What is meant by measurement? l
Answer:
The action of measuring the size, length, or amount of something, as established is called measurement.
Explanation:
“Measurement” is the act of determining a target's size, length, weight, capacity, or other aspect. ... To use measurement tools as necessary. It is also appropriate to say that measurement is done by a worker using a measurement system, and instrumentation is done by a technician.
Clothes are flung to the sides of a round tub during the spin-cycle of a washing machine.If the tub's period of rotation is 0.2s and the tub's radius is 35cm,answer the related qestions below: (a)The frequency of roation (b)The circumference of rotation (c)The spinning of speed (d)The centripetal acceleration (e)The centripetal force of rotation if total mass rotated is 30kg (f)The power of washing machine
Answer:
Explanation:
First I need to tell you that I used .20 s for the period of rotation instead of just .2, and I used 30.0 kg for the mass instead of just 30. The reason being that both those numbers as stated in the problem only have 1 significant digit and that's not generally enough to get the accuracy you're looking for. Adding a 0 to the ends of each of those numbers doesn't change the value of the numbers, only the number of sig fig's in each. Beginning with a:
a. [tex]f=\frac{1}{T}[/tex] so [tex]f=\frac{1}{.2}[/tex] and f = 5.0 Hz
b. The circumference is the distance around the outside of the washer's drum. We need to find that, but before we do, I'm going to state the radius in meters instead of cm. 35 cm = .35 m. Therefore,
C = 2(3.1415)(.35) so
C = d = 2.2 m
c. The speed of the washer is found in d = rt, where r is the rate and our velocity and d is the distance around the outside of the drum (circumference). Therefore,
2.2 = v(.20) so
v = 11 m/s
d. The centripetal acceleration has an equation
[tex]a_c=\frac{v^2}{r}[/tex] so
[tex]a_c=\frac{(11)^2}{.35}[/tex] and
[tex]a_c=\frac{121}{.35}[/tex] so
[tex]a_c=350\frac{m}{s^2}[/tex]
e. The centripetal force has an equation
[tex]F_c=\frac{mv^2}{r}[/tex] and
[tex]F_c=\frac{(30.0)(11)^2}{.35}[/tex] and
[tex]F_c=[/tex] 1.0 × 10⁴ N
f. The equation for Power is
[tex]P=\frac{W}{t}[/tex] where W is work and W = FΔx (force times displacement). Therefore,
[tex]P=\frac{(1.0*10^4)(2.2)}{.20}[/tex] so
P = 1.1 × 10⁵ Watts
Explain how two rolling bowling balls of different masses can have the same momentum
Knowing that the momentum(p) of an object is directly (when one number goes up the other will too) related to both the mass and velocity of an object or p=mv, two rolling bowling balls of different masses can have the same momentum because the one with the lower mass, has a higher velocity. The higher velocity of an object would make up for the lower mass and vice versa.
Answer:
Sample Response: Momentum is equal to the mass of an object multiplied by the velocity of an object. The two bowling balls can have the same momentum if the bowling ball with less mass has a higher velocity, and vice versa. As long as the product of the mass and velocity of one bowling ball is equal to the product of the mass and velocity of the other, the bowling balls will have the same momentum.
Explanation:
An ice skater pushes harder with her legs and begins to move faster. Which two laws best describes this
Answer:
Newton' second law and third law describes the situation.
Explanation:
According to the Newton's second law, the force applied on a body is proportional to the rate of change of momentum of the body.
According to the Newton's third law, for every action there is an equal and opposite reaction.
When ice skater pushes harder means more force is applied so he moves fast and more be the action force more be the reaction force.
Thus, Newton' second law and third law describes the situation.
Priya is responsible for collecting canned food along three different streets for her school's annual Thanksgiving Food Drive. She walks 300 m [N] along Oak Road, 500 m [E] along Second Street, and then 150 m [S45°W] along Cross Ave. She completes the journey in 10 minutes.Calculate her total distance, displacement, speed, and velocity.
As per the details given, Priya's total distance traveled is 950 meters, displacement is approximately 410.52, speed is 95 meters per minute, and velocity is 41.05 meters per minute.
To calculate Priya's total distance:
Total distance = 300 m + 500 m + 150 m = 950 m
So, Priya's total distance traveled is 950 meters.
To calculate Priya's displacement, we need to find the straight-line distance and direction from her starting point to her ending point.
Displacement = √((Δx)² + (Δy)²)
For Δx:
Δx = 500 m - 150 m × cos(45°)
Δx = 500 m - 150 m × 0.707
Δx = 500 m - 106.05 m
Δx = 393.95 m
For Δy:
Δy = 150 m × sin(45°)
Δy = 150 m × 0.707
Δy = 106.05 m
Displacement = √((393.95 m)² + (106.05 m)²)
Displacement ≈ 410.52 m
So, Priya's displacement is approximately 410.52 meters in a direction of approximately N36°W.
To calculate Priya's speed, we use the formula:
Speed = Total distance ÷ Time
Speed = 950 m ÷ 10 min
Speed = 95 m/min
So, Priya's speed is 95 meters per minute.
To calculate Priya's velocity:
Velocity = Displacement ÷ Time
Velocity = 410.52 m ÷ 10 min
Velocity = 41.05 m/min
Thus, Priya's velocity is 41.05 meters per minute in a direction of N36°W.
For more details regarding velocity, visit:
https://brainly.com/question/34025828
#SPJ5
In a whispering gallery, a person standing at one focus of the ellipse can whisper and be heard by another person standing at the other focus, because all sound waves that reach the ceiling from one focus are reflected to the other focus. A hall 120 feet in length is to be designed as a whispering gallery. Of foci are located 40 feet from the center, how high will the ceiling be at the center
Answer:
Hence, the height of the ceiling at the center is 44.72 feet.
Explanation:
Consider that a whispering gallery has a length of 120 feet, and the foci are located 40 feet from the center.
Assume that the shape is a horizontal semi-ellipse with a center (0,0) and has the equation,
[tex]\frac{x^{2} }{ a^{2} } + \frac{y^{2} }{b^{2} } =1[/tex] where a>b,
so,
2a = 120
a = 60
and
c = 40
Therefore, the equation of the ellipse is,
[tex]c^{2} = a^{2} -b^{2} \\\\40^{2} = 60^{2} -b^{2}\\\\b^{2} =2000\\\\b= 44.72.[/tex]
IA body starts to move from rest and travels with uniform acceleration of 7mls2. How far will the body move in 4 second .
what is the angular speed w of the system immediately after the collision in terms f the sstem parameters and I
Answer: hello some part of your question is missing attached below is the missing detail
answer :
wf = M( v cos∅ )D / I
Explanation:
The Angular speed wf of the system after collision in terms of the system parameters and I can be expressed as
considering angular momentum conservation
Li = Lf
M( v cos∅ ) D = ( ML^2 / 3 + mD^2 ) wf
where ; ( ML^2 / 3 + mD^2 ) = I ( Inertia )
In terms of system parameters and I
wf = M( v cos∅ )D / I
Hey, I'm a Turk. What language do you speak? I'm very curious.
Answer:
What languages do i sqeak?
English, Korean and Filipino
Uhh why are you asking it?
Which of the following statements are true with respect to the law of conservation of mass?
i) Mass is conserved during a chemical reaction.
ii) Amount of products formed can be determined using law of conservation of mass.
iii) Mass is destroyed during a chemical reaction.
O i only true
Both i and in
All three statements are true
All three statements are false
Answer:
Only (I) is true
i) Mass is conserved during a chemical reaction.
Your parallel capacitors are 15 μf and 20 μf. The series capacitors are 10 μf and 12 μf. This circuit is connected to a 14 v battery, also determine the potential energy and the voltage across each capacitor
Answer:
a. i. 6.608 V ii. 5.507 V iii. 1.89 V iv. 1.89 V
b. i. 0.22 mJ ii. 0.182 mJ iii. 0.027 mJ iv. 0.036 mJ
Explanation:
a. The voltage across each capacitor
Since the 15 μf and 20 μf capacitors are in parallel, their total capacitance is C = 15 μf + 20 μf = 35 μf.
Also, since C is in series with the 10 μf and 12 μf which are in series, their total capacitance, C' is gotten from 1/C' = 1/10 μf + 1/12 μf + 1/35 μf
1/C' = (12 + 42 + 35)/420 /μf
1/C' = 89/420 /μf
C' = 420/89 μf
C' = 4.72 μf
The total charge in the circuit' is thus Q = C'V where V = voltage = 14 V
So, Q = C'V = 4.72 μf × 14 V = 66.08 μC
Since the 10 μf and 12 μf are in series, Q is the charge flowing through them.
Since Q = CV and V = Q/C
i. The voltage across the 10 capacitor is
V = 66.08 μC/10 μF = 6.608 V
ii. The voltage across the 12 capacitor is
V = 66.08 μC/12 μF = 5.507 V
The voltage across the 15 μF and 20 μF capacitors.
Since the capacitors are in parallel, the voltage across them is the voltage across their combined capacitance, C
So, V = Q/C = 66.08 μC/35 μF = 1.89 V
iii. The voltage across the 15 μF capacitor is 1.89 V
iv. The voltage across the 20 μF capacitor is 1.89 V
b. The potential energy of each capacitor
i. The potential energy of the 10 μF capacitor
E = 1/2CV² where C = Capacitance = 10 μF = 10 × 10⁻⁶ F and V = voltage across capacitor = 6.608 V
E = 1/2CV²
E = 1/2 × 10 × 10⁻⁶ F(6.608 V)²
E = 5 × 10⁻⁶ F(43.666) V²
E = 218.33 × 10⁻⁶ J
E = 0.21833 × 10⁻³ J
E = 0.21833 mJ
E ≅ 0.22 mJ
ii. The potential energy of the 12 μF capacitor
E = 1/2CV² where C = Capacitance = 12 μF = 12 × 10⁻⁶ F and V = voltage across capacitor = 5.507 V
E = 1/2CV²
E = 1/2 × 12 × 10⁻⁶ F(5.507 V)²
E = 6 × 10⁻⁶ F(30.327) V²
E = 181.96 × 10⁻⁶ J
E = 0.18196 × 10⁻³ J
E = 0.18196 mJ
E ≅ 0.182 mJ
iii. The potential energy of the 15 μF capacitor
E = 1/2CV² where C = Capacitance = 15 μF = 15 × 10⁻⁶ F and V = voltage across capacitor = 1.89 V
E = 1/2CV²
E = 1/2 × 15 × 10⁻⁶ F(1.89 V)²
E = 7.5 × 10⁻⁶ F(3.5721) V²
E = 26.79 × 10⁻⁶ J
E = 0.02679 × 10⁻³ J
E = 0.02679 mJ
E ≅ 0.027 mJ
iv. The potential energy of the 15 μF capacitor
E = 1/2CV² where C = Capacitance = 20 μF = 15 × 10⁻⁶ F and V = voltage across capacitor = 1.89 V
E = 1/2CV²
E = 1/2 × 20 × 10⁻⁶ F(1.89 V)²
E = 10 × 10⁻⁶ F(3.5721) V²
E = 35.721 × 10⁻⁶ J
E = 0.035721 × 10⁻³ J
E = 0.035721 mJ
E ≅ 0.036 mJ
A 5.0 kg box moving at 2.0 m/s on a horizontal, frictionless surface runs into a light horizontal spring of force constant 85 N/cm. Use the work-energy theorem to find the maximum compression of the spring.
Answer:
x = 4.85 cm
Explanation:
From work energy theorem when dealing with a spring in compression, we know that total work done is;
W_t = ½kx²
Where;
k is Force constant
x is max compression
Now, we know that this is also equal to the kinetic energy.
K.E = ½mv²
Thus;
½kx² = ½mv²
Making x the subject;
x = √(mv²/k)
We are given;
m = 5 kg
v = 2 m/s
k = 85 N/cm = 8500 N/m
Thus;
x = √(mv²/k)
x = √(5 × 2²/8500)
x = 0.0485 m
x = 4.85 cm
Define couple and give 2 examples
Answer:
Two equal and opposite parallel forces not acting along the same line, form a couple. A couple is always needed to produce the rotation.
For example, turning a key in a lock and turning a steering wheel.
An object is moving with an initial velocity of 9 m/s. It accelerates at a rate of 1.5 m/s2
over a time of 20 s. What is its new velocity?
Answer:
39 m/s²
Explanation:
initial Velocity (u) = 9m/s
acceleration (a) = 1.5m/s²
time(t) = 20s
V=u + at
V=9 + 1.5(20)
V=9 + 30
V=39m/s
The moon's mass is____
a 1.18 x 1011 kg
b 7.35 x 1022 kg
С 5.32 x 10kg
d 3.20 x 1018 kg
Answer:
7.35kg
Explanation:
Hope this is helpful :)
Please help it's for a test.
A car of mass 1000kg is traveling 30m/s
a) What is the kinetic energy?
b) How high will it have to travel up a hill to have the same potential as kinetic energy as this speed? Remember Ep-Ek
Answer:
Explanation:
[tex]KE=\frac{1}{2}mv^2[/tex] so filling in:
[tex]KE=\frac{1}{2}(1000)(30)^2[/tex] so to 2 sig figs (which is actually not accurate, but oh well...)
KE = 450000 J
If we want to find out how high it will have to travel up a hill so that its PE is the same as the KE at this speed, we set the value for KE = to PE:
450000 = (1000)(9.8)h so
[tex]h=\frac{450000}{(1000)(9.8)}=45.9m[/tex]
An airplane flies eastward and always accelerates at a constant rate. At one position along its path, it has a velocity of 32.7 m/s . It then flies a further distance of 48500 m , and afterwards, its velocity is 44.7 m/s . Find the airplane's acceleration.
Answer:
[tex]\quad[/tex]0.0095 m/s²
Explanation:
We have,
Initial velocity (u) = 32.7 m/sFinal velocity (v) = 44.7 m/sDistance travelled (s) = 48500 mWe are asked to calculate the airplane's acceleration.
By using the third equation of motion,
➝ v² - u² = 2as
v denotes final velocityu denotes initial velocitya denotes accelerations denotes distance➝ (44.7)² - (32.7)² = 2 × a × 48500
➝ 1998.09 - 1069.29 = 97000 × a
➝ 928.8 = 97000a
➝ 928.8 ÷ 97000 = a
➝ 0.0095 m/s² = a
A stone attached to a string is whirled round in a horizontal circle with constant speed of 10m/s .Calculate the difference in the velocity with the stone is at
I) opposite ends of a diameter
Ii) in two positions A and B where angle AOB is 90° & O is the centre of the circle
Answer:
Stop going on peoples pages and answering random things kid, get a life
Learn to solve problems instead
Explanation:
I answered this because this kid just goes on random pages, and answers incorrectly for points. Check this egirl wannabe's profile
Two students with masses of 40kg and 32 kg are sitting 22 m apart. What is the gravitational force of attraction between them?
I get 1.76 x 10^-10 Newton.
That's 0.000 000 000 176 Newton
Which is about 0.000 000 000 635 ounce of force pulling them together.
That's why we never notice it.
When your vehicle turns a corner, the tracks made by the rear tires are always: a) Outside of those made by your front tires b) Inside of those made by your front tires c) On top of those made by your front tires d) None are correct
Answer:
I think it's D
Explanation:
because I have seen the tracks of the tires
train starting from a railway station and moving with a uniform accleration attains a speed of 90km/hr in 10s .Find the accleration
Options
90m/s2
1m/s2
10m/s2
0.1m/s2
Answer:
a= 2.5m/s²
Explanation:
U=0
V=90km/hr
T= 10s
Convert 90km/hr to m/s
1km= 1000m
1hr= 3600s
(60×60)
therefore, 90km/hr = 90000/3600
90km/hr= 25m/s
From Newton First Equation,
V=U + AT
25=0+ A(10)
25= 10A
25/10 =10A/10
A= 2.5m/s²
Which component of weight is cause for S.H.M of bob simple pendulum
Explanation:
The Simple Pendulum. A simple pendulum is defined to have a point mass, also known as the pendulum bob, which is suspended from a string of length L with negligible mass ((Figure)). Here, the only forces acting on the bob are the force of gravity (i.e., the weight of the bob) and tension from the string.
hope it helps you
the unit of energy is same as that of work i.e joule give reason
"Energy" is the ability to do work.
"Work" is the process of using energy.
[tex]what \: is \: reflection \: of \: light \: \: \: \: {?}[/tex]
A system consists of multiple objects connected by ropes. How many equations need to be written to solve this problem?
A) two for each object
B) one or two for each object
C) one for each object
D) two for the system
Answer:
the correct answer is B
Explanation:
To solve the system they must have the same amount of unknowns as equations,
a) If the system does not have friction, we must write the x-axis equation for each body, therefore we need to write N equations
b) if the system has friction, two equations are needed for each particle
therefore the correct answer is B
Explain how you can use the factors of production to produce a fruit juice in a production company
Answer:
The factors of production include Land, Labour, Capital and Enterpreneurship
Explanation:
The fruit could be apple, orange , pineapple etc which are usually grown on land . They are tended to by people to ensure there is maximum yield. These people provide the required labour needed.
The cost of planting and payment of workers usually comes from the capital which is often used in running the business by the owner which makes certain decisions to ensure the fruit company is in place. All these factors work hand in hand to ensure production of fruit in a production company is possible.
Find the sum. Express the answer in scientific notation. (1.54 x 10^6)+(6.15 x 10^6)
Answer:
[tex] { \tt{(1.54 \times {10}^{6}) + (6.15 \times {10}^{6}) }} \\ = { \tt{(1.54 + 6.15) \times {10}^{6} }} \\ = { \tt{7.69 \times {10}^{6} }}[/tex]
action and reaction are equal in magnitudeand opposite in direction then why do they not balance each other ?
Because they act on different objects.
Using diagram 1.1 and diagram 1.2, compare the number of turn of the coils, the pattern of the iron fillings and the angle of deflection of the ammeter pointer
Answer:
The number of turns in the second coil is more than the coil 1.
Explanation:
The magnetic field lines are the imaginary path on which an isolated north pole moves if it is free to do so.
The tangent at any point to the magnetic field line, gives the direction of magnetic field at that point.
More be the crowd ness of magnetic field lines more is the strength of magnetic field.
Here the crowd ness of magnetic field lines is more in figure 2 , so the magnetic filed in figure 2 is more than 1. It shows that the number of turns in the second coil is more than the 1 and also the current in the coil 2 is more than 1 .
Answer the question plz
Answer:
b and d
Explanation:
