We will have that the set of rational roots for the expression will be:
[tex]\mleft\lbrace\pm\frac{1}{2},\pm1,\pm2,\pm\frac{5}{2},\pm4,\pm5,\pm10,\pm20\mright\rbrace[/tex][Option C].
Use log, 20.356, log, 3 0.503, and log, 5 0.835 to approximate the value of the given logarithm to 3 decimal places. Assume that b>0 and b + 1.
log, 625
X
A
Answer:
3.34
Step-by-step explanation:
625 is 5^4
Using the log rule [tex]log_b(x^a)=alog_b(x)[/tex],
log_b(5^4) = 4*log_b(5)
4*0.835 = 3.34
-ractions:
On a website, there is an ad for jeans every 5 minutes, an ad for sneakers
every 10 minutes, and an ad for scarves every 45 minutes.
If they all appeared together at 9:00 P.M., when is
the next time they will all appear together?
ICM to solve the problem
Answer:
Step-by-step explanation:
Can you Convert 840 inches to cm. Use unit analysis to convert the rate.
we know that
1 in=2.54 cm
so
840 in
Applying proportion
1/2.54=840/x
x=(840*2.54)/1
x=2,133.6 cm
answer is
2,133.6 cmApplying unit rate or unit analysiswe have
2.54 cm/in
Multiply by 840 in
2.54*(840)=2,133.6 cm40/
Question 8 Let h(t) = –1612 +64 + 80 represent the height of an object
To find the time it takes the object to reach the maximum height we need to remember that this happens in the axis of symmetry of the parabola described by the function:
[tex]h(t)=at^2+bt+c[/tex]The axis of symmetry is given as:
[tex]t=-\frac{b}{2a}[/tex]in this case we have that a=-16 and b=64, then we have:
[tex]t=-\frac{64}{2(-16)}=\frac{-64}{-32}=2[/tex]Therefore it takes 2 seconds to the object to reach its maximum height.
Now, to find the maximum height we plug this value of t in the equation, then we have:
[tex]\begin{gathered} h(2)=-16(2)^2+64(2)+80 \\ =-16(4)+128+80 \\ =-64+128+80 \\ =144 \end{gathered}[/tex]therefore the maximum height is 144 ft.
The answer to
√19
lies between two consecutive integers.
Use your knowledge of square numbers to state which
two integers it lies between.
√19 is between
and
The most appropriate choice for square root will be[tex]\sqrt{19}[/tex] lies between 4 and 5
What is square root of a number?
A number's square root is a value that, when multiplied by itself, yields the original number. The opposite way to square a number is to find its square root. Squares and square roots are therefore related ideas. Assuming that x is the square root of y, the equation would be written as x=y or as x2 = y. The radical symbol for the number's root is "" in this instance. When multiplied by itself, the positive number represents the square of the original number. The original number is obtained by taking the square root of a square of a real integer. For instance, the square of 3 is 9, the square root of 9 is 9, and 9 squared equals 3. Finding the square root of 9 is simple because it is a perfect square.
[tex]\sqrt{p} = p^{\frac{1}{2}}[/tex]
[tex]\sqrt{19} = 4.36\\[/tex]
4.36 lies between 4 and 5
[tex]\sqrt{19}[/tex] lies between 4 and 5
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A ball is thrown in the air. It's height, h (in meters).is given by h = -4.91 +306 + 6 where is thetime (in seconds). What is the height of the ballafter 3 seconds?
The given equation-
[tex]-4.9t^2+30t+6[/tex]After three seconds, we evaluate for t = 3.
[tex]-4.9(3)^2+30(3)+6=-4.9(9)+90+6=-44.1+96=51.9[/tex]Therefore, the height after 3 seconds is 51.9 meters.In a poll, students were asked to choose which of six colors was their favorite. The circle graph shows how the students answered. If 11,000 students participated in the poll, how many chose green?Orange 13%Pink 7%Blue 10%Red 24%Purple 10%Green 36%
Total of 11,000 students
Green 36%
how many chose green?
Chose green = 11000 * 36/100 = 3960
36% of 11,000 is 3960
Answer:
3,960 students chose green
Given the following information, determine which lines, if any, are parallel. State the converse that justifies your answer.
1. angle j and k.
Due to the Converse of Corresponding Angles Postulate, j || k.
2. Angles 2 and 5 are the alternating inner angles of the lines j and k. Given that angle 2 = angle 5,
The Converse of Alternate Interior Angles Theorem states that j || k.
J || K converse alternative interior angles.
what are parallel angles?similarly
3. angle 3 = angle 10 The exterior angles of the lines l and m, respectively, are angle 3 and angle 10. Since the Converse of Alternate Exterior Angles Theorem states that angle 3= angle 10, l || m.
converse alternative exterior angles l || m.
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find the solution to the following system by substitution x + y = 20 y = 3x 8
Based on the substitution method, the solution of the system of the equation is x = 3 and y = 17.
Substitution method:
Substitution method is the way of finding the value of any one of the variables from one equation in terms of the other variable.
Given,
Here we have the system of equations
x + y = 20
y = 3x + 8
Now we need to find the solutions for these equation using the substitution method.
From the given details we know that the value of y is defined as 3x + 8.
So, we have to apply these value on the other equation in order to find the value of x,
x + (3x + 8) = 20
4x + 8 = 20
4x = 20 - 8
4x = 12
x = 3
Now apply the value of x into the other equation in order to find the value of y,
y = 3(3) + 8
y = 9 + 8
y = 17
Therefore, the solution of the equation is x = 3 and y = 17.
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I need help on question number 1 I have been stuck on it for a long time
Explanation
Step 1
Vertical angles are formed when two lines intersect each other. Out of the 4 angles that are formed, the angles that are opposite to each other are vertical angles. vertical angles are congruent so
[tex]\begin{gathered} m\angle5=m\angle7\rightarrow reason\text{ vertical angles} \\ \end{gathered}[/tex]Step 1
replace the given values
[tex]\begin{gathered} m\angle5=m\angle7\rightarrow reason\text{ vertical angles} \\ -2(3x-4)=3(x-3)-1 \end{gathered}[/tex]now, we need to solve for x
a)
[tex]\begin{gathered} -2(3x-4)=3(x-3)-1 \\ \text{apply distributive property} \\ -6x+8=3x-9-1 \\ \text{add like terms} \\ -6x+8=3x-10\rightarrow reason\text{ distributive property} \end{gathered}[/tex]b)subtract 3x in both sides( additioin or subtraction property of equality)
[tex]\begin{gathered} -6x+8=3x-10 \\ subtract\text{ 3x in both sides} \\ -6x+8-3x=3x-10-3x \\ -9x+8=-10 \\ \text{subtract 8 in both sides} \\ -9x+8-8=-10-8 \\ -9x=-18 \\ -9x=-18\rightarrow reason\colon\text{ addition and subtraction property of equality} \end{gathered}[/tex]c) finally, divide both sides by (-9) division property of equality
[tex]\begin{gathered} -9x=-18 \\ \text{divide both side by -9} \\ \frac{-9x}{-9}=\frac{-18}{-9} \\ x=2\rightarrow\text{prove} \end{gathered}[/tex]i hope this helps you
Calculate the slope of the given line using either the slope formula m = y 2 − y 1 x 2 − x 1 or by counting r i s e r u n . Simplify your answer. You can choose your method.
The slope of the line that passes through points (x1, y1) and (x2, y2) is computed as follows:
[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]Replacing with the points (-8, 3) and (0,1) we get:
[tex]m=\frac{1-3}{0-_{}(-8)}=\frac{-2}{8}=-\frac{1}{4}[/tex]helpppppppppppppppppppppppppppppp
Answer:
[tex]f^{-1}[/tex](x) = x/2 - 3/2
Step-by-step explanation:
Swap x and y and solve for y.
Original equation:
y = 2x + 3
Swapped equation:
x = 2y + 3
Now, solve for y:
x -3 = 2y
y = (x-3)/2
If it's wrong, it might just be the way you format your answer, since Pearson (what I assume you're using) is specific about that.
Maybe, [tex]f^{-1}[/tex](x) = x/2 - 3/2 or [tex]f^{-1}[/tex](x) = (x-3)/2
If Nintendo had sold 12.2 million games in March and they had thought that they had sold 20.9 million how off was there percent error?
First let's calculate the absolute error by subtracting both values:
[tex]20.9-12.2=8.7[/tex]So the absolute error is 8.7 millions.
Now, in order to find the percent error, we just need to divide the absolute error by the number of games sold:
[tex]\frac{8.7}{12.2}=0.7131=71.31\text{\%}[/tex]So the percent error is 71.31%.
Find the slope of the tangent line when x=3 using the limit definition f(x) = X^2 - 5
SOLUTION
From the limit definition, we have that
[tex]f^{\prime}(x)=\lim _{h\to0}\frac{f(x+h)-f(x)}{h}[/tex]Now applying we have
[tex]\begin{gathered} f\mleft(x\mright)=x^2-5 \\ f^{\prime}(x)=\lim _{h\to0}\frac{f(x+h)-f(x)}{h} \\ =\lim _{h\to0}\frac{((x+h)^2-5)-(x^2-5)}{h} \\ =\lim _{h\to0}\frac{x^2+2xh+h^2^{}-5-(x^2-5)}{h} \\ =\lim _{h\to0}\frac{x^2+2xh+h^2-5-x^2+5}{h} \\ =\lim _{h\to0}\frac{x^2-x^2+2xh+h^2-5+5}{h} \\ =\lim _{h\to0}\frac{2xh+h^2}{h} \end{gathered}[/tex]factorizing for h, we have
[tex]\begin{gathered} =\lim _{h\to0}\frac{h(2x+h)^{}}{h} \\ \text{cancelling h} \\ =\lim _{h\to0}2x+h \\ =2x \end{gathered}[/tex]So, when x = 3, we have
[tex]\begin{gathered} =2x \\ =2\times3 \\ =6 \end{gathered}[/tex]Hence, the answer is 6
What is the area of a rectangle with vertices
(-1, -4), (-1, 6), (3, 6), and (3, -4)?
* 16 square units
24 square units
O 36 square units
40 square units
The most appropriate choice for distance formula will be given by Area of rectangle is 40 sq units
What is distance formula?
Distance formula is used to find the distance between two points.
Let A and B be two points with coordinate [tex](x_1, y_1)[/tex] and [tex](x_2, y_2)[/tex] respectively
Distance between A and B = [tex]\sqrt{(x_2-x_1)^2 + (y_2-y_1)^2}[/tex]
Here,
Let A = (-1 , -4), B = (-1, 6), C = (3, 6) and D = (3, -4)
Length of AB =
[tex]\sqrt{((-1)-(-1))^2 + (-4-6)^2}\\\sqrt{100}\\10 units[/tex]
Length of BC =
[tex]\sqrt{((-1)-3)^2 + (6-6)^2}\\\sqrt{16}\\4 units[/tex]
Length of rectangle = 10 units
Breadth of rectangle = 4 units
Area of rectangle = [tex]10 \times 4[/tex] = 40 sq units
Fourth option is correct
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The table shows the fraction of students from differentgrade levels who are in favor of adding new items tothe lunch menu at their school. Which list shows the grade levels in order from the greatest fraction of students to the least fraction of students ?
First, write all the fractions using the same denominator. To do so, find the least common multiple of all denominatos. The denominators are:
[tex]50,20,25,75,5[/tex]The least common multiple of all those numbers is 300.
Use 300 as a common denominator for all fractions to be able to compare their values.
5th grade
[tex]\frac{33}{50}=\frac{33\times6}{50\times6}=\frac{198}{300}[/tex]6th grade
[tex]\frac{13}{20}=\frac{13\times15}{20\times15}=\frac{195}{300}[/tex]7th grade
[tex]\frac{18}{25}=\frac{18\times12}{25\times12}=\frac{216}{300}[/tex]8th grade
[tex]\frac{51}{75}=\frac{51\times4}{75\times4}=\frac{204}{300}[/tex]9th grade
[tex]\frac{3}{5}=\frac{3\times60}{5\times60}=\frac{180}{300}[/tex]Now, we can compare the numerators to list the fraction from greatest to lowest:
[tex]\begin{gathered} \frac{216}{300}>\frac{204}{300}>\frac{198}{300}>\frac{195}{300}>\frac{180}{300} \\ \Leftrightarrow\frac{18}{25}>\frac{51}{75}>\frac{33}{50}>\frac{13}{20}>\frac{3}{5} \\ \Leftrightarrow7th\text{ grade}>8th\text{ grade}>5th\text{ grade}>6th\text{ grade}>9th\text{ grade} \end{gathered}[/tex]Therefore, the list of grade levels in order from the greatest fraction of students to the least fraction of students, is:
7th grade (18/25)
8th grade (51/75)
5th grade (33/50)
6th grade (13/20)
9th grade (3/5)
Calculate the probabilities of each of these situations. A standard deck of cards has 52 cards and 13 cards cards in each suit (Spades, Clubs, Hearts, & Diamonds). Which of the following is LEAST likely to occur? a) Selecting any spade card from a standard deck of cards, keeping it, then selecting the queen of hearts. b) Selecting a spade from a standard deck of cards, not putting it back, then selecting another spade. c) Selecting an ace from a standard deck of cards, not replacing it, then selecting a king.Event CEvent AEvent B
Answer
The least likely to occur is Event C
Explanation
A.
P(spade card) = 13/52
P(queen) = 4/51 Note: Without replacement
⇒ 13/52 x 4/51
= 52/2652
= 0.0196
B.
P(a spade) = 13/52
P( another spade) = 12/51 Note: Without replacement
⇒ 13/52 x 12/51
= 156/2652
= 0.0588
C.
P(an ace) = 4/52
P(king) = 4/51
⇒ 4/52 x 4/51
= 16/2652
= 0.006
∴ The least likely to occur is Event C
At Bright Futures Middle School, 576 students ride their bike to school . If this number is 75% of the school enrollment, then how many students are enrolled
In this case, we'll have to carry out several steps to find the solution.
Step 01:
Data
students on bike = 576
% students on bike = 75%
total students = ?
Step 02:
total students
[tex]\text{ \% students on bike = }\frac{students\text{ on bike }}{\text{total students }}\cdot100[/tex][tex]\begin{gathered} 75\text{ = }\frac{576}{\text{total students }}\cdot100 \\ \text{total students = }\frac{576}{75}\cdot100 \end{gathered}[/tex]total students = 768
The answer is:
The number of total students is 768.
what is the range of the number of goals scored?
The minimum number of goals scored is 0 and maximum number of goals scored is 7. The range is equal to difference between maximum number of goals and minimum number of goals.
Determine the range for the goals scored.
[tex]\begin{gathered} R=7-0 \\ =7 \end{gathered}[/tex]So answer is 7.
Solve the quadratic equation by using the quadratic formula. If the solutions are not real, enter NA. 3x2−5x+1=0 Enter the exact answers.
The given quadratic equation is,
[tex]3x^2-5x+1=0[/tex]let us use the formula,
[tex]\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}[/tex]where,
[tex]\begin{gathered} a=3 \\ b=-5 \\ c=1 \end{gathered}[/tex]subistute the values in the formula,
[tex]\begin{gathered} =\frac{-(-5)\pm\sqrt[]{(-5)^2-4\times3\times1}}{2\times3} \\ =\frac{5\pm\sqrt[]{25-12}}{6} \\ =\frac{5\pm\sqrt[]{13}}{6} \\ x=\frac{5+\sqrt[]{13}}{6},x=\frac{5-\sqrt[]{13}}{6} \end{gathered}[/tex]The roots of the quadratic equation are ,
[tex]x=\frac{5+\sqrt[]{13}}{6},x=\frac{5-\sqrt[]{13}}{6}[/tex]A soup can has a radius of 4.3 cm and a height of 11.6 cm. What is the volume of the soup can to the nearest tenth of a cubic centimeter?A. 1816.8B. 49.9C. 168.4D. 673.8
hello
to solve this problem, we need to identify the shape of the soup can first since soup is a liquid and carries the shape of whatever container its in.
volume of a cylinder is given as
[tex]\begin{gathered} V=\pi r^2h \\ \pi=3.142 \\ r=\text{radius} \\ h=\text{height} \end{gathered}[/tex][tex]\begin{gathered} v=\text{ ?} \\ r=4.3\operatorname{cm} \\ h=11.6\operatorname{cm} \\ \pi=3.142 \\ v=\pi r^2h \\ v=3.142\times4.3^2\times11.6 \\ v=673.9\operatorname{cm}^3 \end{gathered}[/tex]from the calculations above, the volume of the soup is equal to 673.9cm^3 which corresponds with option D
4. Find the slope of the two points: (-3,-2) & (5, -8)
Enter Numerical value ONLY. NO Decimals
Try Again!
5. Find the slope of the two points: (6, 10) and (-2, 10) *
Enter Numerical value ONLY. NO Decimals
Your answer
This is a required question
Answer:
The slope of (-3, -2) and (5, -8) is -3/4
The slope of (6, 10) and (-2, 10 ) is 0
Step-by-step explanation:
[tex]\frac{-8 - (-2)}{5 - (-3)} = \frac{-6}{8} = -\frac{3}{4}[/tex]
and
[tex]\frac{10 - 10}{-2 - 6} = \frac{0}{-8} = 0[/tex]
The sum of three consecutive integers is -39. What are the three numbers? Enter your answer as three numbers separated by a comma.
Answer:
-12, -13, and -14
Explanation:
x, y, and z are the three consecutive numbers and they sum -39, so we can write the following equation
x + y + z = -39
Since these numbers are consecutives, we get
y = x + 1
z = x + 2
So, replacing these equation on the first one and solving for x, we get
x + y + z = -39
x + (x + 1) + (x + 2) = -39
x + x + 1 + x + 2 = -39
3x + 3 = -39
3x + 3 - 3 = -39 -3
3x = -42
3x/3 = -42/3
x = -14
Then, y and z are
y = -14 + 1 = -13
z = -14 + 2 = -12
Therefore, the consecutive numbers are
-12, -13, and -14
Determine the value of b for which x = 1 is a solution of the equation shown.
2x + 14 = 10x + b
b=
Answer
Step-by-step explanation:
solve for b.
2x+14=10x+b
Step 1: Flip the equation.
b+10x=2x+14
Step 2: subtract 10x from both sides.
b+10x+−10x=2x+14+−10x
b=−8x+14
Answer:
b=−8x+14
it says i need to find the shortest distance between the point and the line for geometry honors, how would i figure it out
The given line equation is,
[tex]3x-y=-6[/tex]The given point is ,
[tex](5,1)[/tex]The graph will look like this,
let us rewrite the line equtaion as ,
[tex]3x-y+6=0[/tex]now, let us compare with the general equation of line,
[tex]Ax+By+C=0[/tex]then, A= 3,B=-1 and c= 6.
let us use the formula,
[tex]\begin{gathered} d=\frac{|Ax+By+c|}{\sqrt[]{A^2+B^2}} \\ d=\frac{|3\times5+(-1)\times1+6|}{\sqrt[\square]{3^2+(-1)^2}} \\ d=\frac{|15-1+6|}{\sqrt[\square]{9+1}} \\ d=\frac{20}{\sqrt[\square]{10}} \\ d=6.32 \end{gathered}[/tex]The shortest distance is 6.32 .
Are the answers to question six part a b c and d correct?
(CO 6) Find the regression equation for the following data setx 245 187 198 189 176 266 210 255y 50 54 55 78 44 41 51 60cannot be determinedŷ = 74.17x – 0.09ŷ = -0.09x + 74.17ŷ = 0.09x – 74.17
Answer
ŷ = -0.09x + 74.17
Explanation
For the given data set:
x 245 187 198 189 176 266 210 255
y 50 54 55 78 44 41 51 60
The sum of x = 245 + 187 + 198 + 189 + 176 + 266 + 210 + 255 = 1726
The sum of y = 50 + 54 + 55 + 78 + 44 + 41 + 51 + 60 = 433
Mean x = 1726/8 = 215.75
Mean y = 433/8 = 54.125
Sum of squares (SSx) = 8391.5
Sum of products (SP) = -779.75
(Check the table below of the data for a better understanding).
The regression Equation is given by ŷ = bX + a
b = SP/SSx = -779.75/8391.5 = -0.09292
a = My - bMx = 54.13 - (-0.09 x 215.75) = 74.17279
Therefore, the regression equation for the data set is: ŷ = -0.09292x + 74.17279
The correct answer is ŷ = -0.09x + 74.17
How do I graph a line with a equation in slope intercept form?An example is y=-3x+3, how do I graph this?
we have
y=-3x+3
to graph a line we need at least two points
so
Find out the intercepts
y-intercept (value of y when the value of x is zero)
For x=0
y=-3(0)+3
y=3
y-intercept is (0,3)
x-intercept (value of x when the value of y is zero)
For y=0
0=-3x+3
3x=3
x=1
x-intercept is (1,0)
therefore
Plot the points (0,3) and (1,0)
and join them to graph the line
see the attached figure to better understand the problem
A small toy rocket is launched from a 32-foot pad. The height ( h, in feet) of the rocket t seconds after taking off is given by the formula h=−2t2+0t+32 . How long will it take the rocket to hit the ground?t=______(Separate answers by a comma. Write answers as integers or reduced fractions.)
Given: A small toy rocket is launched from a 32-foot pad. The height (h, in feet) of the rocket t seconds after taking off is given by the formula
[tex]h=-2t^2+0t+32[/tex]Required: To find out how long will it take the rocket to hit the ground.
Explanation: When the rocket touches the ground its height will be zero i.e.,
[tex]\begin{gathered} -2t^2+0t+32=0 \\ 2t^2=32 \\ t^2=16 \end{gathered}[/tex]Which gives
[tex]t=\pm4[/tex]Neglecting the negative value of t since time cannot be negative. We have
[tex]t=4\text{ seconds}[/tex]Final Answer: Time, t=4 seconds.
Use four rectangles to estimate the area between the graph of the function f(x) = Ty and the taxis on the interval 12, 6) using the left endpointsof the subintervals as the sample points. Write the exact answer, Do not round,
To find the area using four rectangles, we will use the following equation:
[tex]Area\approx A_1_{}+A_2+A_3+A_4[/tex][tex]Area\approx f(x_1)\Delta x+f(x_2)\Delta x+f(x_3)\Delta x+f(x_4)\Delta x[/tex][tex]Area\approx f(3)\Delta x+f(4)\Delta x+f(5)\Delta x+f(6)\Delta x[/tex][tex]Area\approx(\frac{6}{7(3)})(1)+(\frac{6}{7(4)})(1)+(\frac{6}{7(5)})(1)+(\frac{6}{7(6)})(1)[/tex][tex]Area\approx\frac{57}{70}[/tex]