which high-speed internet technology uses line-of-sight?

Answers

Answer 1

The high-speed internet technology that uses line-of-sight is fixed wireless. Fixed wireless is a type of high-speed internet technology that uses radio waves to transmit and receive data signals between two fixed points. It typically involves a wireless access point or antenna that is mounted on a tall structure.

Such as a building or tower, and aimed directly at the customer's location. The customer also has a receiver that is pointed back at the access point. One of the key features of fixed wireless is that it requires a clear line-of-sight between the access point and the customer's location. This means that there cannot be any obstacles, such as trees, buildings, or hills, in the direct path of the radio waves. If there is an obstacle in the way, the signal may be blocked or weakened, which can lead to slower speeds or connectivity issues.

Fixed wireless is often used in rural or remote areas where traditional wired internet options, such as cable or DSL, are not available or are too expensive to install. It can also be used in urban areas as a way to provide high-speed internet to buildings or areas that are difficult to wire with traditional methods. In summary, fixed wireless is a high-speed internet technology that uses radio waves and requires a clear line-of-sight between the access point and the customer's location. It is often used in rural or remote areas and can be a cost-effective alternative to traditional wired internet options.

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Related Questions

the part of a network that handles the major traffic is the ________.

Answers

The part of a network that handles the major traffic is the backbone. The part of a network that handles the major traffic is the Backbone. The backbone serves as a primary path for data to travel across networks, ensuring high-speed data transfer and efficient communication between various devices and networks.

Involves understanding that the backbone is a central, high-capacity network infrastructure that interconnects different networks and efficiently manages the major traffic. The backbone serves as a primary path for data to travel across networks, ensuring high-speed data transfer and efficient communication between various devices and networks.

The backbone serves as a primary path for data to travel across networks, ensuring high-speed data transfer and efficient communication between various devices and networks. Involves understanding that the backbone is a central, high-capacity network infrastructure that interconnects different networks and efficiently manages the major traffic.

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Write a second ConvertToInches() with two double parameters, numFeet and numInches, that returns the total number of inches. Ex: ConvertToInches(4.0, 6.0) returns 54.0 (from 4.0 * 12 + 6.0).
#include
using namespace std;
double ConvertToInches(double numFeet) {
return numFeet * 12.0;
}
/* Your solution goes here */
int main() {
double totInches = 0.0;
totInches = ConvertToInches(4.0, 6.0);
cout << "4.0, 6.0 yields " << totInches << endl;
totInches = ConvertToInches(5.9);
cout << "5.9 yields " << totInches << endl;
return 0;
}

Answers

The required code is given as follows

#include <iostream>

using namespace std;

double ConvertToInches(double numFeet, double numInches) {

return numFeet * 12.0 + numInches;

}

int main() {

double totInches = 0.0;

totInches = ConvertToInches(4.0, 6.0);

cout << "4.0, 6.0 yields " << totInches << endl;

totInches = ConvertToInches(5.9);

cout << "5.9 yields " << totInches << endl;

return 0;

}

How does this work?

This code defines a function called ConvertToInches() that takes two parameters numFeet and numInches.

It calculates the total number of inches by multiplying numFeet by 12 and adding numInches to it.

The main() function demonstrates the usage of the ConvertToInches() function by providing sample inputs and displaying the resulting total number of inches.

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Consider the following class definition.
public class Gadget
{
private static int status = 0;
public Gadget()
{
status = 10;
}
public static void setStatus(int s)
{
status = s;
}
}
The following code segment appears in a method in a class other than Gadget.
Gadget a = new Gadget();
Gadget.setStatus(3);
Gadget b = new Gadget();
Which of the following best describes the behavior of the code segment?
A. The code segment does not compile because the setStatus method should be called on an object of the class Gadget, not on the class itself.
B. The code segment does not compile because the static variable status is not properly initialized.
C. The code segment creates two Gadget objects a and b. The class Gadget's static variable status is set to 10, then to 3, and then back to 10.
D. The code segment creates two Gadget objects a and b. After executing the code segment, the object a has a status value of 3 and the object b has a status value of 3.
E. The code segment creates two Gadget objects a and b. After executing the code segment, the object a has a status value of 3 and the object b has a status value of 10.

Answers

The correct answer is:C. The code segment creates two Gadget objects a and b. The class Gadget's static variable status is set to 10, then to 3, and then back to 10.

The code segment generates the objects a and b, two gadgets. Following the code segment's execution, object a and object b both have status values of 3.The code section generates the objects a and b for two gadgets. Following the code segment's execution, object a's status value is 3 and object b's status value is 10.

Take a look at the class definition below.

Public-class Drink

{

numOunces; private int;

numSold is a private static int set to 0;

numOz) public Beverage

{

numberOunces = numberOz;

}

sell(); public static void; int n;

{

Implementation is not displayed.

}

}

Which of the following statements most accurately sums up how much access the sale method has to the numOunces and numSold variables? It is possible to access and edit both numOunces and numSold.

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adherence to the official guidelines for coding and reporting is required under

Answers

Adherence to the official guidelines for coding and reporting is required under the healthcare industry's coding standards.

These guidelines serve as a crucial reference for coding professionals and ensure consistency and accuracy in medical coding. The official guidelines for coding and reporting are established and maintained by the Centers for Medicare and Medicaid Services (CMS) and the National Center for Health Statistics (NCHS) in the United States. These guidelines outline specific rules and principles for assigning codes to medical diagnoses and procedures. The guidelines provide detailed instructions on how to code various medical scenarios and situations and emphasize the importance of proper documentation. It is essential for coding professionals to follow the official guidelines to avoid errors and discrepancies in coding, which could result in denial of claims or inaccurate billing. In conclusion, adherence to the official guidelines for coding and reporting is a critical component of the healthcare industry's coding standards, and it is vital for coding professionals to comply with these guidelines for accurate and consistent coding.

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permutations are used when the order in which different objects are arranged matters. T/F

Answers

True. Permutations are a mathematical concept used to calculate the number of ways in which objects can be arranged when the order in which they are arranged matters.

Permutations are used when the order in which different objects are arranged matters. In the main answer, it is important to know that permutations take into account the arrangement of objects, where the order is significant. In more detail, a permutation is a specific ordering of a set of objects or elements, and it is used to determine the number of possible arrangements for those objects.

The formula for calculating permutations is n! / (n-r)! where n represents the total number of objects and r represents the number of objects being arranged in a specific order.

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Because fiber-optic cabling uses light pulses instead of electrical signals, it is immune to interference and highly resistant to eavesdropping. T/F

Answers

True. Fiber-optic cabling is immune to interference and highly resistant to eavesdropping.

Fiber-optic cabling is designed to transmit data using light pulses, making it immune to interference from electromagnetic radiation that can disrupt electrical signals. This immunity to interference is one of the key advantages of fiber-optic technology.

Unlike traditional copper-based cables, which can be susceptible to electromagnetic interference (EMI) from nearby power lines, radio signals, or other electrical devices, fiber-optic cables are not affected by such external factors. The transmission of data through light pulses allows for high-speed and reliable communication without the risk of signal degradation due to interference.

Additionally, fiber-optic cabling offers enhanced security against eavesdropping compared to electrical signaling. Since the data is transmitted as pulses of light through the fiber strands, it is challenging to intercept these signals without physically tapping into the cable.

Unlike electrical signals that can be intercepted or monitored through induction or wiretapping, fiber-optic signals do not emit detectable electromagnetic radiation that can be easily intercepted. This characteristic makes fiber-optic communications highly resistant to eavesdropping attempts, providing an added layer of security for sensitive data transmission.

In summary, fiber-optic cabling is indeed immune to interference, thanks to its use of light pulses instead of electrical signals. It also offers high resistance to eavesdropping due to the lack of detectable electromagnetic radiation emitted by the fiber-optic signals. These properties make fiber-optic technology a reliable and secure choice for transmitting data over long distances.

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