed; instead, it can only be changed from one type of energy to another, according to the principle of energy conservation. This is especially puzzling in the case of non-conservative forces, where energy is converted from mechanical to thermal but the total amount of energy remains constant. To be used, energy must be transformed from one form to another.
Therefore, the equation U[tex]_{T}[/tex]=U[tex]_{i}[/tex]+W+Q determines the amount of energy in any system.
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mountain goats can easily scale slopes angled at from horizontal. what are the normal force and the static friction force acting on a mountain goat that weighs 900 n and is standing on such a slope?
Using these formulas, determine the normal and static friction forces acting on the mountain goat.
What is normal force?
The normal force is the pressure that surfaces apply to stop solid objects from piercing one another. The normal force is a force in contact. Two surfaces cannot exert a normal force on one another if they are not in contact.
What exactly is static friction force?
An object experiences static friction when a force is applied to it; as a result, the object resists the applied force and stays at rest until static friction is removed. In kinetic friction, the frictional force opposes an object's motion.
Given:
The 60° angle from horizontal
900 N is the weight of the mountain goat.
To calculate the normal force, the weight perpendicular to the tilt must be resolved. As a result, we can write:
N = W CosΘ
= 900 N(Cos 60°)
= 900 N(0.5) (0.5)
= 450 N
The forces acting in conjunction with the inclination must all be added to determine the static friction force. We document:
F = W sinΘ
= 900 N(sin 60°)
= 900 N(0.8660254038) (0.8660254038)
= 779.42 N
Therefore, the normal force is 450 N, and the static friction force is 779.42 N.
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facts about the immune system
The immune system is a complex network of organs, cells, and proteins that protect the body's own cells while defending it against infection.
The immune system keeps a record of every germ (microbe) it has ever defeated in order to quickly recognize and destroy the microbe if it re-enters the body.
The immune system, unlike the heart or the brain, does not have a centralized location in the body. Instead, immune system cells are produced in organs throughout the body, including the tonsils, lymph nodes, spleen, bone marrow, and adenoids.
Our immune system also weakens with age, as immune system tissues shrink and our white blood cell count and activity decrease.
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Adhere to the images given:
The reason for the first graph is because of the effects of deceleration and acceleration due to gravity while the arrangements of the graphs are; B> D > A> C.
What is the position- time graph?When we plot a graph, the graph would always have to axes; the vertical axis and the horizontal axis. In this case, the vertical axis is the position and the horizontal axis is the time. The slope of this graph speaks of the displacement of the object.
Looking at the first graph, we can see that it can be able to show the motion of an object that went up and fell down as the speed of the object would decrease during the upward motion as it is decelerated due to gravity and comes to a halt at the maximum height before it is accelerated as it moves downwards.
From the graphs, the ranking of the displacements for the second set of graphs as; B> D > A> C. This is because there is a positive slope in B and D while the slope in A is zero and that in C is negative.
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How does the amount of work trevor performs going to the corner compare with the amount of work he performs coming back? they are the same because he uses the same amount of force. they are the same because he travels the same distance. he does less work coming back because the force moving the wagon is only 50cos30°. he does more work coming back because the force moving the wagon is only 50cos60°.
Answer:C) he does less work coming back because the force moving the wagon is only 50cos30
Explanation: got it right on edge
The amount of work Trevor performs going to the corner compared with the amount of work he performs coming back is that he does less work coming back because the force moving the wagon is only 50cos30°
Since the formula, we refer to for calculating the work, when the angle is applied is:
Wₓ = W cos θ, where for the case the θ is 30 and W is 50
Since the force done is parallel to the motion's direction, and the work has a larger magnitude, the work done in order of pulling the wagon back to the starting point is less than the work done in pulling the wagon to the corner, as the reason is for the angle of 30 degrees in pulling it back
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A source vibrating at constant frequency generates a sinusoidal wave on a string under constant tension. If the power delivered to the string is quadrupled, by what factor does the amplitude change?.
When the amplitude varies, it means twice as much.
Which instances of sinusoidal waves are there?Simple harmonic motion, such the swinging of a pendulum or the weight of a weight on a spring, produces a sinusoidal relationship between position and time. Sound and water waves, for example, can be visualized as sinusoids.
Given:
if the string is given four times as much power.
According to the power that a sinusoidal wave on a stretched string transmits,
P =[tex]\frac{1}{2}[/tex] μω^A^2v
Where μ=mass per unit length, w= angular speed, A= amplitude, v= wave speed, P= power delivered.
P ∝[tex]A^{2}[/tex]
Here, the only terms we need are power and amplitude.
A =K[tex]\sqrt{P}[/tex]
Where K is constant
Here, "power become quadruple" refers to four,
A = [tex]\sqrt{4P}[/tex]
A =2 [tex]\sqrt{P}[/tex]
Therefore, an increase in amplitude by a factor of two is equivalent to a twofold increase.
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What is the normal force on an object weighing 437N at rest on an inclined plane with an angle of 29 degrees?
Answer:408
Explanation:
Answer:
382.2 N
Explanation:
You want the normal force on an object weighing 437 N situated on an inclined plane 29° from the horizontal.
Force vectorThe vector 437 N straight down can be decomposed to vectors parallel to the plane and perpendicular to the plane. That decomposition looks like ...
(perpendicular, parallel) = 437 N · (cos(29°), sin(29°)) ≈ (382.2, 211.9) N
The normal force on the object is about 382.2 N.
an empty beaker is weighed and found to have a mass of 130g. a measuring cylinder contains 50cm3 of an unknown liquid. all the liquid is poured into the beaker which is again weighed and found to have a mass of 170 g. calculate the density of the liquid. pleasee with explanation)
Answer:
0.8 g/cm^3
Explanation:
mass of liquid = mass of beaker + liquid - mass of beaker
= 170g -130g = 40 g
density = mass/ volume
therefore:
density of volume = [tex]\frac{40g}{50cm^3} = 0.8 g/cm^3[/tex]
where need be for 3 significant figure or 2 decimal place, just add zeros at the back of the 8
specular reflection obeys the laws of reflection while diffuse reflection does not. question 18 options: true false
False, In contrast to diffuse reflection, specular reflection violates the laws of reflection. Normal reflections are parallel to the surface of a flat mirror. The law of reflection only applies to flat surfaces. Convex mirrors serve as passenger door mirrors in cars.
The law of reflection states that the angle of incidence & angle of reflection is identical. A smooth finish causes a specular reflection of light. Since incident rays are parallel, reflected rays must also be parallel. Light striking a rough surface causes diffuse reflection.
The two principles governing specular reflection are,
1. At the point of incidence, the incidence angle, the reflected ray, as well as the normal towards the reflecting interface all lie in the very same plane.
2. The angle of incidence and reflection are equal.
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Click to review the online content. Then answer the question(s) below, using complete sentences. Scroll down to view additional questions.
Online Content: Site 1
Fitness Log
What steps can you take in your everyday life to properly care for your skeletal system? (Site 1)
Incorporating physical activity into your everyday routine is one approach to care for your skeletal system.
Walking, running, and climbing stairs are all weight-bearing workouts that can help you grow strong bones and reduce bone loss. Substance misuse should be avoided.
What is the skeletal system?The human skeleton is the body's internal framework. It is made up of around 270 bones at birth, which lowers to approximately 206 bones by adulthood as certain bones fuse together.
It is to be noted that the skeleton's bone mass accounts for around 14% of total body weight and achieves maximal density around the age of 21.
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A heat engine operates between a source at 477°c and a sink at 25°c. If heat is supplied to the heat engine at a steady rate of 65,000 kj/min, determine the maximum power output of this heat engine.
T[tex]_{C}[/tex] = 25 + 273.15 = 298.15K
T[tex]_{H}[/tex] = 477 + 273.15 = 750.15K
And by replacing Carnot efficiency:
e = 1 - [tex]\frac{298.15}{750.15}[/tex] = 0.39475 = 39.47%
W[tex]_{max}[/tex] = e × Q[tex]_{H}[/tex] = 0.39475 × 65000[tex]\frac{KJ}{min}[/tex] = 25658.75 [tex]\frac{KJ}{min}[/tex]
How to calculate temperature?The United States (and its connected territories) and some Caribbean countries frequently use the Fahrenheit temperature scale, which bears the name of German physicist Daniel Gabriel Fahrenheit. Water freezes at 32°F and boils at 212°F according to the Fahrenheit scale (at sea level).
Nearly every other country uses the Celsius temperature scale, which was previously called centigrade before being changed for Swedish astronomer Anders Celsius. Water freezes at 0°C and boils at 100°C on the Celsius scale (at sea level).
For this case we can use the fact that the maximum thermal efficiency for a heat engine between two temperatures are given by the Carnot efficiency:
e = 1 - frac T[tex]_{C}[/tex]T[tex]_{H}[/tex]
We have on this case after convert the temperatures in kelvin this:
T[tex]_{C}[/tex] = 25 + 273.15 = 298.15K
T[tex]_{H}[/tex] = 477 + 273.15 = 750.15K
And replacing in the Carnot efficiency we got :
e = 1 - [tex]\frac{298.15}{750.15}[/tex] = 0.39475 = 39.47%
And the maximum power output on this case would be defined as:
W[tex]_{max}[/tex] = e × Q[tex]_{H}[/tex] = 0.39475 × 65000[tex]\frac{KJ}{min}[/tex] = 25658.75 [tex]\frac{KJ}{min}[/tex]
Where [tex]Q_{H}[/tex] represent the heat associated to the deposit with higher temperature
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when a variable force is applied to an object, it travels a distance of 5 m. the total work done on the object is given by
50 Newton is the total work done on the object.
d=5 cm
F= 10 N
work done=Fd
work done=5×10
work done=50 N
When moving an object over a distance, an external force must direct at least a portion of its force in the direction of the displacement. This is referred to as work done in physics. If the force acting along the path is constant, the amount of work can be calculated by multiplying the length of the path by the force's component. The work W is equal to the force f times the distance h to express this idea mathematically, or W = mgh. The work is W = mas if the force is applied at an angle to the displacement.
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A child whose weight is 350 N swings out
over a pool of water using a rope attached
to the branch of a tree at the edge of the
pool. The branch is 10.2 m above ground
level and the surface of the water is 1.79 m
below ground level. The child holds on to a
rope of length 7.2 m attached to the branch
and moves back until the angle between the
rope and the vertical is 12◦. When the rope is
in the vertical position, the child lets go and
drops into the pool. The acceleration due to gravity is 9.81 m/s^2
Find the speed of the child at the surface of
the water.
Answer in units of m/s.
The speed of this child from this surface would be 14.69 m / s
How to solve for the speedWe have the formula for energy conservation as:
E - potential = E - kinetic
We have the following details with which we are to solve the problem
weight of child w = 350 N
length of rope L = 7.2m
angle θ = 12 degrees
we would have the solution as
m x 9.8m/s² x (10.2 + 1.79 - 7.2 x cos 12) = 1/2 mv²
we would have to solve out the expression that we have above. Such that :
9.8m * (11.99 - 0.9781) = 1/2 mv²
107.9 m = 1/2 mv²
cancel out m
107.9 = 0.5v²
divide through by 0.5
107.9 / 0.5 = v²
215.8 = v²
v = √215.8
v = 14.69
Hence the speed of the child at the surface of the water would be given as 14.69 m / s
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a golf ball of mass 45.93 g has a velocity of 74.22 m/s immediately after being struck. if the club and ball were have an average contact force of 8896 n, how long does the contact last?
The time for that contact force is 0.00038 s.
An impulse is a surprising pressure or choice — this will be an electrical impulse or an impulse to get a few pizzas. if you act on an unexpected feeling or concept, you're following an impulse. it's like a whim: an impulse is not something you have given quite a few concepts. The impulse of pressure is the product of the resultant pressure ΣF and the length of this force Δt if the pressure is constant. The impulse of pressure is the purpose of changes to movement and consequently changes to momentum.
Momentum is a vector amount that has an equal path to the velocity of the item. the amount of force accelerated by the time it's far implemented is called impulse. Impulse is a vector quantity that has an equal path to the pressure. Momentum and impulse have equal gadgets: kg·m/s
Calculation:-
mass = 45.93 g = 0.046 kg
velocity = 74.22 m/s
Impulse = Change in Momentum
Ft = mv
t = 0.046 × 74.22 / 8896
= 6455.696 N
= 3.8 × 10⁻⁴ Sec
Therefore, the time for that contact force is 0.00038 s.
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According to the first law of thermodynamics, work done by a system will cause _________ in the internal energy, assuming that no heat is transferred to or from the system.
According to the first law of thermodynamics, work done by a system will cause decrease in the internal energy, assuming that no heat is transferred to or from the system.
First law of thermodynamics says that energy can neither be created nor it can be destroyed, it can only be transferred from one form to another form. This is also a law of conservation of energy.
It means if there is any work done by any system then that system has burned its energy to do the work. so when energy is used to do the work , there will be decrease in the internal energy of the system, and that will be equal to the workdone.
ΔU = ΔW
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a 2.0-kg object is moving without friction along the x-axis. the potential energy curve as a function of position is shown in the figure, and the system is conservative. if the speed of the object at the origin is 4.0 m/s, what will be its speed at 7.0 m along the x-axis?
The speed at 7.0 m along the x-axis is 4.24 m/s.
Which speed is it?the rate at which the location of an object changes in any direction. The ratio of distance traveled to the time required to travel that distance is known as speed. Considering that speed only has a direction and no magnitude.
given,
speed of the object at origin = 4 m/s
potential energy at origin = 10 J
mass of the object = 2 kg
potential energy at 7 m = 8 J
since the system is conservative so it'll follow the conservation of energy
that is,
initial energy = final energy
kinetic energy = 0.5 ×m× v²
initial potential energy + initial kinetic energy = final potential energy + final kinetic
energy
10+ 0.5 × 2 × 4² = 8 + 0.5 × 2 × v²
v = 4.24 m/s
speed at 7m = 4.24 m/s.
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Two students are pushing a broken-down car. One student is pushing with a force of 200 N. If there is 350 N of frictional force acting against them, how hard must the second student push to cause the car to accelerate?
The second student must push with a force greater than 150 N to cause the car to accelerate.
What is the net force on the car?
The net force on the car is the sum of all the forces acting on the car. The direction of the net force on the car will determine the direction of motion of the car.
According to Newton's second law of motion, the force applied to an object is directly proportional to the product of mass and acceleration of the object.
The net force on the car is calculated as follows;
F(net) = F - Ff
ma = F - Ff
where;
a is the acceleration of the carm is the mass of the carF is the applied force on the carFf is the force of friction resisting the motion of the carFor the car to move, sum of the applied forces must be greater than the force of friction.
200 + F > 350
F > 350 - 200
F > 150
Thus, the second student must push with a force greater than 150 N before the car can accelerate.
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Draw your model to show what happens during the time when a balloon is being rubbed on a girl’s hair.
The electrons are transferred from hair to balloon when a balloon is being rubbed on a girl’s hair and attains a negative charge.
What happens when a balloon is rubbed with hair?Rubbing the balloon against the hair leads to the transfer of electrons from the hair to the balloon because electrons are negatively charged, the balloon attains a negative charge, while on the other hand, the hair with the loss of negative charges gets a net positive charge. Static electricity occurs due to an imbalance between negative charges and positive charges in a body. These charges can build up on the surface of a body until they find a path to be released or discharged. Static electricity is produced when positive and negative charges are not in a balanced situation. Protons and neutrons don't move around but electrons jump from one place to another place. When an object has more electrons than protons, it has a negative charge.
So we can conclude that when a balloon is being rubbed on a girl’s hair, the electrons are transferred from hair to balloon.
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1 5kg cat is lifted 2 m into the air.how much gpe does it gain?
Answer:
Potential Energy= mgh = (5)(9.8)(2)= 98.i want help plase
?????????????????
a ) When they reach the ground, rock B has greater velocity.
b ) Both rocks have the same acceleration
c ) Rock A and Rock B arrives at the same time
According to law of conservation of energy,
1 / 2 m u² + m g hi = 1 / 2 m v² + m g hf
u = 0
hf = 0
m g hi = 1 / 2 m v²
v = √ ( 2 g / m ) √ hi
v ∝ √ hi
a ) hi of rock A will be higher because it reaches a certain height above the ground which will be considered as initial height for rock A. So, the final velocity of rock A is higher.
b ) Both the rock are affected by only the force of gravity. So they will have the same acceleration of 9.8 m / s²
c ) If air resistance is ignored,
s = u t + 1 / 2 at²
For an object that is dropped,
u = 0
a = g
s = at² / 2
t = √ ( 2 s / g )
It can clearly be seen that no matter what height an object might be dropped from, if air resistance is ignore they will fall at the same time.
Therefore,
a ) When they reach the ground, rock B has greater velocity.
b ) Both rocks have the same acceleration
c ) Rock A and Rock B arrives at the same time
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4. at a distance of 7 x 1012 m from a star, the intensity of the radiation from the star is 15.4 w/m2. assuming that the star radiates uniformly in all directions, what is the total power output of the star?
If the star radiates uniformly in all directions, the total power output of the star is 2.37 x 10²⁷ W.
The formula for the intensity of the light at a distance R from the source of light (which is star in this case) is given by,
I = P/A
I is the intensity,
P is the power,
A is the area.
We can write,
P = IA
Intensity is given to be 15.4 W/m².
A = πR²
Here, we will take the value of R is 7 x 10¹² m.
So,
A = π( 7 x 10¹²)²
Putting the values,
P = IA
P = 15.4 x π x ( 7 x 10¹²)²
P = 2.37 x 10²⁷ W.
The power output of the star is 2.37 x 10²⁷ W.
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In Figure 4.7, the net external force on the 24-kg mower is stated to be 51 N. If the force of friction opposing the motion is 24 N, what force F (in newtons) is the person exerting on the mower? Suppose the mower is moving at 1.5 m/s when the force F is removed. How far will the mower go before stopping?
The force (F) exerted on the mower of mass 24 kg is 2.125 N and The distance the mower will travel when before it stopping when F is removed is 0.53m.
What is force?Force can be defined as the product of mass and acceleration.
To calculate the force the person is exerting on the mower, we use the formula below.
Formula:
F = F'+f......... Equation 1Where:
F = Net external force on the mowerf = Force of frictionFrom the question,
Given:
F' = 51 Nf = 24 NSubstitute these values into equation 1
F = 51+24F = 75 NAlso, To calculate the distance the mower will move before stopping, We need to first find the acceleration of the mower using the formula below.
Formula:
a = F/m................. Equation 2Where:
F = Net external force of the mowerm = Mass of the mowera = Acceleration of the mowerFrom the question,
Given:
F = 51 Nm = 24 kgSubstitute these values into equation 2
a = 51/24a = 2.125 m/s²Finally, we use the formula below to calculate the total distance the mower will travel before stopping
Formula:
s = (v²-u²)/2a......... Equation 3Where:
s = Total distancev = Final velocityu = Initial velocityFrom the question,
Given:
v = 1.5 m/su = 0 m/sSubstitute these values into equation 3
s = (1.5²-0²)/(2×2.125)s = 0.53 mHence, the force exerted on the mower is 2.125 N and the distance the mower will travel before it stops is 0.53m.
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what is physical properties of matter
Answer:
A quality of matter that is unrelated to a change in its chemical makeup is called a physical property.
Examples of physical properties of matter:
DensityColorHardnessMelting PointBoiling PointElectrical ConductivityPhysical properties are any qualities of matter that may be felt or seen without changing the sample's chemical composition.
Due to the wide range of features that make up physical attributes, they are further separated into intensive and extensive as well as isotropic and anisotropic categories.
Any characteristic that can be recognized and measured by sight, hearing, touch, smell, or other senses without evoking a chemical reaction is referred to as a physical property. Examples of physical traits are:
Color, Shape, Volume, Density, Calorific value, Boiling point, Viscosity, Pressure, Solubility, electrical current
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a 39-kg crate rests on a horizontal floor, and a 68-kg person is standing on the crate. (a) determine the magnitude of the normal force that the floor exerts on the crate. n (b) determine the magnitude of the normal force that the crate exerts on the person.
The floor normally presses down on the carton with a force of 1049.67N.
The box normally applies 667.08 N of force to the person.
What do you mean by normal reaction force?A perpendicular force that acts on two surfaces that are touching. It stands in for the pressure pressing the two surfaces together. With the size of the usual response force, the value of limiting friction grows. If the weight is the only vertical force acting on an object that is lying or moving on a horizontal surface, While acting in the opposite direction from the weight, the normal response force is of identical size. Raising the weight results in increased friction.
Given,
The crate's mass, mp=68kg, is maintained on a horizontal floor.
mc=39kg is the mass of the guy standing above the crate.
(a) determine the normal force the floor applies to the crate:
N =(mc+mp)g
N =(39kg+68kg)×9.81m/s²
N = 1049.67kg⋅m/s² [tex]\frac{1N}{1Kg.m/s^{2} }[/tex]
N = 1049.67N
∴ The floor normally presses down on the carton with a force of 1049.67N.
(b) determine the typical force the crate would apply to the person:
N = mp g
N = 68kg×9.81m/s²
N = 667.08m/s² [tex]\frac{1N}{1Kg.m/s^{2} }[/tex]
N = 667.08 N
∴ The box normally exerts 667.08 N of force on the person.
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a thermodynamic cycle is shown for an ideal gas in a piston. the system changes state from abca. a) what is the total work done by the gas during this cycle?
The total work done by the gas during this cycle is A −40J.
For process 2→3 (volume constant)
Q=−40 J
W=0 (As V is constant)
ΔU=Q=−40
U3−U2=−40 (i)
For process 1→2 (temperature constant)
T1=T2
U1=U2 (ii)
From (i) & (ii)
U3−U1=−40
ΔU3→1=40 J
For process 3→1 (Adiabatic process)
W=−ΔU
W=−40J
A thermodynamic cycle comprises of a connected grouping of thermodynamic forms that include the exchange of warm and work into and out of the framework.
Whereas changing weight, temperature, and other state factors inside the framework, inevitably returns the framework to its introductory state.
The thermodynamic cycles are exceptionally fundamental for the control-creating frameworks (such as petrol motors, diesel motors, gas turbines, etc.).
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an object is 16.0cm from a concave mirror whose focal length is 10.0cm. (a) how far is the image from the mirror? answer: cm (b) what is the magnification? include any sign answer: (c) is the image real or virtual? answer: (d) is the image upright or inverted? answer:
The distance of the image is 26.67 cm
The magnification is -1.67
The image is real
The image is inverted
The focal length of the concave mirror = 10 cm
The distance of the object from the concave mirror = 16 cm
The distance of the image can be found using the formula1/p + 1/q = 1/f
where p is the distance of the object
q is the distance of the image
f is the focal length
1/q = 1/f - 1/p
1/q = (p - f)/fp
q = fp / (p - f)
q = 16 x 10 / ( 16 - 10)
= 160 / 6
= 26.67 cm
The distance of the image from the concave mirror is 26.67 cm
The magnification of the concave mirror can be found usingM = -q/p
where M is the magnification
M = -26.67 / 16
= -1.67
The distance of the image is positive, so the image is realThe magnification value is negative, so the image is inverted.Learn more about the concave mirror is
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