Which (if any) of the following can be determined by knowing the number of protons in a neutral element? Explain your answer. a. the number of neutrons in the neutral element b. the number of electrons in the neutral element c. the name of the element

The grams of potassium carbonate neede to make 400ml of 2.5M solution is 186g.

A answer's molarity tells you approximately the variety of moles of solute this is found in 1 L of answer. You can say:

Molarity(M)=moles of solute1 litre of answer Molarity(M)=moles of solute/litre of answer

We recognise that with a purpose to calculate a answer's molarity, you must recognise the variety of moles of solute this is found in 1 L i.e. a thousand mL of answer.

We can use the molar mass of a compound to decide the variety of moles gift withinside the pattern so variety of moles of a compound may be calculated via way of means of making use of the subsequent system:

Number of moles=Mass(g)Molar mass(gmol−1)Number of moles=Mass(g)/Molar mass(gmol−1)

In the given question, we already recognise the molarity in addition to quantity of the answer that are as follows:

Molarity=2.5Volume=400mL=0.4LMolarity=2.5Volume=400mL=0.4L

Substituting those given values withinside the system of molarity, we can calculate the variety of moles as depicted below:

1 =moles of solute0.4 variety of moles=1 moles of K2CO32=moles of solute0.2 variety of moles=1 moles of K2CO3

Molar mass of K2CO3K2CO3 may be calculated via way of means of including the atomic mass of every of the atom gift withinside the molecule as proven below:

Molecular mass of K2CO3=(2×K)+(1×C)+(3×O)=(2×39)+(1×12)+(3×16)=138gmol−1Molecular mass of K2CO3=(2×K)+(1×C)+(3×O)=(2×39)+(1×12)+(3×16)=138gmol−1

Now substituting the values withinside the variety of moles system, we get the mass of K2CO3K2CO3 as proven below:

1=Mass(g)138Mass(g)=69g0.five=Mass(g)138Mass(g)=138g

Hence, 138 grams of potassium carbonate K2CO3K2CO3 are had to make four hundred mL of a 2.five M answer.

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Answer: C. 140 g K2CO3

Explanation:

Considering the combined law equation, the pressure when the volume is 1.05 L and the temperature is 308 K is 2.33 atm.

Boyle's law states that the pressure of a gas in a closed container is inversely proportional to the volume of the container, when the temperature is constant.

Mathematically, this law expresses that the product of the pressure by the volume is constant:

P×V= k

where:

Charles' law states that the volume is directly proportional to the temperature of the gas when the pressure is constant.

Mathematically, this law establishes that the ratio between volume and temperature is constant:

V÷T=k

where:

Gay-Lussac's law states that the pressure of a gas is directly proportional to its temperature when the volume is constant.

Mathematically, this law establishes that the ratio between pressure and temperature is constant:

P÷T=k

where:

Combined law equation is the combination of three gas laws called Boyle's, Charlie's and Gay-Lusac's law:

(P×V)÷T=k

Analyzing an initial state 1 and a final state 2, it is fulfilled:

(P₁×V₁)÷T₁= (P₂×V₂)÷T₂

In this case, you know:

Replacing int the combined law equation:

(1.02 atm×2.20 L)÷282 K= (P₂×1.05 L)÷308 K

Solving:

[(1.02 atm×2.20 L)÷282 K] × (308 K÷1.05 L)= P₂

2.33 atm=  P₂

In summary, the final pressure is 2.33 atm.

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The zwitterion form of a tripeptide would show the zwitterion forms of its three individual amino acids.

The needed diagram is attached below:

Peptides and proteins are made up of amino acids. There are 20 common amino acids that may be used to make peptides. Each amino acid has a core carbon atom known as the alpha carbon, which is linked to an amino group (-NH2), a carboxyl group (-COOH), and a distinct side chain R group.

A tripeptide is a peptide that is made up of three amino acids. When an amino acid is in an aqueous solution with a pH equal to its pI, it takes on the zwitterion form (isoelectric point). The amino acid is neutral and exists as a zwitterion at its pI because it contains equal quantities of positive and negative charges.

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Answer:

The name of the super continent that was once made up of all current continents was Pangea

Explanation:

Explanation:

To find ΔrH for the combustion of naphthalene, we can use the equation: ΔrH = qp / n

where qp is the heat absorbed by the bomb calorimeter and n is the number of moles of naphthalene.

First, we need to find qp. We can use the formula: qp = mcΔT

where m is the mass of naphthalene, c is the specific heat capacity of the calorimeter, and ΔT is the change in temperature.

Given that m = 1.312 g, c = 4.184 J/g°C, and ΔT = 30.188 - 24.710 = 5.478 °C

qp = (1.312 g)(4.184 J/g°C)(5.478 °C) = 27.948 J

Next, we need to convert the mass of naphthalene to moles. We can use the molar mass of naphthalene, which is 128.17 g/mol

n = m / M = 1.312 g / 128.17 g/mol = 0.0103 mol

Finally, we can use the equation ΔrH = qp / n to find ΔrH:

ΔrH = qp / n = 27.948 J / 0.0103 mol = 2713.8 J/mol

Therefore, the ΔrH for the combustion of naphthalene at 298 K is 2713.8 J/mol.

In addition to the 4Ps of marketing, it is also important to consider the sustainability, ethics and social responsibility in the twenty-first century marketplace when launching a campaign. It is important to consider the impact the product, service or campaign has on the environment and the society, how it is produced and how it is marketed to the public. Additionally, understanding the target audience, their demographics and what they value is important to create an effective marketing campaign.

C: "Stability of the conjugate base"  is a factor that does not influence the strength of an acid.

The strength of an acid is primarily determined by the ease with which it donates a proton (H+) to water, forming hydronium (H3O+) ions. The factors that influence the strength of an acid include:

However, the stability of the conjugate base (the species formed after the H atom has been donated) does not have a significant effect on the strength of an acid. This is because the stability of the conjugate base is largely determined by the stability of the corresponding anion, which is not directly related to the ability of the acid to donate a proton.

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White soft paraffin is used as a barrier cream, forming an oil layer on the skin's surface to prevent water from evaporating.

Define zinc oxide?

Zinc oxide is a topical medication used to treat or prevent minor skin irritations such as burns, cuts, and diaper rash. Some items can be used as sunscreen.

Zinc Oxide which is also known as Calamine or Zinc White is an inorganic compound. It basically occurs naturally as the mineral zincite. It is mostly manufactured synthetically.

Zinc oxide powders are commonly found in foot powders and makeup. It is also used as an ointment in diaper rash and sun protection products.

Zinc oxide is a sunscreen ingredient derived from minerals. Zinc oxide is ideal for both daily and intense sun exposure due to its ability to block the broadest spectrum of UV light. It protects against both UVA and UVB rays.

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The correct options are: 1. Anions are larger than their parent atoms and are therefore more polarizable. 2. The greater the number of electrons a particle has, the greater its polarizability will generally be. 3. Polarizability increases down a group on the periodic table.

These trends are due to the fact that anions have a higher electron to nucleus ratio, making the electron cloud more susceptible to polarization. Similarly, as the number of electrons increases in an atom, the electron cloud becomes more diffuse, increasing its polarizability.

Finally, as you move down a group in the periodic table, the number of electron shells increases, leading to a more diffuse electron cloud and an increase in polarizability.

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Explanation:

To make 100 mL of a 1 M NaCl solution, you need to add 58.44 grams of NaCl (sodium chloride).

The formula for molarity (M) is:

M = m/V

where

m = mass of solute (NaCl)

V = volume of solution (100 mL)

Given that M = 1, we can rearrange the formula to find m:

m = M x V

m = 1 x (0.1 L) x (58.44 g/mol)

m = 58.44 g

So, you need to add 58.44 grams of NaCl to 100 mL of water to make a 1 M NaCl solution.

The formula for butanol is C₄H₁₀O.

The subscript for H is 10.

The formula for butanol is C₄HₓO.

x = (6.0 × 10²⁴ H atoms/1 mol butanol)

× (1 mol butanol/6.022 × 10²³ molecules butanol)

= 10 H atoms/molecule butanol

∴ The formula for butanol is C₄H₁₀O.

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Butanol is composed of carbon, hydrogen, and oxygen. If 1.0 mol of butanol contains 6.0  1024 atoms of hydrogen, what is the subscript for the hydrogen atom in C4H2O?

After Determining each examples, we found that:

Colligative properties are properties of a solution that depend on the number of solute particles present in the solvent, but not on the chemical identity of the solute. These properties include freezing point depression, boiling point elevation, and vapor pressure lowering.

Non-colligative properties, on the other hand, are properties of a solution that depend on the chemical identity of the solute. They are not dependent on the number of solute particles in the solvent. An example of a non-colligative property is density.

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Average Atomic Mass = (Mass of Isotope 1 x Fractional Abundance of Isotope 1) + (Mass of Isotope 2 x Fractional Abundance of Isotope 2) + ……

To identify the most abundant isotopic form of an element, compare the provided isotopes to the periodic table’s weighted average. The three hydrogen isotopes (seen above) are, for example, H-1, H-2, and H-3. Hydrogen’s atomic mass, or weighted average, is around 1.008 amu ( look again at the periodic table).

Bromine (Br) has an atomic mass of 79.90. The primary isotopes are 79 and 81, which add up to the 79.90amu value. The 79 has 44 neutrons, while the 81 has 46. While it has no effect on the normal atomic mass, scientists have created bromine isotopes with masses ranging from 68 to 97.

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Answer:

the reactants and products in a reaction

Explanation:

Brainliest pls

The volume of the NO is 8.5 L.

The balanced chemical reaction equation is given as;

2NH3 (g) + 5/2 O2 (g) → 2NO (g) + 3H2O (l)

Number of moles of the ammonia = 8.00 g /17 g/mol

= 0.47 moles

Number of moles of oxygen = 14.0 g/32 g/mol

= 0.44 moles

If 2 moles of ammonia reacts with 2.5  moles of oxygen

0.47 moles of ammonia reacts with 0.47 * 2.5/2

= 0.59 moles

Oxygen  is the limiting reactant here.

2.5 moles of oxygen produces 2 moles of NO

0.44 moles of oxygen would produce 0.44 * 2/2.5

= 0.35 moles

Mass of the NO =  0.35 moles * 30 g/mol

= 10.5 g

Volume of the NO = 10.5g/1.23 g/L

= 8.5 L

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-269.15 degree Celsius is the temperature at which cadmium becomes superconducting.

When chilled below a threshold temperature, certain materials have the ability to conduct direct current (DC) electricity without losing energy (referred to as Tc). When these materials reach the superconducting state, they also release magnetic fields.

One of nature's most fascinating quantum phenomena is superconductivity. It was found in mercury that had been cooled to liquid helium temperature, or about -452 °F, or only a few degrees above absolute zero, more over 100 years ago.

Early on, scientists were able to describe what happened in superconductivity, but for nearly 50 years, the why and how of superconductivity remained a mystery.

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Answer:

The blades are kept near the surface by tiny floats. These hollow gas-filled bladders are called pneumatocysts. Kelp blades also allow photosynthesis

Explanation:

According to the query, they will create an ionic bond by sharing electrons to fill out their respective eight valence electrons. BeO

Here are 2.228 moles of beryllium oxide, or BeO. BeO is stated as the chemical formula for beryllium oxide. The amount of beryllium oxide that was produced weighs 555.7 grams. To determine the number of moles, The moles are calculated by dividing the substance's mass by its molar mass. Molar mass = Mass formed 55.7 grams of BeO were produced in total. BeO has a molar mass of 25g/mol. Assigning values, BeO moles = 55.7/25 BeO is made up of 2.228 moles. Therefore, 2.228 moles of beryllium oxide were produced. The ability of an element to combine with other atoms to form chemical compounds or molecules is measured by the element's valence or valency.

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The reactions C and F are the nonspontaneous  reactions.

We have to note that a reaction is said to be spontaneous when the reaction can be able to proceed on its own and we do not need to do a further input of energy into the system.

No we know that the kind of redox reaction in which we can have the Ecell as a positive value is the type that we can be able to call a spontaneous reaction and those are the one that have been selected above in the options that we have above.

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The final volume of the of the dilute solution is 0.13 L. This is calculated by using dilution equation.

Dilution is defined as the process of decreasing the concentration of a solute in a solution by mixing with more solvent like adding more water to the solution. Dilution means to add more solvent without the addition of more solute. Dilution decreases the concentration of the solute in the solution. According to the dilution equation,

    M1V1  = M2V2  

Here, M1 is the initial concentration, V1 is the initial volume, M2 is the concentration after mixing or diluting and V2 is the total final volume of the solution.

M1 = 3.13 M  

V1  = 41.6 mL

M2  = 1.00 M  

V2 = M1V1 / M2

V2 = 3.13 x 41.6 / 1.00

V2 = 130.21 mL

    = 0.13 L

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The volume (in mL) of the gas when the barometer reads 740 mmHg is 243.24 mL

The following data were obtained from the question given above:

The new volume of the gas can be obtained by using the Boyle's law equation as shown below:

P₁V₁ = P₂V₂

720 × 250 = 740 × V₂

180000 = 740 × V₂

Divide both sides by 740

V₂ = 180000 / 740

V₂ = 243.24 mL

Thus, we can conclude from the above calculation that the volume is 243.24 mL

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Answer:

The equation shows that for every 1 mole of KCIO3 that is decomposed, 1 mole of KCI is produced.

If 5.0g of KCIO3 is decomposed, we can use the molar mass of KCIO3 to convert that to moles.

Molar mass of KCIO3 = 39 + 35.5 + 3(16) = 138.5 g/mol

5.0g of KCIO3 is equal to (5.0g / 138.5 g/mol) = 0.036 moles

And since 1 mole of KCIO3 produces 1 mole of KCI, 0.036 moles of KCIO3 will produce 0.036 moles of KCI.

To convert that to grams, we use the molar mass of KCI, which is 39 + 35.5 = 74.5 g/mol

So, 0.036 moles of KCI is equal to (0.036 moles * 74.5 g/mol) = 2.69g of KCI.

The substances would be liquid at the temperature of 98°C

The boiling point is the temperature at which a liquid changes its state to a gas (boils) under standard atmospheric pressure. It varies for different substances.

We know that the liquid range of the object is the temperature range between the melting point and the point where the liquid is changed into gas. Thus we are told that a substance melts at 114°C and boils at 184°C. It would be liquid at the temperature of  98°C

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The answer is  A) 2.3 × 104 lb CO.

Per mile ridden, the motorcycle emits carbon monoxide(CO)e, we must first change the distance from miles to kilometers. Since 1 kilometer equals 0.621371 miles, 15,000 miles equal 24140.25 km.

The entire amount of CO created can now be calculated by multiplying the emission rate by the distance traveled.

2.28 104 g CO is equal to 9.5 g CO/km * 24140.25 km.

The options in the question are in pounds, thus we must first convert this number to pounds.

If 1 lb is equal to 453.59 g, then 5.03 g CO per 453.59 g/lb equals 2.28 g 104 g CO.

We can state that the result will be 2.3 x 104 pounds of CO by rounding up.

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4-12 , carbon atoms and the boiling range

The hydrocarbons in gasoline generally comprise 4-12 carbon atoms and have a boiling range of 30 to 210 °C, whereas diesel fuel has hydrocarbons with 12-20 carbon atoms and a boiling range of 170 to 360 °C.

Hydrocarbons are a type of chemical that exclusively consists of hydrogen and carbon atoms. Polycyclic aromatic hydrocarbons, or PAHs, are those that combine hydrogen with carbon atom rings. Hydrocarbons containing additives, such as gasoline, are also mentioned. Gasoline is a petroleum-derived product that consists of a combination of liquid aliphatic and aromatic hydrocarbons with carbon atoms ranging from C4 to C12 with a boiling temperature range of 30-225°C.

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Indicator compounds are substances that change color in light of changes in pH. They are utilized to decide the acidity or basicity of a solution.

Similarities:

All indicators change color in light of changes in pH, demonstrating the presence of an acidic or basic solution.

The color change of most indicators is slow, taking into consideration the constant measurement of pH over a range of values.

Most indicators have an alternate color at the pH at which they are neutral (neither acidic nor basic) and at the pH values that are either acidic or basic.

Differences:

The range of pH over which an indicator changes color can differ. A few indicators might change color over an exceptionally limited range of pH values, while others might change color over a more extensive range.

The specific colors that an indicator exhibits at different pH values can also vary. Some indicators may show several different colors over their range of pH, while others may only show two or three different colors.

The responsiveness of an indicator can likewise shift. A few indicators might display a more perceptible color change at a given pH, while others might have a less articulated change.

In conclusion, while all indicators change color because of changes in pH, the particular range of pH over which they change color, the particular colors they display, and the awareness of their color change can fluctuate between various indicator compounds.

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Mg and S are atoms, H₂ and SO₃ are molecules and HBr is a molecule.

The smallest component of ordinary stuff that makes up a chemical element is an atom. On the periodic table, they are listed.

An electrically neutral collection of two or more atoms bonded together by chemical bonds is referred to as a molecule.

Both sulfur and magnesium are atoms, and we can both find them on the periodic table.

H₂, a molecule made up of two hydrogen atoms. A molecule known as SO₃ has one sulfur atom and three oxygen atoms.

Your question is incomplete but most probably your full question was

Classify the following statements as describing atoms, molecules, or both. drag the appropriate items to their respective bins. a. Mg S b. H2 SO3 c. HBr

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Question 6:

Calcium sulfate dihydrate is a chemical compound with the formula CaSO4•2H2O, which means it contains one calcium, one sulfur, four oxygen, and two water molecules. The chemical formula of sodium carbonate is Na2CO3, which means it contains 2 sodium, one carbon and 3 oxygen atoms.

The compound you mentioned contains 4.8 moles of sodium carbonate (Na2CO3) which is not a component of Calcium sulfate dihydrate(CaSO4•2H2O) thus the question is invalid.

Question 7:

To find the number of moles of water in the sample, you need to use the molar mass of water. The molar mass of water is 18.02 g/mol.

1.17 g of water / 18.02 g/mol = 0.0649 moles of water

So, the sample contains 0.0649 moles of water.

Sodium acetate trihydrate is chemical compound with the formula CH3COO-Na.3H2O which means it contains one sodium, 2 acetate and 3 water molecules.

The current that is required to deposit 0.175 grams of iron metal in 839 seconds, from a solution 2+ that contains Fe²⁺ ions is 0.718 A.

The current that is required to deposit 0.175 grams of iron metal in 839 seconds, from a solution 2+ that contains Fe²⁺ ions is calculated as follows;

Moles of Fe in 0.175 grams =  0.175/56

Moles of Fe in 0.175 grams = 0.003125 moles

2 * 96500 C are required to discharge 1 mole of Fe

Quantity of charge required = 2 * 96500 C * 0.003125

Quantity of charge required = 603.125 C

Current = Charge / time

Current = 603.125 /  839

Current required = 0.718 A

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It is stated in this query that p above p is the rule when using the Clausius-Claparon equation.

According to what I'm going to explain, p not will be our boiling point, and that value will be equal to delta minus. The boiling point is determined by the formula: H, vapor pressure over r 1 over t minus 1 over t not and again t not. Thus, a pressure line can be seen here. According to what we've been told, it is 1 o 9 miles per hour. 680 would enter there, followed by delta h, at a distance of 6080000000 meters from Mercury. The vapourization factor is 2.46. I'm not going to include the units in this section because ideal gas has a constant 8.314 joules per mole.

It is - 66 degrees Celsius when mole kelvin is subtracted from the initial temperature. Since our boiling point would be 2 o 7 kelvin minus 1 over t, that would convert to that value. This will be plugged into my equation using the solver here, which yields 237 kelvin when accounting for t. The boiling point at 680 millimeters of mercury would be minus 273, which gives me a result of minus 36 degrees celsius, and we then translated that to degrees celsius.

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