Which number of simulation trials would be likely to produce results that are closest to those predicted by probability theory?
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A simulation will produce closer results if the number of trials is increased. In other words, the higher the number of trials performed, the closest to those predicted by probability theory.
Among the given choices, the highest number of trials is 70.
Therefore, the answer should be CHOICE B.
Related Questions
x-5y=-6x+2y=8a. 2/3b. 2c. 4d. 4 2/3
Answers
Answer
Option B is correct
y = 2
x = 4
Explanation
We need to solve the simultaneous equation
x - 5y = -6
x + 2y = 8
To do this, we will just subtract equation 2 from equaton 1 to eliminate x first
x - 5y = -6
x + 2y = 8
x - x - 5y - 2y = -6 - 8
0 - 7y = -14
-7y = -14
Divide both sides by -7
(-7y/-7) = (-14/-7)
y = 2
We can then solve for x
x - 5y = -6
x - 5(2) = -6
x - 10 = -6
x = -6 + 10
x = 4
Hope this Helps!!!
In a 6-by-6 grid two coins are randomly placed in two different cells of the grid. What is the probability that the coins do not lie in the same row or column?
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We have 2 coins placed in one cell of a 6 by 6 grid.
We have to calculate the probability of the two coins not being in the same row or column.
We can think of this as a two-step problem.
The first coin can be in any cell and it won't affect the probability of the two coins being in the same row or column.
Then, once the first coin is placed in a cell, the places where the second coin can be without being in the same row or column of the first coin are limited.
We can see it in a drawing as:
We can then see that the original grid has 6*6 = 36 cells.
If one is occupied by the first coin, 35 cells are left for the secoind coin.
As the coin can not be in the same row or column is like we take one row and one column of the grid: the second coin has 5*5 = 25 cells to be placed without breaking the rule.
Then, if all cells have the same probability for the second coin, there is a probability of 25/35 = 5/7 (approximately 0.71) for the second coin to not be in the same row or column than the first coin.
10.00 divided by 0.38
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An item is regularly priced at $40 . It is on sale for 80% off regular price . What is the sale price ?
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From the information given,
Regular price of item = $40
If it is on sale for 80% off regular price, it means that the amount by which is what reduced or discount is
80/100 x 40 = 32
Sale price = Regular price - discount = 40 - 32
Sale price = $8
2. The points (-2,4) and (-3,-2) lie on the g(x). If g(x) is a linear function, which of the following statements is true? (A) (B) (C) (D) The slope of g(x) is 6 and g(x) is decreasing. The slope of g(x) is - and g(x) is increasing. g)g) . The slope of g(x) is 6 and g(x) is increasing. The slope of g(x) is and g(x) is increasing.
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The slope of the line that passes through the points (x1, y1) and (x2, y2) is computing as follows:
[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]Given that the points (-2,4) and (-3,-2) lie on the g(x), then its slope is:
[tex]m=\frac{-2-4}{-3-(-2)}=\frac{-6}{-1}=6[/tex]Given that the slope is positive, then g(x) is increasing.
The correct choice is (C)
6x - 12y = -243y = 2x + 18These lines : choose one - parallel -concide -intersect and are perpendicular -intersect
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The given equations are
6x - 12y = -24
3y = 2x + 18
We would solve for y in both equations
For 6x - 12y = -24,
12y = 6x + 24
Dividing both sides by 12, it becomes
12y/12 = 6x/12 + 24/12
y = x/2 + 2
For 3y = 2x + 18,
Dividing both sides by 3, it becomes
3y/3 = 2x/3 + 18/3
y = 2x/3 + 6
The equation of a line in the slope intercept form is
y = mx + c
where m is the slope
By comparing both equations, the slopes are different. They are not negative reciprocals of each other. Thus, they are not perpendicular or parallel. Thus, the lines intersect
justify 5(2y-3)-4y=8-2y-15
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We will justify the steps and solve the equation
Statement Justification
Step 1. 5(2y-3)-4y=8-2y-15. Given
Step 2. 10y-15-4y=8-2y-15. Distributive Property
Step 3. 6y-15=23-2y. Combining like terms
Step 4. 6y-15+15=23-2y+15. Addition property of equality
Step 5. 6y+0=38-2y Combining like terms
Step 6. 6y=38-2y Additive identity
Step 7. 6y+2y=38-2y+2y.
Hi, can you help me answer this question please, thank you!
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P (x > Z) = 0.1122
Using the statistical table,
[tex]\begin{gathered} P(z\le z_0)=1.841 \\ P\text{ value, from statistical table is 0.1122} \end{gathered}[/tex]What’s the correct answer answer asap for brainlist
Answers
Shanty towns (areas in a city where poor people live in cheaply built houses) were nicknamed “Hoovervilles”
In cities, families doubled up into small apartments because they could no longer afford a home. The term "Hoovervilles" was used to describe groups of these small, poorly built houses. They were named "Hoovervilles" after President Herbert Hoover because many people criticized him for not doing much about the Great Depression . A lot of Hoovervilles were located in large cities such as, New York and Washington.
Mason read a total of 12 books over 4months. After belonging to the book club for 5 months, how many books would mason have read in all?
Answers
Explanation
From the question, we are given that Mason reads 12 books in 4months. This implies that Maso averages
[tex]\frac{12}{4}=3\text{books per month}[/tex]Therefore, in 5 months, Mason would have read a total of
[tex]3\text{books/per month x 5months = 15 books}[/tex]Answer: 15 books
Need help solving TV. I think I have the answer but need help
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The midpoint theorem of a triangle states that the line segment in a triangle joining the midpoint of two sides of the triangle is said to be parallel to the third side and it is equal to half the length of the third side. Looking at the given triangle,
EF is the midsegment.
EF is the third side.
This means that
EF = 1/2TV
From the diagram,
EF = 7
Thus,
7 = 1/2TV
By cross multiplying,
TV = 7 x 2
TV = 14
2 x 46what is the answer
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2 x 46
Multiplying the above will give 92
Please help me help help me please help help me out day
Answers
The equation is:
[tex]y=-2x^3+2x^2-4x+3[/tex]Explanation:Let the equation be:
[tex]y=ax^3+bx^2+cx+d[/tex]Using (1, -1), x = 1, y = -1, we have:
[tex]a+b+c+d=-1\ldots.\ldots\ldots....\ldots\ldots\ldots\ldots.......\ldots.\ldots\ldots....(1)[/tex]Using (-1, 11), we have:
[tex]\begin{gathered} -a+b-c+d=11 \\ a-b+c-d=-11\ldots\ldots..\ldots..\ldots\ldots..\ldots..\ldots\ldots\ldots\ldots\ldots\ldots\ldots..(2) \end{gathered}[/tex]Add (1) and (2)
[tex]\begin{gathered} 2a+2c=-12 \\ a+c=-6\ldots\ldots...\ldots..\ldots..\ldots..\ldots\ldots\ldots.\ldots\ldots\ldots\ldots\ldots\text{.}(3) \\ c=-6-a\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\text{.}(3i) \end{gathered}[/tex]Substituting (3) into (2), we have:
[tex]\begin{gathered} -6-b-d=-11 \\ -b-d=-11+6=-5 \\ b+d=5\ldots.\ldots..\ldots\ldots\ldots......\ldots\ldots\ldots\ldots\ldots\ldots.........(4) \\ d=5-b\ldots\ldots\ldots\ldots\ldots.........\ldots\ldots....\ldots\ldots....\ldots\ldots.(4i) \end{gathered}[/tex]Using (2, -13)
[tex]\begin{gathered} 8a+4b+2c+d=-13 \\ using\text{ (3i) and (4i)} \\ 8a+4b+2(-6-a)+(5-b)=-13 \\ 8a+4b-12-2a+5-b=-13 \\ 6a+3b=-6 \\ 2a+b=-2\ldots\ldots..\ldots..\ldots..\ldots\ldots....\ldots\ldots\ldots..\ldots.\ldots.\ldots\ldots..(5) \end{gathered}[/tex]Using (3, -45)
[tex]\begin{gathered} 27a+9b+3c+d=-45 \\ \text{using (3i) and (4i)} \\ 27a+9b+3(-6-a)+(5-b)=-45 \\ 27a+9b-18-3a+5-b=-45 \\ 24a+8b=-32 \\ 3a+b=-4\ldots\ldots\ldots\ldots\ldots.\ldots..\ldots\ldots....\ldots.\ldots.\ldots.\ldots..\ldots(6)_{} \end{gathered}[/tex]Subtract (5) from (6)
[tex]a=-2\ldots.\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots................\ldots\ldots..\ldots\ldots..\mathrm{}(A)[/tex]Substitute (A) into (6)
[tex]\begin{gathered} 3(-2)+b=-4 \\ -6+b=-4 \\ b=-4+6=2......\ldots\ldots....\ldots..\ldots\ldots....\ldots\ldots....\ldots\ldots....(B) \end{gathered}[/tex]Using (3i) and (4i) with (A) and (B) respectively, we have:
[tex]\begin{gathered} c=-6-(-2)=-4\ldots\ldots\ldots\ldots\ldots\ldots\ldots..\ldots\ldots\ldots\ldots\text{.(C)} \\ d=5-2=3\ldots\ldots\ldots\ldots\ldots......\ldots\ldots\ldots\ldots\ldots..........(D) \end{gathered}[/tex]Using (A), (B), (C), and (D), we have our desired equation
[tex]y=-2x^3+2x^2-4x+3[/tex]7+(-9)-(-3) Explain and show work
Answers
Let's do this in 2 steps:
[tex]\begin{gathered} 7+(-9)-(-3) \\ =7-9 \\ =-2 \\ \text{Now, } \\ -2-(-3) \\ -2+3 \\ =1 \end{gathered}[/tex]One, is the correct answer for this.
Line SD is a line of symmetry for figure AXPDZHMS. Noah says that AXPDS is congruent to HMZDS because sides AZ and HM are corresponding.
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Identify pair of corresponding sides in the pentagons:
DS and DS
SA and SM
AX and MH
XP and HZ
PD and ZD
Identify corresponding vertices:
A and M
X and H
P and Z
D and D
S and S
1. Noah's congruence statement is incorrect because the corresponding vertices are wrong written in the "name" of the pentagons, and also the corresponding sides he names are not corresponding sides (side AZ doesn't exist in the figure)
2. AXPDS is congruent to MHZDS because sides AX and MH are corresponding
Represent the following sentence as an algebraic expression, where “a number” is the letter x. You do not need to simplify Nine times the difference of 8 and a number
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Explanation:
To write the sentence as an algebraic expression, we will break down the sentence into smaller parts
The difference of 8 and a number
let the number = x
we will be sutracting x from number 8 = 8 - x
The difference of 8 and a number = 8-x
nine times the difference:
We will multiply 9 by the difference we got
nine times the difference = 9(8 - x)
A researcher creates two random samples, each with a sample size of 8. Hedoes not find a statistically significant difference between the two groups.Which of the following statements is correct? Select all that apply.A. Since the sample size of each group is greater than 5, theconclusion is likely to be true.B. Since random samples were used, the conclusion is likely to betrue.C. Increasing or decreasing sample size does not impact theoutcome of a statistical analysis.D. Since the sample size is so small, the conclusion is likely to beuntrue.
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This question is about statistical samples.
In statistics, samples are used to study a certain number of subjects to demonstrate a hypothesis.
Now, in order to rely on the results of the statistical analysis, samples must represent a greater population, otherwise, the study won't have enough reliability to be true.
For example, let's say we are studying the behavior of people after drinking alcohol, a population would be a complete state of the nation, a sample could be a specific location inside that state. However, if we only study 20 people to such study, we can't rely on the results to be true, because the sample is too little.
Therefore, in this case, the right answer is D., since the sample is too small.D. Since the sample size is so small, the conclusion is likely to be untrue.for each solid state whether it is a prism or a pyramid and state the number of faces it has
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The prism is look lin=be :
can someone help me with this?the question is a garden is spotted in the Shaded portion below how many square feet were covered with the sod
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First, we need to find the area of the unshaded part
The unshaded part is a triangle
[tex]A=\frac{1}{2}\times b\times h[/tex][tex]=\frac{1}{2}\times6\times6[/tex][tex]=18ft^2[/tex]The triangles are 2
Area of the two triangles = 18ft² + 18ft² = 36ft²
We can now proceed to find the total area (area of the rectangle)
[tex]A=l\times w[/tex][tex]=20\times9\frac{1}{4}[/tex][tex]=20\times\frac{37}{4}[/tex][tex]=185ft^2[/tex]
Area of the shaded part = Total area - area of the unshaded part
= 185ft² - 36ft²
= 149 ft²
Here is a visual pattern.
Figure
1
2
3
4
Number of Tiles
4
7
10
13
how many tiles will be in the next figure
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Answer:
There will be 16 tiles in the next figure
Step-by-step explanation:
As the figures go up by one, the tiles increase by 3
The equation of the line would be
y = 3x + 1
Find the area of the shaded region. The graph depicts the standard normal distribution with mean 0 and standard deviation 1.The area of the shaded region is__(Round to four decimal places as needed.)
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Answer:
For z=0.54 the cumulative probability and percentile is approximately 70.54%, so in this case the answer is 0.7054
Match each missing side length and angle with the correct value.
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Given:
• YM = 15
,• YN = 8
,• LN = 10
Let's solve for the missing side lengths and angles.
We have the following:
• Measure of angle NLY:
Since traingle NLY is a right traingle, to find the measure of angle NLY, apply trigonometric ratio.
Here, let's apply the trigonometric ratio formula for sine:
[tex]sim\theta=\frac{opposite}{hypotenuse}[/tex]Where:
θ is the angle
opposite side is the side opposite the angle = YN = 8
Hypotneuse = LN = 10
Thus, we have:
[tex]\begin{gathered} sin(\angle NLY)=\frac{8}{10} \\ \\ sin(\angle NLY)=\frac{4}{5} \\ \\ \text{ Take the sine inverse of both sides:} \\ \angle NLY=sin^{-1}(\frac{4}{5})=53.13^o \end{gathered}[/tex]Therefore, m∠NLY = 53.13°.
• Measure of angle NMY:
Apply the trigonometric ratio formula for tangent:
[tex]tan\theta=\frac{opposite}{\text{ adjacent}}[/tex]Where:
θ is the angle
The opposite side is the side opposite the angle = YN = 8
Adjacent side is the side adjacent the angle = YM = 15.
Thus, we have:
[tex]\begin{gathered} tan(\angle NMY)=\frac{8}{15} \\ \\ \text{ Take the tan inverse of both sides:} \\ \angle NMY=tan^{-1}(\frac{8}{15}) \\ \\ \angle NMY=28.07^o \end{gathered}[/tex]Therefore, m∠NMY = 28.07°.
• Length of NM:
To find the length of NM, apply Pythagorean Theorem:
[tex]\begin{gathered} NM=\sqrt{8^2+15^2} \\ \\ NM=\sqrt{64+225} \\ \\ NM=\sqrt{289} \\ \\ NM=17 \end{gathered}[/tex]The length of NM is 17.
• Length of LY:
To find the length of LY, also apply Pythagorean theorem:
[tex]\begin{gathered} LY=\sqrt{10^2-8^2} \\ \\ LY=\sqrt{100-64} \\ \\ LY=\sqrt{36} \\ \\ LY=6 \end{gathered}[/tex]ANSWER:
• m∠NLY ==> 53.13°
,• m∠NMY ==> 28.07°
,• NM ==> 17
,• LY ==> 6
Drag the expressions to the correct locations on the image. Not all expressions will be used.
Answers
Given the polynomial below
[tex](x^3-8x+6)\div(x^2-2x+1)[/tex]Using the long division method
The answer in the equivalent form
[tex]_{}q(x)+\frac{r(x)}{b(x)_{}}[/tex]Where
[tex]\begin{gathered} q(x)=quotient=x+2 \\ r(x)=\text{remainder}=-5x+4 \\ b(x)=\text{divisor}=x^2-2x+1 \end{gathered}[/tex]The answer is
[tex]q(x)+\frac{r(x)}{b(x)_{}}=(x+2)+\frac{-5x+4}{x^2-2x+1}[/tex]nine less than the product of 5 and a number is equal to 7
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In this case the answer is very simple.
We must write the equation analyzing the question.
Step 01:
x = Unknown number
Step 02:
Equation
9 - (5 * x) = 7
9 - 5x = 7
- 5 x = 7 - 9
- 5 x = - 2
x = -2 / -5
x = 2 / 5
The answer is:
The unknown number is 2 / 5
A 15% tax is to be applied to a $120 pair of shoes. Find the total price.
Answers
Total cost of item = $138
Explanation:The tax percentage = 15%
cost of item = $120
sales tax = cost of item × The tax percentage
sales tax = 120 × 15%
=120 × 0.15
sales tax = $18
Total cost of item = initial cost of item + sales tax
Total cost of item = 120 + 18
Total cost of item = $138
28. Find the perimeter of the polygon.9 mma. 55 mmb. 54 mmc. 52 mm
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The perimeter of a figure is the distance around it. The given figure is a regular hexagon because it has 6 equal sides. Given that the length of each side is 9, then the perimeter is
Perimeter = 9 x 6 = 54mm
A prism has congruent parallelograms for bases. One pair of parallel sides of the parallelogram measure 12 feet and are 5 feet apart. The altitude of the prism is 13 feetFind the volume of the prism.
Answers
The volume of the prism can be gotten using the formula
[tex]\begin{gathered} V_{\text{PRISM}}=\text{Base area}\times perpendicularheight \\ \text{the base is a parallelogram} \\ \text{Base area=base}\times height \\ \text{Base}=12ft \\ \text{height}=5ft \\ \text{perpendicular height=13ft} \end{gathered}[/tex]By substitution, we will have
[tex]\begin{gathered} V_{\text{PRISM}}=12ft\times5ft\times13ft \\ V_{\text{PRISM}}=780ft^3 \end{gathered}[/tex]Hence,
The volume of the prism is 780 cubic feet
Let BD bisect 2ABC. If m_ABD =(3x+8) and m DBC =(7x+4), then what is the measure of ABD?
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Note a bisector divide an angle into 2 equal half.
A standard number cube is tossed. Find the following probability. P(greater than 4 or even)
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Let:
A = Get a number greater than 4
B = Get an even number
The probability is given by:
[tex]P(E)=\frac{m}{n}[/tex]Where:
m = Number of favourable outcomes
n = Total number of outcomes
So:
[tex]\begin{gathered} P(A)=\frac{2}{6}=\frac{1}{3} \\ P(B)=\frac{3}{6}=\frac{1}{2} \\ so\colon \\ P(A\cup B)=\frac{1}{3}+\frac{1}{2}=\frac{5}{6}\approx0.833 \end{gathered}[/tex]Answer:
0.833
Solve the equation x^3+2x^2-5x-6=0 given that 2 is a zero of f(x) = x^3+2x^2-5x-6
Answers
Given
[tex]x^3+2x^2-5x-6=0[/tex]2 is the zero of the polynomial
Answer
If 2 is zero of polynomial then x-2 is a factor dividing the polynomial by x-2
[tex]\begin{gathered} x^3+2x^2-5x-6=(x-1)(x^2+4x+3) \\ (x-2)(x+1)(x+3) \end{gathered}[/tex]Zeros are = {2,-1,-3}
