Which is incorrect? multiple choice at equilibrium, ecell = 0. e > 0 for a spontaneous process. e = 0 for a spontaneous process. δg < 0 for a spontaneous process. δg = 0 at equilibrium.

Answers

Answer 1

The incorrect statement is e = 0 for a spontaneous reaction.

e cell = 0

The cell potential is 0 at equilibrium.

e > 0 for a spontaneous reaction

For a spontaneous reaction the value cell potential E cell is positive i.e. >0

e = 0 for a spontaneous reaction

This statement is incorrect because the potential of a cell is positive if the reaction is spontaneous. Hence it cannot be zero.

δ g < 0 for a spontaneous reaction

For a spontaneous reaction gibbs free energy δ g value is negative i.e. < 0

δg = 0 at equilibrium.

At equilibrium the value of gibbs free energy is zero i.e. δg = 0

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Related Questions

A certain first order reaction has a half-life of 54. 3 s. How long will it take (in s) for the reactant concentration to decrease from 6. 50 m to 2. 27 m?

Answers

Answer:

82.4 s

Explanation:

Find the NUMBEr of half lives...then multiply by 54.3

2.27 = 6.5 (1/2)^n

log (2.27/6.5) / log (1/2) = n = 1.52 half lives

1.52 * 54.3 = 82.4 s

Draw the major product of the reaction between 1-butanol and na2cr2o7, h2so4, h2o

Answers

The major product of reaction between 1-butanol and Na2Cr2O7 is butanoic acid.

When a primary alcohol like 1-butanol (OH is bonded to a primary carbon) is begin to oxidize in the presence of strong oxidizing reagent such as sodium dichromate (Na2Cr2O7) and H2SO4, sulfuric acid, the stepwise oxidation take place as above firstly to the corresponding aldehyde which undergoes further oxidation to the corresponding carboxylic acid.

You can find that the formed aldehyde after first oxidation is butanal and the only organic product, due to the strong oxidizing reagent is butanoic acid.

Thus, the major product formed is butanoic acid.

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1) Calculate the empirical formula for a chemical compound that gives the following analysis: 66.6 g titanium and 33.4 g oxygen.
a) Ti_2O_3
b) Ti_2O
c) TiO_3
d) Ti_2

2) The empirical formula for a compound shows the symbols of the elements with subscripts indicating what?

a) actual numbers of atoms in a molecule
b) number of moles of the compound in 100 g
c) smallest whole-number ratio of the atoms
d) atomic masses of each element

3) In the tin oxide laboratory activity, what was the color of the vapor emitted when the nitric acid was added to the tin?

a) orange-brown
b) pink
c) green
d) blue

4) What is the empirical formula for a compound that is 36.6 percent potassium, 33.2 percent chlorine, and 29.9 percent oxygen?

KClO_2
KClO_3
K_2Cl_2O
K_2Cl_2O_5

5) What is the empirical formula for a compound that is 43.6 percent phosphorus and 56.4 percent oxygen?

P_3O_7
PO_3
P_2O_3
P_2O_5

Answers

1. The empirical formula of the compound is Ti₂O₃

2. The correct answer to the question is: smallest whole-number ratio of the atoms (Option C)

3. The correct answer to the question is: orange-brown (Option A)

4. The empirical formula of the compound is KClO₂

5. The empirical formula of the compound is P₂O₅

1. How to determine the empirical formulaTi = 66.6 gO = 33.4 gEmpirical formula =?

Divide by their molar mass

Ti = 66.6 / 48 = 1.3875

O = 33.4 / 16 = 2.0875

Divide by the smallest

Ti = 1.3875 / 1.3875 = 1

O = 2.0875 / 1.3875 = 3/2

Multiply by 2 to express in whole number

Ti = 1 × 2 = 2

O = 3/2 × 2 = 3

Thus, the empirical formula of the compound is Ti₂O₃

2. What is empirical formula?

This is the simplest formula of a compound which shows the smallest whole number ratio of the atoms present in the compound

With the above definition, we can conclude that the correct answer to the question is: smallest whole-number ratio of the atoms (Option C)

3. What colour is shown when nitric acid is added?

In the tin oxide laboratory activity, the colour of the vapor emitted when nitric acid is added to the tin is: orange-brown

NOTE: This colour is visible when we carryout the practical experiment

Thus, the correct answer to the question is orange-brown (Option A)

4. How to determine the empirical formulaK = 36.6%Cl = 33.2%O = 29.9%Empirical formula =?

Divide by their molar mass

K = 36.6 / 39 = 0.9385

Cl = 33.2 / 35.5 = 0.907

O = 29.9 / 16 = 1.8688

Divide by the smallest

K = 0.9385 / 0.907 = 1

Cl = 0.907 / 0.907 = 1

O = 1.8688 / 0.907 = 2

Thus, the empirical formula of the compound is KClO₂

5. How to determine the empirical formulaP = 43.6%O = 56.4%Empirical formula =?

Divide by their molar mass

P = 43.6 / 31 = 1.406

O = 56.4 / 16 = 3.525

Divide by the smallest

P = 1.406 / 1.406 = 1

O = 3.525 / 1.406 = 5/2

Multiply by 2 to express in whole number

P = 1 × 2 = 2

O = 5/2 × 2 = 5

Thus, the empirical formula of the compound is P₂O₅

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How many grams of NaCl are needed in order to make a liter of a 2.00 M NaCl solution? O 58.4 g O 117 g O 2.00 g​

Answers

Answer:

B.) 117 g

Explanation:

(Step 1)

To find the mass, you need to first find the moles of NaCl using the molarity  ratio.

Molarity = moles / volume (L)

2.00 M = moles / 1.0 L

2.00 = moles

(Step 2)

Now that you know the moles, you can convert it to grams using the molar mass.

Molar Mass (NaCl): 22.990 g/mol + 35.453 g/mol

Molar Mass (NaCl): 58.443 g/mol

2.00 moles NaCl          58.443 g
---------------------------  x  -----------------  =  117 g NaCl
                                        1 mole

How many different products can be formed from a poorly planned crossed aldol addition?
a. 1
b. 2
c. 3
d. 4
e. 5

Answers

There are 4 different products will be formed from a poorly planned crossed aldol addition.

In a crossed aldol condensation, two distinct ketone and aldehyde reactants are used. Due to the possibility of several enolate nucleophiles as well as multiple carbonyl electrophiles, similar reactions typically result in a variety of distinct condensation products.

Ethanol and propanol undergo cross-aldol condensation, which results in two products:

one where ethanol serves as an enolate ion and the other where propanol serves as an enolate ion. 2-Methylbut-2-enal and Pent-2-enal are just the two cross-aldol derivatives.

Therefore, the correct answer will be option (d)

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There are four different products can be formed from a poorly planned crossed aldol addition.

So the correct option is D

Two distinct ketone and aldehyde reactants are used in a crossed condensation reaction. Due to presence of distinct ketone and aldehyde reactants there are possibility of formation of several enolate ion nucleophiles as well as multiple carbonyl electrophile .

Example : Ethanal and propanone undergoes cross-aldol condensation reaction and give results in two products.

First case: ethanal acts as enolate ion

Second case: propanone acts as enolate ion

Third case: when self condensation is also a product.

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How can we increase the rate of collisions between the reactants in this reaction? mg 2hcl → mgcl2 h2

Answers

The frequency of collisions between the two reactants increases as the concentration of the reactants increases. When collisions happen, they don't always cause a reaction (atoms misaligned or insufficient energy, etc.). Higher concentrations result in more collisions and reaction opportunities.

Increasing a reactant's surface area increases the frequency of collisions and thus the reaction rate. The surface area of several smaller particles is greater than that of a single large particle. The greater the available surface area for particles to collide, the faster the reaction will occur.

How does concentration affect the rate of collisions between reactants?

Thus, we can conclude that by increasing the concentration of Mg in the reaction mixture we increase the rate of collisions between the reactants in this reaction.

What does the half reaction of an oxidation-reduction reaction show?

Iron gains electrons in the half reaction of an oxidation-reduction reaction. What does iron's electron gain mean? It has been reduced. Predict the product that will precipitate out of the reaction using the solubility rules and the periodic table.

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What are the conjugate acid-base pairs in the reaction of h2seo4h2seo4 with h2oh2o? h2seo4 h2o→productsh2seo4 h2o→products view available hint(s)

Answers

The conjugate acid is H2SeO4 and the conjugate base pairs in the reaction is H2O.

The full equation of the reaction is

H2SeO4 + H2O----- H3O^+(aq) + HSeO4

What is conjugate base?

Conjugate base are those substance formed when an acid loses a hydrogen ion. Considered a base because it can gain a hydrogen ion to reform the acid.

The conjugate acid is the species that donate a proton to the conjugate base, hence H2SeO4 is the conjugate acid while H2O is the conjugate base because it accepts a proton from H2SeO4.

Thus we concluded that the conjugate acid is H2SeO4 and the conjugate base pairs in the reaction is H2O.

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What laboratory conditions (temperature and pressure) were assumed when calculating ksp based on measured electrochemical potential?

Answers

The temperature of the lab is assumed at 25°C while calculating Ksp. Pressure of the lab is assumed at 1 atm normal atmospheric conditions while calculating Ksp.

If we increase the temperature of the solvent, the average kinetic energies of the molecules start increases. Hence, the solvent is more able to dislodge more molecules from the surface of the solute. Thus, by increasing the temperature the solubilities of substances also increases. Temperature is directly proportional to the solubility.

As we goes on increasing the pressure of a gas, the collision between the molecules start increasing and thus the solubility goes up, as we decrease the pressure, the number of collision decreases thus solubility goes down.

Thus, with further increase in the temperature and pressure the Ksp value changes. Thus, temperature of the lab is assumed at 25°C while calculating Ksp. Pressure of the lab is must be 1 atm normal atmospheric conditions while calculating Ksp.

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Consider the hydrocarbon below. a skeletal model has line segments that slant down, run flat in a double bond, slant up, and run flat. which of these is a trans- isomer of the above hydrocarbon?

Answers

The correct answer would be the structure attached of the form slant up, then run flat in a double bond, slant up and run flat.

Cis-Trans isomerism(GEOMETRIC ISOMERS)Cis-trans isomers are compounds that, as a result of the existence of a hard-structure in their molecule, have distinct configurations (elements that are constantly in distinct places in space).Cis-trans isomerism may be seen in alkenes and cyclic molecules.trans-isomers: the two hydrogen atoms are on opposite sides.cis-isomers: the two hydrogen atoms are on the same side, as are the two carbon groups.

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Answer:

D

Explanation:

HELP PLS.. I’LL MARK U BRAINLIEST!

Answers

Old and inefficient mining smokestacks contaminate the soil around abandoned mine sites.

What are mines?

A mine is an area from which natural resources are extracted such as coal, metals, etc. A mine is known to be the source of many heavy metals as well as acid.

As such the statement that does not represent the impact of mining services is that; "Old and inefficient mining smokestacks contaminate the soil around abandoned mine sites".

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A coin collector has a bag of 50 pennies. What is weighted average of a penny in the sample according to the data?

Answers

The weighted average of a penny is = 67.9g

Calculation of average weight

The sample of penny for pre 1982 is a total of = 18 pennies.

The mass of each penny for pre 1982 = 3.1

Therefore the total weight for penny for pre 1982

= 18×3.1

= 55.8

The sample of penny for post 1982 is a total of = 32 pennies.

The mass of each penny for post 1982 = 2.5

Therefore the total weight for penny for post 1982

=32×2.5

= 80

The weighted average

= 55.8+80/2

= 135.8/2

= 67.9g

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If the change in entropy of the surroundings for a process at 451 k and constant pressure is -326 j/k, what is the heat flow absorbed (in kj) by the system?

Answers

If the change in entropy of the surroundings for a process at 451 k and constant pressure is -326 j/k, then heat flow absorbed (in kj) by the system is -147.026kJ.

What is entropy?

The entropy of particle is defined as how random it move. It shows the randomness of the system or may be disorders of the system. It is used to measure the unavailable energy for performing useful work.

Unit of entropy = J/K

Formula:

∆s = ∆Q/T

where,

∆s = change in entropy of the surrounding = -326J/K

∆Q = heat absorbed from surrounding

T = Temperature = 451K

∆Q = ∆s × T

∆Q = -326 × 451

∆Q = 147,026 J

∆Q = 147.026 kJ

Thus we find that the heat absorbed by the system is 147.026 kJ.

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How many grams of mgo are produced by the reaction of 25. 0 g of mg with 25. 0 g of o2?

Answers

When 25.0 g of Mg react with 25.0 g of O₂ it produce 41.9g of MgO.

Chemical reaction:

2Mg + O₂ → 2 MgO

Given,

Mass of Mg = 24g

Mass of O₂ = 25 g

Molar mass of O₂ = 16×2

= 32 g

Molar mass of Mg = 24.3

Moles of Mg  =25/24.3

=1.04mole

Moles of O₂  =25/32

=0.78mole

From above reaction we can say that 2moles of mg react with 1moles of O₂ to give 2moles of MgO.

So, 1 mole of Mg react with 0.5 mole of O₂ to produce 1mole of MgO.

So, 1.04 react with= 0.5× 1.04

= 0.520 g oxygen to give 1.04 moles of MgO.

From above we can say that Mg is limiting reagent.

Moles of MgO =1.04

Molar mass of MgO =40.3

Mole =given mass/ molar mass

1.04  =mass/ 40.3

Mass = 1.04×40.3

41.9 g

Thus, from above we concluded that 25.0 g of Mg react with 25.0 g of O₂  it produce 41.9g of MgO.

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Sodium hydroxide and water will react at room temperature. what does this indicate about its activation energy?

Answers

Answer:

Sodium hydroxide and water will react at room temperature. What does this indicate about its activation energy? The activation energy is at exactly 600 kJ. C. The activation energy is very low.

Explanation:

If 36. 0 ml of 0. 20 m hcl is added to 30. 0 ml of 0. 40 m naoh, what will be the ph of the resulting solution?

Answers

The pH of the resulting solution is 2.05

Sodium hydroxide and hydrochloric acid neutralize each other in a 1:1 mole ratio as described by the balanced chemical equation

           [tex]NaOH_{(aq)} + HCL_{(aq)}[/tex] →  [tex]NaCl_{(aq)} + H_2O_{(aq)}[/tex]

This means that a complete neutralization, which would result in a neutral solution, i.e. a solution that has pH=7 at room temperature, requires equal numbers of moles of sodium hydroxide and hydrochloric acid.

Notice that your two solutions have equal molarities, but that the volume of the hydrochloric acid solution is 1.2 times larger than the volume of the sodium hydroxide solution. This implies that the number of moles of hydrochloric acid is 1.2 times bigger than the number of moles of sodium hydroxide.

This means that after the reaction is complete, you will be left with excess hydrochloric acid → the pH of the resulting solution will be <7.

Now, the number of moles of hydrochloric acid that will not take part in the reaction is given by

= moles of HCL added - moles of NaOH added

= 36 × [tex]\frac{0.100 moles HCL}{10^3 ml}[/tex] - 30 × [tex]\frac{0.100 moles HCL}{10^3 ml}[/tex]

= [tex]\frac{6* 0.100 moles}{10^3}[/tex]

The total volume of the resulting solution will be = ( 30 + 36 ) mL

                                                                            = 66 mL

Since hydrochloric acid is a strong acid that ionizes in a 1:1 mole ratio to produce hydronium cations, you can say that the concentration of hydronium cations in the resulting solution will be

[tex][ H_3O^+] = \frac{\frac{6*0.100}{10^3} }{66*10^3}[/tex]

[tex][ H_3O^+] = \frac{6*0.100}{66}[/tex]

pH = - log [tex](\frac{6*0.100}{66} )[/tex]

pH =  2.05

Therefore, the pH of the resulting solution is 2.05.

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At constant temperature and pressure the gibbs free energy value is a measure of the __________ of a process.

Answers

At constant temperature and pressure the gibbs free energy value is a measure of the spontaneity of a process.

At constant temperature and pressure the gibbs free energy value is zero and when gibbs free energy value is zero then the process is spontaneous . The meaning of spontaneous  is that the process is takes place smothly with any effect and itself .

The Gibbs free energy also known as Gibbs function , Gibbs energy or free enthapy . It is a quantity that is used to measure maximum amount of work done in a thermodynamic system when temperature and pressure is keep constant.

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What products are formed in the following reaction

Answers

The correct product from this reaction is the structure in option D.

What is a secondary amine?

An amine is a compound that contains an alkyl group and an amino group. We know that we can obtain an amine from ammonia by replacing one or more hydrogen atoms with alkyl groups.

The compound as shown here is a secondary amine because two hydrogen atoms have been replaced with alkyl groups. We know that the reaction between the HCl and the amine produces an ionic compound owing to the fact that the nitrogen and the hydrogen from HCl are involved in a Dative bond.

As such, the correct product from this reaction is the structure in option D.

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When 20. 0 g nh3 and 50. 0 g o2 are allowed to react, which is the limiting reagent?

Answers

When 20. 0 g NH₃ and 50. 0 g O₂ are allowed to react, NH₃ is the limiting reagent.

What is limiting reagent ?

Limiting reagent is defined as that reactant in a chemical reaction which is completely consumed in reaction.

Given,

Mass of NH₃ = 20 g

Mass of O₂ = 50 g

Molecular mass of NH₃ = 14 + 7 = 17 g

Molecular mass of O₂ = 2 × 16 = 32 g

Mole = given mass/ molecular mass

Mole of ammonia = 20/17

                             = 1.17 mole

Moles of O2 = 50/32

                    = 1.56 mole

Chemical equation:

4NH₃(g) + 3O₂(g)  ⟶ 2N₂(g) +6H₂O

From above reaction it is clear that 4 moles of NH₃ react with 3 moles of oxygen.

So, 1 mole of ammonia react with = 3/4 moles of O₂

                                                       = 0.75 moles of O₂

Also, 1.18 moles of ammonia react with

= 1.18 × 0.75

= 0.885 moles of O₂

Thus, from above we concluded that ammonia is completely consumed in reaction. Therefore ammonia is limiting reagent.

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Which compound reacts third fastest with fuming sulfuric acid? a. Toluene b. Chlorobenzene d. Nitrobenzene e. Benzene c. Aniline.

Answers

Toluene compound reacts third fastest with fuming sulfuric acid.

The reaction is attached in figure -

When nitration of toluene is carried out in presence of fuming nitric acid and fuming sulfuric acid under 333 K temperature , 2, 4, 6-trinitro toluene is the final product .This 2, 4, 6-trinitro toluene is also called TNT. TNT is used as explosive.

What is toluene?

Toluene is a common ingredient in degreasers. It's a colorless liquid with a sweet smell and taste. It evaporates quickly. Toluene is found naturally in crude oil, and is used in oil refining and the manufacturing of paints, lacquers, explosives (TNT) and glues.

What is a toluene used for?

Toluene is found naturally in crude oil, and is used in oil refining and the manufacturing of paints, lacquers, explosives (TNT) and glues. In homes, toluene may be found in paint thinners, paintbrush cleaners, nail polish, glues, inks and stain removers.

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When removing nail wraps, it is recommended that when the client places her hand in the bowl of acetone, the acetone be about ____ above the nail wraps.

Answers

When removing nail wraps, it is recommended that when the client places her hand in the bowl of acetone, the acetone be about fully covered above the nail wraps.

What is nail wraps?

Nail wraps, often known as nail paint strips, are nail improvements with printed patterns, glitter, or solid colors. Without the use of glue, they are attached to the nail in a flexible strip. There may be 12 to 22 various sized strips per box, depending on the manufacturer, which takes into account the range in size of each person's fingernail.

Nail wraps have a long history that dates back to the 1980s. The popularity of nail polish and the rise in salon visits gave rise to the demand for a better at-home manicure. Although several companies produced nail wraps and polish strips, it wasn't until the 2000s that they truly started to catch popularity. Since then, their appeal has increased.

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An aqueous solution of hso−3 is created at 25∘c. is the solution acidic, basic, or neutral?

Answers

An aqueous solution of hso−3 is created at 25∘c. is the solution basic in nature.

An aqueous solution is a solution wherein the solvent is water. Its miles are primarily shown in chemical equations by appending them to the relevant chemical formula.

An aqueous solution is a water that carries one or more dissolved materials. The dissolved substances in an aqueous answer can be solids, gases, or different beverages.

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At 25°C, an aqueous solution of hso3 is formed. This is the solution basic in nature.

Aqueous solutions are those in which the solvent is water. Its miles are often represented in chemical equations by attaching them to the appropriate chemical formula.

An aqueous solution is a mixture of water and one or more dissolved components. Solids, gases, or various beverages can be dissolved in an aqueous solution.

Aqueous solutions contain liquid water as the solvent. Solute (dissolved) ions and molecules are surrounded by water molecules and absorbed into the water's network of bonds. After then, the dissolved species diffused throughout the water.

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Explain how the rate of diffusion of a gas is related to its molar mass.
carbon dioxide gas (co2) effuses 3.2 times faster than an unknown gas. determine the molar mass of the unknown gas. show your work or explain your answer, giving specific values used to determine the answer.

Answers

The molar mass of the other gas is 450.56 g.

Calculation:

Relation between rate of diffusion and molar mass of two gases is given by:

r₁/r₂ = (√m₂)/(√m₁)

Given,

r₁ = 3.2r₂                          

(r₁ is the diffusion rate of CO₂ and r₂ is the diffusion rate of the other gas)

We know

m₁ = molar mass of CO₂ = 44 g

To find,

m₂ = molar mass of the other gas =?

Put the values in the above equation,

r₁/r₂ = (√m₂)/(√m₁)

3.2r₂/r₂ = (√m₂)/(√44)

3.2 = (√m₂)/(√44)

Squaring both the sides,

10.24 = m₂/44

m₂ = 10.24 (44)

m₂ = 450.56 g

Hence, the molar mass of the other gas is 450.56 g.

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Identify the classification of whipped cream. group of answer choices aerosol solid aerosol foam emulsion solid emulsion

Answers

The classification of whipped cream is a foam.

So, option C is correct one.

The whipped cream is a colloid and it consists of gas ( dispersed phase ) in liquid ( dispersed medium) system.

Sol is a solid dispersed in the liquid . Examples includes Au , S sol in water , milk of magnesia .

The emulsion is liquid dispersed into the liquid . Example is milk

Foam is a gas dispersed into the liquid . Examples includes whipped cream  , shaving cream , foam on the beer .

Gel is the liquid dispersed into the solid . Examples includes , butter , jellies .

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What two properties (one chemical and one physical) combine to make bromcresol green useful as an acidity indicator?

Answers

Two properties are :

Bromcresol green is useful as an acidity indicator because it changes to yellow as the pH becomes more acidic

Also, the bromcresol green protons are easily dissociated making the color change visible and relatively quick.

Why is bromocresol green used as an indicator?

Bromocresol green (BCG) is a dye of the triphenyl methane family (triarylmethane dyes). It belongs to a class of dyes called sulfonephthaleins. It is used as a pH indicator in applications such as growth mediums for microorganisms and titrations.

How does a pH indicator work?

pH indicators detect the presence of H+ and OH-. They do this by reacting with H+ and OH-: they are themselves weak acids and bases. If an indicator is a weak acid and is colored and its conjugate base has a different color, deprotonation causes a color change.

What is chemical change and physical change?

Physical changes are reversible and do not produce a new substance. Chemical changes result in the production of a new substance and cannot be reversed.

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10.0 grams of argon and 20.0 grams of neon are placed in a 1040.0 ml container at 31.5 °c. the partial pressure of neon is ________ atm.

Answers

The partial pressure of neon is 24.0498 atm.

To calculate the partial pressure of neon, we can use the ideal gas equation,

PV = nRT

Pne = nRT / V

Number of moles of neon = Mass of neon / Mass of one mole of neon

n = 20 / 20

n = 1 mole

R = 0.0821 L atm K-1 mol-1

T = 31.5 °C

T = 273.15 + 31.5

  = 304.65 K

V = 1040.0ml

Pne = 1 * 0.0821 * 304.65 / 1040.0 * 10-3

Pne = 24.0498 atm

The partial pressure of neon is 24.0498 atm.

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LOTS OF POINT PLS HELP!!!! What is the balanced, net ionic equation for the reaction shown below? HCI (aq) + NaOH (ag)-> NaCI (aq) +H2P(l)

Answers

The net ionic equation is written as H^+(aq) + OH^-(aq) -------> H2O(l)

What is the net ionic equation?

The term net ionic equation refers to the equation that shows the ions that underwent a change in the reaction. We have to note that the reaction species here must be ionic species which are able to dissociate into ions in solutions.

Now the first step is to put down the molecular equation. The molecular equation shows the reaction of the compounds as follows;

HCI (aq) + NaOH (ag)-> NaCI (aq) +H2O(l)

Next, we put own the complete ionic reaction equation as follows;

H^+(aq) + Cl^-(aq) + Na^+(aq) + OH^-(aq) -------> Na^+(aq) + + Cl^-(aq) + H2O(l)

Next we have the net ionic equation;

H^+(aq) + OH^-(aq) -------> H2O(l)

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Formic acid, which is a component of insect venom, has a ka = 1. 8 ✕ 10-4. what is the [h3o ] in a solution that is initially 0. 10 m formic acid, hcooh?

Answers

The [H3O+ ] in a solution that is initially 0. 10 m formic acid, hcooh is 0.00415M.

What is formic acid?

Formic acid is defined as the simplest carboxalic acid which contain one carbon atom. It is weak acid.

Another name of formic acid is methanoic acid. It is used as the preservation and antibacterial agent in livestock feed.Exposure to Formic Acid can cause headache, dizziness, nausea and vomiting. individuals, may cause a skin allergy.

Thus we concluded from the image that the

concentration of [H30+] is 0.00413M.

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Copper has a delta.hfus = 13.0 kj/mol. what mass of copper releases 112.4 kj of heat as it freezes? use q equals n delta h.. 9.42 g 6.75 g 549 g 1590 g

Answers

The mass of copper releases 112.4 kj of heat as it freezes is 549 gm.

What is heat of fusion?

The most typical illustration is when solid ice transforms into liquid water. The molecules within in the substance become less structured as a result of this process, which is also known as melting or heat of fusion.

Calculation for mass of copper;

The heat of fusion for copper is given as 13.0 kj/mol.

Hfus(Cu) = 13.0 kJ/mol

The heat released during the process is  112.4 kj.

Q = 112.4 kJ;

The formula for molar heat of substance is;

Q = n(Cu) · Hfus(Cu).

Where n(Cu) is the number of moles of copper present in the solution.

Write formula in terms of Number of moles.

n(Cu) = Q / Hfus(Cu)

Substitute the given values;

n(Cu) = 112.4 kJ / 13.0 kJ/mol.

n(Cu) = 8.65 mol (number of moles of copper present)

m(Cu) = n(Cu) · M(Cu).

Where, m(Cu) is the mass of copper.

M(Cu) is the molecular mass of the copper.

Substitute the values in the formula to get the mass.

m(Cu) = 8.65 mol × 63.546 g/mol.

m(Cu) = 549.428 g

Therefore, the mass of copper present in the solution was 549.428 g.

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Answer: C.) 549 g

Explanation:

Identify the substance that conducts electricity. question 19 options: 1) nacl dissolved in water 2) solid nacl 3) solid sugar 4) sugar dissolved in water

Answers

The substance that conducts electricity is [tex]NaCl[/tex] dissolved in water.

So, option A is correct one.

When the sodium chloride dissolve in water , the sodium atoms and chlorine atoms separates under the presence of water molecules and exist as sodium cation and chloride anion . Now , they are free to move around in the water as positively and negatively charged ions . This separation of charge allows the solution to conduct electricity.

The solid [tex]NaCl[/tex] and solid sugar does not conduct electricity because it is not dissolve in water . Similarly, sugar dissolved in water does not conduct electricity .

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How many moles of iron atoms are obtained from 320kg of iron oxide

Answers

Answer: 4010 mol of iron atoms

Explanation:

Given Information

Iron Oxide = Fe₂O₃

Mass = 320 kg

Given atomic mass / molecular weight

Fe = 55.8 g / mol

O = 16.0 g / mol

Fe₂O₃ = 55.8 × 2 + 16.0 × 3 = 159.6 g / mol

Given formula

n = m / M

n = number of molesm = massM = molecular weight

Convert the unit of mass to Gram

1 kg = 1000 g

320 kg = 320 × 1000 = 320 000 g

Substitute values into the given formula

n = m / M

n = (320000) / (159.6)

n ≈ 2005 mol of Fe₂O₃

Calculate the number of moles of Fe (Iron atoms)

Since each mole of Fe₂O₃ has 2 moles of Fe, then:

                                 

                                 2005 × 2 =[tex]\Large\boxed{4010~mol~of~Fe}[/tex]

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