Which graph shows a function and its?

Equation  [tex]c/E - 1/mc = 0[/tex]

Solve for E

E = mc

To solve the equation for E, we can start by isolating the term containing E on one side of the equation. Let's rearrange the equation step by step

c/E - 1/mc = 0

To eliminate the fraction, we can multiply every term by the common denominator, which is mcE

(mcE)(c/E) - (mcE)(1/mc) = (mcE)(0)

Simplifying

[tex]c^2 - E = 0[/tex]

Now, we can isolate E by moving c^2 to the other side of the equation

[tex]E = c^2[/tex]

The equation c/E - 1/mc = 0 can be solved to find that E is equal to c^2. This means that the value of E is the square of the constant c. By rearranging the original equation, we eliminate the fraction and simplify it to the form E = c^2. This result indicates that the value of E is solely determined by the square of c. Therefore, if we know the value of c, we can find E by squaring it.

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Answer:

11.3%

Step-by-step explanation:

Percent error = (|theoretical value - expected value|)/(theoretical value)

= (|6.2-5.5|)/6.2

= 0.7/6.2

= 0.1129

= 11.3%

The orthogonal matrix P is [sqrt(2)/2, -sqrt(2)/2; sqrt(2)/2, sqrt(2)/2] and the diagonal matrix D is [4, 0; 0, 0].

To orthogonally diagonalize the given matrix A, we need to find the eigenvalues and eigenvectors of A. Since the eigenvalues are given as 4 and 0, we can start by finding the eigenvectors corresponding to these eigenvalues.

For the eigenvalue 4, we solve the equation (A - 4I)v = 0, where I is the identity matrix. This gives us the equation:

[O -4 0; 0 20 -2; 0 0 -4]v = 0

Simplifying, we get:

[-4 0 0; 0 20 -2; 0 0 -4]v = 0

This system of equations can be written as three separate equations:

-4v1 = 0

20v2 - 2v3 = 0

-4v3 = 0

From the first equation, we get v1 = 0. From the third equation, we get v3 = 0. Substituting these values into the second equation, we get 20v2 = 0, which implies v2 = 0 as well. Therefore, the eigenvector corresponding to the eigenvalue 4 is [0, 0, 0].

For the eigenvalue 0, we solve the equation (A - 0I)v = 0. This gives us the equation:

[O 0 0; 0 20 -2; 0 0 0]v = 0

Simplifying, we get:

[0 0 0; 0 20 -2; 0 0 0]v = 0

This system of equations can be written as two separate equations:

20v2 - 2v3 = 0

0 = 0

From the second equation, we can see that v2 is a free variable, and v3 can take any value. Let's choose v2 = 1, which implies v3 = 10. Therefore, the eigenvector corresponding to the eigenvalue 0 is [0, 1, 10].

Now that we have the eigenvectors, we can form the orthogonal matrix P by normalizing the eigenvectors. The first column of P is the normalized eigenvector corresponding to the eigenvalue 4, which is [0, 0, 0]. The second column of P is the normalized eigenvector corresponding to the eigenvalue 0, which is [0, 1/sqrt(101), 10/sqrt(101)]. Therefore, P = [0, 0; 0, 1/sqrt(101); 0, 10/sqrt(101)].

The diagonal matrix D is formed by placing the eigenvalues on the diagonal, which gives D = [4, 0; 0, 0].

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(a) fog: (fog)(x) = f(g(x)) = f(x - 3) = (x - 3) + 8 = x + 5

(b) gof: (gof)(x) = g(f(x)) = g(x + 8) = (x + 8) - 3 = x + 5

(c) gog: (gog)(x) = g(g(x)) = g(x - 3) = (x - 3) - 3 = x - 6

(a) The composition fog refers to the function obtained by performing the function g(x) first and then applying the function f(x).

fog(x) = f(g(x)) = f(x - 3) = (x - 3) + 8 = x + 5

In other words, fog(x) is equal to x plus 5.

(b) The composition g of f refers to the function obtained by performing the function f(x) first and then applying the function g(x).

gof(x) = g(f(x)) = g(x + 8) = (x + 8) - 3 = x + 5

Therefore, gof(x) is also equal to x plus 5.

(c) Finally, the composition go g refers to the function obtained by performing the function g(x) twice.

gog(x) = g(g(x)) = g(x - 3) = (x - 3) - 3 = x - 6

Thus, gog(x) simplifies to x minus 6.

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The percentage of students who got a final grade higher than a specific value cannot be determined without knowing the value.

To determine the percentage of students who got a final grade higher than a specific value, we need to know the actual value. Without this information, we cannot calculate the percentage accurately.

For example, if we have the grades of 100 students and we want to know the percentage of students who scored higher than 80, we would need to count the number of students who scored higher than 80 and divide it by 100 (the total number of students) to get the percentage.

Without specifying the specific value or providing the necessary data, it is not possible to calculate the percentage of students who got a final grade higher than a certain value.

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Answer:

Answer as an ordered pair:  (1, 1)

Step-by-step explanation:

Method to solve:  Elimination:

First we need to multiply the first equation by -1.  Then, we'll add the two equations to eliminate the ys and solve for x:

Multiplying y = -2x + 3 by -1:

-1(y = -2x + 3)

-y = 2x - 3

Adding -y = 2x - 3 and y = 5x - 4:

    -y = 2x - 3

+

     y = 5x - 4

----------------------------------------------------------------------------------------------------------

(-y + y) = (2x + 5x) + (-3 - 4)

Solving for x:

(0 = 7x - 7) + 7

(7 = 7x) / 7

1 = x

Thus, x = 1.  Now we can solve for y by plugging in 1 for x in any of the two equations in the system.  Let's use the first one:

Plugging in 1 for x in y = -2x + 3:

y = -2(1) + 3

y = -2 + 3

y = 1

Thus, y = 1

Therefore, the answer as an ordered pair is (1, 1)

Optional Step:  Checking the validity of our answers:

Now we can check that our answers are correct by plugging in (1, 1) for (x, y) in both equations and seeing if we get the same answers on both sides of the equation:

Plugging in 1 for x and 1 for y in y = -2x + 3:

1 = -2(1) + 3

1 = -2 + 3

1 = 1

Plugging in 1 for x and 1 for y in y = 5x - 4:

1 = 5(1) - 4

1 = 5 - 4

1 = 1

Thus, our answers are correct.

To find the cubic yards of concrete for the sidewalk, we need to calculate the volume of concrete needed. The cubic yards of concrete needed for the sidewalk is approximately 31.1 cubic yards.

First, let's calculate the area of the sidewalk in square feet. The area can be calculated by multiplying the length (x) by the width (y). In this case, the length (x) is 63 feet and the width (y) is 40 feet.

The calculation step by step to find the cubic yards of concrete for the sidewalk:

1. Calculate the area of the sidewalk.

Area = x * y = 63 ft * 40 ft = 2520 square feet

2. Convert the thickness of the sidewalk to feet.

Sidewalk Thickness = 4 inches / 12 = 1/3 feet

3. Calculate the volume of concrete needed.

Volume = Area * Thickness = 2520 square feet * (1/3) feet = 840 cubic feet

4. Convert cubic feet to cubic yards.

Cubic Yards = Volume / 27 = 840 cubic feet / 27 = 31.11 cubic yards

Therefore, rounding to one decimal place, the cubic yards of concrete needed for the sidewalk is approximately 31.1 cubic yards.

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Since the question is incomplete, so complete question is:

Find the cubic yards of concrete for the sidewalk (top view pictured below, x = 63' and y = 40'), if it is 4 inches thick, rounded to one decimal place. Assume the entire sidewalk is 4 feet wide.

We can add the missing rectangle by drawing a line to join the edges AG and BD together. This will complete the net of the triangular prism.

The net of a triangular prism is shown below, but one rectangle is missing. To complete the net of the triangular prism, we need to identify all the edges that will complete the missing rectangle. Let's take a look at the net of a triangular prism below to identify the missing rectangle:Triangle ABC is the base of the triangular prism, with points A, B, and C. The other three vertices are D, E, and F.

When the net of a triangular prism is laid out flat, it appears like the figure above. We need to identify the edges that could be added to complete the missing rectangle. This means we need to look at the edges on the net of the triangular prism that are currently open. We can see that three edges are open, namely AG, HC, and BD. Since the missing rectangle needs to have two adjacent sides, we need to identify any two edges that are adjacent to each other. Based on this, we can see that the edges AG and BD are adjacent, forming the base of the missing rectangle.

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The solutions for both equations are located on the complex plane at angles of π/8, 9π/8, 17π/8, etc., counterclockwise from the positive real axis, with a distance of 1 unit from the origin.

To find all values of z for the equation z = ∜i or z^4 = i, we can express i and ∜i in exponential form and solve for z.

1. For z = ∜i:

Expressing i in exponential form: i = e^(iπ/2)

Now, let's find the fourth root (∜) of i:

∜i = (e^(iπ/2))^(1/4)

    = e^(iπ/8)

The solutions for z = ∜i are given by z = e^(iπ/8), where k is an integer.

2. For z^4 = i:

Expressing i in exponential form: i = e^(iπ/2)

Now, let's solve for z:

z^4 = e^(iπ/2)

Taking the fourth root of both sides:

z = (e^(iπ/2))^(1/4)

  = e^(iπ/8)

The solutions for z^4 = i are given by z = e^(iπ/8), where k is an integer.

To locate these values in the complex plane, we represent them using the polar form, where z = r * e^(iθ). In this case, the modulus r is equal to 1 for all solutions.

For z = e^(iπ/8), the angle θ is π/8. We can plot these solutions in the complex plane as follows:

- For z = e^(iπ/8):

 - One solution: z = e^(iπ/8)

   - Angle: π/8

   - Position in the complex plane: Located at an angle of π/8 counterclockwise from the positive real axis, with a distance of 1 unit from the origin.

Since the solutions are periodic with a period of 2π, we can also find additional solutions by adding integer multiples of 2π to the angle.

Therefore, the solutions for both equations are located on the complex plane at angles of π/8, 9π/8, 17π/8, etc., counterclockwise from the positive real axis, with a distance of 1 unit from the origin.

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(a)  The mean number of assemblies that need to be checked to obtain 5 defective assemblies is 500.

(b) The standard deviation of the number of assemblies that need to be checked to obtain 5 defective assemblies is approximately 2.22.

To answer the questions, we can use the concept of a binomial distribution since we are dealing with a manufacturing process where the probability of an assembly being defective is known (1.0%) and the assemblies are assumed to be independent.

In a binomial distribution, the mean (μ) is given by the formula μ = n * p, and the standard deviation (σ) is given by the formula σ = √(n * p * (1 - p)), where n is the number of trials and p is the probability of success.

(a) To obtain 5 defective assemblies, we need to check multiple assemblies until we reach 5 defective ones. Let's denote the number of assemblies checked as X. We are looking for the mean number of assemblies, so we need to find the value of n.

Using the formula μ = n * p and solving for n:

n = μ / p = 5 / 0.01 = 500

Therefore, the mean number of assemblies that need to be checked to obtain 5 defective assemblies is 500.

(b) To find the standard deviation, we use the formula σ = √(n * p * (1 - p)). Substituting the values:

σ = √(500 * 0.01 * (1 - 0.01)) = √(500 * 0.01 * 0.99) = √4.95 ≈ 2.22

Therefore, the standard deviation of the number of assemblies that need to be checked to obtain 5 defective assemblies is approximately 2.22.

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The equation 0.3x² = (2/5)(x - 5/4) simplifies to 3x² - 4x + 5 = 0. Using the quadratic formula, we find that it has no real solutions.

To solve the equation 0.3x² = (2/5)(x - 5/4) using the quadratic formula, we first need to clear the parentheses and fractions.

Clear the parentheses
0.3x² = (2/5)(x) - (2/5)(5/4)

Simplifying, we have:
0.3x² = (2/5)x - (1/2)

Clear the fractions
Multiply the entire equation by the common denominator of 10 to eliminate the fractions.

10 * 0.3x² = 10 * (2/5)x - 10 * (1/2)

Simplifying, we get:
3x² = 4x - 5

Rearrange the equation
Move all terms to one side of the equation to obtain a quadratic equation in standard form (ax² + bx + c = 0).
3x² - 4x + 5 = 0

Now, we can use the quadratic formula to solve for x:
x = (-b ± √(b² - 4ac)) / (2a)

In this case, a = 3, b = -4, and c = 5.

Substituting these values into the quadratic formula, we get:
x = (-(-4) ± √((-4)² - 4(3)(5))) / (2(3))

Simplifying further, we have:
x = (4 ± √(16 - 60)) / 6
x = (4 ± √(-44)) / 6

Since the discriminant (b² - 4ac) is negative, the equation has no real solutions. Therefore, the equation 0.3x² = (2/5)(x - 5/4) has no real solutions.

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The equation of the vertical ellipse with a center at point (8, -4), a major axis of 12 units, and a minor axis of 6 units is ((x - 8)^2 / 36) + ((y + 4)^2 / 144) = 1.

To find the equation of a vertical ellipse, we need to determine the values of the center and the lengths of the major and minor axes. The center of the ellipse is given as (8, -4), the major axis has a length of 12 units, and the minor axis has a length of 6 units.

The general equation of a vertical ellipse with center (h, k), a length of 2a along the major axis, and a length of 2b along the minor axis is:

((x - h)^2 / a^2) + ((y - k)^2 / b^2) = 1

Plugging in the given values, we have:

((x - 8)^2 / 6^2) + ((y + 4)^2 / 12^2) = 1

Simplifying further, we get the equation of the vertical ellipse:

((x - 8)^2 / 36) + ((y + 4)^2 / 144) = 1

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The predicted outcome of the game, or the strategy profile played in the game, would then depend on the remaining strategies.

1. A strategy is considered strictly dominant for a player if it always leads to a higher payoff than any other strategy, regardless of the choices made by the other player. In this game, for player 1 to have a strictly dominant strategy, the payoff for strategy U must be strictly higher than the payoffs for strategies M and D, regardless of the choices made by player 2.

2. For player 2 to have a strictly dominant strategy, the payoff for strategy R must be strictly higher than the payoffs for strategies L and any other possible strategy that player 2 can choose.

3. To determine if any player has a strictly dominant strategy, we need to compare the payoffs for each strategy for both players. In this specific example, using the given values (a=2, b=3, c=4, x=5, y=5, z=2, and w=3),

4. The order in which strategies are deleted does matter when using iterative deletion of weakly dominated strategies. In the given example, when we delete the weakly dominated strategy M for player 1, we are left with a 2x2 game.

(c) In the original game of part (4), when we note that U is a weakly dominated strategy for player 1, we can look for a strategy that weakly dominates it. By comparing the payoffs, we can determine the weakly dominant strategy.

(d) After deleting U and noting that L is weakly dominated for player 2, we can delete it as well. The predicted outcome of the game, or the strategy profile played in the game, would then depend on the remaining strategies.

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The IVP has a unique solution defined on some interval I with 0 € I.

the step-by-step solution to show that there is some interval I with 0 € I such that the IVP has a unique solution defined on I:

The given differential equation is y = y³ + 2.

The initial condition is y(0) = 1.

Let's first show that the differential equation is locally solvable.

This means that for any fixed point x0, there is an interval I around x0 such that the IVP has a unique solution defined on I.

To show this, we need to show that the differential equation is differentiable and that the derivative is continuous at x0.

The differential equation is differentiable at x0 because the derivative of y³ + 2 is 3y².

The derivative of 3y² is continuous at x0 because y² is continuous at x0.

Therefore, the differential equation is locally solvable.

Now, we need to show that the IVP has a unique solution defined on some interval I with 0 € I.

To show this, we need to show that the solution does not blow up as x approaches infinity.

We can show this by using the fact that y³ + 2 is bounded above by 2.

This means that the solution cannot grow too large as x approaches infinity.

Therefore, the IVP has a unique solution defined on some interval I with 0 € I.

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The simplest radical form of the expression (8x^4y^5)^(2/3) is 4∛(x^8y^10).

To find the simplest radical form of the expression (8x^4y^5)^(2/3), we can simplify the exponent and rewrite the expression using the properties of exponents.

First, let's simplify the exponent 2/3. Since the exponent is in fractional form, we can interpret it as a cube root.

∛((8x^4y^5)^2)

Next, we apply the exponent to each term within the parentheses:

∛(8^2 * (x^4)^2 * (y^5)^2)

Simplifying further:

∛(64x^8y^10)

The cube root of 64 is 4:

4∛(x^8y^10)

Therefore, the simplest radical form of the expression (8x^4y^5)^(2/3) is 4∛(x^8y^10).

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a. The values of a and b that make A positive definite are a ∈ ℝ and b >0.

b. The Cholesky decomposition of A with a = 5 and b = 1 is:

A = LL^T, where L = |√2 0 | |(5/√2) (1/√2)|

c. The Cholesky decomposition of A with a = 3 and b = 1 is:A = LL^T, where L = |√2 0| |(3/√2) (1/√2)|

(a) To make the matrix A = |2 a|

|0 b| positive definite, we need to ensure that all the leading principal minors (sub determinants) of A are positive.

The leading principal minors of A are:

The 1x1 sub determinant: |2|

The 2x2 sub determinant: |2 a|

|0 b|

For A to be positive definite, both of these sub determinants need to be positive.

The 1x1 sub determinant is 2. Since 2 is positive, this condition is satisfied.

The 2x2 sub determinant is (2)(b) - (0)(a) = 2b. For A to be positive definite, 2b needs to be positive, which means b > 0.

Therefore, the values of a and b that make A positive definite are a ∈ ℝ and b > 0.

(b) When a = 5 and b = 1, the matrix A becomes:

A = |2 5| |0 1|

To find the Cholesky decomposition of A, we need to find a lower triangular matrix L such that A = LL^T.

Let's solve for L by performing the Cholesky factorization:

L = |√2 0 | |(5/√2) (1/√2)|

The Cholesky decomposition of A with a = 5 and b = 1 is:

A = LL^T, where L = |√2 0 | |(5/√2) (1/√2)|

(c) When a = 3 and b = 1, the matrix A becomes:

A = |2 3| |0 1|

To find the Cholesky decomposition of A, we need to find a lower triangular matrix L such that A = LL^T.

Let's solve for L by performing the Cholesky factorization:

L = |√2 0| |(3/√2) (1/√2)|

The Cholesky decomposition of A with a = 3 and b = 1 is:

A = LL^T, where L = |√2 0| |(3/√2) (1/√2)|

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The conjecture “If two points are equidistant from a third point, then the three points are collinear” is true.

A conjecture is a statement that we believe to be true based on previous observations or an explanation of an observed pattern. Before any conjecture is believed, it must first be tested and proved to be correct.

If two points are equidistant from a third point, then it means they are the same distance from that point, and this forms a circle centered on the third point. If two points in space share the same distance from a third point, the three points must fall on the same line that passes through the third point; thus, the statement is true.

The conjecture is true and the statement is an example of Euclid's first postulate: two points can be joined by a straight line.

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The domain of set B is expressed as: {-4, 0, 2, 4}

The domain of a set is defined as the set of input values for which a function exists.

Meanwhile, the range of values is defined as the set of output values for which the input values gives to make the function defined.

Now, the set B is given as a pair of coordinates as:

B = {(2,0)(4,6)(-4,5)(0,0)}

The x-values will represent the domain while the y-values will represent the range.

Thus:

Domain of set B = {-4, 0, 2, 4}

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i) When the mean is 104, the likelihood of Type II error is 0.071 at the 1% significance level.

ii) The probability of a profitable investment opportunity is 0.929 or 92.9% when the mean is 104 at the 1% significance level.

(i) In hypothesis testing, Type II error happens when the null hypothesis is false, but we fail to reject it. It represents the possibility of missing a positive impact.

When the actual mean is 104, the hypothesis Hο is Hο :

μ ≤ 100 (the number of students visiting the campus is less than or equal to 100 per hour).

The alternative hypothesis H1 is H1: μ > 100 (the number of students visiting the campus is greater than 100 per hour). The population standard deviation is known and the sample size is large (n > 30).

As per the central limit theorem, the distribution of the sample mean is a normal distribution with a mean of μ = 100 and a standard deviation of σ/√n=16/√40=2.5298. The level of significance (α) is 1%. At the 1% level of significance, the critical value of z is 2.33. The probability of Type II error can be represented as β and calculated using the below formula:

β=P(X ≤2.33- (104-100)/2.5298) =P(Z ≤-1.47)

β=0.071

Thus, When the mean is 104, the likelihood of Type II error is 0.071 at the 1% significance level.

(ii) The power of the test is equal to 1-β. The power of the test when the actual mean is 104 is 1 - 0.071 = 0.929 or 92.9%. The power of the test represents the probability of accepting the alternative hypothesis when it is true. Here, it is the probability of the coffee shop being a profitable investment. Hence, the probability of a profitable investment opportunity is 0.929 or 92.9% when the mean is 104 at the 1% significance level.

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The equation of the parabola with vertex at the origin and the given directrix y = -1/3 is:
[tex]x^2 = 4/3y[/tex].

To write the equation of a parabola with vertex at the origin and the given directrix, we can use the standard form of the equation for a parabola with vertical axis of symmetry:

[tex](x - h)^2 = 4p(y - k)[/tex]

where (h, k) represents the vertex coordinates and p represents the distance from the vertex to the directrix.
In this case, the vertex is at the origin (0, 0), and the directrix is y = -1/3.
1: Determine the value of p.
Since the directrix is below the vertex, the value of p is positive and represents the distance from the vertex to the directrix. In this case, p = 1/3.
2: Substitute the vertex and the value of p into the equation.
[tex](x - 0)^2 = 4(1/3)(y - 0)[/tex]
Simplifying this equation, we get:
[tex]x^2 = 4/3y[/tex]

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Answer:

We have no information about the sides of these triangles. So we can't tell if these triangles are congruent.

If ax + by = 1 for some x, y = Z, then ged(a, b) = 1 because if d is not equal to 1, then d is a common divisor of a and b that is greater than 1. This contradicts the fact that d is the gcd of a and b. If m is not a multiple of 5, then m² is either congruent to 1 or −1 modulo 5.

(1) Let m be an integer, not divisible by 5.

Hence, we can write, m = 5k + r,

where k and r are integers, and 0 < r < 5

(as if r = 0, then m would be divisible by 5).

If r = ±1,

then m² = (5k ± 1)²

= 25k² ± 10k + 1

= 5(5k² ± 2k) + 1

≡ 1 (mod 5).

If r = ±2,

then m² = (5k ± 2)²

= 25k² ± 20k + 4

= 5(5k² ± 4k) + 4

≡ −1 (mod 5).

Thus, we see that if m is not a multiple of 5, then m² is either congruent to 1 or −1 modulo 5.

(2) Suppose that d is the gcd of a and b.

Then, there exist integers x' and y' such that d = ax' + by' .

Now, suppose that d is not equal to 1, i.e., d > 1.

Then, ax' and by' are both multiples of d, so d divides ax' + by' = d.

Thus, d = ad' for some integer d'.

Hence, b = (1 − ax')y', so b is a multiple of d.

Therefore, if d is not equal to 1, then d is a common divisor of a and b that is greater than 1. This contradicts the fact that d is the gcd of a and b.

So, we see that there cannot exist a common divisor of a and b that is greater than 1, so ged(a, b) = 1.

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p(male) * p(fail) = 0.2069 and P(male and fail) = 0.2034. The two results are different and so the events are independent

Independent Events are said to be when the probability of one event does not affect the probability of a second event. Dependent Events are said to be when the probability of one event affects the probability of a second event.

Now, the total number of people both male and female are:

48 + 70 = 118

Thus, probability of selecting a male = 48/118 = 0.4068

Probability of selecting someone that failed = (36 + 24)/118 = 0.5085

p(male) * p(fail)= 0.4068 * 0.5085 = 0.2069

P(male and fail) = 24/118 = 0.2034

The two results are different and so the events are independent

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a. the value of the equation x is 0

b. The equilibrium price is $43.

c. The copies of magazines sold after 30 days will be 7448.

(a) i) Given the equation: 12 + 3e^(x+2) = 15

Rearranging the terms, we have:

3e^(x+2) = 15 - 12

3e^(x+2) = 3

Dividing both sides by 3, we get:

e^(x+2) = 1

Subtracting 2 from both sides:

e^(x+2-2) = 1

e^(x) = 1

Taking natural logarithm (ln) of both sides:

ln e^(x) = ln 1

x = 0

Hence, the value of x is 0.

ii) Given the equation: 4 ln (2x) = 10

Taking exponentials to both sides:

2x = e^(10/4) = e^(5/2)

Solving for x:

x = e^(5/2)/2 ≈ 4.3117

(b) i) When the unit price is set at $100, the demand function is:

p = −0.3x^2 + 80 = 100

Solving for x:

x^2 = (80 - 100) / -0.3 = 200

x = ±√200 = ±10√2 (We discard the negative value as it is impossible to have a negative quantity supplied)

Therefore, the quantity supplied when the unit price is set at $100 is 10√2 hundreds of units.

ii) To find the equilibrium price and quantity, we set the demand function equal to the supply function:

-0.3x^2 + 80 = 0.5x^2 + 0.3x + 70

Solving for x, we get:

x = 30

The equilibrium quantity is 3000 hundreds of units.

Substituting x = 30 in the demand function:

p = -0.3(30)^2 + 80

= $43

The equilibrium price is $43.

(c) Given the copies of magazine sold is approximated by the model:

Q(t) = 10,000/1 + 200e^(-kt)

After 10 days, 200 magazines were sold. We need to find out the value of k using this information.

200 = 10,000/1 + 200e^(-k×10)

Solving for k:

k = -ln [99/1000] / 10

k ≈ 0.0069

Substituting the value of k, we get:

Q(t) = 10,000/1 + 200e^(-0.0069t)

At t = 30 days, the number of magazines sold is:

Q(30) = 10,000/1 + 200e^(-0.0069×30)

≈ 7448

Therefore, the copies of magazines sold after 30 days will be 7448.

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Answer:

y=-x-6

Step-by-step explanation:

First step is to put y=-x-6

Second step is to replace the y with x and the x with y:

x=-y-6

Now solve for y:

-y=x+6

y=-x-6

In this case the inverse is the same as the equation

1a: The given differential equation is not exact.

1b: The general solution to the above differential equation is y = (x^7 - C)/(7x^6), where C is an arbitrary constant.

2a: The solution to the linear system using Gauss-Jordan elimination is x = 1, y = -1, z = -1.

2b: The system is homogeneous and consistent. The solution is unique.

For Question 1a, to determine if a differential equation is exact, we need to check if the partial derivatives of the coefficients with respect to the variables satisfy a certain condition. In this case, the equation is not exact because the partial derivative of (-y sin(x)+7x^6y³) with respect to y is not equal to the partial derivative of (8y^7 cos(x)+3x^7y²) with respect to x.

Moving on to Question 1b, we can find the general solution by integrating the equation. Integrating the terms with respect to their respective variables, we obtain y = (x^7 - C)/(7x^6), where C is the constant of integration. This represents the family of solutions to the given differential equation.

In Question 2a, we are asked to solve a linear system using Gauss-Jordan elimination. By performing the necessary row operations, we find the solution x = 1, y = -1, and z = -1.

Regarding Question 2b, the system is homogeneous because the right-hand side of each equation is zero. The system is consistent because it has a solution. Furthermore, the solution is unique since there are no free variables in the system after performing Gauss-Jordan elimination.

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A. (a) If an integer n is not divisible by 3, then it is not divisible by 6.

B. Let's prove statement (a) using the rule of inference "If A implies B, then not B implies not A."

Let A be the statement "n is divisible by 3" and B be the statement "n is divisible by 6."

We want to prove that if A is false (n is not divisible by 3), then B is also false (n is not divisible by 6).

By the contrapositive form of the rule of inference, we can rewrite the statement as follows: "If n is divisible by 6, then n is divisible by 3."

This is true because any number that is divisible by 6 must also be divisible by 3.

Therefore, by using the rule of inference "If A implies B, then not B implies not A," we have proven statement (a) to be true.

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[tex] \sf \longrightarrow \: (3.4 \times {10}^{8} ) +( 7.5 \times {10}^{8} )[/tex]

[tex] \sf \longrightarrow \: (3.4 + 7.5 ) \times {10}^{8} [/tex]

[tex] \sf \longrightarrow \: (10.9 ) \times {10}^{8} [/tex]

[tex] \sf \longrightarrow \: 10.9 \times {10}^{8} [/tex]

The equation in point-slope form for the line parallel to y = (1/2)x - 7 that passes through (-3, -2) is option C. y + 2 = 2(x + 3).

To find the equation of a line that is parallel to the line y = (1/2)x - 7 and passes through the point (-3, -2), we can use the point-slope form of a linear equation, which is given by:

y - y1 = m(x - x1)

where (x1, y1) represents the coordinates of the given point and m represents the slope of the line.

The slope of the given line y = (1/2)x - 7 is 1/2. Since the line we want is parallel to this line, it will have the same slope.

Using the point (-3, -2), we substitute the values into the point-slope equation:

y - (-2) = (1/2)(x - (-3))

y + 2 = (1/2)(x + 3)

Simplifying the equation, we have:

y + 2 = (1/2)x + 3/2

This equation can be rearranged to match one of the options:

C. y + 2 = 2(x + 3)

Therefore, the equation in point-slope form for the line parallel to y = (1/2)x - 7 that passes through (-3, -2) is option C. y + 2 = 2(x + 3).

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Answer:

we replace from the equation as y=1/2x-7 so gradient=1/2or m= 1/2.

Using the given approximation, the approximate value of the derivative of f(x) = x at x = 7 is -2.33. The values used for the approximation were x₀ = 5, x₁ = 6, x₂ = 7, and x₃ = 8, with h = 1.

Using the given approximation, we have:

f'(x₂) ≈ [f(x₀) - 6f(x₁) + 3f(x₂) + 2f(x₃)] / (6h)

We want to find f'(7), so we need to choose values for x₀, x₁, x₂, and x₃ such that x₂ = 7.

Let's choose x₁ = 6, x₂ = 7, and h = 1. Then, we can choose x₀ = 5 and x₃ = 8. Plugging in these values and using f(x) = x, we get:

f'(7) ≈ [f(5) - 6f(6) + 3f(7) + 2f(8)] / (6*1)

f'(7) ≈ [5 - 6(6) + 3(7) + 2(8)] / 6

f'(7) ≈ (-14) / 6

f'(7) ≈ -2.33

Therefore, the approximate value of the derivative of f(x) = x at x = 7 using the given approximation is approximately -2.33.

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