which of the following is the graph of the inequality below?.

a. To calculate the Euclidean distances between the three pairs of facilities, we use the formula:

d = sqrt((x2 - x1)^2 + (y2 - y1)^2)

where (x1, y1) and (x2, y2) are the coordinates of the two points. Calculating the Euclidean distances:

dAB = sqrt((51 - 26)^2 + (59 - 16)^2) ≈ 47.39 miles

dBC = sqrt((36 - 51)^2 + (41 - 59)^2) ≈ 23.53 miles

dAC = sqrt((36 - 26)^2 + (41 - 16)^2) ≈ 25.00 miles

b. To calculate the rectilinear distances, we use the formula:

d = |x2 - x1| + |y2 - y1|

Calculating the rectilinear distances:

dAB = |51 - 26| + |59 - 16| = 25 + 43 = 68 miles

dBC = |36 - 51| + |41 - 59| = 15 + 18 = 33 miles

dAC = |36 - 26| + |41 - 16| = 10 + 25 = 35 miles

Therefore, the Euclidean distances are approximately dAB = 47.39 miles, dBC = 23.53 miles, and dAC = 25.00 miles. The rectilinear distances are dAB = 68 miles, dBC = 33 miles, and dAC = 35 miles.

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Answer:

z = 46/13

Step-by-step explanation:

Step 1: Write equation

z + 6 ÷ 13 = 4

Step 2: Solve for z

Step 3: Check

Plug in z to verify it's a solution.

46/13 + 6/13 = 4

52/13 = 4

4 = 4

Answer:

To find the center of the given equation of a circle, we first need to rewrite it in the standard form:

x² + y² + 8x = 2x - 20y - 105

x² + 8x + y² = 2x - 20y - 105

Completing the square for the x terms:

(x² + 8x + 16) + y² = 2x - 20y - 105 + 16

(x + 4)² + y² = 2x - 20y - 89

Now we can see that the equation is in the standard form:

(x - (-4))² + (y - 0)² = r²

where the center of the circle is (-4, 0) and the radius squared is:

r² = 2x - 20y - 89

Note that the center of the circle can be found by taking the negative of the coefficients of x and y in the completed square terms and reversing their signs. In this case, the completed square term for x is (x + 4)², so the x-coordinate of the center is -4. The completed square term for y is y², so the y-coordinate of the center is 0.

The non-dimensional surface temperature of a sphere with a Biot number of 8 and a non-dimensional centerline temperature of 0.29 is approximately 2.32.

The non-dimensional surface temperature of a sphere can be determined using the Biot number and the non-dimensional centerline temperature. The Biot number is a dimensionless quantity that represents the ratio of internal thermal resistance to external thermal resistance.

The relationship between the non-dimensional surface temperature (θ) and the Biot number (Bi) is given by the following equation:

θ = θ_s/ θ_c

Given that the Biot number (Bi) is 8 and the non-dimensional centerline temperature (θ_c) is 0.29, we can rearrange the equation to solve for the non-dimensional surface temperature (θ).

θ = Bi × θ_c

θ = 8 × 0.29

θ ≅ 2.32

Therefore, the non-dimensional surface temperature of a sphere with a Biot number of 8 and a non-dimensional centerline temperature of 0.29 is approximately 2.32.

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Answer:the sector is 280°

Step-by-step explanation:

The equation is 4 meatballs for every adult and 3 for every child. Replace a and c and solve:

M = 4(20) + 2(8)

M = 80 + 16

M = 96

They need 96 meatballs.

Answer: F(2)=20 means the total cost or the amount if money you spent at the movies after buying a ticket and buying 2 items at the concession stand.

Explanation: One ticket is $12 and if each item is $4, then in order to get to a total of $20, then you would need 2 items, since 2 x $4 = $8, and that plus $12 is $20.

I hope this helps!

Answer:

see explanation

Step-by-step explanation:

The given angles are adjacent and supplementary, thus

149 + 13x + 5 = 180

154 + 13x = 180 ( subtract 154 from both sides )

13x = 26 ( divide both sides by 13 )

x = 2

Thus

13x + 5 = 13(2) + 5 = 26 + 5 = 31°

Answer:

The cost of one pecan cheesecake is $12 and

the cost of 1 chocolate marble cheesecake is 13$

Step-by-step explanation:

Let the cost of one pecan cheesecake be x

And the cost of one chocolate marble cheesecake be y

Now, James sold 12 pecan cheesecakes and 1 chocolate marble cheesecake for $157, we represent this as,

12x + y = 157 (i)

And, Amanda sold 3 pecan cheesecakes and 5 chocolate marble cheesecake for $101, we represent this as,

3x + 5y = 101  (ii)

now, we just need to solve these two equations to get the amounts,

since 12x + y = 157

y = 157 - 12x

putting value of y in (ii)

3x + 5(157-12x) = 101

3x +785 - 60x = 101

-57x + 628 = 101

-57x = 101 - 785

-57x = -684

multiplying by -1 on both sides,

57x = 684

x = 684/57

x = 12

Now, finding y using, y = 157 - 12x

since x = 12,

y = 157 - (12)(12)

y = 157 - 144

y = 13

So, the cost of one pecan cheesecake is $12 and the cost of 1 chocolate marble cheesecake is 13$

The quantitative variables that can be identified from the problem are Median age of town, Average weekly sales, and Median income of town.

The units for Median age of town is years, Average weekly sales is dollars, and Median income of town is dollars.The remaining options City, Whether or not the store sells liquor, Type of food, and Town area have not specified the units and therefore are not quantitative variables. Quantitative variables are variables that are measured on a numerical scale. The problem in this question provides a list of options and asks to select the options that identify quantitative variables and specify their units. The following quantitative variables can be identified from the problem:Median age of town: Median age of town is a quantitative variable since it is measured in years. The median age of the town is the middle value of the ages of the population of the town. The unit for median age is years since it is a numerical scale that represents the age of the population in years.Average weekly sales: Average weekly sales is a quantitative variable since it is measured in dollars. The average weekly sales represent the mean sales of a store over a week, which can be calculated by dividing the total sales by seven. The unit for average weekly sales is dollars since it is a numerical scale that represents the currency value of sales.Median income of town: Median income of town is a quantitative variable since it is measured in dollars. The median income of the town is the middle value of the income of the population of the town. The unit for median income is dollars since it is a numerical scale that represents the income value of the population.

The units of quantitative variables are essential as they provide a measure of the scale of the variable. In this problem, the quantitative variables identified were Median age of town, Average weekly sales, and Median income of town. The units of these variables are years, dollars, and dollars, respectively. The remaining options do not specify the units and hence cannot be classified as quantitative variables.

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a b e  your welcome

Write your question here. We can't read your mind. Yet.

Write your question here. We can't read your mind. Yet.

The fencing that will be required for the rectangular plot is: 162 m

The formula to find the perimeter of a rectangle is:

Perimeter = 2(Length + Width)

Now, we are told that each of the three rectangular plots measure 20m by 11m and as such, if we have 3 meters between each plot and also the boundary of the plot, then we can say that:

Length of Plot = 3 + 11 + 3 + 11 + 3 + 11 + 3 = 45 m

Width of plot = 20 + 3 + 3 = 26 m

Thus:

Fencing required = 2(45 + 36)

Fencing required = 2 * 81

Fencing required =  162 m

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lemme think ill brb

Step-by-step explanation:

The reflective properties of conic sections can be exploited in various applications, such as focusing light or radio waves, enhancing signal reception, and designing optical systems. Each conic section exhibits unique reflective characteristics based on the arrangement of its foci and the shape of the curve.

Let's discuss the reflective properties of the three conic sections: parabola, ellipse, and hyperbola.

Parabola:

Reflective Property: A parabola has a single focus point, located either above or below the vertex. Any ray of light parallel to the axis of symmetry of the parabola will reflect off the curve and pass through the focus point.

Application: This property of the parabola makes it useful in designing reflective surfaces, such as satellite dishes or car headlights, where incoming parallel light rays are focused at a single point.

Ellipse:

Reflective Property: An ellipse has two foci, located at the two foci points on the major axis. When a ray of light enters the ellipse, it reflects off the inner surface of the curve, obeying the law of reflection. The angle of incidence is equal to the angle of reflection.

Application: The reflective property of the ellipse is utilized in applications such as astronomy, where elliptical mirrors are used in telescopes to focus light from distant celestial objects onto a focal point.

Hyperbola:

Reflective Property: A hyperbola has two foci, one on each branch of the curve. When a ray of light enters one branch of the hyperbola, it reflects off the inner surface of the curve, obeying the law of reflection. The angle of incidence is equal to the angle of reflection.

Application: The reflective property of the hyperbola finds applications in antenna design, specifically in satellite dishes and radio telescopes. The hyperbolic shape allows incoming waves to be focused or directed towards a specific point or receiver.

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Answer:

gsugaqsgsuguwsqsw

Step-by-step explanation:

wshwsbgshswswswsw f word you

The extracted volume of component C is 18.0 milliliters.

To find the extracted volume of component C, we need to calculate 90% of the original volume of component C in the liquid mixture.

Given that the volume of component C in the liquid mixture is 20.0%, and the original volume is the same as the volume in the mixture, we can set up the following equation:

Extracted volume of component C = 0.9 * (20.0% of the total volume of the liquid mixture)

To calculate the total volume of the liquid mixture, we need to find the sum of the percentages of all components:

Total volume = Volume of component A + Volume of component B + Volume of component C + Volume of component D

= 10.0% + 25.0% + 20.0% + 45.0% = 100.0%

Now we can substitute the values into the equation:

Extracted volume of component C = 0.9 * (20.0% of 100.0 mL)

= 0.9 * (0.2 * 100.0 mL) = 0.9 * 20.0 mL = 18.0 mL

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Answer:

x = 70

Step-by-step explanation:

The angles are same side interior angles and when the lines are parallel same side interior angles are supplementary

45+ (2x-5) = 180

Combine like terms

2x +40 = 180

Subtract 40 from each side

2x+40-40 =180-40

2x = 140

Divide by 2

2x/2 = 140/2

x = 70

x = 70

Answer:

200 dollars

Step-by-step explanation:

Answer:

$200

Step-by-step explanation:

To calculate the percentage taken off of the price, multiply 250 by 0.2. You should get 50. Now, just subtract that from 250 to get 200.

The equation that represents the table is y = 1/4x - 2.

To determine which equation represents the given table, we can examine the values of x and y in the table and compare them to the equations provided.

Looking at the table:

x: -4, 0, 4

y: -3, -2, -1

We can plug these values into each equation and see which equation gives us the corresponding y-values.

For equation (1): y = 1/4x - 2

-3 = 1/4(-4) - 2 => -3 = -1 - 2 => -3 = -3 (true)

-2 = 1/4(0) - 2 => -2 = 0 - 2 => -2 = -2 (true)

-1 = 1/4(4) - 2 => -1 = 1 - 2 => -1 = -1 (true)

For equation (2): y = -1/4x + 4

-3 = -1/4(-4) + 4 => -3 = 1 + 4 => -3 = 5 (false)

-2 = -1/4(0) + 4 => -2 = 0 + 4 => -2 = 4 (false)

-1 = -1/4(4) + 4 => -1 = -1 + 4 => -1 = 3 (false)

For equation (3): y = 4x - 2

-3 = 4(-4) - 2 => -3 = -16 - 2 => -3 = -18 (false)

-2 = 4(0) - 2 => -2 = 0 - 2 => -2 = -2 (true)

-1 = 4(4) - 2 => -1 = 16 - 2 => -1 = 14 (false)

We can see that only equation (1) satisfies all the given x and y values in the table. The equation that represents the table is y = 1/4x - 2.

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The Value of the printing equipment after 7 years is approximately $3,145.73.

From the given table, we can observe that the values of the printing equipment form a geometric sequence. Let's denote the first term of the sequence as a1 and the common ratio as r.

From the table, we have the following information:

a1 = 12,000

a2 = 9,600

a3 = 7,680

To find the common ratio, we can divide any term by its preceding term:

r = a2/a1 = 9,600/12,000 = 0.8

Alternatively, we can also calculate:

r = a3/a2 = 7,680/9,600 = 0.8

Now that we have the first term (a1 = 12,000) and the common ratio (r = 0.8), we can use the formula for the nth term of a geometric sequence to find the value of the printing equipment after 7 years.

The formula for the nth term (an) of a geometric sequence is:

an = a1 * r^(n-1)

Substituting the values, we have:

a7 = 12,000 * 0.8^(7-1)

a7 = 12,000 * 0.8^6

Evaluating this expression, we find:

a7 ≈ 12,000 * 0.262144

a7 ≈ 3,145.73

Therefore, From the given table, we can observe that the values of the printing equipment form a geometric sequence. Let's denote the first term of the sequence as a1 and the common ratio as r.

From the table, we have the following information:

a1 = 12,000

a2 = 9,600

a3 = 7,680

To find the common ratio, we can divide any term by its preceding term:

r = a2/a1 = 9,600/12,000 = 0.8

Alternatively, we can also calculate:

r = a3/a2 = 7,680/9,600 = 0.8

Now that we have the first term (a1 = 12,000) and the common ratio (r = 0.8), we can use the formula for the nth term of a geometric sequence to find the value of the printing equipment after 7 years.

The formula for the nth term (an) of a geometric sequence is:

an = a1 * r^(n-1)

Substituting the values, we have:

a7 = 12,000 * 0.8^(7-1)

a7 = 12,000 * 0.8^6

Evaluating this expression, we find:

a7 ≈ 12,000 * 0.262144

a7 ≈ 3,145.73

Therefore, the value of the printing equipment after 7 years is approximately $3,145.73.

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TQR

T, R

RQS and SQR

I might be wrong but if I am don't rank 1 star and beat me up

Hope this helps :)

Good luck

Answer:

k=1/2

Step-by-step explanation:

A direct variation equation has the form

Answer:

x² - 5x + c = 0

x = (5 + √(25 - 4c))/2

difference of roots = √(25 - 4c) = 1/4

25 - 4c = 1/16

-4c = -399/16

c = 399/64

It is indeed possible for it to take more than k pivots to find a "real" BFS when using the Big M method, where k is the number of artificial variables introduced.

If the reduced cost of all non-basic variables is strictly ≥0, it does not necessarily mean that the current basic feasible solution (BFS) is optimal. The reduced cost of a variable represents the amount by which the objective function value would improve if that variable were included in the current BFS. When the reduced cost is ≥0 for all non-basic variables, it indicates that there is no incentive to include any of those variables in the current BFS as they would not contribute to improving the objective function.

However, it is still possible that the current BFS is not optimal. There could be other feasible solutions that have a lower objective function value, and these solutions might involve changing the current set of basic variables. To determine optimality, additional criteria need to be considered, such as the feasibility of the solution and the optimality conditions of the linear programming problem.

When using the Big M method to find an initial basic feasible solution (BFS), it is possible that it may take more than k pivots to find a "real" basic feasible solution that includes only the variables in the original problem.

The Big M method introduces artificial variables with a large coefficient (M) in the objective function to enforce constraints during the initial phase of solving a linear programming problem. These artificial variables ensure that all constraints are satisfied and provide a starting BFS. However, these artificial variables are not part of the original problem and need to be removed to obtain a "real" BFS.

The number of pivots required to find a "real" BFS depends on the particular problem and the choice of artificial variables. It is possible that additional pivots are needed to eliminate the artificial variables and identify a feasible solution that includes only the original variables.

Therefore, it is indeed possible for it to take more than k pivots to find a "real" BFS when using the Big M method, where k is the number of artificial variables introduced.

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Answer:

42 ounces

Step-by-step explanation:

3 ounces times 2 is 6 ounces each day and 6 x7 is 42.

The maximal flow from node 1 to node 7 in the given network needs to be determined, along with identifying the associated minimal cut. Additionally, the associated linear-programming problem needs to be written.

To find the maximal flow from node 1 to node 7, various algorithms like the Ford-Fulkerson algorithm or the Edmonds-Karp algorithm can be used. These algorithms iteratively find augmenting paths and update the flow until no more augmenting paths exist. The maximal flow represents the maximum amount of flow that can be sent from the source (node 1) to the sink (node 7).

The associated minimal cut can be found by identifying the set of edges whose removal would disconnect the source from the sink. The minimal cut represents the minimum capacity required to disconnect the source and sink nodes.

To write the associated linear-programming problem, we need to define decision variables, objective function, and constraints that represent the flow network. The objective function is typically to maximize the flow from the source to the sink, subject to capacity constraints on the edges and flow conservation constraints at each node.

Detailed calculations and graph analysis would be required to find the specific maximal flow, associated minimal cut, and formulate the linear programming problem for the given network.

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Answer:

Step-by-step explanation:

The ratio of corresponding sides

Solving for x

Correct option is 110