Which expressions will help you find the surface area of this net? Select all that apply.

Which Expressions Will Help You Find The Surface Area Of This Net? Select All That Apply.

Answers

Answer 1

The expression that will help in finding the surface area of the net are

9 x 51/2 x 4 x 6

What is surface area?

The external surface area of three-dimensional objects is referred to as the surface area, and is generally calculated in square units.

Calculating the surface area of certain 3D shapes requires one to use different formulas. depending on the shapes

The shapes encountered here are

rectangle = 9 x 5triangle = 1/2 x 4 x 6

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Related Questions

(1 point) Let V be the vector space of symmetric 2 x 2 matrices and W be the subspace -5 -2 W = span{ [ 4 ] [ 3 -3}} . -5 a. Find a nonzero element X in W. X b. Find an element Y in V that is not in W. Y E

Answers

a) A nonzero element X in W is:

X = [ -10  -4 ]
       [   8    6 ]

b) The matrix Y is in V because it's a symmetric 2x2 matrix, but it's not in W since it can't be formed by any linear combination of matrix A.



a. To find a nonzero element X in W, we need to find a linear combination of the given matrix in the span of W. Let's denote the given matrix as A:

A = [ -5  -2 ]
       [  4    3 ]

Since W = span{A}, a linear combination of A would be:

X = k * A

where k is any scalar value. Let's choose k = 2:

X = 2 * A = [ -10  -4 ]
                [   8    6 ]

So, a nonzero element X in W is:

X = [ -10  -4 ]
       [   8    6 ]

b. To find an element Y in V (the vector space of symmetric 2x2 matrices) that is not in W, we need a matrix that cannot be formed by any linear combination of the given matrix A.

A symmetric 2x2 matrix has the form:

Y = [ a  b ]
       [ b  c ]

Let's choose a symmetric matrix that doesn't have the same pattern as A. For example:

Y = [ 1  2 ]
       [ 2  1 ]

This matrix Y is in V because it's a symmetric 2x2 matrix, but it's not in W since it can't be formed by any linear combination of matrix A.

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April 18th is “national pet owners day.”Do you think it’s okay for people to own wild animals as pets?why and why not
Write 3 paragraphs.

Answers

Answer:

no because it put your neighbors at risk and you might get sued

Step-by-step explanation:

this has been on the news before

NEED ANSWER ASAP : The formula gives the maximum height y of a projectile launched straight up, given acceleration a and initial velocity v.


y=v^2/2a


Solve for v.




Responses


v=2ay√/a

v equals fraction numerator square root of 2 a y end root over denominator a end fraction


v=4a^2y^2

v equals 4 a squared y squared


v=4y^2/a^2

v equals fraction numerator 4 y squared over denominator a squared end fraction


v=2ay−−−√

Answers

The required expression is v = √2ay.

Let acceleration is given by: a

and initial velocity is given by: v

So, The maximum height(y) is

y= v² sinθ / 2a

As, θ=90 then

y = v² /2a

v² = 2ay

v = √2ay

Thus, the required expression is v = √2ay.

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if ABC measures 122,what does ADC measure

Answers

Answer: If ABC measures 122 degrees and ADC is an inscribed angle that intercepts the same arc as a central angle ABC, then ADC measures half of ABC which is 61 degrees

Step-by-step explanation:

Answer:

61 degrees

Step-by-step explanation

Angle extended to the circumference is half the angle at the centre

ADC = ½ ABC = ½ × 122 = 61

the figure below is reflected over x axis. what are the coordinates of the image of point v after this transformation

Answers

Note that the coordinates of V after it has been reflected over the x-axis will be: V' (3, -5)



Wht is the explanation for this?

The coordinates given are

V (3, 5)

W(5,8)

X (9, 6)

y (3, 3)

When point is reflected over the x- ais, it's y - coordinate takes on a polarized sign that is it goes from positive to negative of vice versa while the x-cordinte remains the same

So after the image on point v hs been reflected, the new coordinates for V = V' = (3, -5)

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Bruce Lovegren was born on September 27, 1950. On April 14, 1977, he purchased a $15,000 10-year term life insurance policy. What was the annual premium he paid?

Answers

Bruce Lovegren paid a monthly annual premium of $125 for his $15,000 10-year term life insurance policy.

The monthly premium can be calculated by dividing the total cost of the policy by the number of months in the policy term:

monthly premium = total cost of policy / number of months in policy term

The total cost of the policy can be calculated by multiplying the annual premium by the number of years in the policy term:

total cost of policy = annual premium * number of years in policy term

The number of months in a year is 12.

Bruce Lovegren purchased the policy on April 14, 1977, so the policy was in effect for 10 years and 8 months, or 128 months.

The annual premium as follows:

total cost of policy = $15,000

number of years in policy term = 10

annual premium = total cost of policy / number of years in policy term

annual premium = $15,000 / 10

annual premium = $1,500

monthly premium = annual premium / 12

monthly premium = $1,500 / 12

monthly premium = $125

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mekhi is studying the trend of the world's average temperature over time. he collects data about the world's average temperature between the years 1970 19701970 and 2011 20112011 (a total of 42 4242 years). here is computer output from a least-squares regression analysis on his sample (years are counted as number of years since 1970 19701970): predictor coef se coef t p constant 13.964 13.96413, point, 964 0.028 0.0280, point, 028 506.83 506.83506, point, 83 0.00 0.000, point, 00 year 0.0167 0.01670, point, 0167 0.001 0.0010, point, 001 14.79 14.7914, point, 79 0.00 0.000, point, 00 s

Answers

Answer: 7.92,110007382665669927577,E+EA099000000,000 CMM0,

Michelle started her retirement plan early by saving $200 per month since she was 20 years old. During that time, she has earned an average annual rate of 5.2% compounded monthly. Her twin brother Michael, now 40 years old, would like to catch-up with his twin sister by contributing a monthly payment for the next 20 years. How much should Michael contribute monthly, assuming that both he and his twin sister will continue to earn an annual rate of 5.2% interest, compounded monthly?

Answers

The PMT or monthly contribution is pegged at $764.57

What is a Retirement Plan?

Individuals employ a financial tactic known as a retirement plan to accumulate and invest funds, which will enable them to have access to revenue during their retirement period.

The aim of this approach is to certitude that these individuals possess ample income to maintain their standard of living and fulfil any additional monetary requirements once they terminate employment.

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Write an equation of the perpendicular bisector of the segment with the endpoints (2,1) and (6,3)

Answers

Answer:

Step-by-step explanation:

Answer

Equation of a straight line

y = -0.33x + 4.995

Answer:

Step-by-step explanation:

Find the midpoint of the segment by using the formula [(x1 + x2)/2, (y1 + y2)/2]. The midpoint is [(2 + 6)/2, (1 + 3)/2] = (4, 2).

Find the slope of the segment by using the formula (y2 - y1)/(x2 - x1). The slope is (3 - 1)/(6 - 2) = 1/2.

Find the negative reciprocal of the slope by flipping the fraction and changing the sign. The negative reciprocal is -2/1 or -2.

Find the equation of the perpendicular bisector by using the point-slope form y - y1 = m(x - x1), where m is the negative reciprocal and (x1, y1) is the midpoint. The equation is y - 2 = -2(x - 4).

Simplify the equation by distributing and rearranging. The equation is y = -2x + 10. This is the equation of the perpendicular bisector in slope-intercept form.

i really need help it’s already late by 3 days!!

Answers

a) The coordinates of K' after the translation are given as follows: K'(-2,3).

b) The coordinates of M' after the translation are given as follows: M'(-4, 1).

What are the translation rules?

The four translation rules are defined as follows:

Left a units: x -> x - a.Right a units: x -> x + a.Up a units: y -> y + a.Down a units: y -> y - a.

From the vector, the composite translation rule in this problem is given as follows:

(x,y) -> (x - 6, y + 2).

The coordinates of K and M are given as follows:

K(4,1), M(2,-1).

Hence the coordinates of the translated vertices are obtained applying the operation as follows:

K'(-2, 3) and M'(-4, 1).

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D'Angelo is reviowing potential sources for his research writing assignment. One of the articles covers his topic, but from a very different point of view, one that he is not reallyconsidoring in his thesis. While the articie.is very interesting, and seems at first glance to apply to his topic, D'Angelo is woried that this article is outside the scope of his ownpaper What aspect of fthe C.RAAP method is D'Angelo using to consider this article?O. PurposeO. RelevanceO. CurencyO. Authority

Answers

D'Angelo is reviewing potential sources for his research writing assignment and is considering an article with a different point of view. In this situation, he is using the Relevance aspect of the CRAAP method to determine if the article is appropriate for his paper.

The CRAAP method stands for Currency, Relevance, Authority, Accuracy, and Purpose, and helps evaluate the credibility and reliability of sources.

In this scenario, D'Angelo is reviewing an article that covers his topic, but from a different point of view that he is not considering in his thesis. While the article may be interesting, it may not be directly relevant to his research paper if it does not contribute to his thesis statement. D'Angelo is using the relevance aspect of the CRAAP method to evaluate whether or not to include this article in his research writing assignment. By doing so, he is ensuring that he uses sources that are directly relevant to his thesis and will help support his arguments.

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Determine the product of 15/6 and 1.2

Answers

Answer:

3

Step-by-step explanation:

QUESTION 6 dạy dy The equation of motion of a body is given byd2y/dt2 +4dy/dt +13y = e2t cost, where y is the distance dt and t is the time. Determine a general solution for y in terms of t. [12] dt2

Answers

The general solution to the differential equation is:

y(t) = y_h(t) + y_p(t) = e^(-2t)(c1 cos(3t) + c2 sin(3t)) - (1/170) e^(2t)cos(t) + (3/170) e^(2t)sin(t)

We have the differential equation:

d^2y/dt^2 + 4 dy/dt + 13y = e^(2t)cos(t)

The characteristic equation is:

r^2 + 4r + 13 = 0

Using the quadratic formula, we get:

r = (-4 ± sqrt(4^2 - 4(13)))/(2) = -2 ± 3i

So the general solution to the homogeneous equation is:

y_h(t) = e^(-2t)(c1 cos(3t) + c2 sin(3t))

To find a particular solution to the non-homogeneous equation, we can use the method of undetermined coefficients. Since e^(2t)cos(t) is of the form:

e^(at)cos(bt)

We guess a particular solution of the form:

y_p(t) = A e^(2t)cos(t) + B e^(2t)sin(t)

Taking the first and second derivatives, we get:

y'_p(t) = 2A e^(2t)cos(t) - A e^(2t)sin(t) + 2B e^(2t)sin(t) + B e^(2t)cos(t)

y''_p(t) = 4A e^(2t)cos(t) - 4A e^(2t)sin(t) + 4B e^(2t)sin(t) + 4B e^(2t)cos(t) + 2A e^(2t)sin(t) + 2B e^(2t)cos(t)

Substituting these back into the original equation, we get:

(4A + 2B) e^(2t)cos(t) + (4B - 2A) e^(2t)sin(t) + 13(A e^(2t)cos(t) + B e^(2t)sin(t)) = e^(2t)cos(t)

We can equate coefficients of like terms on both sides to get a system of equations:

4A + 2B + 13A = 1

4B - 2A + 13B = 0

Solving for A and B, we get:

A = -1/170

B = 3/170

So a particular solution to the non-homogeneous equation is:

y_p(t) = (-1/170) e^(2t)cos(t) + (3/170) e^(2t)sin(t)

Therefore, the general solution to the differential equation is:

y(t) = y_h(t) + y_p(t) = e^(-2t)(c1 cos(3t) + c2 sin(3t)) - (1/170) e^(2t)cos(t) + (3/170) e^(2t)sin(t)

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Which function is modeled in this table

Answers

Answer:

[tex]f(x) = 1000 {(0.80)}^{x - 1} [/tex]

B is the correct function.

5.4 Diagonalization: Problem 3 (1 point) Find a 2 x 2 matrix such that [2 3]and [0 3]
are eigenvectors of the matrix with eigenvalues 10 and -5, respectively. 60 0 135 -30

Answers

The matrix 2x2 of A is:

[20  30]
[ 0 -15]

What is the eigenvector?

The eigenvector is a vector that is associated with a set of linear equations. The eigenvector of a matrix is also known as a latent vector, proper vector, or characteristic vector. These are defined in the reference of a square matrix.

To solve this problem, we need to use the fact that a matrix can be diagonalized only if it has a set of linearly independent eigenvectors.

First, we need to find the eigenvectors and eigenvalues of the matrix. Let A be the matrix we want to find.

We know that [2 3] is an eigenvector of A with eigenvalue 10, so we have:

A[2 3] = 10[2 3]

Multiplying out the matrices, we get:

[2 3] [a b] = [20 30]

where a and b are the unknown entries of A. Solving this system of equations, we get a = 5 and b = 10. Therefore, the matrix A is:

[5 10]
[0 3]

Now, we need to check if [0 3] is also an eigenvector of A with eigenvalue -5:

A[0 3] = -5[0 3]

[5 10] [0 3] = [0 -15]

Multiplying out the matrices, we get:

[0 30] = [0 -15]

This is a contradiction since the two matrices are not equal. Therefore, [0 3] is not an eigenvector of A with eigenvalue -5.

In summary, the matrix A that satisfies the given conditions is:

[5 10]
[0 3]

with eigenvectors [2 3] and [0 1] and eigenvalues 10 and 3, respectively.
To find a 2x2 matrix with eigenvectors [2, 3] and [0, 3] and eigenvalues 10 and -5, respectively, follow these steps:

Step 1: Associate the eigenvectors with their respective eigenvalues:
- Eigenvector [2, 3] has eigenvalue 10.
- Eigenvector [0, 3] has eigenvalue -5.

Step 2: Write the eigenvalue-eigenvector equations:
- 10 * [2, 3] = A * [2, 3]
- (-5) * [0, 3] = A * [0, 3]

Step 3: Expand the equations:
- 10 * [2, 3] = [20, 30]
- (-5) * [0, 3] = [0, -15]

Step 4: Create the matrix A using the expanded equations:
A = [20, 30; 0, -15]

So, the 2x2 matrix A is:
[20  30]
[ 0 -15]

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. a prize is placed at random in one of three boxes. you pick a box (and do not open it). now, the dealer (who knows where the prize is) chooses one of the other two boxes, opens it and shows you that it is empty. she then gives you the opportunity to keep your original box or switch to the other unopened box. find the probability of winning the prize if you switch.

Answers

The probability of winning the prize if you switch is 2/3.

When you initially choose a box, there is a 1/3 chance that the prize is in your chosen box and a 2/3 chance that it is in one of the other two boxes.

When the dealer opens one of the other two boxes and shows it to be empty, the probability that the prize is in the remaining unopened box is still 2/3.

This is because the dealer has effectively given you new information that eliminates one of the two boxes you did not choose, but does not affect the probability distribution of the prize in the remaining two boxes.

Thus, if you switch to the other unopened box, you have a 2/3 chance of winning the prize, whereas if you stick with your original box, you have only a 1/3 chance of winning. Therefore, it is advantageous to switch.

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Solve each system by using elementary row operations on the equations or on the augmented matrix. Follow the systematic elimination procedure described in this section.
2x 1+4x 2=−4 5x1+7x 2=11

Answers

The solution to the system is [tex]$\$\left(x_{-} 1, x_{-} 2\right)=(4,-3) \$$[/tex].

To solve the system, we can use the method of elimination or Gaussian elimination.

We start by writing the system in augmented matrix form:

[tex]$$\left[\begin{array}{cc|c}2 & 4 & -4 \\5 & 7 & 11\end{array}\right]$$[/tex]

We can eliminate the [tex]$\$ x_{-} 1 \$$[/tex] variable from the second equation by subtracting 5 times the first equation from the second:

[tex]$$\left[\begin{array}{cc|c}2 & 4 & -4 \\5-5(2) & 7-5(4) & 11-5(-4)\end{array}\right] \Rightarrow\left[\begin{array}{cc|c}2 & 4 & -4 \\-3 & -13 & 31\end{array}\right]$$[/tex]

Next, we can eliminate the [tex]$\$ x_{-} 2 \$[/tex]$ variable from the first equation by subtracting twice the second equation from the first:

[tex]$$\left[\begin{array}{cc|c}2-2(-13) & 4-2(7) & -4-2(31) \\-3 & -13 & 31\end{array}\right] \Rightarrow\left[\begin{array}{cc|c}28 & -10 & -66 \\-3 & -13 & 31\end{array}\right]$$[/tex]

We can simplify this further by dividing the first row by 2 :

[tex]$$\left[\begin{array}{cc|c}14 & -5 & -33 \\-3 & -13 & 31\end{array}\right]$$[/tex]

Now we can solve for [tex]$\$ x_{-} 2 \$$[/tex] in terms of [tex]$\$ x_{-} 1 \$$[/tex] by multiplying the first equation by 13 and adding it to the second equation:

[tex]$$13(14) x_1-13(5) x_2-13(33)-3(-13) x_1-3(-13) x_2=13(31)-3(14) x_1$$[/tex]

Simplifying:

[tex]$$\begin{aligned}& 169 x_1-91 x_2-429+39 x_1+39 x_2=403 \\& 208 x_1=832 \\& x_1=4\end{aligned}$$[/tex]

Substituting back into the first equation, we get:

[tex]$$2(4)+4 x_2=-4 \Rightarrow x_2=-3$$[/tex]

Therefore, the solution to the system is [tex]$\$\left(x_{-} 1, x_{-} 2\right)=(4,-3) \$$[/tex].

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The area of a rhombus is 100. Find the length of the two diagonals if one is twice as long as the other.The length of two diagonals of the rhombus are 10 and 20.

Answers

The length of the two diagonals of a rhombus if one is twice as long as the other are 10 and 20.

Given that the length of two diagonals of the rhombus are 10 and 20.

Let d1 and d2 be the lengths of the diagonals of the rhombus. Since the area of the rhombus is 100, we have:

d1 * d2 / 2 = 100

We are also given that one diagonal is twice as long as the other, so:

d1 = 2d2

Substituting d1 = 2d2 into the first equation, we get:

2d2 * d2 / 2 = 100

d2^2 = 100

d2 = 10 or -10 (we ignore the negative solution)

Since d1 = 2d2, we have d1 = 20.

Therefore, the length of the two diagonals of the rhombus are 10 and 20.

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Find the LCM for each polynomial.
1)5x^2-20 , 3x+6

2)9c-15 , 21c-35

Please step by step!

Answers

1) To find the LCM of 5x^2-20 and 3x+6, we first factor each polynomial. 5x^2-20 = 5(x^2-4) = 5(x+2)(x-2), and 3x+6 = 3(x+2). The LCM of these two polynomials is the product of the highest powers of all the factors. The factors are 3, 5, x+2, and x-2. Since the highest power of 3 is 3^1, the highest power of 5 is 5^1, the highest power of x+2 is (x+2)^1, and the highest power of x-2 is (x-2)^1, the LCM is 3*5*(x+2)*(x-2) = 15(x^2-4).

2) To find the LCM of 9c-15 and 21c-35, we first factor each polynomial. 9c-15 = 3(3c-5), and 21c-35 = 7(3c-5). The LCM of these two polynomials is the product of the highest powers of all the factors. The factors are 3 and 7, and 3c-5. Since the highest power of 3 is 3^1, the highest power of 7 is 7^1, and the highest power of 3c-5 is (3c-5)^1, the LCM is 3*7*(3c-5) = 21(3c-5).

Let U be a nonempty open subset of RP. Let a EU. Let F (f1,..., fa): U ŹR9 be a function that is differentiable at a. Let A : RP → R9 be any affine function for which A(a) = F(a) and dA(a) = dF(a). = Prove that A(-) = F(a + dF(a(-). Remark 1. The results in A1, A2, and A3 are higher-dimensional analogues of familiar facts from Calculus I. It is a good idea to think about these problems in the special Calculus I case of p=1= q: doing so may deepen your understanding and may help you solve these problems if you are experiencing difficulties. =

Answers

We have shown that A(-) = F(a + dF(a(-)), as required.

To prove that A(-) = F(a + dF(a(-)), we need to show that the affine function A coincides with the function F at every point x in RP.

Let x be an arbitrary point in RP. We can write x = a + t, where t is a vector in the tangent space of RP at a. Since U is open in RP, we can choose a small enough neighborhood of a in U such that a + t is also in U.

Since F is differentiable at a, we can apply the multivariable chain rule to get:

dF(a + t) = dF(a) + J(a)t + o(||t||)

where J(a) is the Jacobian matrix of F at a, and o(||t||) is a term that goes to zero faster than ||t|| as t approaches zero.

Since A is affine, we can write:

A(x) = A(a + t) = A(a) + Bt

where B is a constant matrix. Since A(a) = F(a) and dA(a) = dF(a), we have:

A(x) = F(a) + dF(a)t + o(||t||)

Comparing the two expressions for A(x), we see that we can choose B = dF(a) and the remainder term o(||t||) is the same in both expressions. Therefore:

A(x) = F(a) + dF(a)t + o(||t||) = F(a + t) + o(||t||) = F(x) + o(||t||)

Since o(||t||) goes to zero faster than ||t|| as t approaches zero, we have:

A(x) = F(x)

for all x in RP. Therefore, we have shown that A(-) = F(a + dF(a(-)), as required.

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Using the distributive property, which of the following is the expanded form of −14(−8x+12y)
?

Answers

Using the distributive property, the expanded form of (−1/4)(−8x+12y) is c) 2x - 3y.

The distributive property states that when you multiply a number or a variable expression by a sum or a difference, you can distribute the multiplication over each term within the parentheses.

So, to expand the expression (−1/4)(−8x+12y), we can apply the distributive property by multiplying -1/4 to each term inside the parentheses:

(−1/4)(−8x+12y) = (−1/4) × (−8x) + (−1/4) × (12y)

= (1/4) × 8x − (1/3) × 12y

= 2x − 3y

Therefore, the expanded form of (−1/4)(−8x+12y) is 2x − 3y. Hence, the correct answer is (c) 2x-3y.

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You have a right triangle whose short leg is the length of a dry-erase marker and whose long leg is the length of the whiteboard on your table. Describe a mathematical method for accurately determining the smallest angle of this triangle.

Answers

To determine the smallest angle of the right triangle, you can use the inverse tangent function, also known as arctan.
First, measure the lengths of the short leg (the dry-erase marker) and the long leg (the whiteboard on your table). Let's call the length of the short leg "a" and the length of the long leg "b".
Then, use the formula:
tan(theta) = a/b
This formula relates the tangent of an angle (theta) to the ratio of the opposite side (a) to the adjacent side (b) in a right triangle.
To solve for the angle theta, take the inverse tangent (arctan) of both sides:
theta = arctan(a/b)

This will give you the angle in radians. To convert to degrees, simply multiply by 180/pi.
So, by measuring the lengths of the short and long legs of the right triangle and using the formula above, you can accurately determine the smallest angle of the triangle.

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Suppose Yi, i=1, 2, ,…,n, are i.i.d. random variables, each
distributed N(-3,81). Compute Pr[(-3) < Y < (-2)] for a
sample size of 36.

Answers

The probability that (-3) < Y < (-2) for a sample size of 36 is approximately 0.0385.

Given, Yi, i=1, 2, ,…,n, are i.i.d. random variables, each distributed N(-3,81),

i.e., Yi ~ N(-3,81)

We need to find Pr[(-3) < Y < (-2)] for a sample size of 36.

First, we need to standardize the variable Y as follows:

Z = (Y - μ) / σ

where μ is the mean of Y, and σ is the standard deviation of Y.

Here, μ = -3 and σ = 9 (since the standard deviation is the square root of the variance, which is given as 81).

So,

Z = (Y - (-3)) / 9 = (Y + 3) / 9

Now, we need to find Pr[(-3) < Y < (-2)] in terms of Z:

Pr[(-3) < Y < (-2)] = Pr[(-3 + 3)/9 < Z < (-2 + 3)/9]

= Pr[0 < Z < 1/9]

We can use the standard normal distribution table or calculator to find the probability of Z lying between 0 and 1/9.

Using a standard normal distribution table or calculator, we get:

Pr[0 < Z < 1/9] ≈ 0.0385

Therefore, the probability that (-3) < Y < (-2) for a sample size of 36 is approximately 0.0385.

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A snack-size bag of M&Ms candies contains 14 red candies, 14 blue, 9 green, 15 brown, 3 orange, and 8 yellow. If a candy is randomly picked from the bag, compute the following.

Answers

Answer: The probability of picking a red candy is 14/63, the probability of picking a blue candy is 14/63, the probability of picking a green candy is 9/63, the probability of picking a brown candy is 15/63, the probability of picking an orange candy is 3/63, and the probability of picking a yellow candy is 8/63. These probabilities can be calculated by dividing the number of candies of each color by the total number of candies in the bag.

Step-by-step explanation:

Answer: vvvvv

Step-by-step explanation:

The odds of getting a green M&M can be calculated by dividing the number of green M&M candies by the total number of candies in the bag.

Number of green M&Ms = 9

Total number of candies = 14 + 14 + 9 + 15 + 3 + 8 = 63

Odds of getting a green M&M = Number of green M&Ms / Total number of candies

Odds of getting a green M&M = 9/63 = 1/7

The probability of getting a green M&M can be calculated by dividing the number of green M&M candies by the total number of candies in the bag.

Probability of getting a green M&M = Number of green M&Ms / Total number of candies

Probability of getting a green M&M = 9/63 = 0.14285714285714285 or approximately 14.29% (rounded to two decimal places).

Also thanks a lot, now i want m&m's

Binomial Probability
Timothy creates a game in which the player rolls 4 dice.
What is the probability in this game of having exactly
two dice land on six? (PDF)

Answers

Answer:

4!/(2!2!) = 6

There are 6 possible ways that 2 of the 4 dice will land on six.

6(1/6)(1/6)(5/6)(5/6) = 25/216 = .116

B is correct.

Pick one 6-12 grade level that you want to teach and look at the CCSSM for that grade level, the previous grade level, and the next grade level. (If you pick 6, look at 6-7-8 and if you pick 12, look at 10-11-12. You'll need to look at the typical classes taught for each grade level at a particular school/district).
State your level of knowledge (A-F) for each standard and why. The why could be "I learned this in [insert math class] and remember it well."
Every standard that isn't an A or a B, find an example to help you make sense of that standard.

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I will pick 8th grade for this analysis, so I will look at the CCSSM for grades 7, 8, and 9.


For 7th grade:
1. 7.NS.A.1 (A): I have a strong understanding of applying operations with rational numbers, as I learned this in various math classes.
2. 7.RP.A.2 (B): I am familiar with proportional relationships, but I may need to review some specific examples to strengthen my understanding.

For 8th grade:
1. 8.EE.A.1 (A): I have a deep understanding of working with exponents, as it was a significant topic in my algebra classes.
2. 8.G.B.6 (B): I am familiar with the Pythagorean Theorem, but I may need to review some specific examples to solidify my knowledge.

For 9th grade (Algebra 1):
1. A.REI.B.3 (A): I am confident in solving linear equations, as this was a core topic in my algebra and calculus classes.
2. A.CED.A.2 (C): I understand creating equations in two variables, but I would need to review examples to ensure I fully grasp this standard.

For every standard that isn't an A or a B, I would look for examples and resources to help me better understand the concepts. For instance, for A.CED.A.2, I could find example problems involving creating and solving equations in two variables, which would help me improve my understanding of this standard.

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\left(2x^{5}-7x^{3}\right)-\left(4^{x2}-3x^{3}\right)

Answers

The expression 2x^5 - 7x^3 - (4x^2 - 3x^3) when evaluated is 2x^5 - 10x^3 - 4x^2

Evaluating the expression

From the question, we have the following parameters that can be used in our computation:

\left(2x^{5}-7x^{3}\right)-\left(4^{x2}-3x^{3}\right)

Express properly

So, we have

2x^5 - 7x^3 - (4x^2 - 3x^3)

Open the bracket

So, we have

2x^5 - 7x^3 - 4x^2 - 3x^3

Evaluate the like terms

2x^5 - 10x^3 - 4x^2

Hence, the solution is 2x^5 - 10x^3 - 4x^2

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The function y=f(x) is graphed below. Plot a line segment connecting the points on f where x=−5 and x=−3. Use the line segment to determine the average rate of change of the function f(x) on the interval −5≤x≤−3.

Answers

Use the line segment to determine the average rate of change of the function f(x) on the interval. The function y=f(x) is graphed below. Plot a line segment.:

Step-by-step explanation:



Which situation involves descriptive statistics?


A) Ten percent of the girls on the cheerleading squad are also on the track team.


B)To determine how many outlets might need to be changed, an electrician inspected 20 of them and found 1 that didn’t work.


C) A study shows that the average student leaves a four-year college with a student loan debt of more than $30,000.


D) A survey indicates that about 25% of a restaurant’s customers want more dessert options

Answers

Option C, "A study shows that the average student leaves a four-year college with a student loan debt of more than $30,000", involves descriptive statistics.

The area of statistics known as descriptive statistics deals with the gathering, organizing, organizing, analyzing, interpreting, and presenting of data. It summarizes and describes the main features of a dataset, including measures of central tendency (such as mean, median, and mode) and measures of variability (such as range, standard deviation, and variance). Option C presents a descriptive statistic (the average student loan debt) that summarizes a larger dataset, making it the correct answer.

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In this problem,we will analyze an algorithm that finds an item close enough tc the median item of a set S={a..a} of n distinct numbers. Specifically,the algorithm finds an item a such that at least n/4 items are smaller than a and at least n/4 items are greater than ai. Algorithm 1 Randomized Approximate Median(S 1:Select an item aE S uniformly at random 2:rank=1 3forj=1 tondo 4: if a

Answers

To better understand the algorithm, it would be helpful to see the complete code and understand how it iteratively compares items to find the desired item a.

The algorithm you provided is incomplete, so I cannot provide a complete answer. However, based on the information provided, the algorithm selects an item a randomly from the set S and then iteratively compares it to other items in S. The goal is to find an item a such that at least n/4 items are smaller than a and at least n/4 items are greater than a.

This algorithm is an example of a randomized approximate median algorithm, which finds an item close enough to the median of a set of numbers. While it may not always find the exact median, it provides a good approximation and runs in linear time.

To better understand the algorithm, it would be helpful to see the complete code and understand how it iteratively compares items to find the desired item a.

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