Which combination of cellular junctions is most similar to each other?
A. Tight junction & Desmosomes
B. Tight junctions & Gap junctions
C. Tight junctions & Plasmodesmata
D. Gap junctions & Desmosomes
E. Gap junctions & Plasmodesmata

Answers

Answer 1

Option E: Plasmodesmata and gap junctions are the two junctions that form a combination of cellular junctions most similar to each other.

Gap junctions are present in animals while plasmodesmata are the cellular junctions present in plants. Both of their functions are to facilitate the transport of materials within the cells or to the extracellular matrix. Thus, they are similar in functions.

Animal cells can cling to one another or to the extracellular matrix thanks to connections called cellular junctions. Similar cell connections, known as plasmodesmata, also exist in plants. The plasmodesmata, which create pores between cells, enable the movement of genetic material, water, nutrients, and signaling molecules. There are four primary types of cell junctions in animals: gap junctions, adhesion, desmosomes, and tight junctions.

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Related Questions

18. Amorphophallus johnsonii is a plant growing in West Africa, and it is better known as a "corpse-flower." Its common name comes from the fact that when it flowers, it gives off a "powerful aroma of rotting fish and faeces." The flowers smell this way because their principal pollinators are carrion beetles, who are attracted to such a smell. Beath observed the number of carrion beetles (Phaeochrous amplus) that arrive per night to flowers of this species. The data are as follows: 51, 45, 61, 76, 11, 117, 7, 132, 52, 149 a. What is the mean and standard deviation of beetles per flower? b. What is the standard error of this estimate of the mean? c. Give an approximate 95% confidence interval of the mean. Provide lower and upper limits. d. If you had been given 25 data points instead of 10, would you expect the mean to be greater, less than, or about the same as the mean of this sample? e. If you had been given 25 data points instead of 10, would you have expected the standard deviation to be greater, less than, or about the same as this sample? f. If you had been given 25 data points instead of 10, would you have expected the standard error to be greater, less than, or about the same as this sample?

Answers

The mean number of beetles per flower is 65.3, and the standard deviation is 44.8. The standard error of the estimate of the mean is 14.2, which is calculated as the standard deviation divided by the square root of the sample size.

The 95% confidence interval of the mean is approximately 35.9 to 94.7 beetles per flower using the formula: mean ± (t-value x standard error), where the t-value for a 95% confidence interval with 9 degrees of freedom is 2.31.

With 25 data points, we would expect the mean to be about the same as the mean of this sample, standard deviation to be about the same as this sample and standard error to be less than this sample, as increasing the sample size decreases the standard error.

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Pls help me !!

This is the question :

Write the key biology term into the correct box
1. The difference between alleles
2. one chromosome consisting of a circular DNA molecule.
3. nuclei with one chromosome of each pair.
4. a characteristic feature of members of a species
5. the whole of the genetic information of an organism.

Answers

Answer:

1. Heterozygous

2. Prokaryotes
3. Haploid Nuclei

4. Feature

5. Genome

Explanation:

Suppose that volcanic activity in northern California should become violent and completely destroy all the salamanders in that region. How would this event affect the species Ensatina?

Answers

If volcanic activity in northern California were to become violent and completely destroy all the salamanders in that region, it would have a significant impact on the species Ensatina.

First, the loss of salamanders would reduce the population size of Ensatina, which could lead to a decrease in genetic diversity within the species. This could make the species more vulnerable to environmental changes and potentially lead to a decline in population numbers.

Second, the loss of salamanders could also disrupt the food chain in the region. Salamanders are an important part of the ecosystem, serving as both prey and predators. Without them, other species that rely on salamanders for food may also be affected, potentially leading to further declines in population numbers.

Overall, the loss of salamanders in northern California due to volcanic activity would have a significant impact on the species Ensatina and could potentially lead to a decline in population numbers and a decrease in genetic diversity within the species.

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Find the x- and y-intercepts of the graph of 2x−5y=40. State each answer as an integer or an improper fraction in simplest form.

Answers

Note that the x-intercept is (20, 0) and the y-intercept is (0, -8).

What is the rationale for the above response?

To find the x-intercept, we set y to 0 and solve for x:

2x - 5(0) = 40

2x = 40

x = 20

Therefore, the x-intercept is (20, 0).

To find the y-intercept, we set x to 0 and solve for y:

2(0) - 5y = 40

-5y = 40

y = -8

Therefore, the y-intercept is (0, -8).

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2. What must evolutionists never consider?

Answers

Answer:

Evolution is unscientific because it is not testable or falsifiable. It makes claims about events that were not observed and can never be re-created. This blanket dismissal of evolution ignores important distinctions that divide the field into at least two broad areas: microevolution and macroevolution. Microevolution looks at changes within species over time—changes that may be preludes to speciation, the origin of new species. Macroevolution studies how taxonomic groups above the level of species change. Its evidence draws frequently from the fossil record and DNA comparisons to reconstruct how various organisms may be related.

Evolution is not science because it is not observable or testable. Evolution is 'just' a theory. Evolutionary theory is invalid because it is incomplete and cannot give a total explanation for the biodiversity we see around us. Gaps in the fossil record disprove evolution.

identify what syndrome and/or chromosomal mutation the individual with this karyotype exhibits.

Answers

This individual has an XXY karyotype, which is known as Klinefelter Syndrome.

It is caused by a chromosomal mutation where the individual has an extra X chromosome.This individual has a XYY karyotype and is most likely exhibiting the XYY Syndrome.A chromosome is a long, thread-like structure made up of DNA, which contains genetic information. It is found in nearly every cell of the human body and is responsible for the transfer of genetic instructions from parents to their children. This is a chromosomal mutation that results in an extra Y chromosome in males. It is associated with an increased risk of learning disabilities, delayed development, and behavioral problems.

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complete question:Identify what syndrome and/or chromosomal mutation the individual with this karyotype exhibits.

X X Y

For mutations to affect the gene pool of a future population, they must

Answers

Answer:

For mutations to affect the gene pool of a future population, they must be heritable, meaning that they must be passed down from parent to offspring. This is because the gene pool of a population consists of all the genetic variations present in the individuals within that population. If a mutation occurs in an individual but is not heritable, meaning that it does not get passed down to their offspring, then it will not affect the gene pool of the population.

is it possible to record a wavelenght for white light and dark? why or why not?

Answers

It is not possible to record the wavelength for white light or dark because the white light is a combinations of various wavelengths whereas in dark, no wavelength exists.

Wavelength is the distance between the two adjacent crests or troughs of a wave of light propagated from a source. The wavelength can be measured in various units of distance like meter, centimeter, nanometer, etc.

White light is the collection of all the wavelengths of light of the visible spectrum occurring naturally or artificially. The wavelength of white light ranges from 380 nm to 700 nm. The white light actually has 7 colors (violet, indigo, blue, green, yellow, orange, and red).

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4. Which genus/species had the largest maxillary prognathism? 5. How is the presence or absence of a sagittal crest related to the size of the space created between the zygomatic arch and the post-orbital constriction?

Answers

(4) The genus/species that had the largest maxillary prognathism is the Paranthropus boisei.

(5) The size of the space created between the zygomatic arch and the post-orbital constriction is directly proportional to sagittal crests.

The species Paranthropus boisei had a very prominent jaw and large teeth, which is thought to have been an adaptation for eating tough, fibrous foods.

The presence or absence of a sagittal crest is related to the size of the space created between the zygomatic arch and the post-orbital constriction because the sagittal crest is a bony ridge that runs along the top of the skull and is used for the attachment of large jaw muscles. The larger the space between the zygomatic arch and the post-orbital constriction, the larger the jaw muscles can be, and therefore the larger the sagittal crest can be.

This is why species with larger sagittal crests, such as the Paranthropus boisei, also have larger spaces between the zygomatic arch and the post-orbital constriction.

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Help me answer the question please. I need a thorough explanation!

Answers

Answer:

Added sugars are sugar carbs added to food and beverages before consumption. These include added carbohydrates and more broadly,sugars naturally present in homey syrup and fruits.

Which plasma membrane component provides mechanical strength and maintains the correct amount for rigidity and flexibility?
A) cholesterol
B) triglycerides
C) insulin
D)protein

Answers

The correct answer is A) cholesterol.

Cholesterol is a crucial component of the plasma membrane that provides mechanical strength and maintains the correct amount of rigidity and flexibility. Cholesterol molecules are inserted between the phospholipids in the plasma membrane and help to regulate the fluidity of the membrane. This is important because it allows the membrane to maintain its structure and function properly. Without cholesterol, the plasma membrane would be too fluid and would not be able to maintain its shape or protect the cell.

In contrast, triglycerides (B) are a type of fat that is stored in the body for energy, insulin (C) is a hormone that regulates blood sugar levels, and proteins (D) are a type of macromolecule that performs a wide variety of functions in the cell, including structural support, enzymatic activity, and signaling.
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what is obesity?
ans

please add me in brinly​

Answers

Answer: Obesity is when you are very fat or overweight

Explanation:

Obesity is where you are overweight

What might happen if some of the randomly sampled people in Atlanta refuse to have their blood drawn for this CDC study? Will that affect the sample's generalizability? Why or why not?

Answers

If some of the randomly sampled people in Atlanta refuse to have their blood drawn for the CDC study, it could potentially affect the sample's generalizability. This is because the sample may no longer be representative of the population as a whole. When people refuse to participate in a study, it can create a selection bias, meaning that the sample is not truly random and may not accurately represent the population.

This can affect the generalizability of the study because the results may not be applicable to the entire population. To avoid this issue, researchers may need to increase the sample size or use different sampling methods to ensure that the sample is representative of the population.

Overall, it is important for researchers to consider potential biases and take steps to minimize their impact on the generalizability of the study.

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SOMEONE PLEASE HELPPP!!!!! ( THERE ARE 2 PICTURES)

Answers

Second Weathering Process: Physical weathering through freeze-thaw cycles

Evidence source: Text and Image

Describe Evidence: The text mentions how water seeps into cracks, freezes, and expands, leading to the breaking of rocks. The image shows cracks and fractures on the cliff surface. See attached image.

What is the rationale for the above response?

The response identifies two weathering processes that contribute to the formation of cliffs, namely underground water dissolving rocks and minerals, and physical weathering through freeze-thaw cycles.

The evidence for the second process is drawn from the text, which describes how water seeping into cracks, freezing and expanding can cause rocks to break. The image provided also shows evidence of cracks and fractures on the cliff surface, which further supports the presence of physical weathering.

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The boxer crab, lybia tesselata, carries a small pair of anemones in its claws. when approached by a predator, it waves the anemones around, presenting the stinging tentacles and chasing away the predator. the anemones benefit by eating food particles from prey that the crab catches. what type of relationship is this? a. commensalism b. mutualism c. parasitism d. predation

Answers

Mutualism. When two organisms of different species "operate together," they are said to be in a mutualistic relationship. The oxpecker, a species of bird, and the rhinoceros or zebra are two examples of mutualistic relationships.

Oxpeckers land on rhinos or zebras and consume ticks and other parasites that dwell on their skin. The oxpeckers receive food, and the animals are protected from pests. Also, the oxpeckers fly higher and cry a warning when there is danger, aiding the symbionts.

The algae and the spider crab. Spider crabs inhabit shallow sections of the ocean floor, and their greenish-brown algae-covered backs help them blend in with their surroundings. Both the crab and the algae are given a comfortable environment to live.

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If you want to be 95​% confident of estimating the population proportion to within a sampling error of plus or minus 0.04 comma what sample size is​ needed? A sample size of nothing is needed.

Answers

The sample size needed is 601. To find the sample size needed for a 95% confidence level with a sampling error of plus or minus 0.04, we can use the formula:

n = (Z2 * p * (1-p)) / E2

Where:
- n is the sample size
- Z is the Z-score for the desired confidence level (1.96 for 95% confidence)
- p is the estimated population proportion (0.5 if unknown)
- E is the desired margin of error (0.04 in this case)

Plugging in the values, we get:

n = (1.962 * 0.5 * (1-0.5)) / 0.042

n = 600.25

Since we cannot have a fraction of a person, we round up to the nearest whole number.
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The smallest group that includes gibbons and humans but does not include tarsiers is

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C) the smallest group that includes gibbons and humans but ford not include tarsiers is hominoids.

Although hominoids, which include apes and humans, are among the least diverse living primates, they have a very extensive fossil record that dates back to the late Oligocene and contains a large number of extinct genera from Africa, Europe, and Asia (Fleagle, 2013). There are 26 species of hominoid genera that are still alive (most of which are gibbons). Three groups of living hominoids—Hylobatidae (gibbons), Pongidae (orangutans), and Hominidae—are typically recognized (gorillas, chimpanzees, and humans). The superfamily started in Africa, but both Africa and Eurasia played a role in their evolution. The only species to spread to other regions is humans. From the late Oligocene to the Miocene, the fossil record contains numerous species of stem hominoids and stem hominoids.

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Question:

the smallest group that includes gibbons and humans but ford not include tarsiers is (1 point)

a) primates.

b) anthropoids.

c) hominoids.

d) hominines.

After being exposed to online learning and other social media platforms during the lockdown, assess how you will now prepare to meet the demands of a career during the Digital age ( 4th Industrial revolution)​
URGENT !!!!!

Answers

Since, no career was mentioned, i will use teaching career, To prepare for a teaching career during the digital age, there are several things you can do:

Familiarize yourself with technologyKeep up-to-date with emerging trendsDevelop digital content

How to use the Digital age for carreer?

Familiarize yourself with technology: Digital technology has transformed the way education is delivered. Therefore, you need to have a good understanding of technology tools, including software, hardware, apps, and platforms that are commonly used in education. You should be comfortable using tools such as learning management systems, online collaboration tools, video conferencing platforms, and digital content creation tools.

Keep up-to-date with emerging trends: The digital age is continually evolving, and new technologies, tools, and trends emerge regularly. To stay relevant, you should regularly update yourself with the latest trends and techniques in the education sector. This can involve attending workshops, conferences, webinars, and online courses.

Develop digital content: As a teacher, you need to be able to create digital content that is engaging and interactive for your students. You should develop your skills in creating multimedia content such as videos, images, animations, and infographics.

Use social media to connect with students: Social media has become an integral part of students' lives. You should explore using social media platforms to connect with your students and build relationships with them. You can use social media to share updates on assignments, provide feedback, and encourage collaboration among students.

Foster digital citizenship: As a teacher, you have a critical role to play in promoting responsible digital citizenship among your students. You should educate your students on the responsible use of technology, including digital safety, security, and privacy.

Overall, preparing for a teaching career during the digital age requires a willingness to learn and adapt to new technologies and trends continually. By doing so, you can create a more engaging and effective learning environment for your students.

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The small ball inside the cubed display case has a volume of 8 cubic inches. If the free space inside the display case is 208 cubic inches, then how tall is the display case?

A. 9 inches

B. 6 inches

C. 10 inches

D. 8 inches

Answers

the length of each side of the display case is 6 inches keeping the ball, is (B) 6 inches.

As the display case is a cube, all sides are the same length on each side "s".

We know that the volume of the small ball inside the display case is 8 cubic inches, Thus:

[tex]4/3 * \pi * r^3 = 8[/tex]

where r is the radius of the ball. Solving for r, we get:

[tex]r = (3/(4*\pi ))^(1/3) ≈ 0.899 inches[/tex]

Since the ball fits inside the display case, we know that the length, width, and height of the display case are all greater than or equal to 2r. Therefore:

s ≥ 2r

Also free space inside the display case is 208 cubic inches, which means:

[tex]s^3 - 8 = 208[/tex]

Simplifying this equation, we get:

[tex]s^3 = 216[/tex]

Taking the cube root of both sides, we get:

[tex]s = 6[/tex]

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3. what is the big-o runtime of the buildheap algorithm? is this a more or less efficient algorithm than an o(nlog n) algorithm?

Answers

The big-O runtime of the build heap algorithm is O(n), where n is the number of elements in the input array. This is because the buildup algorithm takes linear time to build a heap from an unsorted array of n elements.

For building a heap, the buildup algorithm is more effective than an O(log n) approach like heapsort because the latter needs O(log n) time to sort an array before building a heap from it. In comparison, the build heap technique creates a heap directly from the unsorted array in only O(n) time. Although heapsort has a total runtime of O(log n) for sorting, it is still the best choice if the aim is to sort the array.

The buildup algorithm can increase the overall performance of the algorithm and is frequently used as a subroutine in other algorithms like heapsort or priority queue implementations.

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The complete question is -

What is the big-o runtime of the build heap algorithm? is this a more or less efficient algorithm than an o(log n) algorithm?

The image below represents starch, a type of carbohydrate. Which sentence explains how the highly branched structure of starch is related to its function in an organism? A. It allows the molecules to store a lot of information. B. It allows the molecules to provide insulation for internal body parts. C. It allows the molecules to pack tightly together and provide strength to cells. D. It allows the molecules to store a lot of energy.



can someone tell me which one is A. B. C. or D.​

Answers

Answer: D. It allows the molecules to store a lot of energy.

Explanation: The highly branched structure of starch is related to its function in an organism because it enables the molecules to store a significant amount of energy.  Starch is a polysaccharide, which is a complex carbohydrate made up of long chains of glucose molecules.

The branching structure of starch increases its surface area, allowing enzymes to break down the molecule more easily.  This enables organisms to efficiently store and access energy when needed.  When an organism requires energy, the stored starch is broken down into glucose units, which can then be utilized for various cellular processes, such as respiration and metabolism.

The ability of starch to store a lot of energy makes it an important source of fuel for organisms. It is commonly found in plants, where it serves as a long-term energy storage molecule.  Animals, including humans, also consume starch-rich foods like grains and potatoes to obtain energy.

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If you're doing a presentation about a slurry tank and you want to talk about the biology side of it, what should the presentation cover?

Here's how the bio-waste into energy process looks like. My focus is just on the slurry tank and the biology of it.

Answers

Answer:

If you are focusing on the biology aspect of a slurry tank, your presentation could cover the following topics:

Microorganisms: The slurry tank is home to a diverse range of microorganisms, including bacteria, fungi, and protozoa. These microorganisms play a crucial role in the biological breakdown of the waste material in the tank.

Anaerobic digestion: Anaerobic digestion is the process by which organic material is broken down by microorganisms in the absence of oxygen. This process is central to the functioning of a slurry tank, as it is the primary means by which bio-waste is converted into energy.

Methane production: As part of the anaerobic digestion process, microorganisms in the slurry tank produce methane gas. This gas can be harnessed as a source of renewable energy, either by being burned to generate electricity or by being used as a fuel for vehicles.

pH levels: The pH level of the slurry tank is a critical factor in maintaining the optimal conditions for the microorganisms to thrive. The pH level can be affected by various factors, including the type of waste material being added to the tank and the rate of digestion.

Nutrient cycling: The slurry tank is an excellent example of nutrient cycling in action. As the microorganisms break down the waste material in the tank, they release nutrients such as nitrogen and phosphorus, which can be used to fertilize crops or other plants.

Challenges: Despite the many benefits of using slurry tanks to convert bio-waste into energy, there are also several challenges associated with their use. These challenges include managing the odors associated with the process, ensuring the proper mixing of the waste material in the tank, and preventing the buildup of toxic substances.

By covering these topics, you can provide a comprehensive overview of the biology aspect of a slurry tank and highlight the many ways in which this technology is helping to reduce waste and promote sustainable energy production.

How does the intermediate produced in nucleophilic aromatic substitution?

Answers

The Process of Nucleophilic Aromatic Substitution Is Revealed by the "Meisenheimer" Intermediate

Intermediates have been separated during the addition of nucleophiles to a variety of aromatic molecules with low electron density and a leaving group. Jacob Meisenheimer separated one of the first in 1902, and this intermediate is known as the "Meisenheimer complex" in general.

The (non-aromatic) addition product between the aromatic ring and the nucleophile is the intermediate

It is possible to isolate and describe Meisenheimer intermediates. The molecule eventually transforms into the final nucleophilic aromatic substitution product when heated, though.

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All of the following are true of the primary response of humoral immunity, except that _____.(a) circulating antibodies undergo a gradual, sustained rise(b) It depends on antigen triggering the appropriate B-cell(c) It requires B-cell differentiation into plasma cells(d) It is delayed by the memory cell stage(e) It peaks 1 to2 weeks after the initial exposure.

Answers

The statement that is not true of the primary response of humoral immunity is (d) "It is delayed by the memory cell stage."

The humoral immunity

The primary response of humoral immunity is the initial immune response to a foreign substance, or antigen, that enters the body. This response involves the activation and differentiation of B cells into plasma cells, which produce and release antibodies specific to the antigen. The correct statements about the primary response of humoral immunity are:

Circulating antibodies undergo a gradual, sustained rise: During the primary response, the production of antibodies by plasma cells increases gradually and reaches a peak around 1 to 2 weeks after the initial exposure.

It depends on antigen triggering the appropriate B-cell: The primary response of humoral immunity is occasioned by the recognition of an antigen by a specific B-cell receptor.

It requires B-cell differentiation into plasma cells: The activated B cells differentiate into plasma cells that produce and secrete large amounts of antibodies specific to the antigen.

It peaks 1 to 2 weeks after the initial exposure: This statement is true, as mentioned above. The production of antibodies by plasma cells during the primary response reaches a peak around 1 to 2 weeks after the initial exposure to the antigen.

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It peaks 1 to2 weeks after the initial exposure.

What is primary response of humoral immunity?

The primary response of humoral immunity is the initial immune response that occurs when the immune system encounters an antigen for the first time. The humoral immune response involves the production of antibodies by B cells, which are a type of white blood cell.

The primary response of humoral immunity takes several days to develop, as the B cells must undergo proliferation and differentiation before sufficient levels of antibodies can be produced.

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The following medical scenario presents information on one of the pathological conditions discussed in this chapter. Read the scenario carefully and select the most appropriate answer for each question that follows. Each correct answer is worth 20 points. Record your score in the space provided at the end of the exercise.
Katrina Goodman, a 45-year-old patient, visited her internist last week, stating, "I’m so tired, and I have these bruises all over me." Katrina also complained of heavier than usual menstrual periods and mouth ulcers. Katrina’s physician mentioned that she needed to complete a few tests to rule out leukemia. She started with a CBC blood test. The results were abnormal. Katrina is scheduled for a follow-up visit today and has many questions for the health care professional about this possible leukemia.
Katrina asks the health care professional how leukemia could cause all the bruises on her body. The health care professional would explain to Katrina that these are called purpura and are due to:
a. an abnormal increase in the number of RBCs
b. a decrease in the hemoglobin and hematocrit
c. an increase in larger than usual WBCs
d. a decrease in circulating platelets

Answers

The health care professional would explain to Katrina that these are called purpura and are due to:d.

a. Decrease in circulating platelets

What would the personnel explain to Katrina?

The health care personnel can explain to Katrina that the brises notices are due to the lack of platelets that should clot blood. Purpura is the result of bleeding that is not regulated by the platelets whose primary duty is that of clotting blood.

In the above case, Katrina is suffering from Purpura and the abnormal complete blood count will most show a decrease in white blood cells that shuld control bleeding.

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________ caused by overuse or improper conditioning of the leg muscles.

Answers

Answer:

Shin splints are caused by overuse or improper conditioning of the leg muscles, specifically the muscles, tendons, and bone tissue around the tibia or shinbone.

Explanation:

Shin splints are caused by overuse or improper conditioning of the leg muscles, specifically the muscles, tendons, and bone tissue around the tibia or shinbone. This condition commonly affects athletes and individuals who engage in physical activities that involve repetitive stress on the legs, such as running, jumping, or dancing. Symptoms of shin splints include pain, tenderness, and swelling in the lower leg.

Which description is the best definition of a stem cell? O a specialized cell that divides by meiosis to produce gametes in order to facilitate sexual reproduction an undifferentiated cell that can replicate itself indefinitely and differentiate into specialized cell types when appropriate O a type of lymphocyte made in the thymus that contributes an adaptive immune response O a type of blood cell that does not have a nucleus, mitochondria, or other organelles

Answers

The best definition of a stem cell is "an undifferentiated cell that can replicate itself indefinitely and differentiate into specialized cell types when appropriate."

A stem cell is an undifferentiated cell that can replicate itself indefinitely and differentiate into specialized cell types when appropriate. It means that stem cells are unique because they have the ability to divide and create more cells, as well as differentiate into specialized cells, such as nerve cells, muscle cells, and blood cells. This makes stem cells extremely important for medical research and treatments, as they have the potential to be used to replace damaged or diseased cells in the body.

Your options aren't well arranged, but  most probably your options were

A. a specialized cell that divides by meiosis to produce gametes in order to facilitate sexual reproduction

B. an undifferentiated cell that can replicate itself indefinitely and differentiate into specialized cell types when appropriate

C. a type of lymphocyte made in the thymus that contributes an adaptive immune response

D. a type of blood cell that does not have a nucleus, mitochondria, or other organelles

Thus, the correct option is B.

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Which type of biomolecule contains phosphorus? A. Nucleic acid B. Protein C. Carbohydrate D. Lipid​

Answers

Answer: Nucleic Acids should be the answer.

Explanation:

Hydrogen, oxygen, nitrogen, carbon, and phosphorus combined and placed under one umbrella term, Biomolecule, are known as one thing; the Nucleic Acids.

Describe the features you would look for to decide on the function of an unknown specialised plant cell. [6 marks]

Answers

Here are six features that could be used to make a determination:

Cell shape: The shape of a plant cell can provide clues to its function. For example, cells that are elongated and have a pointed shape may be involved in transporting fluids.

Cell size: The size of a plant cell can also provide clues to its function. Cells that are large and contain a lot of cytoplasm may be involved in energy storage or metabolism.

Chloroplasts: Chloroplasts are organelles in plant cells that are involved in photosynthesis. The presence of chloroplasts in a cell can indicate that it is involved in producing energy from sunlight.

Vacuoles: Vacuoles are large membrane-bound organelles that are involved in storing and transporting nutrients and waste products. The presence of a large vacuole in a cell can indicate that it is involved in nutrient storage or waste management.

Cell wall: Plant cells have a rigid cell wall that surrounds the cell membrane. The thickness and composition of the cell wall can provide clues to the cell's function. Cells with thick, rigid cell walls may be involved in structural support, while cells with thinner cell walls may be involved in transport or exchange of materials.

Specialized structures: Some plant cells have specialized structures that are unique to their function. For example, root hairs are specialized cells that increase the surface area of roots to improve nutrient uptake from the soil. Cells with specialized structures can provide strong indications of their specific function.

your science teacher, Mrs.waters, informs you that most rivers carry tiny particles that you could not see very well. what is Mrs. Waters describing

Answers

Mrs. Waters is referring to the silt or suspended particles that are present in the majority of rivers. These tiny particles, which might include dirt, sand, clay, and other detritus transported by the river's flow, can be

As Mrs. Waters teaches science, it is probable that she is enthusiastic about the topic and likes to impart her expertise to her pupils. She is probably committed to assisting her pupils in developing both academically and personally. She is informed about the natural world and is likely to stress the value of sustainability and conservation. Mrs Waters is probably kind and empathetic, eager to help her pupils comprehend complex ideas and give them the encouragement they need to succeed. She probably fosters inquiry and critical thinking, assisting her pupils in gaining a greater respect for science and the

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