Which expressions represent the statement divided the difference of 27 and 3 by there difference of 16 and 4

Answer:424000

Step-by-step explanation:

First, you need to find out what is 8 percent of 200,000 which is 16000

So now we know that every year Tacoma's population grows by 16000

Now we calculate 16000 for 14 years which is 224000

Finally, we had the original population which was 200,000, and the people who moved to Tocoma in those 14 years which is 224000

Add it together and you get 424,000

The difference in size between the two guys is approximately -0.3108 inches, which implies that the first guy is bigger than the second guy.

To calculate the difference in size between two people, one measuring in inches and the other measuring in centimeters, we must first convert all measurements to a common unit.

Guy measures 3 inches + 1/4 inch. We can convert 1/4 inch to a decimal fraction by dividing 1 by 4, which gives us 0.25 inches. So your measurement in inches would be 3 + 0.25 = 3.25 inches.

The other guy measures 9.045 cm. To convert centimeters to inches, we use the following relationship: 1 cm = 0.3937 inches. Multiplying the measurement in centimeters by 0.3937, we get the measurement in inches: 9.045 cm * 0.3937 = 3.5608 inches (approximately).

Now we can calculate the size difference between them. We subtract the measurement of the second chavo (3.5608 inches) from the measurement of the first chavo (3.25 inches):

3.25 inches - 3.5608 inches = -0.3108 inches.

The resulting difference is -0.3108 inches. This means that the second chavo is smaller in size than the first. Since the difference is negative, it indicates that the first chavo is bigger than the second.

In summary, the difference in size between the two guys is approximately -0.3108 inches, which implies that the first guy is bigger than the second guy.

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Answer:A' = (15, -15), B' = (9, -9), and C' = (15, -9)

Step-by-step explanation:

To dilate triangle ABC with a center of dilation at the origin (0,0) and a scale factor of 3, you need to multiply the coordinates of each vertex by the scale factor.

Let's calculate the coordinates of triangle A'B'C':

For point A:

x-coordinate of A' = scale factor * x-coordinate of A = 3 * 5 = 15

y-coordinate of A' = scale factor * y-coordinate of A = 3 * (-5) = -15

Therefore, A' = (15, -15)

For point B:

x-coordinate of B' = scale factor * x-coordinate of B = 3 * 3 = 9

y-coordinate of B' = scale factor * y-coordinate of B = 3 * (-3) = -9

Therefore, B' = (9, -9)

For point C:

x-coordinate of C' = scale factor * x-coordinate of C = 3 * 5 = 15

y-coordinate of C' = scale factor * y-coordinate of C = 3 * (-3) = -9

Therefore, C' = (15, -9)

Hence, the correct coordinates of triangle A'B'C' are A' = (15, -15), B' = (9, -9), and C' = (15, -9).

Answer:

6 is the sin

Step-by-step explanation:

Let's use the fact that the sum of the angles of a triangle is always 180 degrees to solve this problem. Let the two equal angles be x, then the third angle is x + 45.Let's add all the angles together:x + x + x + 45 = 180Simplifying this equation, we get:3x + 45 = 180Now, we need to isolate the variable on one side of the equation. We can do this by subtracting 45 from both sides of the equation:3x = 135Finally, we can solve for x by dividing both sides of the equation by 3:x = 45Therefore, the value of x is 45 degrees.

Answer:

Step-by-step explanation:

180 = x + x + x + 45

180 - 45 = 3x

135 = 3x

x = 135 : 3

x = 45°

------------------

check

180 = 45 + 45 + 45 + 45

180 = 180

same value the answer is good

The value of tan(80°) × tan(10°) + sin(70°) + sin(20°) ​= 2.28171276

Trigonometry is the branch of mathematics concerned with specific functions of angles and their application to calculations. There are six functions of an angle commonly used in trigonometry. Their names and abbreviations are sine (sin), cosine (cos), tangent (tan), cotangent (cot), secant (sec), and cosecant (csc). These six trigonometric functions in relation to a right triangle are displayed in the figure.

Given:

tan(80°) × tan(10°) + sin(70°) + sin(20°)

Using Trigonometric identity

sin (A · B) = sin A cos B - cos A sin B

So, tan(80°) × tan(10°) + sin(70°) + sin(20°)

[tex]\rightarrow \tan (80 \times 10)=1[/tex]

[tex]\rightarrow\sin(70^\circ+20^\circ)=1.28171276[/tex]

[tex]\rightarrow 1.28171276+1=\bold{2.28171276}[/tex]

Hence,  tan(80°) × tan(10°) + sin(70°) + sin(20°) = 2.28171276

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The man is in the south direction from the starting point.

Let's visualize the movements of the man step by step:

The man starts by going 10 meters north.

He then turns left (which means he is now facing west) and covers 6 meters in that direction.

Next, he turns left again (which means he is now facing south) and walks 5 meters.

To determine the final direction of the man from the starting point, we can consider the net effect of his movements.

Starting from the north, he moved 10 meters in that direction. Then, he turned left twice, which corresponds to a 180-degree turn, effectively changing his direction by 180 degrees.

Since he initially faced north and then made a 180-degree turn, he is now facing south. Therefore, the direction he is in from the starting point is "south."

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The value of x in the diagram given in the question is 6

From the question given above, the following data were obtained:

The value of x can be obtained using cos ratio.

Cos θ = Adjacent / Hypotenuse

Cos 60 = 3 / x

Cross multiply

x × Cos 60 = 3

Divide both sides by Cos 60

x = 3 / Cos 60

= 3 / 0.5

= 6

Thus, the value of x is 6

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The cost per trainee for the 5-week training course is $7,000.

To find the cost per trainee, we divide the total cost of the training course by the number of trainees.

Total cost of the training course = $140,000

Number of trainees = 20

Cost per trainee = Total cost of the training course / Number of trainees

Cost per trainee = $140,000 / 20

Cost per trainee = $7,000

Therefore, the cost per trainee for the 5-week training course is $7,000.

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The systematic sample would be A. The city manager takes a list of the residents and selects every 6th resident until 54 residents are selected.

The random sample would be C. The botanist assigns each plant a different number. Using a random number table, he draws 80 of those numbers at random. Then, he selects the plants assigned to the drawn numbers. Every set of 80 plants is equally likely to be drawn using the random number table.

The cluster sample is C. The host forms groups of 13 passengers based on the passengers' ages. Then, he randomly chooses 6 groups and selects all of the passengers in these groups.

A systematic sample involves selecting items from a larger population at uniform intervals. A random sample involves selecting items such that every individual item has an equal chance of being chosen.

A cluster sample involves dividing the population into distinct groups (clusters), then selecting entire clusters for inclusion in the sample.

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Answer:

x intercept : -1

y intercept : 3

Step-by-step explanation:

We have 3x - y = -3 ---eq(1)

The x intercept is the value of x when y = 0 in eq(1),

⇒ 3x - 0 = -3

⇒ x = -3/3

⇒ x = -1

The y intercept is the value of y when x = 0 in eq(1),

⇒ 3(0) - y = -3

⇒ -y = -3

⇒ y = 3

Answer:

Step-by-step explanation:

The quadratic formula is y=ax^2+bx+c

If we move everything to the left side of the equation,

-6x^2=-9x+7 becomes

-6x^2+9x-7=0

a=-6, b=9, c=-7, so the third answer choice

(a) Based on the total attendance data provided, a bar chart can be constructed to visualize the attendance trends over time. The horizontal axis represents the years (2011, 2012, 2013, 2014), and the vertical axis represents the total attendance. The bars will correspond to the attendance numbers for each year.

(b) A side-by-side bar chart can be created to compare the attendance by visitor category with the year as the variable on the horizontal axis. The visitor categories (school, general, member) will be represented by different colors or patterns, and the bars will show the attendance for each category in each year.

(c) By analyzing the charts from parts (a) and (b), we can observe the trends in zoo attendance.

(a) The bar chart of total attendance over time shows the following trend: In 2011, the attendance was 350,621. It decreased slightly in 2012 to 341,875, remained relatively stable in 2013 at 342,340, and then decreased again in 2014 to 330,113.

(b) The side-by-side bar chart showing attendance by visitor category with year as the variable on the horizontal axis provides a visual comparison of attendance for each category over the years.

The chart reveals that the general category consistently had the highest attendance throughout the years, followed by the school category. The member category consistently had the lowest attendance.

(c) Based on the charts from parts (a) and (b), it can be observed that there has been a general decline in zoo attendance over the years, with a notable decrease from 2011 to 2014.

The drop in attendance could indicate a potential issue that the zoo needs to address in order to attract more visitors.

Additionally, the consistently lower attendance in the member category suggests that the zoo may need to reconsider its membership benefits and strategies to retain and attract more members.

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Answer: 2 1/2 pounds of more clay

Step-by-step explanation:

To calculate how much more clay Ms. Garcia needs, we need to add up the clay requirements for each grade level and then subtract the amount she already has.

For the sixth graders:

Number of students: 25

Clay required per student: 3/4 pound

Total clay required for sixth graders: 25 * (3/4) = 75/4 = 18 3/4 pounds

For the seventh graders:

Clay required for sculptures: 20 pounds

Total clay required for both grade levels: 18 3/4 + 20 = 38 3/4 pounds

Clay leftover from last year: 5 2/5 pounds

To find out how much more clay Ms. Garcia needs, we subtract the clay she already has from the total required:

38 3/4 - 5 2/5 = 38 3/4 - 27/5 = 38 3/4 - 27/5 = (155 - 108 + 3)/20 = 50/20 = 5/2 = 2 1/2 pounds

Therefore, Ms. Garcia needs an additional 2 1/2 pounds of clay.

Answer:

B

Step-by-step explanation:

SAS Similarity theorem: If two sides in one triangle are proportional to two sides in another triangle and the included angle in both are congruent, then the two triangles are similar.

Side 28 is congruent to side 11.2, whereas side 20 is congruent to side 8 and both angles are congruent. Therefore both triangles are similar.

The periods of daylight and darkness on that day are approximately:

Daylight: 202.5°

Darkness: 157.5°

Hence, the correct option is:

C. 202°3°, 157°30'

To calculate the periods of daylight and darkness on a certain day, we need to find the difference between the times of sunrise and sunset.

Sunrise time: 5.30 am

Sunset time: 7.00 pm

To find the period of daylight, we subtract the sunrise time from the sunset time:

Daylight = Sunset time - Sunrise time

First, let's convert the times to a 24-hour format for easier calculation:

Sunrise time: 5.30 am = 05:30

Sunset time: 7.00 pm = 19:00

Now, let's calculate the period of daylight:

Daylight = 19:00 - 05:30

To subtract the times, we need to convert them to minutes:

Daylight = (19 * 60 + 00) - (05 * 60 + 30)

Daylight = (1140 + 00) - (330)

Daylight = 1140 - 330

Daylight = 810 minutes

To convert the period of daylight back to degrees, we can use the fact that in 24 hours (1440 minutes), the Earth completes a full rotation of 360 degrees.

Daylight (in degrees) = (Daylight / 1440) * 360

Daylight (in degrees) = (810 / 1440) * 360

Daylight (in degrees) ≈ 202.5 degrees

To find the period of darkness, we subtract the period of daylight from a full circle of 360 degrees:

Darkness = 360 - Daylight

Darkness = 360 - 202.5

Darkness ≈ 157.5 degrees

Therefore, the periods of daylight and darkness on that day are approximately:

Daylight: 202.5°

Darkness: 157.5°

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Answer:

$7000

Step-by-step explanation:

700,000 dollars is equal to 70,000,000 pennies.

To convert 700,000 to pennies.

We need to multiply the number by 100, since there are 100 pennies in a dollar.

1 dollar = 100 pennies.

So,  700,000 × 100

= 70,000,000

Therefore, 700,000 is equal to 70,000,000 pennies.

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Answer:

8

Step-by-step explanation:

The solution to the system of equations using the inverse matrix method is x = -1, y = 2, z = 3.

To solve the system of equations using the inverse matrix method, we need to represent the system in matrix form.

The given system of equations can be written as:

| 5 -4 1 | | x | = | 12 |

| 1 7 -1 | [tex]\times[/tex]| y | = | -9 |

| 2 3 3 | | z | | 8 |

Let's denote the coefficient matrix on the left side as A, the variable matrix as X, and the constant matrix as B.

Then the equation can be written as AX = B.

Now, to solve for X, we need to find the inverse of matrix A.

If A is invertible, we can calculate X as [tex]X = A^{(-1)} \times B.[/tex]

To find the inverse of matrix A, we can use the formula:

[tex]A^{(-1)} = (1 / det(A)) \times adj(A)[/tex]

Where det(A) is the determinant of A and adj(A) is the adjugate of A.

Calculating the determinant of A:

[tex]det(A) = 5 \times (7 \times 3 - (-1) \times 3) - (-4) \times (1 \times 3 - (-1) \times 2) + 1 \times (1 \times (-1) - 7\times 2)[/tex]

= 15 + 10 + (-13)

= 12.

Next, we need to find the adjugate of A, which is obtained by taking the transpose of the cofactor matrix of A.

Cofactor matrix of A:

| (73-(-1)3) -(13-(-1)2) (1(-1)-72) |

| (-(53-(-1)2) (53-12) (5[tex]\times[/tex] (-1)-(-1)2) |

| ((5(-1)-72) (-(5(-1)-12) (57-(-1)[tex]\times[/tex](-1)) |

Transpose of the cofactor matrix:

| 20 -7 -19 |

| 13 13 -3 |

| -19 13 36 |

Finally, we can calculate the inverse of A:

A^(-1) = (1 / det(A)) [tex]\times[/tex] adj(A)

= (1 / 12) [tex]\times[/tex] | 20 -7 -19 |

| 13 13 -3 |

| -19 13 36 |

Multiplying[tex]A^{(-1)[/tex] with B, we can solve for X:

[tex]X = A^{(-1)}\times B[/tex]

= | 20 -7 -19 | | 12 |

| 13 13 -3 | [tex]\times[/tex] | -9 |

| -19 13 36 | | 8 |

Performing the matrix multiplication, we can find the values of x, y, and z.

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In general form, the equation 2x^2 - 4x + 6 = 1 can be represented as A = 2, B = -4, and C = 5.

To determine the values of A, B, and C in the general form of the quadratic equation 2x^2 - 4x + 6 = 1, we can compare the given equation with the standard form of a quadratic equation, which is ax^2 + bx + c = 0.

In the given equation, we have:

2x^2 - 4x + 6 = 1

To put it in the general form, we need to move all the terms to the left side of the equation, so the right side is equal to 0:

2x^2 - 4x + 6 - 1 = 0

2x^2 - 4x + 5 = 0

Now we can identify the coefficients A, B, and C in the general form:

A = 2 (coefficient of x^2)

B = -4 (coefficient of x)

C = 5 (constant term)

The values of A, B, and C in the general form of the equation 2x^2 - 4x + 6 = 1 are A = 2, B = -4, and C = 5.

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Domain: The domain is the range of valid heights for the mountain, which is from 3300 feet to 8920 feet.

Range: The range is the set of all possible heights of the linear model, which in this case is also from 3300 feet to 8920 feet.

Domain: The domain of the linear model in this context would represent the possible values for the x variable, which is associated with the height of the mountain.

In this case, the meaningful domain would be the range of valid heights that the mountain can have.

Since the top of the mountain is at 8920 feet and the base is at 3300 feet, the meaningful domain would be the range of heights between 3300 feet and 8920 feet.

Therefore, the domain in this scenario would be [3300, 8920].

Range: The range of the linear model in this context would represent the possible values for the y variable, which is associated with the height of the mountain.

The range would be the set of all possible heights that the linear model can produce.

In this case, since the top of the mountain is at 8920 feet and the base is at 3300 feet, the range would encompass all the valid heights within this range.

Therefore, the range in this scenario would be [3300, 8920].

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Answer:

x = 0.39 or

x = -1.72

Step-by-step explanation:

The quadrateic formula is:

[tex]x = \frac{-b\pm\sqrt{b^2 - 4ac} }{2a}[/tex]

eq: 3x² + 4x - 2

which is of the form ax² + bx + c = 0

where a = 3, b = 4 and c = -2

sub in quadratic formuls,

[tex]x = \frac{-4\pm\sqrt{4^2 - 4(3)(-2)} }{2(3)}\\\\=\frac{-4\pm\sqrt{16 + 24} }{6}\\\\=\frac{-4\pm\sqrt{40} }{6}\\\\=\frac{-4\pm2\sqrt{10} }{6}\\\\=\frac{-2\pm\sqrt{10} }{3}\\\\=\frac{-2+\sqrt{10} }{3} \;or\;=\frac{-2-\sqrt{10} }{3}\\\\=0.39 \;or\; -1.72[/tex]

Answer: E

Step-by-step explanation:

Answer:

Step-by-step explanation:

I think you have to use partial fractions. Substitution won't work because the numerator is not the derivative of the denominator. I hope I am correct on this.

I have attached just the partial fractions part of the question. I did not integrate.

The graph of the logarithmic function f(x) exhibits an increasing trend as x approaches positive infinity, while it approaches negative infinity as x approaches negative infinity. The domain is (0, +∞), and the range is (-∞, +∞).

To graph the given logarithmic function f(x), we can use the information provided in the table. The table gives us various values of x and their corresponding values of f(x). We can plot these points on a graph and connect them to visualize the function.

The table shows the following points: (1, 125), (-3, 1/25), (-2, 1/5), (-1, -1), (0, 5), (1, 125), (2, 2125), and (3, 3).

When we graph these points, we observe that the function starts at (-3, 1/25) and approaches positive infinity as x approaches positive infinity. Similarly, as x approaches negative infinity, the function approaches negative infinity.

From the graph, we can determine the domain and range of the function:

Domain: The domain of a logarithmic function is all real numbers greater than 0. In this case, since the function is defined for x = 1/5 and x = 3, the domain can be expressed as x ∈ (0, +∞).

Range: The range of a logarithmic function is all real numbers. In this case, the function takes values ranging from negative infinity to positive infinity. Therefore, the range can be expressed as f(x) ∈ (-∞, +∞).

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Answer:

Hope this helps and have a nice day

Step-by-step explanation:

To find the probability that a student is accepted at FSU or accepted at UF, we can use the concept of conditional probability and the law of total probability.

Let's denote the events as follows:

A: Accepted at FSU

B: Accepted at UF

We need to find P(A or B), which can be calculated as the sum of the probabilities of each event minus the probability of their intersection:

P(A or B) = P(A) + P(B) - P(A and B)

Given the information provided, we can calculate the probabilities:

P(A) = 0.4 (40% chance of being accepted at FSU)

P(B|A) = 0.6 (60% chance of being accepted at UF if accepted at FSU)

P(B|A') = 0.9 (90% chance of non-acceptance at UF if not accepted at FSU)

P(A and B) = P(A) * P(B|A) = 0.4 * 0.6 = 0.24 (probability of being accepted at both FSU and UF)

Now we can substitute these values into the formula:

P(A or B) = P(A) + P(B) - P(A and B)

= 0.4 + (1 - 0.4) * P(B|A') - P(A and B)

= 0.4 + 0.6 * 0.9 - 0.24

= 0.4 + 0.54 - 0.24

= 0.7

Therefore, the probability that a student is accepted at FSU or accepted at UF is 0.7, or 70%.

The area of the region bounded by the graphs of [tex]f(x) = x^3 + x^2 - 6x[/tex] and [tex]g(x) = 2x - x^2[/tex] is 69 1/3 square units.

To find the area of the region bounded by the graphs of the functions [tex]f(x) = x^3 + x^2 - 6x[/tex] and [tex]g(x) = 2x - x^2[/tex], we need to determine the points of intersection and evaluate the definite integral.

First, let's find the points of intersection by setting f(x) equal to g(x):

[tex]x^3 + x^2 - 6x = 2x - x^2[/tex]

Rearranging the equation, we get:

[tex]x^3 + 2x^2 - 8x = 0[/tex]

Factoring out an x, we have:

[tex]x(x^2 + 2x - 8) = 0[/tex]

Using the quadratic formula, we find the solutions for [tex]x^2 + 2x - 8 = 0[/tex] to be x = -4 and x = 2. Therefore, the points of intersection are (-4, -16) and (2, 4).

To calculate the area, we integrate the difference of the two functions within the bounds of -4 to 2:

Area = ∫[from -4 to 2] (f(x) - g(x)) dx

Evaluating the definite integral, we have:

Area = ∫[-4 to 2] [(x^3 + x^2 - 6x) - (2x - x^2)] dx

= ∫[-4 to 2] (x^3 + 2x^2 - 8x) dx

Integrating each term and evaluating the integral, we find:

Area = [1/4x^4 + 2/3x^3 - 4x^2] from -4 to 2

= [(1/4)(2)^4 + (2/3)(2)^3 - 4(2)^2] - [(1/4)(-4)^4 + (2/3)(-4)^3 - 4(-4)^2]

= [4/4 + 16/3 - 16] - [16/4 + (-128/3) - 64]

= 1/3 + 128/3 - 16 + 4 - 128/3 + 64

= 1/3 + 4 + 64

= 69 1/3

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