Which of the following is NOT TRUE about food irradiation?
O It is practiced around the world.
O It leaves food mildly radioactive.
It is effective in killing microorganisms.
o It destroys microorganisms without cooking.

Answers

Answer 1

Answer:

It is practiced around the world .

Answer 2

The statement, that is, food irradiation leaves food mildly radioactive is not true.  

A technology, which uses ionizing radiation to improve safety and extend the shelf life of foods by eliminating and reducing insects and microbes is known as food irradiation.  

• Irradiation is used in canning fruits and vegetables and pasteurizing milk to make food safer for consumption.  

• Irradiation does not compromise nutritional quality, makes food radioactive, or change the texture, text, or appearance of food. The effect of irradiation is so minimal that it is not easy to identify that whether the food is irradiated.  

• Food irradiation has been approved in over forty countries and is almost practiced globally.  

Thus, the statement, that is, it leaves food mildly radioactive is incorrect.  

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Related Questions

An ice skater pushes harder with her legs and begins to move faster. Which two laws best describes this

Answers

Answer:

Newton' second law  and third law describes the situation.

Explanation:

According to the Newton's second law, the force applied on a body is proportional to the rate of change of momentum of the body.

According to the Newton's third law, for every action there is an equal and opposite reaction.

When ice skater pushes harder means more force is applied so he moves fast and more be the action force more be the reaction force.

Thus, Newton' second law  and third law describes the situation.

What does the temperature of the gas between galaxies in galaxy clusters tell us about the mass of the cluster

Answers

Answer:

HEY THERE!

Explanation:

The temperature tells us the average speeds of the gas particles, which are held in the cluster by gravity, so we can use these speeds to determine the cluster mass

HAVE A GOOD DAY!

A marble is rolling across a smooth 1.2 m tall table at a velocity of 3 m/s. How far from the edge of the table does it land? (SHOW ALL OF YOUR WORK)

Answers

Answer:

S = 1/2 g t^2      where t is the time to fall 1.2 m

t = (2 S / g)^1/2 = (2 * 1.2 / 9.8) = .495 s

Sy = Vy T = 3 m/sec  * .495  sec = 1.48 m     distance from edge of table

(Rotational speed has no effect since table is smooth)

help help help please please​

Answers

Answer:

below

Explanation:

that is the procedure above

Please help it's for a test.

A car of mass 1000kg is traveling 30m/s

a) What is the kinetic energy?

b) How high will it have to travel up a hill to have the same potential as kinetic energy as this speed? Remember Ep-Ek

Answers

Answer:

Explanation:

[tex]KE=\frac{1}{2}mv^2[/tex] so filling in:

[tex]KE=\frac{1}{2}(1000)(30)^2[/tex] so to 2 sig figs (which is actually not accurate, but oh well...)

KE = 450000 J

If we want to find out how high it will have to travel up a hill so that its PE is the same as the KE at this speed, we set the value for KE = to PE:

450000 = (1000)(9.8)h so

[tex]h=\frac{450000}{(1000)(9.8)}=45.9m[/tex]

Students were having a catapult contest, launching a tennis ball with their home built devices. The winner launched a ball at 30 degrees from the ground at 6.0 m/s. How high does the ball go?

Answers

Answer:

The height reached by the ball=0.459 m

Explanation:

We are given that

[tex]\theta=30^{\circ}[/tex]

Initial speed, u=6 m/s

We have to find the maximum height reached by ball.

Maximum height reached by ball

[tex]h=\frac{u^2sin^2\theta}{2g}[/tex]

Where [tex]g=9.8m/s^2[/tex]

Substitute the values

[tex]h=\frac{6^2sin^230^{\circ}}{2\times 9.8}[/tex]

[tex]h=\frac{36\times \frac{1}{4}}{2\times 9.8}[/tex]

[tex]h=0.459 m[/tex]

Hence, the height reached by the ball=0.459 m


[tex]explain \: \\ \\ how \: rainbow \: form \: {?}[/tex]

Answers

Answer:

A rainbow is caused by sunlight and atmospheric conditions. Light enters a water droplet, slowing down and bending as it goes from air to denser water. The light reflects off the inside of the droplet, separating into its component wavelengths--or colors. When light exits the droplet, it makes a rainbow.


[tex]what \: is \: reflection \: of \: light \: \: \: \: {?}[/tex]

Answers

Answer:

When a ray of light approaches a smooth polished surface and the light ray bounces back, it is called the reflection of light. The incident light ray which lands upon the surface is said to be reflected off the surface. The ray that bounces back is called the reflected ray.

An object is moving with an initial velocity of 9 m/s. It accelerates at a rate of 1.5 m/s2
over a time of 20 s. What is its new velocity?

Answers

Answer:

39 m/s²

Explanation:

initial Velocity (u) = 9m/s

acceleration (a) = 1.5m/s²

time(t) = 20s

V=u + at

V=9 + 1.5(20)

V=9 + 30

V=39m/s

your initial speed is zero. if you increased your speed by 4 m/s after only 2 seconds and continue to accelerate at the same rate, what will your speed be after 10 seconds?

Answers

Answer:

20 m/ s

Explanation:

change in velocity = 4m/ s

[tex]acceleration = \frac{rate \: of \: change \: of \: velocity}{time} [/tex]

[tex]acc = \frac{4}{2} \\ = 2[/tex]

initial velocity = 0m/ s

let velocity after 10s be v

[tex]2 = \frac{v - 0}{10} [/tex]

cross multiplying

[tex]20 = v[/tex]

so the velocity after 10s will be 20m/s

Determine the amount of potential energy of a 4.2 kg book that is placed on a shelf with a height of 0.9 meters. Round your answer to one decimal place​

Answers

Answer:

that is a correct answer maybe .

action and reaction are equal in magnitudeand opposite in direction then why do they not balance each other ?​

Answers

Because they act on different objects.

Beginning at the synapse of a neuron, place the events in neuronal signaling in the correct sequence.1. Ion channels bind the ligand and open.2. Na+ is pumped out of the cell, and the membrane potential is restored.3. Acetylcholinesterase breaks down acetylcholine.4. Na+ enters the postsynaptic cell, and the membrane potential changes.5. Acetylcholine is released into the synapse.6. Na+ ion channels close.A. 3, 4, 6, 1, 5, 2B. 5, 1, 4, 3, 6, 2C. 4, 5, 1, 2, 6, 3D. 1, 2, 3, 4, 5, 6E. 6, 4, 3, 1, 2, 5

Answers

Answer:

B. 5, 1, 4, 3, 6, 2

Explanation:

Acetylcholine (ACh) is a molecule that functions as a neurotransmitter and plays diverse roles in brain and muscle function. Ach is released by the presynaptic neurons into the synaptic cleft. The nicotinic acetylcholine receptors are ACh ligand-gated ion channels located at the postsynaptic membrane which admit both sodium (Na+) and potassium (K+) ions. These receptors bind ACh, increasing the permeability of the postsynaptic membrane to Na+ and K+ ions. In consequence, ion channels open and sodium (Na+) ions enter the postsynaptic cell, causing the postsynaptic membrane to depolarize. An enzyme known as acetylcholinesterase breaks down acetylcholine into acetate and choline. If depolarization passes a threshold potential, an action potential is generated in the postsynaptic membrane. The generation of a postsynaptic potential at the excitatory synapse is known as excitatory postsynaptic potential. Once depolarization is complete, Na+ channels close and membrane permeability to Na+ ions declines to the resting levels.

asset question.....only answers otherwise u will be reported ​

Answers

Answer:

C. 24 hrs

Explanation:

it takes the earth 24 hrs to make one full revolution.

Find the sum. Express the answer in scientific notation. (1.54 x 10^6)+(6.15 x 10^6)​

Answers

Answer:

[tex] { \tt{(1.54 \times {10}^{6}) + (6.15 \times {10}^{6}) }} \\ = { \tt{(1.54 + 6.15) \times {10}^{6} }} \\ = { \tt{7.69 \times {10}^{6} }}[/tex]

A car moving east at a velocity of 16.0 m/s collides with a stationary truck with exactly twice the mass. If the two vehicles lock together, calculate the velocity of their combined mass immediately after collision

Answers

Answer:

5.33ms-¹

Explanation:

that is the procedure above

What process forms the Mid-Atlantic Ridge?
A. Radioactive decay
B. Seafloor spreading
C. Radiometric dating
D. Sediment formation

Answers

Answer:

B. seafloor spreading

Explanation:

divergent motion between the Eurasian and North American, and African and South American Plates. ... In this way, as the plates move further apart new ocean lithosphere is formed at the ridge and the ocean basin gets wider

geological society

how much does a car weighr if each tyre cover of 4cm^2 and exert a pressure of 100000Nm^-2 on the ground it is physics questions ​

Answers

Answer:

Weight = 160 N

Explanation:

The weight of an object is a measure of the gravitational force on the object. So that weight is synonymous to the force applied by the object.

i.e Weight = mass x gravitational force

Also, the pressure of an object is the ratio of its force to area covered by the object. So that;

P = [tex]\frac{F}{A}[/tex]

Given that: area = 4 [tex]cm^{2}[/tex] (0.0004 [tex]m^{2}[/tex]), and pressure = 100 000 N[tex]m^{-2}[/tex].

Then;

F = PA

  = 100 000 N[tex]m^{-2}[/tex] x 0.0004 [tex]m^{2}[/tex]

F = 40 N

The force applied on the ground by each of the four tyres of the car is 40 N.

Thus, the weight of the car = 4 x 40 N

                                     = 160 N

Which of the following best distinguishes the relationship between applied research and basic research?

A Applied research commercializes the discoveries of basic research and brings them to the general public.
B Basic research takes place in academia, and complex research takes place in industry.
C Basic research provides fundamental knowledge that can be used to conduct applied research.
D Applied research is not published for peer review, but basic research must be.

Answers

Answer:

C. Basic research provides fundamental knowledge that can be used to conduct applied research.

Explanation:

Applied research is used to solve practical and specific problems. Basic research is used to advance theories and scientific knowledge; it might not result in an invention or a solution, but can be used to gain knowledge about a specific subject.

A. A
B. C
C. D
D. B
HELLLP GUYS!!!

Answers

Answer:

B

Explanation:

One type of atomic particle that is found in the nucleus does not contribute to
an element's atomic number. What are two characteristics of this type of
atomic particle?

Answers

Answer:

1) They are electrically neutral

2) They have slightly more weight than protons

Explanation:

The given atomic particle found in the nucleus has the following characteristics;

The location of the particle = The nucleus

The (numbers of the) particle does not contribute to (change) the atomic number of the element

The particles found within the nucleus of an atom are; Neutrons and protons

The particle within the nucleus that determines the atomic number = The number of protons

Therefore, the particle referenced in the question is the neutrons

The two characteristics of the neutron are;

1) The neutrons are neutral, electrically

2) Neutrons have slightly more weight than protons

3) Neutrons are magnetic

4) Neutrons are very small

5) Neutrons consist of three quarks; One 'Up', and two 'Down' quarks

Therefore, two characteristics of the particle are;

1) They are electrically neutral and 2) They are slightly heavier than protons.

Priya is responsible for collecting canned food along three different streets for her school's annual Thanksgiving Food Drive. She walks 300 m [N] along Oak Road, 500 m [E] along Second Street, and then 150 m [S45°W] along Cross Ave. She completes the journey in 10 minutes.Calculate her total distance, displacement, speed, and velocity.

Answers

Good luck sorry don’t know the answer

As per the details given, Priya's total distance traveled is 950 meters, displacement is approximately 410.52, speed is 95 meters per minute, and velocity is 41.05 meters per minute.

To calculate Priya's total distance:

Total distance = 300 m + 500 m + 150 m = 950 m

So, Priya's total distance traveled is 950 meters.

To calculate Priya's displacement, we need to find the straight-line distance and direction from her starting point to her ending point.

Displacement = √((Δx)² + (Δy)²)

For Δx:

Δx = 500 m - 150 m × cos(45°)

Δx = 500 m - 150 m × 0.707

Δx = 500 m - 106.05 m

Δx = 393.95 m

For Δy:

Δy = 150 m × sin(45°)

Δy = 150 m × 0.707

Δy = 106.05 m

Displacement = √((393.95 m)² + (106.05 m)²)

Displacement ≈ 410.52 m

So, Priya's displacement is approximately 410.52 meters in a direction of approximately N36°W.

To calculate Priya's speed, we use the formula:

Speed = Total distance ÷ Time

Speed = 950 m ÷ 10 min

Speed = 95 m/min

So, Priya's speed is 95 meters per minute.

To calculate Priya's velocity:

Velocity = Displacement ÷ Time

Velocity = 410.52 m ÷ 10 min

Velocity = 41.05 m/min

Thus, Priya's velocity is 41.05 meters per minute in a direction of N36°W.

For more details regarding velocity, visit:

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a trampoline launches a 50kg person 2m into the air. if the springs push with 1960N of force, how much displacement was there in the trampoline

Answers

Answer: 0.5 m

Explanation:

Given

Mass of the person is [tex]m=50\ kg[/tex]

Trampoline launches the person into the air up to height of [tex]h=2\ m[/tex]

Force experience by springs is [tex]F=1960\ N[/tex]

Here, the work done on displacing the springs is equivalent to the Potential energy acquired by the person i.e.

[tex]\Rightarrow F\cdot x=mgh\quad [\text{x=displacement of the trampoline}]\\\\\text{Insert the values}\\\\\Rightarrow x=\dfrac{50\times 9.8\times 2}{1960}\\\\\Rightarrow x=\dfrac{980}{1960}\\\\\Rightarrow x=0.5\ m[/tex]

Answer:

0.5

Explanation:

what is chemical change ??​

Answers

Answer:

the combination,decomposition or replacement that occurs in the molecules of matter during chemical change called chemical reaction

Answer:

A chemical change happens when one chemical substance is transformed into one or more different substances, such as when iron becomes rust. ... A chemical change is different from a physical change, which doesn't rearrange atoms or molecules and produce a completely new substance.

A 5.0 kg box moving at 2.0 m/s on a horizontal, frictionless surface runs into a light horizontal spring of force constant 85 N/cm. Use the work-energy theorem to find the maximum compression of the spring.

Answers

Answer:

x = 4.85 cm

Explanation:

From work energy theorem when dealing with a spring in compression, we know that total work done is;

W_t = ½kx²

Where;

k is Force constant

x is max compression

Now, we know that this is also equal to the kinetic energy.

K.E = ½mv²

Thus;

½kx² = ½mv²

Making x the subject;

x = √(mv²/k)

We are given;

m = 5 kg

v = 2 m/s

k = 85 N/cm = 8500 N/m

Thus;

x = √(mv²/k)

x = √(5 × 2²/8500)

x = 0.0485 m

x = 4.85 cm

A 5.0 kg block of ice is at rest at the top of a smooth inclined plane. The block is released and slides 2.0 m down the plane. Assuming there is no friction between the block and the surface, calculate
a) the gravitational potential energy at the top of the plane
b) the component of the weight parallel to the plane
c) the acceleration of the block
d) the velocity of the block at the bottom of the plane
e) the kinetic energy at the bottom of the plane. ​

Answers

Answer:

a) 98.1 Joules

b) 49.05 N × sin(θ)

c) 9.81 × sin(θ)

d) The velocity of the block at the bottom of the plane, v is approximately 6.264 m/s

e) 98.1 Joules

Explanation:

The given parameters of the block are;

The mass of the block, m = 5.0 kg

The distance down the plane the block slides, h = 2.0 m

The friction between the block and the surface = 0

Let θ represent the angle of inclination oof the plane

a) The gravitational potential energy, P.E. = m·g·h

Where;

g = The acceleration due to gravity ≈ 9.81 m/s²

∴ P.E. ≈ 5.0 kg × 9.81 m/s² × 2.0 m = 98.1 Joules

The gravitational potential energy, P.E. ≈ 98.1 Joules

b) The component of the weight of the block parallel to the plane, [tex]w_{\parallel}[/tex], is given as follows;

[tex]w_{\parallel}[/tex] = w × sin(θ) = m·g·sin(θ)

∴ [tex]w_{\parallel}[/tex] ≈ 5.0 kg × 9.81 m/s² × sin(θ) = 49.05 × sin(θ) N

The component of the weight of the block parallel to the plane, [tex]w_{\parallel}[/tex] ≈ 49.05 N × sin(θ)

c) The component of the weight along the inclined plane = The force with which the block moves along the inclined plane, therefore;

[tex]w_{\parallel}[/tex] = m·g·sin(θ) = m·a

Where a represents the acceleration of the block along the plane

Therefore, by comparison, we have;

g·sin(θ) = a

∴ a ≈ 9.81 × sin(θ)

d) Given that the motion of the block is 2.0 m downwards, we have;

The velocity of the block at the bottom of the plane, v² = 2·g·h

Therefore, v² ≈ 2 × 9.81 m/s²× 2.0 m = 39.24 m²/s²

v = √(39.24 m²/s²) ≈ 6.264 m/s

e) The kinetic energy at the bottom of the plane, K.E. = (1/2)·m·v²

∴ K.E. = (1/2) × 5.0 kg × 39.24 m²/s² = 98.1 J

How does work affect energy between objects so it can cause a change in the form of energy?

A. Work transfers energy.
B. Work changes energy.
C. Work increases energy.
D. Work decreases energy.

Answers

D. Work decreases energy

Answer the question plz

Answers

Answer:

b and d

Explanation:

An instrument rated pilot is planning a flight under IFR on July 10, this year. Before conducting the flight, the pilot must have

Answers

Answer: See explanation

Explanation:

From the information given, we are informed that an instrument rated pilot is planning a flight under IFR on July 10, this year.

It should be noted that before conducting the flight, the pilot must have performed and logged the prescribed tasks and repetitions that are required for instrument currency no earlier than January, 10 for the year.

A car moving along a racetrack has a centripetal acceleration of 11.3 m/ s2. If the speed of the car is 30.0 m/s, what is the distance between the car and the center of the track?

Answers

Answer:

Explanation:

The formula for centripetal acceleration is

[tex]a_c=\frac{v^2}{r}[/tex] and filling in:

[tex]11.3=\frac{(30.0)^2}{r}[/tex] and solving for r:

[tex]r=\frac{(30.0)^2}{11.3}[/tex] gives us that

r = 79.6 m

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