which of the functions in memory is more likely to be the interrupt service routine (isr) for handling system calls?

Answers

Answer 1

The functions in memory is more likely to be the Interrupt Service Routine (ISR) for handling system calls are f4 and f8

What is Interrupt Service Routine?

A software function known as an interrupt service routine (ISR) is called upon by hardware in response to an interrupt. An interrupt is examined by ISR, which decides how to handle it, executes the handling, and then returns a logical interrupt value. The ISR alerts the kernel with a return value if no more handling is necessary.

Reason:

Sending a Unix signal to the process that developed a variant allows for the handling of several variations. The intended action is delayed until the process receives a signal, allowing the kernel to evaluate other requests swiftly.

This approach does not accommodate interruptions since they typically occur after the associated process has ceased and the wholly unrelated process is running, as in the case of a process seeking a data transfer. Sending a Unix signal to the active process is therefore improper.

The handling of disruptions relies on the nature of interruption. We will categorize the three basic types of interruption for our needs as follows:

I/O causes disruptions.

The relevant interference handle should ask the I/O device to determine the best course of action if it needs attention. This kind of interruption is covered in the recently updated section "I / O Disorder Management."

Time is of the essence.

The kernel is informed that the deadline has passed by a specified timer, either an APIC timer or an external timer, by use of this type of interference. The majority of these illnesses are addressed as I/O disorders.

Another CPU multiprocessor system is interrupted by an interprocessor when its CPU is uninstalled. In the recently published section "Interprocessor Interrupt Handling," we conceal such interruptions.

Managing I/O Disruption

The I/O interfering adapter should typically be adaptable enough to support many devices simultaneously. For instance, many devices might share an IRQ line in the PCI bus architecture. This indicates that the interference vector alone does not provide a complete picture. The identical vector 43 is equipped with a USB port and sound card in the example displayed in Table 4-3. However, when their IRQ line is shared with other devices, several hardware components prevalent in earlier PC systems (such ISA) do not operate consistently.

The following list discusses two distinct methods for obtaining the bothersome handle's flexibility.

shared IRQ

Multiple interference lines are produced by the intrusion (ISRs). Each ISR is a feature connected to a single shared IRQ line device. Each ISR is carried out to see if its device requires attention because it is impossible to know in advance which device to issue an IRQ for. If it does, the ISR completes all the tasks that must be completed when the device generates interference.

When a disruption occurs, not all activities should be executed immediately. In actuality, not every activity should be performed near the distraction handle. Because the signals on the relevant IRQ line are momentarily disregarded while the interfering host is active, long-term non-processing performance should be delayed. Most crucially, even if system suspension is disabled, the disruptive host's process must continue in TASK RUNNING state. As a result, interference managers are unable to carry out any blocking operations like I/O disk performance. Linux divides post-disruption activities into the following three groups:

Actions that are crucial, such admitting PIC interference, redistributing the PIC or device controller, or updating the device's data acquisition and processor. Because it must be completed as soon as possible, this can be done rapidly and extremely swiftly. Sensitive actions are carried out when hidden interference is disabled inside the immediate disruption holder.

Not attentive

modifying data structures that are solely visible to the processor, for example (for example, reading a scan code after a push-key keyboard). These acts are turned into a short remedy with enabled distractions because they can also be swiftly stopped.

It is not indirectly transferred.

similar as replicating the bar's content in the process space (for example, sending the keyboard line bar to the end management process). Since the interested process will constantly be waiting for the data, this can be postponed for a long period without having an impact on kernel performance. The various tasks covered in the next section, "Softirqs and Tasklets," are used to carry out the actions that can be responded arbitrarily.

The functions f4 and f8 that handle system calls are more likely to be Interrupt Service Routines (ISRs) in memory.

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Which Of The Functions In Memory Is More Likely To Be The Interrupt Service Routine (isr) For Handling

Related Questions

Factorise 7t² - 19t - 6.
(2 marks)

Answers

Answer:

(t + 3)(7t - 2)

Step-by-step explanation:

7t² - 19t - 6

consider the factors of the product of the coefficient of the t² term and the constant term which sum to give the coefficient of the t- term

product = 7 × - 6 = - 42 and sum = - 19

the factors are 21 and - 2

use these factors to split the t- term

7t² + 21t - 2t - 6 ( factor the first/second and third/fourth terms )

7t(t + 3) - 2(t + 3) ← factor out (t + 3) from each term

(t + 3)(7t - 2) ← in factored form

A circle of center (-3 , -2) passes through the points (0 , -6) and (a , 0). Find a.

Answers

The radial distances from the center (-3, -2), to the points on the circumference (0, -6), and (a, 0), found using the distance formula, indicates that a = -3 ± √21

What is the distance formula for finding the distance between locations on the coordinate plane?

The distance between points (x₁, y₁), and (x₂, y₂), on the coordinate plane, can be found using the formula; d = √((x₂ - x₁)² + (y₂ - y₁)²).

The coordinates of the center of the circle = (-3, -2)

The coordinates of the locations (on the circumference of the circle), through which the circle passes = (0, -6) and (a, 0)

Therefore the distances between points (0, -6) and (-3, -2) and (a, 0) and (-3, -2) are the same;

The distance from (0, -6) to (-3, -2) = The distance from (a, 0) to (-3, -2)

(-3 - 0)² + (-2 - (-6))² = (-3 - a)² + (-2 - 0)²

25 = a² + 6·a + 9 + 4 = a² + 6·a + 13

a² + 6·a + 13 = 25 (symmetric property)

a² + 6·a + 13 - 25 = 0

a² + 6·a - 12 = 0

a = (-6 ± √(6² - 4×1×(-12)))/(2×1) = (-6 ± √(84))/2

a = (-3 ± √(21))

a ≈ 1.58 and a ≈ -7.58

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If m∠B = 62°, a = 11, and c = 19, what are the measures of the remaining side and angles?

Answers

The remaining side is 16.9 and remaining angles are 83.1 and 34.9.

What is Cosine Formula?

The cosine formula to find the side of the triangle is given by:

c = √[a² + b² – 2ab cos C] Where a,b and c are the sides of the triangle.

Given:

m∠B = 62°, a = 11, and c = 19

Now, b² = a² + c² - 2ac cos B.

b = √ a² + c² - 2ac cos B

b = √ 11² + 19² - 2x 11  x 19 cos 62

b= 16.9

Now. a/ sin A = b/ sin B= c/ sin C

So, <C = arc sin ( c sin B /b)

<C = arc sin ( 19 sin 62 /16.9)

<C = 83.1

and, <A = arc sin ( a sin B /b)

<A = arc sin ( 11 sin 62 /16.9)

<A = 34.9

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Let x be a random variable with pdf f(x) = 12/x^3 , x≥a. Find the value of the constant a (round off to second decimal place).

Answers

The value of constant a is 2.45.

To find the value of the constant a, we need to make sure that the pdf (probability density function) is properly normalized. The pdf must satisfy the following property:

∫[a, ∞] f(x) dx = 1

In this case, we have pdf:

∫[a, ∞] (12/x^3) dx = 12∫[a, ∞] (1/x^3) dx

= 12 [-1/(2x^2)]ₐ∞

= 12 * (1/(2a^2))

= 6/ a²

Therefore, to ensure that the integral is equal to 1, we need:

6/ a² = 1

Solving for a:

a^2 = 6

a = ±√6

Since x is always positive, we have a = √6 ≈ 2.45.

So, the constant a is equal to 2.45.

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Which substantive audit sampling technique uses a statistical sampling approach?
Stratified sampling.
Attribute sampling.
Monetary Unit
Sampling or MUS.

Answers

The substantive audit sampling technique uses a statistical sampling approach is Sampling or MUS.

Sampling is a powerful tool in auditing as it allows the auditor to make conclusions about the population without having to test all the transactions, balances or data.

Substantive audit sampling refers to the use of samples in an audit process to make conclusions about a population of transactions, balances or other data.

There are three main substantive audit sampling techniques: Stratified Sampling, Attribute Sampling and Monetary Unit Sampling.

Monetary Unit Sampling or MUS is a statistical sampling approach that focuses on the monetary value of transactions.

The auditor will select a sample of transactions and calculate the expected deviation rate.

This technique is used when the auditor is focused on testing material balances and ensuring that they are correct.

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Please help me with this math problem! Will give brainliest!! :) 20 POINTS!!

Answers

Using the area of the rectangle and circle, the shaded area is equal to 6.88 squared units

What is the area of the shaded region

To determine the area of the shaded region, we can simply find the area of the rectangle and the area of the circle.

The formula of area of the rectangle;

Assuming the width is half the length

Area of rectangle = length * width

Area of rectangle = 8 * 4

Area of rectangle = 32 squared units.

Area of circle = πr²

r = radius of the circle

In this problem, the diameter of the circle is the width of the rectangle or rather, the diameter of the circle is half the length of the the rectangle.

d = 8 / 2 = 4 units

radius = diameter / 2

radius = 4 / 2 = 2 units

Substituting the values into the formula

A = πr²

A = 3.14 * 2²

A = 3.14 * 4

A = 12.56 squared units.

The non-shaded area = 2 * 12.56 = 25.12 squared units.

The shaded area = area of rectangle - non-shaded area

The shared area = 32 - 25.12

The shaded area = 6.88 squared units.

b.

The approximated area to the nearest tenth is 6.9 squared units

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a box of ice cream has a volume of 1.75 quarts. what is the volume in units of cubic inches?

Answers

The volume in units of cubic inches is 101.63 cubic inches.

Unit conversion is a process with multiple steps involving multiplication or division by a numerical factor, particularly a conversion factor. The procedure may also demand the selection of the correct number of substantial digits and rounding. Different units of conversion are used to calculate different parameters.

We convert the units of any quantity to understand better. For example, the length of a table is measured in inches; on the other hand, the length of a garden is measured in yards to make it simple to comprehend. We cannot calculate the length of a finger in miles.

1 quart is equal to 57.75 cubic inches. So, to convert a volume of 1.75 quarts to cubic inches, we multiply by 57.75:

1.75 quarts × 57.75 cubic inches/quart = 101.63 cubic inches

Therefore, the volume of the box of ice cream in cubic inches is 101.63 cubic inches.

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In a certain​ chemical, the ratio of zinc to copper is 4 to 11 . A jar of the chemical contains 539 grams of copper. How many grams of zinc does it​ contain?

Answers

Answer:

196 grams of zinc

Step-by-step explanation:

[tex]\frac{4}{11}=\frac{z}{539}\\ \\(539)(4)=11z\\\\2156=11z\\\\196=z[/tex]

Thus, the jar of the chemical will contain 196 grams of zinc.

Solve the inequality for x and identify the graph of its solution. |x+2l <2
Choose the answer that gives both the correct solution and the correct graph.
(I attached an image)

Answers

Thus, the solution of the inequality is x > -4 or x < 0.

The graph of the solution is option B.

How to solve and graph an inequality?

An inequality is a relationship that makes a non-equal comparison between two numbers or other mathematical expressions e.g. 2x > 4

Because of absolute sign | |, the inequality |x+2l <2 can be written as:

x+2 <2 or -(x+2) <2

For x+2 <2:

x+2 <2

x < 2-2

x < 0

For -(x+2) <2:

-(x+2) <2

-x - 2 < 2

-x < 2+2

-x < 4

x > -4

Thus, the solution is x > -4 or x < 0.

The graph of the solution is option B because x > -4 or x < 0 can be written as -4<x<0, which shows the value of x is between -4 and 0.

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8. The Nebraska license plate has 6 characters. The first three are letters A thru Z. The second
three are numbers 0 thru 9. How many different license plates could there be without repetition?
(page 3 problems 11, 12a, and 12b)
Six digit license plate:
_
lotter
number number number

Answers

Answer:

Below

Step-by-step explanation:

First position   26 possibilities

 second    25

   third   24

       fourth  10

           fifth   9

              sixth 8          

     multiply all of these numbers together = 11 232 000 possible plates

Does anybody know the answer? In the transformation ABC → A'B'C', the prelmage of B' Is__________ Type the answer in the space provided.

Answers

In the transformation ABC → A'B'C', the preimage of B' is B.

What is a transformation?

In Mathematics, a transformation can be defined as the movement of a point from its original (actual) position to a final (new) location. This ultimately implies that, when an object (pre-image) is transformed, all of its points would be transformed as well to form a new image.

What are the types of transformation?

Generally, there are four (4) major types of transformation and these include the following:

ReflectionTranslationRotationDilation

In this context, we can reasonably infer and logically deduce that corresponding vertices, points, or coordinates would be matched together in any type of transformation such as the following:

Point A → Point A'.

Point B → Point B'.

Point C → Point C'.

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y=9x^2 + 9x - 1 rewritten in vertex form

Answers

The vertex form of given expression  y=9x² + 9x - 1  is y = 9 ( x + 1/2  )² - 13 / 4

What is Algebraic expression ?

Algebraic expression can be defined as the combination of variables and constants.

Given expression,

y = 9x² + 9x - 1

complete the square for 9x² + 9x - 1

Use the form ax²+ bx +c , to find the values of a,b,c

a = 9 b = 9 c = -1

Consider the vertex form of a parabola

a ( x+d )² + e

Find the value of d using the formula d = b / 2a

d = 9 / 2.9

d = 1 / 2

So, now we have to find the value of e suing the formula

e = c - b²  / 4a

e = -1 - 9*9 / 4*9

e = -13/ 4

Substitute the values a,d and e into the vertex form

9 ( x + 1/2  )² - 13 / 4

So,

y = 9 ( x + 1/2  )² - 13 / 4

Therefore, The vertex form of given expression  y=9x² + 9x - 1  is

y = 9 ( x + 1/2  )² - 13 / 4

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the critical region for a hypothesis test consists of . group of answer choices outcomes that have a very low probability if the null hypothesis is true outcomes that have a high probability if the null hypothesis is true outcomes that have a very low probability whether or not the null hyposthesis is true outcomes that have a high probability whether or not the null hypothesis is true

Answers

The critical region for a hypothesis test consists of outcomes that have a very low probability if the null hypothesis is true. This means that if the null hypothesis is true, these outcomes should not occur. The critical region is used to decide when to reject the null hypothesis and accept the alternative hypothesis.

Hypothesis testing is a process used in statistics to determine whether a certain claim or hypothesis is valid. It involves collecting data, analyzing the data, and making decisions based on the analysis of the data. The goal of hypothesis testing is to either reject or accept a null hypothesis, which is an assumption that there is no relationship between two measured phenomena. Hypothesis testing can also be used to compare two groups or to determine the effectiveness of a treatment or intervention.

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Which of the following statements regarding the expansion of (x + y)" are
correct?
A. The coefficients of xay and xbya are equal.
B. The coefficients of x-1 and y-1 both equal 1.
C. The coefficients of x" and y both equal 1.
D. For any term xay in the expansion, a - b = n.

Answers

The true statement is (c). The coefficients of x^n and y^n are both equal

How to determine the true statements

From the question, we have the following parameters that can be used in our computation:

(x + y)^n

When the above expression is expanded, we have

(x + y)^n = x^n + ..... + y^n

See that the coefficients of x^n and y^n is 1

This means that they have equal coefficient of 1

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A cold front lowered the temperature
from 23° to -2°. What was the change
in temperature?

Answers

Answer:

25 degree

Step-by-step explanation:

23 - 25 = -2 degree

So, the temperature change is 25 degrees.

Emmy jogged 1/4 of a lap in P.E. class and 1/2 of a lap during track practice. How many laps did Emmy jog in all?

Answers

Answer:

3/4 of a lap

Step-by-step explanation:

You have to find the LCD (lowest common denominator)

That is 4, so your equation will be:

[tex]\frac{1}{4} + \frac{1}{2} = x\\\\\frac{1}{4} + \frac{2}{4} = x \\\\\frac{3}{4} = x[/tex]

the probability of a certain event, event a, is equal to 0.01. another event, event b, has a 0.2 likelihood of occurring. if events a and b are mutually exclusive, what is the probability of the union of events a and b?

Answers

The probability of the union of events a and b is 0.21. the sum of their individual probabilities : P(a ∪ b) = 0.01 + 0.2 = 0.21.  Events a and b are mutually exclusive, it means that they cannot both happen at the same time.

In the event that occasions an and b are totally unrelated, it implies that the two of them can't occur simultaneously. In this way, the likelihood of their association (that is, the likelihood that either occasion an or occasion b will happen) is the amount of their singular probabilities:

P(a ∪ b) = P(a) + P(b)

Considering that P(a) = 0.01 and P(b) = 0.2, we can ascertain the likelihood of their association:

P(a ∪ b) = 0.01 + 0.2 = 0.21

In this way, the likelihood of the association of occasions an and b is 0.21.

The likelihood of occasion An incident is 0.01 and the likelihood of occasion B happening is 0.2. Assuming that these occasions are fundamentally unrelated, it implies the two of them can't occur simultaneously. The complete opportunity of either occasion An or occasion B happening is found by including the singular probabilities. In this way, the likelihood of occasion An occurrence or occasion B happening is 0.01 + 0.2 = 0.21. In basic terms, the opportunity of either occasion happening is 0.21.

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Use the graph of the function to find its domain and range. Write the domain and range in interval notation.

Answers

Domain: (-6, -1]

This is where the graph lines up with the x-axis.

Range: [-6, 4)

This is where the graph lines up with the y-axis.

See the two pictures for a visual reason why.

Special right triangle need help pls

Answers

Therefore , the solution of the given problem of triangle comes out to be sides are a = 10 and b=5√3.

What exactly does a triangle mean?

Due to their four sides or more, triangles are considered polygons. It has a straightforward, geometric form. A triangle is a square angle formed by the letters ABC. A singular rectangle or square is produced by Euclidean geometry when the sides are still not collinear. Triangles are polygons because they have three sides and three corners. Where three sides of a triangle come together are its corners. A triangle's angles sum up to 180 degrees.

Here,

Given :

A right triangle is :

=> 5 , b and a

has 30 degree angle .

=> Sin 30° = 5/a

=> 1/2 = 5/a

=> a = 10

Thus,

Using pythagoras theorem ,

=> 10² = 5² + b²

=> 100 -25 = b²

=>  b² = 75

=> b = 5√3

Thus , sides comes out to be a = 10 and b=5√3

Therefore , the solution of the given problem of triangle comes out to be sides are a = 10 and b=5√3.

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A factory sampled hundreds of 9oz bags of chips off of one of their production lines to make sure the bags had the appropriate
amount of chips. They found the amount of chips to be normally distributed with = 9.12 ounces and o= .05 ounces.
PART A
Given this information, fill out the normal distribution chart below for the weight of 9oz bags of chips from this factory.

Answers

The probability that a bag of chip is lower than 9.07 oz of weight is 0.1587.

What is Normal Distribution ?

A continuous probability distribution for a real-valued random variable is called a normal distribution or a Gaussian distribution.

An example of a continuous probability distribution is the normal distribution, in which the majority of data points cluster in the middle of the range while the remaining ones taper off symmetrically toward either extreme. The distribution's mean is another name for the center of the range.

The normal distribution defines how a variable's values are distributed, just like any probability distribution does. Because it properly depicts the distribution of values for many natural occurrences, it is the most significant probability distribution in statistics.

the mean of the data = 9.12 oz

The SD = 0.05 oz

The probability of the bag to be less than 9.07 oz

x = 9.07

z = x - mean / SD = 9.07 - 9.12/0.05 = - 1

for z = -ve

Ф(z) = 1 - Ф(-z) = 1 - Ф(1) = 1 - 0.8413 = 0.1587

The probability that a bag of chip is lower than 9.07 oz of weight is 0.1587.

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HELP WILL MARK BRAINLIEST!!!!

Answers

The nth value equals 1 more than twice the previous value.

This statement correctly describes the sequence {1, 3, 7, 15, ...}, as each value in the sequence is 1 more than twice the previous value.

if lim f(x)=5, miust be defined at x=1?

Answers

Yes, if function f(x) = 5, then f is defined for all x, including x = 1.

Yes, f is defined for every x, including x = 1, if f(x) = 5. And if f is defined at x = 1, then f(1) = 5. The equation f(x) = 5 means that the function f takes on the value 5 for all x, so if the function is defined at x = 1, its value at that point must be 5.

The term "function" refers to a relationship between a set of inputs and outputs. To put it simply, a function is a relationship between inputs where each input is associated to exactly one output.

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please help bless you !

Answers

Answer:

A = 20, therfore B = 180

Step-by-step explanation:

Technically it's 17 but that is a really awkward scale so I had to round up. This really annoys me because if there was one more box you could had the scale 15 and it would've looked so much nicer but unfortunate you're short one

which abelian groups are isomorphic to subgroups of s6

Answers

The subgroups of S6 include the following abelian groups: Z₁, Z₂, Z₃, Z₆, Z₂ x Z₂, and Z₃ x Z₂

A subgroup of a group is isomorphic to another group if there is a bijective homomorphism between the two groups, meaning there is a one-to-one correspondence between their elements that preserves the group operation. In this case, the subgroup of S6 (the symmetric group on 6 elements) is isomorphic to one of the abelian groups.

It is known that the number of subgroups of a finite group is bounded above by the number of its elements, so there are only finitely many possible subgroups of S6 to consider. The most common abelian groups are the cyclic groups Zₙ, and any group that is isomorphic to a direct sum of cyclic groups is also abelian.

It is known that the subgroups of S6 include the following abelian groups: Z₁, Z₂, Z₃, Z₆, Z₂ x Z₂, and Z₃ x Z₂. These are the only abelian groups that can be isomorphic to subgroups of S6. Note that there may be non-abelian subgroups of S6 as well.

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which of the following would be a line of reflection that would map abcd onto itself? square abcd with c at 1 comma 3, d at 1 comma 1, a at 3 comma 1, and b at 3 comma 3. y = 1 2x + y = 2 x + y = 4 x + y = 1

Answers

The line of reflection would be x+y =4, Hence the correct option is C.

The equation of a line's standard form is given as follows:

[tex]y = mx+c[/tex]

Where m is the slope and c is the y-intercept of the line.

The slope can be determined by

[tex]m =\dfrac{(y_2 - y_1)}{(x_2 - x_1)}[/tex]

Now, Along its diagonals should be reflected in order to reflect it back to itself.

The diagonals will pass through the points [tex]A(3, 1)[/tex] and [tex]C( 1,3)[/tex]

Hence, The slope of the line is,

[tex]m =\dfrac{(y_2 - y_1)}{(x_2 - x_1)}[/tex]

[tex]m =\dfrac{(3 - 1)}{(1 - 3}[/tex]

[tex]m =\dfrac{(2)}{(- 2)}[/tex]

[tex]m = - 1[/tex]

Hence, The equation of the line AC,

[tex](y - y_1) = m(x-x_1)[/tex]

It passes through the point (1,3)

[tex](y - 3) = -1( x-1 )[/tex]

[tex]y - 3 = -x +1[/tex]

[tex]y +x =4[/tex]

Therefore, Option C is true.

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Solve the following equation
{5-b}{12-5b}=0

Answers

The equation {5-b}{12-5b}=0 can be solved by setting each factor equal to zero and solving for b.

First, we set 5-b = 0, which gives b = 5.

Next, we set 12-5b = 0, which gives b = 12/5 = 2.4.

So the solutions to the equation are b = 5 and b = 2.4
Set both brackets equal to zero
(5-b)=0
(12-5b)=0
For the fist equation :(5-b)=0
Remove brackets and add b to both sides 5=b
For the second equation:(12-5b)=0
Remove the brackets and add 5b to each side
12=5b
Divide each side by 5
12/5=b
Therefore b=5 or b=2.4

which expression has the same value as 1 2/3 + (-8 1/2)

Answers

Answer:

(-41)/6 or -6 5/6 as a mixed fraction

Step-by-step explanation:

Simplify the following:

1 + 2/3 - (8 + 1/2)

Put 8 + 1/2 over the common denominator 2. 8 + 1/2 = (2×8)/2 + 1/2:

1 + 2/3 - ((2×8)/2 + 1/2)

2×8 = 16:

1 + 2/3 - (16/2 + 1/2)

16/2 + 1/2 = (16 + 1)/2:

1 + 2/3 - ((16 + 1)/2)

16 + 1 = 17:

1 + 2/3 - 17/2

Put 1 + 2/3 - 17/2 over the common denominator 6. 1 + 2/3 - 17/2 = 6/6 + (2×2)/6 + (3 (-17))/6:

6/6 + (2×2)/6 + (3 (-17))/6

2×2 = 4:

6/6 + 4/6 + (3 (-17))/6

3 (-17) = -51:

6/6 + 4/6 + (-51)/6

6/6 + 4/6 - 51/6 = (6 + 4 - 51)/6:

(6 + 4 - 51)/6

6 + 4 = 10:

(10 - 51)/6

10 - 51 = -(51 - 10):

(-(51 - 10))/6

| 5 | 1

- | 1 | 0

| 4 | 1:

Answer:  (-41)/6

I NEED HELP ASAP!!!
How many boxes would Alan have to sell to earn less than $2050?

Answers

Answer: Alan would have to sell less than 540 boxes.

Step-by-step explanation:

Let X be a random variable with the following PDF:fX​(x)= Cx^2;∣x∣≤1 0;otherwise​Find Var(X).2/54/53/5none of these

Answers

The Var (X) for the random variable X with probability density function

f ₓ(x) = Cx² for |x| ≤ 1 is equal to 3/5.

Probability density function (pdf) :

f ₓ(x) = Cx² for |x| ≤ 1

            0 other wise

[tex]\int\limits^a_b {f(x)} \, dx = 1[/tex]

⇒ [tex]\int_{-1}^{1}Cx^{2}[/tex] = 1

⇒ C (x³ /3) [tex]|_{-1}^{1}[/tex] = 1

⇒ C/3 (  1 - (-1 )) = 1

⇒(2/3) C = 1

⇒ C = 3/2

Now,

E(x) = [tex]\int_{-1}^{1}x (3/2)x^{2}dx[/tex]

      = (3/2)[tex]\int_{-1}^{1}x^{3}dx[/tex]

      = ( 3/2) ( x⁴ /4 ) [tex]|_{-1}^{1}[/tex]

      = 0

Var (X) = [tex]\int_{-1}^{1}x^{2} (3/2)x^{2}dx[/tex] - [E(x)]²

           = (3/2) [tex]\int_{-1}^{1} x^{4}dx[/tex]  -0

           = (3/2) ( x⁵ /5 )[tex]|_{-1}^{1}[/tex]

           = (3/2 ) ( 1/5 + 1/5)

           = 3/5

Therefore, the Var (X) of the probability density function for the random variable X is equal to 3/5.

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I don’t understand how to simplify this problem.

Answers

The simplified dorm of the expression [tex]\frac{\sqrt{15}}{5\sqrt{48}}\times\frac{\sqrt{48}}{\sqrt{48}}[/tex] is √720/240.

What are surds and indices?

We know there are two types of radicals one is surds when the number has been raised by such power that it is greater than zero and less than one,

The other type of radicals are indices where a number is raised to such power that is greater than one.

Given, A radical expression [tex]\frac{\sqrt{15}}{5\sqrt{48}}[/tex].

Therefore,

[tex]\frac{\sqrt{15}}{5\sqrt{48}}\times\frac{\sqrt{48}}{\sqrt{48}}[/tex].

= (√15×√48)/(5×48).

= √720/240 or √720×(1/240).

learn more about surds and indices here :

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