Which elements is malleable and ductile

Answer:

Image distance = 44.8cm, Image height = 16.5cm, Magnification = 0.42

The image is a virtual and upright image.

Explanation:

The nature of image formed by an object placed in front of a convex mirror is always diminished, virtual and erect.

The focal length f and the image distance are always NEGATIVE beacause the image is formed behind the mirror.

Given f = -33.0cm, v = -19.0cm

using thr mirror formula to get the object distance u, we have;

[tex]\frac{1}{f}=\frac{1}{u} + \frac{1}{v}\\ \frac{1}{u}=\frac{1}{f} - \frac{1}{v}\\\frac{1}{u}=\frac{1}{-33} - \frac{1}{-19}\\\frac{1}{u}=\frac{-19+33}{627} \\\frac{1}{u}=\frac{14}{627} \\u=\frac{627}{14} \\u = 44.8cm[/tex]

To calculate the image height, we will use the magnification formula

M = [tex]\frac{image\ height}{object\ height}=\frac{image\ distance}{object\ distance} \\[/tex]

M = [tex]\frac{Hi}{HI}=\frac{v}{u}[/tex]

Given Hi = 7.0cm

v = 19.0cm

u = 44.8cm

HI = 7*44.8/19

HI = 16.5cm

The object height is 16.5cm

Magnification = v/u = 19.0/44.8 = 0.42

SInce the image is formed behind the mirror, the image is a VIRTUAL and UPRIGHT image

Answer:

0.54 sec.

Explanation:

The Speed: 2.4 m/seconds

The Distance: 1.3 m

So time =  Distance/Speed

Time = 1.3 / 2.4

THE ANSWER WILL BE 0.54 seconds.

Answer:

a and b are the correct answers

Explanation:

Answer:

A)  physical property; mass.

Explanation:

took the test

Answer:

D. the linear velocity of the point of contact (relative to the inclined surface) is zero

Explanation:

The force of friction emerges only when there is relative velocity between two objects . In case of perfect rolling , there is no sliding so relative velocity between the surface and the point of contact is zero . In other words the velocity of point of contact becomes zero , even though , the whole body is in linear motion . It happens due  point of contact having two velocities which are equal and opposite . One of the velocity is in forward direction and the other velocity which is due to rotation is in backward direction . So net velocity of point of contact becomes zero . Due to absence of sliding , displacement due to friction  becomes zero . Hence work done by friction becomes zero.

Answer:

t = 2.68 x 10¹⁴ years

Explanation:

First we need to find the amount of energy that Sun produce in one day.

Energy = Power * Time

Energy of Sun in 1 day = (3.839 x 10²⁶ W)(1 day)(24 hr/1 day)(3600 s/ 1 hr)

Energy of Sun in 1 day = 3.32 x 10³¹ J

Now, the time required by the nuclear power generator, in years, will be:

Energy of power generator = Energy Sun in 1 day = 3.32 x 10³¹ J

3.32 x 10³¹ J = Power * Time

3.32 x 10³¹ J = (3.937 x 10⁹ W)(t years)(365 days/1 year)(24 hr/1 day)(3600 s/ 1 hr)

t = 3.32 x 10³¹ /1.24 x 10¹⁷

t = 2.68 x 10¹⁴ years

Answer:

1/2

Explanation:

Solution:-

- The torque ( T ) induced at the pivotal point of the massless rod-disk assembly is given by:

                           T = M*g*r*sin ( θ )

Where,

              M: The mass of the disk

              r: the radius of the disk

              θ: The precession angle

- The rate of change in angular momentum of the disk ( dL / dt ) is due to the induced torque ( T ) given by:

                          dL / dt = M*g*r*sin ( θ )

Hence,

                          dL = M*g*r*sin ( θ ). dt  ... Eq1

- The change in precession angle ( dθ ) is a orthogonal component of change in angular momentum ( dL ) :

                         dθ = dL / ( L*sin ( θ ) ) ... Eq2

- Combine Eq1 and Eq2:

                         dθ = M*g*r*sin ( θ ). dt / ( L*sin ( θ ) )

                         dθ/dt = M*g*r / L   ... Eq3

Where,

- The angular momentum of the disk is given by the product of moment of inertia ( I ) and angular velocity ( w ):

                      [tex]L = I*w\\\\L = \frac{1}{2}*M*r^2*w[/tex]

- Substitute the relationship of angular momentum of disk ( L ) into Eq3:

                      dθ/dt = M*g*r / 0.5*M*r^2*w                

- Hence, the rate of change of precession ( dθ/dt ) is given by:

                      dθ/dt = 2*g / r*w  

- If we double the mass ( M to 2M ) there is no effect on the rate of change of precession ( dθ/dt ). However, if we double the radius of the disk the rate of precession ( dθ/dt ) is halved due to the inverse relationship between the rate of precession ( dθ/dt ) and radius of the disk.

Answer:The factor of change would be ( 1 / 2 ) of the initial rate of change in precession.

Here are a list of items I found.

some brushes

a armature

a permanent magnet

some slip rings

Answer:

A fan pushes hot air out of a vent and into a room. The hot air displaces cold air in the room, causing the cold air to move closer to the floor.

The hot air displacing the cold air is an example of  transfer by

Explanation:

Answer:

2.10 V

Explanation:

To find the potential difference across the ends of the bar, you take into account that when the bar moves with speed v, in a constant magnetic field, the charges in the wire feels a magnetic force that separate the opposite charges, generating an induced potential difference given by the following formula:

[tex]\epsilon=vBL[/tex]   (1)

v: speed of the bar = 11.5 m/s

B: magnitude of the magnetic field = 1.22 T

L: length of the bar = 15.0cm = 0.15m

You replace the values of v, B and L in the equation (1):

[tex]\epsilon=(11.5m/s)(1.22T)(0.15m)=2.10\ V[/tex]

hence, the induced potential difference is 2.10 V

Answer:

The energy released in the process is 3.27 MeV or 5.23 x 10⁻¹³ J

Explanation:

For the release of energy there must be a difference in energies of the reactants and products. The released energy will be equal to this difference in energies of reactants and products.

The difference in mass of reactant and product is:

Difference in mass = Δm = Mass of Reactant - Mass of Products

Δm = 2(Mass of Deuterium) - Mass of Helium - Mass of Neutron

Δm = 2(2.014102 u) - 3.016030 u - 1.008665 u

Δm = 4.028204 u - 3.016030 u - 1.008665 u

Δm = 0.003509 u

This difference in mass corresponds to the released energy. In order to convert this to energy, we use relation:

Released Energy = ΔE = Δm * 931.494 MeV/u

ΔE = (0.003509 u)(931.494 MeV/u)

ΔE = 3.27 MeV

Now, converting it to Joules:

ΔE = (3.27 x 10⁶ eV)(1.6 x 10⁻¹⁹ J/1 eV)

ΔE = 5.23 x 10⁻¹³ J

Answer:10 ohms

Explanation:

Current=0.15A

Voltage=1.5v

Resistance=voltage ➗ current

Resistance=1.5 ➗ 0.15

Resistance=10 ohms

Answer:

c = 4,444.44

Explanation:

You have the following expression for the acceleration of the projectile:

[tex]a=cs[/tex]   (1)

s: distance to the ground of the projectile

To find the value of the constant c you use the following formula:

[tex]v^2=v_o^2+2a \Delta s[/tex]   (2)

vo: initial  velocity = 0 m/s

v: final speed = 200 m/s

Δs: distance traveled by the projectile = 3m - 1.5m = 1.5m

You replace the expression (1) into the expression (2):

[tex]v^2=2(cs)\Delta s[/tex]

You do the constant c in the last equation, then you replace the values of v, s and Δs:

[tex]c=\frac{v^2}{2s\Delta s}=\frac{(200m/s)^2}{2(3m/s^2)(1.5m)}=4444.44[/tex]

Answer:

the answer is a

Explanation:

Answer:

Explanation:

moment of inertia of each blade which is similar to rod rotating about its one end

= 1/3 ml²

moment of inertia of 3 blades = ml²

= 5500 x 46²

I = 11638 x 10³ kg m²

angular velocity = 2πn where n is rotation per second

n = 11 / 60

angular velocity = 2π x 11/60

= 1.1513 rad /s

angular momentum

= moment of inertia x angular velocity

=  11638 x 10³ x 1.1513

= 13399 x 10³ kg m² per second.

Answer:

47°

Explanation:

between the two antennas for an observer difference in length in quadrant I is

ΔL = dCos(θ)

setting θ=0 i.e the observer is north of the station to get

ΔL= d= 120 m.

The wavelength formula is:

λ = c / f = 3x [tex]10^8[/tex] / 3.4 x [tex]10^6[/tex] = 88.2m

Constructive interference occurs when the Length difference is equal to an integer multiple of a wavelength.

At the given spacing, and from an observation point north of the stations, they are more than a wavelength apart, so they are not in constructive interference. Looking for the first peak:

dCos(θ) = λ

Cos(θ) = λ/d

θ = arcCos(λ/d) = arcCos( 88.2 / 120 ) = 42.7°= 43°

For destructive interference:

90° - 43°= 47°

Answer:

b

Explanation:

Answer:

The correct answer is D, diatoms have glass-like cell walls.

Answer:

The force needed is the weight of the rock minus the buoyant force.

Explanation:

Answer:

Explanation:

The problem is based on Newton's law of cooling .

According to Newton's law

dQ / dt = k ( T - T₀ ) ,

dT / dt = k' ( T - T₀ )          ; dT / dt is rate of fall of temperature.

T is average  temperature of hot body , T₀ is temperature of surrounding .

In the first case rate of fall of temperature = (210 - 191) / 2.5

= 7.6 degree / s

average temperature T = (210 + 191) /2

= 200.5  

Putting in the equation

7.6 = k' ( 200.5  - 64 )

k' = 7.6 / 136.5

= .055677

In the second case :---

In the second case, rate of fall of temperature = (191 - 156) / t  

= 35 / t   , t is time required.

average temperature T = (156 + 191) /2

= 173.5  

Putting in the equation

35 / t = .05567 ( 173.5 - 64 )

t = 5.74 minute .

Answer:

Magnetic field can be used to produce current, infact a changing magnetic field can produce current.

A changing magnetic field in a loop causes the flux linked with the loop to change in turn generating a emf in the loop and therefore a current.

For a loop of area A and resistance R.

I =dPhi/dt/R

В. А

I = AcosФ/R .dB /dt

But it isn't reasonable to say that we can create a magnetic field by having a flow of current and this can be used to make more current because the current generated due to change in magnetic field created by increase/decrease in flow of current will be in a direction such that it will counter act the change in magnetic field caused by increase/decrease in current flow.(lenz's law).

We were unable to transcribe this image

Ф= В. А

I = Acos dB Rd

Answer:

A mutation causes a dog to be born with a tail that is shorter than normal. Which best describes this mutation? It is harmful because it obviously affects the dog’s survival. It is harmful because it affects the dog’s physical appearance. It is neutral because it does not obviously affect the dog’s survival. It is beneficial because it affects the dog’s physical appearance.

Explanation:

Answer:

C

Explanation:

:)))

Answer:

During an earthquake, seismic waves travels through the Earth's interior as body or p waves.

Explanation:

If neither of the bold words look familiar from your lesson feel free to ignore this answer

Answer:

A i. E = 9.62 × 10⁻⁷ J/s

ii. The absorbed dose is 4.81 × 10⁻⁶ Gy

iii. The equivalent dose is  3.37 × 10⁻⁴ rem/s

iv.  t = 593471.81 seconds

B. i. 4.025 × 10¹⁵/s

ii. 0.512 mW

C. 7218092.2 seconds

D. i. 6.3 × 10⁻¹ J

ii. 1.4 × 10⁻² W

iii. 1.57 × 10³ Curie

E. 0.129 Ω

Explanation:

The given parameters are;

Mass of tumor = 0.20 kg

Activity of Cobalt-60 = 2.60 × 10⁻⁴ Ci

Photon energy = 1.25 MeV

(i) The energy, E, delivered to the tumor is given by the relation;

[tex]E = \frac{1}{2}\left (Number \, of \, decay / seconds \right )\times \left (Energy \, of \, photon \right )[/tex]

[tex]E = \frac{1}{2}\left (2.6\times 10^{-4}Ci )\times \left (\frac{3.70\times 10^{10}decays/s}{1 Ci} \right )\times 1.25\times 10^{6}eV\times \frac{1.6\times 10^{-19}J}{1eV}[/tex]

E = 9.62 × 10⁻⁷ J/s

(ii) The equation for absorbed dose is given as follows;

Absorbed dose, D, in Grays Gy = (Energy Absorbed Joules J)/Mass kg

Therefore, absorbed dose = (9.62 × 10⁻⁷ J/s)/( kg) = 4.81 × 10⁻⁶ Gy

1 Gray = 100 rad

4.81 × 10⁻⁷ Gy = 100 × 4.81 × 10⁻⁶ = 4.81 × 10⁻⁴ rad/s

(iii) Equivalent dose, H, is  given by the relation;

H = D × Radiation factor, [tex]w_R[/tex]

∴ H = 0.7 × 4.81 × 10⁻⁴ rad/s = 3.37 × 10⁻⁴ Sv = 3.37 × 10⁻⁴ rem/s

(iv) The exposure time required for an equivalent dose of 200 rem is given as follows;

[tex]\dot{H} = \dfrac{H}{t}[/tex]

Therefore;

[tex]t= \dfrac{200}{{3.37 \times 10^{-4}} } = 593471.81 \, s[/tex]

∴ t = 6.9 days

B. The number of electrons ejected is given by the relation;

[tex]N = \frac{P}{E} = \frac{P \times \lambda}{hc}[/tex]

[tex]N = \dfrac{2.0 \times 10^{-3} \times 400 \times 10^{-9}}{6.626 \times 10^{-34} \times 3 \times 10^8} = 4.025 \times 10^{15}/s[/tex]

(ii) The power carried by the electron

The energy carried away by the electrons is given by the relation;

[tex]KE_e = hv - \Phi[/tex]

[tex]KE_e = \frac{6.626 \times 10^{-34} \times 3 \times 10^8}{400 \times 10^{-9}} - 2.31 \times \frac{1.6 \times 10 ^{-19} }{1}[/tex]

[tex]KE_e = 4.9695 \times 10^{-19} - 3.696 \times 10 ^{-19} = 1.2735 \times 10^{-19} J[/tex]

Power, P[tex]_e[/tex], carried away by the electron = 4.025 × 10¹⁵ × 1.2735 × 10⁻¹⁹ = 0.512 mW

C. The given parameters are;

d = 1.19 mm, ∴ r = 1.19/2 = 0.595 × 10⁻³ m

l = 50 mm = 5 × 10⁻³ m

V = 500 ml = 5 × 10⁻⁴ m³

η = 0.0027 Pa

p = 1,900 Pa.

[tex]\dfrac{V}{t} = \dfrac{\pi }{8} \times \dfrac{P/l}{\eta } \times r^4[/tex]

[tex]t = \dfrac{8\times \eta\times V\times l }{\pi \times P \times r^4}[/tex]

[tex]t = \dfrac{8\times 0.0027 \times 5 \times 10^{-4} \times 5 \times 10^{-2} }{\pi \times 1900 \times (0.595 \times 10^{-4} )^4}[/tex]

t = 7218092.2 seconds

D) i. Energy absorbed is given by the relation;

E = m×D

Where:

D = 35 Gray = 35 J/kg

m = 18 g = 18 × 10⁻³ kg

∴ E = 35 × 18 × 10⁻³ = 6.3 × 10⁻¹ J

ii. Total time for treatment = 15 × 5 = 75 minutes

Energy absorbed = 6.3 × 10⁻¹ × 100 = 63 J

Power = Energy(in Joules)/Time (in seconds)

∴ Power = 63/(75×60) = 1.4 × 10⁻² W

iii. Whereby the power is provided by 0.5% of the photons emitted by the source, we have;

[tex]P_{source}= \frac{P_{beam}}{0.005} =\frac{0.0014}{0.005} =0.28 \, W[/tex]

1 MeV = 1.60218 × 10⁻¹³ J

0.03 MeV = 0.03 × 1.60218 × 10⁻¹³ J = 4.80654 × 10⁻¹⁵ J/photon

Therefore, the number of disintegration per second = 0.28 J/s ÷  4.80654 × 10⁻¹⁵ J/photon = 5.83 × 10¹³ disintegrations per second

1 Curie = 3.7 × 10¹⁰  disintegrations per second

Hence, 5.83 × 10¹³ disintegrations per second = (5.83 × 10¹³)/(3.7 × 10¹⁰) Curie

= 1.57 × 10³ Curie

E. The parameters given are;

Density of water = 1000 kg/m³

Volume of water = 250 ml = 0.00025 m³

Initial temperature, T₁, = 25°C

Final temperature, T₂, = 100°C

Change in temperature, ΔT = 100 - 25 = 75°

Specific heat capacity of the water = 4200 J/kg/°C

Mass of water = Density × Volume = 1000 × 0.00025 = 0.25 kg

∴ Heat supplied = 4200 × 0.25 × 75 = 78,750 J

Time to heat the water = 45.0 sec

Therefore, power = Energy/time = 78750/45 = 1750 W

The formula for electrical power = I²R =VI = V²/R

Therefore, where V = 15.0 V, we have;

15²/R = 1750

R = 15²/1750 = 0.129 Ω.

The resistance of the heater = 0.129 Ω.

Answer: B. 9032°F

Explanation:

First we take down the data made available to us.

Estimated temperature of the Earth's core = 5000° Celsius

Now to express this temperature in Fahrenheit, we make use of the formula;

[°F] = [°C] × 9/5 + 32

Where

[°F] is temperature in Fahrenheit and

[°C] is temperature in Celsius

So we just input our figure into the formula

[°F] = [5000°] × 9/5 + 32

°F = 5000 × 1.8 + 32

°F = 9000 + 32

°F = 9032°

So 5000° Celsius is expressed as 9032° Fahrenheit

Answer:

The thickness of ring in model is 0.00001 inch and the height of ring is 0.0001 inch.

Explanation:

The radius of Saturn = 60000 km

The thickness of rings = 0.01 km

The height of ring ripples = 100 m or 0.1 km

Now design a new model with a radius of 60 inches.

Therefore, the  radius of Saturn (600000 km)  = radius of the model (60 inches)

Here, one inch of the model will be equal to 1000 km of Saturn.

1 km of Saturn = 0.001 inch of model

Thickness of ring = 0.01 km

Therefore, thickness of ring in model = 0.01 x 0.001 = 0.00001 inch

The height of Saturn ring = 0.1 km

Therefore, the height of ring in model = 0.1 x 0.001 = 0.0001 inch.

Answer:

Explanation:

The package leaves the chute with a speed of 3 m/s, and lands in the cart after falling for 0.75 seconds . During .75 second duration . package undergoes free fall due to which additional vertical velocity is added

velocity added = a x t

= 9.8 x .75

= 7.35 m /s

Total vertical velocity

= 3 sin27 + 7.35

= 8.71 m /s

Horizontal component = 3 cos 27

= 2.67 m /s

If v be the resultant velocity of these components

v² = 2.67² + 8.71²

v² = 7.13 + 75.86

v = 9.11 m /s .

Answer:

A.

Explanation:

Refraction light rays are bent as they pass into a different medium where its speed is different. As refracted light rays pass from a fast medium to a slow medium, the light ray bends toward the normal to the boundary between the two medium. Light refracts as it travels at an angle into a medium with a different refractive index.

Answer:

A black hole

Explanation:

I'm not sure, i just know that's the right answer

Answer:

.7934[tex]m/s^{2}[/tex]

Explanation:

Acceleration = change in velocity / change in time

A = 10.98[tex]m/s[/tex] / 13.84[tex]s[/tex]

A = .7934[tex]m/s^{2}[/tex]

Answer:0.8 m/s^2

Explanation:

initial velocity(u)=18.54m/s

Final velocity(v)=29.52m/s

Time(t)=13.84 sec

Acceleration =(v-u)/t

acceleration =(29.52-18.54)/13.84

Acceleration =10.98/13.34

Acceleration=0.8 m/s^2

Answer:

a) [tex]\vec{v}_{12}=2.86*10^{8} m/s[/tex]

b) [tex]p=2.81*10^{-16} kg*m/s[/tex]    

Explanation:

a) When we have two particles traveling in parallel directions, the formula for relative velocity is:

[tex]\vec{v}_{12}=\frac{\vec{v}_{1}-\vec{v}_{2}}{1-\frac{\vec{v}_{1}\vec{v}_{2}}{c^{2}}}[/tex]

Here we have that v(1) = -v(2), the speed of the of the second particle is the negative of the first one.

If we use these equivalence we have:

[tex]\vec{v}_{12}=\frac{2\vec{v}_{1}}{1+\frac{\vec{v}_{1}^{2}}{c^{2}}}[/tex]  

[tex]\vec{v}_{12}=\frac{2*2.19*10^{8}}{1+\frac{2.19*10^{16}}{3*10^{16}}}[/tex]  

[tex]\vec{v}_{12}=2.86*10^{8} m/s[/tex]          

And, [tex]\vec{v}_{21}=-2.86*10^{8} m/s[/tex]  

b) The relativistic momentum equation to one particle observed by the other particle, is:

[tex]p=\gamma mv[/tex]

Where gamma is:

[tex]\gamma = \frac{1}{\sqrt{1-\frac{v^{2}}{c^{2}}}}[/tex]

Then gamma will be:

[tex]\gamma=\frac{1}{\sqrt{1-\frac{(2.86*10^{8})^{2}}{(3*10^{8})^{2}}}}[/tex]

[tex]\gamma=3.31[/tex]

Finally, the value of the momentum will be:

[tex]p=3.31*2.97*10^{-25}*2.86*10^{8}[/tex]    

[tex]p=2.81*10^{-16} kg*m/s[/tex]    

I hope it helps you!                        

Answer:

Materials that allow electricity to pass through them are called conductors.

Copper wire is a good conductor. Materials that do not allow electricity to pass through them are called insulators.

Explanation:

Can I have brainliest?

Answer: A. Balloons can be filled with air.

C. Air has mass.

Explanation:

Learn more https://brainly.com/question/3238218

Balloons are able to be filled with air and air has mass.