Which equations are equivalent to Three-fourths + m = negative StartFraction 7 over 4 EndFraction? Select three options. m = StartFraction 10 over 4 EndFraction m = negative StartFraction 10 over 4 EndFraction m = negative five-halves StartFraction 11 over 4 EndFraction + m = negative one-fourth Negative five-fourths + m = negative StartFraction 15 over 4 EndFraction

Answers

Answer 1

Answer:

1)  m = negative StartFraction 10 over 4 EndFraction

2) m = negative five-halves

3) m = [tex]-\frac{7}{4} - \frac{3}{4}[/tex]

Step-by-step explanation:

The given equation is:

=> [tex]\frac{3}{4} +m = -\frac{7}{4}[/tex]

Subtracting 3/4 to both sides

=> m = [tex]-\frac{7}{4} - \frac{3}{4}[/tex]

=> m = [tex]\frac{-10}{4}[/tex]

=> m = [tex]-\frac{5}{2}[/tex]

Answer 2

Answer:

-5/2 ye

cause ya do the math

Step-by-step explanation:


Related Questions

Please help! I got 14 but it says it's incorrect! Find the maximum number of real zeros of the polynomial. f(x)=2x^(6)-3x^(3)+1-2x^(5)

Answers

Answer:

There are two or zero positive solutions and zero negative roots (zeros).

Step-by-step explanation:

Use Descartes' Rule of Signs to determine the number of real zeros of [tex]f(x)=2x^6-3x^3+1-2x^5[/tex]

[tex]f(x)=2x^6-2x^5-3x^3+1\\[/tex]

For the functions f(x)=4x+5 and g(x)=6x+4,find (f•g)(0)and (g•f)(0)

Answers

Answer:

Step-by-step explanation:

f(x)=4x+5

g(x)=6x+4,

first: (f*g)=(4x+5) (6x+4)=24x²+46x+20

next:(f*g)(0)=((g*f)=24x²+46x+20=20

Hi,

f°g means :  apply first g then f . so calculate  "g" and then use result as "x" in f.  

g°f  means :   you apply first  f then g  

so :  f°g =    4 (g (x)) +5  

4 (6x+4) +5  = 24x+16+5 = 24x+21

Ernie deposits $5,500 into a pension fund. The fund pays a simple interest rate of 6% per year. What will the balance be after one year?

Answers

Answer:

Balance after one year will be $5830.

Below are the jersey numbers of 11 players randomly selected from a football team. Find the​ range, variance, and standard deviation for the given sample data.
33 29 97 56 26 78 83 74 65 47 58
What do the results tell​ us?
A. Jersey numbers are nominal data that are just replacements for names, so the resulting statistics are meaningless.
B. Jersey numbers on a football team vary much more than expected.
C. The sample standard deviation is too large in comparison to the range.
D. Jersey numbers on a football team do not vary as much as expected.

Answers

Answer:

Option(A) is correct

Jersey numbers are nominal data that are just replacements for names, so the resulting statistics are meaningless.

Step-by-step explanation:

The given data set in the question are ;33, 29, 97, 56, 26, 78, 83, 74, 65, 47, 58

the range can be determined by finding the highest value and subtract it to the lowest value. In this case the values are:

Highest = 97

Lowest = 71

Range = highest value - Minimum value

Range = 97 - 26 = 71

[tex] Range= 71[/tex]

mean of the data is the summation of all the numbers in the data set divided by the number of given samples.

Mean = (33 + 29 + 97 + 56+ 26 + 78 + 83 74+ 65 + 47 + 58)/11

= 647/11

[tex]Mean value =58.7[/tex]

Now to find the variance of the data set by using below formular

σ²=[ (xᵢ -mean)²]/n-1

[(33-58.7)² +(29-58.7)²+( 97-58.7)²+( 56-58.7)²+( 26 -58.7)²+(78-58.7)²+( 83 -58.7)²+(74-58.7)²+( 65-58.7)²+( 47 -58.7)²+(58 -58.7)²]/10

[tex]Variance=546[/tex]

Now, we will calculate standard deviation by taking square root over variance

σ =√(variance)

σ =√(546)

[tex]Standard deviation= 23.4[/tex]

Hence, the range is 71 ,variance is 546 and standard deviation is 23.4 therefore,

Option A is the answer that is Jersey numbers are nominal data that are just replacements for names, so the resulting statistics are meaningless.

a scale drawing of a rectangular playground has a length of 20 inches and a width of 10 inches as shown below. the scale is 1 inch = 4 feet. what is the area of the actual playground? *

Answers

Answer:

3200ft^2

Step-by-step explanation:

1 inch = 4ft

so 20 inches = 80ft

and 10 inches = 40ft

Area = 80ft*40ft

Area = 3200ft^2

Question 3 (5 points)
POINT
-POINT A
POINT B
What are the coordinates of the point labeled B in the graph shown above?
A) (3, 2)
B) (-3,2)
OC) (-2,3)
D) (-2, -3)
Question 4 (5 points)

Answers

Answer:

(D) -2,-3

Step-by-step explanation:

From the origin, we can find the current position of point B by counting.

B is 2 to the left of the y-axis, meaning that it's x value is -2.

B is 3 down of the x-axis, making it's y value -3.

Therefore, the coordinates of point B are -2,-3.

Hope this helped!

Answer: (D) -2,-3

Step-by-step explanation:

One number is 26 more than another. Their product is -169.

Answers

One number = x

One number more 26 = x + 26

Their product is -169

x . (x + 26) = -169

x² + 26x = -169

x² + 26x + 169 = 0

x² + 2.13.x + 13² = 0

It can be written by

(x + 13)² since we know that (x + 13)² = x² + 2.x.13 + 13²

So

(x + 13)² = 0

x + 13 = 0

x = -13

Our number is -13

Step-by-step explanation:

Here, according to the question,

let one number be x and another number be x +26 as given in question that the another number is more than 26.

And their product is given as -169.

now, as per the condition of question,

x × (x+26)= -169

or, x^2+26x= -169

or, x^2+26x+169=0

or, (x+13)^2=0

or, (x+13)=0 (root under 0= 0)

or, x=-13.

Therefore, thevalue of x is -13.

And the value of (x+26) is (-13+26)=13.

Checking, 13×-13=-169.

Therefore, the 2 numbers are -13 and 13.

hope it helps...

Solve for X. pls help asap

Answers

Answer:

x=3

Step-by-step explanation:

Use the Pythagorean Theorem to write an equation.

x^2+y^2=z^2

Substitute values from the problem.

x^2 + 6^2 = 9^2

Solve for what you know.

x^2 + 36 = 81

Square root it.

x+6=9

Subtract 6 from both sides.

x=3

In the future, if you see a right triangle with an unknown side, and the other two sides are either 3, 6, or 9, you know that the other one is the missing value out of 3/6/9. This is called a 3/6/9 triangle.

Answer:

6.7

Step-by-step explanation:

Hypotenuse (h) = 9

base (b) = X

Perpendicular (p) = 6

Now,

Using Pythagoras theorem:

[tex] {h}^{2} = {p}^{2} + {b}^{2} [/tex]

[tex] {b}^{2} = {h}^{2} - {p}^{2} [/tex]

[tex] {b}^{2} = {(9)}^{2} - {(6)}^{2} [/tex]

[tex] {b}^{2} = 81 - 36[/tex]

[tex] {b}^{2} = 45[/tex]

[tex]b = \sqrt{45} [/tex]

[tex]b = 6.7[/tex]

Hope this helps...

Good luck on your assignment..

Select the correct answer from each drop down menu.


The slope of diagonal OA is
A) 4/3
B) 3/4
C) 1
,and it’s equation is
A) 4x-y=0
B) x-3y=0
C) 4x-3y=0

Answers

Answer:

(A) [tex]\text{The slope of OA is }\dfrac{4}{3}[/tex]

(C) It’s equation is 4x-3y=0.

Step-by-step explanation:

Point O is at (0,0)

Point A is at (3,4)

[tex]\text{Slope of OA}=\dfrac{4-0}{3-0} \\m=\dfrac{4}{3}[/tex]

The equation of a straight line is in the form: y=mx+b

The y-intercept of the line OA=0

Therefore, we have:

[tex]y=\dfrac{4}{3}x+0\\3y=4x+0\\$Subtract 3y from both sides$\\4x-3y=0[/tex]

The equation of the line is: 4x-3y=0

Find the area under the standard normal probability distribution between the following pairs of​ z-scores. a. z=0 and z=3.00 e. z=−3.00 and z=0 b. z=0 and z=1.00 f. z=−1.00 and z=0 c. z=0 and z=2.00 g. z=−1.58 and z=0 d. z=0 and z=0.79 h. z=−0.79 and z=0

Answers

Answer:

a. P(0 < z < 3.00) =  0.4987

b. P(0 < z < 1.00) =  0.3414

c. P(0 < z < 2.00) = 0.4773

d. P(0 < z < 0.79) = 0.2852

e. P(-3.00 < z < 0) = 0.4987

f. P(-1.00 < z < 0) = 0.3414

g. P(-1.58 < z < 0) = 0.4429

h. P(-0.79 < z < 0) = 0.2852

Step-by-step explanation:

Find the area under the standard normal probability distribution between the following pairs of​ z-scores.

a. z=0 and z=3.00

From the standard normal distribution tables,

P(Z< 0) = 0.5  and P (Z< 3.00) = 0.9987

Thus;

P(0 < z < 3.00) = 0.9987 - 0.5

P(0 < z < 3.00) =  0.4987

b. b. z=0 and z=1.00

From the standard normal distribution tables,

P(Z< 0) = 0.5  and P (Z< 1.00) = 0.8414

Thus;

P(0 < z < 1.00) = 0.8414 - 0.5

P(0 < z < 1.00) =  0.3414

c. z=0 and z=2.00

From the standard normal distribution tables,

P(Z< 0) = 0.5  and P (Z< 2.00) = 0.9773

Thus;

P(0 < z < 2.00) = 0.9773 - 0.5

P(0 < z < 2.00) = 0.4773

d.  z=0 and z=0.79

From the standard normal distribution tables,

P(Z< 0) = 0.5  and P (Z< 0.79) = 0.7852

Thus;

P(0 < z < 0.79) = 0.7852- 0.5

P(0 < z < 0.79) = 0.2852

e. z=−3.00 and z=0

From the standard normal distribution tables,

P(Z< -3.00) = 0.0014  and P(Z< 0) = 0.5

Thus;

P(-3.00 < z < 0 ) = 0.5 - 0.0013

P(-3.00 < z < 0) = 0.4987

f. z=−1.00 and z=0

From the standard normal distribution tables,

P(Z< -1.00) = 0.1587  and P(Z< 0) = 0.5

Thus;

P(-1.00 < z < 0 ) = 0.5 -  0.1586

P(-1.00 < z < 0) = 0.3414

g. z=−1.58 and z=0

From the standard normal distribution tables,

P(Z< -1.58) = 0.0571  and P(Z< 0) = 0.5

Thus;

P(-1.58 < z < 0 ) = 0.5 -  0.0571

P(-1.58 < z < 0) = 0.4429

h. z=−0.79 and z=0

From the standard normal distribution tables,

P(Z< -0.79) = 0.2148  and P(Z< 0) = 0.5

Thus;

P(-0.79 < z < 0 ) = 0.5 -  0.2148

P(-0.79 < z < 0) = 0.2852

In the figure, ∆BAT ≅ ∆CAT. Which statement is not true by CPCTC? ∠CAB ≅ ∠SAB ∠CAS ≅ ∠BAS

Answers

Answer:

∠CAB ≅ ∠SAB is not true

Step-by-step explanation:

CPCTC means id ABC = XYZ, than A=X, AB=XY, C=Z and so on. Basically the number numbers that come in the same order as the other one is equal.

So ∠CAS ≅ ∠BAS is true but ∠CAB ≅ ∠SAB is not.

Hope this helps. If you have any follow-up questions, feel free to ask.

Have a great day! :)

Answer:

sap

Step-by-step explanation:

Toni runs around her school's baseball diamond. Each side is 27 m long. Note: A baseball diamond is square. How far does Toni run?

Answers

Answer:

108 m

Step-by-step explanation:

The formula to convert Fahrenheit to Celsius is C=5/9(F-32). Convert 30c to Fahrenheit. Round to the nearest degree

Answers

Answer:

86 degrees farenheit

Step-by-step explanation:

First, we plug 30 in for C.

Next, solve for F

Multiplying both sides by 9/5 gives us 54=F-32

Add 32 to both sides    86=F

what is 20% of 50naira?​

Answers

Answer:

10

Step-by-step explanation:

To find 20% of 50 you need to times 20 with 50 and divide by 100.

20×50÷100

=10

How much do wild mountain lions weigh? Adult wild mountain lions (18 months or older) captured and released for the first time in the San Andres Mountains had the following weights (pounds):
69 103 126 122 60 64
Assume that the population of x values has an approximately normal distribution.
A) Use a calculator with mean and sample standard deviation keys to find the sample mean weight x and sample standard deviation s.
B) Find a 75% confidence interval for the population average weight of all adult mountain lions in the specified region.

Answers

Answer:

Step-by-step explanation:

From the information given:

Mean [tex]\overline x = \dfrac{\sum x_i}{n}[/tex]

Mean [tex]\overline x = \dfrac{69+103+126+122+60+64}{6}[/tex]

Mean [tex]\overline x = \dfrac{544}{6}[/tex]

Mean [tex]\overline x = 90.67[/tex] pounds

Standard deviation [tex]s = \sqrt{\dfrac {\sum (x_i - \overline x) ^2}{n-1}[/tex]

Standard deviation [tex]s = \sqrt{\dfrac {(69 - 90.67)^2+(103 - 90.67)^2+ (126- 90.67) ^2+ ..+ (64 - 90.67)^2}{6-1}}[/tex]

Standard deviation s = 30.011 pounds

B) Find a 75% confidence interval for the population average weight of all adult mountain lions in the specified region.

At 75% confidence interval ; the level of significance ∝ = 1 - 0.75 = 0.25

[tex]t_{(\alpha/2)}[/tex] = 0.25/2

[tex]t_{(\alpha/2)}[/tex] = 0.125

t(0.125,5)=1.30

Degree of freedom = n - 1

Degree of freedom = 6 - 1

Degree of freedom = 5

Confidence interval  = [tex](\overline x - t_{(\alpha/2)(n-1)}(\dfrac{s}{\sqrt{n}})< \mu < (\overline x + t_{(\alpha/2)(n-1)}(\dfrac{s}{\sqrt{n}})[/tex]

Confidence interval  = [tex](90.67 - 1.30(\dfrac{30.011}{\sqrt{6}})< \mu < (90.67+ 1.30(\dfrac{30.011}{\sqrt{6}})[/tex]

Confidence interval  = [tex](90.67 - 1.30(12.252})< \mu < (90.67+ 1.30(12.252})[/tex]

Confidence interval  = [tex](90.67 - 15.9276 < \mu < (90.67+ 15.9276)[/tex]

Confidence interval  =  [tex](74.7424 < \mu <106.5976)[/tex]

i.e the lower limit = 74.74 pounds

    the upper limit = 106.60 pounds

hi if anyone is good with extraneous solutions pleaseeeeeee help meeee tessa solves the equation below by first squaring both sides of the equation√x^2-3x-6=x-1 what extraneous solution does tessa obtain x=

Answers

Answer:

x = -7/5

Step-by-step explanation:

If we square both sides of the equation, we get:

[tex]\sqrt{x^2-3x-6}=x-1\\ (\sqrt{x^2-3x-6})^2=(x-1)^2\\x^2-3x-6=x^2-2x+1\\[/tex]

Then, solving for x, we get:

[tex]x^2-3x-6=x^2-2x+1\\-3x-6=2x+1\\-6-1=2x+3x\\-7=5x\\\frac{-7}{5}=x[/tex]

So, x is equal to -7/5

Answer:

its -7

Step-by-step explanation:

gots it right!

THe graph is going further than the outline ben 10 benden

Answers

Answer:

EB = 9

Step-by-step explanation:

CD = AB

The line with the value of five that also forms a right angle with EB is a perpendicular bisector to AB.

So the value of EB is half of AB (AB is equal to CD).

18/2 = 9

need answers (ASAP!!!) with equations, please!!

Answers

Answer:

a=6, b=5.5

Step-by-step explanation:

By looking at the sides of the triangles it can easily be seen that some of the sides match up. Side b is similar to the side of 11 and same with side a and the side of 3. Since one side is 16 and the other side on the smaller triangle is 8, the bigger triangle is twice as large than the smaller one. So 3 x 2 = 6 and 11 / 2 = 5.5

Suppose that the functions g and h are defined for all real numbers x as follows.
gx = x − 3x
hx = 5x + 2
Write the expressions for (g - h)(x) and (g * h)(x) and evaluate (g + h)(−2).

Answers

Answer:

Step-by-step explanation:

Given the functions g(x) = x − 3x  and h(x) = 5x + 2, we are to calculatae for the expression;

a) (g - h)(x)  an (g * h)(x)

(g - h)(x)  = g(x) - h(x)

(g - h)(x)  = x − 3x -(5x+2)

(g-h)(x) = x-3x-5x-2

(g-h)(x) =-7x-2

b)  (g * h)(x) =  g(x) * h(x)

 (g * h)(x)  = (x − 3x )(5x+2)

(g * h)(x) = 5x²+2x-15x²-6x

(g * h)(x) = 5x²-15x²+2x-6x

(g * h)(x) = -10x²-4x

c) To get (g + h)(−2), we need to first calculate (g + h)(x) as shown;

 (g + h)(x)  an (g * h)(x)

(g + h)(x)  = g(x) +h(x)

(g + h)(x)  = x − 3x + (5x+2)

(g+h)(x) = x-3x+5x+2

(g+h)(x) =3x+2

Substituting x = -2 into the resulting function;

(g+h)(-2) = 3(-2)+2

(g+h)(-2) = -6+2

(g+h)(-2) = -4

Please help with 4d.

Answers

Answer:

(Hemingway, The Old Man and the Sea)(Orwell, 1984)

Step-by-step explanation:

A short web search will turn up the authors of the given titles:

  The Old Man and the Sea - Hemingway

  Huckleberry Finn - Twain

  Moby D.ick - Melville

  1984 - Orwell

  Crime and Punishment - Dostoevsky

f(x)=−4x−9 when x=−5.

Answers

Answer:

11

Step-by-step explanation:

x=-5

-4(-5)-9

=20-9

=11

Hope this helps, and marking me as a brainliest would help me too;)

Answer:

11

Step-by-step explanation:

We just have to plug in -5 for x and when we do so we get f(-5) = -4 * (-5) - 9 = 20 - 9 = 11.

The function f is defined as follows.
f(x) =4x²+6
If the graph of f is translated vertically upward by 4 units, It becomes the graph of a function g.
Find the expression for g(x).


G(x)=

Answers

Answer:

[tex]g(x)=4x^{2} +10[/tex]

Step-by-step explanation:

If we perform a vertical translation of a function, the graph will move from one point to another certain point in the direction of the y-axis, in another words: up or down.

Let:

[tex]a>0,\hspace{10}a\in R[/tex]

For:

y = f (x) + a: The graph shifts a units up.y = f (x)  - a, The graph shifts a units down.

If:

[tex]f(x)=4x^{2} +6[/tex]

and is translated vertically upward by 4 units, this means:

[tex]a=4[/tex]

and:

[tex]g(x)=f(x)+a=(4x^{2} +6)+4=4x^{2} +10[/tex]

Therefore:

[tex]g(x)=4x^{2} +10[/tex]

I attached you the graphs, so you can verify the result easily.

Facespace is a popular form of social media. Recent reports show that the mean time spent on Facespace is 35 minutes a day with a standard deviation of 6 minutes a day. The data is normally distributed. If 1100 people are on in one sitting, how many of them lie within one standard deviation below the mean and two standard deviations above the mean?

Answers

Answer:

897

Step-by-step explanation:

I think it deleted my prior solution because I linked the Wikipedia article for the empirical rule... So to retype this:

We'll be using the empirical, or 68-95-97.5 rule of normal distributions which says that 68% of data in a normal distribution is within 1 standard deviation, 95% is within two, and 97.5% is within three. Graphical representations of the rule can be found online and may be helpful to understand it more easily.

The first part of the problem is relatively straightforward, to get the two pieces within one standard deviation, that's 68% of the total population of 1100. So, 0.68*1100=748.

The second part is a bit trickier, since it is just the part of the second standard deviation out that is above the mean. To get this, we need to think about the difference between one standard deviation out and two, percentage-wise. Since two standard deviations out is 95% of the data, the difference between one and two is 95%-68%, or 27% of the data. However, since we only want the upper half of that, we'll just be using 13.5%. So our second piece is 13.5% of 1100, or 148.5.

Add together our two pieces, 748+148.5=896.5 and round up to 897.

Use differentials to estimate the amount of material in a closed cylindrical can that is 20 cm high and 8 cm in diameter if the metal in the top and bottom is 0.1 cm thick, and the metal in the sides is 0.1 cm thick. Note, you are approximating the volume of metal which makes up the can (i.e. melt the can into a blob and measure its volume), not the volume it encloses

Answers

Answer:

The volume is  [tex]dV = 19.2 \pi \ cm^3[/tex]

Step-by-step explanation:

From the question we are told that

    The height is  h =  20 cm

    The diameter is  d = 8 cm

    The thickness of both top and bottom is  dh  =  2 * 0.1  =  0.2 m

     The  thickness of one the side is dr =  0.1 cm

The  radius is mathematically represented as

            [tex]r = \frac{d}{2}[/tex]

substituting values

            [tex]r = \frac{8}{2}[/tex]

           [tex]r = 4 \ cm[/tex]

Generally the volume of a cylinder is mathematically represented as      

       [tex]V_c = \pi r^2 h[/tex]

Now the partial differentiation with respect to h is  

       [tex]\frac{\delta V_v}{\delta h} = \pi r^2[/tex]

Now the partial differentiation with respect to r is  

      [tex]\frac{\delta V_v}{\delta r} = 2 \pi r h[/tex]

Now the Total differential of [tex]V_c[/tex] is mathematically represented as

       [tex]dV = \frac{\delta V_c }{\delta h} * dh + \frac{\delta V_c }{\delta r} * dr[/tex]

       [tex]dV = \pi *r^2 * dh + 2\pi r h * dr[/tex]

substituting values

      [tex]dV = \pi (4)^2 * (0.2) + (2 * \pi (4) * 20) * 0.1[/tex]

     [tex]dV = 19.2 \pi \ cm^3[/tex]

(I deleted my answer because it was incorrect)

7.
The area of this parallelogram is 120 ft. Find the value of h.
1
20 ft
12 ft
3 ft
15 ft
6 ft

Answers

6ft

the area = base x height
120ft = 20ft x height
height = 120/20 = 6ft

Answer:

h = 6 ft.

Step-by-step explanation:

area = base x height

where base = 20 ft.

        height = ?

           area = 120 ft²

plugin values into the formula

120 = 20 x height

height = 120  

               20

height = 6 ft.

Change -Y + 2X = 4 to the slope-intercept form of the equation of a line.

Answers

Answer:

y=2x-4

Step-by-step explanation:

Add -2x to both sides.

-y=-2x+4

divide each side by -1 to get y=mx+b.

slope= 2

y-intercept= -4

URGENT


What is the length of?

Answers

Answer:

option (c) 4

Step-by-step explanation:

sides opposite to equal angles are equal

so ML = MN

that is 4x = x+3

4x - x = 3

3x = 3

x= 1

ML= 4x = 4*1 = 4 units

MN = x+3= 1+3= 4 units

so answer is option (c) 4

hope this answer help you

Problem 2
In the above diagram, circles O and O' are tangent at X, and PQ is tangent to both circles. Given that
OX= 3 and O'X = 8. find PQ.

Answers

Answer:

√96

Step-by-step explanation:

PQ is tangent to both lines, so PQ is perpendicular to PO and QO'.

The radius of the smaller circle is 3, and the radius of the larger circle is 8.

If we draw a line from O to O', and another line from point O to line QO' that is parallel to PQ, we get a right triangle where OO' is the hypotenuse, the short leg is 8−3=5, and the long leg is the same length as PQ.

Using Pythagorean theorem:

x² + 5² = 11²

x = √96

Which option is the correct option, quick please!

Answers

Answer:

168°

Option A is the correct option

Step-by-step explanation:

Since, we know that angle at center is double that of the circumference.

JL = 2 × 84°

calculate the product

= 168°

Hope this helps..

Best regards!!

Answer:

Option A is the correct answer.

Step-by-step explanation:

By the incribed angle theorem, we have

1/2of angle JKL.

so, JL = 84°×2

Therefore, the answer is 168°.

Hope it helps..

Given a rectangle with an area of 20 square units, if the width is x units and the length is x + 1 units, what is the difference between the length and the width?

Answers

Answer: 1unit.

Step-by-step explanation:

Area of the rectangle

A = length × width

Since the area = 20 and the width is x and the length is x + 1.

We now substitute for the values in the above formula and solve for x

20 = x × x + 1

20 = x( x + 1 ), we now open

20 = x² + x , then re arrange.

x² + x - 20 = 0, this is a quadratic equation.we solve for x using quadratic means

Here, I am going to solve using factorization by grouping

x² + x - 20 = 0

x² + 5x - 4x - 20 = 0

x( x + 5 ) - 4( x + 5 ) = 0

( x + 5 )( x - 4 ). = 0

Therefore, the solution for x will be

x = -5 or 4, but x can not be -5 ( negative), so x = 4.

Now the difference between width and the length can easily be calculated from the above,

Width = 4 (x) , and length = 5 (4 + 1),

Now difference will be

5 - 4 = 1unit.

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