which of the following statements correctly compares the tow functions f(x) and g(x)?.

Which Of The Following Statements Correctly Compares The Tow Functions F(x) And G(x)?.
Which Of The Following Statements Correctly Compares The Tow Functions F(x) And G(x)?.

Answers

Answer 1

We have two functions and we have to find which statements are true.

They both have a maximum value of 1.

f(x) has a minimum and not a maximum, so this statement is not true.

The graphs of both functions cross the x-axis at 0.

f(x) does not cross the x-axis, so this statement is not true.

The graphs of both functions cross the y-axis at 1.

This is true for f(x).

For g(x), we have to calculate g(0) to find at which value of y the function cross the y-axis:

[tex]g(0)=-4\cdot0^2+1=0+1=1[/tex]

This statement is true.

Function f(x) has a minimum value of 1 and function g(x) has a maximum value of 1.

This is true for f(x).

For g(x), the maximum value happens when x=0, because for all other values of x, the quadratic term becomes more negative.

In the previous statement we calculate g(0)=1, so 1 is the maximum value of g(x).

This statement is true.

They both have a minimum value of 1.

g(x) does not have a minimum value. This statement is not true.

Answer: The statement that are true:

- The graphs of both functions cross the y-axis at 1.

- Function f(x) has a minimum value of 1 and function g(x) has a maximum value of 1.


Related Questions

For each problem below find the missing factor by computing the inverse operation

Answers

Given:

There are given that the fraction:

[tex]4\frac{1}{2}-\text{ \lbrack \rbrack}=2\frac{7}{8}[/tex]

Explanation:

Suppose missing information is x

Then,

Ater that we need to find the value of x

So,

[tex]4\frac{1}{2}-x=2\frac{7}{8}[/tex]

Then,

[tex]\begin{gathered} 4\frac{1}{2}-x=2\frac{7}{8} \\ \frac{9}{2}-x=\frac{23}{8} \\ \frac{9}{2}-x-\frac{9}{2}=\frac{23}{8}-\frac{9}{2} \\ -x=\frac{23}{8}-\frac{9}{2} \end{gathered}[/tex]

Now,

[tex]\begin{gathered} -x=\frac{23}{8}-\frac{9}{2} \\ -x=\frac{23-36}{8} \\ -x=\frac{-13}{8} \\ x=\frac{13}{8} \\ x=1\frac{5}{8} \end{gathered}[/tex]

Final answer:

Hence, the missing factor is shown below:

[tex]x=1\frac{5}{8}[/tex]

find the exact value of cosine Pi / 3 express your answer with a rational denominator

Answers

it is given that,

the expression is

cosine Pi/3

we know that

so,

[tex]\cos \frac{\pi}{3}=\cos \frac{180}{3}=\cos 60=\frac{1}{2}[/tex]

thus, the answer is 1/2

write the function value in term of the cofunction of a complementary angle .

Answers

Answer:

Explanations:

Note that the secant and cosecant functions are cofunctions and are also complements.

Therefore, they are related mathematically as:

csc x = sec ( 90° - x)

x = 64°

csc 64° = sec (90° - 64°)

csc 64° = sec 26

Find the real and imaginary solution of (w^3) - 1000=0

Answers

Explanation

Given

[tex]w^3-1000=0[/tex]

We will have;

[tex]\begin{gathered} w^3=1000 \\ \mathrm{For\:}x^3=f\left(a\right)\mathrm{\:the\:solutions\:are\:}x=\sqrt[3]{f\left(a\right)},\:\sqrt[3]{f\left(a\right)}\frac{-1-\sqrt{3}i}{2},\:\sqrt[3]{f\left(a\right)}\frac{-1+\sqrt{3}i}{2} \\ therefore;\text{ }w=\sqrt[3]{1000},\:w=\sqrt[3]{1000}\frac{-1+\sqrt{3}i}{2},\:w=\sqrt[3]{1000}\frac{-1-\sqrt{3}i}{2} \\ hence;w=10,w=10\times\frac{-1+\sqrt{3}i}{2},\:w=10\times\frac{-1-\sqrt{3}i}{2} \\ w=10,\:w=-5+5\sqrt{3}i,\:w=-5-5\sqrt{3}i \end{gathered}[/tex]

Answer: Option D

I need to know 3 equivalent expressions for the total amount of money.

Answers

[tex]M=40pd+25pd+100d[/tex]

we can rewrite the expression with a factor

[tex]M=5(8pd+5pd+20d)[/tex]

and we can rewrite again with the other factor "d"

[tex]\begin{gathered} M=5d(8p+5p+20) \\ M=5d(13p+20) \end{gathered}[/tex]

Keico is selling rattle tickets to raise money for the sancol band. The odds againet winning a prize in the raffleare 121. What is the probability of winning a prize? Express your anewer as a decimal. if necessary, round youranower to the nearest thousandth.0 130 0.923O 0.083O 0.0777

Answers

Given:

The odds against winning a prize in the raffle are 12:1

[tex]\begin{gathered} \text{Probability of winning a prize=}\frac{1}{13} \\ \text{Probability of winning a prize=}0.077 \end{gathered}[/tex]

0.077 is the probability of winning a prize.

This statement is false or true?Expression that contain one variable can be proven true or false by replacing the variable with a number.

Answers

The statement is false.

An expression has no value of true since it is not an equation.

To solve the equation 2x - 6 = 30 by balancing, what would be step?

Answers

Given the equation

[tex]2x-6=30[/tex]

To solve the equation means to determine the value of x, so your objective will be to isolate the x term in one side of the equal sign.

To do this using the balancing method, you have to "pass" all unrelated terms to the other side if the equal sign by performing the oposite operation.

So, first step is to pass -6 to the other side by adding it to both sides of the equation

[tex]\begin{gathered} 2x-6+6=30+6 \\ 2x=36 \end{gathered}[/tex]

Next, the x term is being multiplied by 2, to cancel this multiplication you have to divide it by 2. And, to keep the equality valid, any operation performed in one side of the equal sing must be performed on the other side so, divide 36 by 2 too.

[tex]\begin{gathered} \frac{2x}{2}=\frac{36}{2} \\ x=18 \end{gathered}[/tex]

Here are the graphs of three equations:y = 50(1.5) ^xy = 50(2)^xY = 50(2. 5)^xWhich equation matches each graph? Explain how you know

Answers

The graphs below are exponential function graphs, the general formular takes the form

[tex]y=ab^x[/tex]

The graph of

[tex]y=50(1.5)^x[/tex]

Is shown below

The graph of

[tex]y=50(2^x)[/tex]

Is shown below

The graph of

[tex]y=50(2.5^x)[/tex]

Is shown below

Hence,

[tex]\begin{gathered} y=50(1.5)^x\rightarrow C \\ y=50(2)^x\rightarrow B \\ y=50(2.5)^x\rightarrow A \end{gathered}[/tex]

The equation of the exponential function is

[tex]\begin{gathered} y=ab^x \\ a=50\rightarrow the\text{ initial value} \\ b\rightarrow growht\text{ factor} \end{gathered}[/tex]

Thus the higher the growth factor the greater the rate of attaining a higher value within a short period.

That is why you see that the function with growth factor of 2.5 grows faster than that of 2 and also 1.5.

So the at x value of 3, the function with the greatest growth factor will have the highest y-value.

This implies , growth factor of 2.5 will have the highest, that corresponds to graph with colour green. Function with growth factor 2 will be the next to that of 2.5, that is red colored graph, and the last will be blue.

8. * The functions f(x) and g(x) are both linear. f(2) = 4 and f(3) = -1, while g(2) = 6 and g(-3) = 7. Are these lines parallel, perpendicular, or neither? Show your work algebraically. 9. ** f(x) = 5x – 2 and g(x) = 2x + 4. Are f(x) and g(x) parallel, perpendicular or neither parallel nor perpendicular to each other. Justify.

Answers

[tex]\begin{gathered} \text{for the line f we have 2 points:} \\ (x_1,y_1)=(2,4) \\ \text{and} \\ (x_2,y_2)=(3,-1) \\ \text{hence, the slope} \\ m=\frac{y_2-y_1}{x_2-x_1} \\ is\text{ given by} \\ m=\frac{-1-4}{3-2} \\ m=-\frac{5}{1} \\ m=-5 \\ \text{now we ne}ed\text{ to find the slope for g} \end{gathered}[/tex][tex]\begin{gathered} \text{For g we have 2 points:} \\ (x_1,y_1)=(2,6) \\ (x_2,y_2)=(-3,7) \\ \text{hence, the slope is given by} \\ m=\frac{7-6}{-3-2} \\ m=\frac{1}{-5} \end{gathered}[/tex][tex]\begin{gathered} \text{parallel lines has the same slope.} \\ \text{perpendicular lines has reciprocal negative slope}\colon \\ m\Rightarrow-\frac{1}{m} \\ IN\text{ THIS CASE, they are neither parallel nor perpendicular since} \\ m=-5 \\ \text{and} \\ m=-\frac{1}{5} \\ \text{are not perpendicular } \end{gathered}[/tex]

What Postulate or theorem proves that these triangles are similar?

Answers

Solution

The Side-Angle-Side (SAS) Theorem states if two sides of one triangle are proportional to two corresponding sides of another triangle, and their corresponding included angles are congruent, the two triangles are similar.

Next

AC is corresponding to EC

BC is corresponding to DC

[tex]\begin{gathered} \frac{AC}{EC}\text{ = }\frac{6}{12}\text{ = }\frac{1}{2} \\ \frac{BC}{DC}\text{ = }\frac{5}{10}\text{ = }\frac{1}{2} \end{gathered}[/tex]

The ratio of their corresponding sides is proportional.

Final answer

The Side-Angle-Side (SAS) Theorem

how do you write out this number in word 506,341,209.54

Answers

You write this number in word this way:

Five hundred six million three hundred fourty one thousand two hundred nine point fifty four.

PLEASE HELPPP ASAP For the trapezoid below, what is he correct term for RL

Answers

GIVEN:

We are given the diagram showing a trapezoid REWT, with the vertical line RL.

Required;

Identify the correct term for the line RL.

Solution;

The trapezoid has;

RE = Shorter base

TW = Longer base

RL = Altitude (or vertical height).

ANSWER:

The correct answer is option B

[tex]Altitude[/tex]

Help me with this math and explaining the question solution and quickly and explain it

Answers

To find the distance between V1 and the aquarium we can use the formula of the distance between two points in the plane, that is,

[tex]\begin{gathered} d=\sqrt[]{(x_2-x_1)^2+(y_2-y_1)^2} \\ \text{ Where }(x_1,y_1)\text{ and }(x_2,y_2)\text{ are the coordinates of the points} \end{gathered}[/tex]

So, in this case, we have

[tex]\begin{gathered} V1(-6,5) \\ AQ(5,5) \\ d=\sqrt[]{(x_2-x_1)^2+(y_2-y_1)^2} \\ d=\sqrt[]{(5-(-6))^2+(5-5)^2} \\ d=\sqrt[]{(5+6)^2+(5-5)^2} \\ d=\sqrt[]{(11)^2+(0)^2} \\ d=\sqrt[]{(11)^2} \\ d=11 \end{gathered}[/tex]

Therefore, the distance between v1 and the aquarium is 11 units.

For the experiment, determine the two given events are independent. The answers are guessed on a twenty-question multiple-choice test. The events are "the first question is correct" and "the second answer is correct". Are the two events independent or not independent?

Answers

Two events are independent when one of the events happen and the result does not affect on the result for the second event.

In this case if we have multiple-choice answers on the test the probability of having the correct answer for both of them is the same, however if we get the first one correct it does not mean that we will have the second answer correct.

For this reason the events are independent.

Last season, your favorite basketball teamwon 60 games. So far this season, yourfavorite basketball team has won 72 games.What is the percent change in the numberof games that your favorite team won fromlast season to this season?

Answers

In order to determine the percent change in the number of games, you first calculate the difference between the number of games won last season and current season.

current season = 70 games won

last season = 60 games won

70 - 60 = 10

next, you determine what is the associated percent of 10 games to 60 games from the last season. You proceed as follow:

(10/60)(100) = 16.66

that is, you calculate the quotient between increase of games won, the number of games won last season, and to the result you multiply by 100.

Hence, the increase in the percent of games won is of 16.66%

simplify the expression x² - 3xy - 5xy - 7y² + 4x² + 8y²

Answers

x² - 3xy - 5xy - 7y² + 4x² + 8y² ​

First, let's re-arrange

x² + 4x² - 3xy - 5xy - 7y² + 8y² ​

5x² - 8xy + y²

Convert the angle 225° from degrees to radians. Enter your answer in terms of π.

Answers

Remember that:

[tex]\pi\text{ rad}=180^{\circ}[/tex]

Dividing both sides by 180° we get:

[tex]\frac{\pi\text{ rad}}{180^{\circ}}=1[/tex]

Which we can use as conversion factor to convert degrees to radians.

For an angle of 225°:

[tex]225^{\circ}=\frac{\pi\text{ rad}}{180^{\circ}}=\frac{225}{180}\cdot\pi\text{ rad}=\frac{5}{4}\cdot\pi\text{ rad}[/tex]

Therefore, in terms of π:

[tex]225^{\circ}=\frac{5}{4}\pi\text{ rad}[/tex]

Jamie is cutting for a craft project.she has a ribbon that is 2 1/4 inches long. How many pieces of ribbon can she cut that are 3/8inches long

Answers

Total Lenght = 2 1/4

Lenght of each piece = 3/8

Divide the total lenght by the lenght of each piece:

Total lenght = 2 1/4 = (2*4+1)/4 = 9/4

Total lenght / lenght of each piece = (9/4 ) / (3/8)

To divide 2 fractions we can multiply by the inverse of the second fraction:

[tex]\frac{9}{4}\times\frac{8}{3}=\frac{72}{12}[/tex]

Simplify by 12:

6

Answer: 6 pieces

2.2Determine the value of n for which (3k - 2) = 70

Answers

The value of k is 24.

From the question, we have

(3k - 2) = 70

(3k) = 72

k=24

Subtraction:

Subtraction represents the operation of removing objects from a collection. The minus sign signifies subtraction −. For example, there are nine oranges arranged as a stack (as shown in the above figure), out of which four oranges are transferred to a basket, then there will be 9 – 4 oranges left in the stack, i.e. five oranges. Therefore, the difference between 9 and 4 is 5, i.e., 9 − 4 = 5. Subtraction is not only applied to natural numbers but also can be incorporated for different types of numbers.

The letter "-" stands for subtraction. Minuend, subtrahend, and difference are the three numerical components that make up the subtraction operation. A minuend is the first number in a subtraction process and is the number from which we subtract another integer in a subtraction phrase.

Complete question: Determine the value of k for which (3k - 2) = 70

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Is this relation a function?

{(1, 3), (2, 3), (3, 4), (4, 5)}


No, because at least one output maps to more than one input.
No, because at least one output maps to more than one input.

Yes, because every input has exactly one output.
Yes, because every input has exactly one output.

No, because at least one input maps to more than one output.
No, because at least one input maps to more than one output.

Answers

The given relation {(1, 3), (2, 3), (3, 4), (4, 5)} is a function. Therefore, the correct statement is "Yes, because every input has exactly one output."

Relation:

A relation is a relationship between the x and y-coordinates. It must maps inputs to outputs.

Given,

Here we have the relation

{(1, 3), (2, 3), (3, 4), (4, 5)}

Now, we have to find whether this relation is a function or not.

We know that, a relation is said to be a  relation is a function if the x values map to only one y - value. Simply said that if a relation is one-to-one or many-to-one it is a function.

Based on this rule, here each input has exactly one output. therefore, the given relation is said to be a function.

To know more about Relation here.

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Sallys recipe for chocolate chip cookies yields 48, 1 oz cookies. If she want to make 48,2 oz cookies what is her conversation factor??(Hint : how many total oz cookies is in the original recipe yield and the new recipe yields)

Answers

[tex]\begin{gathered} \text{ In general remember that if to find the conversion factor of } \\ \text{ a number A against B, you would find A/ B } \\ \text{ in this case the conversion factor would be } \\ 48.1/48.2=0.997 \end{gathered}[/tex]

expand and simplify(p+4)(P+3)P-1)

Answers

In linear equation, p³ - 6p² + 5p - 12 is simplify od equation .

What is a linear equation example?

Ax+By=C is the typical form for linear equations involving two variables. A linear equation in standard form is, for instance, 2x+3y=5.Finding both intercepts of an equation in this format is rather simple (x and y).

(p+4)(P+3)(P-1)

= p² + 3p + 4p + 12

= ( p - 1 ) ( p² + 3p + 4p + 12 )

= p³ + 7p² + 12p - p² - 7p - 12

= p³ - 6p² + 5p - 12

Learn more about linear equation

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Can you please help me out with a question

Answers

Answer:

3 degrees

Explanation:

Using the theorem that states that the measure of the angle at the circumference is equal to the half of its intercepted arc. Hence;

31x+ 3 = 1/2(192)

31x + 3 = 96

Subtract 3 from both sides

31x + 3 - 3 = 96 - 3

31x = 93

Divide both sides by 31

31x/31 = 93/31

x = 3

Hence the value of x is 3 degrees

y=0.5x+3; what is the slope?

Answers

The given equation,

[tex]y=0.5x+3[/tex]

Comparing it with the slope intercept equation

[tex]y=mx+c[/tex]

where m is the slope.

Thus the slope is m=0.5.

Suppose ABC is a right triangle of lengths a, b and c and right angle at c. Find the unknown side length using the Pythagorean theorem and then find the value of the indicated trigonometric function of the given angle. Rationalize the denominator if applicable.Find tan B when a=96 and c=100

Answers

To begin with, we will have to sketch the image of the question

To find the value of tan B

we will make use of the trigonometric identity

[tex]\tan \theta=\frac{opposite}{adjacent}[/tex]

From the diagram given

[tex]\tan B=\frac{\text{opposite}}{\text{adjacent}}=\frac{b}{96}[/tex]

Since the value of b is unknown, we will have to get the value of b

To do so, we will use the Pythagorean theorem

[tex]\begin{gathered} \text{hypoteuse}^2=\text{opposite}^2+\text{adjacent}^2 \\ b^2=100^2-96^2 \\ b=\sqrt[]{784} \\ b=28 \end{gathered}[/tex]

Since we now know the value of b, we will then substitute this value into the tan B function

so that we will have

[tex]\tan \text{ B=}\frac{opposite}{adjecent}=\frac{b}{a}=\frac{28}{96}=\frac{7}{24}[/tex]

Therefore

[tex]\tan \text{ B=}\frac{7}{24}[/tex]

I’m in AP Calc AB and can’t figure this out. Any idea?

Answers

Answer::

[tex]f^{\prime}(x)=7x\sec x\tan x+7\sec x+\frac{1}{x}[/tex]

Explanation:

Given f(x) defined below:

[tex]f(x)=\ln x+7x\sec x[/tex]

The derivative is calculated below.

[tex]\begin{gathered} \frac{d}{dx}\lbrack f(x)\rbrack=\frac{d}{dx}\lbrack\ln x+7x\sec x\rbrack \\ =\frac{d}{dx}\lbrack\ln x\rbrack+\frac{d}{dx}\lbrack7x\sec x\rbrack \\ Take\text{ the constant 7 outside the derivative sign.} \\ =$$\textcolor{red}{\frac{d}{dx}\lbrack\ln x\rbrack}$$+7\frac{d}{dx}\lbrack x\sec x\rbrack \\ \text{The derivative of }\ln (x)=\frac{1}{x},\text{ therefore:} \\ $$\textcolor{red}{\frac{d}{dx}\lbrack\ln x\rbrack}$$+7\frac{d}{dx}\lbrack x\sec x\rbrack=$$\textcolor{red}{\frac{1}{x}}$$+7\frac{d}{dx}\lbrack x\sec x\rbrack\cdots(1) \end{gathered}[/tex]

Next, we find the derivative of x sec x using the product rule.

[tex]\begin{gathered} \frac{d}{dx}\lbrack x\sec x\rbrack=x$$\textcolor{blue}{\frac{d}{dx}\lbrack\sec x\rbrack}$$+\sec x\frac{d}{dx}\lbrack x\rbrack\text{ } \\ The\text{ derivative of sec(x), }\text{\textcolor{red}{ }}\textcolor{red}{\frac{d}{dx}\lbrack\sec x\rbrack=\sec x\tan x} \\ =x$$\textcolor{blue}{\lbrack\sec x\tan x\rbrack}$$+\sec x \end{gathered}[/tex]

Substitute the result into equation (1) above.

[tex]\begin{gathered} \frac{1}{x}+7\frac{d}{dx}\lbrack x\sec x\rbrack=\frac{1}{x}+7(x\sec x\tan x+\sec x) \\ =7x\sec x\tan x+7\sec x+\frac{1}{x} \end{gathered}[/tex]

Therefore:

[tex]f^{\prime}(x)=7x\sec x\tan x+7\sec x+\frac{1}{x}[/tex]

please help me with mathHere’s a picture of the question

Answers

Answer:

a) Yes, triangles JNM and JLK are similar by the AA Similarity Postulate

b) JN = 4 in

c) LN = 1.5 in

JK = 3.5 in

d) Area ratio = 2.56 : 1

Explanation:

Given:

KL = 5 in

MN = 8 in

JL = 2.5 in

MK = 2.1 in

From triangle JLK and JNM, we can deduce the following;

[tex]\begin{gathered} \angle J\cong\angle J......Reflexive\text{ property of angles} \\ \angle M\cong\angle K......Corresponding\text{ angles are equal} \\ \angle N\cong\angle L.........Corresponding\text{ angles are equal} \end{gathered}[/tex]

a) The AA Similarity theorem states that if two pairs of corresponding angles in two triangles are congruent, then the two triangles are similar. From the above, we can see that we have two pairs of corresponding angles that are congruent, so we can say that triangles JLK and JNM are similar.

b) Note that, in similar triangles, corresponding sides are equal in proportion.

So we can go ahead and solve for JN as seen below;

[tex]\begin{gathered} \frac{KL}{MN}=\frac{JL}{JN} \\ \frac{5}{8}=\frac{2.5}{JN} \\ 5JN=20 \\ JN=\frac{20}{5} \\ JN=4 \end{gathered}[/tex]

So JN is 4 in

c)

[tex]\begin{gathered} JN=JL+LN \\ LN=JN-JL \\ LN=4-2.5 \\ LN=1.5\text{ in} \end{gathered}[/tex]

So LN is 1.5 in

Let's find the length of JK;

[tex]\begin{gathered} \frac{KL}{MN}=\frac{JK}{JM} \\ \frac{KL}{MN}=\frac{JK}{JK+MK} \\ \frac{5}{8}=\frac{JK}{JK+2.1} \\ 5(JK+2.1)=8JK \\ 5JK+10.5=8JK \\ 8JK-5JK=10.5 \\ 3JK=10.5 \\ JK=\frac{10.5}{3} \\ JK=3.5\text{ in} \end{gathered}[/tex]

So the length of JK is 3.5 in

d) The area ratio of two similar triangles is equal to the square of the ratio of any two corresponding sides.

So the ratio of triangle JNM to JKL is;

[tex]Area\text{ ratio}=\frac{8^2}{5^2}=\frac{64}{25}=\frac{2.56}{1}=2.56:1[/tex]

how many square inches, 1 in. by 1 in., fit in an area if 1 square foot, 1 ft by 1 ft?

Answers

We have the following:

We must convert square feet to square inches

We have that 1 foot is equal to 12 inches

[tex]1ft^2\cdot\frac{(12in)^2}{(1ft)^2}=144in^2[/tex]

Which means that one square foot equals 144 square inches.

The area of a rectangle is given by a=6x^2y+4y^2x and the width of the rectangle is w=2xy. what is the length, l, of the rectangle if l=a/w

Answers

Step 1

Given; The area of a rectangle is given by a=6x^2y+4y^2x and the width of the rectangle is w=2xy. what is the length, l, of the rectangle if l=a/w?

Step 2

[tex]\begin{gathered} l=\frac{a}{w} \\ l=\frac{6x^2y+4y^2x}{2xy} \end{gathered}[/tex][tex]\begin{gathered} factorize \\ l=\frac{2xy\left(3x+2y\right)}{2xy} \end{gathered}[/tex]

Thus;

[tex]l=3x+2y[/tex]

Answer;

[tex]l=3x+2y[/tex]

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