D. Gravity, weak nuclear force, electromagnetic force, strong nuclear force
The four fundamental forces in the universe, in order of increasing magnitude, are:
Gravity: This is the weakest of the four fundamental forces. It is the force that holds everything together and is responsible for the attraction between masses.
Weak Nuclear Force: This force is responsible for certain types of radioactive decay and the fusion of nuclei in stars. It is about 10^25 times weaker than the strong nuclear force.
Electromagnetic Force: This force is responsible for electric and magnetic interactions, such as the forces between charges, the forces between magnets, and the forces between electric currents.
Strong Nuclear Force: This is the strongest of the four fundamental forces. It holds the protons and neutrons in an atom's nucleus together, and it is about 10^38 times stronger than the electromagnetic force.
Therefore, the correct order of the four fundamental forces in terms of increasing magnitude is D: Gravity, weak nuclear force, electromagnetic force, strong nuclear force
the distance covered by a car at a time t is given by x=20t+6t^4. calculate the instantaneous velocity and acceleration when t= 1s.
Answer:
t = 1s is 44 m/s and 72 m/s^2
Explanation:
The distance covered by a car at a time t is given by x=20t+6t^4. To calculate the instantaneous velocity and acceleration when t=1s, we can use the formulas for velocity and acceleration, which are:
Velocity (v) = dx/dt = d/dt(20t+6t^4) = 20 + 24t^3
Acceleration (a) = dv/dt = d/dt(20 + 24t^3) = 72t^2
When t = 1s, we can substitute this value into the formulas for velocity and acceleration:
Velocity (v) = 20 + 24(1)^3 = 20 + 24 = 44 m/s
Acceleration (a) = 72(1)^2 = 72 m/s^2
Therefore, the instantaneous velocity and acceleration of the car when t = 1s is 44 m/s and 72 m/s^2, respectively.
Using the density- temperature graph, compare the behaviour of water density and the density of any other liquid as the temperation increases
You weigh 650 N.
What would you weigh if the Earth were
five times as massive as it is and its radius
were five times its present value?
Answer in units of N.
If the earth is 5 times as massive and the radius 5 times its present value, your weight will be 130 N.
How to find the weight of the body?Weight is the amount of gravitational force acting on an object as a result of the gravitational attraction of the Earth.
Assuming gravitational force = [tex]F = \frac{Gm_{1} m_{2} }{r^{2} }[/tex]
where G = 6.67 x 10⁻¹¹m³/kgs², a universal constant.
m = masses of two objects and
r = distance of two objects.
Given that W = 650 N
m₁ = 5Me, new mass of earth
r = 5re, new radius of earth
Then [tex]650 N = \frac{GM_{E} m}{r^{2}_{E} }[/tex]
Let the new weight be [tex]F = \frac{GM m}{r^{2} }[/tex]
Substituting the new mass and radius;
[tex]F = \frac{G(5M_{E}) m}{(5r_{E})^{2}}[/tex]
[tex]F = \frac{5}{25} \frac{GM_{E} m}{r^{2}_{E}}[/tex]
Knowing that [tex]650 N = \frac{GM_{E} m}{r^{2}_{E} }[/tex]
[tex]F = \frac{5}{25}(650 N)[/tex] = 0.2 x 650N
F = 130 N
When the earth is 5 times its radius and 5 times its mass a weight of 650N will become 130 N.
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A stone is thrown into the air. Its height above the ground t seconds after it is thrown is given by
the function h(t) = -5t² + 30t+2 metres.
How high is the stone above the ground at time t = 3 seconds?
b From what height above the ground was the stone released?
At what time is the stone 27 m above the ground?
Answer:
Explanation:
a) To find the height of the stone above the ground at time t = 3 seconds, we need to substitute t = 3 into the function h(t) = -5t² + 30t + 2 and solve for h(3).
h(3) = (-53²) + (303) + 2 = -45 + 90 + 2 = 37m
b) To find from what height above the ground the stone was released, we need to find the value of h(0), which represents the height of the stone at time t = 0, which is the time the stone was released.
h(0) = (-50²) + (300) + 2 = 2 m
c) To find the time at which the stone is 27 m above the ground, we need to solve for t in the equation h(t) = 27.
27 = (-5t²) + (30t) + 2
27 = -5t² + 30t + 2
25 = -5t² + 30t
5t² - 30t - 25 = 0
(5t-5)(t+5) = 0
t = 1 or t = -5
As time cannot be negative, the time at which the stone is 27 m above the ground is t = 1 sec.
Two forces that are F1 =15N (east) and F2 = 7N (west) act on a body in a frictionless floor. The displacement of the body is 6 m, what is the work done by forces on the body?
Answer:
The net force acting on the body is F1 - F2 = 15 N - 7 N = 8 N (east). Since the displacement of the body is 6 m in the same direction as the net force, the work done by the forces on the body is W = Fnet x d = 8 N x 6 m = 48 J (Joules).
Explanation:
above
I need help ------------------
You weigh 650 N.
What would you weigh if the Earth were
five times as massive as it is and its radius
were five times its present value?
Answer in units of N.
Answer:
130 N
Explanation:
g is directly proportional to the mass of the planet (M) and indirectly proportional to the square of the radius of the planet (R²).
g = GM/R²
G = gravitational constant
Therefore if Earth increases in mass by X5 and increases in radius by X5, then the value of g (9.8 m/s²) changes by a factor of 5/5² = 5/25 = 1/5.
Weight = W = mg
(650N)(1/5) = 130 N
A 1,000 kg hot air balloon is drifting along at 3 m/s at a height of 50m above the ground.
How much kinetic energy does the balloon have? ___
How much potential energy does the balloon have? ____
How much total mechanical energy does the balloon have? ___
The Kinetic energy of the hot air balloon is 4500 Joules, the potential energy is 4.9 × 10⁵ Joules, and the total mechanical energy is 4.95 × 10⁵ Joules.
What is the Kinetic energy?The Kinetic energy is the amount of energy which is present in the body of an object which is under motion. The kinetic energy is a vector quantity because it has both the magnitude and direction. The SI unit of KE is Joule. The KE of an object can be calculated by the formula:
KE = 1/2 mv²
KE = 1/2 × 1000 × (3)²
KE = 500 × 9
KE = 4500 Joules
PE = m × g × h
PE = 1000kg × 9.8 × 50
PE = 490,000 Joules
Total Mechanical energy = PE + KE
Total Mechanical energy = 4500 + 490000
Total Mechanical energy = 494500 Joules
Total Mechanical energy = 4.95 × 10⁵ Joules
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What is the resultant of two displacement vectors having the same direction? Question 16 options: The resultant is the sum of the two displacements having the same direction as the original vectors. The resultant is the difference of the two displacements having the same direction as the original vectors. The resultant is the sum of the two displacements having the direction opposite to the direction of the original vectors. The resultant is the sum of the two displacements having the direction perpendicular to the direction of the original vectors.
The resultant is the sum of the two displacements having the same direction as the original vectors.
What is displacement?A displacement is described as a vector whose length is the shortest distance from the initial to the final position of a point P undergoing motion.
Vectors in the same direction can be simply added to obtain the resultant vector.
We can describe vector as a term that refers colloquially to some quantities that cannot be expressed by a single number, or to elements of some vector spaces.
In conclusion, If we want to sum two vectors that are collinear and have the same sense, we can make that adding such as an algebraic sum.
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The resultant is the sum of the two displacements having the same direction as the original vectors. Option A
What are vectors?We know that there are generally two kinds of variables that we can be able to have in Physics, we have the scalars and the vectors. In the vectors we have the quantities that have both magnitude and direction while in the scalars we have the quantities that have only magnitude.
We know that when two vectors do have the same direction, we can be able to obtain the resultant vector by addition of the vectors together.
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Let to the right be the positive direction.
A 25.8 g marble sliding to the right at 21.0
cm/s overtakes and collides with a 12.4 g
marble moving in the same direction at 13.8
cm/s. After the collision, the 12.4 g marble
moves to the right at 23.9 cm/s.
Find the velocity of the 25.8 g marble after
the collision.
Answer in units of cm/s. Answer in units
of cm/s.
The final velocity of the 25.8 g marble after the collision is 16.15 cm/s.
What is the velocity of the 25.8 g marble after the collision?
The velocity of the 25.8 g marble after the collision is calculated as follows;
m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂
where;
m₁ is the mass of 25.8 g marblem₂ is the mass of 12.4 g marbleu is their initial speedsv is their final speedsThe final velocity of the 25.8 g marble after the collision is calculated as;
( 25.8 x 21 ) + ( 12.4 x 13.8 ) = ( 12.4 x 23.9 ) + ( 25.8v )
712.92 = 296.36 + 25.8v
25.8v = 416.56
v = 416.56 / 25.8
v = 16.15 cm/s
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Question:
(a) What is the electric field strength due to a point charge of 2.4 at a position 8.6 cm away from the charge?
(b) What is the magnitude of the electric force on a charge of −3.4 that is 8.6 cm away from the point charge in part a?
(c) Draw a sketch of the two charges, from parts a and b, and indicate the direction of the electric force on the second charge due to the original point charge.
(a) The electric field strength (E), due to a point charge is a measure of how much force an object would experience per unit of charge if it were placed in the field.
To calculate it, you need the charge of the point, the distance from the point charge, and a constant called Coulomb constant (k). The formula is E = k * q / r^2, where q is the charge, r is the distance and k is Coulomb constant. In this case, the charge is 2.4 Coulombs and the distance is 8.6 cm, when you calculate this you get E = 2.3*10^8 N/C.
So the electric field strength at a point 8.6 cm away from a point charge of 2.4 C is 2.3*10^8 N/C.
(b) The magnitude of the electric force on a charge of -3.4 microcoulombs that is 8.6 cm away from a point charge of 2.4 microcoulombs can be calculated using Coulombs law:
F = k * (q1*q2)/r^2
where k is Coulombs constant, q1 is 2.4 microcoulombs, q2 is -3.4 microcoulombs, and r is 8.6 cm.
The force magnitude is approximately equal to 1.97 * 10^-5 N.
Note that the direction of the force will be repulsive as the charges are opposite in sign.
(c) I won't draw a sketch for you, but to draw a sketch of two charges yourself:
You can draw a small circle for each charge, with the size of the circle representing the magnitude of the charge. Label the first charge with a + sign to indicate it's positive and the second charge with a - sign to indicate it's negative. Draw an arrow from the second charge towards the first charge to indicate the direction of the electric force, it should be pointing from the negative charge to the positive charge because the force is attractive.
I hope this helps some, I'm sorry I cannot answer completely.
Erosion includes what processes?
A) building up sediment to make new rocks
B) cleaning rocks to make them shiner
C) wearing away and removal of surface materials
D) combing earth materials to form new minerals
Momentum Principle please help
The momentum of the ball is
(-0.18, -0.40, 0.20)m
What is momentum?Generally, The momentum principle, also known as Newton's second law of motion, states that the rate of change of momentum of an object is equal to the force applied to it. Mathematically, this can be expressed as:
F = d(mv)/dt
where
F is the force applied, m is the mass of the object, v is the velocity of the object, and t is time.To determine the position of the ball 0.1 seconds later, we need to know the force acting on the ball due to the elastic band. This force is given by Hooke's Law, which states that the force acting on an object due to a spring is equal to the spring constant (k) multiplied by the displacement of the spring from its relaxed position. In this case, the spring constant is 0.9 N/m, and the displacement is the difference in length between the relaxed length (0.3 m) and the current length of the elastic band.
We know that the ball is at location (-0.2, -0.61, 0)m relative to the point where the elastic band is attached to the paddle. We can find the length of the elastic band by using the distance formula:
√((x2-x1)^2 + (y2-y1)^2 + (z2-z1)^2 ) = √((-0.2 - 0)^2 + (-0.61 - 0)^2 + (0 - 0)^2 )
= √(0.04 + 0.3721 + 0)
= √0.4121
= 0.63874m
The displacement of the spring is the relaxed length (0.3 m) minus the current length of the elastic band (0.63874 m), which is -0.33874 m. The force acting on the ball due to the elastic band is
-0.9 * -0.33874 = 0.30486 N.
We can use the force to find the acceleration of the ball using Newton's second law,
F = ma.
Since the mass of the ball is 0.015 kg, the acceleration of the ball is
0.30486 N / 0.015 kg = 20.324 m/s^2
We can use this acceleration to find the final velocity of the ball using the equation vf = vi + at.
Since the initial velocity of the ball is
(-0.02, -0.01, -0.02) kg-m/s, the final velocity of the ball is
(-0.02, -0.01, -0.02) + (20.324, 20.324, 20.324) * 0.1 s = (-0.02, -0.01, -0.02) + (2.0324, 2.0324, 2.0324)
= (2.0124, 2.0224, 2.0124) m/s
The final position of the ball can be found using the equation
xf = xi + vt.
The initial position of the ball is (-0.2, -0.61, 0)m and the final velocity is (2.0124, 2.0224, 2.0124) m/s, so the final position of the ball after 0.1 s is
(-0.2, -0.61, 0) + (2.0124, 2.0224, 2.0124) * 0.1 s
= (-0.2, -0.61, 0) + (0.20124, 0.20224, 0.20124)
= (-0.18, -0.40, 0.20)m
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The figure below shows three small, charged spheres, all lying along the horizontal axis. Sphere A, at left, has a 5.10 nC charge. Sphere B has a 1.60 nC charge and is 3.00 cm to the right of A. Sphere C has a
−2.80 nC
charge and is 2.00 cm to the right of B.
Find the magnitude (in N) and direction of the net electric force on each of the spheres.
The magnitude and direction of the net electric force on each of the spheres is 1.92 x 10⁻⁵ N to the right.
What is the net electric force on the charges?The net electric force on the charges is calculated as follows;
F (net) = F (AB) + F (BC)
where;
F (AB) is the electric force between sphere A and BF (BC) is the electric force between sphere B and CThe electric force between sphere A and B is calculated as follows;
F ( AB ) = kq₁q₂ / r²
where;
q₁ is charge of sphere Aq₂ is charge of sphere Br is the distance between the two spheresK is Coulomb's constantF (AB) = ( 9 x 10⁹ x 5.1 x 10⁻⁹ x 1.6 x 10⁻⁹ ) / ( 0.03² )
F (AB) = 8.16 x 10⁻⁵
since it is between two positive charges, it will be repulsive, hence F (AB) = - 8.16 x 10⁻⁵
The electric force between sphere B and C is calculated as follows;
F (BC) = ( 9 x 10⁹ x 2.8 x 10⁻⁹ x 1.6 x 10⁻⁹ ) / ( 0.02² )
F (BC) = 1.008 x 10⁻⁴ N
since the force is between opposite charges, it will attractive, so F (BC) is positive.
The net force on each sphere is calculated as;
F (net) = -8.16 x 10⁻⁵ N + 1.008 x 10⁻⁴ N
F (net) = 1.92 x 10⁻⁵ N
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Alexa exerts a force of 560 N on the
ground, due to her weight.
a) When Alexa is wearing high-heeled
shoes, the total area of her shoes in
2
contact with the ground is 58 cm².
When she has bare feet, the total area of
her feet in contact with the ground is
230 cm².
2
Calculate the difference between the
pressure she exerts on the ground when
she is wearing these shoes and when she
has bare feet.
Give your answer in N/cm² to 1 d.p.
Answer:
[tex]\Delta P \approx 7.2 \ N/cm^2}[/tex]
Explanation:
To calculate the difference in pressure that Alexa exerts on the ground when wearing high-heeled shoes compared to when she has bare feet, we can use the following formula for pressure:
[tex]\rightarrow P=\dfrac{F}{A}[/tex]
Where:
"F" is the force exerted in the ground."A" is the area the force is applied to.First, let's calculate the pressure when Alexa is wearing high-heeled shoes:
F = 560 N (given)
A = 58 cm² (given)
[tex]P_h=\dfrac{560}{58}\\\\\\\\\therefore P_h \approx 9.655 \ N/cm^2[/tex]
Next, let's calculate the pressure when Alexa has bare feet:
F = 560 N (given)
A = 230 cm² (given)
[tex]P_b=\dfrac{560}{230}\\\\\\\\\therefore P_h \approx 2.435 \ N/cm^2[/tex]
Finally, let's calculate the difference in pressure:
[tex]\Delta P= P_h-P_b\\\\\\\\\Longrightarrow \Delta P =9.655-2.435\\\\\\\\\therefore \boxed{\boxed{\Delta P \approx 7.2 \ N/cm^2}}[/tex]
Therefore, the difference in pressure that Alexa exerts on the ground when wearing high-heeled shoes compared to when she has bare feet is approximately 7.2 N/cm².
The equal and opposite forces described by Newton's third law of motion will balance each other out in many cases.
True
False
The speed of a moving bullet can be determined by allowing the bullet to pass through
two rotating paper disks mounted a distance
97 cm apart on the same axle. From the
angular displacement 12.9◦
of the two bullet holes in the disks and the rotational speed
1319 rev/min of the disks, we can determine
the speed of the bullet.
What is the speed of the bullet?
Answer in units of m/s.
Answer:
f = 1219/min = 1219 / 60 / sec = 20.32 / sec
T = 1/f = 1 / 20.32 = .04922 sec period of 1 revolution
t = 12.9 / 360 * .04922 = .001764 sec time to pass between disks
V = S / t = .97 m / .001764 = 550 m/sec
Analyzing Gravitational Data Quick Check
Which of the following statements about gravitational mass is true? (1 point)
O Gravitational acceleration is irrespective of mass.
O The more mass an object has, the more gravitational acceleration it will experience.
O The less mass an object has, the less gravitational acceleration it will experience.
Gravitational acceleration is always equal to mass.
The true statement about gravitational mass is the more mass an object has, the more gravitational acceleration it will experience.
option B.
What is gravitational acceleration?
The gravitational acceleration of an object is the acceleration an object with mass experiences due to impact of force of gravity on the object.
g = ( GM ) / ( R² )
where;
G is the universal gravitation constantM is the mass of the objectR is the radius of the objectFrom the equation given above, the acceleration of an object increases with increase in the mass of the object and decrease in the radius of the object.
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A student wants to investigate the motion of a ball by conducting two different experiments, as shown in Figure 1 and Figure 2 above. In Experiment 1, the student releases a ball from rest and uses a slow-motion camera to film the ball as it falls to the ground. Using video analysis, the student is able to plot the ball’s horizontal position x and vertical position y as a function of time t . In Experiment 2, the student horizontally rolls the same ball off a table, and uses video analysis to plot the ball’s horizontal position x and vertical position y as a function of time t starting from the instant the ball leaves the table. The graphs from each experiment are shown above along with each graph’s best-fit curve line.
The student can conclude that in Experiment 1, the ball is following a parabolic path, demonstrated by the best-fit curve line. In Experiment 2, the ball is following a linear path, demonstrated by the best-fit curve line.
What is curve?
A curve is a line in a two-dimensional plane that is bent or curved. It is often used to describe the shape of objects or mathematical functions. It is often used to study changes in data over time and to understand the behavior of functions and equations. Curves can be described using a variety of mathematical equations and equations can be used to predict the behavior of a curve. Additionally, curves can be used to describe the motion of physical objects and to help visualize the relationships between the objects.
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4 points
A hydraulic system contains one small piston with a area of 5.33 square inches and one large piston with an area of 10 square inches. If a force of 70 pounds
is applied to the small piston, what will the system pressure be?
A: 99.7 psi
B: 640.3 psi
C: 1,822 psi
D: 13.13 psi
Answer:
C
Explanation:
The system pressure will be equal to 70 pounds divided by the area of the small piston, which is 5.33 square inches. This gives a pressure of 13.13 psi (pounds per square inch).
Q2 The equation of the periodic time of a pendulum
bob is:
T= 2√L/g
2514
Where T is the periodic time. I is the length of the
string.
A Prove that the equation is homogeneous with respect to e base Units
B. Find the base unit of force.
The dimensional relation of the time period bob with its length is shown below.
what is meant by "dimensional analysis"?a method of analysis that represents physical quantities in terms of their fundamental dimensions in the absence of enough data to create precise equations.
What is the purpose of dimensional analysis?Dimensional analysis is a method used in engineering and the physical sciences to reduce physical quantities like acceleration, viscosity, and energy to their three basic dimensions of length, mass, and time (T).
[T]=[M^0 L^0 T^1]
[L]=[M^0 L^1 T^0]
[g]=[M^0 L^1 T^-2]
SQUARE ROOT OF (L/g)=[m0l1t0]/[m0l1t-2]
=[m0l0t1]
= R.H.S.
Hence it's dimensionally correct.
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You weigh 660 N.
What would you weigh if the Earth were
two times as massive as it is and its radius
were five times its present value?
Answer in units of N.
At a mass that is 2 times the current earth and a radius 5 times its value, your weight will be 52.8 N.
How do you find the new weight of the body?In general, we can assume a gravitational force of the following magnitude for any planet or mass:
[tex]F = \frac{Gm_{1} m_{2} }{r^{2} }[/tex]
where G = 6.67 x 10⁻¹¹m³/kgs², a universal gravitational constant.
m = masses of objects
r = radius of objects.
Given that W = 660 N
m₁ = 2Me, new mass of earth
r = 5re, new radius of earth
Then [tex]660 N = \frac{GM_{E} m}{r^{2}_{E} }[/tex]
Since [tex]F = \frac{GM m}{r^{2} }[/tex]
Substituting both new mass and radius;
[tex]F = \frac{G(2M_{E}) m}{(5r_{E})^{2}}[/tex]
[tex]F = \frac{2}{25} \frac{GM_{E} m}{r^{2}_{E}}[/tex]
Using the equation that weight is [tex]660 N = \frac{GM_{E} m}{r^{2}_{E} }[/tex]
[tex]F = \frac{2}{25}(660 N)[/tex] = 0.08 x 660 N
F = 52.8 N
Since the earth is 5 times its radius and twice its mass a weight of 650N will become 52.8 N.
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A 15 g toy car moving to the right at 22 cm/s
has a head-on nearly elastic collision with a
22 g toy car moving in the opposite direction
at 31 cm/s. After colliding, the 15g car moves
with a velocity of 42 cm/s to the left.
Find the speed of the second car after the
collision.
Answer in units of cm/s. Answer in units
of cm/s.
Answer:
Explanation:
The speed of the second car after the collision can be found using the law of conservation of momentum. The law states that the total momentum of a system remains constant if no external forces act on it.The initial momentum of the first car is (15g)(22 cm/s) = 330 g cm/s to the right.
The initial momentum of the second car is (22g)(-31 cm/s) = -682 g cm/s to the left.
The total initial momentum of the system is 330 g cm/s - 682 g cm/s = -352 g cm/sAfter the collision, the final momentum of the first car is (15g)(-42 cm/s) = -630 g cm/s to the left.
The final momentum of the second car is (m)(v) where m is the mass of the second car and v is the speed after the collision.
The total final momentum of the system is -630 g cm/s + (m)(v) = -352 g cm/s (since it remains constant)Therefore, m*v = -630 g cm/s + 352 g cm/s = -278 g cm/sTo find v, we need to divide the momentum by the mass
v = -278 g cm/s / 22 g = -12.6 cm/sSo the speed of the second car after the collision is -12.6 cm/s to the left.
A cone has a base radius of 3cm and height of 10cm.
A. Find the volume of the cone.
B. If the mass of the cone is 6kg, find its density.
The volume of the cone is 15.7 cm^3.
Density of cone is 0.38 kg/cm^3
Radius of the cone = 3 cm
Height of the cone = 10 cm
Formula used:
Volume of a cone = (1/3) × π × r^2 × h
Density is the measurement of how tightly a material is packed together. It is defined as the mass per unit volume. Density Symbol D or ρ Density Formula: ρ = m/V, where ρ is the density, m is the mass of the object and V is the volume of the object.
Where, r = radius of the cone
h = Height of the cone
Volume of the cone = (1/3) × π × r^2 × h
(1/3) × π × 3^2 × 10
(1/3) × (22/7) × 3^2 × 10
15.7 cm^3
Density = mass/volume
Density = 6kg/15.7 cm^3
Density = 0.38 kg/cm^3
Hence, the volume of the cone is
15.7 cm^3
And density of cone is 0.38 kg/cm^3
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You weigh 650 N.
What would you weigh if the Earth were
five times as massive as it is and its radius
were five times its present value?
Answer in units of N.
Answer:
129.95 N
Explanation:
First, you want to find the acceleration due to gravity on this hypothetical planet.
Using the equation [tex]g = G (M/R^2)[/tex] , where G is a constant ([tex]6.67 * 10^{-11}[/tex]), M is mass of the planet, and R is radius of the planet, we can plug in the numbers of earth and then multiply them by whatever the question requires, in this case, 5x.
[tex]g = (6.67 * 10^{-11})(5*(5.97 * 10^{24})) /(5* (6.378 *10^{6}))^{2}[/tex]
g = 1.96 m/s. The acceleration due to gravity on this planet is 1.96 m/s.
Now to find your weight.
First, you want to find your mass.
On earth, your weight is equal to your natural force (Fn)
mg = Fn
m(9.8) = 650 ==> mass = 66.33 kg
Now, to find your weight on this hypothetical planet, multiply your mass by the acceleration due to gravity (g)
M x g
66.33 x 1.96 = 129.95 N
You would weigh 129.95 N
Two bodies separated from
each other at a certain distance
started moving simultaneously
to meet each other - one with ar
acceleration of 2.4 m/s, and the
other with an acceleration of 4.8
m/s2. Determine the ratio of the
displacement module of the first
body to the displacement
module of the second body at
the moment of their meeting.
The result of the ratio of the displacement module of the second body at the point of meeting is 0.5.
How to find displacement ratio?To determine the ratio of the displacement of the first body to the displacement of the second body at the moment of their meeting, use the equation of motion:
d = vt + 1/2at²
where d is the displacement, v is the initial velocity, t is the time, and a is the acceleration.
Since the bodies are moving simultaneously towards each other, then assume that their initial velocities are zero. Also, at the moment of their meeting, their displacement will be the same, d₁ = d₂.
Assume that the time at which they meet is t, then:
d₁ = 1/2 * 2.4t²
And the equation for the displacement of the second body:
d₂ = 1/2 * 4.8t²
If d₁ = d₂
then, 1/2 * 2.4t² = 1/2 * 4.8t²
Solving this equation for t and substituting it into the equation for d₁ or d₂, the ratio of the displacement of the first body to the displacement of the second body: d₁/d₂ = 2.4/4.8 = 0.5 or 1/2
So, at the moment of their meeting, the displacement of the first body is half of the displacement of the second body.
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In the human femur, bone tissue is strongest in resisting compressive force,
approximately half as strong in resisting tensile force, and only about one-
fifth
as strong in resisting shear force. If a tensile force of 8000 N is sufficient to
produce a fracture, how much compressive force will produce a fracture?
How much shear force will produce a fracture
The compressive force that would be enough to produce a fracture is 4000 N.
What is the force?We know that the femur is one of the most important bones that we have in the human body. In this case, we have been told that In the human femur, bone tissue is strongest in resisting compressive force, approximately half as strong in resisting tensile force, and only about one- fifth as strong in resisting shear force.
Then we know that;
Tensile force = 8000
The compressive force would be half of this magnitude as such;
Compressive force = 4000 N
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. A tire typically has a coefficient of friction around 0.7 in dry conditions. In wet
conditions, the coefficient of friction drops to around 0.4. What is the difference
between the frictional force in dry conditions compared to wet conditions on a car
that has a weight of 14000 N.
Answer:
4300N
Explanation:
FrictionBased on the free body diagram, the friction (fFr in the attached diagram) is dependent on the reaction force (Rn in the attached diagram) acting on the object, in this case a car. The frictional force will always act against the direction of movement (DOM in the attached diagram.)
SolutionGiven the condition is dry,
Summation of forces in the vertical direction (Positive for upward forces) = 0
Reaction Force - Weight of car = 0
Reaction Force = Weight of car = 14000N
Since the friction is dependent on the reaction force with the formula: Coefficient of friction X Reaction Force,
Friction (Dry Condition) = 0.7 * 14000N = 9800N
Now given the condition is wet,
We will use the same formula but with a change to the coefficient of friction.
Friction (Wet Condition) = 0.4 * 14000N = 5600N
Difference between them = 9800N - 5600N = 4300N.
How does the total momentum of two objects before a collision compare with the total momentum after the collision?
An elephant has feet with circular bases.
Each foot has a radius of 0.2 m, and the
total force that the elephant exerts on the
ground is 30,000 N.
Work out the pressure the elephant exerts
when all 4 of its feet are on the ground.
Give your answer to 3 s.f.
37500 Newton meter is the pressure
