which of the three organizational forms – projectized, matrix, or functional – is most suited for aligned project accountability and authority, and for rapid reaction to customer needs?

We will multiply the first 7×1 =7. Option A is the correct option.

What is a table?

An array displaying the outcomes of multiplying two numbers.

The results are displayed where a row and a column converge. One number runs along a row, the other down a column.

Information is organized in rows and columns, such as numbers and descriptions.

This table lists the sports that people participate in.

The table for 7:

7×1 = 7

7×2 = 14

7×3 = 21

7×4 = 28

7×5 = 35

7×6 = 42

7×7 = 49

7×8 = 56

7×9 = 63

7×10 = 70

According to the table, we first multiply 7×1  then 7×2.

Thus 7×1 =7 is the correct answer.

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With the money they have left, the students in M. Houton's fifth grade class of 20 students can buy 32 foils.

This is calculated by subtracting the cost of the transportation from the total amount raised ($128 - $5*20 = $28) and then dividing that amount by the cost of each foil ($4). Therefore, the students can buy $28 / $4 = 32 foils.

To calculate how many foils the students in M. Houton's fifth grade class of 20 students can buy with the money they have left, you must subtract the cost of their transportation from the total amount raised ($128 - $5*20 = $28).

Then, divide the remaining amount by the cost of each foil ($4) to get the number of foils they can buy with the money they have left ($28 / $4 = 32 foils).

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A horse has a greater heart rate.

To compare the heart rate of two animals, we need to convert the number of beats per minute (bpm).

A horse's heart beats 440 times in 10 minutes, which is equivalent to 44 bpm (440 beats / 10 minutes).

A cow's heart beats 390 times in 6 minutes, which is equivalent to 65 bpm (390 beats / 6 minutes).

So, we can see that a horse has a heart rate of 44 bpm, while a cow has a heart rate of 65 bpm. Hence, a cow has a greater heart rate compared to a horse.

Generally, ini animal subject, not always calculate like this. This comparison is specific to horses and cows. The heart rate of different species of animals can vary significantly, and it is not possible to make a general statement about the heart rate of all animals based on the comparison of just two species. Additionally, the heart rate of animals can vary based on factors such as age, weight, stress, and activity level, among others.

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Answer: Hi there! X = 7 would be your answer

Step-by-step explanation:

Simplify both sides of the equation.

2(3x − 6) = 3(x + 3)

(2) (3x) + (2) (−6)= (3) (x) + (3) (3)

6x + −12 = 3x + 9

6x − 12 = 3x + 9

Subtract 3x from both sides.

6x − 12−3x = 3x + 9−3x

3x − 12 = 9

Add 12 to both sides.

3x − 12+12 = 9+12

3x=21

Divide both sides by 3.

3x/3=21/3

x=7

I hope this helps!!

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hope it helps!:)

A ordered pair that satisfies the inequality statement serves as the solution for linear inequalities involving two variables.

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The function value that us greater is with estimated value of 96

The estimated value is the value read from the graph which gives the accumulated value for each of the line

The first line gives an estimated value of

10+14+18+19+28 = 89

The second graph gives gives an estimated value of

17+18+19+20+22 = 96

Therefore comparing the two graphs, the one with 96 has the greater value

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The border must have a width of 10 meters.

We first have a rectangular lawn of 10m by 5m, so if we have a border with a width of x meters, the area of the border is given by:

A = 10m*x + 5m*x

Where we compute the area in that way because the flowers will be only on two adjacent sides of the rectangle.

And the area is 150 m^2, then we will get:

150m^2 = 10m*x + 5m*x

150m^2 = 15m*x

150m^2/15m = x

10m = x

The border has a width of 10 meters.

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Answer:

number of senior tickets = 239

number of junior tickets = 187

Step-by-step explanation:

let 's' = number of senior tickets

let 'j' = number of junior tickets

20s + 30j = 10390

s + j = 426

we could use the substitution method to solve the system by making

s = 426-j

we can substitute '426-j' in for 's' in the first equation to get:

20(426-j) + 30j = 10390

8520 - 20j + 30j = 10390

8520 + 10j = 10390

10j = 1870

j = 187

s + 187 = 426

s = 239

The truth value of the given statements if the universe of discourse of each variable is the set of real numbers are 1. false, 2. false, 3. true, 4. false, 5. false, 6. false, 7. true, 8. true, 9. false, 10. true, 11. true, and 12. true.

1. False. There is no real number x such that x^2 = -1.

2. False. For any x in the real numbers, there exists a y such that xy ≠ 1. For example, if x ≠ 0, then y = 1/x will satisfy xy ≠ 1.

3. True. For any real number x, the real number y = x^2 satisfies the equation x^2 = y.

4. False. For any x and y in the real numbers, x + y = y + x.

5. False. For any x in the real numbers, there exists a y such that xy ≠ 0. For example, if x ≠ 0, then y = 1/x will satisfy xy ≠ 0.

6. False. There is no real number y such that y^2 = -1.

7. True. For any x and y in the real numbers, the real number z = x + y^2 satisfies the equation z = x + y^2.

8. True. For any x ≠ 0 in the real numbers, the real number y = 1/x satisfies the equation xy = 1.

9. False. There is no real number x such that x^2 = 2.

10. True. For any x in the real numbers, the real number y = 1 - x satisfies the equation x + y = 1.

11. True. The solution to the system of equations x + 2y = 2 and 2x + 4y = 5 is x = -1 and y = 3.

12. True. For any x in the real numbers, the real number y = (1 - x)/2 satisfies the equation (x + y = 2) and (2x - y = 1).

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Answer:

it is 27

Step-by-step explanation:

because we need to add 27 and the 7m

The total electric flux linked with the cube is .

Electric flux is a characteristic of an electric field and refers to the quantity of electric lines of force (or electric field lines) that span a given area. This hypothesis states that electric field lines have positive electric charges at the beginning and negative electric charges at the end. Field lines pointing toward a closed surface are deemed negative, whereas those pointing away from it are deemed positive.

The electric field inside a charged conductor is zero, and since the wire is a conductor, the electric field inside the cube is zero.

Hence, the total electric flux linked with the cube is also zero.

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I earn $12 in interest after 12 years while my friend earns the same amount in 4 years.

Simple interest is an interest charge that borrowers pay lenders for a loan. It is calculated using the principal only and does not include compounding interest. Simple interest relates not just to certain loans. It's also the type of interest that banks pay customers on their savings accounts.

Given here: My principal = $50 and friend's =$50 also friend's account earns 6% annual interest rate

As per question we get

let the time taken to earn $12 interest rate be t then

12=50×2×t /100

t=12 years

while for my friend

12=50×6×t /100

3t=12

t=4 years

Hence, I earn $12 in interest after 12 years while my friend earns the same amount in 4 years.

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The requried simplified value of the given exponential expression is 1.

The function which is in format f(x) =aˣ where a is constant and x is variable,  the domain of this exponential function lies   (-∞, ∞).

Here,
F = [25x²y¹⁴w³]⁰

Since a⁰ = 1
F = 1

Thus, the requried simplified value of the given exponential expression is 1.

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The result after the endpoint of a line segment is reflected is (-5. -10)

From the question, we have the following parameters that can be used in our computation:

Point = (-5, 10)

The reflection rule is given as

Reflection across the x-axis

Mathematically, this is represented as

(x, y) = (x, -y)

So, we have

Image = (-5, -10)

Hence, the image is (-5, -10)

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The rate of change of f '(x) at (2, 20) is -52

We are given f(x) = 7x² − x³ and are asked to find the rate of change of f'(x) at (2, 20)

We can use the slope formula to find the average rate of change:

                        m = y2-y1/x2-x1

Here we need to find

                     Rate of change = f'(x2) - f'(x1) / x2 - x1

and here x1 = 2 and x2 = 20

First, we need to find f'(x)

                            f'(x) = 14x - 3x²

                           f'(x1) = f'(2) = 16

                           f'(x2) = f'(20) = -920

So, Rate of change = f'(x2) - f'(x1) / x2 - x1 = (-920 - 16)(20 - 2)

                                                                    = -52

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If you join Gym A, it will cost $20 to join for 1 month plus $3 per visit. If you visit the gym x times, your total cost will be 20 + 3x dollars.

If you join Gym B, it will cost a flat rate of $40 for 1 month.

To determine which membership is more cost-effective, you would need to compare the costs for different number of visits. For example, if you plan to visit Gym A 10 times in a month, your total cost would be 20 + 3(10) = $50. If you plan to visit Gym B only 2 times in a month, membership B is more cost-effective. If you plan to visit more than 13 times, membership A is more cost-effective.

It would be helpful to make a table with different number of visits to compare the cost of both gym memberships.

C) randomized block experimental design.

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Answer:c

Step-by-step explanation:

Yes, a triangle can be formed with side lengths of 3 inches, 3 inches, and 5 inches.

A triangle can be formed if and only if the sum of the lengths of any two sides is greater than the length of the third side. In this case, the sum of the lengths of sides 3 inches and 3 inches (6 inches) is greater than the length of the third side (5 inches), so a triangle can be formed.

In summary, a triangle can be formed with side lengths 3 inches, 3 inches, and 5 inches because the sum of the lengths of any two sides is greater than the length of the third side.

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Lucas's slugging ratio, rounded to the nearest thousandth is 0.743.

Therefore the answer is D) 0.743.

To find Lucas's slugging ratio, we first need to calculate the numerator of the equation:

number of singles, s = 18 singles

number of doubles, d = 2 doubles

number of triples, t = 0 triples

number of home runs, h = 1 home run

numerator = (s + 2d + 3t + 4h) = (18 + 2 * 2 + 3 * 0 + 4 * 1) = 26

denominator = b = 35 times at bat

Lucas's slugging ratio is numerator / b

= 26 / 35

= 0.743

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There are 3,265,920 arrangements of the letters in mathematics.

Consider T+H together which is easy to solve, and also consider the “TH” as one letter. There are two Ts in maThemaTics, and they can be together as TH or HT.

so there are actually 2*2=4 ways to build the TH itself. Now just plug a short hold on the “not followed by the h” and let us know how many ways to build it with just the TH restriction.

So with TH together, we can construct 10 letters in the word, two As, two Ms, and 1 as each of the remaining 6 letters. So it means there are

10!2!2!(1!)6=10!2!2!=36288004=907200

Now there are 4 ways to construct the TH, so 907200∗4=3,628,800.

To then add the “not followed by h” restriction, we should first determine all of the combinations where you have “THE” or “HTE” in the word. There are 4 ways to construct this letter grouping.

Then we have the remaining 9 letters in the word, two As, two Ms, and 1 of each of the remaining 5 letters.

So there are 4∗9!2!2!(1!)5=4∗9!4=3628802=362,880 ways to construct the word where you force THE/HTE together.

Finally, subtract the arrangements we have THE/HTE in the word from the arrangements where you just have TH/HT in order to get the arrangements that have TH/HT that is not immediately followed by h. 3,628,800–362,880=3,265,920.

Therefore, there are 3,265,920 arrangements.

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.

Answer:

Below

Step-by-step explanation:

The interior three angles of a triangle sum to 180°

 you know tow of them are 64 degrees

so the third one is 180 - 64 - 64    or  180 °- 128°

Answer:

When x=4, ln x-ln y=y-4, so ln 4-ln 4=4-4, which is true. Therefore, when x=4, y=4, and dy/dx=0.

Step-by-step explanation:

So, when x = 4, the value of the differentiable function dy/dx is 0.

A differentiable function of one real variable is one that has a derivative at each point in its domain. In other words, a differentiable function's graph has a non-vertical tangent line at each interior point in its domain.

Here,

Given the equation ln x - ln y = y - 4, we can rearrange it to get ln(x/y) = y - 4. Taking the derivative of both sides with respect to x using the chain rule:

d/dx (ln(x/y)) = d/dx (y - 4)

(1/x) (dx/dx) - (1/y) (dy/dx) = dy/dx

dy/dx = (1/y) (dx/dx) + (1/x) (dy/dx) = (1/y) + (1/x) (dy/dx)

Rearranging and solving for dy/dx:

(x/y) (dy/dx) = (1/y) - (1/x)

dy/dx = (x/y^2) (1/x - 1/y) = (x/y^2) (1/x - 1/y)

We can substitute x = 4 and y = 4 into the expression to find the value of dy/dx when x = 4:

dy/dx = (4/16) (1/4 - 1/4) = 0

So, the value of differentiable function dy/dx when x = 4 is 0.

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Each DVD cost is $17.80

This is a simple equation

From the question we have the following information :

1. Total spent for 2 dvd ( before tax ) = $17.80

2. Sales Tax for those spending = $2.85

Let's call the cost of each DVD "x".

The total cost of both DVDs would be 2x.

We know that the total cost of both DVDs and the sales tax was $38.45, so we can set up an equation:

2x + $2.85 = $38.45

Solving for x:

2x = $38.45 - $2.85 = $35.60

x = $35.60 / 2 = $17.80

Hence from explanation above, each DVD cost $17.80.

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Answer:

Step-by-step explanatio

23.2

The probability the ball drawn from the second box is red, is 17/56.

In a box are 7 red balls and 8 blue balls.

From this box are drawn 4 balls and placed in a second box.

We have to determine the probability the ball drawn from the second box is red.

The total number of balls = Red Balls + Blue Balls

The total number of balls = 7 + 8

The total number of balls = 15

The number of balls placed in second balls = 4

The number of combination of balls in box 2.

BBBB, BBBR, BBRR and BRRR

Then, one ball is drawn from the second box.

The probability the ball drawn from the second box is red.

P(Ball is red in the second box) = P(BBBB) + P(BBBR) + P(BBRR) + P(BRRR)

P(Ball is red in the second box) = [tex]\frac{^{5}C_{4}}{^{8}C_{0}}(0)+\left(\frac{^{5}C_{3}\times ^{3}C_{1}}{^{8}C_{4}}\right)\times\frac{^{1}C_{1}}{^{4}C_{1}}+\left(\frac{^{5}C_{2}\times ^{3}C_{2}}{^{8}C_{4}}\right)\times\frac{^{2}C_{1}}{^{4}C_{1}}+\left(\frac{^{5}C_{1}\times ^{3}C_{3}}{^{8}C_{4}}\right)\times\frac{^{3}C_{1}}{^{4}C_{1}}[/tex]

P(Ball is red in the second box) = [tex]0+\left(\frac{30}{70}\times\frac{1}{4}\right)+\left(\frac{30}{80}\times\frac{1}{2}\right)+\left(\frac{5}{70}\times\frac{3}{4}\right)[/tex]

P(Ball is red in the second box) = 3/48 + 3/16 + 3/56

P(Ball is red in the second box) = (21 + 63 + 18)/336

P(Ball is red in the second box) = 102/336

P(Ball is red in the second box) = 17/56

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The population of Jeevesium beetles is tripled in a time of approximately 14.265 years.

The statement indicated that a colony of Jeevesium beetles double its population every 9 years and we are required to find the number of years such that the population is tripled, the prediction model for population growth is shown below:

[tex]p(t) = p_{o}\cdot 2^{\frac{t}{9}}[/tex]

Where:

If we know that p(t) / p₀ = 3, then the time needed for the colony of Jeeversium beetles is:

[tex]3 = 2^{t / 9}[/tex]

㏒₂ 3 = t / 9

t = 9 · ㏒₂ 3

t ≈ 14.265

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Step-by-step explanation:

The function g is defined by the rule g(x) = 2x + 5. To complete the function table, we need to substitute different values of x into the function and find the corresponding output values.

Table:

⬇️

x g(x)

1 2*1 + 5 = 7

2 2*2 + 5 = 9

3 2*3 + 5 = 11

4 2*4 + 5 = 13

5 2*5 + 5 = 15

And so on, for any value of x you can substitute it into the function g(x) = 2x + 5 and you will get the result.

an ant travels from the point $a (0,-63)$ to the point $b (0,74)$ as follows. it first crawls straight to $(x,0)$ with $x \ge 0$, moving at a constant speed of $\sqrt{2}$ units per second. it is then instantly teleported to the point $(x,x)$. finally, it heads directly to $b$ at 2 units per second. what value of $x$ should the ant choose to minimize the time it takes to travel from $a$ to $b$?an ant travels from the point $a (0,-63)$ to the point $b (0,74)$ as follows. it first crawls straight to $(x,0)$ with $x \ge 0$, moving at a constant speed of $\sqrt{2}$ units per second. it is then instantly teleported to the point $(x,x)$. finally, it heads directly to $b$ at 2 units per second. what value of $x$ should the ant choose to minimize the time it takes to travel from $a$ to $b$?an ant travels from the point $a (0,-63)$ to the point $b (0,74)$ as follows. it first crawls straight to $(x,0)$ with $x \ge 0$, moving at a constant speed of $\sqrt{2}$ units per second. it is then instantly teleported to the point $(x,x)$. finally, it heads directly to $b$ at 2 units per second. what value of $x$ should the ant choose to minimize the time it takes to travel from $a$ to $b$?an ant travels from the point $a (0,-63)$ to the point $b (0,74)$ as follows. it first crawls straight to $(x,0)$ with $x \ge 0$, moving at a constant speed of $\sqrt{2}$ units per second. it is then instantly teleported to the point $(x,x)$. finally, it heads directly to $b$ at 2 units per second. what value of $x$ should the ant choose to minimize the time it takes to travel from $a$ to $b$?an ant travels from the point $a (0,-63)$ to the point $b (0,74)$ as follows. it first crawls straight to $(x,0)$ with $x \ge 0$, moving at a constant speed of $\sqrt{2}$ units per second. it is then instantly teleported to the point $(x,x)$. finally, it heads directly to $b$ at 2 units per second. what value of $x$ should the ant choose to minimize the time it takes to travel from $a$ to $b$?an ant travels from the point $a (0,-63)$ to the point $b (0,74)$ as follows. it first crawls straight to $(x,0)$ with $x \ge 0$, moving at a constant speed of $\sqrt{2}$ units per second. it is then instantly teleported to the point $(x,x)$. finally, it heads directly to $b$ at 2 units per second. what value of $x$ should the ant choose to minimize the time it takes to travel from $a$ to $b$?an ant travels from the point $a (0,-63)$ to the point $b (0,74)$ as follows. it first crawls straight to $(x,0)$ with $x \ge 0$, moving at a constant speed of $\sqrt{2}$ units per second. it is then instantly teleported to the point $(x,x)$. finally, it heads directly to $b$ at 2 units per second. what value of $x$ should the ant choose to minimize the time it takes to travel from $a$ to $b$?an ant travels from the point $a (0,-63)$ to the point $b (0,74)$ as follows. it first crawls straight to $(x,0)$ with $x \ge 0$, moving at a constant speed of $\sqrt{2}$ units per second. it is t minimize the time it takes to travel from $a$ to $b$?

The function corresponding to zeroes 6 and -4 is f(x)=(x-6)(x+4) i.e. A.

What is a function?

A function is defined as a relation between a set of inputs having one output each. In simple words, a function is a relationship between inputs where each input is related to exactly one output. Every function has a domain and co-domain or range. A function is generally denoted by f(x) where x is the input. The general representation of a function is y = f(x).

There are several types of functions in math. Some important types are:

Injective function or One to one function: When there is mapping for a range for each domain between two sets.

Surjective functions or Onto function: When there is more than one element mapped from domain to range.

Polynomial function: The function which consists of polynomials.

Inverse Functions: The function which can invert another function.

Now ,

We can find function for zeroes 6 and -4 by putting f(x)=0

Therefore,

(x-6)(x+4)=0

x-6=0 and x+4=0

Hence,

           x=6,-4

          The function corresponding to zeroes 6 and -4 is f(x)=(x-6)(x+4).

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The sum of 9/10 and 5/6 is 26/15.

The sum of two fractions can be calculated only if the denominator (the bottom number) is the same. Here, in 9/10, 10 is the denominator and in 5/6, 6 is the denominator. To equate two denominators LCM(least common multiple) should be done.

LCM of 10 and 6 is 30.

To convert is to multiply each by the bottom number of the other over the other

9/10 + 5/6

= 9/10×3/3 + 5/6×6/6

=27/30 + 25/30

=52/30

=26/15 or 1 11/15

Therefore, the sum of 9/10 and 5/6 is 26/15 or 1 11/15.

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The sum of 9/10 and 5/6 equals 26/15.

Only if the denominator (the bottom number) is the same can two fractions' total be calculated. In this case, the denominator in 9/10 is 10 and in 5/6 is 6. The LCM (least common multiple) method should be used to equate two denominators.

30 is the LCM of 10 and 6.:

By multiplying each by the bottom number of the other over the other, you may convert.

9/10 + 5/6

= 9/10×3/3 + 5/6×6/6

=27/30 + 25/30

=52/30

=26/15 or 1 11/15

As a result, 9/10 plus 5/6 equals 26/15.

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