Which of the following is an example of an "experimenter-expectancy effect?"
a. participants come to experiments with preconceived notions of what they are supposed to do, and perform based on those notions rather than on what they are asked to do.
b. the experimenter "expects" females to experience more difficulty on a math task so the experimenter unintentionally behaves in ways that undermine the performance of females on the math task
c. participants in a study are nicebehave differently for the attractive experimenter than for the less attractive experimenter
d. a researcher finds that his participants did not behave as he expected them to, so he changes his statement of his hypothesis when he writes up his results
Answer: . the experimenter "expects" females to experience more difficulty on a math task so the experimenter unintentionally behaves in ways that undermine the performance of females on the math task

Answers

Answer 1

The example of the experimenter-expectancy effect is option (b)  The experimenter "expects" females to experience more difficulty on a math task so the experimenter unintentionally behaves in ways that undermine the performance of females on the math task

The experiment-expectancy is defined as the unintended effect of the hypotheses that is obtained from the the result of the research participant.

It is also defined as how the perceived expectations of an observer can influence.

Hence, the example of the experimenter-expectancy effect is option (b)  The experimenter "expects" females to experience more difficulty on a math task so the experimenter unintentionally behaves in ways that undermine the performance of females on the math task

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Related Questions

5 t-hirt and a hat cot 17£
2 t-hirt and a hat cot 8£
how much doe a t hirt cot
how much doe a hat cot

Answers

The cost of the t-shirt is 3 and the cost of a hat is 2

Let the price of a t-shirt be x

and the price of a hat be y

cost of 5 t-shirt and a hat is 17

5x + y = 17 equation 1

cost of 2 t-shirt and a hat is 8

2x + y = 8   equation 2

subtracting equation 2 from equation 1

5x + y - (2x + y) = 17 - 8

5x + y - 2x - y = 9

3x = 9

x = 3

2x + y = 8

2 (3) + y = 8

y = 8 - 6

y = 2

Therefore, the cost of the t-shirt is 3 and the cost of a hat is 2

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For the triangles to be congruent by hl, what must be the value of x? 8 9 17 34

Answers

Using equations we know that the value of x needs to be (E) 4 to make HL congruent to AC.

What are equations?

A mathematical equation is a formula that uses the equals sign to represent the equality of two expressions.

The point-slope form, standard form, and slope-intercept form are the three main types of linear equations.

So, HL is a hypotenuse that will be congruent to the hypotenuse AC.

We know that HL is 3x + 3.

Ac is 15.

Then the equation will be:

3x + 3 = 15

Now, solve the equation to get x as follows:

3x + 3 = 15

3x = 15 - 3

3x = 12

x = 12/3

x = 4

Therefore, the value of x needs to be (E) 4 to make HL congruent to AC.

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Correct question:
For the triangles to be congruent by hl, what must be the value of x?

a. 8

b. 9

c. 17

d. 3

e. 4

Consider the following time series data. week 1 2 3 4 5 6 value 16 11 13 10 14 12 (a) construct a time series plot. what type of pattern exists in the data? the data appear to follow a seasonal pattern. the data appear to follow a horizontal pattern. the data appear to follow a trend pattern. the data appear to follow a cyclical pattern. (b) develop the three-week moving average for this time series. (round your answers to two decimal places.) week time series value forecast 1 16 2 11 3 13 4 10 5 14 6 12 compute mse. (round your answer to two decimal places.) mse

Answers

The overall MSE for the time series would be (0 + 0 + 0.0289 + 0.0144 + 0.0044 + 0.0144)/6 = 0.0119. This value indicates that the forecasted values are close to the actual time series values, with a small error.

What is MSE?

Mean squared error (MSE) is a standard measure of the average squared difference between predicted and actual value. Regression analysis frequently use it to assess a model's performance pattern. The sum of squared discrepancies between the predicted and actual values is multiplied by the number of observations in the dataset to derive the MSE. A lower MSE signifies a better match between the model and the data. In regression analysis, MSE is generally compared to the variance of the response variable, which is a measure of data dispersion. The MSE reveals how well the model fits the data when it is less than the variance.

How to solve?

To construct a time series plot for the given data, we can plot the values of the data against the weeks on the x-axis.

Week 1 | |

Week 2 | |

Week 3 | |

Week 4 | |

Week 5 | |

Week 6 | |

The three-week moving average for each week would be as follows:

Week 1: 16

Week 2: 11

Week 3: 12.67

Week 4: 11.33

Week 5: 12

Week 6: 11.33

The MSE for each week would be as follows:

Week 1: 0

Week 2: 0

Week 3: 0.0289

Week 4: 0.0144

Week 5: 0.0044

Week 6: 0.0144

The overall MSE for the time series would be (0 + 0 + 0.0289 + 0.0144 + 0.0044 + 0.0144)/6 = 0.0119. This value indicates that the forecasted values are close to the actual time series values, with a small error.

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if a test contains 14 true or false questions, how many ways can a student answer the questions on the test if every question is answered?

Answers

Answer: 28

Step-by-step explanation: a true false question has 2 questions per question if it either true or false so if there is 14 questions with all true and false it would be 14 x 2 = 28

For each 50mm of coloured fabric, I ue 10cm of white fabric. Expre to amount of white fabric to coloured fabric a a ratio of it implet form

Answers

amount of white fabric to coloured fabric a a ratio of it implet form is given by 1/2

2cm = 2 * 10 mm

2 cm = 20 mm

for every 50 mm of colored fabric, Gavyn uses 100 mm of white fabric.

The ratio is expressed as white fabric to colored fabric.

Ratio white to colored = 50/100 =  1/2

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A pile of brick weight 22kg. 18759gram of brick are removed. What weight i left?

Answers

Answer: Answer is 3241 gm or 3.2 kg approx.

Step-by-step explanation:

Weight of the brick( in kg) =22 kg

Weight of the brick in gm= 22*1000 gm      (1 kg = 1000gm)

                                          = 22000 gm

Weight of bricks removed = 18759 gm

Weight of bricks left in the pile= 22000-18759gm

                                                   =3241 gm or 3.2 kg approx

Hence, the weight of the bricks left is 3.2 kg approx.

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data hiding means that critical data stored inside the object is protected from code outside the object. this is accomplished in java by (fill in the blank).

Answers

The correct option is B is correct that is by setting access to private on the class fields using the correct notation.

Given that,

Data hiding refers to the protection of sensitive data from outside code for an object. This is achieved using Options

A) Making use of the class methods' private access specifier.

B) By setting access to private on the class fields using the correct notation.

C) Using the class methods' public access specifier.

D) Using the class definition's private access specifier.

Whichever choice is accurate must be determined.

We know that,

What is a public and private access?

The private modifier limits access to a class's methods or properties from any code that is outside the class, but the public access modifier permits a code from inside or outside the class to access the class's methods and properties.

Therefore, The correct option is B is correct that is by setting access to private on the class fields using the correct notation.

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Lael wants to determine several totals and averages for active students. In cell Q8, enter a formula using the COUNTIF function to count the number of students who have been elected to offices in student organizations.

Answers

The COUNTIF function to count the number of students who have been elected to offices in student organizations in Cell Q8 is ‘=COUNTIF(M2:M31, "Elected")’.

The COUNTIF function is a premade function in Excel, which counts cells as specified. It is one of the statistical functions which is used to count the number of cells that meet a criterion. In the given situation, Lael wants to count the number of students who have been elected to offices in student organizations from the data available in the excel spreadsheet. The COUNTIF function is used to determine the total by using the formula: ‘=COUNTIF(M2:M31, "Elected")’ in the Cell Q8.

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Trekkers footwear bought a piece of machinery on january 1, 2006 at a cost of $2. 3 million, and the machinery is being depreciated annually at an amount of $230,000 for 10 years. Its market value on december 31, 2008 is $1. 75 million. The firm's accountant is preparing its financial statement for the fiscal year end on december 31, 2008. The asset's value should be recognized on the balance sheet at.

Answers

The asset's value should be recognized on the balance sheet at $1.61 million.

Given,

On January 1st, 2006, Trekkers Footwear paid $2.3 million for a piece of equipment that will be depreciated at a rate of $230,000 per year for ten years. As of December 31, 2008, IT was worth $1.75 million in the market. The company's accountant is putting the finishing touches on the financial statement for the fiscal year that ends on December 31, 2008.

The balance sheet should reflect the asset's value at,

Cost of Asset = $2.3 million

Annual depreciation = $230000

Total no. of years depreciated till December 31, 2008, = 3 years

Hence, total depreciation = $230000 x 3 = 690000 = 0.69 million

Hence, book value as on 31 December 2008 = $2.3 million - $0.69 million = 1.61 million

Given Market Value on Dec 31, 2008, = $1.75 million.

But as per accounting conventions, Assets are recorded at Book value.

Hence $1.61 million is the right answer.

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After an alcoholic beverage is consumed, the concentration of alcohol in the bloodstream (blood alcohol concentration, or BAC) surges as the alcohol is absorbed, followed by a gradual decline as the alcohol is metabolized. The function C(t)=0.135 t e^{-2.802 t}C(t)=0.135te −2.802t models the average BAC, measured in g/dL, of a group of eight male subjects t hours after rapid consumption of 15 mL of ethanol (corresponding to one alcoholic drink) What is the maximum average BAC during the first 3 hours? When does it occur?

Answers

It gradually decreases as alcohol is metabolized. The function C(t)=0.135 t e^{-2.802 t}models the mean BAC measured in g/mL.

The maximum average BAC during 3 hours is 0.0001358 g/mL.

f(t) = α t e−βt --(1)

Let's rewrite this in a simple form:

f(t)= α eˡⁿ ᵗ e⁻βt = αe^(ln t −βt)

Since e^x is strictly increasing and it will be maximized exactly when its argument is maximized, so we can maximize instead:

g(t)=ln t −βt

differentiating with respect to t , and g'(t) = 0

g′(t)=1/t − β = 0

=> t =1/β

we have given a function

C(t)=0.135 t e⁻²·⁸⁰²ᵗ

if we compare it with (1) we get

β = 2.802, 0.135 = α

For it's maximized we need to check the second order condition, and that of g will differentiate again , g′′(t)= −1/t² < 0

We have to compute the derivative of C(t):

C′(t) = 0.135 t⋅(−2.802)e⁻²·⁸⁰²ᵗ + 1.35e⁻²·⁸⁰²ᵗ

For optimum at t₀ if C′(t₀)=0 and C′′(t₀)≠0. Here, we have

C′(t₀) = 0.135t₀⋅(−2.802)e⁻²·⁸⁰²ᵗ₀+ 0.135e⁻²·⁸⁰²ᵗ₀ =e⁻²·⁸⁰²ᵗ₀(−0.135* 2.802t₀+ 0.135)=0

It is clear that e⁻²·⁸⁰²ᵗ₀ not equal to zero for all t₀∈R, so that

=> −0.135* 2.802t₀+0.135=0

=> t₀ = 1/2.802 ≈0.36

let us consider t is in hours, so that it makes t₀ =0.36h≈21.41min. This is the only optimum and one should verify it is indeed a maximum, i.e. C′′(t₀)<0.

Now, easily compute the maximum average BAC, which is C(t₀)=C(0.36) = 0.135 (0.36)e⁻²·⁸⁰²⁽⁰·³⁶⁾

= 0.0486(0.3678) = 0.01787508

Hence, the maximum average BAC, is 0.017 g/dL.

Maximum average BAC during the first 3 hours,

t = 3 , C(t)=C(3) = 0.135 (3)e⁻²·⁸⁰²⁽³⁾ = 0.0001358 g/mL

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What is the prime factorization of 54 exponential form?.

Answers

The Prime Factorization of 54 in exponential form is 2¹ × 3³  .

The Exponential Form is a way of writing repeated multiplication that involves base and exponents . For Example : 5×5×5 = 5³ .

In the question ,

it is given that ,

the number is 54 ,

we have to find the prime factorization , and write it in the exponential form .

the number 54 can be expressed in factors as 2 × 3 × 3 × 3 .

which means 54 = 2 × 3 × 3 × 3 .

which can be written as 2 × 3³ .

So , the exponential form is 2¹ × 3³ .

Therefore , The Prime Factorization of 54 in exponential form is 2¹ × 3³  .

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BBQ Corp. had a 3:1 stock split ratio. Pre-split the company had 1.35 Million outstanding shares at a price of $72.45 per share.
How many outstanding shares does BBQ Corp. have post-split?

Answers

The number of outstanding shares that BBQ Corp. will have post-split, given the number of outstanding shares is, 4, 050, 000 shares

What is a stock split?

A stock split refers to when the number of outstanding shares that a company has, are divided into a certain number of shares which is based on the split ratio.

For a 3:1 stock split ratio, the number of outstanding shares will be split into three shares each.

BBQ Corp. has 1. 35 million shares so post - split, they will have:

= Outstanding shares x  3

= 1, 350, 000 x  3

= 4, 050, 000 shares

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Yearly expenses at a state university have increased from $14,000 to $18,500 in the last 4 years. What has been the average annual growth rate in expenses? If this growth rate continues, what will the expenses be 4 years from now?

Answers

The annual growth rate in the expenses is 0.08035 or 8.03 % and with the same rate the expenses after 4 years will be equal to $24,642.

How annual growth rate is calculated?

Annual growth rates are calculated by taking the average revenue for a particular time period into account. The yearly growth rate formula divides the final value of an investment or asset by its original value. When you subtract one from this amount, you are left with a decimal point that can be translated into a percentage. You may determine the percentage by simply moving the decimal point two spaces to the right.

The growth in the 4 years is = 18,500 – 14,000 = 4,500

Growth = initial amount (rate) (time)

4500 = x(4)(14,000) = 0.08035

It means the annual growth rate is 8.03 %

To know the expenses after 4 years, lets take initial value = 18,500, rate = 8.03% = 0.083, time = 4 years,

Increase = 18500(0.083)(4) = 6,142

So, the expenses after 4 years,

Expenses = 18,500 + 6,142 = 24,642

Therefore, the expenses after 4 years are $24,642

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given a plane defined by the points (1,0,0), (0,1,0), and (0,0,1), what is the foot and orientation of the normal vector of this plane whose ray would cross (1,1,1)

Answers

The foot and orientation of the normal vector of this plane whose ray would cross (1,1,1) is (0,1,1) and 2.

Given:

we have three points:

Q(1,0,0),

R(0,1,0),

and S(0,0,1)

when the plane passes through Q,R, and S, then the vectors

QR = (-1,1,0) and QS = (-1,0,1)

lie in the plane. Thus the cross-product

n = I i  j  k  I

      -1 1 0

      -1 0 1 I

= i + j + k is normal to the plane.

If r=⟨x,y,z⟩ determines an arbitrary point P in the plane, the vector

v = QP = ⟨x-1,y−0,z−0⟩

ray = (1,1,1)

v = QP = (1-1, 1-0, 1-0)

= (0,1,1)

lies in the plane and so is perpendicular to n. In this case,

n⋅v = 1(0)+1(1)+1(1)

= 0+1+1

= 2

Hence the foot and orientation f the normal vector of this plane is (0,1,1) and 2.

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Percy rides his bike 11.2 miles in 1.4 hours at a constant rate. Write an equation to represent the proportional relationship between the number of hours Percy rides,x, and the distance in miles, y, that he travels.

Answers

An equation to represent the proportional relationship between the number of hours and the distance in miles is k=y/x.

Given that, Percy rides his bike 11.2 miles in 1.4 hours at a constant rate.

What is the speed?

The speed formula can be defined as the rate at which an object covers some distance. Speed can be measured as the distance travelled by a body in a given period of time. The SI unit of speed is m/s.

The number of hours Percy rides x, and the distance in miles, y, that he travels

So, the proportional relationship is speed = y/x

Thus, 11.2/1.4

= 8 miles per hour

Therefore, an equation to represent the proportional relationship between the number of hours and the distance in miles is k=y/x.

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From standard 52-card deck how many 9-card hands consist of 3 spades and diamonds? There are possible 9-card hands consisting of 3 spades and diamonds

Answers

Answer:

6

Step-by-step explanation:

for this I simply divided that numbers and I got my answer as 5.77 and I turned as 6

mrs. ibanez has come to the ed with painless jaundice (with an obstructive profile on liver tests), a 30-pound weight loss over three months, and profound dehydration, for which she was admitted to the hospital.

Answers

Mrs. Ibanez is experiencing symptoms of a potentially serious condition and should be evaluated by a medical professional as soon as possible.

What is a potentially serious condition?

Any medical disease that has the potential to get worse or be life-threatening if it is not treated quickly and effectively qualifies as potentially serious. Infections, wounds, and long-term medical issues like diabetes or heart disease or profound dehydration are a few examples of potentially catastrophic illnesses. These illnesses can range in severity from moderate to severe, and they might need to be treated right once to avoid long-term harm or other consequences. If you think you may have a dangerous issue, it's crucial to speak with a doctor right away so you can get the proper care and stop the problem from becoming worse.

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Simplify the following please
[tex] log_{3}27 + 2 log_{3}9 - log_{3}54[/tex]

Answers

Answer:

4 - log3 (2)

Step-by-step explanation:

2log3 (9) = log3 (9^2)


log3 (27 * 9^2 / 54)

log3 ( 3^3 * 3^4 / 9 * 6)

log3 (3^7 / 3^2 * 3 * 2)

log3 (3^7 / 3^3 * 2)

log3 ( 3^4 /2)

log3 (3^4) - log3 (2)

4 - log3 (2)

If the point A(1,2), B(k1,2)and C(6,7)are the vertice of triangle having B=90deg ,find value of k

Answers

Using the Pythagoras threoem,

the possible value of k are 6 or 1 in right angled triangle.

We have given that,

There is a triangle say, ∆ABC with vertices A(1,2) ,B(k , 2) and C(6,7).

and angle, B = 90°

that is this is a right angled triangle with angle ABC is 90° .

we have to find out the value of k .

Using Pythagoras threoem,

AB² + BC² = AC²---(*)

where, AB ,BC and AC are sides of ∆ABC.

using distance formula, we find length of sides of ∆ABC . let coordinates of A (a₁,b₁) and B(a₂,b₂)

AB = √(a - a)² + (b-b)²

put a₁ = 1 , b₁ = 2 , a₂ = k , b₂ = 2

AB² = (k - 1)² + (0) = (k-1)²

similarly we can easily calculate the length of other sides of ∆ABC.

BC² = (6-k)² + 25

AC²= (5)² + (5)² = 50

putting all sides value in above formula,

50 = (k-1)² + (6-k)²+ 25

=> 25 = k² + 1 - 2k + 36 + k² - 12k

=> 2k² - 14k + 12 = 0

=> k²- 7k +6 = 0

this is a quadratic equation we solve it and find out value of k

using , roots formula

k = { -(-7) +- √(-7)^2 - 4(1)(6)}/2×1

=> k = either( 7 + √25) /2 or (7- √25)/2

=> k = either 6 or 1

Hence , the possible value of k are 6 or 1

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Which equation represents a line that passes through 5 1 and has a slope of StartFraction one half EndFraction?.

Answers

The equation of line which passes through point (5,1) and having slope ½ is (y-1) = ½ (x-5).

What is the equation of a line?

The equation of a line is given as:

y = mx + c

The equation for the point on slope line is given as:

y - y1 = m ( x - x1 )

Substituting the above given values and the slope:

y - 1 = [tex]\frac{1}{2}[/tex] ( x - 5)

Hence, the equation of line which passes through point (5,1) and slope ½ is (y-1) = ½ (x-5).

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What is a example and a non-example of product of 10

Answers

Answer: 20 & 37

Explanation:

What we know:

Products are numbers that are a result of two numbers being multipliedAll products of 10 end in 0How to solve:

Process:

10*2=20

20 is a product of 10 because (10*2=20)

37 is not a product of 10 because there are no whole numbers that 10 can be multiplied with to make 37

Answer: 20 & 37

HELP MEEEE PLEASEEEEEEE

Answers

Answer:

91.1 cm

Step-by-step explanation:

the formula to find circumferences is pi times diameter

29pi

91.1

Hopes this helps please mark brainliest

find the minimum value of the function f(x)= x2+2.6x-2 to the nearest hundredth.

Answers

Answer:

[tex](-1.3,-3.69)[/tex]

Step-by-step explanation:

Take the derivative of the function and set it equal to 0.

[tex]f(x)=x^2+2.6x-2[/tex]

[tex]f'(x)=2x+2.6 = 0[/tex]

Solve for x.

[tex]2x+2.6=0\\2x=-2.6\\x=-1.3[/tex]

Find [tex]f(-1.3)[/tex]

[tex]f(-1.3)=(-1.3)^2+2.6(-1.3)-2[/tex]

[tex]f(-1.3)=-3.69[/tex]

Can we construct a triangle with the sides 2cm 3cm and 5cm justify?.

Answers

Answer:

No

Step-by-step explanation:

The sum of two sides of a triangle should be greater than the size of the third side.

2 + 3 is not greater than 5, so it's impossible to construct a triangle using the given lengths for the sides.

Find all solutions of x in degrees for (sinx- 1)(sinx+ 1) = 0.

Answers

Answer:

x = 90° + 180° × n, for all integers, n

Step-by-step explanation:

(sin x - 1)(sin x + 1) = 0

sin x = 1  or sin x = -1

The sine function has value 1 at 90° and all coterminal angles.

The sine function has value -1 at 270° and all coterminal angles.

Answer: x = 90° + 180° × n, for all integers, n

Simplify completely
√40x^7

Answers

Simplified value of given expression is 2x³√10x.

What is simplification?

In arithmetic,  simplification is reducing the expression / fraction problem during a less complicated type.

Main body:

Factor 40 into its prime factors

          40 = 2³ • 5

To simplify a square root, we extract factors which are squares, i.e., factors that are raised to an even exponent.

Factors which will be extracted are :

          4 = 2²

Factors which will remain inside the root are :

          10 = 2 • 5

To complete this part of the simplification we take the squre root of the factors which are to be extracted. We do this by dividing their exponents by 2 :

          2 = 2

At the end of this step the partly simplified SQRT looks like this:

        2 • sqrt (10x7)

Rules for simplifing variables which may be raised to a power:

  (1) variables with no exponent stay inside the radical

  (2) variables raised to power 1 or (-1) stay inside the radical

  (3) variables raised to an even exponent: Half the exponent taken out, nothing remains inside the radical. examples:

     (3.1) sqrt(x⁸)=x4

    (3.2) sqrt(x-⁶)=x-3

     (4) variables raised to an odd exponent which is  >2  or  <(-2) , examples:

     (4.1) sqrt(x5)=x²•sqrt(x)

    (4.2) sqrt(x-7)=x³•sqrt(x-1)

Applying these rules to our case we find out that

    SQRT(x7) = x³ • SQRT(x)

 sqrt (40x7) =

       2² x³• sqrt(10x)

Hence the simplification to the value is as 2² x³ • sqrt(10x)

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The compressive strength, in kilopascals, was measured for concrete blocks from five different batches of concrete, both three and six days after pouring: The data are as follows Can you conclude that the mean strength after three days differs from the mean strength after six days? Let /z represent the mean strength after three days and /d = 01 ~ 4z' Use the & = 0.05 level. Block After } days 1354 After 6 doys 1341 131 1338 1330 1320 1307 1327 1371 1351 State the null and alternate hypotheses. Compute the test statistic: State a conclusion

Answers

The null hypothesis is: [tex]H_0: \mu_d = 0[/tex]The alternative hypothesis is: [tex]H_1: \mu_d \neq 0[/tex]The test statistic is: t = -0.69.The conclusion is: there is not enough evidence to conclude that the means are different.

What are the hypothesis tested?

At the null hypothesis, it is tested if there is not enough evidence that the means are difference, that is, if the subtraction is of zero, hence:

[tex]H_0: \mu_d = 0[/tex]

At the alternative hypothesis, it is tested if there is enough evidence that the means are difference, that is, if the subtraction is different of zero, hence:

[tex]H_1: \mu_d \neq 0[/tex]

We have a two-tailed test, as we are testing if the mean is different of a value, with 5 + 5 - 2 = 8 df and a significance level of 0.05, hence the critical value is of:

|t| = 2.306.

What are the mean and the standard error for the distribution of differences?

For each sample, the mean and the standard error are given as follows:

After 3 days: Mean: 1340.8, standard error: 12.16.After 6 days: Mean: 1352.6, standard error: 12.15.

For the distribution of differences, the mean and the standard error are given as follows:

Mean: 1340.8 - 1352.6 = -11.8.Standard error: s = sqrt(12.16² + 12.15²) = 17.19.

What is the test statistic and the conclusion?

The test statistic is given by the division of the sample mean by the standard error, hence:

t = -11.8/17.19

t = -0.69.

The absolute value of the test statistic is less than the critical value for the two-tailed test, hence:

The null hypothesis is not rejected.There is not enough evidence to conclude that the means are different.

Missing Information

The data is given by the image at the end of the answer.

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Karina travel 70 mile at an average peed of 50 mph. She then travel a further 60 mile. The average peed for the entire journey i 44 mph. Auming Karina didn't top, what wa her average peed for the final 60 mile to 2 dp?

Answers

The speed at 60 miles to 2 dp if Karina didn't stop, will be 38.5 mph.

Speed is defined as the rate of change of position of a subject in any direction. We have the basic formula to find the speed given by:

Speed = [tex]\frac{Distance}{Time}[/tex]
s = [tex]\frac{d}{t}[/tex]

To find the average speed for the last 60 miles, we need to know the time spent by Karina during the final 60 miles.

For the initial time during 70 miles, we follow the below calculations:

Initial Speed = [tex]s_{i}[/tex] = 50mph
Initial Distance = [tex]d_{i}[/tex] = 70 miles
Initial time for 70 miles = [tex]t_{i}[/tex]

[tex]s_{i}[/tex] = [tex]\frac{d_{i} }{t_{i} }[/tex]

[tex]t_{i}[/tex] = [tex]\frac{d_{i} }{s_{i}}[/tex]

[tex]t_{i}[/tex] = [tex]\frac{70}{50}[/tex] = 1.4 hr

For the Total time = t,

Total Speed = s = 44 mph.

Total Distance = d = [tex]d_{i} + d_{f}[/tex] = 70 + 60 = 130 miles

Total time = [tex]\frac{d}{t}[/tex] = [tex]\frac{130}{44}[/tex] = 2.96 hr

For the Final time during 70 miles = [tex]t_{f}[/tex]

t = [tex]t_{i} + t_{f}[/tex]
[tex]t_{f}[/tex] = t - [tex]t_{i}[/tex]
[tex]t_{f}[/tex] = 2.96 - 1.4 = 1.56 hr

Hence, the average speed for the final 60 miles can be calculated as:

Final Speed = [tex]s_{f}[/tex] = ?
Final Distance = [tex]d_{f}[/tex] = 60
Final Time = [tex]t_{f}[/tex] = 1.56 hr.

Average Speed = [tex]s_{a}[/tex] =  [tex]\frac{d_{f}}{t_{f}}[/tex] =  [tex]\frac{70}{1.56}[/tex] = 38.50 mph.

So, the Final average speed for the last 60 miles Karina traveled is 38.50 mph

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a simple random sample of 5 months of sales data provided the following information: month: 1 2 3 4 5 units sold: 94 85 85 94 92 (a) develop a point estimate of the population mean number of units sold per month. x

Answers

The point estimate of the population mean number of units sold per month is given by:

90.

How to obtain the point estimate of a parameter?

The point estimate of a population parameter is obtained as the value of the parameter in the sample.

The parameter that we want to obtain the estimate in this problem is:

The mean.

The sample in this problem is given by:

94, 85, 85, 94, 92.

(number of units sold each month).

The sample mean is given by the sum of all observations in the sample divided by the number of observations, hence it is obtained as follows:

Mean = (94 + 85 + 85 + 94 + 92)/5 = 90.

For the fraction, we have that:

The numerator is the sum of all observations.The denominator is the number of observations.

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in a local university 70% of the students live in the dormitories. A random sample of 75 students is selected for a particular study The probability that the sample proportion (the proportion living in the dormitories) is at least 0.60 is
a.0.0294
b.0.9706
c.0.0228
d. 0.9772

Answers

The probability that the sample proportion is at least 0.60 is 0.0294.

Given data,

In a local university, 70% of the students live in dormitories. A random sample of 75 students is selected for a particular study The probability that the sample proportion (the proportion living in the dormitories) is at least 0.60 is,

The sample size in this case,

n = 75

The proportion of students living in dormitories p,

⇒ 70% = 0.7

Since we are taking a distribution of 75-sample samples from the given population into consideration, we have:

The mean, p = 0.7

The standard deviation, s = √p * (1 − p)/n

                                           = √0.7 * (1 − 0.7)/75

                                           = 0.0529

Now, by figuring out their respective Z-scores, we can calculate the probability values corresponding to the supplied proportion values.

The Z-score for a proportion value of 0.60;

Z₀.₆₀ = (0.6 - p)/s

        = (0.6 - 0.7)/0.0529

        = -1.890

The Standard Normal Distribution table can be used to determine the corresponding probability. Consequently, the overall likelihood value for,

Z₀.₆₀ = -1.890

P-value from Z-Table,

P(x < 0.6) = 0.029355 = 0.0294

Hence, there is a 0.0294 percent chance that the sample proportion is at least 0.60.

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