Answer:
its b there circle e not oval
Explanation:
The shape of elliptical galaxies is ellipsoid and not oval shape. They contain more older stars and formation of new stars is hard in the case of elliptical galaxies. Hence, the statement which is not true is options B and D.
What is galaxy?Galaxy is a group of stars, dust and dark matter which are joined together by a force of gravitation. There are billions of galaxies in the universe and they each contains trillions of stars.
The galaxies are of different shapes, force and light. Spiral, elliptical, oval etc are some of them. The light energy and gravitational pull of each of these galaxies differ from each other. The galaxie near to earth is milky way.
The elliptical galaxies are mainly composed of older stars and dust. They have a shape of ellipsoid. Formation of new stars in ellipsoid galaxies is rare. Thus options B and D are not true.
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which of the following compounds would you expect to be soluble in water? select all that apply: nh4f agcl agno3 mgso4
The compounds NH4F, AgNO3, and MgSO4 are anticipated to be soluble in water. It is anticipated that AgCl won't dissolve in water.
We need to take into account the solubility laws for common ionic compounds in order to predict which compounds would be soluble in water.
Ammonium fluoride, or NH4F, is a substance that dissolves in water. The majority of ammonium (NH4+) salts, including NH4F, are soluble.
Silver chloride (AgCl) cannot be dissolved in water. Silver chloride is an exception to the rule that most metals' chlorides (Cl-) are soluble.
AgNO3: Water is soluble in silver nitrate (AgNO3). The majority of nitrates (NO3-), including silver nitrate, are soluble.
Magnesium sulphate (MgSO4) is water soluble. Most metal sulphates (SO4-) are soluble, including the sulphate of magnesium.
NH4F, AgNO3, and MgSO4 are examples of soluble substances according to the solubility laws.
AgCl is an insoluble substance.
According to the solubility principles for typical ionic compounds, NH4F, AgNO3, and MgSO4 should all be soluble in water. Contrarily, AgCl is not soluble in water. By taking into account the solubility regulations for each of their individual ions, it is possible to establish these compounds' solubility.
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a solution is prepared by mixing 25 ml pentane (, ) with 53 ml hexane (, ). assuming that the volumes add on mixing, calculate the mass percent, mole fraction, molality, and molarity of the pentane.
To calculate the mass percent, mole fraction, molality, and molarity of pentane in the solution, we need to consider the volumes and densities of the components.
By using the given volumes of pentane and hexane and their respective densities, we can determine the masses of the substances.
From there, we can calculate the mass percent of pentane, the mole fraction of pentane, the molality of pentane, and the molarity of pentane in the solution.
Mass percent of pentane:
Mass of pentane = volume of pentane * density of pentane
Mass of hexane = volume of hexane * density of hexane
Mass percent of pentane = (mass of pentane / total mass of solution) * 100
Mole fraction of pentane:
Moles of pentane = mass of pentane / molar mass of pentane
Moles of hexane = mass of hexane / molar mass of hexane
Mole fraction of pentane = moles of pentane / (moles of pentane + moles of hexane)
Molality of pentane:
Mass of pentane in kg = mass of pentane / 1000
Molality of pentane = moles of pentane / mass of pentane in kg
Molarity of pentane:
Volume of pentane in L = volume of pentane / 1000
Molarity of pentane = moles of pentane / volume of pentane in L
By substituting the given volumes, densities, and molar masses of pentane and hexane into the above equations, we can calculate the desired values for the pentane solution.
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Aluminum sulfate (Al2(SO4)3) is an iron-based coagulant that is used during water and wastewater treatment to enhance removal of solids. You may assume that when ferric chloride is added to water the following reaction occurs: Al2(SO4)2 AI3 +3 SO,2
a. How much aluminum sulfate is required (in grams) to prepare 500 mL of 3,000 mg/L Al2(SO4)3 solution?
b. How much aluminum sulfate is required (in grams) to prepare 500 mL of 3,000 mg/L Al2(SO4)3 solution if the aluminum sulfate chemical stock is 73% pure?
c. What is the aluminum (Al) concentration (in mg/L) in the solution? d. What is the sulfate (SO4) concentration (in mg/L) in the solution?
To prepare a 500 mL solution with a concentration of 3,000 mg/L of Al2(SO4)3, the amount of aluminum sulfate needed depends on its purity.
Assuming the aluminum sulfate is 100% pure, approximately 15 g of aluminum sulfate is required. However, if the aluminum sulfate is 73% pure, the required amount would be approximately 20.5 g. The aluminum concentration in the solution would be 6,000 mg/L, and the sulfate concentration would be 9,000 mg/L.
a. To calculate the amount of aluminum sulfate needed for a 500 mL solution with a concentration of 3,000 mg/L, we can use the formula:
Mass (g) = Volume (L) x Concentration (mg/L) / Purity (%)
Assuming the aluminum sulfate is 100% pure, the calculation would be:
Mass = 0.5 L x 3,000 mg/L = 1,500 mg = 1.5 g
Therefore, approximately 1.5 g of aluminum sulfate is required.
b. If the aluminum sulfate is 73% pure, we need to adjust the calculation as follows:
Mass = 0.5 L x 3,000 mg/L / 0.73 = 2,054 mg = 2.054 g
Therefore, approximately 2.054 g of aluminum sulfate is required.
c. The aluminum concentration in the solution can be determined by dividing the mass of aluminum sulfate by the volume of the solution:
Aluminum concentration = Mass (g) / Volume (L) = 1.5 g / 0.5 L = 3,000 mg/L
Thus, the aluminum concentration in the solution is 3,000 mg/L.
d. The sulfate concentration can be calculated by multiplying the concentration of aluminum sulfate by the number of sulfate ions in one molecule of Al2(SO4)3:
Sulfate concentration = Aluminum concentration x 3 = 3,000 mg/L x 3 = 9,000 mg/L
Hence, the sulfate concentration in the solution is 9,000 mg/L.
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What are the 3 parts of an atoms?
Answer: Protrons Electrons and Nuetrons
Explanation:
A. Describe the spectrum you would observe for the emission spectrum of elemental hydrogen gas.
B. Describe the spectrum you would observe for the absorption spectrum of elemental hydrogen gas.
A. The emission spectrum of elemental hydrogen gas consists of discrete colored lines.
B. The absorption spectrum of elemental hydrogen gas shows dark lines superimposed on a continuous spectrum.
A. The emission spectrum of elemental hydrogen gas would consist of discrete and distinct lines of colored light, known as the hydrogen emission lines or the Balmer series. These lines correspond to specific energy transitions of electrons within the hydrogen atoms. The visible portion of the spectrum would include several bright lines, such as red, blue-green, and violet, indicating the emission of photons at those specific wavelengths.
B. The absorption spectrum of elemental hydrogen gas would show dark lines, known as absorption lines or the Balmer series, superimposed on a continuous spectrum. The dark lines correspond to the specific wavelengths of light that have been absorbed by hydrogen atoms as electrons transition from lower energy levels to higher ones.
The absorption spectrum would exhibit missing or attenuated regions of certain wavelengths, indicating the absorption of photons by the hydrogen gas at those particular energies.
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valence electrons and a full
Noble gases are not reactive because they have
outer shell.
A).8
B).4
C).2
D).6
what is the theoretical yield of sodium chloride for the reaction of 50.2 g na with 63.0 g cl2 ?what is the theoretical yield of sodium chloride for the reaction of 50.2 with 63.0 ?208 g nacl 128 g nacl 51.9 g nacl 104 g nacl
The balanced equation for the reaction between sodium and chlorine gas is:2 Na(s) + Cl2(g) → 2 NaCl(s)Given, mass of Na = 50.2 gMass of Cl2 = 63.0 gTo find out the theoretical yield of sodium chloride, we need to first find out the limiting reagent. The t limiting reagen is the reactant that gets completely consumed and limits the amount of product formed.
The other reactant that is not the limiting reagent is called the excess reagent.Let's calculate the amount of NaCl formed if Na is the limiting reagent:From the balanced equation,2 moles of Na reacts with 1 mole of Cl2 to give 2 moles of NaCl.The molar mass of Na is 23 g/mol.The molar mass of Cl2 is 71 g/mol.So, 50.2 g of Na is equal to 50.2 g / 23 g/mol = 2.18 moles of Na.63.0 g of Cl2 is equal to 63.0 g / 71 g/mol = 0.887 moles of Cl2. From the balanced equation,2 moles of Na requires 1 mole of Cl2. So, the reaction will consume 2 × 0.887 = 1.77 moles of Na.So, Na is the limiting reagent and Cl2 is the excess reagent.Now, let's find out the amount of NaCl formed if Na is the limiting reagent. From the balanced equation,2 moles of Na reacts with 1 mole of Cl2 to give 2 moles of NaCl.So, 1.77 moles of Na will react with 0.885 moles of Cl2 to give 1.77 moles of NaCl.The molar mass of NaCl is 58.5 g/mol.So, the mass of NaCl formed = 1.77 mol × 58.5 g/mol = 103.45 gNaClHence, the theoretical yield of NaCl for the reaction of 50.2 g Na with 63.0 g Cl2 is 103.45 g NaCl (main answer).
Option D (104 g NaCl) is close to the theoretical yield but not correct as the calculations done above show that the theoretical yield is 103.45 g NaCl.
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When you mix two gases what can you predict about the conservation of volume in this case? Hydrogen gas burns in the presence of oxygen gas to form liquid water. What can you say about the volume and mass conservation in this chemical reaction?
"When two gases are mixed, the conservation of volume depends on the conditions under which the mixing occurs. If the gases are ideal gases and the mixing process is ideal, the total volume of the mixture will be equal to the sum of the individual volumes of the gases before mixing."
This is known as the ideal gas law, which states that the volume of a gas is directly proportional to the number of gas molecules present, assuming constant temperature and pressure.
However, it's important to note that under non-ideal conditions, such as high pressures or low temperatures, gases can deviate from ideal behavior, and the conservation of volume may not hold exactly.
Regarding the chemical reaction where hydrogen gas burns in the presence of oxygen gas to form liquid water, the conservation of volume may not be directly applicable. This is because the reaction involves a change in state from gases (hydrogen and oxygen) to liquid (water). During this chemical reaction, the volume of the gases will decrease as they are consumed, and the volume of the liquid water formed will depend on the conditions (temperature and pressure) under which the reaction occurs.
However, mass is conserved in a chemical reaction. According to the law of conservation of mass, the total mass of the reactants will be equal to the total mass of the products. In the case of hydrogen gas burning in the presence of oxygen gas to form liquid water, the total mass of the hydrogen and oxygen gases will be equal to the total mass of the water formed.
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how many grams of nh3 can be produced from 4.09 mol of n2 and excess h2 . express your answer numerically in grams.
To determine the mass of ammonia (NH₃) that can be produced from 4.09 mol of nitrogen gas (N₂) and excess hydrogen gas (H₂), we need to consider the balanced chemical equation for the reaction between N₂ and H₂ to form NH₃.
The balanced chemical equation for the reaction is:
N₂ + 3H₂ → 2NH₃
From the balanced equation, we can see that for every 1 mole of N₂, we obtain 2 moles of NH₃.
Convert the moles of N₂ to moles of NH₃:
Moles of NH₃ = 2 * Moles of N₂
Moles of N₂ = 4.09 mol
Moles of NH₃ = 2 * 4.09 mol
Convert the moles of NH₃ to grams:
To convert moles to grams, we need to multiply the moles by the molar mass of NH₃.
Molar mass of NH₃ = 17.03 g/mol
Mass of NH₃ = Moles of NH₃ * Molar mass of NH₃
= (2 * 4.09 mol) * 17.03 g/mol
Performing the calculation:
Mass of NH₃ = (2 * 4.09) * 17.03 = 138.67 g
Therefore, approximately 138.67 grams of NH₃ can be produced from 4.09 mol of N₂ and excess H₂.
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A pH of about 5 or less is an _____ environment.
Group of answer choices
acidic
alkaline
basic
neutral
Oxygen was a 'poisonous gas' for early _____ _____organisms in Earth's history.
Group of answer choices
reptile-type
mammalian-type
aerobic type
anaerobic type
A pH of about 5 or less is an acidic environment. Oxygen was a 'poisonous gas' for early anaerobic-type organisms in Earth's history.
A pH of about 5 or less indicates an acidic environment. In the pH scale, values below 7 are considered acidic, with lower values indicating stronger acidity. A pH of 5 or less signifies a relatively high concentration of hydrogen ions (H+) in a solution, which is characteristic of acidic conditions.
In the second statement, it is mentioned that oxygen was a 'poisonous gas' for early anaerobic-type organisms in Earth's history. This refers to organisms that do not require oxygen for their survival and metabolism. During the early stages of Earth's history, the atmosphere had little to no oxygen, and the dominant organisms were anaerobic in nature. Oxygen, being highly reactive, posed a toxic threat to these anaerobic organisms. They were not adapted to deal with the presence of oxygen and lacked the necessary enzymes and metabolic pathways to utilize it effectively.
As a result, oxygen was considered harmful or even poisonous for these early anaerobic organisms. It was only later, with the emergence of oxygenic photosynthesis and the evolution of aerobic organisms, that oxygen became a vital component of the Earth's ecosystems.
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Question 4
1 pts
How many neutrons are in the atom shown in this symbol?
19
9
19
09
Answer:
there are 19 neutrons
What intermolecular forces are present between two molecules of HI? A) dispersion only B) &pole-dipole only C) hydrogen bonding only D) dispersion and dipole-dipole E) dispersion and hydrogen bonding
The intermolecular forces present between two molecules of HI (hydrogen iodide) are dispersion forces (also known as London dispersion forces). Therefore, the correct answer is A) dispersion only.
Dispersion forces are the weakest type of intermolecular forces and occur between all molecules, regardless of their polarity. These forces result from temporary fluctuations in electron distribution, leading to the formation of temporary dipoles. In the case of HI, both hydrogen and iodine atoms have electrons that are constantly in motion, causing temporary imbalances in electron distribution and resulting in the formation of temporary dipoles.
The hydrogen iodide (HI) molecule consists of a hydrogen atom bonded to an iodine atom. Hydrogen has a relatively positive charge due to its low electronegativity, while iodine has a relatively negative charge due to its high electronegativity. This polarity within the molecule gives rise to a dipole-dipole interaction between HI molecules. However, in this case, the dipole-dipole interaction is not strong enough to be considered a significant intermolecular force.
Instead, the dominant intermolecular force between HI molecules is dispersion forces. Dispersion forces occur due to temporary fluctuations in electron distribution. In the case of HI, the movement of electrons creates temporary dipoles, resulting in attractive forces between neighboring molecules. Since dispersion forces are present between all molecules, regardless of their polarity, they are the primary intermolecular force in HI. Other intermolecular forces such as hydrogen bonding or dipole-dipole interactions are not significant in HI molecules.
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HELP ME PLEASE!!!
(1)Enter the symbol of the element which would have 36 electrons and -1 charge.
(2)Enter the symbol of the element which would have 0 electrons and +1 charge.
Answer:
Br (Bromine)
H (Hydrogen)
Explanation:
How did the first DNA formed
Answer:
organic molecules were synthesized in the beginnings of earth and rained down into the oceans. RNA and DNA molecules are just long chains of simple nucleotides that can live in hazardous conditions
Which is NOT an example of ways pants engage with abiotic factors?
A: plants get eaten by animals
B: plants use sunlight
C: plants require water
D: plants use carbon dioxide
Plants require water is not an example of ways pants engage with abiotic factors. Therefore, the correct option is option C.
What are biotic and abiotic?An ecosystem has two parts: biotic and abiotic. An ecosystem is a group of coexisting living and non-living things. An ecosystem's biotic and abiotic components are what distinguish it from other ecosystems. One either a biotic or abiotic component can have an impact on the entire system.
As a result, abiotic factors control how long organisms can survive inside an ecosystem. The primary distinction between biotic as well as abiotic would be that biotic denotes all living organisms within an ecosystem, and abiotic denotes all inorganic, chemical, and physical elements. Plants require water is not an example of ways pants engage with abiotic factors.
Therefore, the correct option is option C.
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Sarah performs an experiment to see whether bees prefer red flowers or yellow flowers. Look at this table of results from the experiment.
What is the independent variable in this investigation?
A. time
B. color of flower
C. total number of bees
D. number of bees at each flower
Answer:
B.) Color of Flower
Explanation:
Took the test and got it right :)
Convert:
129 cm^3 to liters
Answer:
[See Below]
Explanation:
[tex]Hey~There![/tex]
________________________
→ Conversion:
[tex]1 ~cm=1000~liters[/tex]→ Write out an equation:
[tex]129*1000=129000[/tex]________________________
→ So your answer would be:
[tex]129000~liters[/tex]________________________
[tex]Hope~this~helps![/tex]
[tex]-Shane,~SpamIsTheMan :)[/tex]
a 0.50 gram sample of agcl(s) is shaken with 5.0 ml of 6.0 m nh3 until there is no more net reaction. what product is formed?
When a 0.50 gram sample of AgCl(s) is shaken with 5.0 mL of 6.0 M NH3 until there is no more net reaction, the product formed is tetraammine silver(I) chloride [Ag(NH3)4]Cl.
However, it is worth noting that in the beginning, AgCl(s) and NH3 react to form
Ag(NH3)2+(aq) and Cl-(aq) ions.
The reaction is as follows:AgCl(s) + 2NH3(aq) → [Ag(NH3)2]+(aq) + Cl-(aq)
At equilibrium, the reaction goes in the reverse direction with the forward reaction, thereby producing tetraammine silver(I) chloride [Ag(NH3)4]Cl.
[Ag(NH3)2]+(aq) + 2NH3(aq) + Cl-(aq) → [Ag(NH3)4]Cl(s)
Hence, the product formed is tetraammine silver(I) chloride [Ag(NH3)4]Cl.
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What is the approximate energy of a photon having a frequency of 4 x 10
^7 Hz (E = vxh, h= 6.6x 10^-34 JxSec) *
Answer:
E = 26.4 × 10⁻²⁷ j
Explanation:
Given data:
Frequency of photon = 4×10⁷ Hz
Energy of photon = ?
Planck's constant = 6.6 × 10⁻³⁴ js
Solution:
Formula:
E = h × v
v = frequency
Now we will put the values in formula.
E = 6.6 × 10⁻³⁴ js × 4×10⁷ Hz
Hz = s⁻¹
E = 26.4 × 10⁻²⁷ j
The energy of photon is 26.4 × 10⁻²⁷ j.
Answer: I think it’s 3 x 10 ^-27 J, I’m sorry if it wrong
Explanation:
What is the frequency of a light wave with a wavelength of 4.28 x 10-7 m?
Answer:
Frequency of light is 0.701×10¹⁵ Hz
Explanation:
Given data:
Frequency of light = ?
wavelength of light = 4.28×10⁻⁷m
Solution:
Formula:
Speed of light = wavelength × frequency
c = λ × f
f = c/λ
This formula shows that both are inversely related to each other.
The speed of light is 3×10⁸ m/s
Frequency is taken in Hz.
It is the number of oscillations, wave of light make in one second.
Wavelength is designated as "λ" and it is the measured in meter. It is the distance between the two crust of two trough.
Now we will put the values in formula.
f = 3×10⁸ m/s / 4.28×10⁻⁷m
f = 0.701×10¹⁵ s⁻¹
s⁻¹ = Hz
f = 0.701×10¹⁵ Hz
which of the following pure substances has an unusually high normal boiling point? which of the following pure substances has an unusually high normal boiling point? hcl ch3och3 ch3sh ch3cl ch3nh2
The pure substance that has an unusually high normal boiling point among the given options is ch3nh2. The boiling point is the temperature at which the vapor pressure of a liquid equals the external pressure surrounding the liquid.
A pure substance is one that is made up of only one type of atom or molecule, such as ch3nh2. The boiling point of a substance is determined by the intermolecular forces that exist between its molecules.In ch3nh2, the nitrogen atom has a lone pair of electrons that causes hydrogen bonding to occur between its molecules. As a result, the intermolecular forces in ch3nh2 are stronger than those in the other pure substances listed. This means that more energy is required to separate ch3nh2 molecules from each other during boiling, resulting in a higher boiling point. In terms of intermolecular forces, hydrogen bonding is stronger than the dipole-dipole, dispersion, and van der Waals forces present in the other listed substances. Thus, ch3nh2 has an unusually high boiling point due to hydrogen bonding.The normal boiling point of ch3nh2 is about 95°C, while the boiling points of the other pure substances range from -23.8°C to -10°C (ch3cl) and -24.8°C (ch3och3). As a result, ch3nh2 has a boiling point that is much higher than that of the other pure substances.
Thus, the pure substance that has an unusually high normal boiling point among the given options is ch3nh2, and this is due to the hydrogen bonding that occurs between its molecules.
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A chemistry grad student measures the performance Z of the new pump in his lab. The result is: Z=2.2 kPa.mm?:5-1 Convert Z to mJ's-1 I) m).5-1 x 6 ?
The performance of the new pump, Z, is approximately 1.32 mJ's⁻¹ when converted from kPa.mm⁻¹.
To convert Z from kPa.mm⁻¹ to mJ's⁻¹, we need to consider the units and their conversions.
1 kPa = 1000 Pa (pascals)
1 mm = 0.001 m (meters)
1 mJ = 0.001 J (joules)
1 J = 1 N.m (newton-meter)
Therefore, we can convert Z from kPa.mm⁻¹ to mJ's⁻¹ as follows:
Z (in mJ's⁻¹) = Z (in kPa.mm⁻¹) x (1000 Pa / 1 kPa) x (0.001 m / 1 mm) x (0.001 J / 1 mJ) x (1 N.m / 1 J)
Substituting the given value of Z = 2.2 kPa.mm⁻¹ into the conversion equation:
Z (in mJ's⁻¹) = 2.2 x 1000 x 0.001 x 0.001 x 1 ≈ 2.2 mJ's⁻¹
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12. Dylan has been convicted of assault on a police officer and sentenced to two-years incarceration. In what facility will Dylan MOST II O O O detention facility
treatment center
county jail
prison
Dylan will most likely be incarcerated in a prison facility for his two-year sentence for assaulting a police officer (option a).
1. Dylan has been convicted of assault on a police officer: This indicates that Dylan has been found guilty of committing assault against a law enforcement officer.
2. Dylan has been sentenced to two-years incarceration: The court has decided that Dylan should serve a prison sentence for a duration of two years as a consequence of his crime.
3. In what facility will Dylan most likely be detained? The question seeks to determine the type of facility where Dylan will serve his sentence.
4. Detention facility: This term is a general reference to any location where individuals are held in custody. However, it does not specify the type of facility in this particular case.
5. Treatment center: While treatment centers exist for rehabilitation purposes, they are not typically the primary facilities for incarcerating individuals convicted of assault on a police officer.
6. County jail: County jails are usually used for shorter-term sentences or pretrial detention. Since Dylan's sentence is for two years, it is unlikely that he would be held in a county jail for such a long duration.
7. Prison: Given the seriousness of Dylan's crime and the length of his sentence, it is most likely that he will be sent to a prison facility. Prisons are designed to house individuals serving long-term sentences, and they provide a higher level of security compared to county jails.
Therefore, the most appropriate facility for Dylan's incarceration would be a prison facility.
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ch. 17, 92. the solubility of copper(i) chloride, cucl, is 3.91 mg per 100.0 ml of solution. calculate ksp for cucl.
The molar mass of CuCl is 98.98 g/mol. We first need to calculate the molar solubility of CuCl in mol/L to use in our expression for Ksp.
The solubility of CuCl is 3.91 mg per 100.0 ml of solution. We can convert this to mol/L as follows:
3.91 mg CuCl / 1000 mg/g
= 0.00391 g
CuCl98.98 g/mol
= 3.95 x 10^-5 mol
CuCl / 0.1 L
solution = 3.95 x 10^-4 M CuCl This means the molar solubility of CuCl is 3.95 x 104 M.
Using this information, we can write an expression for the Ksp of CuCl:
CuCl (s) ⇌ Cu+ (aq) + Cl- (aq)Ksp = [Cu+][Cl-]
Since CuCl dissolves to produce Cu+ and Cl-, the equilibrium concentrations of these ions are equal to the molar solubility of 3.95 x 104 M. Therefore, we can plug this value into our expression for Ksp:
Ksp = (3.95 x 10^-4)2 = 1.56 x 10^-7
Therefore, the Ksp for CuCl is 1.56 x 107.
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The constant pressure molar heat capacity of argon is 20.79 J K−1 mol−1 at 298 K. Predict the value of the constant volume
The predicted value of the constant volume molar heat capacity of argon at 298 K is 12.476 J K⁻¹ mol⁻¹.
The value of the constant volume molar heat capacity of argon at 298 K can be predicted using the relationship between constant volume and constant pressure molar heat capacities.
The relationship between constant volume (\(C_v\)) and constant pressure (\(C_p\)) molar heat capacities is given by the equation:
\[C_p - C_v = R\]
Where \(R\) is the gas constant. In this case, we are given the value of \(C_p\) for argon at 298 K, which is 20.79 J K⁻¹ mol⁻¹.
To find the value of \(C_v\), we need to substitute the given values into the equation. The gas constant \(R\) can be expressed as:
\[R = C_p - C_v\]
Rearranging the equation, we can solve for \(C_v\):
\[C_v = C_p - R\]
Substituting the values, we have:
\[C_v = 20.79 \, \text{J K⁻¹ mol⁻¹} - R\]
The value of the gas constant \(R\) is 8.314 J K⁻¹ mol⁻¹.
\[C_v = 20.79 \, \text{J K⁻¹ mol⁻¹} - 8.314 \, \text{J K⁻¹ mol⁻¹}\]
Simplifying the equation:
\[C_v = 12.476 \, \text{J K⁻¹ mol⁻¹}\]
Therefore, the predicted value of the constant volume molar heat capacity of argon at 298 K is 12.476 J K⁻¹ mol⁻¹.
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How do doctors use the scientific method
Answer:
By first asking themselves or others about what they are experiencing, and also by doing the experiment by looking at the person and seeing what is wrong with them. They use a hypothesis to determine later how/what has affected the person in any way.
Explanation:
please give brainlyest
Answer:
Students, and sometimes even teachers, often think scientists only use the scientific method to answer science-related questions. In fact, you can apply the scientific method to almost any problem. The key is to use the elements (steps) to reduce bias and help come to a solution to the problem.
Explanation:
Alana summarized what happens when a ball sitting on top of a grassy hill rolls down the hill.
The motionless ball has potential energy. Once the ball starts to roll down the hill, new kinetic energy is made. As the ball rolls across the grass, it slows down. The kinetic energy of the ball is converted to other forms of energy.
Which best describes Alana’s error?
Kinetic energy isn't made it is converted.
Answer:
Kinetic energy is not made; it is a result of energy transformation.
Explanation:
From the half-life for 14 C decay, 5715 yr, calculate the age of the shroud. Express your answer using two significant figures.
X divided by 5715 equals 4.8, it means that 4.8 half-lives have passed. Multiplying 4.8 by 5715 gives us an age of approximately 27,432 years (rounded to two significant figures).
To calculate the age of the shroud using the half-life of 14C, we need to determine how many half-lives have passed. Since each half-life is 5715 years, we can divide the age of the shroud by the half-life to find the number of half-lives. Then, multiplying the number of half-lives by the half-life will give us the age of the shroud. The half-life of 14C is 5715 years, which means that after 5715 years, half of the 14C atoms in a sample will have decayed. The process of decay is exponential, so after another 5715 years, half of the remaining 14C atoms will decay, leaving only one-fourth of the original amount. This pattern continues with each successive half-life.
To calculate the age of the shroud, we need to determine the number of half-lives that have passed. We can do this by dividing the age of the shroud by the half-life of 14C. Let's assume the age of the shroud is X years. If X divided by 5715 gives us n, then n is the number of half-lives that have occurred. Next, we multiply the number of half-lives (n) by the half-life (5715 years) to find the total time that has passed. This will give us the age of the shroud.
For example, if we find that X divided by 5715 equals 4.8, it means that 4.8 half-lives have passed. Multiplying 4.8 by 5715 gives us an age of approximately 27,432 years (rounded to two significant figures). Therefore, by using the half-life of 14C and the number of half-lives that have passed, we can estimate the age of the shroud.
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which is not a noble gas?
a)argon
b) helium
c) nitrogen
d) krypton
can someone answer this for me
Answer:
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