The statement that is NOT true about ensemble methods is:
b. Ensemble methods create multiple data mining models on multiple training sample.
Ensemble methods are a set of techniques that utilize multiple data mining models to improve predictive efficiency and/or statistical power. They combine a group of models in order to generate a single superior outcome. An example of ensemble learning involves creating several decision trees and combining their outputs to make a final prediction. Another example of ensemble learning is the use of bagging methods, boosting methods, or random forests.
The following are the uses of ensemble methods:
Ensemble methods can be used to improve model performanceEnsemble methods may include bagging, boosting, random forest, and hyperparameter tuningEnsemble methods aggregate predictions from multiple data mining models.The above options are true, but ensemble methods do not generate multiple models on multiple training samples; instead, they generate multiple models on the same training sample.
Hence the correct answer is "Ensemble methods create multiple data mining models on multiple training sample" is NOT true.
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Which of the following is not a characteristic of a good Value Log entry? Select the correct option(s) and click submit. An opportunity that can be quickly implemented An opportunity in which customer sees no value An opportunity identified by those performing the BAU work An opportunity with clear details on expected benefits
We can see here the option that is not a characteristic of a good Value Log entry is: B. An opportunity in which customer sees no value
What is Value Log Entry?A value log entry is a record of an opportunity to improve the value of a product or service. It is a way of capturing and tracking ideas for improvement, and it can be used to prioritize and manage improvement projects.
A value log entry should include the following information:
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What are the two major types of knowledge management systems?
A. Management information systems and decision support systems
B. Enterprise systems and knowledge management systems
C. Enterprise-wide knowledge management systems and knowledge work systems
D. Expert systems and knowledge work systems
E. Structured knowledge systems and unstructured knowledge systems
Knowledge management systems are designed to provide support for the creation, storage, sharing, and use of knowledge and information in an organization.
The two major types of knowledge management systems are enterprise-wide knowledge management systems and knowledge work systems.Enterprise-wide knowledge management systems are designed to support knowledge creation, storage, sharing, and use throughout an entire organization. These systems are typically integrated with other enterprise systems such as customer relationship management (CRM), enterprise resource planning (ERP), and supply chain management (SCM) systems to provide a holistic view of organizational data and knowledge.Knowledge work systems, on the other hand, are designed to support the knowledge work of specific individuals or groups within an organization. These systems are typically tailored to the needs of the specific knowledge workers, and may include features such as collaboration tools, expert systems, and workflow management tools.Structured knowledge systems and unstructured knowledge systems are not the major types of knowledge management systems. Structured knowledge systems refer to the knowledge that is explicitly codified, organized, and stored in a format that can be easily accessed and searched. Unstructured knowledge systems, on the other hand, refer to the knowledge that is tacit, informal, and difficult to formalize and store. While these are important considerations in knowledge management, they are not the two major types of knowledge management systems.
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Design a horizontal flow rectangular sedimentation basin for a maximum day design flow rate of 15,000 m^3/d. Assume an overflow rate of 50 m^3/d m^2 and a water temperature of 15 degree C. Provide the following in your summary of the design: Q_design Number of tanks Width of each tank Length of each tank Side water depth Depth of sludge zone L:D v_f Reynolds number Number of launders Launder length Weir loading Type of sludge collector
To design a horizontal flow rectangular sedimentation basin, the steps are:
Q_design (Maximum Day Design Flow Rate)Number, Width and Length of Tanks requiredSide Water Depth and Depth of Sludge ZoneL:D Ratio, Reynolds Number and Number of LaundersLaunder Length and Weir LoadingType of Sludge CollectorWhat is the sludge collector?To design a sedimentation basin, calculate parameters from given info such as the required for tank count calculation.
Sludge Zone Depth: varies with particle settling and removal goals. Overflow velocity is calculated with the formula:
v_f = Overflow Rate / (Width × Length). W
Launder length varies with tank size and number of launders. The type of sludge collector varies based on requirements and options.
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Find the 3x3 Jacobian in frame {3}, ) that calculates the linear velocity of the tooltip from the three joint rates of the manipulator (Fig. 2a). The link lengths and frame assignments are given in Figure 2b. The Jacobian for the base frame (O) (fixed) is given as [(d₂ + L₂ + L₃)C, Si = (dz + L2 + L3)S-G0 0 Joint 2 Joint 3 (dz) Joint 1 (a) Fig. 2a Robot manipulator having three DOF (RPR) 2, 8, 82 L H Veh 2 22 LI (b) (c) Fig. 2(b,c) Link lengths and frame assignments. (Hints: Find rotation matrix R using the frame assignments and then find Jacobian in frame (3)
The given problem involves finding the 3x3 Jacobian matrix in frame {3} for calculating the linear velocity of the tooltip based on the three joint rates of the manipulator.
What is the purpose of finding the 3x3 Jacobian in frame {3} for the given robot manipulator?In order to determine the linear velocity of the tooltip based on the three joint rates of the manipulator, the provided challenge calls for obtaining the 3x3 Jacobian matrix in frame 3.
Figure 2b lists the link lengths and frame assignments. By applying the frame assignments, we can derive the rotation matrix R, which we can then use to calculate the Jacobian in frame 3.
Considering the link lengths and frame assignments stated in the issue, the Jacobian matrix will depict the relationship between the joint rates and the tooltip's linear velocity in frame 3.
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a cylindrical pressure vessel is constructed from a long, narrow steel plate by wrapping plate around a mandrel and then welding along the edges of the plate to make a helical joint. the helical weld makes an angle 450 with the longitudinal axis. the vessel has an inner diameter of 1.25m and a wall thickness of 15mm. when the inner pressure is 8mpa, determine the normal stress and shear stress acting perpendicular and parallel, respectively, to the welding seam.
The normal stress is 21.33 MPa and the shear stress is 10.67 MPa.
What are the magnitudes of the normal and shear stresses acting on the helical weld of the cylindrical pressure vessel?In the given scenario, a cylindrical pressure vessel is constructed by wrapping a long, narrow steel plate around a mandrel and welding it along the edges to form a helical joint. The helical weld makes an angle of 45° with the longitudinal axis. The vessel has an inner diameter of 1.25 m and a wall thickness of 15 mm.
To determine the normal stress acting perpendicular to the welding seam, we need to consider the internal pressure. The formula to calculate the normal stress is given by:
Normal stress = Pressure × Radius / Thickness
Plugging in the values, we have:
Normal stress = (8 MPa) × (0.625 m) / (0.015 m) = 21.33 MPa
To determine the shear stress acting parallel to the welding seam, we need to consider the angle of the helical weld. The formula to calculate the shear stress is given by:
Shear stress = Pressure × Radius / (2 × Thickness × sin(θ))
Plugging in the values, we have:
Shear stress = (8 MPa) × (0.625 m) / (2 × 0.015 m × sin(45°)) = 10.67 MPa
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A red and a blue die are thrown. Both dice are loaded (that is, not all sides are equally likely). Rolling a 4 with the red die is twice as likely as rolling each of the other five numbers and rolling a 3 with the blue die is twice as likely as rolling each of the other five numbers. What is the probability of each outcome of the red die? What is the probability of each outcome of the blue die? what is the probability that the sum of the numbers on the two dice is 7?
The probability of rolling each outcome with the red die is as follows: P(1) = P(2) = P(5) = P(6) = 1/15, and P(3) = P(4) = 2/15. The probability of rolling each outcome with the blue die is as follows: P(1) = P(2) = P(4) = P(5) = P(6) = 1/15, and P(3) = 2/15. The probability that the sum of the numbers on the two dice is 7 is 4/15.
What are the probabilities for each outcome?When throwing a red die, the probability of rolling a 4 is twice as likely as rolling each of the other five numbers. Therefore, the probability of rolling a 4 is 2/15, and the same applies to rolling a 3 with the blue die. For the remaining outcomes, the probabilities are evenly distributed, resulting in a probability of 1/15 for each number.
To calculate the probability of the sum being 7, we need to consider the possible combinations. The only combination that results in a sum of 7 is rolling a 4 with the red die and a 3 with the blue die. Since the probabilities of rolling a 4 and a 3 are 2/15 each, the probability of their joint occurrence is (2/15) * (2/15) = 4/225.
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