Which equations represent functions that are non-linear? Select each correct answer. A. Y = x B. 2 y = 1 2 x C. Y = 8 + x D. Y − 6 = x 2 E. Y = 1 3 − 5 x F. Y = 2 x 2 + 5 − 3 x 3 I NEED HELP NOW!!!

The probability distribution function of Y = |X| is given by:

P(Y ≤ y) = P(|X| ≤ y) = P(-y ≤ X ≤ y)

Since X ~ N(0, 2), we can use the standard normal distribution to find the probability;

P(Y ≤ y) = P(Z ≤ y/√2) - P(Z ≤ -y/√2)

where Z is a standard normal random variable.

To find E(|X|), we can use the formula:

E(|X|) = √(2/π) * σ

where σ is the standard deviation of X. Since X ~ N(0, 2), σ = √2, so:

E(|X|) = √(2/π) * √2 = √(4/π)

To find Var(|X|), we can use the formula:

Var(|X|) = E(X^2) - E(|X|)^2

Since X ~ N(0, 2), E(X^2) = σ^2 = 2. And we already found E(|X|) = √(4/π), so:

Var(|X|) = 2 - (4/π) = (2π - 4)/π

Therefore, the probability distribution function of Y = |X| is P(Y ≤ y) = P(Z ≤ y/√2) - P(Z ≤ -y/√2), the expected value of |X| is E(|X|) = √(4/π), and the variance of |X| is Var(|X|) = (2π - 4)/π.

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The equation of y=x^(2) can be translated 8 units to the left and then 6 units downward by modifying the equation as follows:

y=(x+8)^(2)-6

This equation represents the same parabola as y=x^(2), but it has been shifted 8 units to the left and 6 units downward.

The translation of a function can be represented by modifying the equation in the form y=f(x-h)+k, where h is the horizontal shift and k is the vertical shift. In this case, h=-8 and k=-6, so the equation becomes:

y=f(x-(-8))+(-6)
y=f(x+8)-6

Substituting the original function f(x)=x^(2) into this equation gives:

y=(x+8)^(2)-6

Therefore, the equation of y=x^(2) when it is translated 8 units to the left and then 6 units downward is y=(x+8)^(2)-6.

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The answer is 6a+5.

Distribute the negative sign to the second polynomial:
(9a+6)-(3a+1) = (9a+6)+(-3a-1)

Combine like terms:
(9a+6)+(-3a-1) = (9a-3a)+(6-1) = 6a+5

Therefore, the answer is 6a+5.

So, the subtraction of the polynomials (9a+6)-(3a+1) is 6a+5.

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Using composition function , the price of the computer after both discounts are applied is 0.7x - 140.

To find the price of the computer after both discounts are applied, we can use composition function . Specifically, we can find the composition of f and g, denoted as f(g(x)) or (f o g)(x). This will give us the price of the computer after both discounts are applied.

To find f(g(x)), we can substitute the expression for g(x) into the function f(x):

f(g(x)) = f(0.7x) = (0.7x) - 200

So the price of the computer after both discounts are applied is (0.7x) - 200.

Alternatively, we could find the composition of g and f, denoted as g(f(x)) or (g o f)(x). This will give us the same result, since the order of the discounts does not matter.

To find g(f(x)), we can substitute the expression for f(x) into the function g(x):

g(f(x)) = g(x-200) = 0.7(x-200) = 0.7x - 140


Either way, we can see that the price of the computer after both discounts are applied is a function of the original price x, and can be represented by the composition of the functions f and g.

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The standard matrix for the stated composition of linear operators on R2 is:

The standard matrix for the stated composition of linear operators on R2 can be found by multiplying the matrices for each individual operation.

First, let's find the matrix for a rotation of 270° counterclockwise:

[tex]\textit{equation of a circle}\\\\ (x- h)^2+(y- k)^2= r^2 \hspace{5em}\stackrel{center}{(\underset{-3}{h}~~,~~\underset{6}{k})}\qquad \stackrel{radius}{\underset{5}{r}} \\\\[-0.35em] ~\dotfill\\\\ ( ~~ x - (-3) ~~ )^2 ~~ + ~~ ( ~~ y-6 ~~ )^2~~ = ~~5^2\implies (x+3)^2+(y-6)=25[/tex]

The inequality of the scenario is 8.50n + 9 ≤ 43

From the question, we have the following parameters that can be used in our computation:

Amount = $43

The cost of n books and 4 pens can be expressed as:

8.50n + 2.25(4)

We can simplify this expression:

8.50n + 9

We know the student has a total of $43 to spend, so we can set up an inequality:

8.50n + 9 ≤ 43

Subtracting 9 from both sides, we get:

8.50n ≤ 34

Dividing both sides by 8.50, we get:

n ≤ 4

Hence, the inequality that best represents the scenario is: n ≤ 4 or 8.50n + 9 ≤ 43

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Complete question

For this item, select the answers from the drop-down menus A student has $43 in total to buy books that cost \$8.50 each and pens that cost $2.25 each. The student buys n number of books and 4 pens

Complete the inequality to best represent the scenario.

The expression ((-8x⁵)(x⁻³))/(20x²) when simplified, making all exponents positive, will become -2/5.

To simplify the expression ((-8x⁵)(x⁻³))/(20x²), we need to apply the rules of exponents and simplify the coefficients.

First, let's simplify the coefficients:
-8/20 = -2/5

Next, let's apply the rules of exponents:

Product Rule: When multiplying two exponential expressions with the same base, you can add the exponents. That is, xᵃ · xᵇ = xᵃ⁺ᵇ

Quotient Rule: When dividing two exponential expressions with the same base, you can subtract the exponents. That is, xᵃ / xᵇ = xᵃ⁻ᵇ

(x⁵)(x⁻³) = x⁵⁺⁽⁻³⁾ = x²
x²/x² = x²⁻² = x⁰ = 1

So the expression simplifies to:
(-2/5)(1) = -2/5

Therefore, the simplified expression is -2/5.

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The correct answer is C. the probability of incorrectly rejecting the null hypothesis.

A P-value is used in hypothesis testing to determine the likelihood of observing a test statistic as extreme as the one observed under the null hypothesis. It is a measure of the strength of evidence against the null hypothesis.

A small P-value (typically ≤ 0.05) indicates strong evidence against the null hypothesis, so you reject the null hypothesis. A large P-value (> 0.05) indicates weak evidence against the null hypothesis, so you fail to reject the null hypothesis.

It is important to note that a P-value is not the same as the significance level (option E), which is the threshold used to determine whether to reject or fail to reject the null hypothesis.

The P-value is also not the same as the correlation between two variables (option A), which measures the strength of a linear relationship between two variables.

The P-value is also not the ratio between the test statistic and the standard error (option B), which is used to calculate the P-value but is not the same thing.

Therefore, the correct answer is option C, the probability of incorrectly rejecting the null hypothesis.

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Answer:

Mai is correct. We can use exponential notation to represent the number of coins each day. Let's call the number of coins on the first day "1". Then the number of coins on each subsequent day is twice the number of coins on the previous day. So we have:

Day 1: 1

Day 2: 2 = 2^1

Day 3: 4 = 2^2

Day 4: 8 = 2^3

...

Day n: 2^(n-1)

To find the number of coins Mai has on the 6th day, we substitute n = 6 into the formula for the number of coins:

Day 6: 2^(6-1) = 2^5 = 32

So Mai has 32 coins on the 6th day. Writing out the product of 2's (1.2.2.2.2.2.2) is equivalent to writing 2^6 = 32.

To find out how many coins Mai has after 28 days, we substitute n = 28 into the formula for the number of coins:

Day 28: 2^(28-1) = 2^27 = 134,217,728

So after 28 days, Mai has 134,217,728 coins.

The solution of the given system of the equation will be (0, 1), and (4, 9).

Simultaneous equations, a system of equations Two or more equations in algebra must be solved jointly (i.e., the solution must satisfy all the equations in the system). The number of equations must match the number of unknowns for a system to have a singular solution.

There are four methods for solving systems of equations: graphing, substitution, elimination, and matrices.

Given a system of equations such that,

y = x² - 2x +1

y = 2x + 1

By subtracting both equations we will get,

x²-2x +1 - 2x -1 = 0

x² -4x = 0

x = 0, x = 4

at this value

y = 1, y = 9

therefore, the solution of the given system of the equation will be (0, 1), and (4, 9).

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Instead of regular six-sided dice, some games use dodecahedronal - or 12-sided - dice. If you rolled a pair of dodecahedronal dice (each label 1 through 12) 100 times, you would expect the values on the two dice to add up to 4about 3 times. The correct answer is c) 3.


When rolling two dodecahedronal dice, there are a total of 12 x 12 = 144 possible outcomes. To find the probability of rolling a sum of 4, we need to look at the possible combinations that can result in a sum of 4:

1 + 3

2 + 2

3 + 1

There are a total of 3 possible combinations that can result in a sum of 4. Therefore, the probability of rolling a sum of 4 is 3/144 = 1/48.


If we roll the dice 100 times, we would expect to get a sum of 4 about (1/48) x 100 = 2.08333 times. Since we can't roll a fraction of a time, we can round this to the nearest whole number, which is 3. So, we would expect to roll a sum of 4 about 3 times out of 100 rolls.The correct answer is c) 3.

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Answer:

A, I and III

Step-by-step explanation:

The origin is the point in the center of a graph, where the x- and y-axes intersect. This point is also (0,0).

Ben's ball lands approximately 2.5 seconds after Andrew's ball.

Since the value of parameter a is -5 for both balls, the height of each ball follows the equation:

h(t) = -5t² + vt + h0

where;

Let's assume that Andrew's ball is hit with an initial velocity of v1, and Ben's ball is hit with an initial velocity of v₂. We also know that Ben's ball reaches a maximum height 50% greater than Andrew's, which means that:

h_max2 = 1.5h_max1

At the maximum height, the velocity of the ball is zero, so we can find the time it takes for each ball to reach the maximum height by setting v = 0 in the equation for h(t):

t_max1 = v₁ / (2 x 5)

t_max2 = v₂ / (2 x 5)

Since Ben's ball reaches a maximum height that is 50% greater than Andrew's, we can write:

h_max2 = 1.5h_max1

-5(t_max2)² + v₂t_max2 + h0 = 1.5(-5(t_max1)² + v1 * t_max1 + h0)

Simplifying this equation, we get:

-5(t_max2)² + v₂t_max2 = -7.5(t_max1)² + 1.5v₁t_max1

We also know that Andrew's ball lands after 4 seconds, which means that h(4) = 0:

h(4) = -5(4)² + v1 * 4 = 0

-80 + 4v1 = 0

v1 = 80/4

v1 = 20 m/s

Solving these equations for t_max2 and v2, we get:

t_max1 = v1 / (2 x 5)

t_max1 = 20 / (2 x 5)  = 2 s

t_max2 = 1.5 * t_max1 = 3 s

v2 = 1.5 * v1 = 30 m/s

To find the time it takes for Ben's ball to land, we need to find the time t2 when h(t2) = 0.

We can use the equation for h(t) with v = v2, h0 = 0, and solve for t:

-5t² + v₂t = 0

-5t² + 30 = 0

5t² = 30

t² = 30/5

t² = 6

t = √6

t = 2.5 s

Therefore, Ben's ball lands approximately 2.5 seconds after Andrew's ball.

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The property illustrated in "√2+√8 is a real number" is the closure property of addition,

The property illustrated in the given statement is the closure property of addition, which states that the sum of two real numbers is also a real number.

The closure property of addition states that the sum of any two real numbers is also a real number. In the given statement, √2 and √8 are both real numbers, and therefore their sum √2+√8 is also a real number.

This property applies to all real numbers, and it is an important property of the number system. which states that the sum of two real numbers is also a real number.

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The vector AC can be expressed in terms of vector AB and vector BC as follows:

In Euclidean geometry, a parallelogram is described as a simple quadrilateral with two pairs of parallel sides.

We have that  ABCD is a parallelogram, vector AC is equivalent to vector BD, which can be expressed in terms of vector AB and vector BC as follows:

Vector BD = Vector AB + Vector BC

We can substitute BD for AC in the above equation because  vector AC is equivalent to vector BD, we obtain the following:

Vector AC = Vector AB + Vector BC

In conclusion, vector AC can be expressed in terms of vector AB and vector BC as the sum of vector AB and vector BC.

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To get the chart that you have circled in the second picture, you need to create a table using the given formulas and then create a chart using the table. Here are the steps:

1. Create a table with the following columns: Iteration, Random, Demand, Revenue, Cost, Refund, and Profit.
2. In the first row of the table, enter the given formulas in the respective columns. For example, in the first row of the Random column, enter =RAND(), in the first row of the Demand column, enter =ROUND ( NORM.INV ( RAND(), Mean, Standard Deviation),0), and so on.
3. Copy the formulas down to the 5000th row to get the values for all 5000 iterations.
4. Select the entire table and click on the Insert tab in the Excel ribbon.
5. In the Charts group, click on the type of chart that you want to create. In this case, it looks like you want to create a scatter chart.
6. In the Chart Design tab, click on the Select Data button in the Data group.
7. In the Select Data Source dialog box, click on the Add button in the Legend Entries (Series) section.
8. In the Edit Series dialog box, enter a name for the series, select the Profit column for the Series X values, and select the Demand column for the Series Y values.
9. Click on the OK button to close the Edit Series dialog box and then click on the OK button to close the Select Data Source dialog box.
10. Your chart should now be created and should look like the one that you have circled in the second picture.

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The equation of the horizontal asymptote of P isy = 22818.18.  This means that the insect population will approach a maximum value of approximately 22818 insects, no matter how many months have passed since they were introduced. The unit of measure for this value is insects per month.

a. The equation of the horizontal asymptote can be found by taking the limit of P(t) as t approaches infinity.

lim P(t) as t approaches infinity = lim (50+251)/(2+0.011t) as t approaches infinity

Since the denominator grows without bound as t approaches infinity, the limit of P(t) approaches 251/0.011 = 22818.18. Therefore, the equation of the horizontal asymptote is:

y = 22818.18

b. The horizontal asymptote tells us the maximum population that the protected area can sustain for this type of insect. In other words, as time goes on, the insect population will approach a maximum value of approximately 22818 insects. The unit of measure for the asymptote value is insects.

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V(t)=S ert-W/r

a. The rate at which the account changes (dt/dV) is equal to the interest rate (r) times the value of the account (V) minus the amount withdrawn (W). This can be written mathematically as dt/dV=rV-W. This is a separable differential equation, which can be solved by integrating both sides of the equation with respect to time. The solution is V(t)=S ert-W/r.

b. The value of the Jones' account at the end of 10 years can be found using the solution V(t) from part a: V(10)=500,000 e5%x10-50,000/5% = $387,468.51.

c. To keep their account unchanged at $500,000, the Jones' must withdraw an annual amount W such that V(t)=500,000. From the solution V(t)=S ert-W/r, we can solve for W: W = 500,000e5%x10 - 500,000/5% = $47,613.30.

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By answering the above question, we may infer that The input value 0 equation represents the height at sea level, making it an inappropriate value for this function.

A mathematical equation links two statements and utilises the equals sign (=) to indicate equality. In algebra, an equation is a mathematical assertion that proves the equality of two mathematical expressions. For instance, in the equation 3x + 5 = 14, the equal sign separates the numbers by a gap. A mathematical formula may be used to determine how the two sentences on either side of a letter relate to one another. The logo and the particular piece of software are usually identical. like, for instance, 2x - 4 = 2.

For the predicament, the following input values would be suitable:

B) 1

C) 2

D) 3

E) 4

As the temperature drops by around 5°F for every 1,000 feet of height, we must utilise altitude numbers in thousands of feet to obtain the function's proper input values. Hence, we would utilise a value of 1 as an input for every 1,000 feet of height rise. Consequently, 1, 2, 3, and 4 would be the proper input values, which correspond to altitudes of 1,000, 2,000, 3,000, and 4,000 feet, respectively. The input value 0 represents the height at sea level, making it an inappropriate value for this function.

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Based on the graph of this linear function, the domain and range are as follows;

Domain = {0, 100}.

Range = {450, 1200}.

In Mathematics, a domain is the set of all real numbers for which a particular function is defined.

Additionally, the vertical extent of any graph of a function represents all range values and they are always read and written from smaller to larger numerical values, and from the bottom of the graph to the top.

By critically observing the graph shown in the image attached above, we can reasonably and logically deduce the following domain and range:

Domain = {0, 100}.

Range = {450, 1200}.

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Answer:

The given rectangle is not fully defined, as it is missing some measurements such as the length and width. Without this information, it is not possible to accurately calculate the perimeter of the rectangle.

However, assuming that the missing measurement is the width of the rectangle, then the expressions given by the five students would be:

2(3x + 4x + 3) = 14x + 6

2(6x + 6) + 2(4x + 6) = 20x + 24

2(3x + 3) + 2(4x + 3) = 14x + 12

2(6x + 3) + 2(4x + 3) = 20x + 12

2(6x + 3x) + 2(3 + 4x) = 18x + 10

Note that all expressions follow the formula for the perimeter of a rectangle, which is P = 2l + 2w, where l is the length and w is the width of the rectangle.

The target is 4125 feet away from the bullet.

To find the distance between the target and the bullet, we need to use the formula distance = speed × time. We have two distances to find: the distance the bullet travels and the distance the sound travels. Let's call the distance between the target and the bullet d.

The distance the bullet travels is given by:
d = 3300 × t

The distance the sound travels is given by:
d = 1100 × (t - 2.5)

Since the two distances are equal, we can set the two equations equal to each other and solve for t:

3300 × t = 1100 × (t - 2.5)
3300t = 1100t - 2750
2200t = 2750
t = 1.25

Now that we have the time, we can plug it back into one of the equations to find the distance:

d = 3300 × 1.25
d = 4125 feet

So the target is 4125 feet away from the bullet.

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We are only interested in the critical numbers on the interval [1,3], so we can disregard x = 0. Therefore, the critical numbers of the function f(x) on the interval [1,3] are x = 3.

The critical numbers of a function are the points where the derivative of the function is either zero or undefined. To find the critical numbers of the given function f(x) = x^2/(3-x), we need to first find its derivative:

f'(x) = (2x(3-x) - (-1)x^2)/ (3-x)^2 = (6x - x^2 - x^2)/ (3-x)^2 = (6x - 2x^2)/ (3-x)^2

Now, we need to find the values of x for which f'(x) = 0 or f'(x) is undefined. f'(x) is undefined when the denominator (3-x)^2 is equal to 0, which occurs when x = 3. f'(x) is equal to 0 when the numerator 6x - 2x^2 is equal to 0:

6x - 2x^2 = 0
2x(3 - x) = 0
x = 0 or x = 3

However, we are only interested in the critical numbers on the interval [1,3], so we can disregard x = 0. Therefore, the critical numbers of the function f(x) on the interval [1,3] are x = 3.

Answer: 3

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After evaluating using the correct order of operations, the result will become 22/9.

The correct order of operations is to perform any calculations inside parentheses first, then exponents, then multiplication and division from left to right, and finally addition and subtraction from left to right. This order of operations is known as PEMDAS. Using this order, we can evaluate the expression as follows:

(17)/(18) + (6)/(35) ÷ (5)/(7) x (25)/(4)

Divide 6/35 by 5/7 by multiplying 6/35 by the reciprocal of 5/7.
= (17/18) + (6/35) x (7/5) x (25/4)
= (17/18) + (6/25) x (25/4)

Multiply 6/25 by 25/4.
= (17/18) + (6/4)

Finally, add 17/18 and 6/4 together.
= 22/9

Therefore, the final answer is 22/9,

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The product of ((2)/(3)x+(4)/(3)) and (2x+(5)/(6)) as a trinomial in simplest form is (4/3)x^2 + (13/9)x + (10/9).

To express the product of ((2)/(3)x+(4)/(3)) and (2x+(5)/(6)) as a trinomial in simplest form, we need to multiply the two binomials using the distributive property.

First, we will multiply the first term of the first binomial by each term of the second binomial:
(2/3)x * 2x = (4/3)x^2
(2/3)x * (5/6) = (10/18)x = (5/9)x

Next, we will multiply the second term of the first binomial by each term of the second binomial:
(4/3) * 2x = (8/3)x
(4/3) * (5/6) = (20/18) = (10/9)

Now we will combine like terms:
(4/3)x^2 + (5/9)x + (8/3)x + (10/9) = (4/3)x^2 + (13/9)x + (10/9)

Therefore, the product of ((2)/(3)x+(4)/(3)) and (2x+(5)/(6)) as a trinomial in simplest form is (4/3)x^2 + (13/9)x + (10/9).

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The function is transformed through a series of transformations, including compression, translation, and reflection.

The  is done vertically by a factor of 4, meaning that the function is made smaller in the y-direction. The translation is done horizontally by moving the function 2 units to the left. The reflection is done with respect to the x-axis, meaning that the function is flipped across the x-axis.

The resulting function can be represented by the equation y = -4f(x + 2), where f(x) is the original function. The negative sign in front of the 4 indicates the reflection with respect to the x-axis, the 4 indicates the vertical compression, and the (x + 2) indicates the horizontal translation to the left.

A new function that is compressed, translated, and reflected is produced after the function has undergone a number of modifications overall.

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The general solution to a 2nd order derivative for f(x) with real coefficients can be obtained by finding the other root of the auxiliary equation and then using those roots to write the general solution.

Since one of the roots of the auxiliary equation is 3 + 7i, the other root must be the conjugate of this root, which is 3 - 7i. This is because the coefficients of the auxiliary equation are real, so the roots must come in conjugate pairs.

Now that we have both roots, we can write the general solution to the 2nd order derivative as:

f(x) = e^(3x)(C1*cos(7x) + C2*sin(7x))

where C1 and C2 are arbitrary constants.

This is the general solution to the 2nd order derivative for f(x) with real coefficients when one of the roots of the auxiliary equation is 3 + 7i.

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Using the sine rule and triangle ABC,   the height  is 14.43375ft. BAC=40° and ABC=30°

if C is 20° and  A is 50°

ABC=50°-20°=30°

BCA=20°+90°=110°

ABC+BCA+BAC=180°

30°+110°+BAC=180°

BAC=180°-140°=40°

Using the sine rule and triangle ABC,

opposite=x

adjacent =25 m.

tanθ =x/25

Multiplying both sides by 25 gives

x=25* tan 30° =25* 0.57735.=14.43375

To put it another way, there is only one plane that contains all of the triangles. All triangles are enclosed in a single plane on the Euclidean plane, however this is no longer true in higher-dimensional Euclidean spaces. Unless otherwise specified, this article deals with triangles in Euclidean geometry, specifically the Euclidean plane.

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