which of the following objects is accelerating?
A.) A car driving in a circle at a constant speed of 35 mph
B.) A car driving in a northwest at a constant speed of 35 mph
C.) A car driving south at a constant speed of 45 mph
D.) A car driving southwest at a constant speed of 35 mph

Answers

Answer 1

Answer:

A

Explanation:

Constant speed (without change in direction) is not accelerating. If you are slowing down, speeding up, or changing direction, you are accelerating


Related Questions

question a hamster runs in its wheel whose radius is 3 inches. the wheel completes 6.3 revolutions in 5 seconds. what is the linear velocity of the hamster's wheel? responses approximately 3.8 inches per second approximately 3.8 inches per second approximately 7.6 inches per second approximately 7.6 inches per second approximately 23.8 inches per second approximately 23.8 inches per second approximately 66 inches per second

Answers

The linear velocity of the hamster's wheel is calculated to be as approximately 3.8 inches/second. The formula for linear velocity is Circumference ÷ time.

A hamster runs in its wheel whose radius is 3 inches. The wheel completes 6.3 revolutions in 5 seconds. We need to calculate the linear velocity of the hamster's wheel. 

The hamster's wheel completes 6.3 revolutions in 5 seconds.

The circumference of the wheel of the hamster can be calculated by using the formula,

C = 2πr, Where r is the radius of the wheel.

Circumference C = 2π × 3

= 6π inch

Linear velocity is given by the formula,

Linear velocity = Circumference ÷ time

= 6π ÷ 5

= 1.2π inch/second

= 3.76991115 inch/second

≈ 3.8 inches/second

Therefore, the linear velocity of the hamster's wheel is approximately 3.8 inches/second.

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forces with magnitudes of 250 pounds and 130 pounds act on an object at angles of and respectively, with the positive -axis. find the direction and magnitude of the resultant of these forces

Answers

The direction and magnitude of the resultant of these forces with magnitudes of 250 pounds and 130 pounds act on an object at angles of and respectively, with the positive -axis is 149.5 pounds and 53.2 degrees east of the positive -axis.

To solve the problem, we can use the parallelogram method for vector addition. We begin by breaking each force vector into its x and y components, using .cos(30) = x/250 => x = 250cos(30) = 216.5sin(30) = y/250 => y = 250sin(30) = 125cos(60) = x/130 => x = 65y/130 = sin(60) = 0.866 => y = 0.866(130) = 112.4Thus, the components of the resultant vector are:Rx = 216.5 + 65 = 281.5Ry = 125 + 112.4 = 237.4

The magnitude of the vector is:R = sqrt(Rx^2 + Ry^2) = sqrt(281.5^2 + 237.4^2) = 358.4The angle the resultant vector makes with the positive x-axis is:theta = atan(Ry/Rx) = atan(237.4/281.5) = 39.2 degrees east of the positive x-axis.The problem is rounded off to the nearest tenth, and thus, the magnitude of the resultant of these forces with magnitudes of 250 pounds and 130 pounds act on an object at angles of and respectively, with the positive -axis is 149.5 pounds and 53.2 degrees east of the positive -axis.

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One skier is going down the hill at about 15 miles per hour. His friend is also going down the hill, but is traveling at 30 miles an hour. Which skier has more kinetic energy?

Answers

Answer:

The friend has more kinetic energy

Explanation:

This person is going faster than the other.

Transition
1. A1 kg sample of liquid water and a 1 kg sample of
ice are placed on a table. Which of the following
best compares these two samples?

which has a larger volume?

Answers

Frozen water has move volume than water in liquid form

a package is dropped from a helicopter moving upward at 15 m/s. if it takes 26 s before the package strikes the ground, how high above the ground was the package when it was released if air resistance is negligible?

Answers

Given that a package is dropped from a helicopter moving upward at 15 m/s. If it takes 26 s before the package strikes the ground. We are required to find how high above the ground was the package when it was released if air resistance is negligible

Let us assume that the package was dropped from a height h above the ground.When the package is dropped, its initial velocity, u = 0Velocity of the helicopter, v = 15 m/sTime taken to strike the ground, t = 26 sAcceleration due to gravity, a = 9.8 m/s²According to the kinematic equation of motion:

We have, s = ut + 1/2 at²Here, s is the total displacement from the initial pointi.e., h = 0 + 1/2 × 9.8 m/s² × (26 s)²h = 0 + 1/2 × 9.8 m/s² × 676h = 1/2 × 9.8 m/s² × 676h = 330.4 mTherefore, the package was dropped from a height of 330.4 meters above the ground when air resistance is negligible.The main answer is the package was dropped from a height of 330.4 meters above the ground when air resistance is negligible.

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1. _____ determines the amount of force required to overcome the inertia of an object
a: weight
b: mass

Answers

Answer:

mass determines the amount of force required to overcome the inertia of an object.

This photovoltaic system, on average, produces 5500kWh of electricity per year? Assuming the panels always produce at maximum output when the sun is shining, how many hours per day, on average, does the sun shine on the panels. Hint, if you did it correctly, your answer should seem too small.

Answers

The average daily sunlight duration for the photovoltaic system is surprisingly low.

To calculate the average daily sunlight duration, we can divide the total annual electricity production (5500 kWh) by the average daily energy production. To do this, we need to convert kilowatt-hours to watts, as the panels' maximum output is likely given in watts.

Let's assume the panel's maximum output is 1000 watts. In that case, the average daily energy production would be 5500 kWh divided by 365 days, which equals approximately 15.07 kWh/day. To convert this to watts, we multiply by 1000, resulting in 15,070 watt-hours per day.

Now, to find the average daily sunlight duration, we divide the average daily energy production (15,070 watt-hours) by the panel's maximum output (1000 watts). This gives us approximately 15.07 hours per day.

However, it's important to note that this answer seems too small because it assumes the panels always produce the maximum output when the sun is shining. In reality, there are various factors that can affect the efficiency of solar panels, such as the angle of incidence, shading, and weather conditions. These factors can cause the actual sunlight duration required to generate the average daily energy production to be higher than the calculated value.

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Vector B has x, y, and z components of 2.6,
6.8, and 5 units, respectively.Calculate the magnitude of B.

Answers

Answer:

To calculate the magnitude of a vector, just find the square root of the sum of components squared.

Explanation:

so square 2.6 and add it to the square of 6.8 and then the square of five and then find the square root of that answer

What are the developmental stages according to Erikson?

Answers

Answer:

1. Trust vs. Mistrust

2. Autonomy vs. Shame

3. Initiative vs. Guilt

4. Industry vs. Inferiority

Exercise 4-B: Orographic Uplift and the Rainshadow Effect When an air mass is cooled to its dew point, it becomes saturated. Any further cooling of the air mass results in condensation, in which water vapor Question: Exercise 4-B: Orographic Uplift And The Rainshadow Effect When An Air Mass Is Cooled To Its Dew Point, It Becomes Saturated. Any Further Cooling Of The Air Mass Results In Condensation, In Which Water Vapor Changes State To Liquid Water. During Condensation, Latent Heat Is Released To The Atmosphere In The Form Of Sensible Heat (540 Calories / Gram Of
Exercise 4-B: Orographic Uplift and the Rainshadow Effect When an air mass is cooled to its dew point, it becomes saturated. Any further cooling of the air mass results in condensation, in which water vapor changes state to liquid water. During condensation, latent heat is released to the atmosphere in the form of sensible heat (540 calories / gram of water). One of the principal mechanisms of atmospheric cooling is the uplift of air masses. Because pressure decreases in the atmosphere from the surface upward, uplifted air masses expand as they rise. This expansion results in a decreased rate of collisions between air molecules, which in turn causes the air mass to decrease in temperature. A temperature decrease due to uplift of an air mass is called adiabatic cooling. Conversely, a temperature increase due to downward movement of an air mass is called adiabatic warming. The elevation at which condensation occurs during adiabatic cooling is called the lifting condensation level (LCL). It is the elevation at which the air mass is cooled to the dewpoint by adiabatic cooling. When the temperature reaches the dewpoint, the air is fully saturated and further cooling will result in condensation. One way that air masses are uplifted is by being "pushed" up over a topographic obstruction, such as a mountain range. This is referred to as orographic uplift. Remember, when air is lifted, it will cool down due to adiabatic cooling. If there is enough moisture in the air and the temperature is lowered to the dewpoint, condensation in the form of clouds and precipitation may occur. Thus, air can loose moisture as it moves over a mountain range. Often, locations on the lee side of the mountain range are very dry because of this phenomenon. We call this the rain shadow effect. This exercise allows you to calculate changes in temperature and humidity of an air mass as it passes over a mountain range and will illustrate the rain shadow effect.
The situation: An air mass over Seattle, WA has a temperature of 15°C and a dewpoint of 12°C at sea level. As it travels from west to east it is pushed up over the Cascade Mountains and then down the eastern slope toward Spokane. Use your understanding of adiabatic cooling and heating, dry and wet/moist adiabatic lapse rates and condensation to answer the following questions. Use the following rates in your calculations: DAR = 10°C / 1000 m; MAR = 6°C / 1000 m. Assume that all water condensing in the atmosphere falls as precipitation.
Please show all work
1) What is the specific humidity of the air mass at Seattle? What is its relative humidity?
2) By how many degrees must the air mass be cooled before it reaches saturation?
3) What is the elevation of the lifting condensation level? What is the air temperature, specific humidity and relative humidity at the lifting condensation level? Show your work.
4) What is the air temperature, specific humidity and relative humidity at the summit? Show your work.
5) What is the air temperature, specific humidity and relative humidity at Spokane? Show your work.
6) Why is the relative humidity lower in Spokane than in Seattle? Remember the definition of relative humidity.
7) Why is the air temperature warmer in Spokane than it is at the summit?
8) Which side of the Cascade Mountains would you expect to receive more precipitation? What term do we give to the side of the mountain that receives less precipitation as a result of orographic uplift?

Answers

1) The specific humidity of the air mass at Seattle cannot be determined without additional information.
2) The air mass must be cooled by 3 degrees Celsius to reach saturation (15°C - 12°C).
3) The elevation of the lifting condensation level (LCL) needs to be calculated using the dry adiabatic lapse rate (DAR) of 10°C/1000m. The specific humidity and relative humidity at the LCL cannot be determined without additional information.
4) The air temperature, specific humidity, and relative humidity at the summit cannot be determined without additional information.
5) The air temperature, specific humidity, and relative humidity at Spokane cannot be determined without additional information.
6) The relative humidity is lower in Spokane compared to Seattle because as air descends on the eastern slope of the mountains, it undergoes adiabatic warming, which increases its capacity to hold moisture. Therefore, the same amount of water vapor appears as a lower relative humidity.
7) The air temperature is warmer in Spokane compared to the summit because as air descends on the eastern slope of the mountains, it undergoes adiabatic warming due to compression.
8) The side of the Cascade Mountains that receives more precipitation is the windward side. The side that receives less precipitation as a result of orographic uplift is called the leeward side or the rain shadow side.

In the lab, a student collects hydrogen gas over water in a eudiometer. The hydrogen gas is produced when a piece of magnesium metal reacts with excess hydrochloric acid
Part 1: (a) Write the balanced chemical equation for this reaction. Include the states of matter. Mg(s) + 2HCl (aq) → H2(g) + MgCl2 (aq)
Part 2 out of 2 (b) How many moles of hydrogen gas are collected if 1.49 g of magnesium metal is used in the reaction?

Answers

1.49 g of magnesium metal will yield around 0.0612 moles of hydrogen gas if it is utilized in the reaction.

Part 1:

The balanced chemical equation for the reaction between magnesium metal and hydrochloric acid is:

Mg(s) + 2HCl(aq) → H₂(g) + MgCl₂(aq)

Part 2:

To determine the number of moles of hydrogen gas collected when 1.49 g of magnesium metal is used, we need to use the molar mass of magnesium (Mg).

The molar mass of magnesium is approximately 24.31 g/mol.

We can calculate the number of moles of magnesium using the formula:

[tex]\begin{equation}\text{Number of moles} = \frac{\text{Mass}}{\text{Molar mass}}[/tex]

[tex]\begin{equation}\text{Number of moles of magnesium} = \frac{1.49~\text{g}}{24.31~\frac{\text{g}}{\text{mol}}} \approx 0.0612~\text{mol}[/tex]

According to the balanced chemical equation, the stoichiometry between magnesium and hydrogen gas is 1:1. This means that for every mole of magnesium, one mole of hydrogen gas is produced.

Therefore, the number of moles of hydrogen gas collected will also be 0.0612 mol.

Hence, if 1.49 g of magnesium metal is used in the reaction, approximately 0.0612 moles of hydrogen gas will be collected.

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calculate the period of oscillations of a simple pendulum if the length of a simple pendulum is increased by 4% and the mass is decreased by 4%,

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QUICK HELP FAST WILL GIVE BRAILIST
Which type of rock will be formed if sedimentary rock becomes molten and then hardens?
A. metamorphic
B. igneous
C. clastic
D. foliated

Answers

Answer:

B. igneous rock

Explanation:

The lava that reaches the Earth's surface will harden and become igneous rock.

Have you heard of any particle, which moves faster than light? Explore the recent researches and find about it.

Answers

Answer:

There is nothing faster then light

Explanation:

if the speed of an object is doubled, its kinetic energy will be

Answers

When the speed of an object is doubled, its kinetic energy increases by a factor of four.

Kinetic energy (KE) is given by the formula KE = 1/2 * mass * [tex]velocity^2[/tex]. The relationship between kinetic energy and velocity is quadratic, meaning that the kinetic energy is proportional to the square of the velocity.

When the speed of an object is doubled, the velocity is multiplied by 2. Plugging this new velocity into the kinetic energy formula, we have KE = 1/2 * mass * [tex](2v)^2[/tex] = 1/2 * mass * [tex]4v^2[/tex]. Simplifying further, we get KE = 2 * (1/2 * mass * [tex]v^2[/tex]) = 2 * KE.

This demonstrates that when the speed of an object is doubled, its kinetic energy increases by a factor of four. This relationship holds true for any object, regardless of its mass, as long as the speed is doubled. The increase in kinetic energy is a result of the squared relationship between velocity and kinetic energy.

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a microscope has a 13.0x eyepiece and a 58.0x objective lens 20.0 cm apart. a. draw the ray diagram for the microscope under normal use. b. calculate the total magnification. c. calculate the focal length of each lens. d. calculate where the object must be located for a normal, relaxed eye to see it in focus.

Answers

a. Ray Diagram: The objective lens produces a real image inside the focal length of the eyepiece lens, which is then magnified to create a virtual image at infinity.

b. Total Magnification: The microscope has a total magnification of 754x, calculated by multiplying the magnification of the eyepiece (13x) by the magnification of the objective lens (58x).

c. Focal Length: To calculate the focal length of each lens, we can use the lens formula. Assuming the image distance for the objective lens is -20.0 cm (on the same side as the object) and the image distance for the eyepiece lens is infinity (virtual image), we find that both lenses have a focal length of -20.0 cm.

d. Object Location: To find where the object must be located for a normal, relaxed eye to see it in focus, consider the near point of around 25 cm. Use the lens formula for the objective lens to calculate the object distance that corresponds to the image distance of 20.0 cm.

a. Ray Diagram for the Microscope:

To draw the ray diagram for the microscope, we need to understand the basic principles of how a compound microscope works. In a compound microscope, the objective lens produces a magnified real image of the object, which is then further magnified by the eyepiece to create the final virtual image. The eyepiece acts as a magnifying lens for the image produced by the objective lens.

In the ray diagram, draw an arrow representing the object placed to the left of the objective lens. The objective lens will produce a real, inverted, and magnified image of the object. This image is located inside the focal length of the eyepiece lens. The eyepiece lens will then magnify this real image to create the final virtual image, which is located at infinity. Draw the refracted rays for each lens, showing the path of the rays as they pass through each lens and are refracted.

b. Total Magnification:

The total magnification of a compound microscope is calculated by multiplying the magnification of the objective lens by the magnification of the eyepiece. In this case, the eyepiece has a magnification of 13.0x, and the objective lens has a magnification of 58.0x. To find the total magnification, multiply these two values:

Total Magnification = Eyepiece Magnification × Objective Lens Magnification

Total Magnification = 13.0x × 58.0x

Total Magnification = 754x

c. Focal Length of Each Lens:

To calculate the focal length of each lens, we can use the lens formula:

1/f = 1/v - 1/u

Where:

f = focal length of the lens

v = image distance

u = object distance

For the objective lens:

Given that the objective lens and eyepiece are 20.0 cm apart, the image produced by the objective lens will serve as the object for the eyepiece.

Let's assume the image distance for the objective lens is -20.0 cm (since it is on the same side as the object). Plugging the values into the lens formula:

1/[tex]f_o_b_j_e_c_t_i_e[/tex] = 1/-20.0 - 1/u

For the eyepiece lens:

Since we're dealing with the virtual image produced by the objective lens, the image distance for the eyepiece lens is infinity (as the virtual image appears at infinity when viewed through the eyepiece).

Plugging the values into the lens formula:

1/[tex]f_e_y_e_p_i_e_c_e[/tex] = 1/infinity - 1/20.0

Simplifying the equation:

1/[tex]f_e_y_e_p_i_e_c_e[/tex] = 0 - 1/20.0

Now, we can solve for the focal lengths:

[tex]f_o_b_j_e_c_t_i_e[/tex] = -20.0 cm

[tex]f_o_b_j_e_c_t_i_e[/tex] = -20.0 cm

The negative sign indicates that the lenses are diverging lenses commonly used in microscopes.

d. Object Location for Normal, Relaxed Eye to See in Focus:

To calculate the object location for a normal, relaxed eye to see the image in focus, we need to consider the concept of the near point (the closest distance at which the eye can focus). The near point is typically considered to be around 25 cm for a relaxed eye.

Using the lens formula for the objective lens, we can find the object distance ([tex]u_o_b_j_e_c_t_i_v_e[/tex]) that corresponds to the image distance ([tex]v_o_b_j_e_c_t_i_v_e[/tex]) of 20.0 cm:

1/[tex]f_o_b_j_e_c_t_i_v_e[/tex] = 1/20.0 - 1/[tex]u_o_b_j_e_c_t_i_v_e[/tex]

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The question probable may be:

a microscope has a 13.0x eyepiece and a 58.0x objective lens 20.0 cm apart.

A. explain how the ray diagram should be drawn for the microscope under normal use.

B. calculate the total magnification.

C. calculate the focal length of each lens.

D. calculate where the object must be located for a normal, relaxed eye to see it in focus.

1. A duck swims 10 meters in 5
seconds. What is the average speed of the duck?

Answers

Answer:

2 meter/ sec

Explanation:

Speed= distance/ time

s= 10/5

=2 meter/ sec

Average speed = total distance divided by total time, this means that we'll have to divide 10(M) by 5(S) which will equal 2 meters per second

if a samsung galaxy s9 (mass: 0.168 kg) and an iphone x (mass: 0.846 kg) are dropped from a 50 m tower, which will hit the ground first? assume no air resistance.

Answers

Both the Samsung Galaxy S9 and the iPhone X will hit the ground at the same time when dropped from a 50 m tower, as their masses do not affect their acceleration due to gravity.

When dropped from a 50 m tower, the Samsung Galaxy S9 and the iPhone X will both hit the ground at the same time if there is no air resistance. This is because their masses do not affect their acceleration due to gravity. The acceleration due to gravity is the same for all objects regardless of their mass, and it is equal to 9.8 m/s².As a result, the time it takes for the Samsung Galaxy S9 and the iPhone X to hit the ground will be the same. Therefore, their masses will not influence the time it takes for them to hit the ground. In a vacuum, two objects of different mass, when dropped from a certain height, will hit the ground at the same time. This is because the acceleration due to gravity is the same for all objects and is independent of mass. Therefore, in this situation, the Samsung Galaxy S9 and the iPhone X will hit the ground at the same time, regardless of their masses.

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The given problem relates to motion under gravity. The free fall of objects can be best understood through the concept of acceleration due to gravity, which is considered to be 9.8 m/s2 for all objects dropped near the Earth's surface.

The formula to calculate the time taken by a free-falling object to reach the ground level can be given as:t= √(2h/g)where t is the time taken, h is the height of the tower, and g is the acceleration due to gravity. Let's first calculate the time taken by Samsung Galaxy s9.t= √(2h/g)t = √(2 × 50/9.8)t = √(100/9.8)t = 3.19 s2.

Now, calculate the time taken by iPhone X.t= √(2h/g)t = √(2 × 50/9.8)t = √(100/9.8)t = 3.19 s Therefore, both the Samsung Galaxy s9 and iPhone X will hit the ground at the same time.

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The slope of a position-time graph can be used to find the moving object’s
A. Velocity
B. Position
C. Acceleration
D. None of the Above

Answers

The answer is A. Velocity. This is because velocity is obtained using position and time

what is happening in the strength of laundry bleach experiment

Answers

The strength of the laundry bleach experiment aims to provide an accurate measurement of the concentration of sodium hypochlorite in the bleach sample, which is essential for various applications and ensuring effective bleaching performance.

In the strength of laundry bleach experiment, the objective is to determine the concentration or strength of a given sample of laundry bleach. The strength of bleach is typically measured by its concentration of sodium hypochlorite (NaClO), which is the active ingredient responsible for its bleaching properties.

The experiment involves titration, a common technique used in analytical chemistry, to determine the concentration of the bleach solution. The process usually involves adding a measured volume of the bleach solution to a flask and then titrating it with a standardized solution of a suitable titrant, such as sodium thiosulfate (Na2S2O3). The titrant reacts with the bleach, and the endpoint of the reaction is indicated by a color change. This color change can be observed by adding an indicator, such as starch, which turns the solution blue-black.

By carefully measuring the volume of the titrant required to reach the endpoint, and knowing the concentration of the titrant, the concentration of the bleach solution can be calculated using stoichiometry and the balanced chemical equation for the reaction.

Overall, the strength of the laundry bleach experiment aims to provide an accurate measurement of the concentration of sodium hypochlorite in the bleach sample, which is essential for various applications and ensuring effective bleaching performance.

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What is the minimum value of the resultant if we combine a 6 Newton force and a 3 Newton force?

Lmk asap

Answers

The minimum is 3 Newton, when the two forces act in opposite directions.

Jack is practicing prior to a football tryout. He wants to work on his speed and agility, so he practices running forward the length of a football field and then running backwards the length of a football field. When he runs forward, he can run 100 yards in 10 seconds. When he is running backward, he can run 100 yards in 20 seconds. What is his speed when he is running backward?
1) 10yd/sec
2) -5yd/sec
3) -10 yd/sec
4) 5 yd/sec

Answers

I think the answer is 3 or -10 yd/sec

Answer:

-10

Explanation:

hope this helps :)

Which event is an example of condensation?
O A. Ice forms on the surface of a puddle.
B. The outside of a glass of ice water becomes moist.
C. Perspiration dries on a person's skin.
D. Fog disappears when the Sun comes out.

Answers

Answer:

Fog forms in a valley

Explanation: that’s the only reasonable response

An example of condensation Fog disappears when the Sun comes out.

What is condensation?

Condensation is the change of the state of matter from the gas phase into the liquid phase, and is the reverse of vaporization. The word most often refers to the water cycle.

The process through which the physical state of matter changes from the gaseous phase into the liquid phase Fog disappears when the Sun comes out.

An example of condensation Fog disappears when the Sun comes out.

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logarithm of the sound is measured to be 5.2 times the intensity of the weakest sound heard by the human ear, what is the decibel level of the sound

Answers

Given, the logarithm of the sound is measured to be 5.2 times the intensity of the weakest sound heard by the human ear. We have to calculate the decibel level of the sound.Main Answer:Decibel Level of the sound is 47.9 dBThe sound level of any sound is measured in decibels (dB).

Decibels (dB) is the most commonly used unit for measuring sound intensity.Sound intensity is defined as the energy carried by sound waves per unit area perpendicular to the direction of the waves.The logarithm of the ratio of the intensity of sound to the intensity of the weakest sound heard by the human ear is used to express sound intensity.

The formula for calculating the sound intensity is as follows;`β = 10 log10 (I/I0)`Where,β - The sound level in dB.I - The intensity of the sound.I0 - The intensity of the weakest sound heard by the human ear.Here,Logarithm of the sound is measured to be 5.2 times the intensity of the weakest sound heard by the human ear.`β = 10 log10 (I/I0)`5.2 = 10 log10 (I/I0)Log10(I/I0) = 5.2/10I/I0 = 10^(5.2/10)I/I0 = 5.0119So,`β = 10 log10 (I/I0)`β = 10 log10 (5.0119)β = 10(0.7008)β = 7.008The decibel level of the sound is 47.9 dB.

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consider two identical small metal balls, one having a charge of 1 microcoulombs and the other having a charge of 3 microcoulombs. the balls are separated from each other by 15 cm. each exerts a force f on the other. the balls are brought into momentary contact with each other (assume each ball is on the end of its own non-conducting rod for handling purposes) and then separated such that the distance between them is once again 15 cm. at this point, each exerts a force f' on the other. how does f' compare with f?

Answers

F' will be four times as strong as F, as q2 has doubled.

Electrostatic force is directly proportional to the charge and inversely proportional to the square of the distance between charges. So if two identical metal balls are separated by 15 cm and one has a charge of 1 microcoulomb and the other has a charge of 3 microcoulombs, each will exert a force, F on the other. The magnitude of this force can be found using Coulomb's Law: F = (kq1q2)/r2, where k is Coulomb's constant, q1 and q2 are the charges on the balls, and r is the distance between them. After they are brought into contact, the charge will distribute evenly between the two, with each having a charge of 2 microcoulombs. When they are separated again, they will still be separated by 15 cm, but each will exert a force, F' on the other. As they now have the same charge, the magnitude of the force will be given by: F' = (kq2²)/r², where q2 is the charge on each ball. Therefore, F' will be four times as strong as F, as q2 has doubled. This can be confirmed using the formula.

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GIVING BRAINLIEST FIVE STARS AND THANKS TO CORRECT ANSWER!
A sperm cell joins with an egg cell during:

fertilization

pollination

mitosis

growth

Answers

Answer:

fretillization

because when the sperm meets the egg it fertilize the egg.

Consider a column of gas with a uniform density. Light enters one end of the column and exits the other end. (a) If only 1% of the light is absorbed, what is the optical depth through the column? (b) If 50% of the light is absorbed, what is the optical depth through the column? (c) If 99% of the light is absorbed, what is the optical depth through the column?

Answers

(a) If only 1% of the light is absorbed, what is the optical depth through the column? The optical depth is 10.

The optical depth is a measure of how much light is absorbed by a material. It is calculated by dividing the number of photons absorbed by the number of photons that enter the material. In this case, only 1% of the photons are absorbed, so the optical depth is 10.

The optical depth is calculated using the following formula:

optical depth = -ln(transmission)

where transmission is the fraction of light that is transmitted through the material. In this case, the transmission is 0.99, so the optical depth is:

optical depth = -ln(0.99) = 10

(b) If 50% of the light is absorbed, what is the optical depth through the column? The optical depth is 1.

The optical depth is a measure of how much light is absorbed by a material. It is calculated by dividing the number of photons absorbed by the number of photons that enter the material. In this case, 50% of the photons are absorbed, so the optical depth is 1.

The optical depth is calculated using the following formula:

optical depth = -ln(transmission)

where transmission is the fraction of light that is transmitted through the material. In this case, the transmission is 0.5, so the optical depth is:

optical depth = -ln(0.5) = 1

(c) If 99% of the light is absorbed, what is the optical depth through the column? The optical depth is 100.

The optical depth is a measure of how much light is absorbed by a material. It is calculated by dividing the number of photons absorbed by the number of photons that enter the material. In this case, 99% of the photons are absorbed, so the optical depth is 100.

The optical depth is calculated using the following formula:

optical depth = -ln(transmission)

where transmission is the fraction of light that is transmitted through the material. In this case, the transmission is 0.01, so the optical depth is:

optical depth = -ln(0.01) = 100

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the forklift exerts a 1,500.0 n force on the box and moves it 2.00 m forward to the stack. how much work does the forklift do against the force of gravity?

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The forklift exerts a 1,500.0 n force on the box and moves it 2.00 m forward to the stack. The forklift does zero work against the force of gravity because there is no vertical displacement in the given scenario.

To calculate the work done by the forklift against the force of gravity, we need to consider the vertical displacement of the box and the gravitational force acting on it.

Given:

Force exerted by the forklift (F) = 1500.0 N

Distance moved by the box horizontally (d) = 2.00 m

The work done against the force of gravity can be calculated using the formula:

Work = Force × Displacement × cos(θ)

In this case, the vertical displacement is zero because the box is moved horizontally, and the angle (θ) between the force and the displacement is 90 degrees since the force of gravity acts vertically downward. Therefore, the cosine of 90 degrees is zero.

Work = Force × Displacement × cos(90°)

Work = 1500.0 N × 0 m × cos(90°)

Work = 0 Joules

Therefore, the forklift does zero work against the force of gravity because there is no vertical displacement in the given scenario.

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A girl weighing 500 Newton’s climbs 40 m vertically when walking up the stairs.what How much work does she do against gravity

Answers

Answer:

you first convert 40m to cm to 4000cm then W=Fxd 500x4000

therefore W=2,000000J.

Explanation:

this is the correct answer.

Given the following measurements slope t Sslope Use the error propagation rules and show the correct formula for the following: еrror a) A y-slope SA= b) B 5 Sg= n. C y+slope -2 c) Sc= If in d) D=+slope 64 Sp=

Answers

To calculate the error propagation for the given measurements, we can use the following formulas:

a) Error in slope (SA):

SA = t * Sslope

b) Error in B (Sg):

Sg = 5

c) Error in y + slope (Sc):

Sc = t * Sslope

d) Error in D (+slope):

Sp = 64

Given the following measurements slope t Sslope Use the error propagation rules and show the correct formula for the following: Error propagation rules show how the maximum error in the result depends on the errors in the data used in the calculation. It is given as follows: let `A` and `B` be two variables that each depend on several other variables [tex]`x_1, x_2, ..., x_n`.[/tex]

We can calculate the maximum error in `A` due to errors in [tex]`x_1, x_2, ..., x_n`.[/tex] For example, consider two measurements `x` and `y` that have errors `Sx` and `Sy`. The maximum error in `x+y` is then `Sx+Sy`. Let's take a look at each of the given measurements and calculate their maximum errors:

Given: t = slope S slope = maximum error in the slope

a) A = y-slopeSA = maximum error in y-slope

Error propagation formula for

a) `A = y-slope` is given by: [tex]`SA = \sqrt(Sy^2 + (t*Sslope)^2)`[/tex]

b) B = 5Sg = maximum error in 5Error propagation formula for `B = 5` is given by: `Sg = S/5` where `S` is the maximum error in `B`.

c) C = y+slope-2Sc = maximum error in y+slope-2Error propagation formula for `C = y+slope-2` is given by: [tex]`Sc = \sqrt(Sy^2 + (t*Sslope)^2)`[/tex]

d) D = +slope 64Sp = maximum error in +slope 64Error propagation formula for `D = +slope 64` is given by: `Sp = S` where `S` is the maximum error in `D`.

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