Answers
Answer:
Option C may be the anawer for it
Related Questions
Like charges repel, whereas opposite charges attract. Is this true or false?
Answers
The electrostatic force between the like charges is positive and between the unlike charges is negative.
The positive value of force indicates the repulsion and the negative value of the force represent the attarction between the charges.
Thus, the like charges repel each other and unlike charges attract each other.
Hence, the given statement is true.
Answer: True
Explanation: Completed & passed test <3
HELP! A car drives 15 miles, then drives 5 miles. Calculate car's distance and displacement.
Answers
A car drives 15 miles, then drives 5 miles. The distance travelled by the car is 20 miles and the displacement is 10miles.
What is distance?Distance is defined as the entire motion of an object, regardless of direction.
It can also be defined as the product of an object's speed and the entire time required for it to complete the distance of its journey.
Displacement is defined as the distance between the two markings, which is irrespective of the route that was used to get there.
It can also be defined as a one-dimensional measurement used to express the distance between two specified places.
Distance = 15 + 5
= 20 miles
Displacement = 15 - 5
= 10 miles
Thus, a car drives 15 miles, then drives 5 miles. The distance travelled by the car is 20 miles and the displacement is 10miles.
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A force of 200 N is exerted on an object of mass 80 kg that is located on a sheet of perfectly smooth ice. What is the acceleration of the object?
Answers
Answer:down below
Explanation: Mass of first object = 40 kg
Mass of similar second object = 40 kg
Total mass = 40+40 = 80 kg
Force = 200 N
S
Force = Mass × Acceleration
200 = 80 × Acceleration
Acceleration = 200/80 = 2.5 m/s²
4. What is the kinetic energy of a bike with a mass of 16 kg traveling at 4 m/s?
Answers
The kinetic energy of a 16kg bike with a velocity of 4m/s is 128 joules.
What is the kinetic energy of the bike?Kinetic energy is simply the energy a body possesses due to its motion.
Its expressed as;
K.E = 1/2 × m × v²
Where m is mass and v is velocity
Given the data in the question;
Mass m = 16kgVelocity v = 4m/sKinetic energy K.E = ?Plug the given values into the formula above and solve for K.E.
K.E = 1/2 × m × v²
K.E = 1/2 × 16kg × (4m/s)²
K.E = 8kg × 16m²/s²
K.E = 128kgm²/s²
K.E = 128J
Therefore, the kinetic energy is 128 Joules.
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Use the data given to decide which water heater is more efficient. Show all relevant calculations to
support your choice.
Answers
Answer:
Heater B
Explanation:
The efficiency = Energy output / Energy input.
This is because the efficiency is basically "how well can this thing use energy, will it waste a lot of energy or will most of the energy go towards the use?"
The efficiency of A is:
Energy input = 7 * 10^3
Energy output = 4.5 * 10^3
4.5 * 10^3 / (7.0*10^3) = 0.642857143 = 64 %
The efficiency of B is:
Energy input = 5*10^4
Energy output = 3.3 * 10^4
3.3 * 10^4 / (5 * 10^4) = 0.66 = 66 %
The efficiency of B is greater, so heater B is more efficient by a little margin
The efficiency = Energy output / Energy input.
This is because the efficiency is basically "how well can this thing use energy, will it waste a lot of energy or will most of the energy go towards
the use?"
The efficiency of A is:
Energy input = 7 * 10^3
Energy output = 4.5 * 10^3
4.5 * 10^3 / (7.0*10^3) = 0.642857143 = 64 %
The efficiency of B is:
Energy input = 5*10^4
Energy output = 3.3 * 10^4
3.3 * 10^4 / (5 * 10^4) = 0.66 = 66 %
The efficiency of B is greater, so heater B is more efficient by a little margin
A 58-kg boy swings a baseball bat, which causes a 0.140-kg baseball to move towards 3rd base with a velocity of 38.0 m/s. What is the kinetic energy of the baseball?
Answers
ANSWER:
101.08 joules.
STEP-BY-STEP EXPLANATION:
Given:
m = 0.140 kg
v = 38.0 m/s
Kinetic energy can be calculated using the following formula:
[tex]E=\frac{1}{2}\cdot m\cdot v^2[/tex]Replacing
[tex]\begin{gathered} E=\frac{1}{2}\cdot0.140\cdot(38.0)^2 \\ E=101.08\text{ J} \end{gathered}[/tex]The kinetic energy of baseball is 101.08 joules.
A lever is being used to try to lift a heavy object, but it is not working. Which of these actions would increase the output force the most?
Answers
The given problem can be exemplified in the following diagram:
Where:
[tex]\begin{gathered} F_i=\text{ input force} \\ d_i=\text{ input displacement} \\ d_0=\text{ output displacement} \\ F_o=\text{ output force} \end{gathered}[/tex]Now, we add the torques in the lever and we get:
[tex]\Sigma M=F_0d_0-F_id_i[/tex]If we consider the system in equilibrium then the sum of torque is equal to zero, therefore:
[tex]F_0d_0-F_id_i=0[/tex]Now we solve for the output force, first by adding "Fidi" to both sides:
[tex]F_0d_0=F_id_i[/tex]Now we divide both sides by the output distance:
[tex]F_0=\frac{F_id_i}{d_0}[/tex]Therefore, we get an expression for the output force. In this expression, we see that in order to increase the output force we need to decrease the output distance and increase the input force.
A train accelerates at a rate of 2 Km/hr/sec for a period of 30 seconds. If its initial speed was 15 Km/hr, what will be its final speed?
Answers
a = Vf - vi / t
Where:
a = acceleration = 2 km/h/s
vf= final speed
vi= initial speed = 15 km/h
t= time = 30 sec
Isolate Vf
at = Vf- vi
at + vi = vf
Replacing:
vf = 2 km/h/s * 30s + 15 km/h
vf = 60 km/h + 15 km/h
Vf= 75 km/h
A car applies a force of 36.8 Newtons for a 668-meter loop; what was the work done? (1 point)
O 18.2 J
O 705 J
O OJ
O 24,600 J
Answers
Answer:OJ
Explanation: it ok you can trust me (-_-)
Answer:
(Question) What is the mathematical relationship between force and work?
(Answer) W=F×d
(Question) If W=F×d, which of the following equations shows work being calculated using the correct units?
(Answer) 113 J=(17.4 N)×(6.51 m)
(Question) A force of 57.1 Newtons is applied for 0.977 meters; what work was done on the object?
(Answer) 55.8 J
(Question) A car applies a force of 36.8 Newtons for a 668-meter loop; what was the work done?
(Answer) 0J
(Question) A 8.43-Newton force was applied for an unknown displacement; however, it is known that 376 joules of work was done. What is the value of the mystery displacement?
(Answer) 44.6 m
Explanation:
just did the quick check UwU
Which of the following is true about the relationship between the gravitational force of Earth and the Moon? (1 point)
O The Earth has identical gravitational attraction to that of the Moon.
O The Moon has a greater gravitational attraction than the Earth.
O The Earth has no impact on the gravitational attraction of the Moon.
O The Earth has a greater gravitational attraction than the Moon.
Answers
Answer:
The Earth has a greater gravitational attraction than the moon.
Explanation:
Three crates with various contents are pulled by a force Fpull = 3677 N across a horizontal, frictionless roller-conveyor system.
The group of boxes accelerates at 1.430 m/s? to the right. Between each adjacent pair of boxes is a force meter that measures the
magnitude of the tension in the connecting rope. Between the box of mass m₁ and the box of mass m₂, the force meter reads
F12 = 1397 N. Between the box of mass m₂ and the box of mass m3, the force meter reads F23 = 2351 N. Assume that the
ropes and force meters are massless.
m
m.
m₂
Answers
If the three crates are pulled by a force of F pull = 3677 N and an acceleration of 1.43 m / s / s, the mass of box 1 is 976.92 kg, mass of box 2 is 667.18 kg and the mass of box 3 is 927.23 kg
F = m a
F = Force
m = Mass
a = Acceleration
F = 3677 N
a = 1.43 m / s²
F = ( m1 + m2 + m3 ) a
3677 = ( m1 + m2 + m3 ) 1.43
m1 + m2 + m3 = 2571.33 → ( 1 )
The force between masses 1 and 2 is F12 = 1397 N,
F12 = m1 a
1397 = m1 * 1.43
m1 = 976.92 kg
The force between masses 2 and 3 is F23 = 2351 N.
F23 = ( m1 + m2 ) a
2351 = ( 976.92 + m2 ) 1.43
m2 = 1644.1 - 976.92
m2 = 667.18 kg
From ( 1 ),
m1 + m2 + m3 = 2571.33
976.92 + 667.18 + m3 = 2571.33
m3 = 927.23 kg
Therefore,
Mass of box 1, m1 = 976.92 kgMass of box 2, m2 = 667.18 kgMass of box 3, m3 = 927.23 kgTo know more about Force meters
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What is the work done on a box if a force of 20.0N is applied at an angle of -25.0° while the box moves 8.00m?159J145J-67.6J21.2J
Answers
The work done by a constant force in a rectilinear motion is given by:
[tex]W=Fd\cos\theta[/tex]where F is the magnitude of the force, d is the distance the object moves and θ is the angle between the force vector and the displacement vector. In this case we have that:
0. The magnitude of the force is 20 N
,1. The distance is 8 m
,2. The angle between the force and the displacement vector is -25°.
Plugging these values in the expression for the work we have:
[tex]\begin{gathered} W=(20)(8)\cos(-25) \\ W=145 \end{gathered}[/tex]Therefore, the work done on the box is 145 J
If a giant molecular cloud is a distance of 21 pc away from Earth and drifts at a speed of 21 km/s toward Earth, how long (in years) would it take to reach Earth if the Sun remained at its current position?
Answers
The time it would take it to reach Earth if the Sun remained at its current position is 978,349.5 years.
What is the time of motion of the giant molecular cloud?
The time of motion of the giant molecular cloud is the time take for the giant molecular cloud to reach the earth.
Mathematically, the time taken for the giant molecular cloud to reach the earth is given as;
time = distance / speed
where;
the distance = 21 pc = 6.48 x 10¹⁴ kmspeed of the cloud = 21 km/stime of motion = (6.48 x 10¹⁴ km) / (21 km/s)
time of motion = 3.086 x 10¹³ seconds = 978,349.5 years.
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An amusement park game requires you to knock down a wood post by throwing a ball at it. You can choose between a tennis ball and a sticky clay ball of equal mass.Assume you can trow either balls with the same speed and accuracy. Which one would you choose:a.It will be all the same.b.The tennis ball.c.The clay ball.
Answers
We know that the impulse is defined by the change in momentum, that is:
[tex]Impulse=\Delta\vec{p}[/tex]Now, we know that we can throw the balls with the same speed and accuracy which means that both balls have the same initial momentum. Now, since the tennis ball will bounce from the wood and the clay ball will stick on it this means that the final momentum of the tennis ball is greater; this means that the change in momentum of the tennis ball will be greater and hence the impulse it exerts on the wood is greater.
Therefore, you should choose the tennis ball.
Which procedure describes how the scientific method might solve a problem? Find something scientists say is true and then ask questions about it. Identify something you think is true and then set out to prove it. Identify a question, make observations, create a hypothesis, and then set up an experiment to test the hypothesis. Do an experiment and then ask questions about it.
Answers
Identify a question, make observations, create a hypothesis, and then set up an experiment to test the hypothesis.
What is hypothesis?
A hypothesis is a put forth explanation for a phenomenon (plural: hypotheses). A hypothesis must be testable according to the scientific method for it to be considered a scientific hypothesis. Scientific hypotheses are typically based on prior observations that cannot be adequately explained by the current body of knowledge. Despite the frequent confusion between the terms "hypothesis" and "theory," a scientific hypothesis differs from a scientific theory. A working hypothesis is an accepted theory that has been tentatively supported and is put up for further investigation.
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3. If you puth 350 ON on a 45kg box to move it in the same direction as the push, while using 4462.53 of work. How far did you move it?
Answers
Given,
The applied force, F=350.0 N
The mass of the box, m=45 kg
The work done by the applied force, W=4462.5 J
The work is given by the product of the applied force and the distance through which the force is applied.
Thus the work done by the applied force on the box is given by,
[tex]W=F\times d[/tex]Where d is the distance covered by the box.
On rearranging the above equation,
[tex]d=\frac{W}{F}[/tex]On substituting the known values,
[tex]\begin{gathered} d=\frac{4462.5}{350} \\ =12.75\text{ m} \end{gathered}[/tex]Thus the box move for a distance of 12.75 m
19
Sonya says her interest in reality competition shows is waning. What is the state of her interest in these shows?
A.
B.
C.
D.
it's in decline
it's growing
it's stable
it's nonexistent
Answers
Answer:
a. its in decline
Explanation:
waning means decreasing
abigal drives her car with a constant speed of 32 miles per hour . how far can she travel in 1 hour?
Answers
Abigail drives her car with a constant speed of 32 miles per hour . How far can she travel in 1 hour?
Abigail is driving 32 miles an hour. This means she goes 32 miles in 1 hour.
Question 2 of 10Voltage:O A. makes the current flow in a circuit.O B. slows down the electrons in a circuit.aC. opposes energy flow in the circuit.O D. is measured in ohms.SIRA
Answers
When voltage is supplied to a circuit, potential difference is generated in the circuit.
The potential difference causes the current to flow in the circuit.
Thus, the voltage makes the current flow in a circuit.
What is the half life of an isotope that has a decay constant of 0.00567?
Answers
We are asked to determine the half-life of an isotope. To do that we will use the following formula:
[tex]T=\frac{ln(2)}{\lambda}[/tex]Where:
[tex]\begin{gathered} T=\text{ half-life} \\ \lambda=\text{ decay constant} \end{gathered}[/tex]Now, we plug in the values:
[tex]T=\frac{ln(2)}{0.00567}[/tex]Solving the operations:
[tex]T=122.25[/tex]Therefore, the half-life is 122.25
please solve exponential function10^2a+3=10^a-4
Answers
Given the exponential function:
[tex]10^{2a+3}=10^{a-4}[/tex]Let's evaluate the given exponential function.
Since the base of both sides are the same, the expressions are equal if the exponents are equal.
Remove the bases and equate the exponents:
[tex]2a+3=a-4[/tex]Subtract 3 from both sides:
[tex]\begin{gathered} 2a+3-3=a-4-3 \\ \\ 2a=a-7 \end{gathered}[/tex]Subtract a from both sides:
[tex]\begin{gathered} 2a-a=a-a-7 \\ \\ a=-7 \end{gathered}[/tex]ANSWER:
a = -7
this is a 3 part question33) The human head can be considered as a 3.3-kg cranium protecting a 1.5-kg brain, with a small amount of cerebrospinal fluid that allows the brain to move a little bit inside the cranium. Suppose a cranium at rest is subjected to a force of 2800 N for 6.5 ms in the forward direction. (a) What is the finalspeed of the cranium? (b) The back of the cranium then collides with the back of the brain, which is still at rest, and the two move together. What is their final speed? (c) The cranium now hits an external object and suddenly comes to rest, but the brain continues to move forward. If the front of the brain interacts with the front of the cranium over a period of 15 m/s before coming to rest, what average force is exerted on the brain by the cranium?
Answers
Given data:
* The force applied is 2800 N.
* The time for which the force applied is 6.5 ms.
* The mass of the cranium is 3.3 kg.
Solution:
(a). The momentum of the cranium in the terms of the force applied is,
[tex]p=Ft[/tex]where F is the force applied, and t is the time,
Substituting the known values,
[tex]\begin{gathered} p=2800\times6.5\times10^{-3} \\ p=18200\times10^{-3} \\ p=18.2kgms^{-1} \end{gathered}[/tex]The velocity of the cranium from the momentum is,
[tex]\begin{gathered} mv=p \\ v=\frac{p}{m} \end{gathered}[/tex]where m is the mass of cranium including the brain inside it,
Substituting the known values,
[tex]\begin{gathered} v=\frac{18.2}{3.3+1.5} \\ v=3.79\text{ m/s} \end{gathered}[/tex]Thus, the final speed of the cranium is 3.79 m/s.
A vector starts at point (-3, 4) and ends at point (6,-3). What is the magnitude of the vector? AnswerTo two decimal places
Answers
Given data
*A vector starts with a point is P = (-3, 4)
*A vector ends with a point is Q = (6, -3)
The formula for the magnitude of the vector PQ is given as
[tex]\lvert\vec{PQ}\rvert=\sqrt[]{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]Substitute the known values in the above expression as
[tex]\begin{gathered} \lvert\vec{PQ}\rvert=\sqrt[]{(6-(-3))^2+(-3-4)^2} \\ =\sqrt[]{(9)^2+(-7)^2} \\ =\sqrt[]{81+49} \\ =\sqrt[]{130} \\ =11.40 \end{gathered}[/tex]Identify the physical property of a material that plays an important role in determining if the collision is elastic or not.
Answers
The collisions are of two types as,
1. Elastic Collision: It is a collision in which the momentum of the system and net energy of the system before and after the collision remain same.
2. Inelastic Collision: It is a collision in which the momentum of the system before and after the system remain conserved but there is a loss in the energy takes place during the collision. Thus, the energy of the system does not remain conserved before and after the collision.
Hence, the energy of the material is a physical property of the same material that plays an important role in determining if the collision is elastic or not.
The coefficient of kinetic friction between the surface and the largest block is 0.20, and the coefficient of kinetic friction between the surface and the smaller block is 0.40. If F=25 N and M=4.0kg in the figure, what is the tension (in N) on the connecting string
Answers
The coefficient of kinetic friction between the surface and the largest block is 0.20, and the coefficient of kinetic friction between the surface and the smaller block is 0.40. If F=25 N and M=4.0kg , then the tension on the connecting string is 13.68N .
Given ,
the coefficient of kinetic friction between the surface and the largest block is 0.2 .
the coefficient of kinetic friction between the surface and the smaller block is 0.4 .
F = 25N
M= 4kg
thus the mass of smaller box is 4kg and the mass of largest box is 8kg .
Now , using free body diagram , to apply newton's second law ,
For m1 :∑Fx =T−f1 =m1a or T=m1a+f 1 ........... [1]
And also ∑Fy =n1−m1g=0 or n1=m1g
Also, the definition of the coefficient of friction gives
f1=μn1 =(0.4)(4kg)(9.80m/s^2)=15.68N
For m2:∑Fx=F–T–f2 =ma...................................... [2]
Also from the y component, n2–m2g=0 or n2=m2g
And again f2=μn2=(0.2)(8kg)(9.80m/s^2)=15.68N
Substituting T from equation [1] into [2], we get
F−m1a−f1−f2=m2a or F−f1−f2=m2a+m1a
Solving for a,
a=(F−f1 −f2)/(m1+m2) =( 25-15.68-15.68)/4+8 = -6.36/12 = -0.53m/s^2
Thus ,
T = m1a +f1 = 4(-0.53)+15.68 = 13.68N
Hence , the tension on connecting string is 13.68N .
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A team of horses is pulling a 910 kg wagon with a force of 4500 N. Assuming there are no other forces on the wagon, what is the wagon's acceleration?
Answers
A 20.0-N box rests on a 50.0-N box on a perfectly smooth horizontal floor. When a horizontal 15.0-N pull to the right is exerted on the lower box (see figure), both boxes move together what is the net force on the top block
Answers
The net force on the top block is 33.54 N.
What is net force?
Net force is the sum or resultant of two or more forces acting on a body.
Also, the net force is the force which is the sum of all the forces acting on an object simultaneously.
The sum of the upward forces is calculated as follows;
F(upward) = 50 N - 20 N = 30 N
The sum of the horizontal forces is calculated as follows;
F(horizontal) = 15 N
The net force or resultant force on the top block is calculated as follows;
F(net) = √Fy² + Fx²
where;
Fy is the sum of the vertical forcesFx is the sum of the horizontal forcesF(net) = √Fy² + Fx²
F(net) = √[(30)² + (15)²]
F(net) = 33.54 N
Thus, the net force or resultant force on the top block is determined as 33.54 N.
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What is the answer to this question? The answer has to be in 3 significant digits.
Answers
ANSWER:
2.99 meters per second
STEP-BY-STEP EXPLANATION:
Given:
m1 = 1.16 kg
m2 = 1.98 kg
Vi1 = 8.64 m/s
Vi2 = -3.34 m/s
Vf1 = -2.16 m/s
We can determine the speed of the second car thanks to the law of conservation of momentum which is the following:
[tex]m_1\cdot V_{i1}+m_2\cdot V_{i2}=m_1\cdot V_{f1}+m_2\cdot V_{f2}[/tex]We replace each value and we would have:
[tex]\begin{gathered} 1.16\cdot8.64+1.98\cdot3.34=1.16\cdot-2.16+1.98\cdot V_{f2} \\ 3.4092=-2.5056+1.98\cdot V_{f2} \\ 1.98\cdot V_{f2}=3.4092+2.5056 \\ V_{f2}=\frac{5.9148}{1.98} \\ V_{f2}=2.99\text{ m/s} \end{gathered}[/tex]The velocity of the second car is 2.99 meters per second
Motion can be described in terms of the speed, position, velocity, and acceleration of an object. How do these quantities relate to one another?
Answers
Speed is defined as a change in position over time. Position's derivative is velocity, and velocity's derivative is acceleration.
What is the relation between speed, position, velocity , acceleration?The speed equation is as simple as distance divided by time. We can define Speed as the rate at which an object's position changes in any direction.S = d/t
The direction is also indicated by the position function.In these problems, you're usually given a position equation of the form " x=" or " s (t) = s(t)= s(t)=", which tells you how far an object is from a given reference point.v = v 0 + a t
The velocity of something is the rate at which it moves in a specific direction.Although speed and velocity are frequently used interchangeably, they are distinct concepts in physics. The equation,v = s/t
represents velocity (v) as a vector quantity that measures displacement (or change in position, s) over time (t). A point or object moving in a straight line is accelerated if it accelerates or decelerates. Even if the speed is constant, motion on a circle is accelerated because the direction is constantly changing.a = (v - v0) / t = Δv / t
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When an object is placed at a distance greater than twice the focal length of the lens, the real image produced is ___________.1) inverted and smaller than the object2) inverted and large than the object3) inverted and the same size as the object4) upright and the same size as the object
Answers
When an object is placed at a distance greater than twice the focal length of the lens, the real image produced by lens is inverted and smaller than the object, which means option (1) is correct.
