which field of science does gregor johann mendel related with ?​

Answers

Answer 1

The field of science related to Gregor Mendel is genetics since he discovered fundamental laws in this discipline.

Who was Gregor Mendel?

Gregor Mendel was a Hungarian botanist the experimented with pea plants and observed how traits are inherited across generations, which led him to develop a series of genetic rules that can be used in virtually all organisms such as the principle of independent segregation or the principle of dominance in dominant traits.

Therefore, with this data, we can see that Gregor Mendel developed important experiments in genetics and discovered the basis of this field.

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Related Questions

How are plants affected by an increase in thermal energy on Earth?
There are fewer plants growing.
The plants release more heat.
Plants produce more pollen.
Plants grow less.

I will give whoever answer correctly 15 points AND brainlyest.

Answers

Answer:

The plants release more heat

An increase in thermal energy on Earth can have a number of effects on plants. Firstly, it can lead to higher temperatures, which can cause some plants to experience decreased growth and increased stress. Additionally, high temperatures can reduce the amount of water available for plants, leading to drought-like conditions in some areas. This can also have a negative effect on the growth of plants. An increase in thermal energy can also lead to an increase in pollen production due to plants flowering earlier in the season, which can be a major problem for people with allergies.

how does the disturbance travel through the coil when you move your arm back and forth?

Answers

The medium of transmission, the oscillating material that revolves around a fixed point with little translational motion, limits the wave's ability to travel.

When a spring toy is moved up and down, what kind of disturbance is caused?

Longitudinal Waves and Transverse Waves: In Figure 13.3, a woman moves a toy spring up and down, causing waves to propagate away from her in the horizontal direction while disturbing the toy spring in the vertical direction. This is an illustration of a transverse wave.

What kind of wave goes back and forth?

Longitudinal Waves: The particles do not follow the wave as it travels down the tube. They simply move in and out of their respective equilibrium positions.

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as you shift mass from one hanger to the other for each successive data run what changes?

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As mass is shifted from one hanger to the other several changes that occur are net force acting, acceleration, tension in string , displacement of system changes.

The net force acting on the system changes: The net force acting on the system is equal to the difference in the weights of the masses on the two sides. As mass is shifted from one hanger to the other, the weights on each side change, and therefore the net force acting on the system changes.

The acceleration of the system changes: The acceleration of the system is directly proportional to the net force acting on it, and inversely proportional to the total mass of the system. As the net force acting on the system changes, so does its acceleration.

The tension in the string changes: The tension in the string connecting the two masses is equal to the force required to accelerate the masses. As the acceleration of the system changes, so does the tension in the string.

The displacement of the system changes: The displacement of the system refers to the difference in height between the two masses. As mass is shifted from one hanger to the other, the displacement of the system changes, and this can affect the acceleration and tension in the string.

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The following data were collected from a 0.4 in. diameter test specimen of polyvinyl chloride (l0=2.0in):Load (lb) Length Increment(in.)0 0.00000300 0.00746600 0.01496900 0.023741200 0.0321500 0.0461660 0.070 (maximum load)1600 0.0941420 0.12 (fracture)After fracture, the total length was 2.09 in. and the diameter was 0.393 in. Plot the data and calculate(a) the 0.2% offset yield strength;(b) the tensile strength;(c) the modulus of elasticity;

Answers

The modulus of elasticity is 457,400 psi.

To calculate the required values, we need to first plot the data as a stress-strain curve.

To do this, we will first calculate the engineering stress (σ) and engineering strain (ε) using the following formulas:

σ = Load / Area

ε = Increment in length / Original length

where the area of the test specimen is given by:

Area = π/4 x (diameter)² = π/4 x (0.4 in)² = 0.1257 in²

Using these formulas, we can create the following table:

Load (lb)      Length Increment (in.)       σ (psi)                    ε

0                        0.000003                          0                         0

300                   0.0074                               2,386              0.0037

600                   0.0149                                4,772              0.00745

900                    0.0237                              7,158               0.01185

1200                   0.0321                               9,543             0.01605

1500                   0.0461                               11,929            0.02305

1600                   0.070                                 12,719            0.035

1420                   0.0941                                11,378            0.0475

Next, we can plot the stress-strain curve using this data, using the curve the following data is obtained:

(a) To calculate the 0.2% offset yield strength, we need to draw a line parallel to the elastic region of the stress-strain curve that intersects the x-axis at a strain of 0.002. We can see from the graph that this line intersects the stress-strain curve at a stress of approximately 7,800 psi. Therefore, the 0.2% offset yield strength is 7,800 psi.

(b) The tensile strength is the maximum stress achieved during the test, which occurs at the maximum load of 1,600 lb. We can see from the graph that this corresponds to a stress of approximately 12,700 psi. Therefore, the tensile strength is 12,700 psi.

(c) To calculate the modulus of elasticity, we need to determine the slope of the linear region of the stress-strain curve. We can see from the graph that this region occurs up to a strain of approximately 0.01. Using the two points on the curve that corresponds to a strain of 0.0037 and 0.01185, we can calculate the slope using the formula:

Modulus of elasticity = (Stress at point 2 - Stress at point 1) / (Strain at point 2 - Strain at point 1)

Modulus of elasticity = (7,158 psi - 2,386 psi) / (0.01185 - 0.0037) = 457,400 psi

Therefore, the modulus of elasticity is 457,400 psi.

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what are the two major hazards of electricity?

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The two major hazards of electricity are electric shock and fire.

Electric shock occurs when a person comes into contact with an electric current. This can result in serious injury or even death. The severity of the shock depends on the amount of current that passes through the body and the length of time the person is in contact with the current.

Fire is another major hazard of electricity. Electrical fires can be caused by faulty wiring, overloaded circuits, or the improper use of electrical appliances. These fires can quickly spread and cause extensive damage to property and can also result in injury or death.

It is important to take safety precautions when dealing with electricity to prevent these hazards from occurring. This includes using proper wiring and circuit breakers, avoiding overloading outlets, and following the manufacturer's instructions when using electrical appliances.

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In a ____________ circuit, the total resistance is bigger than the smallest resistance in the circuit

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In a series circuit I believe

a particle moves along a straight line with equation of motion s = f(t), where s is measured in meters and t in seconds. find the velocity and speed when t = 5. f(t) = 100 50t − 4.6t2

Answers

When t = 5, the velocity is 50.2 m/s and the speed is also 50.2 m/s.

The equation of motion is given by:

s = 100t + 50t^2 - 4.6t^3

To find the velocity, we need to take the derivative of s with respect to time t:

v = ds/dt = 100 + 100t - 13.8t^2

Substituting t = 5 in the above equation, we get:

v = 100 + 100(5) - 13.8(5)^2 = 50.2 m/s

To find the speed, we need to take the absolute value of the velocity:

speed = |v| = 50.2 m/s

Therefore, when t = 5, the velocity is 50.2 m/s and the speed is also 50.2 m/s.

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Electrolytes are compounds that conduct electricity in aqueous solutions. For a compound to be considered an electrolyte, what must happen when it dissolves in water?

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When a compound dissolves in water to become an electrolyte, it must dissociate or break apart into ions.

These ions are then able to carry an electrical charge and conduct electricity in the aqueous solution. The greater the degree of dissociation, the stronger the electrolyte will be.

For example, when sodium chloride (NaCl) dissolves in water, it dissociates into sodium ions (Na+) and chloride ions (Cl-). These ions are then able to conduct electricity in the solution.

In contrast, a compound that does not dissociate into ions when dissolved in water is considered a nonelectrolyte and will not conduct electricity.

In summary, for a compound to be considered an electrolyte, it must dissociate into ions when dissolved in water, allowing it to conduct electricity in the aqueous solution.

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a 40 watt bulb is run for 3 seconds. how much energy is used

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The energy which is used by the light bulb is 120 J.

What is Power?

Power is defined as the amount of energy transferred or changed per unit time. The unit of power is the watt, which is equal to one joule per second. Power is the scalar quantity as it has only magnitude.

The formula for evaluating the power consumed is given by,

Power = Energy Used / Time Taken

Given,

Power Consumed (P) = 40 Watt

Time for which it has been operated (t) = 3 seconds

So, Energy Used = Power Consumed * Time Taken

Energy Used = 40 * 3 = 1200 J

Therefore, the energy used by the light bulb is 120 J.

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An old lightbulb draws only 50. 0 W, rather than its original 60. 0 W, due to evaporative thinning of its filament. By what factor is its diameter reduced, assuming uniform thinning along its length

Answers

The diameter of the filament has been reduced by a factor of 0.833 or approximately 17%.

The power of a light bulb is related to the resistance of its filament by the equation: P = [tex]V^{2}[/tex]/R

where P is the power, V is the voltage, and R is the resistance. Assuming the voltage remains constant, we can write: R = [tex]V^{2}[/tex]/P

If the filament of the light bulb has thinned uniformly along its length, then its resistance will increase. We can express the new resistance in terms of the old resistance as:

[tex]R_{new}[/tex] = k x [tex]R_{old}[/tex]

where k is the factor by which the diameter is reduced. Since the power has decreased by a factor of 60 W/50 W = 1.2, we have:

[tex]R_{new}[/tex]= [tex](1/1.2)^2[/tex] x [tex]R_{old}[/tex] = 0.694 x [tex]R_{old}[/tex]

Substituting this expression for [tex]R_{new}[/tex] in the equation for k, we get:

k = ([tex]R_{new}[/tex]/[tex]R_{old}[/tex])[tex]^(1/2)[/tex] = 0.833

Therefore, the diameter of the filament has been reduced by a factor of 0.833 or approximately 17%.

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A 24 V potential difference is applied across a parallel combination of four 6 Ω resistor. The current in each resistor is: A. 1 A B. 4 A C.16 A D. 36 A

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A 24 V potential difference is applied across a parallel combination of four 6 Ω resistors. The current in each resistor is 16 A. Therefore, option C is correct.

Use Ohm's Law, which states that the current (I) flowing through a resistor is equal to the voltage (V) across the resistor divided by its resistance (R).

A parallel combination of four 6 Ω resistors, which means the total resistance ([tex]R_{total}[/tex]) is given by the reciprocal of the sum of the reciprocals of each resistor's resistance:

[tex]1/R_{total}[/tex] = 1/R₁ + 1/R₂ + 1/R₃ + 1/R₄

= 1/6 Ω + 1/6 Ω + 1/6 Ω + 1/6 Ω

= 4/6 Ω

[tex]R_{total}[/tex]= 6/4 Ω

= 3/2 Ω

Use Ohm's Law to find the current in each resistor:

I = V/R_total

I = 24 V / (3/2 Ω)

I = 24 V × (2/3 Ω)

I = 16 A

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n-polarized light falls on two polarizer sheets whose transmission axes are at right angles. A third polarizer is placed between the first two so that its axis makes a 52° angle with the axis of the first polarizer.a) What fraction of the incident light intensity is transmitted through the first polaroid?b) What fraction of the incident light intensity is transmitted through the second polaroid.c) What is the angle of polarization of the light that enters the third polaroid?d) What fraction of the incident light intensity is transmitted through the third polaroid. e) What happens if the middle polaroid is removed?

Answers

a) The fraction of the incident light intensity transmitted through the first polaroid is 1/2.

b) The fraction of the incident light intensity transmitted through the second polaroid is 0.144.

c) The angle of polarization of the light that enters the third polaroid is 52°.

d) The fraction of the incident light intensity transmitted through the third polaroid is 0.072.

e) If the middle polaroid is removed, the fraction of the incident light intensity transmitted through the system is 0.144

a) The first polaroid only transmits the component of the incident light that is parallel to its transmission axis. Since the incident light is unpolarized, half of its intensity is parallel to the transmission axis of the first polaroid, and the other half is perpendicular. Therefore, the fraction of the incident light intensity transmitted through the first polaroid is 1/2.

b) The second polaroid only transmits the component of the light that is parallel to its transmission axis and that has already passed through the first polaroid. Since the transmission axes of the two polaroid's are at right angles, no light that is perpendicular to the transmission axis of the first polaroid can pass through the second polaroid. The light that passed through the first polaroid has its intensity reduced to half, so the fraction of the incident light intensity transmitted through the second polaroid is 1/2 times cos^2(52°) = 0.144.

c) The light that passed through the first polaroid and is incident on the third polaroid is polarized along the transmission axis of the first polaroid. The third polaroid has its transmission axis at an angle of 52° with respect to the transmission axis of the first polaroid. Therefore, the angle of polarization of the light that enters the third polaroid is also 52°.

d) The third polaroid only transmits the component of the light that is parallel to its transmission axis and that has already passed through the first two polaroid. The light that passed through the first polaroid has its intensity reduced to half, and the light that passed through the second polaroid has its intensity reduced to 1/2 times cos^2(52°) = 0.144. Therefore, the fraction of the incident light intensity transmitted through the third polaroid is 1/2 times 0.144 = 0.072.

e) If the middle polaroid is removed, the light that passed through the first polaroid is no longer blocked by the second polaroid, so all of its intensity can pass through. Therefore, the fraction of the incident light intensity transmitted through the system is 1/2 times cos^2(52°) = 0.144.

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what are the energies of the lowest eight energy levels in a three-dimensional box with a=b=c ?

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The energies of the lowest eight energy levels in a three-dimensional box with a=b=c are h^2/(8*m*L^2), h^2/(2*m*L^2), (9/8)*h^2/(m*L^2), 2*h^2/(m*L^2), (25/8)*h^2/(m*L^2), (36/8)*h^2/(m*L^2), (49/8)*h^2/(m*L^2), and 8*h^2/(m*L^2).

The energies of the lowest eight energy levels in a three-dimensional box with a=b=c are given by the equation E = (n^2*h^2)/(8*m*L^2), where n is the quantum number, h is Planck's constant, m is the mass of the particle, and L is the length of the box.

For the lowest energy level, n = 1, so the energy is E = (1^2*h^2)/(8*m*L^2) = h^2/(8*m*L^2).

For the next seven energy levels, the quantum numbers are n = 2, 3, 4, 5, 6, 7, and 8. The energies for these levels are:

E = (2^2*h^2)/(8*m*L^2) = 4*h^2/(8*m*L^2) = h^2/(2*m*L^2)

E = (3^2*h^2)/(8*m*L^2) = 9*h^2/(8*m*L^2) = (9/8)*h^2/(m*L^2)

E = (4^2*h^2)/(8*m*L^2) = 16*h^2/(8*m*L^2) = 2*h^2/(m*L^2)

E = (5^2*h^2)/(8*m*L^2) = 25*h^2/(8*m*L^2) = (25/8)*h^2/(m*L^2)

E = (6^2*h^2)/(8*m*L^2) = 36*h^2/(8*m*L^2) = (36/8)*h^2/(m*L^2)

E = (7^2*h^2)/(8*m*L^2) = 49*h^2/(8*m*L^2) = (49/8)*h^2/(m*L^2)

E = (8^2*h^2)/(8*m*L^2) = 64*h^2/(8*m*L^2) = 8*h^2/(m*L^2)

So, the energies of the lowest eight energy levels in a three-dimensional box with a=b=c are h^2/(8*m*L^2), h^2/(2*m*L^2), (9/8)*h^2/(m*L^2), 2*h^2/(m*L^2), (25/8)*h^2/(m*L^2), (36/8)*h^2/(m*L^2), (49/8)*h^2/(m*L^2), and 8*h^2/(m*L^2).

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takes an array t of times as mandatory argument; takes the mandatory argument omega to set the frequency; returns an array of the same size as t in which θ(t) was evaluated for each element in t

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This function calculates the angular frequency, θ, for each element in the array, t as It takes t as a mandatory argument and omega as the frequency and returns an array of the same size as t with the evaluated θ(t) for each element.

To answer this question, we can use the formula for θ(t) = omega * t to evaluate each element in the array t.

We can do this by creating a new array of the same size as t and using a for loop to iterate through each element in t, evaluating θ(t) for each element, and storing the result in the new array. Here is the code in Python:

```
def evaluate_theta(t, omega):
 # Create a new array of the same size as t
 theta = [0] * len(t)
 # Iterate through each element in t
 for i in range(len(t)):
   # Evaluate θ(t) for each element in t
   theta[i] = omega * t[i]
 # Return the new array
 return theta
```

This function takes an array t of times as a mandatory argument and a mandatory argument omega to set the frequency. It returns an array of the same size as t in which θ(t) was evaluated for each element in t.

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A 1.0 cm -diameter rod carries a 50 A current when the electric field in the rod is 1.3 V/m .What is the resistivity of the rod material? (Express your answer using two significant figures.)

Answers

The resistivity of the rod material is [tex]2.0 \times 10^{-6}[/tex] Ω·m (to two significant figures).

The resistivity of the rod material can be calculated using the equation for resistivity, which is:

ρ = E / J

where ρ is the resistivity, E is the electric field, and J is the current density.

To find the current density, we need to divide the current by the cross-sectional area of the rod:

J = I / A

where I is current and A is the cross-sectional area.

Since the diameter of the rod is 1.0 cm, the radius is 0.5 cm or 0.005 m.

The cross-sectional area of the rod is:

A = πr^2

A = π(0.005 m)^2

A = 7.854 × 10^-5 m^2

Now we can find the current density:

J = I / A

J =[tex]50 A / 7.854 \times 10^{-5}m^2[/tex]

J = 636619.772

Finally, we can calculate the resistivity:

ρ = E / J

=> 1.3 V/m / 636619.772 A/m^2

=>  [tex]2.04 \times 10^{-6}[/tex]Ω·m

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A physicist uses a cylindrical metal can 0.270 mm high and 0.090 mm in diameter to store liquid helium at 4.22 KK; at that temperature the heat of vaporization of helium is 2.09×104J/kg2.09×104J/kg. Completely surrounding the metal can are walls maintained at the temperature of liquid nitrogen, 77.3 KK, with vacuum between the can and the surrounding walls.
How much helium is lost per hour? The emissivity of the metal can is 0.200. The only heat transfer between the metal can and the surrounding walls is by radiation.

Answers

The amount of helium lost per hour is 6.13×10⁻⁸ kg.

To find out how much helium is lost per hour, we need to calculate the heat transfer rate between the metal can and the surrounding walls by radiation. The heat transfer rate by radiation is given by the formula:

Q = εσA(T₁⁴ - T₂⁴)

where Q is the heat transfer rate, ε is the emissivity of the metal can, σ is the Stefan-Boltzmann constant (5.67×10⁻⁸ W/m²K⁴), A is the surface area of the metal can, T₁ is the temperature of the metal can, and T₂ is the temperature of the surrounding walls.

Using the given values, we can calculate the heat transfer rate as follows:

Q = (0.200)(5.67×10⁻⁸)(π(0.090)² + 2π(0.090/2)(0.270))(4.22⁴ - 77.3⁴)

Q = -3.57×10⁻³ W

Now, to find out how much helium is lost per hour, we need to divide the heat transfer rate by the heat of vaporization of helium:

Q/ΔHv = m/t-3.57×10⁻³ W / (2.09×10⁴ J/kg)

= m / (1 hour)(1 hour)(1 kg)(1000 J) / (2.09×10⁴ J)(1 W)(3600 s)

= m / (-3.57×10⁻³ W)m

= 6.13×10⁻⁸ kg

Hence, 6.13×10⁻⁸ kg of helium is lost per hour in the can.

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You have an infinite line of charge with an electric field strength of 800 N/C at a point 12 cm away. What is the line's linear charge density?
Express your answer with the appropriate units.
lambda = ?

Answers

The required linear charge density when electric field strength is calculated to be 4.44 × 10⁻⁸ C/m.

Electric field strength is given as 800 N/C.

The distance on an infinite line of charge is given as 12 cm.

The expression for electric field at a distance r is given as,

E = λ/2πε₀r

where,

E is the Electric field strength

r is the distance

ε₀ is electric permittivity (8.85 × 10⁻¹²F/m)

When we enter the numbers into the equation, we get,

E = λ/2πε₀r

Making λ as subject, we have,

λ = E × 2πε₀r = 800 × 2π × 8.85×10⁻¹² = 44462.4 × 10⁻¹² C/m = 4.44 × 10⁻⁸ C/m

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The full moon has an apparent magnitude of roughly:________

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A full Moon is typically described as having a brightness of magnitude -13, or 400,000 times fainter than that of the Sun, or around 14 magnitudes. The Moon is actually as dark as weathered asphalt, having a typical albedo, or reflectance, of just 13%.

How big does a planet appear to be?

He gave the brightest stars in the sky an apparent magnitude of 1, and the faintest ones he observed had an apparent magnitude of 6. He excluded the sun, moon, and planets from his system.

What is the apparent magnitude that is highest?

The brightest apparent magnitude star, Sirius, has been given a magnitude of 1.5 on the current magnitude scale. Much brighter celestial bodies occasionally occur. Venus

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Because sound is a wave, it's possible to make a diffraction grating for sound from a large board of sound-absorbing material with several parallel slits cut for sound to go through. When 9. 0 kHz sound waves pass through such a grating, listeners 12 mfrom the grating report "loud spots" 1. 3 m on both sides of center.


What is the spacing between the slits?


Use 340 m/s for the speed of sound.

Answers

The first-order maxima correspond to m = 1, angle can be found using tanθ = opposite/adjacent. Therefore, θ = tan^-1(1.3/12) = 6.23 degrees. The wavelength of the 9.0 kHz sound wave can be found using equation λ = v/f, where v is the speed of sound (340 m/s) and f is frequency (9.0 kHz = 9000 Hz). Therefore, λ = 0.038 m.

Substituting values: dsin6.23° = 1(0.038 m). d = 0.38 mm. A diffraction grating for sound can be created using a large board of sound-absorbing material with several parallel slits. In problem, spacing was found to be 0.38 mm for a grating produced "loud spots" 1.3 m away from center when 9.0 kHz sound waves were passed through it.

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A tennis ball on Mars, where the acceleration due to gravity is 0.379 g and air resistance is negligible, is hit directly upward and returns to the same level 6.20 s later.a) How high above its original point did the ball go?b) How fast was it moving just after being hit?

Answers

A tennis ball on Mars, where the acceleration due to gravity is 0.379 g and air resistance is negligible, is hit directly upward and returns to the same level 6.20 s later. a) Δy = 7.53 m b) V = 7.41 m/s is the velocity.

A moving object's speed and direction are denoted by the scientific word velocity. Due to the fact that it is a vector quantity, it possesses both magnitude and direction. Different units, such as metres per second (m/s), feet per second (ft/s), or kilometres per hour (km/h), can be used to measure velocity. The relationship between time and distance gives the formula for calculating velocity: V=distance/time. Velocity is measured in metres per second (m/s), the SI unit. In physics, the concept of velocity is crucial since it clarifies how objects move. Depending on the forces acting on an object, its velocity may be constant, fluctuating, or even zero.

a) Δy = V₀t + 1/2at²

Δy = 0 + 1/2(0.379g)(6.20 s)²

Δy = 7.53 m

b) V = V₀ + at

V = 0 + (0.379g)(6.20 s)

V = 7.41 m/s

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. why are the coldest temperatures in the lowest 50 km on earth generally at the tropical tropopause?

Answers

The coldest temperatures in the lowest 50 km on Earth are generally found at the tropical tropopause because of the relatively low air density and lack of solar heating at this altitude. The tropical tropopause is located at around 12-18 km, meaning that temperatures will drop as you move lower.

The coldest temperatures in the lowest 50 km on Earth are generally at the tropical tropopause because of the presence of very dry and thin air at this altitude. The tropical tropopause is the boundary between the troposphere and the stratosphere in the tropical regions of the Earth. It is located at an altitude of approximately 17 km above the Earth's surface. At the tropical tropopause, the air is very dry and thin, which allows for very little heat to be retained. This causes the temperature to drop significantly, resulting in the coldest temperatures in the lowest 50 km on Earth. Additionally, the tropical tropopause is located at a higher altitude than the polar tropopause, which also contributes to the colder temperatures at this altitude. In conclusion, the coldest temperatures in the lowest 50 km on Earth are generally at the tropical tropopause due to the presence of very dry and thin air at this altitude, which allows for very little heat to be retained.

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There is an AC source which is connected to a 23.5μF capacitor and has a frequency of 59.5Hz and an rms voltage of 480V.
a). What rms current flows through this circuit?
b). What would the rms current be if the source frequency was changed to 0.25kHz?

Answers

There is an AC source which is connected to a 23.5μF capacitor and has a frequency of 59.5Hz and an rms voltage of 480V. rms current flows through this circuit is:

a) The rms current that flows through the circuit can be calculated using the formula: I = V/Xc where I is the rms current, V is the rms voltage, and Xc is the capacitive reactance. The capacitive reactance can be calculated using the formula: Xc = 1/(2πfC) where f is the frequency and C is the capacitance. Plugging in the given values, we get:

Xc = 1/(2π × 59.5Hz × 23.5μF) = 114.28Ω

I = 480V/114.28Ω = 4.20A

Therefore, the rms current that flows through the circuit is 4.20A.

b) If the source frequency is changed to 0.25kHz, the capacitive reactance will change and thus the rms current will also change. We can calculate the new rms current using the same formula as before, but with the new frequency value:

Xc = 1/(2π × 0.25kHz × 23.5μF) = 27.08Ω

I = 480V/27.08Ω = 17.72A

Therefore, the rms current with the new source frequency of 0.25kHz is 17.72A.

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how are analog and digital signals similar? check all that apply

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Both audio and video as well as data may be communicated through wired or wireless lines. These all convey information along a transmission medium.

Uses for wireless communication

Information is transmitted over the air utilizing electromagnetic waves such as satellite, RF (Radio Frequency), and infrared (IR). For instance, Bluetooth, Wi-Fi, GPS, satellite television, mobile computer components, and wireless phones with 3G and 4G networks.

What are some fundamental wireless communications?

Information can be sent wirelessly among two or more sites without a physical link. Wireless communication benefits from the lack of a "physical infrastructure" due to this. This frequently entails shrinking time or space.

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Second exercise (7 points) Role of a fuse In order to show evidence of the role of a fuse, we construct the circuit of the adjacent figure. This circuit includes in series : - a generator (G) delivering across its terminals a constant voltage UPN = U = 24 V. P - two identical lamps (L₁) and (L₂) considered as resistors, carrying the indications (12 V; 0.6 A). - a fuse (F) of negligible resistance carrying the indication 0.65 A. 1) a) Give the significance of each of the indications carried by the lamps. 2) The voltage across (F) is zero. b) Determine the values of the voltages U₁and U₂ across the terminals of (L₁) and (L₂) respectively. c) deduce that the lamps function normally. d) What is then the value of the current I through the circuit? A (F) (G) (L₁) B (L₂)​

Answers

a) The indication "12 V" for each lamp means that when the lamp is connected to a voltage source, it will consume a voltage of 12 volts. The indication "0.6 A" for each lamp means that when the lamp is consuming 12 volts, it will draw a current of 0.6 amperes.

b) Since the fuse has negligible resistance, the voltage drop across it will be negligible. Therefore, the voltage across the lamps (L1 and L2) will be equal to the voltage of the generator (U), which is 24 V. Thus, U1 = U2 = 24 V.

c) Since the voltage across each lamp is within its specified range (12 V), and the current through each lamp is also within its specified range (0.6 A), we can conclude that the lamps are functioning normally.

d) The total current in the circuit is the sum of the currents through the lamps and the fuse. Since the lamps are identical and the voltage across them is the same, their currents will also be the same. Therefore, the total current I is given by:

I = I1 + I2 + Ifuse

Since each lamp consumes 12 V and draws 0.6 A, their resistance can be calculated as:

R = V/I = 12/0.6 = 20 Ω

Therefore, the total resistance of the circuit is:

Rtotal = 2R + Rfuse

Since the lamps are identical, their resistance adds up. We add the resistance of the fuse, which is negligible, so we can consider it as zero. Thus,

Rtotal = 2(20 Ω) + 0 Ω = 40 Ω

Now we can calculate the total current I using Ohm's law:

I = V/Rtotal = 24/40 = 0.6 A

Therefore, the current through the circuit is 0.6 A.

A 10lb block is in equilibrium. What is the magnitude of the frictional force between this block and the surface?

Answers

The magnitude of the frictional force must be equal to the weight of the block, which is 10lb.

To determine the magnitude of the frictional force between the 10lb block and the surface, we need to know the other forces acting on the block.

If the block is in equilibrium, that means the net force acting on it is zero. In other words, the forces pulling the block in one direction are balanced by the forces pulling it in the opposite direction.

One of the forces acting on the block is its weight, which is 10lb (assuming the acceleration due to gravity is 9.8 m/s²). The other force is the normal force exerted by the surface on the block, which is equal in magnitude but opposite in direction to the weight force.

Since the block is not moving, the frictional force acting on it must be equal and opposite to the force that would make it start moving (i.e. the maximum static frictional force).

So, the magnitude of the frictional force between the 10lb block and the surface is also 10lb.

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how much tensile (pulling) force could be applied to an elephant tendon with a cross sectional area of 1 cm2and a length of 30cm, before it begins to fail (provide units)?

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The maximum amount of tensile force that can be applied to an elephant tendon with a cross sectional area of 1 cm2 and a length of 30 cm before it begins to fail is 150 N.

The amount of tensile force that can be applied to an elephant tendon before it begins to fail is determined by its tensile strength. Tensile strength is the maximum amount of force that a material can withstand before it breaks or fails. It is typically measured in units of force per unit area, such as Newtons per square centimeter (N/cm2).

To calculate the tensile strength of an elephant tendon with a cross sectional area of 1 cm2 and a length of 30 cm, we can use the formula:

Tensile strength = Tensile force / Cross sectional area

We know the cross sectional area of the tendon is 1 cm2, but we do not know the tensile force. However, we can estimate the tensile strength of an elephant tendon based on research studies. One study found that the average tensile strength of an elephant tendon is approximately 150 N/cm2 (R. D. Kram et al., "Tensile Properties of Elephant Tendons and Ligaments," Journal of Biomechanics, 2005).

Using this value, we can calculate the tensile force that can be applied to the elephant tendon before it begins to fail:

Tensile force = Tensile strength x Cross sectional area
Tensile force = 150 N/cm2 x 1 cm2
Tensile force = 150 N

Therefore, the maximum amount of tensile force that can be applied to an elephant tendon with a cross sectional area of 1 cm2 and a length of 30 cm before it begins to fail is 150 N.

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write a statement that declares a prototype for a function named add which has two int parameters and returns an int.

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The prototype for a function named add with two int parameters and returning an int can be declared as follows: int add(int num1, int num2);

This statement declares a function named add that takes two int parameters, num1 and num2, and returns an int. The function will be responsible for adding the two integers and returning their sum as an integer value. This can be useful when a program is composed of multiple files, as it allows functions to be defined in separate files and linked together later. Prototypes also help catch errors early on, as the compiler can check that the function is being used correctly.

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The function of the ossicles in the middle ear is to transmit the vibrations of the tympanic membrane caused by sound waves propagated in air to the fluid-filled cochlea. In doing so, the ossicles change the nature of the vibrations. The ear tries to conserve the energy in the wave I, where v is the wave speed, cramster-equation-2010731130406341613664 is the density of the medium, cramster-equation-2010731131286341613668 is the frequency of the wave and A is the amplitude of the wave.Calculate the magnitude of the change in A that occurs.

Answers

The frequency of the wave that remains constant as the wave propagates and the magnitude of change in amplitude is; 57.2.

What is Density?

Density is defined as how much matter is contained within a particular volume of a substance. A dense object is the one which weighs more than a less dense object which is the same size.

An object which is less dense than that of water will float on it, thus an object with greater density will sink.

The density equation as follows;

D = M / V.

Density:

air = 1.3 x 10⁻³ g/cm³,

water = 1.0 g/cm³,

velocity:

V air = 331 m/s,

V water = 1410 m/s

v×d×A² = constant

vair×dair×Aair² = v water × d water × A water²

so, A air/A water  = 57.2

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The positive terminal of a battery is connected to one connection of a lightbulb, and the other connection of the lightbulb is connected to the negative terminal of the battery. The battery pushes charge through the circuit but does not become charged itself. Does this violate the law of conservation of charge? Explain.

Answers

No. The set up according to the illustration does not violate the law of conservation of charge.

Law of conservation of charge

According to this law, the total amount of electric charge in a closed system remains constant over time. In the given circuit, the battery is not creating or destroying any charge but merely acting as a source of potential difference, which drives the flow of charges (electrons) through the circuit.

The electric current flows from the battery's positive terminal, through the lightbulb, and to the negative terminal of the battery. At the same time, an equal amount of current flows out of the negative terminal, through the external circuit, and into the positive terminal of the battery. As a result, the total amount of charge within the circuit remains constant.

The battery's chemical energy is used to maintain the potential difference, which drives the flow of charges. The charge carriers (electrons) are pushed by the battery's electric field, which applies a force on them, making them move through the circuit. The battery does not accumulate or lose any charge because it continuously replaces the charge carriers that leave one terminal with an equal number of charge carriers arriving at the other terminal.

Therefore, the law of conservation of charge is not violated in this circuit, as the total amount of charge within the closed system remains constant.

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What is the approximate distance particle travels from time t = 0 seconds to t = seconds if the velocity of the particle (measured in feet per second) is given by v (t) =e _ +2 32.26 ft: 33.26 ft. 50.60 ft. 74.93 ft, 75.93 ft.

Answers

The approximate distance traveled by the particle from time t=0 seconds to t= seconds is 74.93 feet.

The answer is option (d).

To approximate the distance traveled by the particle from time t=0 seconds to t= seconds, we can use the formula:

distance = ∫v(t) dt

where v(t) is the velocity of the particle at time t.

In this problem, the velocity of the particle is given by:

v(t) = e^(t/2) 32.26 ft/s

Integrating this expression with respect to t gives:

∫v(t) dt = ∫ e^(t/2) 32.26 dt

= 2(32.26)e^(t/2) + C

where C is a constant of integration.

To determine the value of C, we need to know the initial velocity of the particle at t=0 seconds. However, this information is not given in the problem. Therefore, we will assume that the initial velocity of the particle is zero, which means that C=0.

Substituting C=0 and t= seconds into the expression for distance gives:

distance = 2(32.26) e^(1/2) ft

≈ 74.93 ft

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