which of the following is not a environmental factor that would affect the hamsters growth

The magnitude of the vector difference is approximately 12.98.

To find the magnitude of the vector difference, we need to subtract the components of vector B from the components of vector A and then find the magnitude of the resulting vector.

The components of the vector difference, C = A - B, are given by:

Cx = Ax - Bx = 7.6 - (-5.1) = 12.7

Cy = Ay - By = -9.2 - (-6.8) = -2.4

The magnitude of vector C is given by:

|C| = √(C² + Cy²)

Substituting the values of Cx and Cy, we get:

|C| = √(12.7² + (-2.4)²) = √(162.25 + 5.76) = √168.01

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The amount of time which the impetus was implemented is 3.04 seconds.

The momentum of the automobile is 34124.26 kg*m/s.

In order to figure out the time, the following formula for impulse can be applied: impulse = force x time. Reformulating and rearranging this equation, we reach the derivative of time = impulse / force. With the provided calculations of 536.49 N*s divided by 176.32 N, these figures conclude that the amount of time which the impetus was implemented is 3.04 seconds.

Additionally, we can use the formula of momentum = mass x velocity to further determine the vehicular testament of import. When applying these specified numbers of 2546.9 kg and 13.4 m/s respectively, the momentum of the automobile is 34124.26 kg*m/s.

momentum = 2546.9 kg x 13.4 m/s

= 34124.26 kg

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The total system momentum would remain the same before and after the collision. Option D

The law of conservation of momentum, which states that when no external forces are exerted on a system of objects, the system's overall momentum will remain constant, is a fundamental principle of physics.

The momenta of all the objects added together in the system prior to an event or interaction are equal to the momenta of the objects added together after the event or interaction.

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Answer:

equator

Explanation:

in south & north pole you could have 20+ hours daylight or night, everyday!

The length of the x-component of the vector is 8.1

The component that pushes right or left is called the x-component, and the part that pushes up or down is called the y-component.

To calculate the x-component of the vector plotted below, we use the formula below

Formula:

Where:

From the diagram,

Given:

Substitute these values into equation 1

Hence, the right option is B. 8.1

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A spring scale with a spring constant of 120 N/m would stretch by 0.14 meters if it had 3.75 J of work done on it.

The work done on a spring can be calculated using formula:

[tex]W = (1/2) * k * x^2[/tex]

where W is the work done in joules (J), k is spring constant in Newtons per meter (N/m), and x is displacement of the spring from its equilibrium position in meters (m).

Rearranging the formula, we get:

x = sqrt(2W/k)

Plugging in given values, we get:

x = sqrt(2 * 3.75 J / 120 N/m) = 0.14 m

Therefore, a spring scale with a spring constant of 120 N/m would stretch by 0.14 meters if it had 3.75 J of work done on it.

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Answer:

The pressure at a depth h in a fluid with density ρ is given by:

P = ρgh

where g is the acceleration due to gravity.

The force exerted on the eardrum is equal to the pressure difference between the inside and outside of the eardrum multiplied by the area of the eardrum:

F = A(Pinside - Poutside)

where A is the area of the eardrum, Pinside is the pressure inside the ear, and Poutside is the pressure outside the ear.

To find the depth at which the force on the eardrum is 1.5 N above atmospheric pressure, we need to first find the pressure difference and then the corresponding depth.

The atmospheric pressure at sea level is approximately 101,325 Pa. Adding 1.5 N of force per the eardrum means adding 1.5 N of force per the area of the eardrum, which is:

A = π(0.0079 m/2)^2 = 4.909×10^-5 m^2

So the pressure difference is:

ΔP = F/A = 1.5 N/4.909×10^-5 m^2 = 3.057×10^4 Pa

Now we can solve for the depth using the pressure equation:

ΔP = ρgh

h = ΔP/(ρg) = (3.057×10^4 Pa)/(1.03×10^3 kg/m^3 × 9.81 m/s^2) ≈ 3.02 m

Therefore, the eardrum can be damaged when scuba diving at a depth of approximately 3.02 meters in seawater.

The total resistance in the circuit is 30 ohms. Option d is correct.

In an electric circuit, resistors can be connected in different ways, such as in series or parallel. When resistors are connected in series, the total resistance is equal to the sum of the individual resistances. This is because the same current flows through each resistor, and the total voltage across the resistors is divided among them.

The resistances in series is the sum of all resistances. The three resistances are, 10 ohms, 15 ohms and 5 ohms. Therefore,

Total Resistance = 10 ohms + 15 ohms + 5 ohms = 30 ohms.

Hence, option d is correct.

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The frequency of red light having wavelength 650nm in vacuum is 4.6 x 10¹⁴ Hz.

The frequency of light can be calculated using the formula:

frequency = speed of light / wavelength

In vacuum, the speed of light is approximately 3 x 10⁸ m/s.

Converting the wavelength to meters: 650 nm = 650 x 10⁻⁹ m

Plugging these values into the formula, we get:

frequency = (3 x 10⁸ m/s) / (650 x 10⁻⁹ m) = 4.6 x 10¹⁴ Hz

Therefore, the frequency of red light with a wavelength of 650nm in vacuum is 4.6 x 10¹⁴ Hz.

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The minimum stopping distance of the car is determined as 8 m.

The minimum stopping distance of the car is calculated as follows;

d = (u²)/(2a)

where;

when the minimum stopping distance = 2 m, initial velocity = 40 km/hr = 11.11 m/s

2 = (11.11²)/(2a)

a = (11.11²)/(2 x 2)

a = 30.86 m/s²

when the speed becomes 80 km/h, the minimum stopping distance is calculated as;

u = 80 km/h = 22.22 m/s

d = (22.22² )/ (2 x 30.86)

d = 8 m

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The net force on particle q₂ is 1.05 x 10¹³ N, directed towards particle q1.

To find the net force on particle q₂, we need to calculate the force between q₁ and q₂, and the force between q₂ and q₃, and then add these two forces together.

The force between two point charges can be calculated using Coulomb's law, which states that

F = k × q₁× q₂ / r²

where F is the force, k is Coulomb's constant (9.0 x 10⁹ N m² / C²), q₁ and q₂ are the magnitudes of the charges, and r is the distance between the charges.

The force between q₁ and q₂ is

F₁ = k × q₁ × q₂ / r₁²

where r₁ = 0.10 m.

Substituting the values, we get

F₁ = 9.0 x 10⁹ N m² / C²  × 8.0 C  × 3.5 C / (0.10 m)² = 2.52 x 10¹³ N

The force between q₂ and q₃ is

F₂ = k  × q₂  × q₃ / r₂²

where r₂ = 0.15 m.

Substituting the values, we get

F₂ = 9.0 x 10⁹ N m² / C²  × 3.5 C  × (-3.5 C) / (0.15 m)² = -1.47 x 10¹³ N

Note that the negative sign indicates that the force is attractive, since q₂ and q₃ have opposite signs.

The net force on q₂ is the vector sum of F₁ and F₂

[tex]F_{net}[/tex] = F₁ + F₂ = 2.52 x 10¹³ N - 1.47 x 10¹³ N = 1.05 x 10³ N

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The angle of the free surface relative to the horizontal direction after deceleration is approximately 20.2 degrees.

Let's assume that the tank has a mass of m, the angle of the inclined surface is θ, and the height of the inclined surface is h. The initial kinetic energy of the tank is given by:

KE = (1/2)mv²

where v is the initial velocity of the tank. When the tank reaches the top of the inclined surface, its potential energy is given by:

PE = mgh

where g is the acceleration due to gravity (9.81 m/s²). Since there is no change in the total energy of the system (tank + water), we can equate the initial kinetic energy to the final potential energy:

(1/2)mv² = mgh

Solving for v, we get:

v = √(2gh)

When the tank decelerates with an acceleration of a, its velocity decreases at a rate of a m/s². The time taken for the tank to come to a complete stop is given by:

t = v/a

The distance traveled by the tank during this time is:

s = (1/2)at²

[tex]=\dfrac{1}{2} (\dfrac{v}{a})^2a = \dfrac{v^2}{2a}[/tex]

The angle of the free surface relative to the horizontal direction after deceleration is given by:

[tex]\theta' = tan^{-1}\dfrac{s}{h}[/tex]

Substituting the values of v and s, we get:

[tex]\theta' = tan^{-1}\dfrac{\sqrt{2gh}^2}{2ah}\\\\ = tan^{-1}\dfrac{2h}{3a}[/tex]

Substituting the given values of h and a, we get:

[tex]\theta' = tan^{-1}\dfrac{2(9.81)sin(15)}{3.83}\\ = 20.2[/tex]

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The minimum stopping distance is determined as 8 m.

The minimum stopping distance of the car is calculated as follows;

d = (u²)/(2a)

where;

when the minimum stopping distance = 2 m, initial velocity = 40 km/hr = 11.11 m/s

2 = (11.11²)/(2a)

a = (11.11²)/(2 x 2)

a = 30.86 m/s²

when the speed becomes 80 km/h, the minimum stopping distance is calculated as;

u = 80 km/h = 22.22 m/s

d = (22.22² )/ (2 x 30.86)

d = 8 m

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Ocean tides are caused by the gravitational pull of the Moon and the Sun. The moon has the strongest effect on the tides. When the Sun, Moon, and Earth are in a straight line, we have spring tides. When the Sun, Moon, and Earth are at right angles, we have neap tides. Spring tides are especially high tides while neap tides are especially low tides.

Ocean tides are caused by the gravitational pull of the moon and the sun on the Earth's oceans. The moon has a greater effect on tides than the sun because it is closer to the Earth.

When the Sun, moon, and Earth are in a straight line, we have higher high tides and lower low tides, which are called spring tides.

When the Sun, moon, and Earth are at right angles, we have less extreme tides, which are called neap tides.

Spring tides occur during a full moon and a new moon, while neap tides occur during a first quarter and a third quarter moon. Spring tides are especially strong tides because the gravitational pull of the moon and the sun are working together to pull the oceans in the same direction. Neap tides are weaker tides because the gravitational pull of the moon and the sun are working against each other, which leads to a lesser tidal range.

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The child's speed at the lowest point is 5.42 m/s.

At the highest point of the swing, the child is momentarily at rest and has only potential energy. At the lowest point, the child has only kinetic energy.

Using the conservation of mechanical energy, we can write:

Potential energy at highest point = Kinetic energy at lowest point

mgh = (1/2)mv²

where m is the mass of the child, g is the acceleration due to gravity, h is the height of the swing at the highest point, and v is the speed of the child at the lowest point.

First, we need to find the height of the swing at the highest point. Since the swing is supported by two chains, the height of the swing at the highest point is half the length of the chains:

h = (1/2)3.00 m = 1.50 m

Next, we can solve for the child's speed at the lowest point:

mgh = (1/2)mv²

40.0 kg * 9.81 m/s² * 1.50 m = (1/2) * 40.0 kg * v²

588 J = 20.0 kg * v²

v² = 29.4 m²/s²

v = 5.42 m/s

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The sacrifice involved in making one decision over another  is known as opportunity cost.

The opportunity cost of a choice is described as  the value of the best alternative forgone where, given limited resources, a choice needs to be made between several mutually exclusive alternatives.

When talking about an opportunity cost, it is referred to as those benefits that exist when making a decision which  could either be in business or a personal decision.

The law of increasing opportunity cost sates that as you increase the production of one good, the opportunity cost to produce the additional good will increase . It is always recommended to make a cost-benefit analysis to contemplate all the benefits.  

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#complete question:

What is the sacrifice involved in making one decision over another ?

1. The terrestrial planets experience quakes; the gas giants do not. 4.Terrestrial planets experience tectonic activity; gas giants do not.

6. Activity in molten interior of the terrestrial planets results in tectonic activity. Correct options are: 1, 4, 6.

Terrestrial planets, such as Earth, Mars, and Venus, have a solid surface that is broken into several pieces called tectonic plates. Gas giants like Jupiter and Saturn, on  other hand, do not have a solid surface and, therefore, do not experience quakes. For example, is responsible for the formation of mountains, ocean basins, and other geological features. Heat generated by decay of radioactive elements within Earth's core causes convection currents, which move the tectonic plates around. Hence Correct answer: 1,4,6.

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--The complete Question is, Which statements accurately compare the tectonic activity of the planets?

Check all that apply.

1. The terrestrial planets experience quakes; the gas giants do not.

2. The gas giants have multiple plates; the terrestrial planets do not.

3. The gas giants have no true surfaces, so they experience tectonic activity.

4. Terrestrial planets experience (or experienced) tectonic activity; gas giants do (or did) not. 5. Mountains and volcanoes are found on the gas giants, not on terrestrial planets.

6. Activity in the molten interior of the terrestrial planets results (or resulted) in tectonic --

According to the George Washington Carver quotation, most mistakes are the result of those who prefer to find reasons not to take responsibility for their acts.

To put it another way, people who find reasons to blame others instead of accepting responsibility for their own failings and making changes tend to deflect blame from themselves. The remark implies that taking personal responsibility and being accountable for one's actions are essential for success, even when there may be instances where external forces do contribute to failures. Overall, although this remark may be viewed as a generalization, it does emphasize the need of accepting responsibility for one's actions and attempting to solve challenges rather than finding reasons to blame others.

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Information technology has greatly impacted the economy, leading to increased productivity, efficiency, and innovation across industries.

The widespread adoption of information technology in the business world has led to a significant transformation in the way companies operate. Through the use of computers, software, and other digital tools, businesses are now able to streamline their operations, automate processes, and access vast amounts of data that can inform decision-making.

This has resulted in increased productivity, efficiency, and cost savings for companies. Additionally, information technology has facilitated the rise of new industries, such as e-commerce and digital marketing, while also enabling existing industries to adapt and innovate in response to changing market conditions.

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--The complete question is, How has information technology impacted the economy?--

A mercury barometer gives the local atmospheric pressure as 750 mmHg, then the absolute pressure of carbon dioxide is 89.87 kPa.

A vacuum gage indicates that the pressure of carbon dioxide in a closed tank is −10 kPa. A mercury barometer gives the local atmospheric pressure as 750 mmHg.

To determine the absolute pressure of carbon dioxide, we need to add the atmospheric pressure to the pressure indicated by the vacuum gauge.

Converting the atmospheric pressure from mmHg to kPa

750 mmHg x (101.3 kPa / 760 mmHg) = 99.87 kPa

Absolute pressure of carbon dioxide

-10 kPa + 99.87 kPa = 89.87 kPa

Therefore, the absolute pressure of carbon dioxide is 89.87 kPa.

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The angle of the free surface relative to the horizontal direction after deceleration is approximately 20.2 degrees.

Let's assume that the tank has a mass of m, the angle of the inclined surface is θ, and the height of the inclined surface is h. The initial kinetic energy of the tank is given by:

KE = (1/2)mv²

where v is the initial velocity of the tank. When the tank reaches the top of the inclined surface, its potential energy is given by:

PE = mgh

where g is the acceleration due to gravity (9.81 m/s²). Since there is no change in the total energy of the system (tank + water), we can equate the initial kinetic energy to the final potential energy:

(1/2)mv² = mgh

Solving for v, we get:

v = √(2gh)

When the tank decelerates with an acceleration of a, its velocity decreases at a rate of a m/s². The time taken for the tank to come to a complete stop is given by:

t = v/a

The distance traveled by the tank during this time is:

s = (1/2)at²

[tex]=\dfrac{1}{2} (\dfrac{v}{a})^2a = \dfrac{v^2}{2a}[/tex]

The angle of the free surface relative to the horizontal direction after deceleration is given by:

[tex]\theta' = tan^{-1}\dfrac{s}{h}[/tex]

Substituting the values of v and s, we get:

[tex]\theta' = tan^{-1}\dfrac{\sqrt{2gh}^2}{2ah}\\\\ = tan^{-1}\dfrac{2h}{3a}[/tex]

Substituting the given values of h and a, we get:

[tex]\theta' = tan^{-1}\dfrac{2(9.81)sin(15)}{3.83}\\ = 20.2[/tex]

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The terminal velocity of the sphere is approximately 22.68 mph.

The terminal velocity of a sphere is the constant speed at which the gravitational force pulling the sphere down is balanced by the drag force pushing the sphere up. The drag force is proportional to the velocity of the sphere, and can be calculated using the following formula:

Fd = (1/2) * rho * Cd * A * v²

where Fd is the drag force, rho is the density of the fluid (air in this case), Cd is the drag coefficient (which depends on the shape of the object), A is the cross-sectional area of the object perpendicular to the direction of motion, and v is the velocity of the object.

The gravitational force pulling the sphere down is given by:

Fg = m * g

where m is the mass of the sphere and g is the acceleration due to gravity.

At terminal velocity, the drag force is equal in magnitude to the gravitational force, so:

Fd = Fg

Substituting the expressions for Fd and Fg and solving for v, we get:

v = √((2 * m * g) / (rho * Cd * A))

where A = pi * r² is the cross-sectional area of the sphere, and r is the radius of the sphere.

Plugging in the given values, we get:

v = sqrt((2 * 0.6 * 9.81) / (1.2 * 0.47 * pi * 0.3²)) ≈ 10.13 m/s

To convert this to mph, we multiply by 2.23694:

v ≈ 22.68 mph

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Increasing the voltage delivered to an electric motor is one approach to get it to spin more quickly.

Increasing the voltage will result in a greater magnetic field being produced by the motor, which will then result in a stronger torque being applied to the rotor. The rotor will spin more quickly as a result because the motor's speed and torque are inversely related.

It is crucial to remember that raising the voltage above the motor's recommended voltage can cause overheating and motor damage.

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The wavelength of the wave in the spring is 0.357 m.

Wavelength is the length of a complete revolution of a wave.

To calculate the wavelength of the wave in the spring, we use the formula below

Formula:

Where:

From the question,

Given:

Substitute these values into equation 1 and solve for λ

Hence, the wavelength is 0.357 m.

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Answer:

It will be same as the length of arc

Explanation:

See we can see that the magnitude of force is equal to the magnitude of the arc so it is equal

A student measured the length of a wire four times using a meter rule, then average length will be 18.55 cm

A student measured the length of a wire four times using a meter rule and obtained the following reading 18.6,18.5,18.6,18.5.

To determine the length of the wire, we need to calculate the average of the four measurements.

Wadding up all the readings and dividing by the number of readings.

Average length = (18.6 + 18.5 + 18.6 + 18.5) / 4

Average length = 74.2 / 4

Average length = 18.55 cm

Therefore, the length of the wire is approximately 18.55 cm.

The question is incomplete and the complete question is

'' A student measured the length of a wire four times using a meter rule and obtained the following readings: 18.6 cm; 18.5 cm and 18.6 cm. Determine the length the length the student should record''.

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The charge required for the fixed point charge is approximately [tex]4.8032 * 10^{-10} C[/tex].

The electrostatic force between the fixed point charge and the electron is equal in magnitude to the gravitational force between the electron and the Earth, so we can set these two forces equal to each other and solve for the charge of the fixed point charge.

Electrostatic force between two point charges is given by Coulomb's law:

[tex]F = k * q1 * q2 / r^2[/tex]

The gravitational force between two masses is given by Newton's law of gravitation:

[tex]F = G * m1 * m2 / r^2[/tex]

Setting these two forces equal to each other and solving for q2, we get:

[tex]k * q1 * q2 / r^2 = G * m_e * m\_earth / r^2[/tex]

Solving for q2, we get:

[tex]q2 = G * m_e * m\_earth / k[/tex]

Substituting the given values, we get:

[tex]q2 = (6.67430 * 10^{-11} N * m^2 / kg^2) *\\ (9.10938356 *10^{-31} kg) *\\ (5.9722 *10^{24} kg) / (8.98755 * 10^9 N * m^2 / C^2)[/tex]

[tex]q2 = 4.8032 * 10^{-10} C[/tex]

Therefore, the charge required for the fixed point charge is approximately [tex]4.8032 * 10^{-10}[/tex]C.

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The numbers of minutes that were played in a men's Water Polo match is option A: four 7-minute quarters

A water polo game for men comprises of four quarters with each one spanning for 8 minutes of effective play time. Between the initial and subsequent quarters, there is a breather of two minutes, followed by a halftime of five minutes, and then a two-minute interlude between the third and fourth quarters.

The clock ceases to tick during breaks, upon scoring a goal, when the ball is beyond the limits, or when the referee whistles for an offense. The overall duration of a men's water polo game can fluctuate based on the number of interruptions that take place during the match.

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