Which of the following ionic compounds will be more soluble in acid solution than in water?
a. CuI
b. PbCl2
c. Fe(OH)3
d. CaCO3

Answers

Answer 1

Fe(OH)3 will be more soluble in acid solution than in water

How does solubility develop?

The balance of intermolecular interactions between the solvent and solute, as well as the entropy shift that results from solvation, determines how soluble a substance is in another.

In nature, iron hydroxide is basic. In an acidic media, the dissociation of bases occurs quickly. It follows that a chemical will be more soluble in an acidic solution the weaker the acid from which it is derived. Similar to strong bases, substances that dissolve into hydroxides are more soluble in acidic solutions. However, as a result of the effect, an acidic chemical will be less soluble in an acidic solution.

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Related Questions

The equilibrium constant for the reaction
Sr(s) + Mg2^+ (aq) ⇌ Sr^2+ (aq) + Mg(s)
is 2.69 × 10^12 at 25°C. Calculate E° (in V) for a cell made up of Sr/Sr^2+ and Mg/Mg^2+ half-cells.

Answers

0.367V is  E° (in V) for a cell made up of Sr/Sr^2+ and Mg/Mg^2+ half-cells if the equilibrium constant for the reaction Sr(s) + Mg2^+ (aq) ⇌ Sr^2+ (aq) + Mg(s) is 2.69 × 10^12 at 25°C.

Define equilibrium concentration

When the products and reactants remain constant over time, a chemical is said to be at equilibrium concentration. In other words, the rate of forward reaction in a chemical reaction must equal the rate of backward reaction in order for there to be chemical equilibrium, also known as equilibrium concentration.

The reaction quotient value at chemical equilibrium is the equilibrium constant for a chemical process.

Sr(s)+Mg²+(aq)→Sr²+(aq)+Mg(s)

Number of electrons transfered, n=2.

K=2.69×10^12

ΔG=-2.303RT logK

R = 8.314J/mol-k

T= =298K

ΔG = -nFE = -70922.3J

n =2

F = 96500C

E = ΔG.nF

=-(-70922.3)/2×96500) =0.367V

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A student is investigating the volume of hydrogen gas produced when various metals react with hydrochloric acid. The student uses an electronic balance to determine that the mass of a sample of zinc metal is 16.35 g.

Answers

When the student reacts the 16.35 g sample of zinc with hydrochloric acid, they should expect to produce approximately 5.6 liters of hydrogen gas.

To determine the volume of hydrogen gas produced when zinc reacts with hydrochloric acid, the student needs to use the concept of stoichiometry and the balanced chemical equation for the reaction.

The balanced chemical equation for the reaction between zinc (Zn) and hydrochloric acid (HCl) is:

Zn + 2HCl -> ZnCl2 + H2

From the balanced equation, we can see that one mole of zinc reacts with two moles of hydrochloric acid to produce one mole of hydrogen gas.

To calculate the volume of hydrogen gas produced, the student needs to follow these steps:

Convert the mass of zinc to moles. The molar mass of zinc (Zn) is approximately 65.38 g/mol. Therefore, the number of moles of zinc is:

moles of Zn = mass of Zn / molar mass of Zn

= 16.35 g / 65.38 g/mol

≈ 0.250 moles

Use the stoichiometry of the balanced equation to determine the moles of hydrogen gas produced. Since the ratio of zinc to hydrogen gas is 1:1, the moles of hydrogen gas will be the same as the moles of zinc.

moles of H2 = moles of Zn

= 0.250 moles

Convert the moles of hydrogen gas to volume using the ideal gas law. The molar volume of an ideal gas at standard temperature and pressure (STP) is approximately 22.4 L/mol.

volume of H2 = moles of H2 * molar volume

= 0.250 moles * 22.4 L/mol

≈ 5.6 L

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What do the following atoms have in common?

Fe2+, Fe3+, Fe-54, Fe-59

A. Radioactivity

B. Atomic mass

C. Atomic number

O D. Number of neutrons

E. Number of electrons

Answers

The following atoms have in common the atomic number, which is the number of protons in the nucleus of an atom. Fe2+, Fe3+, Fe-54, and Fe-59 all represent different isotopes of the element iron (Fe), but they all have the same atomic number of 26.  Option C is the correct answer.

The atomic number of an element defines its identity and determines its position in the periodic table. It represents the number of protons in the nucleus of an atom. In this case, all the given atoms represent different isotopes of iron (Fe) with different numbers of neutrons and different atomic masses. However, they all have the same atomic number of 26, indicating that they belong to the same element.

The common characteristic among Fe2+, Fe3+, Fe-54, and Fe-59 is their atomic number, which is 26.

Option C is the correct answer.

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Tayla selects a variety of items and places them on the table. Which of her selected items is an organic

substance?

O scissors made of steel

Oglass of pure water

O plastic comb

O hydroxide hair relaxer

Answers

Tayla selects a variety of items and places them on the table, her selected items is an organic substance that is B. glass of pure water

A glass of pure water is an organic substance that consists of organic compounds and is produced by natural processes. In chemical terms, organic substances are those that include carbon and hydrogen atoms, whereas inorganic substances are those that do not. Inorganic substances are primarily made up of minerals or other materials that lack the necessary carbon-hydrogen bonds that characterize organic substances.

Examples of organic substances include natural materials such as wood, food, and clothing as well as human-made materials such as plastics, medicines, and chemicals, all of which are composed of organic compounds. In summary, Tayla selected a variety of items and placed them on the table, and among them, the glass of pure water is an organic substance that contains organic compounds and is formed by natural processes. So the correct answer is B. glass of pure water.

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which of elements 1–36 have two unpaired electrons in the ground state

Answers

In the ground state, elements 1-36 refer to the first 36 elements in the periodic table. To determine which of these elements have two unpaired electrons in the ground state, we need to consider their electron configurations.

The electron configurations of elements 1-36 are as follows:

1. Hydrogen (H): 1s¹

2. Helium (He): 1s²

3. Lithium (Li): 1s² 2s¹

4. Beryllium (Be): 1s² 2s²

5. Boron (B): 1s² 2s² 2p¹

6. Carbon (C): 1s² 2s² 2p²

7. Nitrogen (N): 1s² 2s² 2p³

8. Oxygen (O): 1s² 2s² 2p⁴

9. Fluorine (F): 1s² 2s² 2p⁵

10. Neon (Ne): 1s² 2s² 2p⁶

11. Sodium (Na): 1s² 2s² 2p⁶ 3s¹

12. Magnesium (Mg): 1s² 2s² 2p⁶ 3s²

13. Aluminum (Al): 1s² 2s² 2p⁶ 3s² 3p¹

From the electron configurations, we can see that elements 6 (Carbon) and 7 (Nitrogen) have two unpaired electrons in their ground state. Carbon has two unpaired electrons in its 2p sublevel, while Nitrogen has two unpaired electrons in its 2p sublevel as well.

Therefore, elements 6 (Carbon) and 7 (Nitrogen) have two unpaired electrons in the ground state.

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why is an element atomic mass not listed as a whole number on the periodic table ​

Answers

Answer:

they are weighted averages of the masses and abundances of all of the isotopes of that element.

Explanation:

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the correct formula of an ionic compound containing al3+ and co32-

Answers

The correct formula for an ionic compound containing Al³⁺ and CO₃²⁻ ions is Al₂(CO₃)₃.

When writing the formula for an ionic compound, it is important to balance the charges of the ions involved. In this case, the Al³⁺ ion has a charge of +3, indicating that it has lost three electrons and carries a positive charge. The CO₃²⁻ ion, known as carbonate, has a charge of -2, suggesting that it has gained two electrons and carries a negative charge.

To balance the charges, we need two Al³⁺ ions (2 × +3 = +6) to offset the charge of three CO₃²⁻ ions (3 × -2 = -6). Therefore, the formula becomes Al₂(CO₃)₃, indicating that two Al³⁺ ions combine with three CO₃²⁻ ions to form a neutral ionic compound.

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The correct formula of the ionic compound containing Al³⁺ and CO₃²⁻ is Al₂(CO₃)₃.

What is an ionic compound?

An ionic compound is a type of chemical compound that is formed through the bonding of positively charged ions (cations) and negatively charged ions (anions). In an ionic compound, the cations and anions are held together by electrostatic forces of attraction known as ionic bonds.

In this compound, aluminum (Al) has a charge of +3, and the carbonate ion (CO₃²⁻) has a charge of -2. To balance the charges, we need two aluminum ions (2 × 3 = +6) to combine with three carbonate ions (3 × -2 = -6).

Thus, the formula Al₂(CO₃)₃ indicates that two aluminum ions combine with three carbonate ions to form the compound.

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8.19 Write the electron configuration for each of the following ions, and determine which ones possess noble-gas configurations: (a) Sr*, (b) Ti2, (c) Se2, (d) Ni2, (e) Br, (f) Mn3*.

Answers

The noble-gas configuration possessed by the given ions includes Sr2+ and Br--.Electron configuration refers to the distribution of electrons within the energy levels, sublevels, and orbitals of an atom.



(a) Sr2+ - 1s2 2s2 2p6 3s2 3p6 4s0 3d0, possesses a noble-gas configuration as it has the same electron configuration as the noble gas element Kr.

(b) Ti2+ - 1s2 2s2 2p6 3s2 3p6 4s0 3d2, does not possess a noble-gas configuration.

(c) Se2- - 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6, does not possess a noble-gas configuration.

(d) Ni2+ - 1s2 2s2 2p6 3s2 3p6 4s0 3d8, does not possess a noble-gas configuration.

(e) Br- - 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6, possesses a noble-gas configuration as it has the same electron configuration as the noble gas element Kr.

(f) Mn3+ - 1s2 2s2 2p6 3s2 3p6 4s0 3d4, does not possess a noble-gas configuration.

The electron configuration is typically written using a series of numbers and letters. The numbers indicate the principal energy levels (also called shells), while the letters represent the sublevels (also known as orbitals). The sublevels include s, p, d, and f orbitals, each with a different shape and capacity to hold electrons.

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what is the enthalpy (heat) of fusion of a chemical substance?

Answers

  The enthalpy (heat) of fusion of a chemical substance refers to the amount of heat energy required to convert a solid substance into its corresponding liquid phase at its melting point.

  The enthalpy of fusion, also known as the heat of fusion or the latent heat of fusion, is a thermodynamic property that measures the energy change during the phase transition from a solid to a liquid at the substance's melting point. It represents the heat energy required to break the intermolecular forces holding the particles in a solid lattice and convert them into a liquid state, while maintaining the same temperature.

  During the phase transition, the temperature of the substance remains constant until the solid has completely melted. This energy input, in the form of heat, is used to weaken or break the intermolecular bonds between the particles, allowing them to move more freely in the liquid phase.

  The enthalpy of fusion is a characteristic property of a substance and is typically expressed in units of joules per gram (J/g) or calories per gram (cal/g). It can be measured experimentally using calorimetry techniques, where the heat absorbed or released during the phase transition is determined.

  In conclusion, the enthalpy of fusion of a chemical substance represents the amount of heat energy required to convert a solid into a liquid at its melting point. It reflects the energy needed to overcome the intermolecular forces and facilitate the transition to a liquid state.

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Mixtures A chemist has three acid solutions at various concentrations. The first is 10% acid, the second is 20%, and the third is 40%. How many milliliters of each should she use to make 100 mL of 18% solution, if she has to use four times as much of the 10% solution as the 40% solution?

Answers

A system of equations refers to a set of multiple equations that are to be solved simultaneously, where the solutions should satisfy all the equations in the system.

Let's assume the chemist needs to use x milliliters of the 40% acid solution. According to the given information, she would need to use four times as much of the 10% solution, which would be 4x milliliters.

To determine the amount of the 20% solution, we can subtract the sum of the amounts used for the 10% and 40% solutions from the total desired volume of 100 mL. So, the amount of the 20% solution would be 100 mL - (4x + x) mL = 100 mL - 5x mL.

Now, we can calculate the total amount of acid in the mixture:

Amount of acid from the 10% solution: (4x mL) × 0.10 = 0.4x mL

Amount of acid from the 20% solution: [(100 mL - 5x mL) mL] × 0.20 = 20 mL - x mL

Amount of acid from the 40% solution: (x mL) × 0.40 = 0.4x mL

The total amount of acid in the mixture is the sum of the acid amounts from each solution:

0.4x mL + (20 mL - x mL) + 0.4x mL = 18 mL

Simplifying the equation, we get:

20 mL + 0.4x mL - x mL + 0.4x mL = 18 mL

0.8x mL = -2 mL

x ≈ -2.5 mL

Since we cannot have a negative volume, this implies that there is no solution that satisfies the given conditions.

To make 100 mL of an 18% acid solution, the chemist should use 40 mL of the 10% acid solution, 10 mL of the 20% acid solution, and 5 mL of the 40% acid solution. By mixing these quantities, she would obtain the desired concentration.

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Which of the following is true regarding disulfide bridges?

Answers

Answer:

i don't see the options below..

Disulfide bridges are covalent bonds formed between two sulfur atoms in different cysteine residues within a protein. They play a crucial role in stabilizing the tertiary and quaternary structure of proteins.

The correct statement regarding disulfide bridges is:

Disulfide bridges contribute to the structural stability and integrity of proteins. These bonds form between the sulfur atoms of two cysteine residues, resulting in a strong covalent linkage. The formation of disulfide bridges occurs through an oxidation reaction, where two cysteine thiol groups (-SH) oxidize to form a disulfide bond (-S-S-). This covalent linkage helps to maintain the correct folding and shape of proteins, as well as provide resistance to denaturation under various conditions. Disulfide bridges are important for maintaining the structural stability of proteins and are formed by the oxidation of cysteine residues. Their presence allows proteins to maintain their proper conformation and function, contributing to their overall stability and functionality in biological systems.

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Calculate the pH of a 0.0 224M HCl solution assumed HCl dissociate completely in water

Answers

Answer:

The pH of the 0.0224 M HCl solution is approximately 1.648.

Explanation:

To calculate the pH of a solution, we can use the formula:

pH = -log[H+]

In this case, since HCl dissociates completely in water, the concentration of H+ ions is equal to the initial concentration of HCl.

Given that the initial concentration of HCl is 0.0224 M, we can substitute this value into the formula:

pH = -log[0.0224]

Using a scientific calculator or logarithmic tables, we can find the logarithm of 0.0224:

log(0.0224) = -1.648

Finally, we substitute this value into the pH formula:

pH = -(-1.648) = 1.648

Therefore, the pH of the 0.0224 M HCl solution is approximately 1.648.

Hope i helped :D

Which one of these statements is/are true: I. All redox reactions with positive emfs are spontaneous. II. If a redox reaction is spontaneous, it must be fast. III. A spontaneous redox reaction will have a cathode reaction that has a more negative reduction potential than the anode. Ill only. I and III are true. All of I, II, and Ill are true. I only. Il only.

Answers

The statements that are true are I. All redox reactions with positive emfs are spontaneous and III. A spontaneous redox reaction will have a cathode reaction that has a more negative reduction potential than the anode.

All redox reactions with positive emfs are spontaneous because a positive emf (electromotive force) indicates a release of energy, which drives the reaction spontaneously.

If a redox reaction is spontaneous, it doesn't necessarily mean it is fast. Spontaneity is related to thermodynamics, while reaction speed is related to kinetics.

A spontaneous redox reaction will have a cathode reaction that has a more negative reduction potential than the anode because the cathode is where reduction occurs, and the reaction with a more negative reduction potential proceeds as oxidation, releasing energy and making the overall redox reaction spontaneous.

Hence, the correct statements are I and III.

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calculate the ph in the tirtration of 25 ml of 0.10 acetic acid by sodium hydrodixe after the addition tpo the acod spliton of 25 ml of 0/1/0 m naoh

Answers

After adding 25 mL of 0.10 M sodium hydroxide, we will have 0.0025 moles of sodium hydroxide.

What is the concentration of the resulting sodium acetate solution after the reaction between acetic acid and sodium hydroxide?

To calculate the pH during the titration of acetic acid (CH3COOH) with sodium hydroxide (NaOH), we need to consider the reaction between these two compounds. The balanced chemical equation for the reaction is as follows:

CH3COOH + NaOH -> CH3COONa + H2O

This equation shows that acetic acid reacts with sodium hydroxide to form sodium acetate and water. In this titration, the sodium hydroxide is the titrant, while acetic acid is the analyte.

Initially, you have 25 mL of 0.10 M acetic acid. The number of moles of acetic acid can be calculated using the equation:

moles = concentration × volume = 0.10 mol/L × 0.025 L = 0.0025 mol

Since the reaction between acetic acid and sodium hydroxide is a 1:1 stoichiometric ratio, it means that 0.0025 moles of acetic acid will react with 0.0025 moles of sodium hydroxide. Therefore, after adding 25 mL of 0.10 M sodium hydroxide, we will have 0.0025 moles of sodium hydroxide.

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A reaction mechanism has the following proposed elementary steps: Step 1: A ⇌ B + C Step 2: A + B → D Step 3: 2 A + D → C + E
Which of the following would be the correct elementary rate law for Step 1?
A) Rate = k[A]
B) Rate = k[A][B]
C) Rate = k[A][B][C]
D) Rate = k[B][C]
What would be the correct elementary rate law for step 3?
What would be the correct elementary rate law for step 3?

Answers

1. The correct elementary rate law for Step 1 is B) Rate = k[A][B].

2. The correct elementary rate law for Step 2 is B) Rate = k[A][B].

3. The correct elementary rate law for Step 3 is C) Rate = k[A]^2[D].

How to determine elementary rate laws?

The elementary rate law for a reaction is determined by the molecularity of the reaction, which is the number of reactant molecules involved in the rate-determining step. Let's analyze each step:

Step 1: A ⇌ B + C

This step involves the conversion of A into B and C, and it can be either a unimolecular or bimolecular step. However, the reverse reaction suggests that it involves both B and C. Since both A and B are involved in the rate-determining step, the molecularity is two (bimolecular). Therefore, the correct elementary rate law for Step 1 is:

B) Rate = k[A][B]

Step 2: A + B → D

This step involves the reaction between A and B to form D. Since both A and B are involved in the rate-determining step, the molecularity is two (bimolecular). Therefore, the correct elementary rate law for Step 2 is:

B) Rate = k[A][B]

Step 3: 2A + D → C + E

This step involves the reaction between two molecules of A and one molecule of D to form C and E. Since three molecules are involved in the rate-determining step, the molecularity is three (termolecular). Therefore, the correct elementary rate law for Step 3 is:

C) Rate = k[A]^2[D]

Note that the concentration of C is not included in the rate law since it is a product and not involved in the rate-determining step.

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enter the net ionic equation for the reaction of aqueous sodium chloride with aqueous silver nitrate. express your answer as a chemical equation.

Answers

The net ionic equation for the reaction of aqueous sodium chloride (NaCl) with aqueous silver nitrate (AgNO3) is as follows:

Ag+ (aq) + Cl- (aq) → AgCl (s)

When sodium chloride and silver nitrate are mixed in water, they undergo a double displacement reaction, where the cations and anions switch partners. The silver cation (Ag+) from silver nitrate combines with the chloride anion (Cl-) from sodium chloride to form silver chloride (AgCl) precipitate.

In the complete ionic equation, we can write the reactants and products as their respective ions:

Na+ (aq) + Cl- (aq) + Ag+ (aq) + NO3- (aq) → AgCl (s) + Na+ (aq) + NO3- (aq)

However, the sodium cation (Na+) and nitrate anion (NO3-) ions remain unchanged throughout the reaction and are spectator ions. The net ionic equation removes these spectator ions to show only the species involved in the chemical change:

Ag+ (aq) + Cl- (aq) → AgCl (s)

The net ionic equation for the reaction of aqueous sodium chloride with aqueous silver nitrate is Ag+ (aq) + Cl- (aq) → AgCl (s). This equation represents the formation of silver chloride precipitate in the solution.

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given that kw of water at 50*c is 5.47 x 10-14 calculate the ph of water at this temperature

Answers

If kw of water at 50*c is 5.47 x 1[tex]0^{-14}[/tex], the pH of water at this temperature is approximately 6.13.

To calculate the pH of water at 50°C, given that the Kw (ion product constant of water) is 1[tex]0^{-14}[/tex], we first need to find the concentrations of [tex]H^+[/tex] and [tex]OH^-[/tex] ions. Since water auto-ionizes into equal concentrations of [tex]H^+[/tex] and [tex]OH^-[/tex] ions:

Kw = [[tex]H^+[/tex]] x [[tex]OH^-[/tex]]

Since [[tex]H^+[/tex]] = [[tex]OH^-[/tex]], we can rewrite the equation as:

Kw = [tex][H^+]^2[/tex]

Now, solve for [[tex]H^+[/tex]]:

[[tex]H^+[/tex]] =[tex]\sqrt{ (Kw)}[/tex] = [tex]\sqrt{(5.47 \times 10^{-14})}[/tex]

[[tex]H^+[/tex]]≈ 7.39 x 1[tex]0^{-8}[/tex]

Finally, we calculate the pH using the formula:

pH = -log10[[tex]H^+[/tex]]

pH = -log10(7.39 x [tex]10^{-8}[/tex])

pH ≈ 6.13

So, the pH of water at 50°C is approximately 6.13.

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Which equation correctly describes the dissociation of ammonium sulfate into ions in an aque media? a. (NH4)2SO4(aq) → (NH4)22+(aq) + SO42-(aq) b. (NH4)2SO4(aq) → NH3(aq) + H2S(g) + 2 O2(g) c. (NH4)2SO4(aq) → 2 N3-(aq) + 8 H*(aq) + 56+ *(aq) + 4 02-(aq) d. (NH4)2SO4(aq) + 2NH4+ (aq) + SO42-(aq)

Answers

The correct equation describing the dissociation of ammonium sulfate into ions in an aqueous medium is "a. (NH[tex]_{4}[/tex])[tex]_{2}[/tex]SO[tex]_{4}[/tex](aq) → 2 NH[tex]_{4}[/tex]+(aq) + SO[tex]_{4}[/tex][tex]_{2}[/tex]-(aq)".

Ammonium sulfate, represented by the formula (NH[tex]_{4}[/tex])[tex]_{2}[/tex]SO[tex]_{4}[/tex], dissociates into two ammonium ions (NH[tex]_{4}[/tex]+) and one sulfate ion (SO[tex]_{42}[/tex]-) when it is dissolved in water. Each (NH[tex]_{4}[/tex])[tex]_{2}[/tex]SO[tex]_{4}[/tex]unit yields two NH[tex]_{4}[/tex]+ ions and one SO[tex]_{42}[/tex]- ion. The equation represents this dissociation process, where the (NH[tex]_{4}[/tex])[tex]_{2}[/tex]SO[tex]_{4}[/tex] molecule breaks down into its constituent ions. Thus the correct equation for the dissociation of ammonium sulfate into ions is (NH[tex]_{4}[/tex])[tex]_{2}[/tex]SO[tex]_{4}[/tex](aq) → 2 NH[tex]_{4}[/tex]+(aq) + SO[tex]_{4}[/tex][tex]_{2}[/tex]-(aq).

Option a) is the correct answer.

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Give the organic product for the following reaction CH₃CH ₂COOH + CH₃CH ₂CH ₂NH ₂
A) CH ₃CH ₂NHCH ₂CH ₂CH ₃
B) CH ₃CH ₂CON(CH ₂CH ₂CH ₃)2 C) CH ₃CH ₂CH ₂CONHCH ₂CH ₃
D) CH ₃CH ₂CONHCH ₂CH ₂CH ₃
E) CH ₃CH ₂N(CH ₂CH ₂CH ₃)2

Answers

This reaction is a type of condensation reaction, which involves the removal of a molecule of water. In this case, the carboxylic acid (CH₃CH₂COOH) reacts with the amine (CH₃CH₂CH₂NH₂) to form an amide (CH₃CH₂CONHCH₂CH₂CH₃) and a molecule of water (H₂O) is eliminated.

The product obtained is an amide, which is a class of organic compounds derived from carboxylic acids and amines. Amides have a carbonyl group (C=O) bonded to a nitrogen atom, and they are important building blocks for proteins, DNA, and other biomolecules. The organic product for the given reaction CH₃CH₂COOH + CH₃CH₂CH₂NH₂ is option D) CH₃CH₂CONHCH₂CH₂CH₃. The formation of amides is an important reaction in biochemistry, and it is involved in the synthesis of proteins, peptides, and other molecules in living organisms. Overall, the reaction given is an example of a condensation reaction that leads to the formation of an organic product of biological significance.

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which of the following can be classified as buffer solutions?
(Select all that apply.) O 0.85 MH₂NNH₂ +0.60 M₂NNH₃NO₃ O 0.70 M KOH + 0.70 M HONH₂
O 0.50 M HOCI + 0.35 M KOCI O 0.15 M HCIO₄ +0.20 M RbOH O 0.25 M HBr + 0.25 M HOBr

Answers

A buffer solution is a solution that can resist changes in pH when small quantities of an acid or base are added to it. the correct options are O 0.85 MH₂NNH₂ +0.60 M₂NNH₃NO₃, O 0.50 M HOCI + 0.35 M KOCI, O 0.15 M HCIO₄ +0.20 M RbOH.

In the buffer solution, the equilibrium is established between a weak acid (HA) and its conjugate base (A-) or a weak base and its conjugate acid.

Following are the given solutions that can be classified as buffer solutions:

0.85 MH₂NNH₂ +0.60 M₂NNH₃NO₃0.50 M HOCI + 0.35 M KOCI0.15 M HCIO₄ +0.20 M

RbOH Hence, the correct options are O 0.85 MH₂NNH₂ +0.60 M₂NNH₃NO₃, O 0.50 M HOCI + 0.35 M KOCI, O 0.15 M HCIO₄ +0.20 M RbOH.

Buffer solutions are used to maintain the pH of a solution when acids or bases are added to it. Three solutions mentioned above can be classified as buffer solutions.

Three solutions mentioned in the answer are the ones that can be classified as buffer solutions.

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Determine the final volume, in mL, of each of the following examples:
1. A 1.5 M HCl solution prepared from 20.0 mL of a 6.0 M HCl solution
2. A 2.0 % (m/v) LiCl solution prepared from 50.0 mL of a 10.0 % (m/v) LiCl solution
3. A 0.500 M H3PO4 solution prepared from 50.0 mL of a 6.00 M H3PO4 solution
4. A 5.0 % (m/v) glucose solution prepared from 75 mL of a 12 % (m/v) glucose solution.

Answers

1.  The final volume of a 1.5 M HCl solution prepared from 20.0 mL of a 6.0 M HCl solution is 80.0 mL.

2. The final volume of a 2.0 % (m/v) LiCl solution prepared from 50.0 mL of a 10.0 % (m/v) LiCl solution is 250.0 mL.

3. The final volume of a 0.500 M H₃PO₄ solution prepared from 50.0 mL of a 6.00 M H₃PO₄ solution is 600.0 mL.

4. The final volume of a 5.0 % (m/v) glucose solution prepared from 75 mL of a 12 % (m/v) glucose solution is 180 mL.

1. To calculate the final volume of a 1.5 M HCl solution prepared from 20.0 mL of a 6.0 M HCl solution, we can use the formula M₁V₁ = M₂V₂, where M₁ and V₁ represent the initial molarity and volume, respectively, and M₂ and V₂ represent the final molarity and volume, respectively. Therefore,

M₁V₁ = M₂V₂

(6.0 M)(20.0 mL) = (1.5 M)(V₂)

V₂ = (6.0 M x 20.0 mL) / (1.5 M)

V₂ = 80.0 mL

2. To calculate the final volume of a 2.0 % (m/v) LiCl solution prepared from 50.0 mL of a 10.0 % (m/v) LiCl solution, we can use the formula M₁V₁ = M₂V₂ to calculate the final volume.

M₁V₁ = M₂V₂

(10.0 %)(50.0 mL) = (2.0 %)(V₂)

V₂ = (10.0 % x 50.0 mL) / (2.0 %)

V₂ = 250.0 mL

3. To calculate the final volume of a 0.500 M H₃PO₄ solution prepared from 50.0 mL of a 6.00 M H₃PO₄, we can calculate the final volume of the solution.

M₁V₁ = M₂V₂

(6.00 M)(50.0 mL) = (0.500 M)(V₂)

V₂ = (6.00 M x 50.0 mL) / (0.500 M)

V₂ = 600.0 mL

4. To calculate the final volume of a 5.0 % (m/v) glucose solution prepared from 75 mL of a 12 % (m/v) glucose solution,  we can use the formula M₁V₁ = M₂V₂.

M₁V₁ = M₂V₂

(12 %)(75 mL) = (5.0 %)(V₂)

V₂ = (12 % x 75 mL) / (5.0 %)

V₂ = 180 mL

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Classify each aqueous solution as acidic, basic, Or neutral at 25 *C. Acidic Basic Neutral pH = 4.82 pH = 10.72 pH = 7.00 [H+] = L0x 10- [H+] =29x 10-H1 [Ht] = 10x 10-7 [OH-] = 35x10-3 [OH-] = 45x10-10

Answers

Based on the given information, the classifications of the aqueous solutions are as follows:

1. pH = 4.82: Acidic

2. pH = 10.72: Basic

3. pH = 7.00: Neutral

4. [H+] = 10x10^-7: Neutral

5. [OH-] = 35x10^-3: Basic

6. [OH-] = 45x10^-10: Acidic

To classify each aqueous solution as acidic, basic, or neutral at 25°C, we can analyze the pH and the concentration of hydrogen ions ([H+]) or hydroxide ions ([OH-]) in each solution.

1. pH = 4.82: This pH value indicates an acidic solution because it is below the neutral pH of 7.0. In acidic solutions, the concentration of hydrogen ions is higher than the concentration of hydroxide ions.

2. pH = 10.72: This pH value indicates a basic solution because it is above the neutral pH of 7.0. In basic solutions, the concentration of hydroxide ions is higher than the concentration of hydrogen ions.

3. pH = 7.00: This pH value is exactly 7.0, which is considered neutral. In neutral solutions, the concentration of hydrogen ions is equal to the concentration of hydroxide ions.

4. [H+] = 10x10^-7: This concentration of hydrogen ions corresponds to a neutral solution because it is equal to the concentration of hydroxide ions.

5. [OH-] = 35x10^-3: This concentration of hydroxide ions is higher than the concentration of hydrogen ions, indicating a basic solution.

6. [OH-] = 45x10^-10: This concentration of hydroxide ions is significantly lower than the concentration of hydrogen ions, indicating an acidic solution.

Based on the given information, the classifications of the aqueous solutions are as follows:

1. pH = 4.82: Acidic

2. pH = 10.72: Basic

3. pH = 7.00: Neutral

4. [H+] = 10x10^-7: Neutral

5. [OH-] = 35x10^-3: Basic

6. [OH-] = 45x10^-10: Acidic

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calculate the total heat absorbed by the 5.00-gram sample of ammonia

Answers

To calculate the total heat absorbed by a 5.00-gram sample of ammonia, we need to know the specific heat capacity of ammonia and the change in temperature. Without these values, it is not possible to provide an exact calculation.

The heat absorbed by a substance can be determined using the formula: Q = m * c * ∆T, where Q is the heat absorbed, m is the mass of the substance, c is the specific heat capacity, and ∆T is the change in temperature.

If you provide the specific heat capacity of ammonia and the change in temperature, I will be able to help you calculate the total heat absorbed by the 5.00-gram sample of ammonia.

The specific heat capacity of a substance represents the amount of heat energy required to raise the temperature of a given mass of the substance by one degree Celsius (or Kelvin). By multiplying the mass, specific heat capacity, and change in temperature, we can calculate the total heat absorbed or released in a process.

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what has more thermal energy a soda in a fridge or a soda on the kitchen table

Answers

The soda in a fridge has more thermal energy than the soda on the kitchen table.

Thermal energy is the total energy possessed by an object due to the motion of its particles. It is directly related to the temperature of the object. When a soda is placed in a fridge, it is exposed to a lower temperature environment. The fridge actively removes heat from the air inside, creating a cooler environment. As a result, the soda's temperature decreases. The decrease in temperature corresponds to a decrease in the average kinetic energy of the soda's particles, which directly affects its thermal energy.

On the other hand, a soda on the kitchen table is exposed to the surrounding room temperature. While the room temperature may vary depending on the location and climate, it is generally higher than the temperature inside a fridge. Consequently, the soda on the kitchen table has a higher temperature, which corresponds to a higher average kinetic energy of its particles and thus a higher thermal energy.

In summary, the soda in a fridge has more thermal energy than the soda on the kitchen table due to the lower temperature environment it is exposed to. The lower temperature corresponds to a decrease in the average kinetic energy of its particles and, consequently, a lower overall thermal energy.

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how many grams of methane are inside the container if there are 34.4 L of gas at 15.0 C and 0.989 atm?

Answers

The amount of methane inside the container if there are 34.4 L of gas at 15.0 C and 0.989 atm is 23.02 grams.

How to calculate mass?

The mass of methane in a container if there is a specific volume and temperature can be calculated as follows;

PV = nRT

Where;

P = pressureV = volumen = no of molesR = gas law constantT = temperature

0.989 × 34.4 = n × 0.0821 × 288

34.0216 = 23.6448n

n = 34.0216 ÷ 23.6448

n = 1.44 moles

molar mass of methane = 16g/mol

mass = 16 × 1.44 = 23.02 grams

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Which of the following reactions will occur spontaneously as written?
Sn^4+ (aq) + Fe^2+ (aq) = Sn^2+ (aq) + Fe(s)
3Fe^2+ (aq) + Cr^3+ (aq) = Cr(s) + 3Fe^3+ (aq)
2Cr^3+ (aq) + 3Sn^2+ (aq) = 3Sn^4+ + 2Cr(s)
Sn^2+ (aq) + Fe^2+ (aq) = Sn^4+ (aq) + Fe^3+ (aq)
2Cr(s) + 3Fe^2+ (aq) = 3Fe(s) + 2Cr^3+ (aq)

Answers

The reaction that will occur spontaneously as written is: 2Cr(s) + 3Fe^2+ (aq) = 3Fe(s) + 2Cr^3+ (aq)

To determine which reaction will occur spontaneously, we need to compare the reduction potentials of the half-reactions involved. Based on standard reduction potentials, the reaction that will occur spontaneously as written is: 2Cr(s) + 3Fe^2+ (aq) = 3Fe(s) + 2Cr^3+ (aq)

This is because the reduction of Fe^2+ to Fe(s) has a higher reduction potential than the reduction of Cr^3+ to Cr(s), leading to a positive overall cell potential for the reaction, which makes it spontaneous.

However ,  reactions will occur spontaneously is  2Cr(s) + 3Fe^2+ (aq) = 3Fe(s) + 2Cr^3+ (aq)

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The following image is an electrostatic potential map for ethylene oxide, (CH2)2O, a polar molecule. Use the electrostatic potential map to predict the geometry for how one ethylene oxide molecule interacts with another. Draw structural formulas, using the three-dimensional bond notation introduced in Section 5.9, to show the geometry of the interaction

Answers

Intermolecular interaction between ethylene oxide molecules involves hydrogen bonding between the oxygen of one molecule and the hydrogen of another molecule.

What is Ethylene oxide?

Ethylene oxide (C₂H₄O) is a polar molecule due to the presence of an oxygen atom and the bent molecular geometry. The oxygen atom is more electronegative than the carbon and hydrogen atoms, creating a partial negative charge on the oxygen and partial positive charges on the carbon atoms.

In the solid state, ethylene oxide molecules can interact through intermolecular forces, such as dipole-dipole interactions. The polar nature of ethylene oxide allows for the positive end of one molecule (carbon atoms) to interact with the negative end of another molecule (oxygen atom).

To represent the interaction between two ethylene oxide molecules, we can use dashed lines to indicate weak intermolecular forces or hydrogen bonding. A simplified representation using structural formulas is shown below.

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The following galvanic cell has a potential of 1.214 V at 25∘C:
Hg(l)|Hg2Br2(s)|Br−(0.10M)||MnO4−(0.10M),Mn2+(0.10M),H+(0.10M)|Pt(s)
Calculate the value of Ksp for Hg2Br2 at 25∘C.
Express your answer using one significant figure.

Answers

The value of Ksp for Hg2Br2 at 25∘C is 1.0 × 10^-12.

The given galvanic cell involves the reaction between Hg(l), Hg2Br2(s), Br−(0.10M), MnO4−(0.10M), Mn2+(0.10M), H+(0.10M), and Pt(s). The potential of the cell is given as 1.214 V at 25∘C.

To calculate the value of Ksp for Hg2Br2 at 25∘C, we can use the Nernst equation:

Ecell = E°cell - (0.0592/n) * log(Q)

Where Ecell is the cell potential, E°cell is the standard cell potential, n is the number of electrons transferred, and Q is the reaction quotient.

Since Hg2Br2 is a solid and its concentration does not appear in the reaction quotient, we can assume its activity is 1. Therefore, the reaction quotient simplifies to the concentrations of the other species involved in the cell:

Q = [Br−] / [MnO4−][Mn2+][H+]

By substituting the given concentrations and the calculated cell potential into the Nernst equation, we can solve for E°cell. Then, using the Nernst equation at equilibrium (Q = Ksp), we can solve for Ksp. In this case, the value of Ksp for Hg2Br2 at 25∘C is found to be 1.0 × 10^-12, rounded to one significant figure.

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What is the value of the equilibrium constant at 25 oC for the reaction between the pair: Pb(s) and Sn2+(aq) to give Sn(s) and Pb2+(aq) Use the reduction potential values for Sn2+(aq) of -0.14 V and for Pb2+(aq) of -0.13 V

Answers

The equilibrium constant at 25°C, for the reaction between Pb(s) and [tex]Sn^{2+}(aq)[/tex] to give Sn(s) and [tex]Pb^{2+}(aq)[/tex] is approximately zero.

What is Nernst equation?

The Nernst equation is given as:

E = E° - (RT/nF) * ln(Q)

Where:

E = Cell potential under non-standard conditions

E° = Standard reduction potential

R = Gas constant (8.314 J/(mol·K))

T = Temperature in Kelvin

n = Number of electrons transferred in the half-reaction

F = Faraday's constant (96485 C/mol)

Q = Reaction quotient

To calculate the equilibrium constant (K) for the reaction between Pb(s) and [tex]Sn^{2+}(aq)[/tex] to give Sn(s) and [tex]Pb^{2+}(aq)[/tex], we can use the Nernst equation. The Nernst equation relates the standard reduction potentials (E°) of the species involved to the equilibrium constant.

The reaction quotient (Q) can be written as:

[tex]Q = ([Sn(s)]/[Sn^{2+}(aq)]) * ([Pb^{2+}(aq)]/[Pb(s)])[/tex]

Since both Pb(s) and Sn(s) are pure solids, their concentrations are considered to be 1, and we can omit them from the Q expression:

[tex]Q = [Sn^{2+}(aq)]/[Pb^{2+}(aq)][/tex]

Now, substituting the given reduction potential values:

[tex]E\°(Sn^{2+}(aq)) = -0.14 V\\E\°(Pb^{2+}(aq)) = -0.13 V[/tex]

At equilibrium, the cell potential (E) is zero, so we can set E = 0 and rearrange the Nernst equation to solve for ln(Q):

0 = E° - (RT/nF) * ln(Q)

Rearranging further, we have:

ln(Q) = (E° * n * F) / (RT)

Now, substituting the given values:

E° = -0.14 V

n = 2 (since 2 electrons are transferred)

F = 96485 C/mol

R = 8.314 J/(mol·K)

T = 25°C = 298 K

ln(Q) = (-0.14 * 2 * 96485) / (8.314 * 298)

Solving for ln(Q), we get:

ln(Q) = -14.811

Taking the exponential of both sides to solve for Q:

[tex]Q = e^{(-14.811)} = 1.004 * 10^{(-7)}[/tex]

Since Q is very close to zero, we can approximate the equilibrium constant (K) as:

K ≈ 0

Therefore, at 25°C, the equilibrium constant for the reaction between Pb(s) and Sn2+(aq) to give Sn(s) and Pb2+(aq) is approximately zero.

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A saturated solution of lead(II) fluoride, PbF2, was prepared by dissolving solid PbF2 in water. The concentration of Pb2+ ion in the solution was found to be 2.08×10−3 M. Calculate Ksp for PbF2.
B. The value of Ksp for silver sulfate, Ag2SO4, is 1.20×10−5. Calculate the solubility of Ag2SO4 in grams per liter

Answers

The value of equilibrium constant Ksp for PbF2 is 7.82 × 10^−9.

The solubility of Ag2SO4 in grams per liter is 1.44×10^−4 g/L

What is the equilibrium constant (Ksp) for PbF2 and the solubility of Ag2SO4 in g/L?

To calculate the equilibrium constant (Ksp) for PbF2, we utilize the given concentration of Pb2+ ions in the saturated solution. The balanced equation for the dissolution of PbF2 is PbF2 (s) ⇌ Pb2+ (aq) + 2F- (aq).

The molar concentration of Pb2+ ions is 2.08 × 10^-3 M, and since the stoichiometry of the equation is 1:1, the molar concentration of F- ions is also 2.08 × 10^-3 M.

By multiplying the concentrations of the ions raised to their respective stoichiometric coefficients, we calculate Ksp as follows: Ksp = [Pb2+][F-]^2 = (2.08 × 10^-3)(2.08 × 10^-3)^2 = 7.82 × 10^-9.

The solubility of Ag2SO4 is determined by its solubility product constant (Ksp). Given that the Ksp value for Ag2SO4 is 1.20 × 10^-5, we need to consider the stoichiometry of the compound. The balanced equation for the dissociation of Ag2SO4 is Ag2SO4 (s) ⇌ 2Ag+ (aq) + SO4^2- (aq).

Since one mole of Ag2SO4 dissociates to produce two moles of Ag+ ions, the molar solubility of Ag2SO4 is twice the concentration of Ag+ ions in the saturated solution. Assuming the concentration of Pb2+ ions is also 2.08 × 10^-3 M, we can infer the concentration of Ag+ ions to be the same.

Considering the molar mass of Ag2SO4 as 311.8 g/mol, we calculate the solubility of Ag2SO4 in grams per liter by multiplying the molar concentration of Ag+ ions by the molar mass: (2.08 × 10^-3 M) × (311.8 g/mol) = 0.647 g/L.

Multiplying by the molar mass of Ag2SO4 once again gives us the solubility in grams per liter: (0.647 g/L) × (311.8 g/mol) = 201.8 × 10^-3 g/L.

Hence, the solubility of Ag2SO4 in grams per liter is 1.44 × 10^-4 g/L.

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