Which of the following was one reason why electronic (computer-based) information sharing was challenging in the not too distant past?
a. Individuals and/or members of organizations did not speak the same language.
b. Hardware and software applications on either end could not talk to one another.
c. The most powerful computers were owned by large companies.
d. Organizations needed to protect information for competitive advantage.

Answer:

Here the answer is given as follows,

Explanation:

Operating Platform:-  

In terms of platforms, there are differences between, mobile games and pc games within the way it's used, the operator, the most event play, the sport design, and even the way the sport work. we all know that each one the games on console platforms, PC and mobile, have their own characteristic which has advantages and disadvantages All platforms compete to win the rating for the sake of their platform continuity.  

Operating system architectures:-  

Arm: not powerful compared to x86 has many limitations maximum possibility on arm arch is mobile gaming.  

X86: very powerful, huge development so easy to develop games on platforms like unity and unreal, huge hardware compatibility and support  

Storage management:-  

On the storage side, we've few choices where HDD is slow and too old even a replacement console using SSD. so SSD is the suggested choice. But wait SSD have also many options like SATA and nvme.    

Memory management:-  

As recommended windows, Each process on 32-bit Microsoft Windows has its own virtual address space that permits addressing up to 4 gigabytes of memory. Each process on 64-bit Windows features a virtual address space of 8 terabytes. All threads of a process can access its virtual address space. However, threads cannot access memory that belongs to a different process.  

Distributed systems and networks:-  

Network-based multi-user interaction systems like network games typically include a database shared among the players that are physically distributed and interact with each other over the network. Currently, network game developers need to implement the shared database and inter-player communications from scratch.  

Security:-  

As security side every game, there's an excellent risk that, within the heat of the instant, data are going to be transmitted that you simply better keep to yourself. There are many threats to your IT.  

Define on the whole data protection matters when developing games software may cause significant competitive advantages. Data controllers are obliged under the GDPR to attenuate data collection and processing, using, as an example , anonymization or pseudonymization of private data where feasible.

Answer:

hope it helps PLZ MARK ME BRAINLIEST,,!

Explanation:

They stabilize your grpahic image.

Incomplete question. Here's the full question:

Data-Time Inc. is a company that manages databases for a large city in Colorado. Included in these databases is information collected from the city’s homeless shelters and free clinics. Specifically, the databases contain personal information of the users of these services over the past 10 years; this includes people’s Social Security numbers and health records.

This data is highly secure and only accessible to the employees of Data-Time Inc. Employees are given a laptop when they are hired which allows them to access the database remotely. Unfortunately, one of these laptops is stolen and the security of the database is compromised.

A majority of the people whose information was compromised are homeless; therefore there is no easy way to contact them in order to alert them of the security breach. How should Data-Time Inc. manage this breach in security?

Explanation:

Since the emphasis is not on reversing the breach that has occurred, but on managing the level of security damage that could occur, it is important measures are directed towards preventing unauthorized access to sensitive information.

For example, the Media Access Control Address (MAC address) of the laptop if known could be greylisted from accessing the server that contains the sensitive information.

Answer:

Vulnerability assessment

Explanation:

Cyber security can be defined as preventive practice of protecting computers, software programs, electronic devices, networks, servers and data from potential theft, attack, damage, or unauthorized access by using a body of technology, frameworks, processes and network engineers.

Some examples of cyber attacks are phishing, zero-day exploits, denial of service, man in the middle, cryptojacking, malware, SQL injection, spoofing etc.

A vulnerability assessment is a systematic and methodical evaluation used by network security experts to determine the exposure of network assets such as routers, switches, computer systems, etc., to attackers, forces of nature, or any other entity that is capable of causing harm i.e potential harms. Thus, vulnerability assessment simply analyzes and evaluate the network assets of an individual or business entity in order to gather information on how exposed these assets are to hackers, potential attackers, or other entities that poses a threat.

Answer:

Explanation:

The following code is written in Java. It creates a loop within a loop that plays the game 10 times. As soon as the inner loop tosses a Heads (represented by 1) the inner loop breaks and the cost of that game is printed to the screen. A test case has been made and the output is shown in the attached image below.

import java.util.Random;

import java.util.Scanner;

class Brainly {

   public static void main(String[] args) {

       int count = 0;

       int loopCount = 0;

       while (loopCount < 10) {

           while (true) {

               Random rand = new Random();

               int coinFlip = rand.nextInt(2);

               count++;

               if (coinFlip == 1) {

                   System.out.println("Cost: $" + 2*count);

                   count = 0;

                   break;

               }

               loopCount++;

           }

       }

   }

}

Answer:

Memory-mapped I/O and port-mapped I/O are two complementary methods of performing input/output between the central processing unit and peripheral devices in a computer. An alternative approach is using dedicated I/O processors, commonly known as channels on mainframe computers, which execute their own instructions.

Answer:-

CODE:

#include <iostream>

#include<cmath>

using namespace std;

float calcBaseArea(float a);

float calcSideArea(float s,float l);

void prntSprfArea(float base_area,float side_area);

int main()

{

float h;

float a;

float base_area

float side_area;

cout<<"Enter the side length of the base of the square pyramid in feet : ";

cin>>a;

cout<<"Enter the height of the square pyramid in feet : ";

cin>>h;

base_area=calcBaseArea(a);

side_area=calcSideArea(a,h);

cout<<"Base surface area of the square pyramid is "<<base_area<<" square feet. "<<endl;

cout<<"Side area of the square pyramid is "<<side_area<<" square feet."<<endl;

prntSprfArea(base_area,side_area);

return 0;

}

float calcBaseArea(float a)

{

return pow(a,2);

}

float calcSideArea(float s,float l)

{

float area=(s*l)/2;

return 4*area;

}

void prntSprfArea(float base_area,float side_area)

{

cout<<"Total surface area of the pyramid is "<<base_area+side_area<<" square feet.";

OUTPUT:

Answer:

Following are the solution to the given question:

Explanation:

The common folder called Report has also been shared. Writing access to a shared folder was given to management group members. Mark is a member of a group of managers. We can access the files within your reporting directory, but you really should not access the Confidential.xls file. We want to add Mark Mangum to our ACL files using Deny permissions on Confidential.xls.

Answer:

it would have to be flow control which would be C.

Explanation:

Flow Control is restricts the ability for individuals to reveal information present in some part of the database. Hence, option C is correct.

The management of data flow between computers, devices, or network nodes is known as flow control. This allows the data to be processed at an effective rate. Data overflow, which occurs when a device receives too much data before it can handle it, results in data loss or retransmission.

A design concern at the data link layer is flow control. It is a method that typically monitors the correct data flow from sender to recipient. It is very important because it allows the transmitter to convey data or information at a very quick rate, which allows the receiver to receive it and process it.

The amount of data transmitted to the receiver side without any acknowledgement is dealt with by flow control.

Thus, option C is correct.

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Answer:

The correct answer is A) Support Analyst

Explanation:

From the question, we can see that Roland is familiar with both machines and software. He is familiar with the operations of both parts of a computer to the end that he can attempt a fix. And if he can't he knows who to refer the end-users to. Usually, some IT personnel that is more experienced.

From the above points, we can safely say that Roland is an IT Support Analyst. He cannot be the Systems analyst because Systems Analysts are usually at the top of the Pyramid. They take on problems that are referred upwards to them from support analysts.

Cheers

Answer:

Header and footer

Explanation:

The page layout tab usually found in document programs such as Microsoft Word hold options used to configure several page options which is to be applied to a document. The page layout option gives users options to set page margins, orientation, page numbering, indentation and the other page layout options which is primarily how we would like our document to look like when printed. The page layout option also allows the insertion of a header and footer which is a note which can be written at the topmost and bottomost part of the document. Once, a header and footer option is selected, it is applied to every page of the document being worked on at the moment.

Answer:

The program in Python is as follows:

def ASCIIsum(str1,str2):

   asciisum1 = 0;    asciisum2 = 0

   for chr in str1:

       asciisum1 += (ord(chr) - 96)

   for chr in str2:

       asciisum2 += (ord(chr) - 96)

   if asciisum1 > asciisum2:

       return True

   else:

       return False

str1 = input("Enter first string: ")

str2 = input("Enter second string: ")

if ASCIIsum(str1,str2) == True:

   print(str1,"has a higher ASCII value")

else:

   print(str2,"has a higher ASCII value")

Explanation:

This defines the function

def ASCIIsum(str1,str2):

This initializes the ascii sum of both strings to 0

   asciisum1 = 0;    asciisum2 = 0

This iterates through the characters of str1 and add up the ascii values of each character

   for chr in str1:

       asciisum1 += (ord(chr) - 96)

This iterates through the characters of str2 and add up the ascii values of each character

   for chr in str2:

       asciisum2 += (ord(chr) - 96)

This returns true if the first string has a greater ascii value

   if asciisum1 > asciisum2:

       return True

This returns false if the second string has a greater ascii value

   else:

       return False

The main begins here

This gets input for first string

str1 = input("Enter first string: ")

This gets input for second string

str2 = input("Enter second string: ")

If the returned value is True

if ASCIIsum(str1,str2) == True:

Then str1 has a greater ascii value

   print(str1,"has a higher ASCII value")

If otherwise

else:

Then str2 has a greater ascii value

   print(str2,"has a higher ASCII value")

C. users to access and view web pages on the internet.

Answer:

The program is as follows:

[tex]mult\_table = [[1, 2, 3], [2, 4, 6], [3, 6, 9]][/tex]

count = 1

for row in mult_table:

   for item in row:

       if count < len(row):

           count+=1

           print(item,end="|")

       else:

           print(item)

   count = 1

Explanation:

This initializes the 2D list

[tex]mult\_table = [[1, 2, 3], [2, 4, 6], [3, 6, 9]][/tex]

This initializes the count of print-outs to 1

count = 1

This iterates through each rows

for row in mult_table:

This iterates through each element of the rows

   for item in row:

If the number of print-outs is less than the number of rows

       if count < len(row):

This prints the row element followed by |; then count is incremented by 1

           count+=1

           print(item,end="|")

If otherwise

       else:

This prints the row element only

           print(item)

This resets count to 1, after printing each row

   count = 1

To delete the whitespace, you have to print each element as:            print(item,end="|")

See that there is no space after "/"

Answer:

count = 1

for row in mult_table:

  for item in row:

      if count < len(row):

          count+=1

          print(item,end=" | ")

      else:

          print(item)

  count = 1

Explanation: Other answers didnt have the spacing correct

Answer:

Explanation:

C

kilo = 1000

mega = 1,000,000

giga = 1 billion = 1 000 000 000

tera = 1 trillion = 1 000 000 000  000

Answer:

oh nice yes good fine I like it

Answer:

Data use policies

Explanation:

Technically data use policies are not specifically made to protect user privacy, however it also should not violate user privacy. Data use policies are required by law. They are compulsory disclosures that list the various ways in which data in the form of personal data of individuals is collected, shared or used by digital companies(companies that operate on the internet, make use of email lists, etc ) are used.

Answer:

10 documents ^_^

Explanation:

I can open it at the same time on my laptop ●~●

Answer:

Here the code is given as follows,

Explanation:

def isPalindrome(x):

   stack = []

   #for strings with even length

   if len(x)%2==0:

       for i in range(0,len(x)):

           if i<int(len(x)/2):

               stack.append(x[i])

           elif stack.pop()!=x[i]:

               return False

       if len(stack)>0:

           return false

       return True

   #for strings with odd length    

   else:

       for i in range(0,len(x)):

           if i==int(len(x)/2):

               continue

           elif i<int(len(x)/2):

               stack.append(x[i])

           elif stack.pop()!=x[i]:

               return False

       if len(stack)>0:

           return false

       return True  

def main():  

   while True:  

       string = input("Enter a string or Return to quit: ")  

       if string == "":  

           break  

       elif isPalindrome(string):  

           print("It's a palindrome")  

       else:  

           print("It's not a palindrome")  

if __name__ == '__main__':  

   main()

Answer:

#include <stdio.h>

int main()

{

   int avg = 0;

   int sum =0;

   int x=0;

   /* Array- declaration – length 4*/

   int num[4];

   /* We are using a for loop to traverse through the array

    * while storing the entered values in the array

    */

   for (x=0; x<4;x++)

   {

       printf("Enter number %d \n", (x+1));

       scanf("%d", &num[x]);

   }

   for (x=0; x<4;x++)

   {

       sum = sum+num[x];

   }

   avg = sum/4;

   printf("Average of entered number is: %d", avg);

   return 0;

}

Answer:

The Open Software Foundation (OSF) was a not-for-profit industry consortium for creating an open standard for an implementation of the operating system Unix. It was formed in 1988 and merged with X/Open in 1996, to become The Open Group.

Explanation:

YOUR PROFILE PIC IS CUTE :)

Answer:

Explanation:

The following is written in Java. It uses File input, to get the file and read every line in the file. It adds all the lines into a variable called fullString. Then it uses regex to split the string into separate words. Finally, it maps the words into an array that counts all the words and how many times they appear. A test case has been created and the output can be seen in the attached image below. Due to technical difficulties I have added the code as a txt file below.

Answer:

Explanation:

Important functions of an operating System:  

Security –  

The operating system uses password protection to protect user data and similar other techniques. it also prevents unauthorized access to programs and user data.  

Control over system performance –  

Monitors overall system health to help improve performance. records the response time between service requests and system response to have a complete view of the system health. This can help improve performance by providing important information needed to troubleshoot problems.  

Job accounting –  

Operating system Keeps track of time and resources used by various tasks and users, this information can be used to track resource usage for a particular user or group of user.  

Error detecting aids –  

Operating system constantly monitors the system to detect errors and avoid the malfunctioning of computer system.  

Coordination between other software and users –  

Operating systems also coordinate and assign interpreters, compilers, assemblers and other software to the various users of the computer systems.  

Memory Management –  

The operating system manages the Primary Memory or Main Memory. Main memory is made up of a large array of bytes or words where each byte or word is assigned a certain address. Main memory is a fast storage and it can be accessed directly by the CPU. For a program to be executed, it should be first loaded in the main memory. An Operating System performs the following activities for memory management:  

It keeps tracks of primary memory, i.e., which bytes of memory are used by which user program. The memory addresses that have already been allocated and the memory addresses of the memory that has not yet been used. In multi programming, the OS decides the order in which process are granted access to memory, and for how long. It Allocates the memory to a process when the process requests it and deallocates the memory when the process has terminated or is performing an I/O operation.  

Processor Management –  

In a multi programming environment, the OS decides the order in which processes have access to the processor, and how much processing time each process has. This function of OS is called process scheduling. An Operating System performs the following activities for processor management.  

Keeps tracks of the status of processes. The program which perform this task is known as traffic controller. Allocates the CPU that is processor to a process. De-allocates processor when a process is no more required.  

Device Management –  

An OS manages device communication via their respective drivers. It performs the following activities for device management. Keeps tracks of all devices connected to system. designates a program responsible for every device known as the Input/Output controller. Decides which process gets access to a certain device and for how long. Allocates devices in an effective and efficient way. Deallocates devices when they are no longer required.  

File Management –  

A file system is organized into directories for efficient or easy navigation and usage. These directories may contain other directories and other files. An Operating System carries out the following file management activities. It keeps track of where information is stored, user access settings and status of every file and more… These facilities are collectively known as the file system.  

Answer:

The function is as follows:

int returnsFixed(int arr [],int n){

   int retVal = -1;

   for(int i = 0; i<n;i++){

       if(i == arr[i]){

           retVal = i;

           break;

       }

   }

   return retVal;

}

Explanation:

This defines the functionl it receives the array and the length of the array

int returnsFixed(int arr [],int n){

This initializes the return value to -1

   int retVal = -1;

This iterates through the array

   for(int i = 0; i<n;i++){

This checks if i equals arr[i]

       if(i == arr[i]){

If yes, the return value (i.e. the fixed point) is set to i

           retVal = i;

And the code is exited

           break;

       } This ends the if condition

   } This ends the iteration

This returns the calculated fixed point

   return retVal;

}

Answer:

caca

Explanation:

Answer:

Hence the answer is top and peek.

Explanation:

In a stack, we insert and delete an item from the top of the stack. So we use variables top, peek to stay track of the position.

The insertion operation is understood as push and deletion operation is understood as entering stack.

Hence the answer is top and peek.

Answer:

speed

accuracy

diligence

versatility

reliabiility

memory

speed: a computer works with more higher speed compared to humans when performing mathematical calculations

accuracy: computer perform calculations with 100% accuracy

dilligence:a computer can perform calculations with the same consistentcy and accuracy

versatility:refers to the capability of a computer to perform different kind of works with same accuracy and efficiencies

reliability

Answer:

speed

accuracy

diligent

versatile

storage and communication

Answer:

see the code snippet below writing in Kotlin Language

Explanation:

fun main(args: Array<String>) {

   sumOfNumbers()

}

fun sumOfNumbers(): Int{

   var firstNum:Int

   var secondNum:Int

   println("Enter the value of first +ve Number")

   firstNum= Integer.valueOf(readLine())

   println("Enter the value of second +ve Number")

   secondNum= Integer.valueOf(readLine())

   var sum:Int= firstNum+secondNum

  println("The sum of $firstNum and $secondNum is $sum")

   return sum

}

Answer:

are better data entry designs than entering data directly to a table. ... hence a user can design input fields linked to several tables/queries.

Explanation:

Input screens are better data entry designs than entering data directly to a table because a user can design input fields linked to several tables/queries.

Digital information generally consists of data that is created or prepared for electronic systems and devices such as computers, screens, calculators, communication devices. These information are stored by cloud.

They are converted from digital to analog and vice versa with the help of a device.

Data entered in the table directly is easier than data entry method.

Thus, input screens are better data entry than entering data directly to a table.

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Answer:

a. Youthful

Explanation:

The river gets its water from youth stage fluvial water. The river meanders from side to side. East Brownsville will be less stable in international boundary in terms of physical position on the landscape because its base level drops.